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diff --git a/basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter1_UaQSIvn.ipynb b/basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter1_UaQSIvn.ipynb deleted file mode 100644 index e394c7f6..00000000 --- a/basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter1_UaQSIvn.ipynb +++ /dev/null @@ -1,785 +0,0 @@ -{ - "cells": [ - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "# Chapter 1:Introduction to electrical engineering" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.1:Page number-6" - ] - }, - { - "cell_type": "code", - "execution_count": 1, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "E= 90065423.52 N\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "q1=q2=0.1\n", - "r=1\n", - "e=8.84*(10**-12)\n", - "\n", - "E=(q1*q2)/float(4*3.14*e*(r**2))\n", - "\n", - "print \"E=\",format(E,'.2f'),\"N\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.2:Page number-7" - ] - }, - { - "cell_type": "code", - "execution_count": 38, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "5.52146091786 J\n", - "Vab=-vba=5.4V\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#given\n", - "\n", - "q1=2*(10**-9)\n", - "q2=3*(10**-9)\n", - "\n", - "#q1 and q2 are 6m apart in air\n", - "#on substituting the values in the formula for calculating force between q and q1 and q and q2 we get 9[(3/(6-x**2)-(2/(x**2)))]\n", - "\n", - "import sympy as sp\n", - "x=sp.Symbol('x')\n", - "sp.integrate(((3/(6-x)**2)-(2/x**2)),x)\n", - "\n", - "from scipy.integrate import quad\n", - "import scipy.integrate\n", - "\n", - "def f(x):\n", - " return -(x+12)/(x**2 - 6*x)\n", - " \n", - " \n", - " \n", - "\n", - "i=quad(f,1,4)\n", - "print (i[0]),\"J\"\n", - "\n", - "\n", - "print \"Vab=-vba=5.4V\"\n", - "\n", - "#the value obtained is directly given with print \n", - "\n", - "\n", - "\n", - "\n", - "\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.3:Page number-11" - ] - }, - { - "cell_type": "code", - "execution_count": 2, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "iav= 1.6 A\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "charge=1.6*(10**-19)\n", - "iav=1.6*(10**-19)*(10**19) #total charge movement per second\n", - "\n", - "print \"iav=\",format(iav,'.1f'),\"A\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.4:Page number-14" - ] - }, - { - "cell_type": "code", - "execution_count": 3, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "energy of each coulomb of charge= 3.0 J\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "p=30\n", - "i=10\n", - "\n", - "v=p/i\n", - "dt=1\n", - "dq=i*dt\n", - "\n", - "dw=v*dq\n", - "energy=dw/i\n", - "\n", - "print \"energy of each coulomb of charge=\",format(energy,'.1f'),\"J\"\n", - "\n", - "\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.5" - ] - }, - { - "cell_type": "code", - "execution_count": 4, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "torque= 95.54 Nm\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#given\n", - "\n", - "p=15000\n", - "n=1500\n", - "\n", - "t=(60*p)/float(1500*2*3.14)\n", - "\n", - "print \"torque=\",format(t,'.2f'),\"Nm\"\n" - ] - }, - { - "cell_type": "markdown", - "metadata": { - "collapsed": true - }, - "source": [ - "## Example 1.6:Page number-16" - ] - }, - { - "cell_type": "code", - "execution_count": 2, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " R= 0.1376 ohm\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "res=1.72*(10**-8)\n", - "l=200\n", - "a=25*(10**-6)\n", - "\n", - "R=(res*l)/float(a)\n", - "\n", - "print \"R=\",format(R,'.4f'),\"ohm\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.7 " - ] - }, - { - "cell_type": "code", - "execution_count": 4, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "R= 0.00000270 ohm\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#given and derived\n", - "meanrad=0.08\n", - "meanlen=3.14*meanrad\n", - "a=0.04*0.04\n", - "res=1.72*(10**-8)\n", - "\n", - "R=(res*meanlen)/float(a)\n", - "\n", - "print \"R=\",format(R,'.8f'),\"ohm\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.8:Page number-17 " - ] - }, - { - "cell_type": "code", - "execution_count": 2, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "R= 80.0000 ohm\n", - "power= 661.25 W\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "res=0.02*(10**-6)\n", - "l=4000*80*(10**-2)\n", - "a=0.8*(10**-6)\n", - "\n", - "R=(res*l)/float(a)\n", - "\n", - "print \"R=\",format(R,'.4f'),\"ohm\"\n", - "\n", - "power=(230*230)/float(80)\n", - "\n", - "print \"power=\",format(power,'.2f'),\"W\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.9" - ] - }, - { - "cell_type": "code", - "execution_count": 11, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "R= 0.2675 ohm\n", - "0.40127388535\n", - "dcu= 0.000569 nm\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "lal=7.5\n", - "lcu=6\n", - "rcu=0.017*(10**-6)\n", - "ral=0.028*(10**-6)\n", - "d=(10**-6)\n", - "a=((3.14*d))/float(4)\n", - "Ral=(lal*ral)/float(a)\n", - "\n", - "print \"R=\",format(Ral,'.4f'),\"ohm\"\n", - "\n", - "ial=3\n", - "\n", - "pv=Ral*ial\n", - "\n", - "\n", - "Rcu=pv/float(2)\n", - "print Rcu\n", - "\n", - "a=(rcu*lcu)/float(Rcu)\n", - "\n", - "dcu=(((a*4)/3.14)**0.5)\n", - "\n", - "print \"dcu=\",format(dcu,'.6f'),\"nm\"\n", - "\n", - "\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.10" - ] - }, - { - "cell_type": "code", - "execution_count": 9, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "l= 2706.896552 cm\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#given and derived\n", - "\n", - "a=100/0.32 #area required to dissipate 100W power\n", - "d=5\n", - "#length of cyclinder L,length of wire if l,diameter of the wire is d\n", - "L=a/float(3.14*d)\n", - "\n", - "r=100/1**2\n", - "\n", - "#spacing is d cm\n", - "#distance along the axis of the cylinder is 2d cm\n", - "\n", - "#no of turns is 10/d\n", - "#length of one turn of the wire is 3.14*5 cm\n", - "#length of the wire is 50*3.14/d\n", - "res=10**-4\n", - "\n", - "#d=(((2*10**-4))**(0.6))\n", - "d=0.058\n", - "\n", - "l=(50*3.14)/d\n", - "\n", - "print \"l=\",format(l,'.6f'),\"cm\"\n", - "\n", - "\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.11: Page number-20" - ] - }, - { - "cell_type": "code", - "execution_count": 10, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "t= 84.62 centigrade\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#given\n", - "v=250\n", - "i=5\n", - "i1=3.91\n", - "\n", - "t0=0.00426 #temperature coefficient\n", - "\n", - "r15=v/i #at 15 degrees\n", - "\n", - "rt=v/i1 #at t degrees\n", - "\n", - "l=(rt*(1+t0*15))/50 #left hand side\n", - "\n", - "t=(l-1)/t0\n", - "\n", - "print \"t=\",format(t,'.2f'),\"centigrade\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.12" - ] - }, - { - "cell_type": "code", - "execution_count": 11, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "al2=al1/(1+al1*(t1-t2))\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#this is a derivation by substitution problem\n", - "\n", - "#al1=al0/(1+al0*t1)\n", - "#al2=al0/(1+al0*t2)\n", - "#where t1 and t2 are different temperatures al0,al1 and al2 are temperature coefficients\n", - "\n", - "#substitute al0 in al2\n", - "\n", - "#on deriving and solving for al2 we get,\n", - "print \"al2=al1/(1+al1*(t1-t2))\"\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.13:Page number-22" - ] - }, - { - "cell_type": "code", - "execution_count": 12, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "v= 20.0 v\n", - "v= -10.0 v\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#values are obtained from the graph\n", - "\n", - "i=10 #10t A for 0 to 1 second\n", - "\n", - "d=10 #where di/dt is 10\n", - "L=2\n", - "# at one second\n", - "\n", - "v=L*d\n", - "\n", - "print \"v=\",format(v,'.1f'),\"v\"\n", - "\n", - "#for 1 to 5 seconds\n", - "\n", - "d=-5\n", - "\n", - "#at t=3 seconds voltage across the inductor is\n", - "\n", - "v=L*d\n", - "print \"v=\",format(v,'.1f'),\"v\"\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.16:Page number-27" - ] - }, - { - "cell_type": "code", - "execution_count": 2, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " i= 0.0005 A\n", - "q= 0.0005 C\n", - "p= 0.0100 W\n", - "wc= 0.0050 J\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#given\n", - "\n", - "dv=20 #dv/dt\n", - "c=25*(10**-6)\n", - "\n", - "#case a\n", - "\n", - "i=c*dv\n", - "\n", - "print \"i=\",format(i,'.4f'),\"A\"\n", - "\n", - "#case b\n", - "q=c*dv\n", - "\n", - "print \"q=\",format(q,'.4f'),\"C\"\n", - "\n", - "#case c\n", - "\n", - "p=dv*i\n", - "\n", - "print \"p=\",format(p,'.4f'),\"W\"\n", - "\n", - "#case d\n", - "v=dv**2\n", - "wc=(c*v)/2\n", - "\n", - "print \"wc=\",format(wc,'.4f'),\"J\"\n", - " " - ] - }, - { - "cell_type": "markdown", - "metadata": { - "collapsed": true - }, - "source": [ - "## Example 1.18:Page number-34" - ] - }, - { - "cell_type": "code", - "execution_count": 3, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "f= 75.0 N\n", - "p= 375.0 W\n", - "e= 7.5 V\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "l=1\n", - "b=1.5\n", - "i=50\n", - "u=5\n", - "\n", - "#case a\n", - "\n", - "f=b*i*l\n", - "\n", - "print \"f=\",format(f,'.1f'),\"N\"\n", - "\n", - "#case b\n", - "\n", - "p=f*u\n", - "\n", - "print \"p=\",format(p,'.1f'),\"W\"\n", - "\n", - "#case c\n", - "\n", - "e=b*l*u\n", - "\n", - "print \"e=\",format(e,'.1f'),\"V\"\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.19:Page number-35" - ] - }, - { - "cell_type": "code", - "execution_count": 5, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "e= 30.0 V\n", - "e= 15.0 V\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#e=b*l*u*sin(angle)\n", - "\n", - "b=0.5\n", - "l=40\n", - "u=1.5\n", - "\n", - "#when angle=90 sin(90)=1=s\n", - "s=1\n", - "e=b*l*u*s\n", - "\n", - "print \"e=\",format(e,'.1f'),\"V\"\n", - "\n", - "#when angle=30 sin(angle)=s=0.5\n", - "s=0.5\n", - "e=b*l*u*s\n", - "\n", - "print \"e=\",format(e,'.1f'),\"V\"\n", - "\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 1.22:Page number-37" - ] - }, - { - "cell_type": "code", - "execution_count": 6, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "vse= 8.0 V\n" - ] - } - ], - "source": [ - "import math\n", - "\n", - "#applying kcl to circuit at node b i3+i4=6-4=2\n", - "i3=i4=1 #potential of node b with respect to node c\n", - "vb=8\n", - "vba=2 #voltage drop across nodes b and a\n", - "va=6 #potential of node a w.r.t note c\n", - "i2=3\n", - "#applying kcl to node a\n", - "\n", - "isa=1\n", - "\n", - "vs=va+2*isa\n", - "\n", - "print \"vse=\",format(vs,'.1f'),\"V\"\n", - "\n" - ] - }, - { - "cell_type": "code", - "execution_count": null, - "metadata": { - "collapsed": true - }, - "outputs": [], - "source": [] - } - ], - "metadata": { - "kernelspec": { - "display_name": "Python 2", - "language": "python", - "name": "python2" - }, - "language_info": { - "codemirror_mode": { - "name": "ipython", - "version": 2 - }, - "file_extension": ".py", - "mimetype": "text/x-python", - "name": "python", - "nbconvert_exporter": "python", - "pygments_lexer": "ipython2", - "version": "2.7.9" - } - }, - "nbformat": 4, - "nbformat_minor": 0 -} |