diff options
Diffstat (limited to 'backup/mechanics_of_fluid_version_backup/Chapter7-.ipynb')
| -rwxr-xr-x | backup/mechanics_of_fluid_version_backup/Chapter7-.ipynb | 295 |
1 files changed, 0 insertions, 295 deletions
diff --git a/backup/mechanics_of_fluid_version_backup/Chapter7-.ipynb b/backup/mechanics_of_fluid_version_backup/Chapter7-.ipynb deleted file mode 100755 index 2d73578f..00000000 --- a/backup/mechanics_of_fluid_version_backup/Chapter7-.ipynb +++ /dev/null @@ -1,295 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:53c88693c5ad5193ad81179b96376eeb7bad9150fdb2bbf705d611fc5268083f"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter7-Flow and Losses in Pipes and Fittings"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex1-pg255"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate Head lost to friction\n",
- "Q=50*10**-3; ## m^3/s\n",
- "d=0.15; ## m\n",
- "l=300.; ## m\n",
- "v=1.14*10**-6; ## m^2/s\n",
- "g=9.81; ## m/s^2\n",
- "\n",
- "## For galvanised steel\n",
- "k=0.00015; ## m\n",
- "t=0.001; ## ratio of k to d ; (k/d)\n",
- "f=0.00515;\n",
- "\n",
- "A1=math.pi/4.*d**2;\n",
- "\n",
- "u=Q/A1; \n",
- "Re=u*d/v;\n",
- "\n",
- "h_f=4*f*l*u**2/d/(2*g);\n",
- "print'%s %.3f %s'%(\"Head lost to friction =\",h_f,\"m\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Head lost to friction = 16.811 m\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex2-pg255"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\t\t\t\n",
- "#calculate rate of discharge\n",
- "k=0.00025; ## m\n",
- "d=0.1; ## m\n",
- "l=120.; ## m\n",
- "h_f=5.; ## m\n",
- "g=9.81; ## m/s^2\n",
- "v=10**-5; ## m^2/s\n",
- "\n",
- "f=0.0079042;\n",
- "\n",
- "u=math.sqrt(h_f*d*(2.*g)/(4.*f*l));\n",
- "Re=u*d/v;\n",
- "\n",
- "Q=u*math.pi/4*d**2;\n",
- "print'%s %.4f %s'%(\"Rate =\",Q,\"m^3/s\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Rate = 0.0126 m^3/s\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex3-pg256"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate The size of galvanized steel pipe \n",
- "h_f=9.; ## m\n",
- "l=180.; ## m\n",
- "Q=85.*10**-3; ## m^3/s\n",
- "f=0.00475; \n",
- "k=0.00015; ## m\n",
- "v=1.14*10**-6; ## m^2/s\n",
- "g=9.81; ## m/s^2\n",
- "\n",
- "d=(4.*f*l*Q**2./h_f/(math.pi/4.)**2/(2.*g))**(1/5.);\n",
- "Re=(Q/(math.pi*d**2/4))*d/v;\n",
- "\n",
- "print'%s %.3f %s'%(\"The size of galvanized steel pipe =\",d,\"m \")"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The size of galvanized steel pipe = 0.187 m \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4-pg275"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate Revised estimate of the optimum pipe diameter\n",
- "## D1=(5*b1/3/a)^(1/8)\n",
- "## D2=(5*b1/3/a)^(1/8)\n",
- "\n",
- "## But b2=2.5*b1\n",
- "## Therefore D2=(2.5)^(1/8)*D1\n",
- "\n",
- "D1=600.; ## mm\n",
- "\n",
- "D2=(2.5)**(1/8.)*D1;\n",
- "\n",
- "print'%s %.1f %s'%(\"Revised estimate of the optimum pipe diameter =\",D2,\"mm\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Revised estimate of the optimum pipe diameter = 672.8 mm\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex5-pg282"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate Pressure difference and Feed is at the centre of the main and Pressure difference \n",
- "Q0=4.5*10**-3; ## m**3/s\n",
- "d=0.1; ## m\n",
- "l=4.5*10**3; ## m\n",
- "g=9.81; ## m/s**2\n",
- "f=0.006; \n",
- "rho=1000.; ## kg/m**3\n",
- "\n",
- "u0=Q0/(math.pi/4.*d**2);\n",
- "h_f=4.*f*u0**2*l/3./(d*2*g);\n",
- "\n",
- "dp=h_f*rho*g;\n",
- "print'%s %.1f %s'%(\"Pressure difference =\",dp,\"N/m**2\")\n",
- "\n",
- "\n",
- "print(\"Feed is at the centre of the main\")\n",
- "\n",
- "Q0_b=Q0/2.;\n",
- "u0_b=u0/2.;\n",
- "l_b=l/2.;\n",
- "\n",
- "dp_b=(u0_b/u0)**2*(l_b/l)*dp;\n",
- "print'%s %.1f %s'%(\"Pressure difference =\",dp_b,\"N/m**2\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Pressure difference = 59090.5 N/m**2\n",
- "Feed is at the centre of the main\n",
- "Pressure difference = 7386.3 N/m**2\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex6-pg286"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate The change in the level in larger tank \n",
- "d1=3.; ## m\n",
- "d2=2.; ## m\n",
- "f=0.007;\n",
- "l=75.; ## m\n",
- "d=0.05; ## m\n",
- "g=9.81; ## m/s**2\n",
- "h1=1.8; ## m\n",
- "\n",
- "A1=math.pi/4.*d1**2;\n",
- "A2=math.pi/4.*d2**2;\n",
- "\n",
- "## dh/dt=dz1/dr*(1+A1/A2)\n",
- "## Q=-A1*dz1/dt = -4/13*A1*dh/dt\n",
- "\n",
- "## u=(Q/2)**2/(%pi/4*d**2)\n",
- "## h=(4*f*l/d + 1.5)*u**2/2g = 1.438*10**5*Q**2\n",
- "\n",
- "## t=integrate('-1/(1+A1/A2)*A1*(1.438*10**5/h)**(1/2)','h',h1,H)\n",
- "\n",
- "## By integrating, we get\n",
- "H=(h1**(1/2.)-(900./2./824.7))**2;\n",
- "h=h1-H;\n",
- "dz1=1./(1+A1/A2)*h;\n",
- "\n",
- "print'%s %.3f %s'%(\"The change in the level in larger tank =\",dz1,\"m\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The change in the level in larger tank = 0.359 m\n"
- ]
- }
- ],
- "prompt_number": 7
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |