diff options
Diffstat (limited to 'Thermodynamics_for_Engineers/Chapter_16_2.ipynb')
| -rwxr-xr-x | Thermodynamics_for_Engineers/Chapter_16_2.ipynb | 253 |
1 files changed, 253 insertions, 0 deletions
diff --git a/Thermodynamics_for_Engineers/Chapter_16_2.ipynb b/Thermodynamics_for_Engineers/Chapter_16_2.ipynb new file mode 100755 index 00000000..efa01670 --- /dev/null +++ b/Thermodynamics_for_Engineers/Chapter_16_2.ipynb @@ -0,0 +1,253 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:dc464f4ef08695f8cec0668d0c21cb89b005d8581737f852d592d0e688b3aa48"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 16 - Gas cycles"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 1 - Pg 330"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the max. pressure, temperature and thermal efficiency\n",
+ "#Initalization of variables\n",
+ "import math\n",
+ "cr=9.\n",
+ "p1=14. #psia\n",
+ "t1=80.+460 #R\n",
+ "n=1.4\n",
+ "heat=800. #Btu\n",
+ "c=0.1715\n",
+ "R=53.35\n",
+ "J=778.\n",
+ "#calculations\n",
+ "p2=p1*math.pow(cr,n)\n",
+ "t2=t1*math.pow(cr,(n-1))\n",
+ "t3=heat/c +t2\n",
+ "p3=p2*t3/t2\n",
+ "eff=(1-1/math.pow(cr,(n-1)))*100\n",
+ "t4=t3/math.pow(cr,(n-1))\n",
+ "Qr=c*(t4-t1)\n",
+ "cyclework=heat-Qr\n",
+ "eff2= cyclework/heat *100\n",
+ "V1=R*t1/(144*p1)\n",
+ "pd=(1-1/cr)*V1\n",
+ "mep=cyclework*J/(pd*144)\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Max. temperature =\",t3,\"R\")\n",
+ "print '%s %d %s' %(\"\\n Max. pressure =\",p3,\"psia\")\n",
+ "print '%s %.1f %s' %(\"\\n In method 1,Thermal efficiency =\",eff,\" percent\")\n",
+ "print '%s %.1f %s' %(\"\\n In method 2,Thermal efficiency =\",eff2,\" percent\")\n",
+ "print '%s %.1f %s' %(\"\\n Mean effective pressure mep =\",mep,\" psia\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Max. temperature = 5965 R\n",
+ "\n",
+ " Max. pressure = 1391 psia\n",
+ "\n",
+ " In method 1,Thermal efficiency = 58.5 percent\n",
+ "\n",
+ " In method 2,Thermal efficiency = 58.5 percent\n",
+ "\n",
+ " Mean effective pressure mep = 199.0 psia\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2 - Pg 333"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the max temperature, pressure and thermal efficiency\n",
+ "#Initalization of variables\n",
+ "import math\n",
+ "t1=80+460. #R\n",
+ "p1=14. #psia\n",
+ "n=1.4\n",
+ "cr=16.\n",
+ "heat=800. #Btu\n",
+ "cp=0.24\n",
+ "c=0.1715\n",
+ "#calculations\n",
+ "t2=t1*math.pow(cr,(n-1))\n",
+ "p2=p1*math.pow(cr,n)\n",
+ "t3=t2 +heat/cp\n",
+ "v32=t3/t2\n",
+ "v43=cr/v32\n",
+ "t4=t3/math.pow(v43,(n-1))\n",
+ "Qr=c*(t4-t1)\n",
+ "etat=(heat-Qr)/heat *100\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Max. Temperature =\",t3,\" R\")\n",
+ "print '%s %d %s' %(\"\\n Max. Pressure =\",p2,\"psia\")\n",
+ "print '%s %.1f %s' %(\"\\n Thermal efficiency =\",etat,\" percent\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Max. Temperature = 4970 R\n",
+ "\n",
+ " Max. Pressure = 679 psia\n",
+ "\n",
+ " Thermal efficiency = 56.8 percent\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3 - Pg 335"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the Mean effective pressure\n",
+ "#Initalization of variables\n",
+ "eff=0.585\n",
+ "heat=800. #Btu\n",
+ "t1=80+460. #R\n",
+ "p1=14. #psia\n",
+ "n=1.4\n",
+ "R=53.35\n",
+ "cr=9.\n",
+ "cp=0.24\n",
+ "J=778.\n",
+ "#calculations\n",
+ "W=eff*heat\n",
+ "v1=R*t1/(144*p1)\n",
+ "v2=v1/cr\n",
+ "t2=1301 #R\n",
+ "t3=t2+ heat/cp\n",
+ "v3=v2*t3/t2\n",
+ "v4=cr*v3\n",
+ "mep=W*J/(144*(v4-v2))\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Mean effective pressure =\",mep,\" psia\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Mean effective pressure = 51.3 psia\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4 - Pg 340"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the max temperature, pressure, thermal efficiency, mean effective pressure\n",
+ "#Initalization of variables\n",
+ "import math\n",
+ "eff=0.585\n",
+ "heat=500. #Btu\n",
+ "heat1=300. #Btu\n",
+ "t1=80+460. #R\n",
+ "p1=14. #psia\n",
+ "n=1.4\n",
+ "R=53.35\n",
+ "cr=9.\n",
+ "J=778.\n",
+ "c=0.1715\n",
+ "cp=0.24\n",
+ "t2=1301. #R\n",
+ "p2=308. #psia\n",
+ "#calculations\n",
+ "t3=t2+ heat/c\n",
+ "p3=p2*t3/t2\n",
+ "t4=t3+ heat1/cp\n",
+ "v43=t4/t3\n",
+ "v54=cr/v43\n",
+ "t5=t4/math.pow(v54,(n-1))\n",
+ "Qr=c*(t5-t1)\n",
+ "etat=(heat+heat1-Qr)/(heat+heat1) *100\n",
+ "mep=(heat+heat1-Qr)*J/(12.69*144)\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Max. Temperature =\",t4,\" R\")\n",
+ "print '%s %d %s' %(\"\\n Max. Pressure =\",p3,\"psia\")\n",
+ "print '%s %.1f %s' %(\"\\n Thermal efficiency =\",etat,\"percent\")\n",
+ "print '%s %.1f %s' %(\"\\n Mean effective pressure =\",mep,\" psia\")\n",
+ "print '%s' %(\"The calculations are a bit different due to rounding off error in textbook\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Max. Temperature = 5466 R\n",
+ "\n",
+ " Max. Pressure = 998 psia\n",
+ "\n",
+ " Thermal efficiency = 57.6 percent\n",
+ "\n",
+ " Mean effective pressure = 196.2 psia\n",
+ "The calculations are a bit different due to rounding off error in textbook\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |