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diff --git a/Thermodynamics_for_Chemists/ch14.ipynb b/Thermodynamics_for_Chemists/ch14.ipynb new file mode 100755 index 00000000..7665275b --- /dev/null +++ b/Thermodynamics_for_Chemists/ch14.ipynb @@ -0,0 +1,244 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:8929370eda354c28fce9b829f100333cf5fedfea917f7bb51452b097667996b2" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 14 : The Properties of Solution" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.1 Page No : 322" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "import math \n", + "M2 = 92. \t\t\t#gms\n", + "M1 = 78. \t\t\t#gms\n", + "pb = 118.2 \t\t\t#mm\n", + "pt = 36.7 \t\t\t#mm\n", + "\n", + "# Calculations\n", + "n1 = M2/(M1+M2)\n", + "n2 = 1-n1\n", + "p1 = n1*pb\n", + "p2 = n2*pt\n", + "w = p1*M1/(p2*M2)\n", + "\n", + "# Results\n", + "print 'partial pressure of benzene = %.f mm'%(p1)\n", + "print ' partial pressure of toulene = %.1f mm'%(p2)\n", + "print ' weight proportions = %.2f '%(w)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "partial pressure of benzene = 64 mm\n", + " partial pressure of toulene = 16.8 mm\n", + " weight proportions = 3.22 \n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.2 Page No : 325" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "vpe = 42 \t\t\t#atm\n", + "p2 = 1. \t\t\t#atm\n", + "\n", + "# Calculations\n", + "N2 = p2/vpe\n", + "\n", + "# Results\n", + "print 'Ideal solubility of ethane = %.3f mole fraction'%(N2)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Ideal solubility of ethane = 0.024 mole fraction\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.3 Page No : 325" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "import math \n", + "p1 = 25.7 \t\t\t#atm\n", + "p2 = 11.84 \t\t\t#atm\n", + "T1 = 173. \t\t\t#K\n", + "T2 = 153. \t\t\t#K\n", + "T3 = 25. \t\t\t#C\n", + "\n", + "# Calculations\n", + "dH = math.log10(p1/p2)*4.579*T1*T2/(T1-T2)\n", + "p = p1*10**((dH/4.576)*(273+T3-T1)/((273+T3)*T1))\n", + "s = 1./p\n", + "\n", + "# Results\n", + "print 'Heat of reaction = %d cal mole**-1'%(dH)\n", + "print ' pressure = %d atm'%(p)\n", + "print ' Solubility of methane = %.5f '%(s)\n", + "\n", + "# note : rounding error is there. please check. " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Heat of reaction = 2039 cal mole**-1\n", + " pressure = 309 atm\n", + " Solubility of methane = 0.00323 \n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.4 Page No : 329" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "T1 = 20. \t\t\t#C\n", + "T2 = 80. \t\t\t#C\n", + "H1 = 4540. \t\t\t#cal mole**-1\n", + "\n", + "# Calculations\n", + "n = 10**(H1*(-T2+T1)/(4.576*(273+T1)*(273+T2)))\n", + "\n", + "# Results\n", + "print 'ideal solubility of napthalene = %.3f '%(n)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "ideal solubility of napthalene = 0.266 \n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.5 Page No : 342" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "R = 1.987 \t\t\t#cal mole**-1 K**-1\n", + "T = 278.6 \t\t\t#K\n", + "dH = 30.2 \t\t\t#cal g**-1\n", + "m = 6.054 \t\t\t#gms\n", + "a = 0.1263 \t\t\t#degrees\n", + "\n", + "# Calculations\n", + "l = R*T**2/(1000*dH)\n", + "m1 = a/l\n", + "M2 = m/m1\n", + "\n", + "# Results\n", + "print 'molal depression consmath.tant = %.2f '%(l)\n", + "print ' molality = %.4f '%(m1)\n", + "print ' molecular weight of solute = %.f gms'%(M2)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "molal depression consmath.tant = 5.11 \n", + " molality = 0.0247 \n", + " molecular weight of solute = 245 gms\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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