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-{
- "metadata": {
- "name": "",
- "signature": "sha256:080ddee320ed2e8325a1bba2bf7e96e362906d7bc4b7f00bae6953ceccc830a0"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 5: The Second Law of Thermodynamics"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.1, page no. 87"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#initilisation\n",
- "Tr = 540.0 #R\n",
- "Te = 2000.0 #R\n",
- "m = 200.0 #B/lbm\n",
- "\n",
- "#calculation\n",
- "eta = 1-(Tr/Te)\n",
- "Qr = m*(1-eta)\n",
- "\n",
- "\n",
- "#result\n",
- "print \"Thermal efficiency is \", eta*100, \"%\"\n",
- "print \"Heat rejected = %d B/lbm\" %Qr"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Thermal efficiency is 73.0 %\n",
- "Heat rejected = 54 B/lbm\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.2, page no. 90"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "import scipy.integrate\n",
- "\n",
- "#initilisation\n",
- "cv=0.171 #B/lbm F\n",
- "T2=580 #F\n",
- "T1=520 #F\n",
- "\n",
- "#calculation\n",
- "def fun(T):\n",
- " cp=cv/T\n",
- " return cp\n",
- "\n",
- "ds = scipy.integrate.quadrature(fun, T1, T2)[0]\n",
- "\n",
- "#result\n",
- "print \"Change in entropy = %.4f B/lbm R\" %ds"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Change in entropy = 0.0187 B/lbm R\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.3, page no. 95"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "import scipy.integrate\n",
- "\n",
- "#initilisation\n",
- "\n",
- "Q = 100.0 #B/lbm\n",
- "Cp = 0.24 #B/lbm F\n",
- "T1 = 70.0+460.0 #R\n",
- "T2 = 550.0+460.0 #R\n",
- "Ts = 50.0+460.0 #R\n",
- "\n",
- "#calculation\n",
- "def fun(T):\n",
- " cp = Cp/T\n",
- " return cp\n",
- " \n",
- "ds1 = scipy.integrate.quadrature(fun, T1, T2)[0]\n",
- "Tf = Q/Cp + T1\n",
- "ds2 = scipy.integrate.quadrature(fun, T1, Tf)[0]\n",
- "Qr = Ts*(ds2)\n",
- "Qa = Q-Qr\n",
- "Qun = Ts*(ds1)\n",
- "Qa2 = Q-Qun\n",
- "\n",
- "#result\n",
- "print \"Case 1\"\n",
- "print \"Change in entropy = %.4f B/lbm R\" %ds1\n",
- "print \"case 2\"\n",
- "print \"Entropy change = %.4f B/lbm R\" %ds2\n",
- "print \"Available energy = %.1f B/lbm\" %Qa\n",
- "print \"case 3\"\n",
- "print \"Available energy = %.1f B/lbm\" %Qa2"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Case 1\n",
- "Change in entropy = 0.1548 B/lbm R\n",
- "case 2\n",
- "Entropy change = 0.1392 B/lbm R\n",
- "Available energy = 29.0 B/lbm\n",
- "case 3\n",
- "Available energy = 21.1 B/lbm\n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file