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diff --git a/Thermodynamics_by_F_P_Durham/chapter10.ipynb b/Thermodynamics_by_F_P_Durham/chapter10.ipynb deleted file mode 100755 index c9d863da..00000000 --- a/Thermodynamics_by_F_P_Durham/chapter10.ipynb +++ /dev/null @@ -1,164 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:290fc441b8b16bf79982880c80bb6a81fed30d12de1c6a3c7f5a66a567e435bd" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 10: Refrigeration" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 10.1, page no. 193" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "#initialization\n", - "capacity = 5.0 #tons\n", - "hp = 10.0 #hp\n", - "\n", - "#calculation\n", - "beta = (778*3.33*capacity)/(hp*550)\n", - "\n", - "#result\n", - "print \"Coefficient of performance = \", round(beta, 2)" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Coefficient of performance = 2.36\n" - ] - } - ], - "prompt_number": 6 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 10.2, page no. 197" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "#initialization\n", - "P1 = 30.0 #lb/in^2\n", - "P2 = 200.0 #lb/in^2\n", - "capacity = 3.0 #tons\n", - "\n", - "#calculation\n", - "#From the pressure enthalpy chart\n", - "Tt1 = -1 #F\n", - "st1 = 1.34\n", - "ht1 = 612.0\n", - "ht2 = 733.0\n", - "ht3 = 141.0\n", - "ht4 = 141.0\n", - "WbyJ = ht2-ht1\n", - "Q = ht1-ht3\n", - "beta = Q/WbyJ\n", - "Qdot = capacity*3.33\n", - "wdot = Qdot/Q\n", - "Power = wdot*778*WbyJ\n", - "Power = Power/550.0\n", - "\n", - "#result\n", - "print \"Coefficient of performance = \", round(beta, 2)\n", - "print \"Evarator temperature = %d F\" %Tt1\n", - "print \"Power required = %.2f hp\" %Power\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Coefficient of performance = 3.89\n", - "Evarator temperature = -1 F\n", - "Power required = 3.63 hp\n" - ] - } - ], - "prompt_number": 13 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 10.3, page no. 200" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "#initialization\n", - "P1 = 14.0 #lb/in^2\n", - "P2 = 60.0 #lb/in^2\n", - "Tt1 = 80+460.0 #R\n", - "Tt4 = -20+460.0 #R\n", - "m = 30.0 #lbm/sec\n", - "cp = 0.24\n", - "\n", - "#calculation\n", - "Tt2 = round(Tt1*(P2/P1)**(0.286))\n", - "Tt3 = round(Tt4*(P2/P1)**(0.286))\n", - "WbyJ1 = cp*(Tt2-Tt1)\n", - "WbyJ2 = cp*(Tt3-Tt4)\n", - "Q = cp*(Tt1-Tt4)\n", - "beta = Q/(WbyJ1-WbyJ2)\n", - "Power = (m*778)*(WbyJ1-WbyJ2)\n", - "Wdot = Power/550.0\n", - "\n", - "#result\n", - "print \"Coefficient of performance = %.3f\" %beta\n", - "print \"Net power = %d hp\" %Wdot\n", - "\n", - "#difference in answer due to rounding of in Python" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Coefficient of performance = 1.923\n", - "Net power = 529 hp\n" - ] - } - ], - "prompt_number": 24 - } - ], - "metadata": {} - } - ] -}
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