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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:de09a4c2813282719223c840622b4f97d21f59c5103e9a20c830f4005781fd9e"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter6 -Control volume"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example1-pg 83"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate diameter for given variable\n",
+ "##initialisation of variables\n",
+ "R= 8.314 ##J/mol K\n",
+ "M= 29 ##gms\n",
+ "T= 80 ##C\n",
+ "p= 104 ##/kPa\n",
+ "v= 30 ##m/sec\n",
+ "m= 8000 ##kg/h\n",
+ "##CALCULATIONS\n",
+ "V= R*(273.15+T)/(M*p)\n",
+ "A= m*V/(3600*v)\n",
+ "D=math.sqrt(4*A/math.pi)\n",
+ "##RESULTS\n",
+ "print'%s %.5f %s'%('diameter = ',D,'m^2')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "diameter = 0.30301 m^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2-pg 88"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate intial areas\n",
+ "##initialisation of variables\n",
+ "R= 8.314 ##J/mol K\n",
+ "M= 29. ##gms\n",
+ "T1= 230. ##C\n",
+ "p1= 30. ##/bar\n",
+ "k= 1.4\n",
+ "T2= 180. ##C\n",
+ "v1= 10. ##m/s\n",
+ "p2= 20. ##bar\n",
+ "m2= 0.84 ##kg/s\n",
+ "##CALCULATIONS\n",
+ "V1= R*(273.15+T1)/(M*p1*100)\n",
+ "cp= k*R/((k-1)*M)\n",
+ "A= m2*V1*10*10*10*10/v1\n",
+ "v2= math.sqrt(v1*v1+2*cp*10*10*10*(T1-T2))\n",
+ "V2= R*(273.15+T2)/(M*p2*100)\n",
+ "A2= m2*V2*10*10*10*10/v2\n",
+ "##RESULTS\n",
+ "print'%s %.1f %s'%('inlet area =',A,'cm^2')\n",
+ "print'%s %.2f %s'%('inlet area =',A2,'cm^2')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "inlet area = 40.4 cm^2\n",
+ "inlet area = 1.72 cm^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example3-pg 89"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate quantity x and specific volume\n",
+ "##initialisation of variables\n",
+ "h= 2676.2 ##kJ/kg\n",
+ "hf= 721.11 ##kJ/kg\n",
+ "hg= 2679.1 ##kJ/kg\n",
+ "vf= 0.001115 ##m^3/kg\n",
+ "vg= 0.2404 ##m^3/kg\n",
+ "##CALCULATIONS\n",
+ "x= (h-hf)/(hg-hf)\n",
+ "v1= vf+x*(vg-vf)\n",
+ "##RESULTS\n",
+ "print'%s %.4f %s'%('quantity =',x,'')\n",
+ "print'%s %.4f %s'%('specific volume = ',v1,'m^3/kg')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "quantity = 0.9985 \n",
+ "specific volume = 0.2400 m^3/kg\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example4-pg 92"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate heat pump and reate heat interaction and work of the turbine and at another point rate of heat interaction and all four areas at given poin\n",
+ "##initialisation of variables\n",
+ "h4= 419.05 ##kJ/kg\n",
+ "h1= 434.92 ##kJ/kg\n",
+ "m= 2.5 ##kg/s\n",
+ "h2= 3272.4 ##kJ/kg\n",
+ "h3= 2601.7 ##kJ/kg\n",
+ "v1= 0.001401 ##m^3/kg\n",
+ "V1= 5 ##m/s\n",
+ "v2= 0.03817 ##m^3/kg\n",
+ "V2= 20. ##m/s\n",
+ "v3= 0.8415 ##m^3/kg\n",
+ "V3= 100. ##m/s\n",
+ "v4= 0.00104 ##m^3/kg\n",
+ "V4= 5 ##m/s\n",
+ "##CALCULATIONS\n",
+ "W41= m*(h4-h1)\n",
+ "Q12= m*(h2-h1)\n",
+ "W23= m*(h2-h3)\n",
+ "Q34= m*(h4-h3)\n",
+ "A1= m*v1*10*10*10*10/V1\n",
+ "A2= m*v2*10*1010*10/V2\n",
+ "A3= m*v3*10*1010*10/V3\n",
+ "A4= m*v4*10*1010*10/V4\n",
+ "##RESULTS\n",
+ "print'%s %.1f %s'%('rate of pump =',W41,'kW')\n",
+ "print'%s %.f %s'%('rate of heat ineraction =',Q12,'kW')\n",
+ "print'%s %.1f %s'%('rate of work of the turbine =',W23,'W')\n",
+ "print'%s %.f %s'%('rate of heat ineraction =',Q34,'kW')\n",
+ "print'%s %.2f %s'%('area =',A1,'cm^2')\n",
+ "print'%s %.2f %s'%('area =',A2,'cm^2')\n",
+ "print'%s %.2f %s'%('area =',A3,'cm^2')\n",
+ "print'%s %.2f %s'%('area =',A4,'cm^2')\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "rate of pump = -39.7 kW\n",
+ "rate of heat ineraction = 7094 kW\n",
+ "rate of work of the turbine = 1676.8 W\n",
+ "rate of heat ineraction = -5457 kW\n",
+ "area = 7.00 cm^2\n",
+ "area = 481.90 cm^2\n",
+ "area = 2124.79 cm^2\n",
+ "area = 52.52 cm^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example5-pg 96"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate mass of helium and temperature of helium\n",
+ "##initialisation of variables\n",
+ "m1= 0.03 ##kg\n",
+ "R= 8.314 ##J/mol K\n",
+ "T1= 300. ##C\n",
+ "p1= 120. ##kPa\n",
+ "k= 5./3.\n",
+ "M=4. ##kg\n",
+ "p2= 600. ##kPa\n",
+ "##CALCULATIONS\n",
+ "V= m1*R*(273.15+T1)/(p1*M)\n",
+ "m2= m1*((p2/p1)+k-1)/k\n",
+ "T2= p2*V*M/(m2*R)\n",
+ "##RESULTS\n",
+ "print'%s %.3f %s'%('mass of helium =',m2,'kg')\n",
+ "print'%s %.1f %s'%('temperature of helium =',T2,'K')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "mass of helium = 0.102 kg\n",
+ "temperature of helium = 842.9 K\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Eaxmple 6-pg97"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate volume of container and pressure\n",
+ "##initialisation of variables\n",
+ "m1= 0.03 ##kg\n",
+ "v1= 2.1977 ##m^3/kg\n",
+ "h2= 3073.8 ##kJ/kg\n",
+ "h1= 3061.6 ##kJ/kg\n",
+ "p2= 600. ##kPa\n",
+ "p1= 120. ##kPa\n",
+ "##CALCULATIONS\n",
+ "V=m1*v1\n",
+ "r= ((h2-h1)/v1)+p2-p1\n",
+ "##RESULTS\n",
+ "print'%s %.5f %s'%('volume of container =',V,'m^3')\n",
+ "print'%s %.2f %s'%('pressure =',r,'kPa')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "volume of container = 0.06593 m^3\n",
+ "pressure = 485.55 kPa\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file