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diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter16_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter16_1.ipynb
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--- a/Thermodynamics:_From_concepts_to_applications/Chapter16_1.ipynb
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@@ -1,109 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:e59b2fd71b4552cea44cac8d6a7db5757cb1bae32cfc202beb06aefa6735b63c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter16-equlibrium"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg349"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at the equllibrium state\n",
-      "##initialisation of variables\n",
-      "m= 10. ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "k= 1.4\n",
-      "M= 29. ##kg\n",
-      "TA= 20. ##C\n",
-      "TB= 200. ##C\n",
-      "##CALCULATIONS\n",
-      "T= (TA+TB)/2\n",
-      "dS= 0.5*m*R*(math.log(273.15+T)*math.log(273.15+T))/((273.15+TA)*(273.15+TB))/((k-1)*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('entropy at the equillibrium state=',dS,'kJ/K')\n",
-      "\n",
-      "\n",
-      "##answer GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy at the equillibrium state= 0.0009 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg357"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte equlibrium pressure and diameter of droplet\n",
-      "##initialisation of variables\n",
-      "psat= 143.3 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 110. ##C\n",
-      "m= 18.02 ##gms\n",
-      "pv= 150. ##kPa\n",
-      "v= 0.001052 ##m^3/kg\n",
-      "s= math.pow(10,-3)\n",
-      "##CALCULATIONS\n",
-      "PL= psat+((R*(273.15+T)/(m*0.0010502))*math.log(pv/psat))\n",
-      "D= (4*s/(PL-pv))*(75.64-13.91*(T/100)-3*(T/100)*(T/100))*10*10*10\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('equilibrium pressure=',PL-13,'kPa')\n",
-      "print'%s %.4f %s'% ('diameter of droplet=',D,'mm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium pressure= 7822 kPa\n",
-        "diameter of droplet= 0.0295 mm\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file