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diff --git a/Stoichiometry_And_Process_Calculations/ch8.ipynb b/Stoichiometry_And_Process_Calculations/ch8.ipynb deleted file mode 100755 index f4b3762e..00000000 --- a/Stoichiometry_And_Process_Calculations/ch8.ipynb +++ /dev/null @@ -1,927 +0,0 @@ -{ - "metadata": { - "name": "" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 8 : Humidity and Humidity chart" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.1 pageno : 206" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "T = 280. #K\n", - "P = 105. #kPa\n", - "Pas = 13.25 #kPa ( Vpaour pressure of acetone )\n", - "Pa = Pas # ( As gas is saturated, partial pressure = vapour pressure )\n", - "\n", - "# Calculation \n", - "Mfr = Pa / P #(Mole fraction) \n", - "Mpr = Mfr * 100 \n", - "print \"(a)The mole percent of acetone in the mixture = %.2f %%\"%Mpr\n", - "Ma = 58.048 #(molecular weight of acetone)\n", - "Mn = 28. #(molecular weight of nitrogen)\n", - "N = 1. #mole\n", - "Na = Mfr * N \n", - "Nn = N - Na \n", - "ma = Na * Ma \n", - "mn = Nn * Mn \n", - "mtotal = ma + mn \n", - "maper = ma *100 / mtotal \n", - "mnper = mn *100/ mtotal \n", - "\n", - "# Result\n", - "print \"(b)Weight percent of acetone = %.2f %%\"%maper\n", - "print \"Weight percent of nitrogen = %.2f %%\"%mnper\n", - "Vstp = 22.4 #m**3/kmol\n", - "Pstp = 101.3 #kPa\n", - "Tstp = 273.15 #K\n", - "V = Vstp * Pstp * T / ( Tstp * P ) \n", - "C = ma/V \n", - "print \"(c)Concentration of vapour = %.4f kg/m**3\"%C\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)The mole percent of acetone in the mixture = 12.62 %\n", - "(b)Weight percent of acetone = 23.04 %\n", - "Weight percent of nitrogen = 76.96 %\n", - "(c)Concentration of vapour = 0.3307 kg/m**3\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.2 pageno : 207" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math \n", - "\n", - "# Variables \n", - "P = 101.3 #kPa\n", - "Per1 = 10. #%\n", - "\n", - "# Calculation \n", - "Pa = P * Per1 / 100 # ( a - benzene )\n", - "Ps = Pa #( saturation )\n", - "#lnPs = 13.8858 - 2788.51/(T - 52.36)\n", - "T = 2788.51 / ( 13.8858 - math.log(Ps)) + 52.36 \n", - "\n", - "# Result\n", - "print \"Temperature at which saturation occurs = %.1f K\"%T\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Temperature at which saturation occurs = 293.4 K\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.3 pageno : 207" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "Pdryair = 101.3 #kPa\n", - "Pacetone = 16.82 #kPa\n", - "\n", - "# Calculation \n", - "Nratio = Pacetone / (Pdryair - Pacetone) \n", - "mratio = Nratio * 58.048 / 29 # ( Macetone = 58.048, Mair = 29 )\n", - "macetone = 5. #kg ( given )\n", - "mdryair = macetone / mratio \n", - "\n", - "# Result\n", - "print \"Minimum air required = %.2f kg\"%mdryair\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Minimum air required = 12.55 kg\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.4 pageno : 209" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math \n", - "\n", - "# Variables \n", - "Pa = 15. #kPa ( partial pressure of acetone)\n", - "Ptotal = 101.3 #kPa\n", - "\n", - "# Calculation and Result \n", - "Mfr = Pa / Ptotal \n", - "print \"(a)Mole fraction of acetone = %.4f \"%Mfr\n", - "Macetone = 58.048 \n", - "Mnitrogen = 28. \n", - "mafr = Mfr * Macetone / ( Mfr * Macetone + (1-Mfr)* Mnitrogen ) \n", - "print \"(b)Weight fraction of acetone = %.4f\"%mafr\n", - "Y = Mfr / ( 1 - Mfr ) \n", - "print \"(c)Molal humidity = %.4f\"%Y,\"moles of acetone/moles of nitrogen\"\n", - "Y1 = Y * Macetone / Mnitrogen \n", - "print \"(d)Absolute humidity = %.4f\"%Y1,\"kg acetone/kg nitrogen\"\n", - "Pas = 26.36 #kPa ( vapour pressure)\n", - "Ys = Pas / ( Ptotal - Pas) #saturation humidity\n", - "print \"(e)Saturation humidity = %.4f\"%Ys,\"moles of acetone/moles of nitrogen\"\n", - "Y1s = Ys * Macetone / Mnitrogen \n", - "print \"(f)Absolute saturation humidity = %.4f\"%Y1s,\"kg acetone/kg nitrogen\"\n", - "V = 100. #m**3\n", - "Vstp =22.4143 #m**3/kmol\n", - "Pstp = 101.3 #kPa\n", - "Tstp = 273.15 #K\n", - "T = 295. #K\n", - "N = V * Ptotal * Tstp / (Vstp * Pstp * T ) \n", - "Nacetone = N * Mfr \n", - "macetone = Nacetone * Macetone \n", - "print \"(g)Mass of acetone in 100m**3 of the total gas = %.1f\"%macetone,\"kg\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)Mole fraction of acetone = 0.1481 \n", - "(b)Weight fraction of acetone = 0.2649\n", - "(c)Molal humidity = 0.1738 moles of acetone/moles of nitrogen\n", - "(d)Absolute humidity = 0.3603 kg acetone/kg nitrogen\n", - "(e)Saturation humidity = 0.3517 moles of acetone/moles of nitrogen\n", - "(f)Absolute saturation humidity = 0.7292 kg acetone/kg nitrogen\n", - "(g)Mass of acetone in 100m**3 of the total gas = 35.5 kg\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.5 pageno : 211" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "Pa = 15. #kPa ( Partial pressure )\n", - "Pas = 26.36 #kPa ( Vapour pressure )\n", - "\n", - "# Calculation \n", - "RS = Pa * 100 / Pas \n", - "Y = 0.1738 \n", - "Ys = 0.3517 \n", - "PS = Y * 100 / Ys \n", - "\n", - "# Result\n", - "print \"Relative humidity = %.1f\"%RS,\"%\"\n", - "print \"Percent humidity = %.2f\"%PS,\"%\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Relative humidity = 56.9 %\n", - "Percent humidity = 49.42 %\n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.6 page no : 211" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math \n", - "\n", - "# Variables \n", - "mwater = 0.0109 #kg\n", - "V = 1. #m**3\n", - "T = 300. #K\n", - "P = 101.3 #kPa\n", - "Vstp =22.4143 #m**3/kmol\n", - "Pstp = 101.3 #kPa\n", - "Tstp = 273.15 #K\n", - "\n", - "# Calculation \n", - "N = V * P * Tstp / (Vstp * Pstp * T ) \n", - "Nwater = mwater / 18.016 \n", - "Nfr = Nwater / N \n", - "Pwater = Nfr * P \n", - "\n", - "# Result\n", - "print \"(a)Partial pressure of water vapour = %.2f\"%Pwater,\"kPa\"\n", - "Ps = math.exp(16.26205 - 3799.887/(T - 46.854)) \n", - "RS = Pwater * 100 / Ps \n", - "print \"(b)Relative saturation = %.2f\"%RS,\"%\"\n", - "Y1 = Pwater *18 / ((P - Pwater)*29) \n", - "print \"(c)Absolute humidity = %.2e\"%Y1,\"kg water / kg dry air\"\n", - "Y1s = Ps *18 / ((P - Ps)*29) \n", - "PS1 = Y1 * 100 / Y1s \n", - "print \"(d)Percent saturation = %.2f\"%PS1,\"%\"\n", - "PS = 10. #%\n", - "Y1S = Y1 * 100/PS \n", - "#Y1S = Pas/(P - Pas ) * 18 /29\n", - "Pas1 = 29 * P * Y1S / (18 + 29*Y1s) \n", - "T1 = 3799.887 / (16.26205-math.log(Pas1)) + 46.854 \n", - "print \"(e)Temperature at which 10%% saturation occurs = %.1f\"%T1,\"K\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)Partial pressure of water vapour = 1.51 kPa\n", - "(b)Relative saturation = 43.17 %\n", - "(c)Absolute humidity = 9.38e-03 kg water / kg dry air\n", - "(d)Percent saturation = 42.31 %\n", - "(e)Temperature at which 10% saturation occurs = 326.9 K\n" - ] - } - ], - "prompt_number": 11 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.7 page no : 213" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "T = 300. #K\n", - "P = 100. #kPa\n", - "S = 25000. #kJ/m**3\n", - "T1= 295. #K\n", - "P1 = 105. #kPa\n", - "RS = 50. #%\n", - "Ps = 3.5 #kPa\n", - "Ps1 = 2.6 #kPa\n", - "Vstp = 22.4143 #m**3/kmol\n", - "Pstp = 101.3 #kPa\n", - "Tstp = 273.15 #K\n", - "V = 1. #m**3\n", - "\n", - "# Calculation \n", - "N = V * P * Tstp/(Vstp * Pstp * T) \n", - "Nfuel = N * (P - Ps)/P \n", - "Smol = S / Nfuel #kJ/kmol\n", - "N1 = V * P1 * Tstp/(Vstp * Pstp * T1) \n", - "Pwater = Ps1 * RS /100 \n", - "Nfuel1 = N1 * (P1 - Pwater )/P1 \n", - "S1 = Smol * Nfuel1 \n", - "\n", - "# Result\n", - "print \"Heating value of gas at 295K and 105kPa = %.f\"%S1,\"kJ/m**3\"\n", - "\n", - "# note : answer may vary because of rounding error.\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Heating value of gas at 295K and 105kPa = 27321 kJ/m**3\n" - ] - } - ], - "prompt_number": 13 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.8 pageno : 215" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math \n", - "# Variables \n", - "T = 300. #K\n", - "T1 = 335. #K\n", - "P = 150. #kPa\n", - "\n", - "# Calculation \n", - "#lnPs = 13.8858 - 2788.51 / ( T - 52.36)\n", - "Ps = math.exp(13.8858 - 2788.51 / ( T - 52.36)) \n", - "Ps1 = math.exp(13.8858 - 2788.51 / ( T1 - 52.36)) \n", - "Pa = Ps #(Vapour pressure at dew point is equal to the partial pressure of the vapour)\n", - "Y = Pa / (P - Pa) \n", - "Ys = Ps1 / (P - Ps1) \n", - "PS = Y * 100 / Ys \n", - "\n", - "# Result \n", - "print \"(a)Percent saturation = %.2f\"%PS,\"%\"\n", - "Ma = 78.048 \n", - "Mb = 28 \n", - "Q = Y * Ma / Mb \n", - "print \"(b)Quantity of benzene per kilgram of nitrogen = %.4f\"%Q,\"kg benzene/kg nitrogen\"\n", - "V = 1. #m**3 ( basis )\n", - "Vstp = 22.4143 #m**3/kmol\n", - "Pstp = 101.3 #kPa\n", - "Tstp = 273.15 #K\n", - "N = V * P * Tstp/(Vstp * Pstp * T1) \n", - "y = Y / ( 1 + Y ) \n", - "Nbenzene = N * y \n", - "C = Nbenzene * Ma \n", - "print \"(c)Kilogram of benzene per m**3 of nitrogen = %.4f\"%C,\"kg/m**3\"\n", - "P1 = 100. #kPa\n", - "Pbenzene = y * P1 \n", - "T1 = 2788.51 / ( 13.8858 - math.log (Pbenzene)) + 52.36 \n", - "print \"(d)Dew point = %.2f\"%T1,\"K\"\n", - "Per1 = 60 #%\n", - "Y2 = Y * (1- Per1/100.) \n", - "#Y2 = Pa / (P - Pa)\n", - "P = Pa / Y2 + Pa \n", - "print \"(e)Pressure required = %.1f\"%P,\"kPa\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)Percent saturation = 17.17 %\n", - "(b)Quantity of benzene per kilgram of nitrogen = 0.2827 kg benzene/kg nitrogen\n", - "(c)Kilogram of benzene per m**3 of nitrogen = 0.3871 kg/m**3\n", - "(d)Dew point = 291.39 K\n", - "(e)Pressure required = 354.3 kPa\n" - ] - } - ], - "prompt_number": 16 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.9 pageno : 216" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "T = 300. #K\n", - "T1 = 285. #K\n", - "Pwater = 3.56 #kPa\n", - "Pwater1 = 1.4 #kPa\n", - "V = 1. #m**3 ( Basis )\n", - "Vstp = 22.4143 #m**3/kmol\n", - "\n", - "# Calculation \n", - "N = V / Vstp \n", - "Pstp = 101.3 #kPa\n", - "Y = Pwater / (Pstp - Pwater) \n", - "Y1 = Pwater1 / (Pstp - Pwater1) \n", - "Nremoved = Y - Y1 \n", - "Ndryair = N * 1 / (1 + Y) \n", - "mremoved = Ndryair * Nremoved * 18.016 \n", - "\n", - "# Result\n", - "print \"(a)amount of water removed = %.4f\"%mremoved,\"kg\"\n", - "Nremaining = Ndryair * Y1 \n", - "V1 = (Ndryair + Nremaining) * Vstp \n", - "print \"(b)Volume of gas at stp after drying = %.4f\"%V1,\"m**3\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)amount of water removed = 0.0174 kg\n", - "(b)Volume of gas at stp after drying = 0.9784 m**3\n" - ] - } - ], - "prompt_number": 18 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.11 page no : 220" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "Td = 328. #K ( dry bulb )\n", - "P = 101.3 #kPa\n", - "PS = 10. #%\n", - "#refering to the psychometric chart, corresponding to 328 K and 10% saturation\n", - "Y1 = 0.012 #kg water / kg dry air\n", - "print \"(a)Absolute humidity = \",Y1,\"kg water / kg dry air\"\n", - "#Y1 = Pa * 18 / ( P - Pa ) * 29\n", - "\n", - "# Calculation \n", - "Pa = Y1 * P * 29 /( 18 + Y1 * 29 ) \n", - "\n", - "# Result\n", - "print \"(b)Partial Pressure of water vapour = %.3f\"%Pa,\"kPa\"\n", - "#using psychometric chart, saturation humidity at 328 K is given as\n", - "Y1s = 0.115 #kg water / kg dry air\n", - "print \"(c)The absolute humidity at 328K = \",Y1s,\"kg water / kg dry air\"\n", - "#at saturation partial pressure = vapour pressure\n", - "Pas = Y1s * P * 29 /( 18 + Y1s * 29 ) \n", - "print \"(d)Vapour Pressure of water vapour = %.1f\"%Pas,\"kPa\"\n", - "RS = Pa * 100 / Pas \n", - "print \"(e)Percent relative saturation = %.2f\"%RS,\"%\"\n", - "#using psychometric chart, moving horizontally keeping humidity constant to 100% saturation, we get dew point as,\n", - "T = 290. #K\n", - "print \"(f)Dew point = \",T,\"K\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)Absolute humidity = 0.012 kg water / kg dry air\n", - "(b)Partial Pressure of water vapour = 1.921 kPa\n", - "(c)The absolute humidity at 328K = 0.115 kg water / kg dry air\n", - "(d)Vapour Pressure of water vapour = 15.8 kPa\n", - "(e)Percent relative saturation = 12.13 %\n", - "(f)Dew point = 290.0 K\n" - ] - } - ], - "prompt_number": 20 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.12 pageno : 222" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "Ca = 1.884 #kJ/kgK\n", - "Cb = 1.005 #kJ/kgK\n", - "Y1 = 0.012 \n", - "\n", - "# Calculation \n", - "#Cs = Cb + Y1 * Ca\n", - "Cs = Cb + Y1 * Ca \n", - "\n", - "# Result\n", - "print \"Humid heat of the sample = %.4f\"%Cs,\"kJ/kgK\"\n", - "P = 101.3 #kPa\n", - "V = 100. #m**3\n", - "R = 8.314 \n", - "T = 328. #K\n", - "T1 = 373. #K\n", - "N = P * V / ( R * T ) \n", - "Pa = 1.921 #kPa\n", - "Ndryair = N * (P - Pa)/P \n", - "mdryair = Ndryair * 29 \n", - "Ht = mdryair * Cs * (T1 - T) \n", - "print \"Heat to be supplied = %.f\"%Ht,\"kJ\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Humid heat of the sample = 1.0276 kJ/kgK\n", - "Heat to be supplied = 4887 kJ\n" - ] - } - ], - "prompt_number": 22 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.14 pageno : 224" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "P = 101.3 #kPa\n", - "MW = 58. \n", - "T1 = 280.8 #K\n", - "Ps = 5. #kPa\n", - "pr = 2. #kJ/kgK ( Psychometric ratio )\n", - "Hvap = 360. #kJ/kg\n", - "Tw = T1 \n", - "\n", - "# Calculation \n", - "Yw1 = Ps * MW / (( P - Ps) * 29) \n", - "# Tw = Tg - Hvap * ( Yw1 - Y1) / (hG / kY), where hG/kY is the psychmetric ratio pr\n", - "Y1 = 0 \n", - "Tg = Tw + Hvap * ( Yw1 - Y1) / pr \n", - "\n", - "# Result\n", - "print \"The air temperature = %.2f\"%Tg,\"K\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The air temperature = 299.49 K\n" - ] - } - ], - "prompt_number": 23 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.15 pageno : 225" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "Td = 353.2 #K\n", - "Tw = 308. #K\n", - "Hvap = 2418.5 #kJ/kg\n", - "pr = 0.950 #kJ/kg\n", - "Ps = 5.62 #kPa\n", - "P = 101.3 #kPa\n", - "\n", - "# Calculation \n", - "Yw1 = (Ps * 18)/ (( P - Ps) * 29) \n", - "Y1 = Yw1 - pr * ( Td - Tw ) / Hvap \n", - "\n", - "# Result\n", - "print \"Humidity = %.4f\"%Y1,\"kg water/kg dry air\"\n", - "#humidity can also be directly obtained from psychometric chart, which we get to be 0.018 kg water/kg dry air\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Humidity = 0.0187 kg water/kg dry air\n" - ] - } - ], - "prompt_number": 24 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.16 page no : 227" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "%pylab inline\n", - "\n", - "import math\n", - "from matplotlib.pyplot import *\n", - "\n", - "# Variables\n", - "TK = [283,293,303,313]\n", - "PaS = []\n", - "Ys = []\n", - "\n", - "# Calculations - part A\n", - "for i in range(len(TK)):\n", - " Ps = 13.8858 - (2788.51 / (TK[i] - 52.36))\n", - " PaS.append(round(math.e**Ps,2))\n", - " Ys.append(PaS[i]/(101.3 - PaS[i]) * 78.048/29)\n", - " \n", - "# Results\n", - "plot(TK,Ys)\n", - "plot(TK,Ys,\"go\")\n", - "xlabel(\"Temperature, K\")\n", - "ylabel(\"Y', kg benzene/ kg dry air\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Populating the interactive namespace from numpy and matplotlib\n" - ] - }, - { - "metadata": {}, - "output_type": "pyout", - "prompt_number": 1, - "text": [ - "<matplotlib.text.Text at 0x3797790>" - ] - }, - { - "metadata": {}, - "output_type": "display_data", - "png": 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- "text": [ - "<matplotlib.figure.Figure at 0x2c0e610>" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.17 pageno : 228" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "Tin = 380.7 #K\n", - "Pin = 101.3 #kPa\n", - "Tdew = 298. #K\n", - "mremoved = 2.25 #kg\n", - "V = 100. #m**3\n", - "#using humidity chart, humidity of air at dry bulb temperature of 380.7K and dew point = 298K is,\n", - "Y = 0.02 # kg water /kg dry air\n", - "print \"(a)Humidity of air entering the drier = \",Y,\"kg water /kg dry air\"\n", - "Tstp = 273.15 #K\n", - "Vstp = 22.4143 #m**3/kmol\n", - "\n", - "# Calculation \n", - "N = V * Tstp / ( Vstp * Tin ) \n", - "MY = Y * 29 / 18. #molal humidity\n", - "Ndryair = N / ( 1 + MY ) \n", - "mdryair = Ndryair *29 \n", - "mwaterin = mdryair * Y \n", - "mwaterout = mwaterin + mremoved \n", - "Yout = mwaterout / mdryair \n", - "# percent humidity is calculated using the chart, and is\n", - "PY = 55. #%\n", - "\n", - "# Result\n", - "print \"(b)exit air humidity = %.3f\"%Yout,\"kg water /kg dry air\"\n", - "print \"Percent humidity = \",PY,\"%\"\n", - "#from the humidity chart \n", - "Twet = 313.2 #K\n", - "Td = 322.2 #K\n", - "print \"(c)exit air wet bulb temperature = \",Twet,\"K\"\n", - "print \"(c)exit air dry bulb temperature = \",Td,\"K\"\n", - "MYout = Yout * 29 / 18 \n", - "Nout = Ndryair * ( 1 + MYout ) / 1 \n", - "V1 = Nout * Vstp * Td / Tstp \n", - "print \"(d)Volume of exit air = %.2f\"%V1,\"m**3\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)Humidity of air entering the drier = 0.02 kg water /kg dry air\n", - "(b)exit air humidity = 0.045 kg water /kg dry air\n", - "Percent humidity = 55.0 %\n", - "(c)exit air wet bulb temperature = 313.2 K\n", - "(c)exit air dry bulb temperature = 322.2 K\n", - "(d)Volume of exit air = 87.94 m**3\n" - ] - } - ], - "prompt_number": 25 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.18 pageno : 231" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "P = 101.3 #kPa\n", - "Td = 303. #K\n", - "Tw = 288. #K\n", - "#using psychometric chart,\n", - "Y1 = 0.0045 #kg water/ kg dry air\n", - "PY = 18. #%\n", - "Theated = 356.7 #K\n", - "Cb = 1.005 \n", - "Ca = 1.884 \n", - "\n", - "# Calculation \n", - "Cs = Cb + Y1 * Ca \n", - "Q = 1 * Cs * (Theated - Td) \n", - "\n", - "# Result\n", - "print \"(a)Humidity of the initial air = %.4f\"%Y1,\"kg water/ kg dry air\"\n", - "print \"(b)Percent humidity = \",PY,\"%\"\n", - "print \"(c)Temperature to which the air is heated = \",Theated,\"K\"\n", - "print \"(d)Heat to be suppplied = %.2f\"%Q,\"kJ\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)Humidity of the initial air = 0.0045 kg water/ kg dry air\n", - "(b)Percent humidity = 18.0 %\n", - "(c)Temperature to which the air is heated = 356.7 K\n", - "(d)Heat to be suppplied = 54.42 kJ\n" - ] - } - ], - "prompt_number": 27 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8.19 pageno : 232" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# variables \n", - "Tw = 313. #K\n", - "Td = 333. #K\n", - "#Using th psychometric chart,\n", - "Y = 0.04 #kg water/ kg dry air\n", - "PS = 26.5 #%\n", - "VS = 1.18 #m**3/kg dry air ( volume of saturated air )\n", - "VD = 0.94 #m**3/kg dry air ( volume of dry air )\n", - "\n", - "# Calculation \n", - "VH = VD + PS * (VS - VD )/100 \n", - "HS = 470. #J / kg dry air ( enthalpy of saturated air )\n", - "HD = 60. #J / kg dry air ( enthalpy of dry air )\n", - "H = HD + PS * ( HS - HD )/100 \n", - "Cs = 1.005 + (Y * 1.884)\n", - "H = Cs*(333 - 273.15) + Y*2502.3\n", - "# Result\n", - "print \"(a)Absolute Humidity of the air = \",Y,\"kg water/ kg dry air\"\n", - "print \"(b)Percent humidity = \",PS,\"%\"\n", - "print \"(c)Humid volume = \",VH,\"m**3/kg dry air\"\n", - "print \"(d)Enthalpy of wet air = \",H,\"kJ/kg dry air\"\n", - "print \"Enthalpy of humid air : %.2f kJ/kg dry air\"%H" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a)Absolute Humidity of the air = 0.04 kg water/ kg dry air\n", - "(b)Percent humidity = 26.5 %\n", - "(c)Humid volume = 1.0036 m**3/kg dry air\n", - "(d)Enthalpy of wet air = 164.751546 kJ/kg dry air\n", - "Enthalpy of humid air : 164.75 kJ/kg dry air\n" - ] - } - ], - "prompt_number": 3 - } - ], - "metadata": {} - } - ] -}
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