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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 2 : Special Purpose Diodes"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.1, Page No. 68"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# maximum current\n",
+      "\n",
+      "import math\n",
+      "#Variable declaration\n",
+      "Pmax=364.0               #dissipation in milliwatt\n",
+      "Vz=9.1                   #in V\n",
+      "\n",
+      "#Calculations\n",
+      "Izmax=Pmax/Vz            #in mA\n",
+      "\n",
+      "#Result\n",
+      "print(\"maximum current the diode can handle is ,(mA)= %.f\"%Izmax)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "maximum current the diode can handle is ,(mA)= 40\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.2, Page No. 68"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# resistance\n",
+      "\n",
+      "import math\n",
+      "#Vaariable declaration\n",
+      "mip=15.0                  #in volt\n",
+      "op=6.8                    #output potential in volt\n",
+      "pd=mip-op                 #potential difference across series resistor\n",
+      "Il=5                      #load current in mA\n",
+      "nmip=20                   #new maximum input voltage in volt\n",
+      "pd1=nmip-op               #new potential difference across series resistor\n",
+      "Il1=20                    #new load current in mA\n",
+      "\n",
+      "#Calculations\n",
+      "R=((pd1-pd)/((Il1-Il)*10**-3))\n",
+      "print(\"value of series resistance is,(ohm)= %.1f\"%R)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "value of series resistance is,(ohm)= 333.3\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2.3, Page No.69"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Current\n",
+      "\n",
+      "import math\n",
+      "#VAriable declaration\n",
+      "V=120.0              #in V\n",
+      "Vz=50.0              #in V\n",
+      "R=5.0                #in ohm\n",
+      "Rl=10.0              #in k-ohm\n",
+      "\n",
+      "#Calculations\n",
+      "vd5=V-Vz             #voltage drop across 5 ohm resistor\n",
+      "I5=vd5/R             #current through 5 ohm resistor\n",
+      "Il=Vz/(Rl*10**3)     #current through load resistor\n",
+      "Iz=I5-Il             #in A\n",
+      "\n",
+      "#Result\n",
+      "print(\"current through zener diode is ,(A)= %.3f\"%Iz)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "current through zener diode is ,(A)= 13.995\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file