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Diffstat (limited to 'Quantum_mechanics_by_M.C.Jain/chapter7.ipynb')
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diff --git a/Quantum_mechanics_by_M.C.Jain/chapter7.ipynb b/Quantum_mechanics_by_M.C.Jain/chapter7.ipynb deleted file mode 100755 index 50969726..00000000 --- a/Quantum_mechanics_by_M.C.Jain/chapter7.ipynb +++ /dev/null @@ -1,238 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:df09a01a18ea5b59bfa81431af3bf540f8785c24b7f1fddb025b95df17f9d0c1"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 7 particle in a potential well"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 7.4 Page no 134"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=9.1*10**-31 #Kg\n",
- "h=1.05*10**-34 #Js\n",
- "ev=1.6*10**-19\n",
- "n1=1\n",
- "n2=2 \n",
- "n3=3\n",
- "a=10**-10 #m\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "E1=((n1**2*math.pi**2*h**2)/(8.0*m*a**2))/(1.6*10**-19) #ev\n",
- "E2=n2**2*E1\n",
- "E3=n3**2*E1\n",
- "\n",
- "#Result \n",
- "print\"three lowest energy levels are \",round(E1,1),\"ev,\", round(E2,1),\"ev and \",round(E3,2),\"ev\"\n",
- "print \"their eigenfunctions are 1/10**-5*cos(pie*x/2*10**-10),1/10**-5*sin(pie*x/10**-10) and 1/10**-5*cos(3*pie*x/2*10**-10)\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "three lowest energy levels are 9.3 ev, 37.4 ev and 84.08 ev\n",
- "their eigenfunctions are 1/10**-5*cos(pie*x/2*10**-10),1/10**-5*sin(pie*x/10**-10) and 1/10**-5*cos(3*pie*x/2*10**-10)\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 7.5 Page no 135"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=10.0*10**-3 #kgram\n",
- "l= 10.0*10**-2 #Length in m\n",
- "h=1.054*10**-34\n",
- "n1=1\n",
- "n2=2 \n",
- "n3=3\n",
- "\n",
- "#Calculation\n",
- "E1=(((3.14*h*n1)**2)/(2.0*m*(l**2)))/(1.6*10**-19)\n",
- "E2=(((3.14*h*n2)**2)/(2.0*m*(l**2)))/(1.6*10**-19)\n",
- "E3=(((3.14*h*n3)**2)/(2.0*m*(l**2)))/(1.6*10**-19)\n",
- "\n",
- "#Result\n",
- "print\"energies are \", round(E1,46),\"ev,\",round(E2,46),\"ev,\",round(E3,45),\"ev\"\n",
- "print\"these energies are extremely small and close together and hence can't be measured\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "energies are 3.4e-45 ev, 1.37e-44 ev, 3.1e-44 ev\n",
- "these energies are extremely small and close together and hence can't be measured\n"
- ]
- }
- ],
- "prompt_number": 84
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 7.7 Page no 136"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=10**-9 #Width in m\n",
- "v=9.0*10**-9\n",
- "h=1.054*10**-34 #Js\n",
- "c=3*10**8 #m/s\n",
- "m=9.1*10**-31\n",
- "v1=(9.0+1)*10**-9\n",
- "v2=(9.0-1)*10**-9\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "n=math.sqrt((4*c*m*(L**2))/(v*math.pi*h))\n",
- "n1=math.sqrt((4*c*m*(L**2))/(v1*math.pi*h))\n",
- "n2=math.sqrt((4*c*m*(L**2))/(v2*math.pi*h))\n",
- "\n",
- "#Result\n",
- "print\"value of n is \",round(n,0),\", When + sign is taken \",round(n2,0),\", when -ve sign is taken \",round(n1,0)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "value of n is 19.0 , When + sign is taken 20.0 , when -ve sign is taken 18.0\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 7.8 Page no 136"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L1=0.4\n",
- "L2=0.6\n",
- "L=1 #Say\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "dx=(L2-L1)*L\n",
- "#for ground state\n",
- "P1=2/L*(math.sin(math.pi*L/2.0*L))**2*dx\n",
- "#for first excited state\n",
- "P2=2/L*(math.sin(2*math.pi*L/2.0*L))**2*dx\n",
- "#for second excited state\n",
- "P3=2/L*(math.sin(3*math.pi*L/2.0*L))**2*dx\n",
- "\n",
- "#Result\n",
- "print\"(a) probability for ground state \", P1\n",
- "print\"(b) probability for first excited state \",round(P2,1)\n",
- "print\"(c) Probability for second excited state \", P3"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) probability for ground state 0.4\n",
- "(b) probability for first excited state 0.0\n",
- "(c) Probability for second excited state 0.4\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 7.9 Page no 140"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=10.0**-14 #m\n",
- "m=1.6*10**-27 #mass of a nucleon in kg\n",
- "h=1.054*10**-34 #Js\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Emin=((3*(math.pi**2)*(h**2))/(2.0*m*(a**2)))/(1.6*10**-19)\n",
- "\n",
- "#Result\n",
- "print\"minimum energy of a nucleon is \", round(Emin*10**-6,1),\"Mev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "minimum energy of a nucleon is 6.4 Mev\n"
- ]
- }
- ],
- "prompt_number": 17
- }
- ],
- "metadata": {}
- }
- ]
-}
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