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diff --git a/Quantitative_Aptitude_for_Competitive_Examinations/Chapter9.ipynb b/Quantitative_Aptitude_for_Competitive_Examinations/Chapter9.ipynb new file mode 100755 index 00000000..b7d05043 --- /dev/null +++ b/Quantitative_Aptitude_for_Competitive_Examinations/Chapter9.ipynb @@ -0,0 +1,1115 @@ +{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# 9: Mixtures"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.1, Page number 9.4"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "proportion to be mixed is 4\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "c1=9.5; #cost of oil per kg(Rs)\n",
+ "c2=10; #cost of another oil(Rs)\n",
+ "Cm=9.6; #cost of mixture(Rs)\n",
+ "\n",
+ "#Calculation\n",
+ "q1byq2=(c2-Cm)/(Cm-c1); #proportion to be mixed\n",
+ "\n",
+ "#Result\n",
+ "print \"proportion to be mixed is\",int(q1byq2)"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.2, Page number 9.4"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "proportion to be mixed is 0.666666666667\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "c1=25; #percentage of alcohol(%)\n",
+ "c2=50; #percentage of alcohol(%)\n",
+ "Cm=40; #alcohol strength(%)\n",
+ "\n",
+ "#Calculation\n",
+ "q1byq2=(c2-Cm)/(Cm-c1); #proportion to be mixed\n",
+ "\n",
+ "#Result\n",
+ "print \"proportion to be mixed is\",q1byq2"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.3, Page number 9.5"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 6,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "quantity of money lent at 8% is 400.0 Rs\n",
+ "quantity of money lent at 10% is 600.0 Rs\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "c1=8; #first part(%)\n",
+ "c2=10; #second part(%)\n",
+ "Cm=9.2; #yearly average(%)\n",
+ "A=1000; #amount(Rs)\n",
+ "\n",
+ "#Calculation\n",
+ "q1=c2-Cm;\n",
+ "q2=Cm-c1; \n",
+ "A1=q1*A/(q1+q2); #quantity of money lent at 8%(Rs)\n",
+ "A2=q2*A/(q1+q2); #quantity of money lent at 10%(Rs)\n",
+ "\n",
+ "#Result\n",
+ "print \"quantity of money lent at 8% is\",A1,\"Rs\"\n",
+ "print \"quantity of money lent at 10% is\",A2,\"Rs\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.4, Page number 9.5"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 13,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "amount of water to be added is 5.0 litres\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "c1=0; #pure milk(litres)\n",
+ "c2=3.6; #cost of pure milk(Rs)\n",
+ "Cm=3; #cost of mixture(Rs)\n",
+ "\n",
+ "#Calculation\n",
+ "q1byq2=(Cm-c1)/(c2-Cm); #amount of water to be added(litres)\n",
+ "\n",
+ "#Result\n",
+ "print \"amount of water to be added is\",q1byq2,\"litres\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.5, Page number 9.5"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 14,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "amount of salt is 20.0 kg\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "c1=24; #cost of salt(paise)\n",
+ "c2=42; #cost of salt(paise)\n",
+ "c=40; #cost of mixture(paise)\n",
+ "e=25; #efficiency(%) \n",
+ "\n",
+ "#Calculation\n",
+ "Cm=c*100/(100+e); #cost price of mixture(paise)\n",
+ "q1byq2=(Cm-c1)/(c2-Cm); #proportion to be mixed\n",
+ "q=q1byq2*e; #amount of salt(kg)\n",
+ "\n",
+ "#Result\n",
+ "print \"amount of salt is\",q,\"kg\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.6, Page number 9.5"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 15,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "strength of alcohol is 16.6666666667 %\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "a=5; #amount of alcohol solution(litres)\n",
+ "p=20/100; #percentage of solution\n",
+ "\n",
+ "#Calculation\n",
+ "A=p*a; #amount of alcohol(litre)\n",
+ "S=A*100/(A+a); #strength of alcohol(%)\n",
+ "\n",
+ "#Result\n",
+ "print \"strength of alcohol is\",S,\"%\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.7, Page number 9.6"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 16,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "amount of water to be added is 5.0 litres\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "p1=90/100; #percentage of milk in mixture(%)\n",
+ "p2=10/100; #percentage of water in mixture(%)\n",
+ "a=40; #amount of mixture(litres)\n",
+ "p_2=20; #new percent of water(%)\n",
+ "\n",
+ "#Calculation\n",
+ "A=(p1*a*p_2/(100-p_2))-(p2*a); #amount of water to be added(litres)\n",
+ "\n",
+ "#Result\n",
+ "print \"amount of water to be added is\",A,\"litres\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.8, Page number 9.6"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 17,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "amount of pure milk is 25.0 litres\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "c1=0; \n",
+ "c2=3.0; #cost of pure milk(Rs)\n",
+ "e=20/100; #efficiency(%) \n",
+ "\n",
+ "#Calculation\n",
+ "Cm=c2/(1+e); #CP of mixture(Rs)\n",
+ "q1byq2=(Cm-c1)/(c2-Cm); #proportion to be mixed\n",
+ "A=q1byq2**2; #amount of pure milk(litres)\n",
+ "\n",
+ "#Result\n",
+ "print \"amount of pure milk is\",A,\"litres\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.9, Page number 9.6"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 18,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "selling price of mixture is Rs 7.04 per kg\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "a1=6; #amount of tea(kg)\n",
+ "p1=6; #cost of tea(Rs)\n",
+ "a2=4; #amount of tea(kg)\n",
+ "p2=7; #cost of tea(Rs)\n",
+ "p=10/100; #profit(p)\n",
+ "\n",
+ "#Calculation\n",
+ "cp=((a1*p1)+(a2*p2))/(a1+a2); #cost price of mixture(Rs)\n",
+ "sp=(1+p)*cp; #selling price of mixture(Rs)\n",
+ "\n",
+ "#Result\n",
+ "print \"selling price of mixture is Rs\",sp,\"per kg\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.10, Page number 9.6"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 19,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "strength of acid in mixture is 60.0 %\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "p1=20; #percentage of sulphuric acid(%)\n",
+ "q1=5; #amount of acid(litres)\n",
+ "p2=100; #percentage of pure sulphuric acid(%)\n",
+ "q2=5; #amount of acid(litres)\n",
+ "\n",
+ "#Calculation\n",
+ "s=((p1*q1)+(p2*q2))/(q1+q2); #strength of acid in mixture(%)\n",
+ "\n",
+ "#Result\n",
+ "print \"strength of acid in mixture is\",s,\"%\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.11, Page number 9.6"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 20,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "cost price of 1st liquid is Rs 10.8 per litre\n",
+ "cost price of 2nd liquid is Rs 8.8 per litre\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "q1=3\n",
+ "q2=2; \n",
+ "c=11; #cost at which mixture is sold(Rs)\n",
+ "p=10/100; #profit(%)\n",
+ "\n",
+ "#Calculation\n",
+ "Cm=c/(1+p); #cost price of mixture(Rs)\n",
+ "x=((q2*Cm)+(q1*Cm)+(q2*q2))/(q1+q2); #cost price of 1st liquid(Rs)\n",
+ "x2=x-q2; #cost price of 2nd liquid(Rs)\n",
+ "\n",
+ "#Result\n",
+ "print \"cost price of 1st liquid is Rs\",x,\"per litre\"\n",
+ "print \"cost price of 2nd liquid is Rs\",x2,\"per litre\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.12, Page number 9.7"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 23,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "alcohol and water are in the proportion of 1.4\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "a=2;\n",
+ "b=1; #proportion of 1st mixture of alcohol and water\n",
+ "x=1;\n",
+ "y=1; #proportion of 2nd mixture of alcohol and water\n",
+ "\n",
+ "#Calculation\n",
+ "q1=(a/(a+b))+(x/(x+y)); #quantity of alcohol in 3rd glass\n",
+ "q2=(b/(a+b))+(y/(x+y)); #quantity of water in 3rd glass\n",
+ "\n",
+ "#Result\n",
+ "print \"alcohol and water are in the proportion of\",q1/q2 "
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.13, Page number 9.7"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 24,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "gain made on sale of 5 quintals is Rs 110.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "c1=2.10; #cost price of coffee(Rs)\n",
+ "q1=15; #quantity of coffee(parts)\n",
+ "c2=0.98; #cost price of chicory(Rs)\n",
+ "q2=1; #quantity of chicory(part)\n",
+ "s=2.25; #selling price per kg(Rs)\n",
+ "a=500; #amount(kg)\n",
+ "\n",
+ "#Calculation\n",
+ "Cm=((c1*q1)+(c2*q2))/(q1+q2); #cost price of mixture(Rs)\n",
+ "p=(s-Cm)*a; #gain made on sale of 5 quintals(Rs)\n",
+ "\n",
+ "#Result\n",
+ "print \"gain made on sale of 5 quintals is Rs\",p"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.14, Page number 9.8"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 25,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "percentage of alcohol is 28.0 %\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "qa=35; #percentage of alcohol by weight\n",
+ "qw=25; #weight of water(gms)\n",
+ "m=100; #total mixture(g)\n",
+ "\n",
+ "#Calculation\n",
+ "p=qa*100/(m+qw); #percentage of alcohol(%)\n",
+ "\n",
+ "#Result\n",
+ "print \"percentage of alcohol is\",p,\"%\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.15, Page number 9.8"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 28,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "quantity of the butt stolen is 0.57\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "Cm=24; #strength of butt(%)\n",
+ "c1=18; #percentage of spirit(%)\n",
+ "c2=32; #percentage of spirit(%)\n",
+ "\n",
+ "#Calculation\n",
+ "q1=Cm-c1; #quantity of 32% spirit\n",
+ "q2=c2-Cm; #quantity of 18% spirit\n",
+ "f=q2/(q1+q2); #quantity of the butt stolen\n",
+ "\n",
+ "#Result\n",
+ "print \"quantity of the butt stolen is\",round(f,2)"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.16, Page number 9.8"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 29,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "quantity of water added is 22.0 litres\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "m=66; #mixture of milk(litres)\n",
+ "a=5;\n",
+ "b=1; #ratio of milk and water\n",
+ "x=5;\n",
+ "y=3; #new ratio \n",
+ "\n",
+ "#Calculation\n",
+ "x1=a*m*y/(a+b);\n",
+ "x2=a*m/(x+b);\n",
+ "x=(x1-x2)/a; #quantity of water added(litres)\n",
+ "\n",
+ "#Result\n",
+ "print \"quantity of water added is\",x,\"litres\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.17, Page number 9.8"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 30,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "amount of dry fruit obtained is 35.0 kg\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "qw1=72/100; #content of water in fresh fruit(%)\n",
+ "a=100; #amount of fresh fruit(kg)\n",
+ "qw2=20/100; #content of water in dry fruit(%)\n",
+ "\n",
+ "#Calculation\n",
+ "x=(1-qw1)*a/(1-qw2); #amount of dry fruit obtained(kg)\n",
+ "\n",
+ "#Result\n",
+ "print \"amount of dry fruit obtained is\",x,\"kg\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.18, Page number 9.8"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 31,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "quantity of fresh water to be added is 40.0 kg\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "qs=5/100; #content of salt by water(%)\n",
+ "a=60; #amount of sea water(kg)\n",
+ "q=3; #content of salt in solution(%)\n",
+ "\n",
+ "#Calculation\n",
+ "x=((qs*a*100)-(q*a))/q; #quantity of fresh water to be added(kg)\n",
+ "\n",
+ "#Result\n",
+ "print \"quantity of fresh water to be added is\",x,\"kg\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.19, Page number 9.9"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 32,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "amount of first alloy is 7.0 kg\n",
+ "amount of second alloy is 21.0 kg\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "qa=1; #copper in 1st alloy\n",
+ "qb=1; #copper in 2nd alloy\n",
+ "x=3;\n",
+ "y=4; #ratio of copper to zinc\n",
+ "a=5;\n",
+ "b=2; #ration of copper to zinc in new alloy\n",
+ "q=28; #quantity of new alloy(kg) \n",
+ "\n",
+ "#Calculation\n",
+ "Cm=qa/(qa+qb); #copper in new alloy\n",
+ "c1=x/(x+y); #copper in 2nd alloy\n",
+ "c2=a/(a+b); #copper in 1st alloy\n",
+ "q1=(Cm-c1);\n",
+ "q2=(c2-Cm);\n",
+ "a1=q1*q/(q1+q2); #amount of 1st alloy(kg)\n",
+ "a2=q-a1; #amount of second alloy(kg)\n",
+ "\n",
+ "#Result\n",
+ "print \"amount of first alloy is\",a1,\"kg\"\n",
+ "print \"amount of second alloy is\",a2,\"kg\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.20, Page number 9.9"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 33,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "weight of new alloy is 35.0 kg\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "a1=4;\n",
+ "b1=1; #relation of copper and zinc\n",
+ "a2=1;\n",
+ "b2=3; #relation of copper and zinc\n",
+ "a3=3;\n",
+ "b3=2; #ratio of copper to zinc \n",
+ "q1=10; #amount of 1st alloy(kg)\n",
+ "q2=16; #amount of 2nd alloy(kg)\n",
+ "\n",
+ "#Calculation\n",
+ "c1=a1*q1/(a1+b1); #copper in 1st alloy\n",
+ "c2=a2*q2/(a2+b2); #copper in 2nd alloy\n",
+ "x=(a3*(q1+q2))-((a3+b3)*(c1+c2)); \n",
+ "w=(x/2)+q1+q2; #weight of new alloy(kg)\n",
+ "\n",
+ "#Result\n",
+ "print \"weight of new alloy is\",w,\"kg\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.21, Page number 9.10"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 34,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "number of boys is 33.0\n",
+ "number of girls is 12.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "a=39; #amount(Rs)\n",
+ "s=45; #number of boys and girls\n",
+ "c1=50/100; #amount girl gets(Rs)\n",
+ "c2=1; #amount boy gets(Rs)\n",
+ "\n",
+ "#Calculation\n",
+ "Cm=a/s;\n",
+ "qb=(Cm-c1); #number of boys in ratio\n",
+ "qg=(c2-Cm); #number of girls in ratio\n",
+ "b=qb*s/(qb+qg); #number of boys\n",
+ "g=s-b; #number of girls\n",
+ "\n",
+ "#Result\n",
+ "print \"number of boys is\",b\n",
+ "print \"number of girls is\",g"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.22, Page number 9.10"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 35,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "quantity of mixture released is 2.0 litres\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "co=9/100; #content of oxygen\n",
+ "vo=16/100; #volume of oxygen\n",
+ "q=8; #quantity of cylinder(litre)\n",
+ "\n",
+ "#Calculation\n",
+ "r=math.sqrt(co*q/(vo*q));\n",
+ "R=q*(1-r); #quantity of mixture released(litres)\n",
+ "\n",
+ "#Result\n",
+ "print \"quantity of mixture released is\",R,\"litres\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.23, Page number 9.10"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 36,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "amount of milk left is 72.9 kg\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "x0=100; #original amount of milk(kg)\n",
+ "xr=10; #amount of milk removed(kg)\n",
+ "n=3; #number of operations\n",
+ "\n",
+ "#Calculation\n",
+ "a=x0*(1-(xr/x0))**n; #amount of milk left(kg)\n",
+ "\n",
+ "#Result\n",
+ "print \"amount of milk left is\",a,\"kg\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.24, Page number 9.11"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 44,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "ratio of dettol and water is 0.25\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "x0=1; #quantity of dettol(litre)\n",
+ "xr=1/3; #quantity of dettol removed(litre)\n",
+ "n=4; #number of operations\n",
+ "\n",
+ "#Calculation\n",
+ "Aa=(1-(xr/x0))**n; #amount of dettol left(litre)\n",
+ "Ba=1-Aa; #amount of water left(litre)\n",
+ "r=Aa/Ba; #ratio of dettol and water \n",
+ "\n",
+ "#Result\n",
+ "print \"ratio of dettol and water is\",round(r,2)"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.25, Page number 9.12"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 40,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "part of the mixture taken out is 0.2\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "a1=5; #parts of after shave lotion\n",
+ "b1=3; #parts of water\n",
+ "Al=1/2; #amount of after shave lotion\n",
+ "\n",
+ "#Calculation\n",
+ "Ap=a1/(a1+b1); #amount of after shave lotion present\n",
+ "R=1-(Al/Ap); #part of the mixture taken out\n",
+ "\n",
+ "#Result\n",
+ "print \"part of the mixture taken out is\",R"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example number 9.26, Page number 9.12"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 41,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "three kinds of rice are mixed in the ratio 11.0 : 77.0 : 7.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "c1=12; #cost price of 1st variety(Rs)\n",
+ "c2=14.40; #cost price of 2nd variety(Rs)\n",
+ "c3=17.40; #cost price of 3rd variety(Rs)\n",
+ "Cm=14.10; #cost price of mixture(Rs)\n",
+ "f=11.11; #factor to be rounded off\n",
+ "\n",
+ "#Calculation\n",
+ "q1=(c2-Cm)*(c3-Cm)*f; #quantity of 1st variety(kg)\n",
+ "q2=(Cm-c1)*(c3-Cm)*f; #quantity of 2nd variety(kg)\n",
+ "q3=(c2-Cm)*(Cm-c1)*f; #quantity of 3rd variety(kg)\n",
+ "\n",
+ "\n",
+ "#Result\n",
+ "print \"three kinds of rice are mixed in the ratio\",round(q1),\":\",round(q2),\":\",round(q3)"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
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