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diff --git a/Principles_of_physics/Chapter12.ipynb b/Principles_of_physics/Chapter12.ipynb new file mode 100755 index 00000000..d7cd7474 --- /dev/null +++ b/Principles_of_physics/Chapter12.ipynb @@ -0,0 +1,540 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:1f479e444a408fcb9cb7e4430e1c4545dad453af571a814f51ef48ce1d81ede8"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 12 Direct current circut"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.1 page no 192"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(6,6.0,12) #Resistances from circuit diagram 12.34 on page no.192 in ohms\n",
+ "V=(5,2) #Voltage in V from circuit diagram 12.20 on page no.192\n",
+ "\n",
+ "#Calculations\n",
+ "Re=(R[2]*R[1])/(R[2]+R[1])\n",
+ "Re2=Re+R[1]\n",
+ "I=V[0]/Re2\n",
+ "Ve=I*Re\n",
+ "I1=Ve/R[2]\n",
+ "RE=(R[0]*R[1])/(R[0]+R[1])\n",
+ "RE2=RE+R[2]\n",
+ "I2=Ve/RE2\n",
+ "Itotal=I1-I2\n",
+ "\n",
+ "#Output\n",
+ "print\"The current is \",round(Itotal,2),\"A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The current is 0.03 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.2 page no 193"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(3,5,6,7) #Resistances from circuit diagram 12.36(a) on page no. 193 in ohms\n",
+ "V=12 #Voltage in V from circuit diagram 12.36(a) on page no. 193\n",
+ "\n",
+ "#Calculations\n",
+ "Vth=(V*R[2])/(R[2]+R[3]+R[1])\n",
+ "Rth=R[0]+(V*R[2])/(V+R[2])\n",
+ "\n",
+ "#Output\n",
+ "print\"Thevenin equivalent resistance is \",Rth,\"ohms\" \n",
+ "print\"Thevenin equivalent voltage is \",Vth,\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Thevenin equivalent resistance is 7 ohms\n",
+ "Thevenin equivalent voltage is 4 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.3 page no 193"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(2,3,4.0) #Resistances from circuit diagram 12.37(a) on page no.194 in ohms\n",
+ "V=5 #Voltage in V from circuit diagram 12.37(a) on page no.194\n",
+ "\n",
+ "#Calculations\n",
+ "RN=(V*R[2])/(V+R[2])\n",
+ "IN=V/(R[0]+R[1])\n",
+ "\n",
+ "#Output\n",
+ "print\"Nortons equivalent resistance is \",round(RN,1),\"ohms\"\n",
+ "print\"Nortons equivalent current is \",IN,\"A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Nortons equivalent resistance is 2.2 ohms\n",
+ "Nortons equivalent current is 1 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.4 page no 194 "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "C=10*10**-6 #Capicitance in F\n",
+ "R=10.0*10.0**3 #Resistance in ohms\n",
+ "e=6 #Emf of the battery in V\n",
+ "\n",
+ "#Calculations\n",
+ "t=C*R\n",
+ "Qm=(C*e)/10.0**-6\n",
+ "Im=(e/R)*1000\n",
+ "\n",
+ "#Output\n",
+ "print\"Time constant of the circuit is \",t,\"s\" \n",
+ "print\"Maximum charge on the capacitor is \",Qm,\"micro C\" \n",
+ "print\"Maximum current in the circuit is \",Im,\"mA\" \n",
+ "print\"Charge at time t is Q(t) = \",Qm,\"micro C\"\n",
+ "print\"Currrent at time t is I(t) = \",Im,\"mA\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Time constant of the circuit is 0.1 s\n",
+ "Maximum charge on the capacitor is 60.0 micro C\n",
+ "Maximum current in the circuit is 0.6 mA\n",
+ "Charge at time t is Q(t) = 60.0 micro C\n",
+ "Currrent at time t is I(t) = 0.6 mA\n"
+ ]
+ }
+ ],
+ "prompt_number": 18
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.5 page no 194"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "L=50 #Inductance in mH\n",
+ "R=5.0 #Resistance in ohms\n",
+ "V=6 #Volatage of the battery in V\n",
+ "t=5 #Time in ms\n",
+ "\n",
+ "#Calculations\n",
+ "import math\n",
+ "t1=(L/R)\n",
+ "I=(V/R)*(1-math.exp(-t/t1))\n",
+ "\n",
+ "#Output\n",
+ "print\"The time constant of the circuit is \",t1,\"ms\" \n",
+ "print\"The current in the circuit is \",round(I,2),\"A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The time constant of the circuit is 10.0 ms\n",
+ "The current in the circuit is 0.47 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 20
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.6 page no 194"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "L=6 #Inductance in mH\n",
+ "C=12 #Capacitance in pF\n",
+ "V=6 #Voltage of the battery in V\n",
+ "\n",
+ "#Calculations\n",
+ "import math\n",
+ "f=(1/(2.0*3.14*math.sqrt(L*10**-3*C*10**-12)))/10**5\n",
+ "Qm=(C*10**-12*V)/10.0**-12\n",
+ "Im=(2*3.14*f*10**5*Qm*10**-12)/10.0**-6\n",
+ "\n",
+ "#Output\n",
+ "print\"Frequency of oscillation is \",round(f,2),\"*10^5 Hz\" \n",
+ "print\"The maximum value of charge on capacitor is \",Qm,\"*10**-12 C\" \n",
+ "print\"The current in the circuit is \",round(Im,0),\"micro A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Frequency of oscillation is 5.93 *10^5 Hz\n",
+ "The maximum value of charge on capacitor is 72.0 *10**-12 C\n",
+ "The current in the circuit is 268.0 micro A\n"
+ ]
+ }
+ ],
+ "prompt_number": 23
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.e.1 Page no 175"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "V=10 #voltage in V from fig.12.7 on page no.175\n",
+ "R=10.0 #Resistance in ohms from fig.12.7 on page no.175\n",
+ "\n",
+ "#Calculations\n",
+ "I=(V/R)\n",
+ "\n",
+ "#Output\n",
+ "print\"Current in the circuit shown in fig.12.7 is \",I,\"A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Current in the circuit shown in fig.12.7 is 1.0 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 24
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.e.2 Page no 175"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(6,6,3.0) #Resistances in the circuit from circuit diagram 12.9 on page no. 175 in ohms\n",
+ "V=(24,16) #Voltages in the circuit from circuit diagram 12.9 on page no. 175 in V\n",
+ "\n",
+ "#Calculations\n",
+ "Re=(R[1]*R[2])/(R[1]+R[2])\n",
+ "Re1=Re+R[0]\n",
+ "I=V[0]/Re1\n",
+ "Ve=I*Re\n",
+ "Ie=Ve/R[2]\n",
+ "RE=(R[0]*R[1])/(R[0]+R[1])\n",
+ "RE1=RE+R[2]\n",
+ "I1=V[1]/RE1\n",
+ "VE=R[2]*I1\n",
+ "I2=VE/R[0]\n",
+ "Itotal=Ie+I2\n",
+ "#Output\n",
+ "print\"The current shown in the circiut is \",round(Itotal,1),\"A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The current shown in the circiut is 3.3 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 23
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.e.3 Page no 177"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(4,12,2.0,12) #Resistances from circuit diagram 12.12 on page no. 177 in ohms\n",
+ "V=12 #Voltage in V from circuit diagram 12.12 on page no. 177\n",
+ "\n",
+ "#Calculations\n",
+ "Rth=((R[0]+R[2])*R[1])/(R[0]+R[2]+R[1])\n",
+ "Vth=(V*R[1])/(R[0]+R[2]+R[1])\n",
+ "I=(Vth/(Rth+R[3]))\n",
+ "\n",
+ "#Output\n",
+ "print\"The current through the resistor is \",I,\"A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The current through the resistor is 0.5 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 24
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.e.4 Page no 178"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(2,3,6) #Resistances from circuit diagram 12.15 on page no. 178 in ohms\n",
+ "I=2 #Current in A from circuit diagram 12.15 on page no. 178\n",
+ "\n",
+ "#Calculations\n",
+ "Rth=(R[1]+R[2])\n",
+ "Vth=(R[2]*I)\n",
+ "\n",
+ "#Output\n",
+ "print\"Thevenin equivalent resistance is \",Rth,\"ohms\" \n",
+ "print\"Thevenin equivalent voltage is \",Vth,\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Thevenin equivalent resistance is 9 ohms\n",
+ "Thevenin equivalent voltage is 12 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 26
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.e.5 Page no 178"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(12,8.0,3.0,6) #Resistances from circuit diagram 12.17 on page no.179 in ohms\n",
+ "V=12 #Voltage in V from circuit diagram 12.17 on page no.179\n",
+ "\n",
+ "#Calculations\n",
+ "Rth=((R[2]*R[0])/(R[2]+R[0]))+((R[1]*R[3])/(R[1]+R[3]))\n",
+ "Vth=V*((R[1]*R[3])/(R[1]+R[3]))/(R[0]+R[2])\n",
+ "\n",
+ "#Output\n",
+ "print\"Thevenin equivalent resistance is \",round(Rth,2),\"ohms\" \n",
+ "print\"Thevenin equivalent voltage is \",round(Vth,2),\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Thevenin equivalent resistance is 5.83 ohms\n",
+ "Thevenin equivalent voltage is 2.74 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.e.6 Page no 180"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(4,12,2,12) #Resistances from circuit diagram 12.20 on page no.180 in ohms\n",
+ "V=12 #Voltage in V from circuit diagram 12.20 on page no.180\n",
+ "\n",
+ "#Calculations\n",
+ "RN=((R[0]+R[2])*R[1])/(R[0]+R[2]+R[1])\n",
+ "IN=V/(RN+R[2])\n",
+ "\n",
+ "#Output\n",
+ "print\"Nortons equivalent resistance is \",RN,\"ohms\"\n",
+ "print\"Nortons equivalent current is \",IN,\"A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Nortons equivalent resistance is 4 ohms\n",
+ "Nortons equivalent current is 2 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 32
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.e.7 Page no 181"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "R=(4.0,5,6) #Resistances from circuit diagram 12.22 on page no.181 in ohms\n",
+ "I=2 #Current in A from circuit diagram 12.22 on page no.181\n",
+ "\n",
+ "#Calculations\n",
+ "RN=(R[0]+R[1]+R[2])\n",
+ "IN=(R[0]*I)/RN\n",
+ "\n",
+ "#Output\n",
+ "print\"Nortons equivalent resistance is \",RN,\"ohms\"\n",
+ "print\"Nortons equivalent current is \",round(IN,2),\"A\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Nortons equivalent resistance is 15.0 ohms\n",
+ "Nortons equivalent current is 0.53 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 35
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |