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Diffstat (limited to 'Physical_Chemsitry/Chapter15.ipynb')
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diff --git a/Physical_Chemsitry/Chapter15.ipynb b/Physical_Chemsitry/Chapter15.ipynb new file mode 100755 index 00000000..8ce44ac5 --- /dev/null +++ b/Physical_Chemsitry/Chapter15.ipynb @@ -0,0 +1,322 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:633d2351722f70bcb5591bec1c39746dd272ca892962c335e9bfb247bc80518a"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 15 - Electrochemistry"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 1 - pg 384"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the Weight of copper leaving\n",
+ "#Initialization of variables\n",
+ "I=0.5 #amp\n",
+ "t=55 #min\n",
+ "we=31.77\n",
+ "#calculations\n",
+ "Q=I*t*60\n",
+ "n=Q/96496.\n",
+ "w=n*we\n",
+ "#results\n",
+ "print '%s %.3f %s' %(\"Weight of copper leaving =\",w,\" g\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Weight of copper leaving = 0.543 g\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2 - pg 386"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the values of tplus and tminus\n",
+ "#Initialization of variables\n",
+ "w1=0.7532 #g\n",
+ "w2=0.9972 #g\n",
+ "wdep=0.4 #g\n",
+ "we=31.77 #g\n",
+ "#calculations\n",
+ "dn=w2/we - w1/we\n",
+ "t=dn/(wdep/we)\n",
+ "dne=wdep/we\n",
+ "dnmig=dn-dne\n",
+ "tplus=-dnmig/dne\n",
+ "tminus=1-tplus\n",
+ "#results\n",
+ "print '%s %.3f' %(\"tplus =\",tplus)\n",
+ "print '%s %.3f' %(\"\\n tminus=\",tminus)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "tplus = 0.390\n",
+ "\n",
+ " tminus= 0.610\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3 - pg 393"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the Equivalent conductance\n",
+ "#Initialization of variables\n",
+ "R1=312 #ohms\n",
+ "R2=1043 #ohms\n",
+ "c=0.01 #N\n",
+ "kdash=0.002768 #ohm^-1cm^-1\n",
+ "#calculations\n",
+ "k=kdash*R1\n",
+ "kdash2=k/R2\n",
+ "ambda=kdash2/(c/1000.)\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Equivalent conductance =\",ambda,\"ohm^-1 cm^2 equiv^-1\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Equivalent conductance = 82.8 ohm^-1 cm^2 equiv^-1\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4 - pg 393"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the Conductance for acetic acid\n",
+ "#Initialization of variables\n",
+ "l1=349.8 \n",
+ "l2=40.9\n",
+ "#calculations\n",
+ "l=l1+l2\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Conductance for acetic acid =\",l,\" ohm^-1 cm^2\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Conductance for acetic acid = 390.7 ohm^-1 cm^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5 - pg 395"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the Specific conductanc\n",
+ "#Initialization of variables\n",
+ "l1=63.6\n",
+ "l2=79.8\n",
+ "n=1 #mg/lt\n",
+ "we=116.7 #g/equiv\n",
+ "#calculations\n",
+ "l=l1+l2\n",
+ "c=n*10**-3 /we\n",
+ "k=c*l/1000.\n",
+ "#results\n",
+ "print '%s %.2e %s' %(\"Specific conductance =\",k,\" ohm^-1 cm^-1\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Specific conductance = 1.23e-06 ohm^-1 cm^-1\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6 - pg 402"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the SEP of the cell\n",
+ "#Initialization of variables\n",
+ "e1=0.763 #volt\n",
+ "e2=0.337 #volt\n",
+ "#calculations\n",
+ "e0=e1+e2\n",
+ "#results\n",
+ "print '%s %.3f %s' %(\"Standard electrode potential of the cell =\",e0,\"volts\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Standard electrode potential of the cell = 1.100 volts\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 7 - pg 403"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the Emf of the cell\n",
+ "#Initialization of variables\n",
+ "import math\n",
+ "aZn=0.1\n",
+ "aCu=0.01\n",
+ "e1=0.763 #volt\n",
+ "e2=0.337 #volt\n",
+ "#calculations\n",
+ "e0=e1+e2\n",
+ "Q=aZn/aCu\n",
+ "E=e0- 0.05915*math.log10(Q) /2\n",
+ "#results\n",
+ "print '%s %.3f %s' %(\"Emf of the cell =\",E,\" volts\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Emf of the cell = 1.070 volts\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8 - pg 410"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the Decomposition potential\n",
+ "#Initialization of variables\n",
+ "e1=1.2 #volts\n",
+ "e2=0.15 #volts\n",
+ "e3=0.45 #volts\n",
+ "#calculations\n",
+ "E=e1+e2+e3\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Decomposition potential =\",E,\" volt\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Decomposition potential = 1.8 volt\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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