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diff --git a/OpAmps_And_Linear_Integrated_Circuits_by_Gayakwad/Chapter1.ipynb b/OpAmps_And_Linear_Integrated_Circuits_by_Gayakwad/Chapter1.ipynb new file mode 100644 index 00000000..e4a0b038 --- /dev/null +++ b/OpAmps_And_Linear_Integrated_Circuits_by_Gayakwad/Chapter1.ipynb @@ -0,0 +1,220 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "# Chapter 1: Introduction to Operational Amplifiers" + ] + }, + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "## Example 1.1_a" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Collector current Ic1 is 0.39 mA\n", + "Voltage Vc1 is 3.38 V\n", + "Voltage Ve4 is 2.68 V\n", + "Current Ie4 is 0.297 mA\n", + "Current Ic5 is 0.297 mA\n", + "Voltage Vc5 is 4.87 V\n", + "Voltage Ve6 is 4.17 V\n", + "Current Ie6 is 0.678 mA\n", + "Voltage Ve7 is 4.87 V\n", + "Current I1 is 2.82 mA\n", + "Current Ie8 is 2.82 mA\n", + "Voltage Ve8 at the output terminal is -0.35 V\n" + ] + } + ], + "source": [ + "\n", + "\n", + "#Example 1.1_a\n", + "#The equivalent circuit of the Motorola op-amp MC 1435 is shown in Figure.No-1.2\n", + "#Determine the collector current in each transistor and the dc voltage at the\n", + "#output terminal\n", + "\n", + "#Variable declaration\n", + "Vcc=6 #Voltage in volts\n", + "Vbe5=0.7 #Voltage in volts\n", + "Vee=6 #Voltage in volts\n", + "Vbe3=6.7 #Voltage in volts\n", + "Vbe6=0.7 #Voltage in volts\n", + "Vbe7=0.7 #Voltage in volts\n", + "Rc1=6.7*10**3 #Resistance in ohms\n", + "Ic1=0 #initialization\n", + "\n", + "#Calculation\n", + "Vc1=Vcc-Rc1*Ic1\n", + "Ve4=Vc1-Vbe5\n", + "I4=(Ve4+Vee)/(9.1*10**3+5.5*10**3)\n", + "Vb3=5.5*10**3*I4-Vee\n", + "Ve3=Vb3-Vbe3\n", + "Ie3=(Ve3+Vbe3)/3.3*10**3\n", + "Ic1=1.08*10**-3/2.765 #Since Ie3=2*Ic1\n", + "Vc1=Vcc-Rc1*Ic1\n", + "Ve4=Vc1-Vbe5\n", + "Ie4=(Ve4+Vee)/(29.2*10**3)\n", + "Ic5=Ie4\n", + "Vc5=Vcc-3.8*10**3*Ic5\n", + "Ve6=Vc5-Vbe6\n", + "Ie6=(Ve6+Vee)/(15*10**3)\n", + "Ve7=Ve6+Vbe7\n", + "I1=(Vcc-Ve7)/400\n", + "Ie8=I1\n", + "Ve8=-Vee+2*10**3*Ie8\n", + "\n", + "#Result\n", + "print \"Collector current Ic1 is\",round(Ic1*10**3,2),\"mA\"\n", + "print \"Voltage Vc1 is\",round(Vc1,2),\"V\" \n", + "print \"Voltage Ve4 is\",round(Ve4,2),\"V\"\n", + "print \"Current Ie4 is\",round(Ie4*10**3,3),\"mA\"\n", + "print \"Current Ic5 is\",round(Ic5*10**3,3),\"mA\"\n", + "print \"Voltage Vc5 is\",round(Vc5,2),\"V\"\n", + "print \"Voltage Ve6 is\",round(Ve6,2),\"V\"\n", + "print \"Current Ie6 is\",round(Ie6*10**3,3),\"mA\"\n", + "print \"Voltage Ve7 is\",round(Ve7,2),\"V\"\n", + "print \"Current I1 is\",round(I1*10**3,2),\"mA\"\n", + "print \"Current Ie8 is\",round(Ie8*10**3,2),\"mA\"\n", + "print \"Voltage Ve8 at the output terminal is\",round(Ve8,2),\"V\"\n" + ] + }, + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "## Example 1.1_b" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Voltage gain of the dual-input,balanced output-differential amplifier is 82.55\n", + "Voltage gain of the dual-input,unbalanced output-differential amplifier is 22.6\n", + "Overall gain of the op-amp is 1866.34\n" + ] + } + ], + "source": [ + "\n", + "\n", + "#Example 1.1_b, Figure.No-1.2\n", + "#Calculate the Voltage gain of the opamp\n", + "\n", + "#Variable decclaration\n", + "Ie1=0.39*10**-3 #Current in amps\n", + "Ie4=0.298*10**-3 #Current in amps\n", + "Ie6=0.678*10**-3 #Current in amps\n", + "Rc1=6.7*10**3 #Resistance in ohms\n", + "Rc5=3.8*10**3 #Resistance in ohms\n", + "beta_ac=150\n", + "\n", + "#Calculation\n", + "re1=(25*10**-3)/Ie1\n", + "re2=re1\n", + "re4=(25*10**-3)/Ie4\n", + "re5=re4\n", + "re6=(25*10**-3)/Ie6\n", + "k=(Rc1*2*beta_ac*re4)/(Rc1+2*beta_ac*re4)\n", + "Ad1=k/re1\n", + "k1=(Rc5*beta_ac*(re6+15*10**3))/(Rc5+beta_ac*(re6+15*10**3))\n", + "Ad2=k1/(2*re5)\n", + "Ad=Ad1*Ad2\n", + "\n", + "#Result\n", + "print \"Voltage gain of the dual-input,balanced output-differential amplifier is\",round(Ad1,2)\n", + "print \"Voltage gain of the dual-input,unbalanced output-differential amplifier is\",round(Ad2,1)\n", + "print \"Overall gain of the op-amp is\",round(Ad,2)\n" + ] + }, + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "## Example 1.1_c" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Input resistance Ri is 19.23 kilo ohms\n" + ] + } + ], + "source": [ + "\n", + "#Example 1.1_c, Figure.No-1.2\n", + "#Determine the Input resistance of the opamp\n", + "\n", + "#Variable declaration\n", + "beta_ac=150\n", + "re1=64.1 #Resistance in ohms\n", + "\n", + "#calculation\n", + "Ri=2*beta_ac*re1\n", + "\n", + "#result\n", + "print \"Input resistance Ri is\",round(Ri/10**3,2),\"kilo ohms\"\n" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.6" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |