1 files changed, 0 insertions, 17 deletions
diff --git a/Materials_science_and_engineering_an_introduction/CH7.ipynb b/Materials_science_and_engineering_an_introduction/CH7.ipynb
index ffef5715..262231ec 100644
--- a/Materials_science_and_engineering_an_introduction/CH7.ipynb
+++ b/Materials_science_and_engineering_an_introduction/CH7.ipynb
@@ -27,21 +27,17 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "#Resolved Shear Stress Computations\n",
       "\n",
-      "#Direction for given plane\n",
       "u1=1\n",
       "v1=1\n",
       "w1=0\n",
       "u2=0\n",
       "v2=1\n",
       "w2=0\n",
-      "#For lamda\n",
       "u3=-1\n",
       "v3=1\n",
       "w3=1\n",
       "\n",
-      "#Calculation\n",
       "import math\n",
       "phi=math.acos((u1*u2+v1*v2+w1*w2)/(math.sqrt((u1**2+v1**2+w1**2)*(u2**2+v2**2+w2**2))))\n",
       "lam=math.acos((u3*u2+v3*v2+w3*w2)/(math.sqrt((u3**2+v3**2+w3**2)*(u2**2+v2**2+w2**2))))\n",
@@ -50,7 +46,6 @@
       "trc=30         #in MPa Critical resolved shear stress\n",
       "sy=trc/(math.cos(phi)*math.cos(lam))\n",
       "\n",
-      "#Result\n",
       "print\"(a)The resolved shear stress is \",round(tr,2),\"MPa\"\n",
       "print\"(b)Yield strength is\",round(sy,1),\"MPa\"\n",
       "\n"
@@ -81,18 +76,14 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "#Tensile Strength and Ductility Determinations for Cold-Worked Copper\n",
       "\n",
-      "#Given\n",
       "df=12.2  #Final dia in mm\n",
       "di=15.2  #Initial dia in mm\n",
       "\n",
-      "#Calculation\n",
       "CW = ((di**2-df**2)/di**2)*100\n",
       "ts=340  #in Mpa  tensile strength, from fig 7.19 (b)\n",
       "duc=7   #in %  Ductility from fig 7.19 (c)\n",
       "\n",
-      "#result\n",
       "print\"Percent Cold Work is \",round(CW,1),\"%\"\n",
       "print\"Tensile strength is\",ts,\"MPa\"\n",
       "print\"Ductility is \",duc,\"%\"\n",
@@ -125,21 +116,13 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "#Description of Diameter Reduction Procedure\n",
       "\n",
-      "#Given\n",
       "di=6.4  #Initial dia in mm\n",
       "df=5.1  #Final dia in mm\n",
       "\n",
-      "#Calculation\n",
-      "#Cold Work Computation\n",
       "CW = ((di**2-df**2)/di**2)*100\n",
-      "#From Figures 7.19a and 7.19c, \n",
-      "#A yield strength of 410 MPa \n",
-      "#And a ductility of 8% EL are attained from this deformation\n",
       "dmid = math.sqrt(df**2/(1-0.215))\n",
       "\n",
-      "#Result\n",
       "print\"Cold work is \",round(CW,1),\"%\"\n",
       "print\"But required ductility and yield strength is not matched at this cold work\"\n",
       "print\"Hence required Cold work is 21.5 %\"\n",