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diff --git a/Materials_Science/Chapter18_1.ipynb b/Materials_Science/Chapter18_1.ipynb new file mode 100755 index 00000000..5ae109b8 --- /dev/null +++ b/Materials_Science/Chapter18_1.ipynb @@ -0,0 +1,251 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:bc4f145530554f550ad02c41bb92fc1d8f9fdac80b4d0ae7b519b9e02a3d9b4f"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter18:Magnetic Materials"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex18.1:pg-346"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 18.1 : magnetization and flux density\n",
+ "import math\n",
+ "#given data :\n",
+ "mu0=4*math.pi*10**-7;\n",
+ "H=10**4;# in A/m\n",
+ "Xm=3.7*10**-3;# room temperature\n",
+ "mu_r=1+Xm;\n",
+ "B=mu0*mu_r*H;\n",
+ "M=Xm*H;\n",
+ "print \"{:.2e}\".format(B),\"= the flux density,B(Wb/m**2) \"\n",
+ "print M,\"= magnetization,M(A/m) \"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "1.26e-02 = the flux density,B(Wb/m**2) \n",
+ "37.0 = magnetization,M(A/m) \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex18.2a:pg-350"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 18.2.a : saturation magnetization\n",
+ " \n",
+ "#given data :\n",
+ "mu_b=9.27*10**-24;# A.m**2\n",
+ "p=8.9; # in g/cm**3\n",
+ "Na=6.023*10**23;# avogadro's number\n",
+ "A=58.71; # in g/mol\n",
+ "n=((p*Na)/A)*10**6;\n",
+ "Ms=0.60*mu_b*n;\n",
+ "print \"{:.1e}\".format(Ms),\"= saturation magnetization,Ms(A/m) \"\n",
+ "# the answe ris slightly different in textbook due to approximation"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "5.1e+05 = saturation magnetization,Ms(A/m) \n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex18.2b:pg-350"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 18.2.b : saturation flux density\n",
+ "import math\n",
+ "#given data :\n",
+ "\n",
+ "mu0=4*math.pi*10**-7;\n",
+ "mu_b=9.27*10**-24;# A.m**2\n",
+ "p=8.9; # in g/cm**3\n",
+ "Na=6.023*10**23;# avogadro's number\n",
+ "A=58.71; # in g/mol\n",
+ "n=((p*Na)/A)*10**6;\n",
+ "Ms=0.60*mu_b*n;\n",
+ "Bs=mu0*Ms;\n",
+ "print round(Bs,2),\"= saturation flux density,Bs(tesla) \"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "0.64 = saturation flux density,Bs(tesla) \n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex18.3:pg-351"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 18.3 : magnetic moment\n",
+ "import math \n",
+ "#given data :\n",
+ "\n",
+ "mu0=4*math.pi*10**-7;\n",
+ "mu_b=9.27*10**-24;# A.m**2\n",
+ "p=8.9; # in g/cm**3\n",
+ "Na=6.023*10**23;# avogadro's number\n",
+ "A=58.71; # in g/mol\n",
+ "n=((p*Na)/A)*10**6;\n",
+ "Bs=0.65;#in Wb/m**2\n",
+ "Ms=Bs/mu0;\n",
+ "m_mu_b=Ms/n;\n",
+ "print round(m_mu_b,26),\" is saturation magnetisation,m_mu_b(A.m**2) \"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "5.67e-24 is saturation magnetisation,m_mu_b(A.m**2) \n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex18.4:pg-355"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 18.4 : power loss\n",
+ " \n",
+ "#given data :\n",
+ "V=0.01;#in m**3\n",
+ "f=50;# in Hz\n",
+ "area=600;#in jm**-1\n",
+ "Wh=area*V*f;\n",
+ "print Wh,\"= power loss,Wh(watts) \"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "300.0 = power loss,Wh(watts) \n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex18.5:pg-355"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 18.4 : los of energy\n",
+ " \n",
+ "#given data :\n",
+ "mass=10.0;# in kg\n",
+ "energy_loss=250.0;# in J/m**2\n",
+ "#energy loss at the rate of 50 cycles/s\n",
+ "E=energy_loss*50.0;# in J/m**3\n",
+ "E_loss=E*3600.0;#in J/m**3\n",
+ "D=7500.0;#density in kg/m**3\n",
+ "Volume=mass/D;\n",
+ "energy_loss_per_hour=E_loss/Volume;\n",
+ "print \"{:.1e}\".format(energy_loss_per_hour),\"= energy_loss_per_hour(J/hour) \"\n",
+ "\n",
+ "# answer is incorrect in textbook"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "3.4e+10 = energy_loss_per_hour(J/hour) \n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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