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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:7315f4cd0dbe1ea8c121564011c9ce9945618f308024d617157c5ed6076bc7d9"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter15:Composite Materials and Ceramics"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex15.1:pg-299"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Example 15.1 : colume ratio of aluminium and boron\n",
+      " \n",
+      "import numpy.linalg as lin\n",
+      "yal=715;# in GN/,**2\n",
+      "yfe=210;# in GN/,**2\n",
+      "yb=440;# in GN/,**2\n",
+      "A=numpy.array([[71, 71],[71, 440]]);#\n",
+      "B=numpy.array([71,210]);#\n",
+      "X=lin.solve(A,B)\n",
+      "print round(X[0],3),\"is volume ratio of aluminium \"\n",
+      "print round(X[1],3),\"is volume ratio of boron \"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "0.623 is volume ratio of aluminium \n",
+        "0.377 is volume ratio of boron \n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file