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diff --git a/Linear_Integrated_Circuits/Chapter6.ipynb b/Linear_Integrated_Circuits/Chapter6.ipynb new file mode 100755 index 00000000..4ddd3b93 --- /dev/null +++ b/Linear_Integrated_Circuits/Chapter6.ipynb @@ -0,0 +1,147 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 6 : Voltage Regulators" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.1 Page No.246" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data \n", + "\n", + "Veb = 1.0\n", + "beta = 15.0\n", + "Vc = 5.0\n", + "Io = 1.0 # for 7805 maximum value of I b is 1 Ampere \n", + "R1 = 7.0\n", + "# Solution \n", + "\n", + "# for Load = 100ohms \n", + "\n", + "Rl = 100.0\n", + "\n", + "Il=Ic=Ii = Vc/Rl\n", + "# voltage across R1\n", + "V1 = R1*(50*10**-3)\n", + "# for load = 5 ohms\n", + "\n", + "Rl1 = 5.0\n", + "Il1 = Vc/Rl1\n", + "V12 = Il1 * Rl1 # Finding the Voltage drop across R1 when Rl = 5 Ohms \n", + "# Finding the value of Io\n", + "Io = (Il1 + (beta*(Veb/R1)))/(beta + 1)\n", + "Ic = beta*(Io - (Veb/R1))\n", + "\n", + "# for load = 1 Ohm\n", + "\n", + "Rl2 = 1.0\n", + "Il2 = Vc/Rl2\n", + "# Finding the value of Io\n", + "Io1 = (Il2 + (beta*(Veb/R1)))/(beta + 1)\n", + "Ic1 = beta*(Io1 - (Veb/R1))\n", + "\n", + "print \" The value of load current when Rl = 100 ohms is =\",int(Il*10**3),\"mA\"\n", + "print \" The voltage across R1 when load is 100 ohms =\",int(V1*10**3),\"mV\"\n", + "print \" The value of load current when Rl = 5 ohms =\",int(Il1),\"A\"\n", + "print \" The voltage across R1 when load is 5 Ohms =\",int(V12),\"V\"\n", + "print \" The value of output current when load is 5 ohms =\",int(Io*10**3),\"mA\"\n", + "print \" The value of collector current is =\",int(round(Ic*10**3)),\"mA\"\n", + "print \" The value of output current when load is 1 Ohm =\",int(Io1*10**3),\"mA\"\n", + "print \" The value of collector current is =\",round(Ic1,2),\"A\" \n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The value of load current when Rl = 100 ohms is = 50 mA\n", + " The voltage across R1 when load is 100 ohms = 350 mV\n", + " The value of load current when Rl = 5 ohms = 1 A\n", + " The voltage across R1 when load is 5 Ohms = 5 V\n", + " The value of output current when load is 5 ohms = 196 mA\n", + " The value of collector current is = 804 mA\n", + " The value of output current when load is 1 Ohm = 446 mA\n", + " The value of collector current is = 4.55 A\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.2 Page No.247" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "\n", + "Vo = 7.5\n", + "Iq = 4.2*10**-3\n", + "Ir1 = 25*10**-3\n", + "Vr = 5\n", + "\n", + "# Solution \n", + "\n", + "R1 = Vr/Ir1\n", + "R2 = 2.5/(Ir1 + Iq)\n", + "\n", + "# Displaying the outputs \n", + "\n", + "print \"The value of R1 =\",int(R1),\"Ohms\" \n", + "print \"The value of R2 =\",int(R2),\"Ohms\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of R1 = 200 Ohms\n", + "The value of R2 = 85 Ohms\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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