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diff --git a/Heat_And_Thermodynamics_by_A._Manna/ch2.ipynb b/Heat_And_Thermodynamics_by_A._Manna/ch2.ipynb new file mode 100755 index 00000000..b2e44ac0 --- /dev/null +++ b/Heat_And_Thermodynamics_by_A._Manna/ch2.ipynb @@ -0,0 +1,229 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 2 : Thermometry" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 2.1 pageno : 29" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "li = 1.23;\t\t\t#length of melting ice in mm\n", + "lf = 18.56;\t\t\t#length of melting ice reading in pressure of 74.24cm of mercury in mm\n", + "l = 10.75;\t\t\t#length of melting ice at which temperature to be calculated\n", + "mp = 0;\t\t\t#melting point in deg.C\n", + "T = 50;\t\t\t#temperature of melting ice at which length to be calculated in deg.C\n", + "\n", + "# Calculations\n", + "sp = 100-(76-74.24)/(2.7);\t\t\t#76cm of mercury steam point is 100 deg.C so at 74.24cm of mercury the steam point in deg.C\n", + "t = (l-li)*(sp-mp)/(lf-li);\t\t\t#temperature at 10.75mm of melting ice in deg.C\n", + "lt = ((T*(lf-li))/(sp-mp))+li;\t\t\t#length of ice at 50 deg.C\n", + "\n", + "# Result\n", + "print 'the temperature of melting ice at 10.75mm of hg is %3.2f deg.C \\\n", + " \\nthe length of ice corresponding to 50 deg.C is %3.2f mm of mercury'%(t,lt)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "the temperature of melting ice at 10.75mm of hg is 54.58 deg.C \n", + "the length of ice corresponding to 50 deg.C is 9.95 mm of mercury\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 2.2 pageno : 30" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "p1 = 23.5;\t\t\t#pressure when immersed in liquid air in cm\n", + "p2 = 75.;\t\t\t#pressure when immersed in ice in cm\n", + "p3 = 102.4;\t\t\t#pressure when immersed in steam in cm\n", + "T = 100.;\t\t\t#boiling point of temperature in deg.C\n", + "\n", + "# Calculations\n", + "t = (p1-p2)*T/(p3-p2);\t\t\t#temperature of the liquid air in deg.C\n", + "\n", + "# Result\n", + "print 'the temperature of liquid of air is %3.2f deg.C'%(t)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "the temperature of liquid of air is -187.96 deg.C\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 2.3 pageno : 30" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "t1 = 283.;\t\t\t#temperature of bulb when pressure is h-2cm of hg in k\n", + "t2 = 546.;\t\t\t#temperature of bulb when pressure is h-22cm of hg in k\n", + "h1 = 2.;\t\t\t#differnce of mercury level at 283k in cm\n", + "h2 = 22.;\t\t\t#differnce of mercury level at 546k in cm\n", + "\n", + "# Calculations\n", + "h = ((h2*t1)+(h1*t2))/(t2-t1);\t\t\t#height of the barometer in cm\n", + "\n", + "# Result\n", + "print 'height of the barometer is %3.2f cm'%(h)\n", + "\n", + "print \"Note : Answer in book is wrong. Please calculate manually and check.\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "height of the barometer is 27.83 cm\n", + "Note : Answer in book is wrong. Please calculate manually and check.\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "\n", + "Example 2.4 pageno : 30" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "p0 = 76.;\t\t\t#pressure at 0 deg.C in cm of hg\n", + "p1 = 228.;\t\t\t#pressure (76+152) at T deg.C in cm of hg\n", + "t0 = 273.;\t\t\t#temperature of bulb in K\n", + "\n", + "# Calculations\n", + "T = p1*t0/p0;\t\t\t#temperature at 228 cm of hg pressure in K\n", + "\n", + "# Result\n", + "print 'the temperature of bulb is %3.2f K'%(T)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "the temperature of bulb is 819.00 K\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 2.5 page no : 30" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "t1 = 0;\t\t\t #temperature in deg.C\n", + "t2 = 100;\t\t\t#temperature in deg.C\n", + "t3 = 208;\t\t\t#temperature in deg.C\n", + "r1 = 3.5;\t\t\t#resistance in ohms\n", + "r2 = 5.2;\t\t\t#resistance in ohms\n", + "r3 = 6.9;\t\t\t#resistance in ohms\n", + "r4 = 9.4;\t\t\t#resistance in ohms\n", + "\n", + "# Calculations\n", + "tpt = (r3-r1)*100/(r2-r1);\t\t\t#temperature in deg.C\n", + "d = round((t3-tpt)/(2.08*1.08),2);\t\t\t#deflection\n", + "tp = round((r4-r1)*100/(r2-r1),2);\t\t\t#temperature in deg.C\n", + "t6 = (3.5*(((tp/100)**2)-tp/100))+tp;\t\t\t#temperature in deg.C\n", + "t7 = (3.5*(((t6/100)**2)-t6/100))+tp;\t\t\t#temperature in deg.C\n", + "t8 = (3.5*(((t7/100)**2)-t7/100))+tp;\t\t\t#temperature in deg.C\n", + "t9 = (3.5*(((t8/100)**2)-t8/100))+tp;\t\t\t#temperature in deg.C\n", + "\n", + "#Result\n", + "print 'the temperature of the bath is %3.2f deg.C'%(t9)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "the temperature of the bath is 385.50 deg.C\n" + ] + } + ], + "prompt_number": 13 + } + ], + "metadata": {} + } + ] +}
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