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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:ef8a83f912d8b81107a82e5afb87ec1b0700272a7362a57c794757b82a1ddfa1"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 11 : Impulse Turbine"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.1 Page No : 233"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "# Variables\n",
+ "P = 8820.*1000\n",
+ "N = 600./60\n",
+ "H = 500.\n",
+ "Cv = 0.97\n",
+ "Cu = 0.46\n",
+ "no = 0.85\n",
+ "w = 9810.\n",
+ "g = 9.81\n",
+ "\n",
+ "# Calculations \n",
+ "Q = P/(no*w*H)\n",
+ "V1 = Cv*((2*g*H)**0.5)\n",
+ "u = Cu*V1\n",
+ "D = u/(3.142*N)\n",
+ "d = D/15\n",
+ "a = 3.142*d*d/4\n",
+ "n = Q/(a*V1)\n",
+ "n1 = round(n+1)\n",
+ "\n",
+ "# Results \n",
+ "print \"discharge in m3/sec,wheel diameter in m, jet diameter in cm, number os jets \",round(Q,6),round(D,4),round(d*100,2),n1\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "discharge in m3/sec,wheel diameter in m, jet diameter in cm, number os jets 2.115488 1.4066 9.38 4.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.2 Page No : 235"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "H = 46.\n",
+ "Q = 1.\n",
+ "u1 = 15.\n",
+ "y = 165.\n",
+ "y2 = 180-y\n",
+ "Cv = 0.975\n",
+ "g = 9.81\n",
+ "\n",
+ "# Calculations \n",
+ "V1 = ((2*g*H)**0.5)\n",
+ "Vw1 = V1\n",
+ "Vr1 = V1-u1\n",
+ "Vr2 = Vr1\n",
+ "Vw2 = (Vr2*(math.cos(math.radians(y2))))-u1\n",
+ "w = 9810.\n",
+ "P = (w*Q*(Vw1+Vw2)*u1)/(g*1000)\n",
+ "n = P*1000/(w*Q*H)\n",
+ "\n",
+ "# Results \n",
+ "print \"power developed in Kw and efficiency of the wheel\",round(P,3),round((n*100),3)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "power developed in Kw and efficiency of the wheel 443.571 98.296\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.3 Page No : 236"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "H = 340.\n",
+ "P = 4410.*1000\n",
+ "N = 500./60\n",
+ "Cv = 0.97\n",
+ "no = 0.86\n",
+ "w = 9810.\n",
+ "g = 9.81\n",
+ "\n",
+ "# Calculations \n",
+ "Q = P/(w*H*no)\n",
+ "V1 = Cv*(math.sqrt(2*g*H))\n",
+ "u = 0.45*V1\n",
+ "D = u/(3.142*N)\n",
+ "a = Q/V1\n",
+ "\n",
+ "# Results \n",
+ "print \"mean diameter in m,jet area in m2\",round(D,4),round(a,7)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "mean diameter in m,jet area in m2 1.3616 0.0194058\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.4 Page No : 237"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "H = 45.\n",
+ "Q = 50./60\n",
+ "u1 = 12.5\n",
+ "y = 160.\n",
+ "y2 = 180.-y\n",
+ "Cv = 0.97\n",
+ "g = 9.81\n",
+ "\n",
+ "# Calculations and Results\n",
+ "V1 = Cv*((2*g*H)**0.5)\n",
+ "Vw1 = V1\n",
+ "Vr1 = V1-u1\n",
+ "Vr2 = Vr1\n",
+ "Vw2 = Vr2*(math.cos(math.radians(y2)))-u1\n",
+ "w = 9810\n",
+ "P = (w*Q*(Vw1+Vw2)*u1)/(g*1000)\n",
+ "nh = (2*u1*(Vw1+Vw2))/(V1*V1)\n",
+ "print \"power developed in Kw and hydraulic efficiency\",P,nh*100\n",
+ "\n",
+ "H1 = 50\n",
+ "V11 = Cv*((2*g*H1)**0.5)\n",
+ "Vw11 = V11\n",
+ "Vr11 = V11-u1\n",
+ "Vr21 = Vr11\n",
+ "Vw21 = Vr21*(math.cos(math.radians(y2)))-u1\n",
+ "w = 9810\n",
+ "P = (w*Q*(Vw11+Vw21)*u1)/(g*1000)\n",
+ "print \"Power developed in Kw if head is increased to 50\",P\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "power developed in Kw and hydraulic efficiency 329.792686546 95.2790189845\n",
+ "Power developed in Kw if head is increased to 50 361.293854458\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.5 Page No : 237"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "# Variables\n",
+ "H = 50.\n",
+ "Q = 1.2\n",
+ "u1 = 18.\n",
+ "y = 160.\n",
+ "y2 = 180-y\n",
+ "Cv = 0.94\n",
+ "g = 9.81\n",
+ "\n",
+ "# Calculations \n",
+ "V1 = Cv*((2*g*H)**0.5)\n",
+ "Vw1 = V1\n",
+ "Vr1 = V1-u1\n",
+ "Vr2 = Vr1\n",
+ "Vw2 = Vr2*(math.cos(math.radians(y2)))-u1\n",
+ "w = 9810\n",
+ "P = (w*Q*(Vw1+Vw2)*u1)/(g*1000)\n",
+ "n = P*1000/(w*Q*H)\n",
+ "\n",
+ "# Results \n",
+ "print \"power developed in Kw and efficiency of the wheel\",P,n*100\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "power developed in Kw and efficiency of the wheel 479.375537454 81.4433464923\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.6 Page No : 238"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "D = 1.\n",
+ "N = 1000./60\n",
+ "H = 700.\n",
+ "y = 165.\n",
+ "y2 = 180-y\n",
+ "Q = 0.1\n",
+ "Cv = 0.97\n",
+ "g = 9.81\n",
+ "\n",
+ "# Calculations \n",
+ "u = D*math.pi*N\n",
+ "V1 = Cv*(math.sqrt(2*g*H))\n",
+ "nh = (2*u*(V1-u)*(1+(math.cos(math.radians(y2)))))/(V1*V1)\n",
+ "\n",
+ "# Results \n",
+ "print \"hydraulic efficiency of the wheel\",round((nh*100),2),\"%\"\n",
+ "\n",
+ "# note : rounding off error"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "hydraulic efficiency of the wheel 97.69 %\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.7 Page No : 239"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "Hg = 500.\n",
+ "hf = Hg/3\n",
+ "H = Hg-hf\n",
+ "Q = 2.\n",
+ "y = 165.\n",
+ "y2 = 180.-y\n",
+ "g = 9.81\n",
+ "w = 9810.\n",
+ "Cv = 1.\n",
+ "\n",
+ "# Calculations \n",
+ "V1 = Cv*(math.sqrt(2*g*H))\n",
+ "u = 0.45*V1\n",
+ "Vr1 = V1-u\n",
+ "Vw1 = V1\n",
+ "Vr2 = Vr1\n",
+ "Vw2 = (Vr2*(math.cos(math.radians(y2))))-u\n",
+ "W = w*Q*(Vw1+Vw2)*u/g\n",
+ "P = W/1000\n",
+ "nh = 2*u*(Vw1+Vw2)/(V1*V1)\n",
+ "\n",
+ "# Results \n",
+ "print \"power given by the water to the runner in Kw : %.3f \\\n",
+ "\\nHydraulic efficiency %.2f\"%(P,(nh*100)),\"%\"\n",
+ "\n",
+ "# note : rounding off error"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "power given by the water to the runner in Kw : 6364.292 \n",
+ "Hydraulic efficiency 97.31 %\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.8 Page No : 240"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "L = 1600.\n",
+ "H = 550.\n",
+ "Dp = 1.2\n",
+ "d = 0.18\n",
+ "f = 0.006\n",
+ "Cv = 0.97\n",
+ "g = 9.81\n",
+ "\n",
+ "# Calculations \n",
+ "V1 = Cv*(math.sqrt(2*g*H))\n",
+ "a = math.pi*d*d/4\n",
+ "Q = a*V1\n",
+ "w = 9810\n",
+ "P = (w*Q*V1*V1)/(2*g*1000)\n",
+ "ap = math.pi*Dp*Dp/4\n",
+ "Vp = Q/ap\n",
+ "Hf = (4*f*L*Vp*Vp)/(Dp*2*g)\n",
+ "Tp = 4*w*Q*(H+Hf)/1000\n",
+ "\n",
+ "# Results \n",
+ "print \"power to each jet in Kw : %.1f \\\n",
+ "\\ntotal power at reserviour i Kw : %.2f\"%(P,Tp)\n",
+ "\n",
+ "# note : rounding off error."
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "power to each jet in Kw : 13017.1 \n",
+ "total power at reserviour i Kw : 56182.23\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.9 Page No : 241"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "Q = 4.\n",
+ "H = 250.\n",
+ "L = 3000.\n",
+ "n1 = 4.\n",
+ "n = 0.91\n",
+ "nh = 0.9\n",
+ "Cv = 0.975\n",
+ "f4 = 0.0045\n",
+ "\n",
+ "# Calculations \n",
+ "hf = H-H*n\n",
+ "Hn = H-hf\n",
+ "g = 9.81\n",
+ "w = 9810\n",
+ "V1 = Cv*(math.sqrt(2*g*Hn))\n",
+ "Pw = w*Q*V1*V1/(2*g*1000)\n",
+ "Pt = nh*Pw\n",
+ "q = Q/n1\n",
+ "d = math.sqrt(4*q/(3.142*V1))\n",
+ "D = ((f4*L*16*16)/(2*g*3.142*3.142*hf))**0.2\n",
+ "\n",
+ "# Results \n",
+ "print \"power developed by turbine in Kw : %.1f \\\n",
+ "\\ndiameter jet and diameter of pipeline\"%(Pt),round(d,4),round(D,4)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "power developed by turbine in Kw : 7637.7 \n",
+ "diameter jet and diameter of pipeline 0.1398 0.9547\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": []
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file