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diff --git a/Fluid_Mechanics_and_Hydraulic_Machines/ch11.ipynb b/Fluid_Mechanics_and_Hydraulic_Machines/ch11.ipynb new file mode 100755 index 00000000..8285c578 --- /dev/null +++ b/Fluid_Mechanics_and_Hydraulic_Machines/ch11.ipynb @@ -0,0 +1,493 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:ef8a83f912d8b81107a82e5afb87ec1b0700272a7362a57c794757b82a1ddfa1" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 11 : Impulse Turbine" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.1 Page No : 233" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "P = 8820.*1000\n", + "N = 600./60\n", + "H = 500.\n", + "Cv = 0.97\n", + "Cu = 0.46\n", + "no = 0.85\n", + "w = 9810.\n", + "g = 9.81\n", + "\n", + "# Calculations \n", + "Q = P/(no*w*H)\n", + "V1 = Cv*((2*g*H)**0.5)\n", + "u = Cu*V1\n", + "D = u/(3.142*N)\n", + "d = D/15\n", + "a = 3.142*d*d/4\n", + "n = Q/(a*V1)\n", + "n1 = round(n+1)\n", + "\n", + "# Results \n", + "print \"discharge in m3/sec,wheel diameter in m, jet diameter in cm, number os jets \",round(Q,6),round(D,4),round(d*100,2),n1\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "discharge in m3/sec,wheel diameter in m, jet diameter in cm, number os jets 2.115488 1.4066 9.38 4.0\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.2 Page No : 235" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\n", + "# Variables\n", + "H = 46.\n", + "Q = 1.\n", + "u1 = 15.\n", + "y = 165.\n", + "y2 = 180-y\n", + "Cv = 0.975\n", + "g = 9.81\n", + "\n", + "# Calculations \n", + "V1 = ((2*g*H)**0.5)\n", + "Vw1 = V1\n", + "Vr1 = V1-u1\n", + "Vr2 = Vr1\n", + "Vw2 = (Vr2*(math.cos(math.radians(y2))))-u1\n", + "w = 9810.\n", + "P = (w*Q*(Vw1+Vw2)*u1)/(g*1000)\n", + "n = P*1000/(w*Q*H)\n", + "\n", + "# Results \n", + "print \"power developed in Kw and efficiency of the wheel\",round(P,3),round((n*100),3)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "power developed in Kw and efficiency of the wheel 443.571 98.296\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.3 Page No : 236" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\n", + "# Variables\n", + "H = 340.\n", + "P = 4410.*1000\n", + "N = 500./60\n", + "Cv = 0.97\n", + "no = 0.86\n", + "w = 9810.\n", + "g = 9.81\n", + "\n", + "# Calculations \n", + "Q = P/(w*H*no)\n", + "V1 = Cv*(math.sqrt(2*g*H))\n", + "u = 0.45*V1\n", + "D = u/(3.142*N)\n", + "a = Q/V1\n", + "\n", + "# Results \n", + "print \"mean diameter in m,jet area in m2\",round(D,4),round(a,7)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "mean diameter in m,jet area in m2 1.3616 0.0194058\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.4 Page No : 237" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\n", + "# Variables\n", + "H = 45.\n", + "Q = 50./60\n", + "u1 = 12.5\n", + "y = 160.\n", + "y2 = 180.-y\n", + "Cv = 0.97\n", + "g = 9.81\n", + "\n", + "# Calculations and Results\n", + "V1 = Cv*((2*g*H)**0.5)\n", + "Vw1 = V1\n", + "Vr1 = V1-u1\n", + "Vr2 = Vr1\n", + "Vw2 = Vr2*(math.cos(math.radians(y2)))-u1\n", + "w = 9810\n", + "P = (w*Q*(Vw1+Vw2)*u1)/(g*1000)\n", + "nh = (2*u1*(Vw1+Vw2))/(V1*V1)\n", + "print \"power developed in Kw and hydraulic efficiency\",P,nh*100\n", + "\n", + "H1 = 50\n", + "V11 = Cv*((2*g*H1)**0.5)\n", + "Vw11 = V11\n", + "Vr11 = V11-u1\n", + "Vr21 = Vr11\n", + "Vw21 = Vr21*(math.cos(math.radians(y2)))-u1\n", + "w = 9810\n", + "P = (w*Q*(Vw11+Vw21)*u1)/(g*1000)\n", + "print \"Power developed in Kw if head is increased to 50\",P\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "power developed in Kw and hydraulic efficiency 329.792686546 95.2790189845\n", + "Power developed in Kw if head is increased to 50 361.293854458\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.5 Page No : 237" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "# Variables\n", + "H = 50.\n", + "Q = 1.2\n", + "u1 = 18.\n", + "y = 160.\n", + "y2 = 180-y\n", + "Cv = 0.94\n", + "g = 9.81\n", + "\n", + "# Calculations \n", + "V1 = Cv*((2*g*H)**0.5)\n", + "Vw1 = V1\n", + "Vr1 = V1-u1\n", + "Vr2 = Vr1\n", + "Vw2 = Vr2*(math.cos(math.radians(y2)))-u1\n", + "w = 9810\n", + "P = (w*Q*(Vw1+Vw2)*u1)/(g*1000)\n", + "n = P*1000/(w*Q*H)\n", + "\n", + "# Results \n", + "print \"power developed in Kw and efficiency of the wheel\",P,n*100\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "power developed in Kw and efficiency of the wheel 479.375537454 81.4433464923\n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.6 Page No : 238" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\n", + "# Variables\n", + "D = 1.\n", + "N = 1000./60\n", + "H = 700.\n", + "y = 165.\n", + "y2 = 180-y\n", + "Q = 0.1\n", + "Cv = 0.97\n", + "g = 9.81\n", + "\n", + "# Calculations \n", + "u = D*math.pi*N\n", + "V1 = Cv*(math.sqrt(2*g*H))\n", + "nh = (2*u*(V1-u)*(1+(math.cos(math.radians(y2)))))/(V1*V1)\n", + "\n", + "# Results \n", + "print \"hydraulic efficiency of the wheel\",round((nh*100),2),\"%\"\n", + "\n", + "# note : rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "hydraulic efficiency of the wheel 97.69 %\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.7 Page No : 239" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\n", + "# Variables\n", + "Hg = 500.\n", + "hf = Hg/3\n", + "H = Hg-hf\n", + "Q = 2.\n", + "y = 165.\n", + "y2 = 180.-y\n", + "g = 9.81\n", + "w = 9810.\n", + "Cv = 1.\n", + "\n", + "# Calculations \n", + "V1 = Cv*(math.sqrt(2*g*H))\n", + "u = 0.45*V1\n", + "Vr1 = V1-u\n", + "Vw1 = V1\n", + "Vr2 = Vr1\n", + "Vw2 = (Vr2*(math.cos(math.radians(y2))))-u\n", + "W = w*Q*(Vw1+Vw2)*u/g\n", + "P = W/1000\n", + "nh = 2*u*(Vw1+Vw2)/(V1*V1)\n", + "\n", + "# Results \n", + "print \"power given by the water to the runner in Kw : %.3f \\\n", + "\\nHydraulic efficiency %.2f\"%(P,(nh*100)),\"%\"\n", + "\n", + "# note : rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "power given by the water to the runner in Kw : 6364.292 \n", + "Hydraulic efficiency 97.31 %\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.8 Page No : 240" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\n", + "# Variables\n", + "L = 1600.\n", + "H = 550.\n", + "Dp = 1.2\n", + "d = 0.18\n", + "f = 0.006\n", + "Cv = 0.97\n", + "g = 9.81\n", + "\n", + "# Calculations \n", + "V1 = Cv*(math.sqrt(2*g*H))\n", + "a = math.pi*d*d/4\n", + "Q = a*V1\n", + "w = 9810\n", + "P = (w*Q*V1*V1)/(2*g*1000)\n", + "ap = math.pi*Dp*Dp/4\n", + "Vp = Q/ap\n", + "Hf = (4*f*L*Vp*Vp)/(Dp*2*g)\n", + "Tp = 4*w*Q*(H+Hf)/1000\n", + "\n", + "# Results \n", + "print \"power to each jet in Kw : %.1f \\\n", + "\\ntotal power at reserviour i Kw : %.2f\"%(P,Tp)\n", + "\n", + "# note : rounding off error." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "power to each jet in Kw : 13017.1 \n", + "total power at reserviour i Kw : 56182.23\n" + ] + } + ], + "prompt_number": 11 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 11.9 Page No : 241" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\n", + "# Variables\n", + "Q = 4.\n", + "H = 250.\n", + "L = 3000.\n", + "n1 = 4.\n", + "n = 0.91\n", + "nh = 0.9\n", + "Cv = 0.975\n", + "f4 = 0.0045\n", + "\n", + "# Calculations \n", + "hf = H-H*n\n", + "Hn = H-hf\n", + "g = 9.81\n", + "w = 9810\n", + "V1 = Cv*(math.sqrt(2*g*Hn))\n", + "Pw = w*Q*V1*V1/(2*g*1000)\n", + "Pt = nh*Pw\n", + "q = Q/n1\n", + "d = math.sqrt(4*q/(3.142*V1))\n", + "D = ((f4*L*16*16)/(2*g*3.142*3.142*hf))**0.2\n", + "\n", + "# Results \n", + "print \"power developed by turbine in Kw : %.1f \\\n", + "\\ndiameter jet and diameter of pipeline\"%(Pt),round(d,4),round(D,4)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "power developed by turbine in Kw : 7637.7 \n", + "diameter jet and diameter of pipeline 0.1398 0.9547\n" + ] + } + ], + "prompt_number": 12 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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