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Diffstat (limited to 'Fluid_Mechanics_/Chapter8.ipynb')
| -rw-r--r-- | Fluid_Mechanics_/Chapter8.ipynb | 33 |
1 files changed, 0 insertions, 33 deletions
diff --git a/Fluid_Mechanics_/Chapter8.ipynb b/Fluid_Mechanics_/Chapter8.ipynb index 51f3481e..6972a7f7 100644 --- a/Fluid_Mechanics_/Chapter8.ipynb +++ b/Fluid_Mechanics_/Chapter8.ipynb @@ -28,9 +28,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Determine maximum velocity and shear stress\n", "\n", - "# Given\n", "\n", "from math import *\n", "\n", @@ -46,7 +44,6 @@ "\n", "g = 9.81 # acceleration due to gravity in m/s**2\n", "\n", - "# properties of kerosene\n", "\n", "mu = 19.1*10**-4 # viscosity of kerosene at 20 deg C\n", "\n", @@ -54,17 +51,13 @@ "\n", "rho = 1000 # density in kg/m**3\n", "\n", - "# Solution\n", "\n", - "# calculating direction of flow\n", "\n", "p1 = (P1+g*z*S)*1000 # point 1\n", "\n", "p2 = (P2)*1000 # point 2\n", "\n", - "# direction of flow is from point 1-2\n", "\n", - "# shear stress\n", "\n", "Sp = -((p1-p2)/sqrt(L**2+z**2))\n", "\n", @@ -74,19 +67,16 @@ "\n", "print \"(a) Maximum shear stress =\",round(Tau_max,3),\"N/m**2\"\n", "\n", - "# maximum velocity\n", "\n", "Vmax = r**2*Sp/(4*mu)\n", "\n", "print \"(b) Maximum velocity =\",round(Vmax,3),\"m/s\"\n", "\n", - "# discharge\n", "\n", "Q = pi*r**4*Sp/(8*mu)\n", "\n", "print \"(c) Discharge = \",round(Q,7),\"m**3/s\"\n", "\n", - "# calculate reynolds number\n", "\n", "V = Vmax/2\n", "\n", @@ -122,9 +112,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Determine the head loss\n", "\n", - "# Given\n", "\n", "d = 0.02 # diameter of the pipe in m\n", "\n", @@ -134,11 +122,9 @@ "\n", "g = 9.81 # acceleration due to gravity in m/s**2\n", "\n", - "# for water at 5 deg C\n", "\n", "nu = 1.54*10**-6 # kinematic viscosity of water in m**2/s\n", "\n", - "# Solution\n", "\n", "R = v*d/nu\n", "\n", @@ -178,13 +164,10 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Horsepower required to pump 50 tons of oil\n", "\n", - "# Given\n", "\n", "from math import *\n", "\n", - "# oil properties\n", "\n", "S = 0.92 # specific gravity\n", "\n", @@ -198,7 +181,6 @@ "\n", "g = 32.2 # acceleration due to gravity in ft/s**2\n", "\n", - "# Solution\n", "\n", "Q = W*2000/(gma*3600) # discharge in ft**3/s\n", "\n", @@ -244,9 +226,7 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Viscosity of the liquid in poise\n", "\n", - "# Given\n", "\n", "from math import *\n", "\n", @@ -268,9 +248,7 @@ "\n", "a = pi*d1**2/4\n", "\n", - "# Solution\n", "\n", - "# From derivation we obtain a equation for T\n", "\n", "H2 = H1-(V/A)\n", "\n", @@ -303,13 +281,10 @@ "cell_type": "code", "collapsed": false, "input": [ - "# Velocity distribution; Discharge ; shear on the upper plate\n", "\n", - "# Given\n", "\n", "from math import *\n", "\n", - "# properties of kerosene oil at 20 deg C\n", "\n", "S = 0.81 # specific gravity of oil\n", "\n", @@ -327,35 +302,27 @@ "\n", "theta = pi/6 # angle of inclination\n", "\n", - "# Solution\n", "\n", - "# point 1\n", "\n", "P1 = p1*144 + gma*l*sin(theta)\n", "\n", - "# point 2\n", "\n", "P2 = p2*144\n", "\n", - "# flow is taking from poont 2-1\n", "\n", "Sp = (P2-P1)/4\n", "\n", - "# equation for u = 2154.75*y-359125*y**2\n", "\n", "y = h\n", "\n", - "# discharge per ft width\n", "\n", "q = (2154.75*y**2/2) - (359125*y**3/3)\n", "\n", "print \"Discharge q = \",round(q,3),\"per unit ft of the plate\"\n", "\n", - "# to find shear at the top of the plate take du/dy = 0\n", "\n", "dV = 2154.75 - 718250*h\n", "\n", - "# shear stress\n", "\n", "T = -mu*dV\n", "\n", |