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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:b809e6889d9fdf33446744d4f1caf3aac2e77607182761aeef234f4a6cc34adc"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Chapter : Turbomachines"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.1 Page no 443"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 12.1\n",
+ "\n",
+ "from math import *\n",
+ "\n",
+ "from __future__ import division\n",
+ "\n",
+ "# Given\n",
+ "\n",
+ "Q = 0.25 # discharge from the pump in m**3/s\n",
+ "\n",
+ "gma= 0.8*9810 # specific weight in kg/m**3\n",
+ "\n",
+ "H=25 # elevation head in m\n",
+ "\n",
+ "T = 350 # Torque to drive the shaft in Nm\n",
+ "\n",
+ "N = 1800 # Speed in RPM\n",
+ "\n",
+ "w = 2*pi*N/60 # angular velocity\n",
+ "\n",
+ "# Solution\n",
+ "\n",
+ "Eff = gma*Q*H*100/(T*w) # efficiency\n",
+ "\n",
+ "print \"Efficiency of th pump =\",round(Eff,0),\"%\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Efficiency of th pump = 74.0 %\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.2 Page no 447"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 12.2\n",
+ "\n",
+ "from math import *\n",
+ "\n",
+ "from __future__ import division\n",
+ "\n",
+ "# Given\n",
+ "\n",
+ "d = 0.4 # diameter of the pump in m\n",
+ "\n",
+ "b = 0.03 # width in m\n",
+ "\n",
+ "theta = pi/3 # blade angle\n",
+ "\n",
+ "N = 1500 # speed in RPM\n",
+ "\n",
+ "Q = 0.4 # flow rate in m**3/s\n",
+ "\n",
+ "g = 9.81 # acceleration due to gravity in m/s**2\n",
+ "\n",
+ "# Solution\n",
+ "\n",
+ "w = 2*pi*N/60 # anggular velocity in rad/s\n",
+ "\n",
+ "u2 = (d/2)*w # blade velocity in m/s\n",
+ "\n",
+ "V2r = Q/(2*pi*(d/2)*b) # relative velocity in m/s\n",
+ "\n",
+ "print \"(a)\"\n",
+ "\n",
+ "print \"Radial velocity at exit =\",round(V2r,1),\"m/s\"\n",
+ "\n",
+ "V2t = u2 - V2r*(cos(theta)/sin(theta))\n",
+ "\n",
+ "print \"Whirl velocity = \",round(V2t,1),\"m/s\"\n",
+ "\n",
+ "v2 = V2r/sin(theta)\n",
+ "\n",
+ "print \"Relative velocity = \",round(v2,2),\"m/s\"\n",
+ "\n",
+ "V2 = sqrt(V2t**2+V2r**2)\n",
+ "\n",
+ "print \"Actual velocity =\",round(V2,2),\"m/s\"\n",
+ "\n",
+ "print \"(b)\"\n",
+ "\n",
+ "H = u2*V2t/g\n",
+ "\n",
+ "print\"Head added for no inlet whirl =\",round(H,0),\"m\"\n",
+ "\n",
+ "print \"(c)\"\n",
+ "\n",
+ "P = g*Q*H\n",
+ "\n",
+ "print \"Power required =\",round(P,1),\"kW\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " (a)\n",
+ "Radial velocity at exit = 10.6 m/s\n",
+ "Whirl velocity = 25.3 m/s\n",
+ "Relative velocity = 12.25 m/s\n",
+ "Actual velocity = 27.43 m/s\n",
+ "(b)\n",
+ "Head added for no inlet whirl = 81.0 m\n",
+ "(c)\n",
+ "Power required = 317.8 kW\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.3 Page no 450"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 12.3\n",
+ "\n",
+ "from math import *\n",
+ "\n",
+ "from __future__ import division\n",
+ "\n",
+ "# Given\n",
+ "\n",
+ "d = 0.36 # diameter of the impeller of pump\n",
+ "\n",
+ "N = 1500 # Speed of impeller in RPM\n",
+ "\n",
+ "# Solution\n",
+ "\n",
+ "# For best efficiency\n",
+ "\n",
+ "Q1 = 82 # discharge in l/s\n",
+ "\n",
+ "H1 = 17.5 # Head in m\n",
+ "\n",
+ "Eta = 0.8 # efficiency \n",
+ "\n",
+ "Q2 = 100 # discharge in l/s\n",
+ "\n",
+ "H2 = 20 # head in m\n",
+ "\n",
+ "# Solving the simulataneous equation we get\n",
+ "\n",
+ "D2 = 38.45\n",
+ "\n",
+ "print \"Impeller size =\",round(D2,2),\"cm\"\n",
+ "\n",
+ "N2 = 1500 \n",
+ "\n",
+ "print \"Speed of the pump =\",round(N2,0),\"RPM\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Impeller size = 38.45 cm\n",
+ "Speed of the pump = 1500.0 RPM\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.4 Page no 454 "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 12.4\n",
+ "\n",
+ "from math import *\n",
+ "\n",
+ "from __future__ import division\n",
+ "\n",
+ "# Given\n",
+ "\n",
+ "q = 500 # discharge in cgm\n",
+ "\n",
+ "Q = 500/449 # discharge in ft**3/s\n",
+ "\n",
+ "D = 0.667 # diameter in ft\n",
+ "\n",
+ "A = pi*D**2/4\n",
+ "\n",
+ "V = Q/A # velocity in ft/s\n",
+ "\n",
+ "g = 32.2 # acceleration due to gravity in ft/s**2\n",
+ "\n",
+ "N = 1800 # speed in RPM\n",
+ "\n",
+ "# Solution\n",
+ "\n",
+ "# for water at 65 deg C\n",
+ "\n",
+ "nu = 1.134*10**-5 # viscosity in ft**2/s\n",
+ "\n",
+ "e = 0.00085 # epssilon in ft\n",
+ "\n",
+ "r = 0.001275 \n",
+ "\n",
+ "R = V*D/nu # reynolds no\n",
+ "\n",
+ "f = 0.022 # from moody's diagram\n",
+ "\n",
+ "Hl = V**2*(12.1+(f*224.9))/64.4\n",
+ "\n",
+ "hs = 119.4 + Hl\n",
+ "\n",
+ "print \"Discharge, Q = \",round(Q,2),\"ft**3/s\"\n",
+ "print \"Dynamic head of the pump, H =\",round(hs,1),\"m\"\n",
+ "\n",
+ "Ns = N*sqrt(q)/(hs)**(3/4)\n",
+ "\n",
+ "print \"Specific speed of the pump, Ns =\",round(Ns,0),\"RPM\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Discharge, Q = 1.11 ft**3/s\n",
+ "Dynamic head of the pump, H = 122.1 m\n",
+ "Specific speed of the pump, Ns = 1096.0 RPM\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.5 Page no 457"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 12.5 \n",
+ "\n",
+ "from math import *\n",
+ "\n",
+ "from __future__ import division\n",
+ "\n",
+ "# Given\n",
+ "\n",
+ "H = 60 # height in m\n",
+ "\n",
+ "Pb = 98*10**3 # barometric pressure in N/m**2\n",
+ "\n",
+ "Hl = 1 # head in m\n",
+ "\n",
+ "Pv = 1707 # vapour pressure \n",
+ "\n",
+ "sigma = 0.08\n",
+ "\n",
+ "w = 9810 # specific weight\n",
+ "\n",
+ "# Solution\n",
+ "\n",
+ "Npsh_m = sigma*60 # minimum NPSH\n",
+ "\n",
+ "Hsm = (Pb/w)-(Pv/w)-Npsh_m-Hl\n",
+ "\n",
+ "print \"Minimum value of static suction lift = \",round(Hsm,2),\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Minimum value of static suction lift = 4.02 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": []
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file