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diff --git a/Engineering_Thermodynamics_by_P._K._Nag/ch4.ipynb b/Engineering_Thermodynamics_by_P._K._Nag/ch4.ipynb new file mode 100755 index 00000000..d353eb40 --- /dev/null +++ b/Engineering_Thermodynamics_by_P._K._Nag/ch4.ipynb @@ -0,0 +1,353 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:eafe81375ae6bd6abb8d4dff5b78c1d88df56b904362e7f55dc57c603062c8b9" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 4 : First Law of Thermodynamics" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.1 Page No : 78" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "V1 = 0.3; \t\t\t# Initial volume in m3\n", + "V2 = 0.15; \t\t\t# Final volume in m3\n", + "P = 0.105e06; \t\t\t# Pressure in Pa\n", + "Q = -37.6e03; \t\t\t# Heat tranferred in J\n", + "\n", + "# Calculation\n", + "W = P*(V2-V1); \t\t\t# Work done\n", + "U = Q-W; \t\t\t# Internal energy change\n", + "\n", + "# Results\n", + "print \"Change in the internal energy of the system is %.2f kJ\"%(U/1000)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Change in the internal energy of the system is -21.85 kJ\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.2 Page No : 78" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "Qacb = 84e03;\n", + "Wacb = 32e03;\n", + "Uba = Qacb-Wacb; \t\t\t# Ub-Ua\n", + "\n", + "# Calculation and Results\n", + "# Part (a)\n", + "Wadb = 10.5e03; \n", + "Qadb = Uba+Wadb; \n", + "print \"The heat flow into the system along the path adb\",(Qadb/1000),\"kJ\"\n", + "\n", + "# Part (b)\n", + "Wb_a = -21e03;\n", + "Uab = - Uba;\n", + "Qb_a = Uab+Wb_a;\n", + "print \"The heat liberated along the path b-a is\",round(Qb_a/1000),\"kJ\"\n", + "\n", + "# Part (c)\n", + "Wdb = 0.; \t\t\t# Constant volume\n", + "Wad = 10.4e03; \n", + "Wadb = Wdb-Wad; \n", + "Ud = 42e03;\n", + "Ua = 0.;\n", + "Qad = Ud-Ua+Wad;\n", + "Qdb = Qadb-Qad; \n", + "print \"The heat absorbed in the path ad and db are\",round(Qdb/1000),\"kJ\",\"and\",round(Qad/1000),\"kJ\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The heat flow into the system along the path adb 62.5 kJ\n", + "The heat liberated along the path b-a is -73.0 kJ\n", + "The heat absorbed in the path ad and db are 10.0 kJ and 52.0 kJ\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.3 Page No : 79" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "# Process a-b\n", + "Qab = 0;\n", + "Wab = 2170; \t\t\t# in KJ/min\n", + "Eab = Qab-Wab; \n", + "\n", + "# Process b-c\n", + "Qbc = 21000;\n", + "Wbc = 0; \n", + "Ebc = Qbc-Wbc;\n", + "\n", + "# Process c-d\n", + "Qcd = -2100;\n", + "Ecd = -36600; \n", + "Wcd = Qcd-Ecd;\n", + "\n", + "# Calculation\n", + "# Process d-a\n", + "Q = -17000; \t\t\t# Total heat transfer\n", + "Qda = Q-Qab-Qbc-Qcd; \n", + "Eda = -Eab-Ebc-Ecd;\n", + "Wda = Qda-Eda;\n", + "M = [[Qab, Wab, Eab],[Qbc, Wbc ,Ebc],[Qcd, Wcd, Ecd],[Qda, Wda, Eda]];\n", + "process = [\"a-b\",\"b-c\",\"c-d\",\"d-a\"]\n", + "# Results\n", + "print \"The completed table is\"\n", + "print \" process Q W deltaE\"\n", + "for i in range(4):\n", + " print \"%10s\"%process[i],\n", + " for j in range(3):\n", + " print \"%10d\"%M[i][j],\n", + "\n", + " print \"\"\n", + "print \"\\nRate of work output : %.f kJ/min\"%(sum([M[0][0],M[1][0],M[2][0],M[3][0]]))\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The completed table is\n", + " process Q W deltaE\n", + " a-b 0 2170 -2170 \n", + " b-c 21000 0 21000 \n", + " c-d -2100 34500 -36600 \n", + " d-a -35900 -53670 17770 \n", + "\n", + "Rate of work output : -17000 kJ/min\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.4 Page No : 80" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Part (a)\n", + "import math \n", + "\n", + "# Variables\n", + "m = 3.;\n", + "V1 = 0.22; #volume m^3\n", + "P1 = 500.e03; #initial pressure Pa\n", + "P2 = 100.e03; #final pressure Pa\n", + "\n", + "# Calculation\n", + "V2 = V1*(P1/P2)**(1./1.2);\n", + "dU = 3.56*(P2*V2-P1*V1);\n", + "gama = 1.2;\n", + "W = (P2*V2-P1*V1)/(1-gama);\n", + "Q = dU+W;\n", + "\n", + "# Results\n", + "print \"Q,W and dU of the quasi static process are\",int(dU/1000),round(W/1000),round(Q/1000),\"kJ respectively\"\n", + "\n", + "# Part (b)\n", + "Qb = 30e03;\n", + "Wb = Qb-dU; \n", + "print \"Work transfer for the process is\",round(Wb/1000),\"kJ\"\n", + "\n", + "# Part (c)\n", + "print \"Wb is not equal to integral(p*dv) .since the process is not quasi static\"\n", + "\n", + "# rounding off error. please check" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Q,W and dU of the quasi static process are -92 129.0 37.0 kJ respectively\n", + "Work transfer for the process is 122.0 kJ\n", + "Wb is not equal to integral(p*dv) .since the process is not quasi static\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.5 Page No : 81" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from numpy.linalg import inv\n", + "from numpy import *\n", + "from scipy.integrate import *\n", + "\n", + "# Variables\n", + "V1 = 0.03; #initial volume m^3\n", + "P1 = 170e03; #initial pressure Pa\n", + "P2 = 400e03; #final pressure Pa\n", + "V2 = 0.06; #final volume m^3\n", + "U = 3.15*(P2*V2-P1*V1);\n", + "B = array([P1, P2]);\n", + "B= B.transpose()\n", + "\n", + "A = [[1, V1],[1, V2]];\n", + "A = array(A)\n", + "x = inv(A)*B;\n", + "\n", + "a = -60000\n", + "b = 7666666.7;\n", + "\n", + "# Calculation\n", + "def pressure(V):\n", + " return a+b*V;\n", + "\n", + "W = quad(pressure,V1,V2)[0]\n", + "Q = U+W;\n", + "\n", + "# Results\n", + "print \"The work done by the system is\",round(W/1000,2),\"kJ\"\n", + "print \"The internal energy change of the system is\",round(U/1000,1),\"J\"\n", + "print \"The heat flow into the system is\",round(Q/1000,2),\"kJ\"\n", + "\n", + "# rounding off error. please check." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The work done by the system is 8.55 kJ\n", + "The internal energy change of the system is 59.5 J\n", + "The heat flow into the system is 68.09 kJ\n" + ] + } + ], + "prompt_number": 36 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.6 Page No : 82" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Process 1-2\n", + "import math \n", + "\n", + "# Variables\n", + "Q12 = 235; \t\t\t# in KJ/Kg\n", + "W12 = 0 ;\n", + "\n", + "# Calculation\n", + "U12 = Q12-W12;\n", + "# Process 2-3\n", + "Q23 = 0; \n", + "U23 = -70 ;\n", + "W23 = Q23-U23;\n", + "\n", + "# Process 3-1\n", + "Q31 = - 200; \n", + "U31 = -U12-U23;\n", + "W31 = Q31-U31;\n", + "W = W12 + W23 + W31;\n", + "Q = Q12 + Q23 + Q31;\n", + "\n", + "# Results\n", + "print \"Heat trasfer in the cycle is\",Q,\"KJ/Kg\"\n", + "print \"Work done during the the cycle is\",W,\"KJ/Kg\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Heat trasfer in the cycle is 35 KJ/Kg\n", + "Work done during the the cycle is 35 KJ/Kg\n" + ] + } + ], + "prompt_number": 39 + } + ], + "metadata": {} + } + ] +}
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