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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:eafe81375ae6bd6abb8d4dff5b78c1d88df56b904362e7f55dc57c603062c8b9"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 4 : First Law of Thermodynamics"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.1 Page No : 78"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "# Variables\n",
+ "V1 = 0.3; \t\t\t# Initial volume in m3\n",
+ "V2 = 0.15; \t\t\t# Final volume in m3\n",
+ "P = 0.105e06; \t\t\t# Pressure in Pa\n",
+ "Q = -37.6e03; \t\t\t# Heat tranferred in J\n",
+ "\n",
+ "# Calculation\n",
+ "W = P*(V2-V1); \t\t\t# Work done\n",
+ "U = Q-W; \t\t\t# Internal energy change\n",
+ "\n",
+ "# Results\n",
+ "print \"Change in the internal energy of the system is %.2f kJ\"%(U/1000)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Change in the internal energy of the system is -21.85 kJ\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.2 Page No : 78"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "# Variables\n",
+ "Qacb = 84e03;\n",
+ "Wacb = 32e03;\n",
+ "Uba = Qacb-Wacb; \t\t\t# Ub-Ua\n",
+ "\n",
+ "# Calculation and Results\n",
+ "# Part (a)\n",
+ "Wadb = 10.5e03; \n",
+ "Qadb = Uba+Wadb; \n",
+ "print \"The heat flow into the system along the path adb\",(Qadb/1000),\"kJ\"\n",
+ "\n",
+ "# Part (b)\n",
+ "Wb_a = -21e03;\n",
+ "Uab = - Uba;\n",
+ "Qb_a = Uab+Wb_a;\n",
+ "print \"The heat liberated along the path b-a is\",round(Qb_a/1000),\"kJ\"\n",
+ "\n",
+ "# Part (c)\n",
+ "Wdb = 0.; \t\t\t# Constant volume\n",
+ "Wad = 10.4e03; \n",
+ "Wadb = Wdb-Wad; \n",
+ "Ud = 42e03;\n",
+ "Ua = 0.;\n",
+ "Qad = Ud-Ua+Wad;\n",
+ "Qdb = Qadb-Qad; \n",
+ "print \"The heat absorbed in the path ad and db are\",round(Qdb/1000),\"kJ\",\"and\",round(Qad/1000),\"kJ\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The heat flow into the system along the path adb 62.5 kJ\n",
+ "The heat liberated along the path b-a is -73.0 kJ\n",
+ "The heat absorbed in the path ad and db are 10.0 kJ and 52.0 kJ\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.3 Page No : 79"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "# Variables\n",
+ "# Process a-b\n",
+ "Qab = 0;\n",
+ "Wab = 2170; \t\t\t# in KJ/min\n",
+ "Eab = Qab-Wab; \n",
+ "\n",
+ "# Process b-c\n",
+ "Qbc = 21000;\n",
+ "Wbc = 0; \n",
+ "Ebc = Qbc-Wbc;\n",
+ "\n",
+ "# Process c-d\n",
+ "Qcd = -2100;\n",
+ "Ecd = -36600; \n",
+ "Wcd = Qcd-Ecd;\n",
+ "\n",
+ "# Calculation\n",
+ "# Process d-a\n",
+ "Q = -17000; \t\t\t# Total heat transfer\n",
+ "Qda = Q-Qab-Qbc-Qcd; \n",
+ "Eda = -Eab-Ebc-Ecd;\n",
+ "Wda = Qda-Eda;\n",
+ "M = [[Qab, Wab, Eab],[Qbc, Wbc ,Ebc],[Qcd, Wcd, Ecd],[Qda, Wda, Eda]];\n",
+ "process = [\"a-b\",\"b-c\",\"c-d\",\"d-a\"]\n",
+ "# Results\n",
+ "print \"The completed table is\"\n",
+ "print \" process Q W deltaE\"\n",
+ "for i in range(4):\n",
+ " print \"%10s\"%process[i],\n",
+ " for j in range(3):\n",
+ " print \"%10d\"%M[i][j],\n",
+ "\n",
+ " print \"\"\n",
+ "print \"\\nRate of work output : %.f kJ/min\"%(sum([M[0][0],M[1][0],M[2][0],M[3][0]]))\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The completed table is\n",
+ " process Q W deltaE\n",
+ " a-b 0 2170 -2170 \n",
+ " b-c 21000 0 21000 \n",
+ " c-d -2100 34500 -36600 \n",
+ " d-a -35900 -53670 17770 \n",
+ "\n",
+ "Rate of work output : -17000 kJ/min\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.4 Page No : 80"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Part (a)\n",
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "m = 3.;\n",
+ "V1 = 0.22; #volume m^3\n",
+ "P1 = 500.e03; #initial pressure Pa\n",
+ "P2 = 100.e03; #final pressure Pa\n",
+ "\n",
+ "# Calculation\n",
+ "V2 = V1*(P1/P2)**(1./1.2);\n",
+ "dU = 3.56*(P2*V2-P1*V1);\n",
+ "gama = 1.2;\n",
+ "W = (P2*V2-P1*V1)/(1-gama);\n",
+ "Q = dU+W;\n",
+ "\n",
+ "# Results\n",
+ "print \"Q,W and dU of the quasi static process are\",int(dU/1000),round(W/1000),round(Q/1000),\"kJ respectively\"\n",
+ "\n",
+ "# Part (b)\n",
+ "Qb = 30e03;\n",
+ "Wb = Qb-dU; \n",
+ "print \"Work transfer for the process is\",round(Wb/1000),\"kJ\"\n",
+ "\n",
+ "# Part (c)\n",
+ "print \"Wb is not equal to integral(p*dv) .since the process is not quasi static\"\n",
+ "\n",
+ "# rounding off error. please check"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Q,W and dU of the quasi static process are -92 129.0 37.0 kJ respectively\n",
+ "Work transfer for the process is 122.0 kJ\n",
+ "Wb is not equal to integral(p*dv) .since the process is not quasi static\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.5 Page No : 81"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from numpy.linalg import inv\n",
+ "from numpy import *\n",
+ "from scipy.integrate import *\n",
+ "\n",
+ "# Variables\n",
+ "V1 = 0.03; #initial volume m^3\n",
+ "P1 = 170e03; #initial pressure Pa\n",
+ "P2 = 400e03; #final pressure Pa\n",
+ "V2 = 0.06; #final volume m^3\n",
+ "U = 3.15*(P2*V2-P1*V1);\n",
+ "B = array([P1, P2]);\n",
+ "B= B.transpose()\n",
+ "\n",
+ "A = [[1, V1],[1, V2]];\n",
+ "A = array(A)\n",
+ "x = inv(A)*B;\n",
+ "\n",
+ "a = -60000\n",
+ "b = 7666666.7;\n",
+ "\n",
+ "# Calculation\n",
+ "def pressure(V):\n",
+ " return a+b*V;\n",
+ "\n",
+ "W = quad(pressure,V1,V2)[0]\n",
+ "Q = U+W;\n",
+ "\n",
+ "# Results\n",
+ "print \"The work done by the system is\",round(W/1000,2),\"kJ\"\n",
+ "print \"The internal energy change of the system is\",round(U/1000,1),\"J\"\n",
+ "print \"The heat flow into the system is\",round(Q/1000,2),\"kJ\"\n",
+ "\n",
+ "# rounding off error. please check."
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The work done by the system is 8.55 kJ\n",
+ "The internal energy change of the system is 59.5 J\n",
+ "The heat flow into the system is 68.09 kJ\n"
+ ]
+ }
+ ],
+ "prompt_number": 36
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.6 Page No : 82"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Process 1-2\n",
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "Q12 = 235; \t\t\t# in KJ/Kg\n",
+ "W12 = 0 ;\n",
+ "\n",
+ "# Calculation\n",
+ "U12 = Q12-W12;\n",
+ "# Process 2-3\n",
+ "Q23 = 0; \n",
+ "U23 = -70 ;\n",
+ "W23 = Q23-U23;\n",
+ "\n",
+ "# Process 3-1\n",
+ "Q31 = - 200; \n",
+ "U31 = -U12-U23;\n",
+ "W31 = Q31-U31;\n",
+ "W = W12 + W23 + W31;\n",
+ "Q = Q12 + Q23 + Q31;\n",
+ "\n",
+ "# Results\n",
+ "print \"Heat trasfer in the cycle is\",Q,\"KJ/Kg\"\n",
+ "print \"Work done during the the cycle is\",W,\"KJ/Kg\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Heat trasfer in the cycle is 35 KJ/Kg\n",
+ "Work done during the the cycle is 35 KJ/Kg\n"
+ ]
+ }
+ ],
+ "prompt_number": 39
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file