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diff --git a/Engineering_Physics/chapter8_2.ipynb b/Engineering_Physics/chapter8_2.ipynb deleted file mode 100755 index 2dc13b1f..00000000 --- a/Engineering_Physics/chapter8_2.ipynb +++ /dev/null @@ -1,253 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:064d55405a5d05f007b28f32cf39a9f99d10f303fc4084e2d14d99aaeb87858c" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Physics of Nano Materials" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 8.1, Page number 320" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#import modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable decleration\n", - "r=5; #radius in m\n", - "pi=3.14;\n", - "\n", - "#Calculation \n", - "SA=4*pi*r**2; #surface area of sphere in m^2\n", - "V=(4/3)*pi*r**3; #volume of sphere in m^3\n", - "R=SA/V; #ratio\n", - "#surface area to volume ratio can also be given by 3/radius\n", - "\n", - "#Result\n", - "print(\"surface area to volume ratio of sphere in m-1 is\",R);" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "('surface area to volume ratio of sphere in m-1 is', 0.6)\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 8.2, Page number 321" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#import modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable decleration\n", - "d=26; #distance in m\n", - "r=d/2; #radius in m\n", - "pi=3.14;\n", - "\n", - "#Calculation\n", - "SA=4*pi*r**2; #surface area of sphere in m^2\n", - "V=(4/3)*pi*r**3; #volume of sphere in m^3\n", - "R=SA/V; #ratio\n", - "R=math.ceil(R*10**3)/10**3; #rounding off to 3 decimals\n", - "#surface area to volume ratio can also be given by 3/radius\n", - "\n", - "#Result\n", - "print(\"surface area to volume ratio of sphere in m-1 is\",R);" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "('surface area to volume ratio of sphere in m-1 is', 0.231)\n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 8.3, Page number 321" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#import modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable decleration\n", - "r=1; #radius in m\n", - "h=1; #height in m\n", - "pi=3.14\n", - "\n", - "#Calculation\n", - "V=(1/3)*pi*(r**2)*h;\n", - "V=math.ceil(V*10**2)/10**2; #rounding off to 2 decimals\n", - "\n", - "#Result\n", - "print(\"volume of cone in m^3 is\",V); " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "('volume of cone in m^3 is', 1.05)\n" - ] - } - ], - "prompt_number": 11 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 8.4, Page number 321" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#import modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable decleration\n", - "r=3; # radius in m\n", - "h=4; # height in m\n", - "pi=3.14\n", - "\n", - "#Calculation\n", - "SA=pi*r*math.sqrt((r**2)+(h**2));\n", - "TSA=SA+(pi*r**2);\n", - "\n", - "#Result\n", - "print(\"total surface area of cone in m^2 is\",TSA);\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "('total surface area of cone in m^2 is', 75.36)\n" - ] - } - ], - "prompt_number": 16 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 8.5, Page number 322" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#import modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable decleration\n", - "V=100; #volume of cone in cubic inches\n", - "r=5; #radius of cone in inches\n", - "pi=3.14;\n", - "\n", - "#Calculation\n", - "r_m=r*0.0254; #radius of cone in m\n", - "#volume V=(1/3)*pi*(r**2)*h\n", - "#therefore h = (3*V)/(pi*r**2)\n", - "h=(3*V)/(pi*r**2); #height in inches\n", - "R=3/r_m;\n", - "h=math.ceil(h*10**3)/10**3; #rounding off to 3 decimals\n", - "\n", - "#Result\n", - "print(\"height of the cone in inches is\",h);\n", - "print(\"surface area to volume ratio in m-1 is\",R);\n", - "\n", - "#answer for the surface area to volume ratio given in the book is wrong" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "('height of the cone in inches is', 3.822)\n", - "('surface area to volume ratio in m-1 is', 23.62204724409449)\n" - ] - } - ], - "prompt_number": 18 - }, - { - "cell_type": "code", - "collapsed": false, - "input": [], - "language": "python", - "metadata": {}, - "outputs": [] - } - ], - "metadata": {} - } - ] -}
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