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-rw-r--r--Engineering_Physics/chapter8_2.ipynb156
1 files changed, 138 insertions, 18 deletions
diff --git a/Engineering_Physics/chapter8_2.ipynb b/Engineering_Physics/chapter8_2.ipynb
index c344140a..2dc13b1f 100644
--- a/Engineering_Physics/chapter8_2.ipynb
+++ b/Engineering_Physics/chapter8_2.ipynb
@@ -1,6 +1,7 @@
{
"metadata": {
- "name": "chapter8"
+ "name": "",
+ "signature": "sha256:064d55405a5d05f007b28f32cf39a9f99d10f303fc4084e2d14d99aaeb87858c"
},
"nbformat": 3,
"nbformat_minor": 0,
@@ -11,25 +12,49 @@
"cell_type": "heading",
"level": 1,
"metadata": {},
- "source": "Physics of Nano Materials"
+ "source": [
+ "Physics of Nano Materials"
+ ]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
- "source": "Example number 8.1, Page number 320"
+ "source": [
+ "Example number 8.1, Page number 320"
+ ]
},
{
"cell_type": "code",
"collapsed": false,
- "input": "# To calculate the surface area to volume ratio\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=5; #radius in m\npi=3.14;\n\n#Calculation \nSA=4*pi*r**2; #surface area of sphere in m^2\nV=(4/3)*pi*r**3; #volume of sphere in m^3\nR=SA/V; #ratio\n#surface area to volume ratio can also be given by 3/radius\n\n#Result\nprint(\"surface area to volume ratio of sphere in m-1 is\",R);",
+ "input": [
+ " \n",
+ "#import modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable decleration\n",
+ "r=5; #radius in m\n",
+ "pi=3.14;\n",
+ "\n",
+ "#Calculation \n",
+ "SA=4*pi*r**2; #surface area of sphere in m^2\n",
+ "V=(4/3)*pi*r**3; #volume of sphere in m^3\n",
+ "R=SA/V; #ratio\n",
+ "#surface area to volume ratio can also be given by 3/radius\n",
+ "\n",
+ "#Result\n",
+ "print(\"surface area to volume ratio of sphere in m-1 is\",R);"
+ ],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
- "text": "('surface area to volume ratio of sphere in m-1 is', 0.6)\n"
+ "text": [
+ "('surface area to volume ratio of sphere in m-1 is', 0.6)\n"
+ ]
}
],
"prompt_number": 5
@@ -38,19 +63,43 @@
"cell_type": "heading",
"level": 2,
"metadata": {},
- "source": "Example number 8.2, Page number 321"
+ "source": [
+ "Example number 8.2, Page number 321"
+ ]
},
{
"cell_type": "code",
"collapsed": false,
- "input": "# To calculate the surface area to volume ratio\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nd=26; #distance in m\nr=d/2; #radius in m\npi=3.14;\n\n#Calculation\nSA=4*pi*r**2; #surface area of sphere in m^2\nV=(4/3)*pi*r**3; #volume of sphere in m^3\nR=SA/V; #ratio\nR=math.ceil(R*10**3)/10**3; #rounding off to 3 decimals\n#surface area to volume ratio can also be given by 3/radius\n\n#Result\nprint(\"surface area to volume ratio of sphere in m-1 is\",R);",
+ "input": [
+ " \n",
+ "#import modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable decleration\n",
+ "d=26; #distance in m\n",
+ "r=d/2; #radius in m\n",
+ "pi=3.14;\n",
+ "\n",
+ "#Calculation\n",
+ "SA=4*pi*r**2; #surface area of sphere in m^2\n",
+ "V=(4/3)*pi*r**3; #volume of sphere in m^3\n",
+ "R=SA/V; #ratio\n",
+ "R=math.ceil(R*10**3)/10**3; #rounding off to 3 decimals\n",
+ "#surface area to volume ratio can also be given by 3/radius\n",
+ "\n",
+ "#Result\n",
+ "print(\"surface area to volume ratio of sphere in m-1 is\",R);"
+ ],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
- "text": "('surface area to volume ratio of sphere in m-1 is', 0.231)\n"
+ "text": [
+ "('surface area to volume ratio of sphere in m-1 is', 0.231)\n"
+ ]
}
],
"prompt_number": 7
@@ -59,19 +108,40 @@
"cell_type": "heading",
"level": 2,
"metadata": {},
- "source": "Example number 8.3, Page number 321"
+ "source": [
+ "Example number 8.3, Page number 321"
+ ]
},
{
"cell_type": "code",
"collapsed": false,
- "input": "# To calculate the volume of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=1; #radius in m\nh=1; #height in m\npi=3.14\n\n#Calculation\nV=(1/3)*pi*(r**2)*h;\nV=math.ceil(V*10**2)/10**2; #rounding off to 2 decimals\n\n#Result\nprint(\"volume of cone in m^3 is\",V); ",
+ "input": [
+ " \n",
+ "#import modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable decleration\n",
+ "r=1; #radius in m\n",
+ "h=1; #height in m\n",
+ "pi=3.14\n",
+ "\n",
+ "#Calculation\n",
+ "V=(1/3)*pi*(r**2)*h;\n",
+ "V=math.ceil(V*10**2)/10**2; #rounding off to 2 decimals\n",
+ "\n",
+ "#Result\n",
+ "print(\"volume of cone in m^3 is\",V); "
+ ],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
- "text": "('volume of cone in m^3 is', 1.05)\n"
+ "text": [
+ "('volume of cone in m^3 is', 1.05)\n"
+ ]
}
],
"prompt_number": 11
@@ -80,19 +150,40 @@
"cell_type": "heading",
"level": 2,
"metadata": {},
- "source": "Example number 8.4, Page number 321"
+ "source": [
+ "Example number 8.4, Page number 321"
+ ]
},
{
"cell_type": "code",
"collapsed": false,
- "input": "# To calculate the total surface area of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nr=3; # radius in m\nh=4; # height in m\npi=3.14\n\n#Calculation\nSA=pi*r*math.sqrt((r**2)+(h**2));\nTSA=SA+(pi*r**2);\n\n#Result\nprint(\"total surface area of cone in m^2 is\",TSA);\n",
+ "input": [
+ " \n",
+ "#import modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable decleration\n",
+ "r=3; # radius in m\n",
+ "h=4; # height in m\n",
+ "pi=3.14\n",
+ "\n",
+ "#Calculation\n",
+ "SA=pi*r*math.sqrt((r**2)+(h**2));\n",
+ "TSA=SA+(pi*r**2);\n",
+ "\n",
+ "#Result\n",
+ "print(\"total surface area of cone in m^2 is\",TSA);\n"
+ ],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
- "text": "('total surface area of cone in m^2 is', 75.36)\n"
+ "text": [
+ "('total surface area of cone in m^2 is', 75.36)\n"
+ ]
}
],
"prompt_number": 16
@@ -101,19 +192,48 @@
"cell_type": "heading",
"level": 2,
"metadata": {},
- "source": "Example number 8.5, Page number 322"
+ "source": [
+ "Example number 8.5, Page number 322"
+ ]
},
{
"cell_type": "code",
"collapsed": false,
- "input": "# To calculate the height of cone\n\n#import modules\nimport math\nfrom __future__ import division\n\n#Variable decleration\nV=100; #volume of cone in cubic inches\nr=5; #radius of cone in inches\npi=3.14;\n\n#Calculation\nr_m=r*0.0254; #radius of cone in m\n#volume V=(1/3)*pi*(r**2)*h\n#therefore h = (3*V)/(pi*r**2)\nh=(3*V)/(pi*r**2); #height in inches\nR=3/r_m;\nh=math.ceil(h*10**3)/10**3; #rounding off to 3 decimals\n\n#Result\nprint(\"height of the cone in inches is\",h);\nprint(\"surface area to volume ratio in m-1 is\",R);\n\n#answer for the surface area to volume ratio given in the book is wrong",
+ "input": [
+ " \n",
+ "#import modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable decleration\n",
+ "V=100; #volume of cone in cubic inches\n",
+ "r=5; #radius of cone in inches\n",
+ "pi=3.14;\n",
+ "\n",
+ "#Calculation\n",
+ "r_m=r*0.0254; #radius of cone in m\n",
+ "#volume V=(1/3)*pi*(r**2)*h\n",
+ "#therefore h = (3*V)/(pi*r**2)\n",
+ "h=(3*V)/(pi*r**2); #height in inches\n",
+ "R=3/r_m;\n",
+ "h=math.ceil(h*10**3)/10**3; #rounding off to 3 decimals\n",
+ "\n",
+ "#Result\n",
+ "print(\"height of the cone in inches is\",h);\n",
+ "print(\"surface area to volume ratio in m-1 is\",R);\n",
+ "\n",
+ "#answer for the surface area to volume ratio given in the book is wrong"
+ ],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
- "text": "('height of the cone in inches is', 3.822)\n('surface area to volume ratio in m-1 is', 23.62204724409449)\n"
+ "text": [
+ "('height of the cone in inches is', 3.822)\n",
+ "('surface area to volume ratio in m-1 is', 23.62204724409449)\n"
+ ]
}
],
"prompt_number": 18
@@ -121,7 +241,7 @@
{
"cell_type": "code",
"collapsed": false,
- "input": "",
+ "input": [],
"language": "python",
"metadata": {},
"outputs": []