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Diffstat (limited to 'Engineering_Physics/Chapter_7.ipynb')
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diff --git a/Engineering_Physics/Chapter_7.ipynb b/Engineering_Physics/Chapter_7.ipynb deleted file mode 100755 index acb1144d..00000000 --- a/Engineering_Physics/Chapter_7.ipynb +++ /dev/null @@ -1,185 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:0a8ebb52dee60395969030b1d2962543e204a93314e21a66724d3bafb10b7ddf" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Crystal Imperfections" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 7.1, Page number 207 " - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#importing modules\n", - "import math\n", - "\n", - "#Variable declaration\n", - "k=1.38*10**-23;\n", - "Ev=0.98; #energy in eV/atom\n", - "T1=900; #temperature in C\n", - "T2=1000;\n", - "A=6.022*10**26; #avagadro's constant\n", - "w=196.9; #atomic weight in g/mol\n", - "d=18.63; #density in g/cm^3\n", - "\n", - "#Calculation\n", - "Ev=Ev*1.6*10**-19; #converting eV to J\n", - "d=d*10**3; #converting g/cm^3 into kg/m^3\n", - "N=(A*d)/w;\n", - "n=N*math.exp(-Ev/(k*T1));\n", - "#let valency fraction n/N be V\n", - "V=math.exp(-Ev/(k*T2));\n", - "\n", - "#Result\n", - "print(\"concentration of atoms per m^3 is\",N);\n", - "print(\"number of vacancies per m^3 is\",n);\n", - "print(\"valency fraction is\",V);\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "('concentration of atoms per m^3 is', 5.69780904012189e+28)\n", - "('number of vacancies per m^3 is', 1.8742498047705634e+23)\n", - "('valency fraction is', 1.1625392535344139e-05)\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 7.2, Page number 208 " - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#importing modules\n", - "import math\n", - "\n", - "#Variable declaration\n", - "k=1.38*10**-23;\n", - "A=6.022*10**26; #avagadro's constant\n", - "T=1073; #temperature in K\n", - "n=3.6*10**23; #number of vacancies\n", - "d=9.5; #density in g/cm^3\n", - "w=107.9; #atomic weight in g/mol\n", - "\n", - "#Calculation\n", - "d=d*10**3; #converting g/cm^3 into kg/m^3\n", - "N=(A*d)/w; #concentration of atoms\n", - "E=k*T*math.log((N/n), ); #energy in J\n", - "EeV=E/(1.602176565*10**-19); #energy in eV\n", - "EeV=math.ceil(EeV*10**2)/10**2; #rounding off to 2 decimals\n", - "\n", - "#Result\n", - "print(\"concentration of atoms per m^3 is\",N);\n", - "print(\"energy for vacancy formation in J\",E);\n", - "print(\"energy for vacancy formation in eV\",EeV);" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "('concentration of atoms per m^3 is', 5.3020389249304915e+28)\n", - "('energy for vacancy formation in J', 1.762092900344914e-19)\n", - "('energy for vacancy formation in eV', 1.1)\n" - ] - } - ], - "prompt_number": 6 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 7.3, Page number 209 " - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#importing modules\n", - "import math\n", - "\n", - "#Variable declaration\n", - "A=6.022*10**26; #avagadro's constant\n", - "k=1.38*10**-23;\n", - "w1=39.1; #atomic weight of K\n", - "w2=35.45; #atomic weight of Cl\n", - "Es=2.6; #energy formation in eV\n", - "T=500; #temperature in C\n", - "d=1.955; #density in g/cm^3\n", - "\n", - "#Calculation\n", - "Es=Es*1.6*10**-19; #converting eV to J\n", - "T=T+273; #temperature in K\n", - "d=d*10**3; #converting g/cm^3 into kg/m^3\n", - "N=(A*d)/(w1+w2);\n", - "n=N*math.exp(-Es/(2*k*T));\n", - "\n", - "#Result\n", - "print(\"number of Schotky defect per m^3 is\",n);\n", - "\n", - "#answer given in the book is wrong by 3rd decimal point" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "('number of Schotky defect per m^3 is', 5.373777171020081e+19)\n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "code", - "collapsed": false, - "input": [], - "language": "python", - "metadata": {}, - "outputs": [] - } - ], - "metadata": {} - } - ] -}
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