diff options
Diffstat (limited to 'Engineering_Physics/Chapter2.ipynb')
-rwxr-xr-x | Engineering_Physics/Chapter2.ipynb | 84 |
1 files changed, 84 insertions, 0 deletions
diff --git a/Engineering_Physics/Chapter2.ipynb b/Engineering_Physics/Chapter2.ipynb new file mode 100755 index 00000000..fff10b22 --- /dev/null +++ b/Engineering_Physics/Chapter2.ipynb @@ -0,0 +1,84 @@ +{ + "metadata": { + "name": "Chapter2", + "signature": "sha256:ac80f9dfe1725f11a5d4ce0fbda5ffed825d99c680f116629e5e3fcb8b69c198" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": "2: Lasers" + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example number 2.1, Page number 52" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "#importing modules\nimport math\n\n#Variable declaration\nlamda = 590; #wavelength(nm)\nh = 6.625*10**-34; #planck's constant\nc = 3*10**8; #velocity of light(m/s)\nk = 1.38*10**-23; #boltzmann's constant\nT = 523; #temperature(Kelvin)\n\n#Calculation\nlamda = lamda*10**-9; #wavelength(m) \n#n1byn2 = math.exp(-(E2-E1)/(k*T))\n#but E2-E1 = h*new and new = c/lamda\n#therefore n1byn2 = math.exp(-h*c/(lamda*k*T))\nn1byn2 = math.exp(-h*c/(lamda*k*T));\n\n#Result\nprint \"relative population of Na atoms is\",n1byn2", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "relative population of Na atoms is 5.36748316686e-21\n" + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example number 2.2, Page number 53" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "#importing modules\nimport math\n\n#Variable declaration\nlamda = 590; #wavelength(nm)\nh = 6.625*10**-34; #planck's constant\nc = 3*10**8; #velocity of light(m/s)\nk = 1.38*10**-23; #boltzmann's constant\nT = 523; #temperature(Kelvin)\n\n#Calculation\nlamda = lamda*10**-9; #wavelength(m) \n#n21dashbyn21 = 1/(math.exp(h*new/(k*T))-1)\n#but new = c/lamda\n#therefore n21dashbyn21 = 1/(math.exp(h*c/(lamda*k*T))-1)\nA = math.exp(h*c/(lamda*k*T))-1;\nn21dashbyn21 = 1/A; \n\n#Result\nprint \"ratio of stimulated to spontaneous emission is\",n21dashbyn21\nprint \"answer given in the book is wrong\"", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "ratio of stimulated to spontaneous emission is 5.36748316686e-21\nanswer given in the book is wrong\n" + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example number 2.3, Page number 53" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "#importing modules\nimport math\n\n#Variable declaration\nlamda = 632.8; #wavelength of laser(nm)\nh = 6.625*10**-34; #planck's constant\nc = 3*10**8; #velocity of light(m/s)\np = 3.147; #output power(mW)\n\n#Calculation\np = p*10**-3; #output power(W)\nlamda = lamda*10**-9; #wavelength(m) \nnew = c/lamda; #frequency(Hz)\nE = h*new; #energy of each photon(J)\nEm = p*60; #energy emitted per minute(J/min)\nN = Em/E; #number of photons emitted per second\n\n#Result\nprint \"number of photons emitted per second is\",N", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "number of photons emitted per second is 6.01183879245e+17\n" + } + ], + "prompt_number": 3 + } + ], + "metadata": {} + } + ] +}
\ No newline at end of file |