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diff --git a/Engineering_Physics/Chapter13_1.ipynb b/Engineering_Physics/Chapter13_1.ipynb deleted file mode 100755 index 75d0d1f7..00000000 --- a/Engineering_Physics/Chapter13_1.ipynb +++ /dev/null @@ -1,340 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:be254bf95838dd01a87a63582117a886c3167a80cf387f9901b2e2de7a990b8e" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "13: Dielectric Properties of Materials" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 13.1, Page number 287" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "\n", - "#importing modules\n", - "import math\n", - "\n", - "#Variable declaration\n", - "epsilon_0 = 8.85*10**-12; #Absolute electrical permittivity of free space(F/m)\n", - "R = 0.52; #Radius of hydrogen atom(A)\n", - "n = 9.7*10**26; #Number density of hydrogen(per metre cube)\n", - "\n", - "#Calculation\n", - "R = R*10**-10; #Radius of hydrogen atom(m)\n", - "alpha_e = 4*math.pi*epsilon_0*R**3; #Electronic polarizability of hydrogen atom(Fm**2)\n", - "\n", - "#Result\n", - "print \"The electronic polarizability of hydrogen atom is\", alpha_e, \"Fm**2\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The electronic polarizability of hydrogen atom is 1.56373503182e-41 Fm**2\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 13.2, Page number 287" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "\n", - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "epsilon_0 = 8.854*10**-12; #Absolute electrical permittivity of free space(F/m)\n", - "A = 100; #Area of a plate of parallel plate capacitor(cm**2)\n", - "d = 1; #Distance between the plates of the capacitor(cm)\n", - "V = 100; #Potential applied to the plates of the capacitor(V)\n", - "\n", - "#Calculation\n", - "A= A*10**-4; #Area of a plate of parallel plate capacitor(m**2)\n", - "d = d*10**-2; #Distance between the plates of the capacitor(m)\n", - "C = epsilon_0*A/d; #Capacitance of parallel plate capacitor(F)\n", - "Q = C*V; #Charge on the plates of the capacitor(C)\n", - "\n", - "#Result\n", - "print \"The capacitance of parallel plate capacitor is\",C, \"F\"\n", - "print \"The charge on the plates of the capacitor is\",Q, \"C\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The capacitance of parallel plate capacitor is 8.854e-12 F\n", - "The charge on the plates of the capacitor is 8.854e-10 C\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 13.3, Page number 288" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "\n", - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "epsilon_0 = 8.854*10**-12; #Absolute electrical permittivity of free space(F/m)\n", - "epsilon_r = 5.0; #Dielectric constant of the material between the plates of capacitor\n", - "V = 15; #Potential difference applied between the plates of the capacitor(V)\n", - "d = 1.5; #Separation between the plates of the capacitor(mm)\n", - "\n", - "#Calculation\n", - "d = d*10**-3; #Separation between the plates of the capacitor(m)\n", - "#Electric displacement, D = epsilon_0*epsilon_r*E, as E = V/d, so \n", - "D = epsilon_0*epsilon_r*V/d; #Dielectric displacement(C/m**2)\n", - "\n", - "#Result\n", - "print \"The dielectric displacement is\",D, \"C/m**2\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The dielectric displacement is 4.427e-07 C/m**2\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 13.4, Page number 288" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "epsilon_0 = 8.854*10**-12; #Absolute electrical permittivity of free space(F/m)\n", - "N = 3*10**28; #Number density of solid elemental dielectric(atoms/metre cube)\n", - "alpha_e = 10**-40; #Electronic polarizability(Fm**2)\n", - "\n", - "#Calculation\n", - "epsilon_r = 1 + (N*alpha_e/epsilon_0); #Relative dielectric constant of the material\n", - "epsilon_r = math.ceil(epsilon_r*10**3)/10**3; #rounding off the value of epsilon_r to 3 decimals\n", - "\n", - "#Result\n", - "print \"The Relative dielectric constant of the material is\",epsilon_r\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The Relative dielectric constant of the material is 1.339\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 13.5, Page number 288" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "\n", - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "N_A = 6.02*10**23; #Avogadro's number(per mole)\n", - "epsilon_0 = 8.854*10**-12; #Absolute electrical permittivity of free space(F/m)\n", - "epsilon_r = 3.75; #Relative dielectric constant\n", - "d = 2050; #Density of sulphur(kg/metre cube)\n", - "y = 1/3; #Internal field constant\n", - "M = 32; #Atomic weight of sulphur(g/mol)\n", - "\n", - "#Calculation\n", - "N = N_A*10**3*d/M; #Number density of atoms of sulphur(per metre cube)\n", - "#Lorentz relation for local fields give E_local = E + P/(3*epsilon_0) which gives\n", - "#(epsilon_r - 1)/(epsilon_r + 2) = N*alpha_e/(3*epsilon_0), solving for alpha_e\n", - "alpha_e = (epsilon_r - 1)/(epsilon_r + 2)*3*epsilon_0/N; #Electronic polarizability of sulphur(Fm**2)\n", - "\n", - "#Result\n", - "print \"The electronic polarizability of sulphur is\",alpha_e, \"Fm**2\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The electronic polarizability of sulphur is 3.2940125351e-40 Fm**2\n" - ] - } - ], - "prompt_number": 6 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 13.6, Page number 289" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "N = 3*10**28; #Number density of atoms of dielectric material(per metre cube)\n", - "epsilon_0 = 8.854*10**-12; #Absolute electrical permittivity of free space(F/m)\n", - "n = 1.6; #Refractive index of dielectric material\n", - "\n", - "#Calculation\n", - "#As (n^2 - 1)/(n^2 + 2) = N*alpha_e/(3*epsilon_0), solving for alpha_e\n", - "alpha_e = (n**2 - 1)/(n**2 + 2)*3*epsilon_0/N; #Electronic polarizability of dielectric material(Fm**2)\n", - "\n", - "#Result\n", - "print \"The electronic polarizability of dielectric material is\",alpha_e, \"Fm**2\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The electronic polarizability of dielectric material is 3.029e-40 Fm**2\n" - ] - } - ], - "prompt_number": 8 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 13.7, Page number 289" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - " \n", - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "epsilon_r = 4.9; #Absolute relative dielectric constant of material(F/m)\n", - "n = 1.6; #Refractive index of dielectric material\n", - "\n", - "#Calculation\n", - "#As (n^2 - 1)/(n^2 + 2)*(alpha_e + alpha_i)/alpha_e = N*(alpha_e + alpha_i)/(3*epsilon_0) = (epsilon_r - 1)/(epsilon_r + 2)\n", - "#let alpha_ratio = alpha_i/alpha_e\n", - "alpha_ratio = ((epsilon_r - 1)/(epsilon_r + 2)*(n**2 + 2)/(n**2 - 1) - 1)**(-1); #Ratio of electronic polarizability to ionic polarizability\n", - "alpha_ratio = math.ceil(alpha_ratio*10**3)/10**3; #rounding off the value of alpha_ratio to 3 decimals\n", - "\n", - "#Result\n", - "print \"The ratio of electronic polarizability to ionic polarizability is\",alpha_ratio" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The ratio of electronic polarizability to ionic polarizability is 1.534\n" - ] - } - ], - "prompt_number": 9 - }, - { - "cell_type": "code", - "collapsed": false, - "input": [], - "language": "python", - "metadata": {}, - "outputs": [] - } - ], - "metadata": {} - } - ] -}
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