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diff --git a/Elements_of_Electromagnetics/chapter_6.ipynb b/Elements_of_Electromagnetics/chapter_6.ipynb
index 21f353b6..2e3b83ef 100644
--- a/Elements_of_Electromagnetics/chapter_6.ipynb
+++ b/Elements_of_Electromagnetics/chapter_6.ipynb
@@ -1,80 +1,78 @@
-{
- "metadata": {
- "name": "chapter_6.ipynb"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h1>Chapter 6: Electrostatic Boundary Value Problems<h1>"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 6.12, Page number: 238<h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "'''\n",
- "Determine the capacitance of each of the capacitors in Figure 6.20.\n",
- "Take epsilon_r1 = 4, epsilon_r2 = 6, d = 5 mm, S = 30 cm^2 '''\n",
- "\n",
- "import scipy\n",
- "\n",
- "#Variable Declaration\n",
- "\n",
- "e0=10**-9/(36*scipy.pi) #Permittivity of free space in Farad/m\n",
- "er1=4 #Relative permittivity of material 1 (dimensionless)\n",
- "er2=6 #Relative permittivity of material 2 (dimensionless)\n",
- "d=5*10** -3 #The spacing between the capacitor plates in m\n",
- "S=30*10** -4 #The surface area of the plates\n",
- "\n",
- "#Calculations\n",
- "\n",
- "#Calculation for Capacitor 1\n",
- "\n",
- "C1=e0*er1*S*2/d #Capacitance in Farads\n",
- "C2=e0*er2*S*2/d #Capacitance in Farads\n",
- "Ca=C1*C2/(C1+C2) #Total capacitance in Farads\n",
- "\n",
- "#Calculation for Capacitor 2\n",
- "\n",
- "C1= e0*er1*S/(2*d) #Capacitance in Farads\n",
- "C2= e0*er2*S/(2*d) #Capacitance in Farads\n",
- "Cb= C1+C2 #Total capacitance in Farads\n",
- "\n",
- "\n",
- "#Results\n",
- "\n",
- "print 'The capacitance of capacitor 1 =',round(Ca*10**12,2),'pF'\n",
- "print 'The capacitance of capacitor 2 =',round(Cb*10**12,2),'pF'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The capacitance of capacitor 1 = 25.46 pF\n",
- "The capacitance of capacitor 2 = 26.53 pF\n"
- ]
- }
- ],
- "prompt_number": 1
- }
- ],
- "metadata": {}
- }
- ]
+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:0404b66522ba62c52bb8d112f6cb8c3bcc64527b3152c58a7bd723197eac9b68"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h1>Chapter 6: Electrostatic Boundary Value Problems<h1>"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 6.12, Page number: 238<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " \n",
+ "import scipy\n",
+ "\n",
+ "#Variable Declaration\n",
+ "\n",
+ "e0=10**-9/(36*scipy.pi) #Permittivity of free space in Farad/m\n",
+ "er1=4 #Relative permittivity of material 1 (dimensionless)\n",
+ "er2=6 #Relative permittivity of material 2 (dimensionless)\n",
+ "d=5*10** -3 #The spacing between the capacitor plates in m\n",
+ "S=30*10** -4 #The surface area of the plates\n",
+ "\n",
+ "#Calculations\n",
+ "\n",
+ "#Calculation for Capacitor 1\n",
+ "\n",
+ "C1=e0*er1*S*2/d #Capacitance in Farads\n",
+ "C2=e0*er2*S*2/d #Capacitance in Farads\n",
+ "Ca=C1*C2/(C1+C2) #Total capacitance in Farads\n",
+ "\n",
+ "#Calculation for Capacitor 2\n",
+ "\n",
+ "C1= e0*er1*S/(2*d) #Capacitance in Farads\n",
+ "C2= e0*er2*S/(2*d) #Capacitance in Farads\n",
+ "Cb= C1+C2 #Total capacitance in Farads\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "\n",
+ "print 'The capacitance of capacitor 1 =',round(Ca*10**12,2),'pF'\n",
+ "print 'The capacitance of capacitor 2 =',round(Cb*10**12,2),'pF'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The capacitance of capacitor 1 = 25.46 pF\n",
+ "The capacitance of capacitor 2 = 26.53 pF\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ }
+ ],
+ "metadata": {}
+ }
+ ]
} \ No newline at end of file