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-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "CHAPTER 4 DIODE CIRCUITS"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-1, Page 92"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "import math\n",
- "\n",
- "Vrms=10 #RMS Value of sine wave(V)\n",
- "f=60 #frequency(Hz)\n",
- "\n",
- "Vp=Vrms/0.707 #peak source voltage(V)\n",
- "Vpout=Vp #peak load voltage(V)\n",
- "Vdc=Vp/math.pi #dc load voltage(V)\n",
- "Vpouts=Vp-0.7 #peak load voltage in 2nd approx.\n",
- "Vdc=Vpouts/math.pi #dc load voltage(V)\n",
- "\n",
- "print 'Vp=',round(Vp,2),'V'\n",
- "print 'With an ideal diode, Vpout =',round(Vpout,2),'V'\n",
- "print 'DC load voltage, Vdc =',round(Vdc,2),'V'\n",
- "print 'With second approximation, Vpout =',round(Vpouts,2),'V'\n",
- "print 'DC load voltage, Vdc =',round(Vdc,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Vp= 14.14 V\n",
- "With an ideal diode, Vpout = 14.14 V\n",
- "DC load voltage, Vdc = 4.28 V\n",
- "With second approximation, Vpout = 13.44 V\n",
- "DC load voltage, Vdc = 4.28 V\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-2, Page 94"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "import math\n",
- "\n",
- "Vs=120 #supply voltage(V)\n",
- "\n",
- "V2=Vs/5 #Secondary voltage(V)\n",
- "Vp=V2/0.707 #peak secondary voltage\n",
- "Vpout=Vp #peak load voltage(V)\n",
- "Vdc1=Vp/math.pi #dc load voltage(V)\n",
- "Vpouts=Vp-0.7 #peak load voltage in 2nd approx.(V)\n",
- "Vdc2=Vpouts/math.pi #dc load voltage(V)\n",
- "\n",
- "print 'As per fig.4-5, Transformer turns ratio is 5:1'\n",
- "print 'V2=',round(V2,2),'V'\n",
- "print 'Vp=',round(Vp,2),'V'\n",
- "print 'With an ideal diode, Vpout =',round(Vpout,2),'V'\n",
- "print 'DC load voltage, Vdc =',round(Vdc1,2),'V'\n",
- "print 'With second approximation, Vpout =',round(Vpouts,2),'V'\n",
- "print 'DC load voltage, Vdc =',round(Vdc2,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "As per fig.4-5, Transformer turns ratio is 5:1\n",
- "V2= 24.0 V\n",
- "Vp= 33.95 V\n",
- "With an ideal diode, Vpout = 33.95 V\n",
- "DC load voltage, Vdc = 10.81 V\n",
- "With second approximation, Vpout = 33.25 V\n",
- "DC load voltage, Vdc = 10.58 V\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-3, Page 97"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vrms=120 #RMS value of supply(V)\n",
- "N12=10 #turn ratio\n",
- "\n",
- "Vp1=Vrms/0.707 #peak primary voltage(V)\n",
- "Vp2=Vp1/N12 #peak secondary voltage(V)\n",
- "Vpin=0.5*Vp2 #input voltage(V)\n",
- "Vpout=Vpin #Output voltage (V)\n",
- "Vpouts=Vpin-0.7 #Output voltage in 2nd approx.(V)\n",
- "\n",
- "print 'Peak primary voltage Vp1=',round(Vp1,2),'V'\n",
- "print 'Peak secondary voltage Vp2=',round(Vp2,2),'V'\n",
- "print 'Due to center-tap,' \n",
- "print 'input voltage to each half-wave rectifier is only half the secondary voltage:'\n",
- "print 'With an ideal diode, Vpout =',round(Vpout,2),'V'\n",
- "print 'With second approximation, Vpout =',round(Vpouts,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Peak primary voltage Vp1= 169.73 V\n",
- "Peak secondary voltage Vp2= 16.97 V\n",
- "Due to center-tap,\n",
- "input voltage to each half-wave rectifier is only half the secondary voltage:\n",
- "With an ideal diode, Vpout = 8.49 V\n",
- "With second approximation, Vpout = 7.79 V\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-4, Page 99"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vrms=120 #RMS value of supply(V)\n",
- "N12=10 #turn ratio\n",
- "\n",
- "Vp1=Vrms/0.707 #peak primary voltage(V)\n",
- "Vp2=Vp1/N12 #peak secondary voltage(V)\n",
- "Vpin=0.5*Vp2 #input voltage(V)\n",
- "Vpout=Vpin #Output voltage(V)\n",
- "Vpouts=Vpin-0.7 #Output voltage in 2nd approx.(V)\n",
- "\n",
- "print 'Peak primary voltage Vp1=',round(Vp1,2),'V'\n",
- "print 'Peak secondary voltage Vp2=',round(Vp2,2),'V'\n",
- "print 'Due to one of the diodes were open, load voltage will be the half wave signal'\n",
- "print 'But still peak of half wave signal is same as prior case'\n",
- "print 'With an ideal diode, Vpout =',round(Vpout,2),'V'\n",
- "print 'With second approximation, Vpout =',round(Vpouts,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Peak primary voltage Vp1= 169.73 V\n",
- "Peak secondary voltage Vp2= 16.97 V\n",
- "Due to one of the diodes were open, load voltage will be the half wave signal\n",
- "But still peak of half wave signal is same as prior case\n",
- "With an ideal diode, Vpout = 8.49 V\n",
- "With second approximation, Vpout = 7.79 V\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-5, Page 102"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vrms=120 #RMS value of supply(V)\n",
- "N12=10 #turn ratio\n",
- "\n",
- "Vp1=Vrms/0.707 #peak primary voltage(V)\n",
- "Vp2=Vp1/N12 #peak secondary voltage(V)\n",
- "Vpout=Vp2 #Output voltage(V)\n",
- "\n",
- "print 'Peak primary voltage Vp1=',round(Vp1,2),'V'\n",
- "print 'Peak secondary voltage Vp2=',round(Vp2,2),'V'\n",
- "print 'secondary voltage is input of rectifier'\n",
- "print 'With an ideal diode, Vpout =',round(Vpout,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Peak primary voltage Vp1= 169.73 V\n",
- "Peak secondary voltage Vp2= 16.97 V\n",
- "secondary voltage is input of rectifier\n",
- "With an ideal diode, Vpout = 16.97 V\n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-6, Page 108"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vrms=120 #RMS value of supply(V)\n",
- "N12=5 #turn ratio\n",
- "RL=5 #Load resistance(KOhm)\n",
- "C=100 #Capacitance(uF)\n",
- "f=60 #Frequency(Hz)\n",
- "\n",
- "V2=Vrms/N12 #RMS secondary voltage(V)\n",
- "Vp=V2/0.707 #peak secondary voltage(V)\n",
- "VL=Vp #dc load voltage(V)\n",
- "IL=VL/RL #Load current(mA)\n",
- "VR=(IL/(f*C))*(10**3) #ripple voltage(V)\n",
- "\n",
- "print 'RMS secondary voltage V2=',V2,'V'\n",
- "print 'Peak secondary voltage Vp=',round(Vp,2),'V'\n",
- "print 'with ideal diode and small ripple, dc load voltage, VL =',round(VL,2),'V'\n",
- "print 'To calculate ripple get, dc load current,'\n",
- "print 'DC Load current IL=',round(IL,2),'mA'\n",
- "print 'As per ripple formula,'\n",
- "print 'Ripple voltage VR=',round(VR,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "RMS secondary voltage V2= 24 V\n",
- "Peak secondary voltage Vp= 33.95 V\n",
- "with ideal diode and small ripple, dc load voltage, VL = 33.95 V\n",
- "To calculate ripple get, dc load current,\n",
- "DC Load current IL= 6.79 mA\n",
- "As per ripple formula,\n",
- "Ripple voltage VR= 1.13 V\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-7, Page 109"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vrms=120 #RMS value of supply(V)\n",
- "N12=5 #turn ratio\n",
- "RL=5 #Load resistance(KOhm)\n",
- "C=100 #Capacitance(uF)\n",
- "f=60 #Frequency(Hz)\n",
- "\n",
- "V2=Vrms/N12 #RMS secondary voltage(V)\n",
- "Vp=V2/0.707 #peak secondary voltage(V)\n",
- "VL=Vp/2 #dc load voltage(V)\n",
- "IL=VL/RL #Load current(mA)\n",
- "VR=(IL/(2*f*C))*(10**3) #ripple voltage(V)\n",
- "\n",
- "print 'RMS secondary voltage V2=',V2,'V'\n",
- "print 'Peak secondary voltage Vp=',round(Vp,2),'V'\n",
- "print 'Half this voltage is input to each half-wave section, with ideal diode and small ripple, dc load voltage, VL =',round(VL,2),'V'\n",
- "print 'But, due to 0.7V across conducting diode actual dc voltage is, VL =',round((VL-0.7),2),'V'\n",
- "print 'To calculate ripple get, dc load current,'\n",
- "print 'DC Load current IL=',round(IL,2),'mA'\n",
- "print 'As per ripple formula,'\n",
- "print 'Ripple voltage VR=',round(VR,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "RMS secondary voltage V2= 24 V\n",
- "Peak secondary voltage Vp= 33.95 V\n",
- "Half this voltage is input to each half-wave section, with ideal diode and small ripple, dc load voltage, VL = 16.97 V\n",
- "But, due to 0.7V across conducting diode actual dc voltage is, VL = 16.27 V\n",
- "To calculate ripple get, dc load current,\n",
- "DC Load current IL= 3.39 mA\n",
- "As per ripple formula,\n",
- "Ripple voltage VR= 0.28 V\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-8, Page 110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vrms=120 #RMS value of supply(V)\n",
- "N12=5 #turn ratio\n",
- "RL=5 #Load resistance(KOhm)\n",
- "C=100 #Capacitance(uF)\n",
- "f=60 #Frequency(Hz)\n",
- "\n",
- "V2=Vrms/N12 #RMS secondary voltage(V)\n",
- "Vp=V2/0.707 #peak secondary voltage(V)\n",
- "VL=Vp #dc load voltage(V)\n",
- "IL=VL/RL #Load current(mA)\n",
- "VR=(IL/(2*f*C))*(10**3) #ripple voltage(V)\n",
- "\n",
- "print 'RMS secondary voltage V2=',V2,'V'\n",
- "print 'Peak secondary voltage Vp=',round(Vp,2),'V'\n",
- "print 'with ideal diode and small ripple, dc load voltage, VL =',round(VL,2),'V'\n",
- "print 'But, due to 1.4V across two conducting diodes actual dc voltage is, VL =',round((VL-1.4),2),'V'\n",
- "print 'To calculate ripple get, dc load current,'\n",
- "print 'DC Load current IL=',round(IL,2),'mA'\n",
- "print 'As per ripple formula,'\n",
- "print 'Ripple voltage VR=',round(VR,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "RMS secondary voltage V2= 24 V\n",
- "Peak secondary voltage Vp= 33.95 V\n",
- "with ideal diode and small ripple, dc load voltage, VL = 33.95 V\n",
- "But, due to 1.4V across two conducting diodes actual dc voltage is, VL = 32.55 V\n",
- "To calculate ripple get, dc load current,\n",
- "DC Load current IL= 6.79 mA\n",
- "As per ripple formula,\n",
- "Ripple voltage VR= 0.57 V\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-9, Page 111"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vrms=120 #RMS value of supply(V)\n",
- "N12=15 #turn ratio\n",
- "RL=0.5 #Load resistance(KOhm)\n",
- "C=4700 #Capacitance(uF)\n",
- "f=60 #Frequency(Hz)\n",
- "\n",
- "V2=Vrms/N12 #RMS secondary voltage(V)\n",
- "Vp=V2/0.707 #peak secondary voltage(V)\n",
- "VL=Vp-1.4 #dc load voltage(V)\n",
- "IL=VL/RL #Load current(mA)\n",
- "VR=(IL/(2*f*C))*(10**3) #ripple voltage(V)\n",
- "\n",
- "print 'RMS secondary voltage V2=',V2,'V'\n",
- "print 'Peak secondary voltage Vp=',round(Vp,2),'V'\n",
- "print 'with ideal diode and small ripple & due to 1.4V across two conducting diodes actual dc voltage is, VL =',round(VL,2),'V'\n",
- "print 'To calculate ripple get, dc load current,'\n",
- "print 'DC Load current IL=',round(IL,2),'mA'\n",
- "print 'As per ripple formula,'\n",
- "print 'Ripple voltage VR=',round((VR*1000),2),'mV'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "RMS secondary voltage V2= 8 V\n",
- "Peak secondary voltage Vp= 11.32 V\n",
- "with ideal diode and small ripple & due to 1.4V across two conducting diodes actual dc voltage is, VL = 9.92 V\n",
- "To calculate ripple get, dc load current,\n",
- "DC Load current IL= 19.83 mA\n",
- "As per ripple formula,\n",
- "Ripple voltage VR= 35.16 mV\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4-10, Page 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vrms=120 #RMS value of supply(V)\n",
- "N12=8 #turn ratio\n",
- "f=60 #Frequency(Hz)\n",
- "\n",
- "V2=Vrms/N12 #RMS secondary voltage(V)\n",
- "Vp=V2/0.707 #peak secondary voltage(V)\n",
- "PIV = Vp #Peak Inverse Voltage(V)\n",
- "\n",
- "print 'RMS secondary voltage V2=',V2,'V'\n",
- "print 'Peak inverse voltage PIV =',round(PIV,2),'V'\n",
- "print 'PIV << breakdown voltage(50V), So, it is safe to use IN4001'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "RMS secondary voltage V2= 15 V\n",
- "Peak inverse voltage PIV = 21.22 V\n",
- "PIV << breakdown voltage(50V), So, it is safe to use IN4001\n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [],
- "language": "python",
- "metadata": {},
- "outputs": []
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file
generated by cgit (git 2.34.1) at 2025-01-24 11:02:37 +0000