diff options
Diffstat (limited to 'Electronic_Principles_/Chapter_2_New.ipynb')
| -rw-r--r-- | Electronic_Principles_/Chapter_2_New.ipynb | 17 |
1 files changed, 0 insertions, 17 deletions
diff --git a/Electronic_Principles_/Chapter_2_New.ipynb b/Electronic_Principles_/Chapter_2_New.ipynb index cf7eaae1..4404a233 100644 --- a/Electronic_Principles_/Chapter_2_New.ipynb +++ b/Electronic_Principles_/Chapter_2_New.ipynb @@ -27,23 +27,17 @@ "cell_type": "code",
"collapsed": false,
"input": [
- "#Example 2.5.py\n",
- "#A barrier potential of 0.7V at an ambient temperature of 25 deg C,\n",
- "#Find arrier potential of a silicon diode when the junction temperature is 100 deg C. At 0 deg C.\n",
"\n",
- "#Variable declaration\n",
"Tj=100 #junction temperature 1(C)\n",
"Vb=0.7 #Barrier potential(V)\n",
"Tamb=25 #Ambient temperature(C)\n",
"T1=0 #junction temperature 2(C)\n",
"\n",
- "#Calculation\n",
"Vd=-0.002*(Tj-Tamb) #Change in barrier potential(V)\n",
"Vbn=Vb+Vd #Barrier potential(V)\n",
"Vd1=-0.002*(T1-Tamb) #Change in barrier potential(V)\n",
"Vb1n=Vb+Vd1 #Barrier potential(V)\n",
"\n",
- "#Result\n",
"print 'Change in barrier potential = Vd =',Vd,'V'\n",
"print 'Brrier potential = Vbn =',Vbn,'V'\n",
"print 'For junction temperature 0 C'\n",
@@ -79,21 +73,16 @@ "cell_type": "code",
"collapsed": false,
"input": [
- "#Example 2.6.py\n",
- "#A silicon diode has a saturation current of 5 nA at 25 deg C. What is the saturation current at 100 deg C?\n",
"\n",
"\n",
- "#Variable declaration\n",
"T2=100 #Temperature(C)\n",
"T1=25 #Temperature(C)\n",
"Isat1=5 #Current(nA)\n",
"\n",
- "#Calculation\n",
"Td=T2-T1 #Temperature change(C)\n",
"Is1=(2**7)*Isat1 #Current(nA)\n",
"Is2=(1.07**5)*Is1 #Current(nA)\n",
"\n",
- "#Result\n",
"print 'Change in temperature = Td = T2-T1 =',Td,'C'\n",
"print 'For first 70 C change seven doublings are there.'\n",
"print 'Is1 = (2^7)*Isat1 =',Is1,'nA'\n",
@@ -129,20 +118,14 @@ "cell_type": "code",
"collapsed": false,
"input": [
- "#Example 2.7.py\n",
- "#surface-leakage current is 2nA for a reverse voltage of 25 V, \n",
- "#find surface leakage current for a reverse voltage of 35V.\n",
"\n",
- "#Variable declaration\n",
"Isl=2*(10**-9) #surface leakage current(nA)\n",
"Vr=25 #Reverse voltage(V)\n",
"Vr1=35 #Reverse voltage(V)\n",
"\n",
- "#Calculation\n",
"Rsl=Vr/Isl #surface leakage reistance(Ohm)\n",
"Isl1=(Vr1/Rsl)*(10**9) #surface leakage current(nA)\n",
"\n",
- "#Result\n",
"print 'surface-leakage reistance Rsl = Vr/Isl =',Rsl*10**-6,'MOhm'\n",
"print 'for Vr1 = 35 V,'\n",
"print 'surface-leakage reistance Isl1 = Vr1/Rsl =',Isl1,'nA'"
|