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Diffstat (limited to 'Electronic_Principles_/Chapter_1_New.ipynb')
| -rw-r--r-- | Electronic_Principles_/Chapter_1_New.ipynb | 256 |
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diff --git a/Electronic_Principles_/Chapter_1_New.ipynb b/Electronic_Principles_/Chapter_1_New.ipynb deleted file mode 100644 index 5245d442..00000000 --- a/Electronic_Principles_/Chapter_1_New.ipynb +++ /dev/null @@ -1,256 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "CHAPTER 1 INTRODUCTION"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1-1, Page 9"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Rs=50 #source resistance(Ohm)\n",
- "\n",
- "RL=100*Rs/1000 #Minimum Load resistance(KOhm)\n",
- "\n",
- "print 'Minimum Load resistance =',RL,'KOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Minimum Load resistance = 5 KOhm\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1-2, Page 12"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Is=0.002 #Current source(A)\n",
- "Rs=10000000 #internal resistance(Ohm)\n",
- "\n",
- "Rl_Max=0.01*Rs/1000 #Maximum load resistance(KOhm)\n",
- "\n",
- "print 'With 100:1 Rule, Maximum Load resistance =',Rl_Max,'KOhm'\n",
- "print 'Stiff range for current source is load resistance from 0 KOhm to',Rl_Max,'KOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "With 100:1 Rule, Maximum Load resistance = 100.0 KOhm\n",
- "Stiff range for current source is load resistance from 0 KOhm to 100.0 KOhm\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1-3, Page 13"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Il=0.002 #current source(A)\n",
- "Rl=10000 #load resistance(Ohm)\n",
- "\n",
- "Vl=Il*Rl #load voltage(V)\n",
- "\n",
- "print 'Load Voltage =',Vl,'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Load Voltage = 20.0 V\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1-4, Page 14"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "print 'As per figure 1-9a, Calculate Thevenin resistor by opening load resistor'\n",
- "\n",
- "Vs=72 #source voltage\n",
- "R1=6 #Resistance (KOhm)\n",
- "R2=3 #Resistance (KOhm)\n",
- "R3=4 #Resistance (KOhm)\n",
- "\n",
- "Ro=R1+R2 #Resistance (KOhm)\n",
- "I=Vs/Ro\n",
- "Vab=R2*Vs/(R1+R2) #Thevenin voltage(V)\n",
- "Rth=((R1*R2)/(R1+R2))+R3 #Thevenin Resistance(KOhm)\n",
- "\n",
- "print 'After removing Rl current flowing through 6KOhm is',I,'mA'\n",
- "print 'Thevenin Voltage Vth =',Vab,'V'\n",
- "print 'Calculating Thevenin Resistance with considering R1 & R2 in parallel'\n",
- "print 'Thevenin Resistance =',Rth,'KOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "As per figure 1-9a, Calculate Thevenin resistor by opening load resistor\n",
- "After removing Rl current flowing through 6KOhm is 8 mA\n",
- "Thevenin Voltage Vth = 24 V\n",
- "Calculating Thevenin Resistance with considering R1 & R2 in parallel\n",
- "Thevenin Resistance = 6 KOhm\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1-5, Page 15"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vs=72 #source voltage\n",
- "R1=2 #resistance1 (KOhm)\n",
- "R2=2 #resistance1 (KOhm)\n",
- "R3=1 #resistance1 (KOhm)\n",
- "R4=2 #resistance1 (KOhm)\n",
- "R5=1 #resistance1 (KOhm)\n",
- "R6=2 #resistance1 (KOhm)\n",
- "R7=0.5 #resistance1 (KOhm)\n",
- "RL=1 #load resistance (KOhm)\n",
- "\n",
- "Vth=9 #Thevenin voltage(V)\n",
- "Rth=1.5 #Thevenin resistance(KOhm)\n",
- "\n",
- "print 'Thevenin Voltage Vth =',Vth,'V'\n",
- "print 'Thevenin Resistance =',Rth,'KOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Thevenin Voltage Vth = 9 V\n",
- "Thevenin Resistance = 1.5 KOhm\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1-6, Page 19"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vs=10 #source voltage\n",
- "Rs=2 #series source resistance (KOhm)\n",
- "\n",
- "IN=Vs/Rs #Norton current(mA)\n",
- "Rp=Rs #parallel source resistance(KOhm)\n",
- "\n",
- "print 'Norton current IN =',IN,'mA'\n",
- "print 'Norton Resistance =',Rp,'KOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Norton current IN = 5 mA\n",
- "Norton Resistance = 2 KOhm\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [],
- "language": "python",
- "metadata": {},
- "outputs": []
- }
- ],
- "metadata": {}
- }
- ]
-}
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