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Diffstat (limited to 'Electronic_Principles_/Chapter_17_New.ipynb')
-rw-r--r-- | Electronic_Principles_/Chapter_17_New.ipynb | 614 |
1 files changed, 0 insertions, 614 deletions
diff --git a/Electronic_Principles_/Chapter_17_New.ipynb b/Electronic_Principles_/Chapter_17_New.ipynb deleted file mode 100644 index a6647813..00000000 --- a/Electronic_Principles_/Chapter_17_New.ipynb +++ /dev/null @@ -1,614 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "CHAPTER 17 DIFFERENTIAL AMPLIFIERS"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-1, Page 625"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=15 #supply voltage(V)\n",
- "RE=7.5 #Emitter resistance(KOhm)\n",
- "\n",
- "IT=VCC/RE #tail current (mA)\n",
- "IE=IT/2 #emitter current (mA)\n",
- "\n",
- "print 'tail current = ',IT,'mA'\n",
- "print 'emitter current = ',IE,'mA'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "tail current = 2.0 mA\n",
- "emitter current = 1.0 mA\n"
- ]
- }
- ],
- "prompt_number": 94
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-2, Page 626"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=15 #supply voltage(V)\n",
- "RE=7.5 #Emitter resistance(KOhm)\n",
- "VBE=0.7 #base-emitter voltage(V)\n",
- "RC=5 #collector resistance(KOhm)\n",
- "\n",
- "IT=(VCC-VBE)/RE #tail current (mA)\n",
- "IE=IT/2 #emitter current (mA)\n",
- "VC=VCC-(IE*RC) #collector quiescent voltage(V) \n",
- "\n",
- "print 'tail current = ',round(IT,2),'mA'\n",
- "print 'emitter current = ',round(IE,2),'mA'\n",
- "print 'collector quiescent voltage VC = ',round(VC,2),'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "tail current = 1.91 mA\n",
- "emitter current = 0.95 mA\n",
- "collector quiescent voltage VC = 10.23 V\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-3, Page 626"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=12.0 #supply voltage(V)\n",
- "RE=5.0 #Emitter resistance(KOhm)\n",
- "RC=3.0 #collector resistance(KOhm)\n",
- "\n",
- "IT=VCC/RE #tail current (mA)\n",
- "IE=IT/2 #emitter current (mA)\n",
- "VC=VCC-(IE*RC) #collector quiescent voltage(V) \n",
- "IT1=(VCC-VBE)/RE #tail current (mA)\n",
- "IE1=IT1/2 #emitter current (mA)\n",
- "VC1=VCC-(IE1*RC) #collector quiescent voltage(V) \n",
- "\n",
- "print 'tail current = ',IT,'mA'\n",
- "print 'emitter current = ',IE,'mA'\n",
- "print 'collector quiescent voltage VC = ',VC,'V'\n",
- "print 'with second approximation,'\n",
- "print 'tail current = ',IT1,'mA'\n",
- "print 'emitter current = ',IE1,'mA'\n",
- "print 'collector quiescent voltage VC = ',VC1,'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "tail current = 2.4 mA\n",
- "emitter current = 1.2 mA\n",
- "collector quiescent voltage VC = 8.4 V\n",
- "with second approximation,\n",
- "tail current = 2.26 mA\n",
- "emitter current = 1.13 mA\n",
- "collector quiescent voltage VC = 8.61 V\n"
- ]
- }
- ],
- "prompt_number": 92
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-4, Page 631"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=12.0 #supply voltage(V)\n",
- "RE=7.5 #Emitter resistance(KOhm)\n",
- "RC=5.0 #collector resistance(KOhm)\n",
- "IE=1 #emitter current as per preceding example(mA)\n",
- "Vin=1 #input ac voltage(mV)\n",
- "B=300 #current gain\n",
- "\n",
- "re=25/IE #ac emitter resistance(Ohm)\n",
- "Av=1000*RC/re #voltage gain\n",
- "Vout=Av*Vin #Output voltage(mV)\n",
- "Zinb=2*B*re #input impedance of diff amp(Ohm)\n",
- "\n",
- "print 'voltage gain Av = ',Av\n",
- "print 'Output voltage Vout = ',Vout,'mV'\n",
- "print 'input impedance of diff amplifier, Zin(base) = ',Zinb/1000,'KOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain Av = 200.0\n",
- "Output voltage Vout = 200.0 mV\n",
- "input impedance of diff amplifier, Zin(base) = 15 KOhm\n"
- ]
- }
- ],
- "prompt_number": 91
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-5, Page 632"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=12.0 #supply voltage(V)\n",
- "RE=7.5 #Emitter resistance(KOhm)\n",
- "RC=5.0 #collector resistance(KOhm)\n",
- "IE=0.955 #emitter current as per previous example(mA)\n",
- "Vin=1 #input ac voltage(mV)\n",
- "B=300 #current gain\n",
- "\n",
- "re=25/IE #ac emitter resistance(Ohm)\n",
- "Av=1000*RC/re #voltage gain\n",
- "Vout=Av*Vin #Output voltage(mV)\n",
- "Zinb=2*B*re #input impedance of diff amp(Ohm)\n",
- "\n",
- "print 'voltage gain Av = ',Av\n",
- "print 'Output voltage Vout = ',Vout,'mV'\n",
- "print 'input impedance of diff amplifier, Zin(base) = ',round((Zinb/1000),2),'KOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain Av = 191.0\n",
- "Output voltage Vout = 191.0 mV\n",
- "input impedance of diff amplifier, Zin(base) = 15.71 KOhm\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-6, Page 633"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=12.0 #supply voltage(V)\n",
- "RE=7.5 #Emitter resistance(KOhm)\n",
- "RC=5.0 #collector resistance(KOhm)\n",
- "IE=1 #emitter current as per preceding example(mA)\n",
- "V2=1 #input ac voltage(mV)\n",
- "B=300 #current gain\n",
- "\n",
- "re=25/IE #ac emitter resistance(Ohm)\n",
- "Av=1000*RC/re #voltage gain\n",
- "Vout=Av*V2 #Output voltage(mV)\n",
- "Zinb=2*B*re #input impedance of diff amp(Ohm)\n",
- "\n",
- "print 'V2 input is at inverting input, So, ideally same as previous case.'\n",
- "print 'Voltage gain Av = ',Av\n",
- "print 'Output voltage Vout = ',Vout,'mV'\n",
- "print 'input impedance of diff amplifier, Zin(base) = ',Zinb/1000,'KOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "V2 input is at inverting input, So, ideally same as previous case.\n",
- "Voltage gain Av = 200.0\n",
- "Output voltage Vout = 200.0 mV\n",
- "input impedance of diff amplifier, Zin(base) = 15 KOhm\n"
- ]
- }
- ],
- "prompt_number": 96
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-7, Page 633"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=15.0 #supply voltage(V)\n",
- "RC=1.0**10**6 #collector resistance(Ohm)\n",
- "RE=1.0**10**6 #emitter resistance(Ohm)\n",
- "IE=1 #emitter current as per preceding example(mA)\n",
- "Vin=7 #input ac voltage(mV)\n",
- "B=300 #current gain\n",
- "\n",
- "IT=VCC/RE #tail current (uA)\n",
- "IE=IT/2 #emitter current (uA)\n",
- "re=25/IE/1000 #ac emitter resistance(Ohm)\n",
- "Av=RC/(2*re) #voltage gain\n",
- "Vout=Av*Vin #Output voltage(V)\n",
- "Zinb=2*B*re #input impedance of diff amp(MOhm)\n",
- "\n",
- "print 'Voltage gain Av = ',Av\n",
- "print 'Output voltage Vout = ',Vout/1000,'V'\n",
- "print 'input impedance of diff amplifier, Zin(base) = ',Zinb,'MOhm'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Voltage gain Av = 150.0\n",
- "Output voltage Vout = 1.05 V\n",
- "input impedance of diff amplifier, Zin(base) = 2.0 MOhm\n"
- ]
- }
- ],
- "prompt_number": 97
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-8, Page 639"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=15.0 #supply voltage(V)\n",
- "RC=5.0*10**3 #collector resistance(Ohm)\n",
- "RE=7.5*10**3 #emitter resistance(Ohm)\n",
- "RB=1*10**3 #base resistance(Ohm)\n",
- "Vin=10 #input ac voltage(mV)\n",
- "Av=200 #voltage gain\n",
- "Iinb=3*10**-6 #bias current(A)\n",
- "Iino =0.5*10**-6 #Iin(off) (A) \n",
- "Vino=1.0 #Vin(off) (mV)\n",
- "\n",
- "V1err=RB*Iinb*1000 #dc error input1 (mV)\n",
- "V2err=RB*(Iino/2)*1000 #dc error input2 (mV)\n",
- "V3err=Vino #dc error input3 (mV)\n",
- "Verror=Av*(V1err+V2err+V3err) #output error voltage(mV)\n",
- "V1err1=0 #dc error input1 (mV)\n",
- "V2err1=RB*Iino*1000 #dc error input2 (mV)\n",
- "V3err1=Vino #dc error input3 (mV)\n",
- "Verror1=Av*(V1err1+V2err1+V3err1) #output error voltage(mV)\n",
- "\n",
- "print 'output error voltage Verror = ',Verror,'mV'\n",
- "print 'output error voltage Verror = ',Verror1,'mV'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output error voltage Verror = 850.0 mV\n",
- "output error voltage Verror = 300.0 mV\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-9, Page 640"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=15.0 #supply voltage(V)\n",
- "RC=1.0*10**6 #collector resistance(Ohm)\n",
- "RE=1.0*10**6 #emitter resistance(Ohm)\n",
- "RB=10*10**3 #base resistance(Ohm)\n",
- "Vin=10 #input ac voltage(mV)\n",
- "Av=300 #voltage gain\n",
- "Iinb=80*10**-9 #bias current(A)\n",
- "Iino=20*10**-9 #Iin(off) (A) \n",
- "Vino=5.0 #Vin(off) (mV)\n",
- "\n",
- "V1err=0 #dc error input1 (mV)\n",
- "V2err=RB*(Iino/2)*1000 #dc error input2 (mV)\n",
- "V3err=Vino #dc error input3 (mV)\n",
- "Verror=Av*(V1err+V2err+V3err) #output error voltage(mV)\n",
- "\n",
- "print 'output error voltage Verror = ',Verror/1000,'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output error voltage Verror = 1.53 V\n"
- ]
- }
- ],
- "prompt_number": 98
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-10, Page 643"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=15.0 #supply voltage(V)\n",
- "RC=1.0*10**6 #collector resistance(Ohm)\n",
- "RE=1.0*10**6 #emitter resistance(Ohm)\n",
- "Vin=1 #input ac voltage(mV)\n",
- "\n",
- "Av_CM=RC/(2*RE) #common mode voltage gain\n",
- "Vout=Av_CM*Vin #output voltage(mV) \n",
- "\n",
- "print 'common mode voltage gain : Av(CM) = ',Av_CM\n",
- "print 'Output voltage Vout = ',Vout,'mV'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "common mode voltage gain : Av(CM) = 0.5\n",
- "Output voltage Vout = 0.5 mV\n"
- ]
- }
- ],
- "prompt_number": 45
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-11, Page 643"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Vin=1 #input ac voltage(mV)\n",
- "Av=150 #voltage gain\n",
- "Av_CM=0.5 #common mode voltage gain\n",
- "\n",
- "Vout1=Av*Vin #output voltage1(mV)\n",
- "Vout2=Av_CM*Vin #output voltage2(mV)\n",
- "Vout=Vout1+Vout2 #output volatge(mV)\n",
- "\n",
- "print 'output voltage Vout1 = ',Vout1,'mV'\n",
- "print 'output voltage Vout2 = ',Vout2,'mV'\n",
- "print 'output voltage Vout = ',Vout,'mV'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output voltage Vout1 = 150 mV\n",
- "output voltage Vout2 = 0.5 mV\n",
- "output voltage Vout = 150.5 mV\n"
- ]
- }
- ],
- "prompt_number": 46
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-12, Page 644"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "CMRR_dB=90 #CMRR(dB)\n",
- "Av=200000 #voltage gain\n",
- "Vin=1*10**-6 #input voltage(V)\n",
- "\n",
- "CMRR=10**(CMRR_dB/20.0) #CMRR \n",
- "Av_CM=Av/CMRR #common mode voltage gain \n",
- "Vout1=Av*Vin #desired output: voltage1(V)\n",
- "Vout2=Av_CM*Vin #common mode output: voltage2(V)\n",
- "\n",
- "print 'output voltage Vout1 = ',Vout1,'V'\n",
- "print 'output voltage Vout2 = ',round((Vout2*10**6),2),'uV'\n",
- "print 'see, desired output is much larger than common mode output.'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output voltage Vout1 = 0.2 V\n",
- "output voltage Vout2 = 6.32 uV\n",
- "see, desired output is much larger than common mode output.\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-13, Page 651"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "VCC=15.0 #supply voltage(V)\n",
- "RC=7.5*10**3 #collector resistance(Ohm)\n",
- "RE=7.5*10**3 #emitter resistance(Ohm)\n",
- "V1=10 #input ac voltage(mV)\n",
- "re=25 #as per example 17-4 (Ohm) \n",
- "RL=15*10**3 #load resistance(KOhm)\n",
- "\n",
- "Av=RC/re #voltage gain\n",
- "Vout=Av*V1/1000 #output voltage(V) \n",
- "RTH=2*RC #Thevenin resistance(Ohm)\n",
- "VL=(RL/(RL+RTH))*Vout #load voltage(V)\n",
- "\n",
- "print 'Load voltage VL = ',VL,'V'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Load voltage VL = 1.5 V\n"
- ]
- }
- ],
- "prompt_number": 67
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17-14, Page 652"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "RL=15.0 #load resistance as per previous example(Ohm)\n",
- "VL=3 #load voltage as per previous example(V)\n",
- "\n",
- "iL=VL/RL #load current(mA)\n",
- "\n",
- "print 'Load current iL = ',iL,'mA'"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Load current iL = 0.2 mA\n"
- ]
- }
- ],
- "prompt_number": 69
- }
- ],
- "metadata": {}
- }
- ]
-}
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