diff options
Diffstat (limited to 'Electronic_Devices_and_Circuits')
67 files changed, 0 insertions, 36232 deletions
diff --git a/Electronic_Devices_and_Circuits/Chapter1.ipynb b/Electronic_Devices_and_Circuits/Chapter1.ipynb deleted file mode 100755 index 47b8b5fc..00000000 --- a/Electronic_Devices_and_Circuits/Chapter1.ipynb +++ /dev/null @@ -1,307 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 01 : Basic semiconductor and pn junction theory"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.1, Page No 15"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Nd=3*10**14\n",
- "Na=0.5*10**14 #all in atom/cm**3\n",
- "ni=1.5*10**10\n",
- "\n",
- "#Calculations\n",
- "print(\"resultant densities of free electrons and hole\")\n",
- "ne=(-(Na-Nd)+(math.sqrt(((Na-Nd)**2)+4*ni**2)))/2\n",
- "print(\"Electron densities = %.1f x 10^14 electron/cm**3\" %(ne/(10**14))) #electron densities in electron/cm**3\n",
- "Nd>Na\n",
- "n=Nd-Na\n",
- "print(n)\n",
- "p=(ni**2)/n\n",
- "\n",
- "#Results\n",
- "\n",
- "print(\"densities of hole is =%.1f X 10^6 dhole/cm3\" %(p/(10**6)))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resultant densities of free electrons and hole\n",
- "Electron densities = 2.5 x 10^14 electron/cm**3\n",
- "2.5e+14\n",
- "densities of hole is =0.9 X 10^6 dhole/cm3\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.2, Page No 18"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "l=1*10**-3\n",
- "E=10\n",
- "\n",
- "#Calculations\n",
- "un=1500*10**-4\n",
- "up=500*10-4\n",
- "Vn=-(un*E)/l\n",
- "\n",
- "#Results\n",
- "print(\"drift current is =%.2dm/s\\n\" %Vn)\n",
- "print(\"drift current of hole\")\n",
- "Vp=(up*E)/l\n",
- "print(\"drift current is =%.f dm/s\\n\" %(Vp/10**5))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "drift current is =-1500m/s\n",
- "\n",
- "drift current of hole\n",
- "drift current is =500 dm/s\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.3 Page No 19"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "l=1*10**-3\n",
- "a=0.1*10**-4\n",
- "ni=1.5*10**10\n",
- "p=1.5*10**10\n",
- "un=1500\n",
- "up=500 #in cm3/V.s\n",
- "q=1.6*10**-19\n",
- "\n",
- "#Calculations\n",
- "m=q*((ni*un)+(p*up))*10**6\n",
- "print( \"mobility is =%.1fmicro/ohmcm\" %m)\n",
- "R=l/(m*a)\n",
- "print(\" resistance is =%.1fMohm\" %R)\n",
- "\n",
- "#for doped material\n",
- "n=8*10**13\n",
- "p=(ni**2)/n\n",
- "m=q*((n*un)+(p*up))\n",
- "\n",
- "#Results\n",
- "print(\"mobility is =%3.4f/ohmcm\" %m)\n",
- "R=l/(m*a)\n",
- "print(\" resistance is %.2f Kohm\" %(R/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "mobility is =4.8micro/ohmcm\n",
- " resistance is =20.8Mohm\n",
- "mobility is =0.0192/ohmcm\n",
- " resistance is 5.21 Kohm\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.4, Page No 25"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "T1=25.0\n",
- "T2=35.0\n",
- "T3=45.0\n",
- "I0=30.0 # nA\n",
- "print(\"I0(35)=I0*2**(T2-T1)/10\")\n",
- "#on solving\n",
- "I035=I0*2**((T2-T1)/10)\n",
- "print(\"Current at 35c is =%.2f nA\\n\" %I035)\n",
- "print(\"I0(45)=I0*2**(T3-T1)/10\")\n",
- "#on solving\n",
- "I045=30*2**2\n",
- "print(\"current at 45c is =%.2f nA\\n\" %I045)\n",
- "I_CS=100.0 \n",
- "V_CC=200.0 \n",
- "t_on=40*10**-6"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "I0(35)=I0*2**(T2-T1)/10\n",
- "Current at 35c is =60.00 nA\n",
- "\n",
- "I0(45)=I0*2**(T3-T1)/10\n",
- "current at 45c is =120.00 nA\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.5, Page No 28"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "I0=30\n",
- "Vd=0.7\n",
- "n=2\n",
- "\n",
- "#Calculations\n",
- "Vt=26.0*10**-3\n",
- "k=Vd/(n*Vt)\n",
- "Id=I0*((2.7**k)-1)*10**-6 #Junction current\n",
- "print(\" a) Forward bais current is =%.2f mA\\n\" %Id)\n",
- "Vd=-10 #reverse bais\n",
- "k=Vd/(n*Vt)\n",
- "Id=I0*((2.7**k)-1)\n",
- "\n",
- "#Results\n",
- "print(\" b) Forward bais current is =%.2f nA\" %Id)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " a) Forward bais current is =19.23 mA\n",
- "\n",
- " b) Forward bais current is =-30.00 nA\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.6, Page No 29"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=.1*10**-3\n",
- "n=2\n",
- "vt=26*10**-3\n",
- "I0=30*10**-9\n",
- "\n",
- "#Calculations\n",
- "Vd=(n*Vt)*math.log(Id/I0)*10**3\n",
- "print(\" a) Forward bais current is =%.2f mV\\n\" %Vd)\n",
- "Id=10*10**-3\n",
- "Vd=(n*Vt)*math.log(Id/I0)*10**3\n",
- "\n",
- "#Results\n",
- "print(\"b) forward bais current is %dmV\\n\" %Vd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " a) Forward bais current is =421.81 mV\n",
- "\n",
- "b) forward bais current is 661mV\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter10.ipynb b/Electronic_Devices_and_Circuits/Chapter10.ipynb deleted file mode 100755 index b92c4b1d..00000000 --- a/Electronic_Devices_and_Circuits/Chapter10.ipynb +++ /dev/null @@ -1,587 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 10 : FET biasing"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.1, Page No 381"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=22.0\n",
- "Rd=2.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"when Id=0\")\n",
- "Id=0\n",
- "Vds=Vdd-Id*Rd\n",
- "print('at point A Vds = %.2f V' %Vds)\n",
- "Vds=0\n",
- "Id=Vdd/Rd\n",
- "\n",
- "#Results\n",
- "print(\"when Vds=0\")\n",
- "print('at point A Id = %.2f mA' %(Id*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0\n",
- "at point A Vds = 22.00 V\n",
- "when Vds=0\n",
- "at point A Id = 11.00 mA\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.4, Page No 387"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Idss=8.0*10**-3\n",
- "Vpmax=6.0\n",
- "Vgs=2.3\n",
- "Vgsmax=6\n",
- "\n",
- "#Calculations\n",
- "Id=Idss*(1-(Vgs/Vgsmax))**2\n",
- "Idss=4*10**-3\n",
- "Vp=3\n",
- "Idmin=Idss*(1-(Vgs/Vp))**2\n",
- "\n",
- "#Results\n",
- "print('at point A Idmin = %.2f mA' %(Idmin*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "at point A Idmin = 0.22 mA\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.6 Page No 393"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vdd=25.0\n",
- "R2=1.0*10**6\n",
- "R1=3.8*10**6\n",
- "Rs=2.5*10**3\n",
- "Rd=2.5*10**3\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"when Id=0\")\n",
- "Id=0\n",
- "Vgs=Vg-Id*Rs\n",
- "print(\" plot point A at Id=0\")\n",
- "print('at point A Vds = %.2f A/s' %Vds)\n",
- "Vgs=0\n",
- "Id=Vg/Rs\n",
- "print(\" plot point B Vgs=0\")\n",
- "print('at point A Id = %.2f A/s' %Id)\n",
- "Idmax=3*10**-3\n",
- "Idmin=2.3*10**-3\n",
- "Vdsmin=Vdd-Idmax*(Rd+Rs)\n",
- "Vdsmax=Vdd-Idmin*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vdsmax = %.2f V' %(Vdsmax))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0\n",
- " plot point A at Id=0\n",
- "at point A Vds = 0.00 A/s\n",
- " plot point B Vgs=0\n",
- "at point A Id = 0.00 A/s\n",
- "The value of Vdsmax = 13.50 V\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.7, Page No 401"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Id=3.0*10**-3\n",
- "Vgs=-2.3\n",
- "Vdsmin=10.0\n",
- "Vdd=25.0\n",
- "Vgsoff=-6\n",
- "Idss=8.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Rd=(Vdd-Vdsmin)/Id\n",
- "\n",
- "#Results\n",
- "print('The value of Td = %.2f kohm' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Td = 5.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.8 Page No 403"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vgs=2.3\n",
- "\n",
- "#Calculations\n",
- "Rs=Vgs/Id\n",
- "Rd=((Vdd-Vds)/Id)-Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Rd = %.2f ohm' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd = 4.23 ohm\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.9 Page No 405"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vg=5.2\n",
- "Vgsoff=-6\n",
- "Idss=8.0*10**-3\n",
- "R2=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "R=(Vdd-Vds)/Id#R=(Rs+Rd)/2\n",
- "Rd=R/2\n",
- "Rs=Rd\n",
- "Vgs=Id*Rs\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vs=Id*Rs\n",
- "Vg=Vs-(-Vgs)\n",
- "R1=((Vdd-Vg)*R2)/Vg\n",
- "\n",
- "#Results\n",
- "print('The value of R = %.2f Mohm' %(R1/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R = 3.83 Mohm\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.11, Page No 412"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vee=20.0\n",
- "Id=3.0*10**-3\n",
- "Vds=9.0\n",
- "Vbe=.7\n",
- "Vb=0\n",
- "Ve=Vee-Vbe\n",
- "\n",
- "#Calculations\n",
- "Re=Ve/Id\n",
- "Re=6.8*10**3#satnadard value\n",
- "Id=Ve/Re\n",
- "Idss=16*10**-3\n",
- "Vgsoff=-8\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vs=Vb-Vgs\n",
- "Vrd=Vee-Vds-Vs\n",
- "Rd=Vrd/Id\n",
- "\n",
- "#Results\n",
- "print('The value of Rd = %.2f V' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd = 2.24 V\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.12 Page No 415"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Idss=5.0*10**-3\n",
- "Vgsoff=6.0\n",
- "Rs=3.3*10**3\n",
- "Vdd=20.0\n",
- "Rd=Rs\n",
- "\n",
- "#Calculations\n",
- "print(\"when Id=0 % Vgs=Vs=0\")\n",
- "Id=0\n",
- "Vgs=0\n",
- "Vs=0\n",
- "print(\" at point A universal transfer characteristic Id/Idss and Vgs/Vgsoff=0\")\n",
- "Id=1.5*10**-3\n",
- "Vgs=Id*Rs\n",
- "y=Id/Idss\n",
- "x=Vgs/Vgsoff\n",
- "print(\" point B the universal transfer charecteristic x=.825 and y=.3\")\n",
- "Id=.2*Idss\n",
- "Vds=Vdd-Id*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vds = %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0 % Vgs=Vs=0\n",
- " at point A universal transfer characteristic Id/Idss and Vgs/Vgsoff=0\n",
- " point B the universal transfer charecteristic x=.825 and y=.3\n",
- "The value of Vds = 13.40 V\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.13 Page No 416"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Idss=9.0*10**-3\n",
- "Vgsoff=7.0\n",
- "Vdd=22.0\n",
- "R1=4.7*10**6\n",
- "R2=1.0*10**6\n",
- "Rs=2.7*10**3\n",
- "Rd=Rs\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"when Vgs=0 % Vgs/Vgsoff=0\")\n",
- "Id=Vg/Rs\n",
- "print(\"when Vgs/Vgsoff=.5\")\n",
- "Vgs=.5*(-Vgsoff)\n",
- "Id=(Vg-Vgs)/Rs\n",
- "x=Id/Idss\n",
- "print(\" point Y on universal characteristic x=.3 and Vgs/Vgsoff=.5\")\n",
- "print(\"draw voltage divider bias line through X nad Y where bisa line intersect transfer curve\")\n",
- "Id=.29*Idss\n",
- "Vds=Vdd-Id*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Vgs=0 % Vgs/Vgsoff=0\n",
- "when Vgs/Vgsoff=.5\n",
- " point Y on universal characteristic x=.3 and Vgs/Vgsoff=.5\n",
- "draw voltage divider bias line through X nad Y where bisa line intersect transfer curve\n",
- "The value of Vds= 7.91 V\n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.14 Page No 419"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=40.0\n",
- "R2=1.0*10**6\n",
- "R1=5.6*10**6\n",
- "Rd=4.7\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"from the point where the bias line intersect the transfer curve\")\n",
- "Id=6.2\n",
- "Vds=Vdd-Id*Rd\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "from the point where the bias line intersect the transfer curve\n",
- "The value of Vds= 10.86 V\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.16, Page No 422"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "rDS=25.0\n",
- "Vgsoff=10.0\n",
- "Vds=200.0*10**-3\n",
- "Vdd=12.0\n",
- "\n",
- "#Calculations\n",
- "Id=Vds/rDS\n",
- "Rd=Vdd/Id\n",
- "Vi=-(Vgsoff+1)\n",
- "\n",
- "#Results\n",
- "print('The value of Vi= %.2f V' %(Vi))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vi= -11.00 V\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.17, Page No 424"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=50.0\n",
- "Rd=10.0\n",
- "R2=1.0*10**6\n",
- "rDS=0.25\n",
- "\n",
- "#Calculations\n",
- "Id=Vdd/Rd\n",
- "print(\" from transfer curve at Id=5 and Vgs=5.7\")\n",
- "Vgs=5.7\n",
- "R1=((Vdd-Vgs)*R2)/Vgs#use 6.8Mohm to make Vgs>5.7V to ensure that the FET is biased on\n",
- "Vds=Id*rDS\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " from transfer curve at Id=5 and Vgs=5.7\n",
- "The value of Vds= 1.25 V\n"
- ]
- }
- ],
- "prompt_number": 12
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter10_1.ipynb b/Electronic_Devices_and_Circuits/Chapter10_1.ipynb deleted file mode 100755 index b92c4b1d..00000000 --- a/Electronic_Devices_and_Circuits/Chapter10_1.ipynb +++ /dev/null @@ -1,587 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 10 : FET biasing"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.1, Page No 381"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=22.0\n",
- "Rd=2.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"when Id=0\")\n",
- "Id=0\n",
- "Vds=Vdd-Id*Rd\n",
- "print('at point A Vds = %.2f V' %Vds)\n",
- "Vds=0\n",
- "Id=Vdd/Rd\n",
- "\n",
- "#Results\n",
- "print(\"when Vds=0\")\n",
- "print('at point A Id = %.2f mA' %(Id*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0\n",
- "at point A Vds = 22.00 V\n",
- "when Vds=0\n",
- "at point A Id = 11.00 mA\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.4, Page No 387"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Idss=8.0*10**-3\n",
- "Vpmax=6.0\n",
- "Vgs=2.3\n",
- "Vgsmax=6\n",
- "\n",
- "#Calculations\n",
- "Id=Idss*(1-(Vgs/Vgsmax))**2\n",
- "Idss=4*10**-3\n",
- "Vp=3\n",
- "Idmin=Idss*(1-(Vgs/Vp))**2\n",
- "\n",
- "#Results\n",
- "print('at point A Idmin = %.2f mA' %(Idmin*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "at point A Idmin = 0.22 mA\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.6 Page No 393"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vdd=25.0\n",
- "R2=1.0*10**6\n",
- "R1=3.8*10**6\n",
- "Rs=2.5*10**3\n",
- "Rd=2.5*10**3\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"when Id=0\")\n",
- "Id=0\n",
- "Vgs=Vg-Id*Rs\n",
- "print(\" plot point A at Id=0\")\n",
- "print('at point A Vds = %.2f A/s' %Vds)\n",
- "Vgs=0\n",
- "Id=Vg/Rs\n",
- "print(\" plot point B Vgs=0\")\n",
- "print('at point A Id = %.2f A/s' %Id)\n",
- "Idmax=3*10**-3\n",
- "Idmin=2.3*10**-3\n",
- "Vdsmin=Vdd-Idmax*(Rd+Rs)\n",
- "Vdsmax=Vdd-Idmin*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vdsmax = %.2f V' %(Vdsmax))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0\n",
- " plot point A at Id=0\n",
- "at point A Vds = 0.00 A/s\n",
- " plot point B Vgs=0\n",
- "at point A Id = 0.00 A/s\n",
- "The value of Vdsmax = 13.50 V\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.7, Page No 401"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Id=3.0*10**-3\n",
- "Vgs=-2.3\n",
- "Vdsmin=10.0\n",
- "Vdd=25.0\n",
- "Vgsoff=-6\n",
- "Idss=8.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Rd=(Vdd-Vdsmin)/Id\n",
- "\n",
- "#Results\n",
- "print('The value of Td = %.2f kohm' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Td = 5.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.8 Page No 403"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vgs=2.3\n",
- "\n",
- "#Calculations\n",
- "Rs=Vgs/Id\n",
- "Rd=((Vdd-Vds)/Id)-Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Rd = %.2f ohm' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd = 4.23 ohm\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.9 Page No 405"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vg=5.2\n",
- "Vgsoff=-6\n",
- "Idss=8.0*10**-3\n",
- "R2=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "R=(Vdd-Vds)/Id#R=(Rs+Rd)/2\n",
- "Rd=R/2\n",
- "Rs=Rd\n",
- "Vgs=Id*Rs\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vs=Id*Rs\n",
- "Vg=Vs-(-Vgs)\n",
- "R1=((Vdd-Vg)*R2)/Vg\n",
- "\n",
- "#Results\n",
- "print('The value of R = %.2f Mohm' %(R1/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R = 3.83 Mohm\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.11, Page No 412"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vee=20.0\n",
- "Id=3.0*10**-3\n",
- "Vds=9.0\n",
- "Vbe=.7\n",
- "Vb=0\n",
- "Ve=Vee-Vbe\n",
- "\n",
- "#Calculations\n",
- "Re=Ve/Id\n",
- "Re=6.8*10**3#satnadard value\n",
- "Id=Ve/Re\n",
- "Idss=16*10**-3\n",
- "Vgsoff=-8\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vs=Vb-Vgs\n",
- "Vrd=Vee-Vds-Vs\n",
- "Rd=Vrd/Id\n",
- "\n",
- "#Results\n",
- "print('The value of Rd = %.2f V' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd = 2.24 V\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.12 Page No 415"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Idss=5.0*10**-3\n",
- "Vgsoff=6.0\n",
- "Rs=3.3*10**3\n",
- "Vdd=20.0\n",
- "Rd=Rs\n",
- "\n",
- "#Calculations\n",
- "print(\"when Id=0 % Vgs=Vs=0\")\n",
- "Id=0\n",
- "Vgs=0\n",
- "Vs=0\n",
- "print(\" at point A universal transfer characteristic Id/Idss and Vgs/Vgsoff=0\")\n",
- "Id=1.5*10**-3\n",
- "Vgs=Id*Rs\n",
- "y=Id/Idss\n",
- "x=Vgs/Vgsoff\n",
- "print(\" point B the universal transfer charecteristic x=.825 and y=.3\")\n",
- "Id=.2*Idss\n",
- "Vds=Vdd-Id*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vds = %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0 % Vgs=Vs=0\n",
- " at point A universal transfer characteristic Id/Idss and Vgs/Vgsoff=0\n",
- " point B the universal transfer charecteristic x=.825 and y=.3\n",
- "The value of Vds = 13.40 V\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.13 Page No 416"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Idss=9.0*10**-3\n",
- "Vgsoff=7.0\n",
- "Vdd=22.0\n",
- "R1=4.7*10**6\n",
- "R2=1.0*10**6\n",
- "Rs=2.7*10**3\n",
- "Rd=Rs\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"when Vgs=0 % Vgs/Vgsoff=0\")\n",
- "Id=Vg/Rs\n",
- "print(\"when Vgs/Vgsoff=.5\")\n",
- "Vgs=.5*(-Vgsoff)\n",
- "Id=(Vg-Vgs)/Rs\n",
- "x=Id/Idss\n",
- "print(\" point Y on universal characteristic x=.3 and Vgs/Vgsoff=.5\")\n",
- "print(\"draw voltage divider bias line through X nad Y where bisa line intersect transfer curve\")\n",
- "Id=.29*Idss\n",
- "Vds=Vdd-Id*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Vgs=0 % Vgs/Vgsoff=0\n",
- "when Vgs/Vgsoff=.5\n",
- " point Y on universal characteristic x=.3 and Vgs/Vgsoff=.5\n",
- "draw voltage divider bias line through X nad Y where bisa line intersect transfer curve\n",
- "The value of Vds= 7.91 V\n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.14 Page No 419"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=40.0\n",
- "R2=1.0*10**6\n",
- "R1=5.6*10**6\n",
- "Rd=4.7\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"from the point where the bias line intersect the transfer curve\")\n",
- "Id=6.2\n",
- "Vds=Vdd-Id*Rd\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "from the point where the bias line intersect the transfer curve\n",
- "The value of Vds= 10.86 V\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.16, Page No 422"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "rDS=25.0\n",
- "Vgsoff=10.0\n",
- "Vds=200.0*10**-3\n",
- "Vdd=12.0\n",
- "\n",
- "#Calculations\n",
- "Id=Vds/rDS\n",
- "Rd=Vdd/Id\n",
- "Vi=-(Vgsoff+1)\n",
- "\n",
- "#Results\n",
- "print('The value of Vi= %.2f V' %(Vi))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vi= -11.00 V\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.17, Page No 424"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=50.0\n",
- "Rd=10.0\n",
- "R2=1.0*10**6\n",
- "rDS=0.25\n",
- "\n",
- "#Calculations\n",
- "Id=Vdd/Rd\n",
- "print(\" from transfer curve at Id=5 and Vgs=5.7\")\n",
- "Vgs=5.7\n",
- "R1=((Vdd-Vgs)*R2)/Vgs#use 6.8Mohm to make Vgs>5.7V to ensure that the FET is biased on\n",
- "Vds=Id*rDS\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " from transfer curve at Id=5 and Vgs=5.7\n",
- "The value of Vds= 1.25 V\n"
- ]
- }
- ],
- "prompt_number": 12
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter10_2.ipynb b/Electronic_Devices_and_Circuits/Chapter10_2.ipynb deleted file mode 100755 index b92c4b1d..00000000 --- a/Electronic_Devices_and_Circuits/Chapter10_2.ipynb +++ /dev/null @@ -1,587 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 10 : FET biasing"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.1, Page No 381"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=22.0\n",
- "Rd=2.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"when Id=0\")\n",
- "Id=0\n",
- "Vds=Vdd-Id*Rd\n",
- "print('at point A Vds = %.2f V' %Vds)\n",
- "Vds=0\n",
- "Id=Vdd/Rd\n",
- "\n",
- "#Results\n",
- "print(\"when Vds=0\")\n",
- "print('at point A Id = %.2f mA' %(Id*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0\n",
- "at point A Vds = 22.00 V\n",
- "when Vds=0\n",
- "at point A Id = 11.00 mA\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.4, Page No 387"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Idss=8.0*10**-3\n",
- "Vpmax=6.0\n",
- "Vgs=2.3\n",
- "Vgsmax=6\n",
- "\n",
- "#Calculations\n",
- "Id=Idss*(1-(Vgs/Vgsmax))**2\n",
- "Idss=4*10**-3\n",
- "Vp=3\n",
- "Idmin=Idss*(1-(Vgs/Vp))**2\n",
- "\n",
- "#Results\n",
- "print('at point A Idmin = %.2f mA' %(Idmin*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "at point A Idmin = 0.22 mA\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.6 Page No 393"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vdd=25.0\n",
- "R2=1.0*10**6\n",
- "R1=3.8*10**6\n",
- "Rs=2.5*10**3\n",
- "Rd=2.5*10**3\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"when Id=0\")\n",
- "Id=0\n",
- "Vgs=Vg-Id*Rs\n",
- "print(\" plot point A at Id=0\")\n",
- "print('at point A Vds = %.2f A/s' %Vds)\n",
- "Vgs=0\n",
- "Id=Vg/Rs\n",
- "print(\" plot point B Vgs=0\")\n",
- "print('at point A Id = %.2f A/s' %Id)\n",
- "Idmax=3*10**-3\n",
- "Idmin=2.3*10**-3\n",
- "Vdsmin=Vdd-Idmax*(Rd+Rs)\n",
- "Vdsmax=Vdd-Idmin*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vdsmax = %.2f V' %(Vdsmax))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0\n",
- " plot point A at Id=0\n",
- "at point A Vds = 0.00 A/s\n",
- " plot point B Vgs=0\n",
- "at point A Id = 0.00 A/s\n",
- "The value of Vdsmax = 13.50 V\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.7, Page No 401"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Id=3.0*10**-3\n",
- "Vgs=-2.3\n",
- "Vdsmin=10.0\n",
- "Vdd=25.0\n",
- "Vgsoff=-6\n",
- "Idss=8.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Rd=(Vdd-Vdsmin)/Id\n",
- "\n",
- "#Results\n",
- "print('The value of Td = %.2f kohm' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Td = 5.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.8 Page No 403"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vgs=2.3\n",
- "\n",
- "#Calculations\n",
- "Rs=Vgs/Id\n",
- "Rd=((Vdd-Vds)/Id)-Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Rd = %.2f ohm' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd = 4.23 ohm\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.9 Page No 405"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vg=5.2\n",
- "Vgsoff=-6\n",
- "Idss=8.0*10**-3\n",
- "R2=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "R=(Vdd-Vds)/Id#R=(Rs+Rd)/2\n",
- "Rd=R/2\n",
- "Rs=Rd\n",
- "Vgs=Id*Rs\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vs=Id*Rs\n",
- "Vg=Vs-(-Vgs)\n",
- "R1=((Vdd-Vg)*R2)/Vg\n",
- "\n",
- "#Results\n",
- "print('The value of R = %.2f Mohm' %(R1/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R = 3.83 Mohm\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.11, Page No 412"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vee=20.0\n",
- "Id=3.0*10**-3\n",
- "Vds=9.0\n",
- "Vbe=.7\n",
- "Vb=0\n",
- "Ve=Vee-Vbe\n",
- "\n",
- "#Calculations\n",
- "Re=Ve/Id\n",
- "Re=6.8*10**3#satnadard value\n",
- "Id=Ve/Re\n",
- "Idss=16*10**-3\n",
- "Vgsoff=-8\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vs=Vb-Vgs\n",
- "Vrd=Vee-Vds-Vs\n",
- "Rd=Vrd/Id\n",
- "\n",
- "#Results\n",
- "print('The value of Rd = %.2f V' %(Rd/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd = 2.24 V\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.12 Page No 415"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Idss=5.0*10**-3\n",
- "Vgsoff=6.0\n",
- "Rs=3.3*10**3\n",
- "Vdd=20.0\n",
- "Rd=Rs\n",
- "\n",
- "#Calculations\n",
- "print(\"when Id=0 % Vgs=Vs=0\")\n",
- "Id=0\n",
- "Vgs=0\n",
- "Vs=0\n",
- "print(\" at point A universal transfer characteristic Id/Idss and Vgs/Vgsoff=0\")\n",
- "Id=1.5*10**-3\n",
- "Vgs=Id*Rs\n",
- "y=Id/Idss\n",
- "x=Vgs/Vgsoff\n",
- "print(\" point B the universal transfer charecteristic x=.825 and y=.3\")\n",
- "Id=.2*Idss\n",
- "Vds=Vdd-Id*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vds = %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Id=0 % Vgs=Vs=0\n",
- " at point A universal transfer characteristic Id/Idss and Vgs/Vgsoff=0\n",
- " point B the universal transfer charecteristic x=.825 and y=.3\n",
- "The value of Vds = 13.40 V\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.13 Page No 416"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Idss=9.0*10**-3\n",
- "Vgsoff=7.0\n",
- "Vdd=22.0\n",
- "R1=4.7*10**6\n",
- "R2=1.0*10**6\n",
- "Rs=2.7*10**3\n",
- "Rd=Rs\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"when Vgs=0 % Vgs/Vgsoff=0\")\n",
- "Id=Vg/Rs\n",
- "print(\"when Vgs/Vgsoff=.5\")\n",
- "Vgs=.5*(-Vgsoff)\n",
- "Id=(Vg-Vgs)/Rs\n",
- "x=Id/Idss\n",
- "print(\" point Y on universal characteristic x=.3 and Vgs/Vgsoff=.5\")\n",
- "print(\"draw voltage divider bias line through X nad Y where bisa line intersect transfer curve\")\n",
- "Id=.29*Idss\n",
- "Vds=Vdd-Id*(Rd+Rs)\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Vgs=0 % Vgs/Vgsoff=0\n",
- "when Vgs/Vgsoff=.5\n",
- " point Y on universal characteristic x=.3 and Vgs/Vgsoff=.5\n",
- "draw voltage divider bias line through X nad Y where bisa line intersect transfer curve\n",
- "The value of Vds= 7.91 V\n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.14 Page No 419"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=40.0\n",
- "R2=1.0*10**6\n",
- "R1=5.6*10**6\n",
- "Rd=4.7\n",
- "\n",
- "#Calculations\n",
- "Vg=(Vdd*R2)/(R1+R2)\n",
- "print(\"from the point where the bias line intersect the transfer curve\")\n",
- "Id=6.2\n",
- "Vds=Vdd-Id*Rd\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "from the point where the bias line intersect the transfer curve\n",
- "The value of Vds= 10.86 V\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.16, Page No 422"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "rDS=25.0\n",
- "Vgsoff=10.0\n",
- "Vds=200.0*10**-3\n",
- "Vdd=12.0\n",
- "\n",
- "#Calculations\n",
- "Id=Vds/rDS\n",
- "Rd=Vdd/Id\n",
- "Vi=-(Vgsoff+1)\n",
- "\n",
- "#Results\n",
- "print('The value of Vi= %.2f V' %(Vi))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vi= -11.00 V\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10.17, Page No 424"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vdd=50.0\n",
- "Rd=10.0\n",
- "R2=1.0*10**6\n",
- "rDS=0.25\n",
- "\n",
- "#Calculations\n",
- "Id=Vdd/Rd\n",
- "print(\" from transfer curve at Id=5 and Vgs=5.7\")\n",
- "Vgs=5.7\n",
- "R1=((Vdd-Vgs)*R2)/Vgs#use 6.8Mohm to make Vgs>5.7V to ensure that the FET is biased on\n",
- "Vds=Id*rDS\n",
- "\n",
- "#Results\n",
- "print('The value of Vds= %.2f V' %(Vds))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " from transfer curve at Id=5 and Vgs=5.7\n",
- "The value of Vds= 1.25 V\n"
- ]
- }
- ],
- "prompt_number": 12
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter11.ipynb b/Electronic_Devices_and_Circuits/Chapter11.ipynb deleted file mode 100755 index e211f994..00000000 --- a/Electronic_Devices_and_Circuits/Chapter11.ipynb +++ /dev/null @@ -1,305 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 11 : Ac analysis of FEt circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.2, Page No 443"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Yos=10.0*10**-6\n",
- "Yfs=3000.0*10**-6\n",
- "R1=1.0*10**6\n",
- "R2=5.6*10**6\n",
- "Rd=2.7*10**3\n",
- "Rl=Rd\n",
- "\n",
- "#Calculations\n",
- "rd=1.0/Yos\n",
- "Zi=((R1*R2)/(R1+R2))*10**-3\n",
- "print(\"input impedance is %dKohm \" %Zi)\n",
- "Zo=(Rd*rd)/(Rd+rd)\n",
- "print(\" output inpedance is %dohm \" %Zo)\n",
- "Av=-Yfs*((Rl*rd)/(Rl+rd))\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance is 848Kohm \n",
- " output inpedance is 2629ohm \n",
- "The value of Av= -7.89 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.03, Page No 447"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Yos=10.0*10**-6\n",
- "Yfs=4000.0*10**-6\n",
- "Ig=1.0*10**-9\n",
- "Vgs=15.0\n",
- "Rs=3.3*10**3\n",
- "Rg=1.0*10**6\n",
- "Rd=4.7*10**3\n",
- "Rl=33*10**3\n",
- "\n",
- "#Calculations\n",
- "rd=1.0/Yos\n",
- "Rgs=(Vgs/Ig)\n",
- "Zg=(Rgs*(1+Yfs*Rs))\n",
- "Zi=Rg\n",
- "Zd=rd+Rs+(Yfs*Rs*rd)\n",
- "Zo=(Rd*Zd)/(Rd+Zd)\n",
- "Av=-(Yfs*((Rd*Rl)/(Rd+Rl)))/(1+Yfs*Rs)\n",
- "Av=-((Rd*Rl)/(Rd+Rl))/Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= -1.25 \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.4 Page No 451"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Yfs=3000.0*10**-6\n",
- "Rgs=100.0*10**6\n",
- "rd=50.0*10**3\n",
- "Rs=5.6*10**3\n",
- "Rl=12.0*10**3\n",
- "R1=1.5*10**6\n",
- "R2=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "Zg=Rgs*(1+Yfs*((Rs*Rl)/(Rs+Rl)))\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "Zs=((1/Yfs)*rd)/((1/Yfs)+rd)\n",
- "Zo=(Rs*Rl*(1/Yfs))/(Rs*Rl+Rs*(1/Yfs)+Rl*(1/Yfs))\n",
- "Av=-(Yfs*((Rs*Rl)/(Rs+Rl)))/(1+Yfs*((Rs*Rl)/(Rs+Rl)))\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= -0.92 \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.5, Page No 456"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Yfs=3000.0*10**-6\n",
- "rd=50.0*10**3\n",
- "Rs=3.3*10**3\n",
- "Rd=4.7*10**3\n",
- "Rl=50.0*10**3\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Zs=1/Yfs\n",
- "Zi=((1/Yfs)*Rs)/((1/Yfs)+Rs)\n",
- "Zd=rd\n",
- "Zo=(Rd*rd)/(Rd+rd)\n",
- "Av=Yfs*((Rd*Rl)/(Rd+Rl))\n",
- "print(\"overall volateg gain\")\n",
- "Av=(Yfs*((Rd*Rl)/(Rd+Rl))*Zi)/(rs+Zi)\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall volateg gain\n",
- "The value of Av= 4.32 \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.6 Page No 459"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vgs=2.3\n",
- "\n",
- "#Calculations\n",
- "Rs=Vgs/Id\n",
- "Rd=((Vdd-Vds)/Id)-Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Rd= %.2f ' %(Rd))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd= 4233.33 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.7 Page No 462"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Crss=1.0*10**-12\n",
- "Ciss=5.0*10**-12\n",
- "Yfs=2500.0*10**-6\n",
- "Yos=75.0*10**-6\n",
- "Rd=5.6*10**3\n",
- "Rl=100.0*10**3\n",
- "R1=3.3*10**6\n",
- "R2=1.0*10**6\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Cgd=Crss\n",
- "Cgs=Ciss-Crss\n",
- "Av=Yfs*(((1/Yos)*Rd*Rl))/((Rd*Rl+(1/Yos)*Rd+(1/Yos)*Rl))\n",
- "Cin=Cgs+(1+Av)*Cgd\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "f2=1/(2*3.14*Cin*((rs*Zi)/(rs+Zi)))\n",
- "\n",
- "#Results\n",
- "print('The input capicitance limited = %.2f ' %(f2/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The input capicitance limited = 18.34 \n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter11_1.ipynb b/Electronic_Devices_and_Circuits/Chapter11_1.ipynb deleted file mode 100755 index e211f994..00000000 --- a/Electronic_Devices_and_Circuits/Chapter11_1.ipynb +++ /dev/null @@ -1,305 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 11 : Ac analysis of FEt circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.2, Page No 443"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Yos=10.0*10**-6\n",
- "Yfs=3000.0*10**-6\n",
- "R1=1.0*10**6\n",
- "R2=5.6*10**6\n",
- "Rd=2.7*10**3\n",
- "Rl=Rd\n",
- "\n",
- "#Calculations\n",
- "rd=1.0/Yos\n",
- "Zi=((R1*R2)/(R1+R2))*10**-3\n",
- "print(\"input impedance is %dKohm \" %Zi)\n",
- "Zo=(Rd*rd)/(Rd+rd)\n",
- "print(\" output inpedance is %dohm \" %Zo)\n",
- "Av=-Yfs*((Rl*rd)/(Rl+rd))\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance is 848Kohm \n",
- " output inpedance is 2629ohm \n",
- "The value of Av= -7.89 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.03, Page No 447"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Yos=10.0*10**-6\n",
- "Yfs=4000.0*10**-6\n",
- "Ig=1.0*10**-9\n",
- "Vgs=15.0\n",
- "Rs=3.3*10**3\n",
- "Rg=1.0*10**6\n",
- "Rd=4.7*10**3\n",
- "Rl=33*10**3\n",
- "\n",
- "#Calculations\n",
- "rd=1.0/Yos\n",
- "Rgs=(Vgs/Ig)\n",
- "Zg=(Rgs*(1+Yfs*Rs))\n",
- "Zi=Rg\n",
- "Zd=rd+Rs+(Yfs*Rs*rd)\n",
- "Zo=(Rd*Zd)/(Rd+Zd)\n",
- "Av=-(Yfs*((Rd*Rl)/(Rd+Rl)))/(1+Yfs*Rs)\n",
- "Av=-((Rd*Rl)/(Rd+Rl))/Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= -1.25 \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.4 Page No 451"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Yfs=3000.0*10**-6\n",
- "Rgs=100.0*10**6\n",
- "rd=50.0*10**3\n",
- "Rs=5.6*10**3\n",
- "Rl=12.0*10**3\n",
- "R1=1.5*10**6\n",
- "R2=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "Zg=Rgs*(1+Yfs*((Rs*Rl)/(Rs+Rl)))\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "Zs=((1/Yfs)*rd)/((1/Yfs)+rd)\n",
- "Zo=(Rs*Rl*(1/Yfs))/(Rs*Rl+Rs*(1/Yfs)+Rl*(1/Yfs))\n",
- "Av=-(Yfs*((Rs*Rl)/(Rs+Rl)))/(1+Yfs*((Rs*Rl)/(Rs+Rl)))\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= -0.92 \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.5, Page No 456"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Yfs=3000.0*10**-6\n",
- "rd=50.0*10**3\n",
- "Rs=3.3*10**3\n",
- "Rd=4.7*10**3\n",
- "Rl=50.0*10**3\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Zs=1/Yfs\n",
- "Zi=((1/Yfs)*Rs)/((1/Yfs)+Rs)\n",
- "Zd=rd\n",
- "Zo=(Rd*rd)/(Rd+rd)\n",
- "Av=Yfs*((Rd*Rl)/(Rd+Rl))\n",
- "print(\"overall volateg gain\")\n",
- "Av=(Yfs*((Rd*Rl)/(Rd+Rl))*Zi)/(rs+Zi)\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall volateg gain\n",
- "The value of Av= 4.32 \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.6 Page No 459"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vgs=2.3\n",
- "\n",
- "#Calculations\n",
- "Rs=Vgs/Id\n",
- "Rd=((Vdd-Vds)/Id)-Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Rd= %.2f ' %(Rd))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd= 4233.33 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.7 Page No 462"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Crss=1.0*10**-12\n",
- "Ciss=5.0*10**-12\n",
- "Yfs=2500.0*10**-6\n",
- "Yos=75.0*10**-6\n",
- "Rd=5.6*10**3\n",
- "Rl=100.0*10**3\n",
- "R1=3.3*10**6\n",
- "R2=1.0*10**6\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Cgd=Crss\n",
- "Cgs=Ciss-Crss\n",
- "Av=Yfs*(((1/Yos)*Rd*Rl))/((Rd*Rl+(1/Yos)*Rd+(1/Yos)*Rl))\n",
- "Cin=Cgs+(1+Av)*Cgd\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "f2=1/(2*3.14*Cin*((rs*Zi)/(rs+Zi)))\n",
- "\n",
- "#Results\n",
- "print('The input capicitance limited = %.2f ' %(f2/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The input capicitance limited = 18.34 \n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter11_2.ipynb b/Electronic_Devices_and_Circuits/Chapter11_2.ipynb deleted file mode 100755 index e211f994..00000000 --- a/Electronic_Devices_and_Circuits/Chapter11_2.ipynb +++ /dev/null @@ -1,305 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 11 : Ac analysis of FEt circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.2, Page No 443"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Yos=10.0*10**-6\n",
- "Yfs=3000.0*10**-6\n",
- "R1=1.0*10**6\n",
- "R2=5.6*10**6\n",
- "Rd=2.7*10**3\n",
- "Rl=Rd\n",
- "\n",
- "#Calculations\n",
- "rd=1.0/Yos\n",
- "Zi=((R1*R2)/(R1+R2))*10**-3\n",
- "print(\"input impedance is %dKohm \" %Zi)\n",
- "Zo=(Rd*rd)/(Rd+rd)\n",
- "print(\" output inpedance is %dohm \" %Zo)\n",
- "Av=-Yfs*((Rl*rd)/(Rl+rd))\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance is 848Kohm \n",
- " output inpedance is 2629ohm \n",
- "The value of Av= -7.89 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.03, Page No 447"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Yos=10.0*10**-6\n",
- "Yfs=4000.0*10**-6\n",
- "Ig=1.0*10**-9\n",
- "Vgs=15.0\n",
- "Rs=3.3*10**3\n",
- "Rg=1.0*10**6\n",
- "Rd=4.7*10**3\n",
- "Rl=33*10**3\n",
- "\n",
- "#Calculations\n",
- "rd=1.0/Yos\n",
- "Rgs=(Vgs/Ig)\n",
- "Zg=(Rgs*(1+Yfs*Rs))\n",
- "Zi=Rg\n",
- "Zd=rd+Rs+(Yfs*Rs*rd)\n",
- "Zo=(Rd*Zd)/(Rd+Zd)\n",
- "Av=-(Yfs*((Rd*Rl)/(Rd+Rl)))/(1+Yfs*Rs)\n",
- "Av=-((Rd*Rl)/(Rd+Rl))/Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= -1.25 \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.4 Page No 451"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Yfs=3000.0*10**-6\n",
- "Rgs=100.0*10**6\n",
- "rd=50.0*10**3\n",
- "Rs=5.6*10**3\n",
- "Rl=12.0*10**3\n",
- "R1=1.5*10**6\n",
- "R2=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "Zg=Rgs*(1+Yfs*((Rs*Rl)/(Rs+Rl)))\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "Zs=((1/Yfs)*rd)/((1/Yfs)+rd)\n",
- "Zo=(Rs*Rl*(1/Yfs))/(Rs*Rl+Rs*(1/Yfs)+Rl*(1/Yfs))\n",
- "Av=-(Yfs*((Rs*Rl)/(Rs+Rl)))/(1+Yfs*((Rs*Rl)/(Rs+Rl)))\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= -0.92 \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.5, Page No 456"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Yfs=3000.0*10**-6\n",
- "rd=50.0*10**3\n",
- "Rs=3.3*10**3\n",
- "Rd=4.7*10**3\n",
- "Rl=50.0*10**3\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Zs=1/Yfs\n",
- "Zi=((1/Yfs)*Rs)/((1/Yfs)+Rs)\n",
- "Zd=rd\n",
- "Zo=(Rd*rd)/(Rd+rd)\n",
- "Av=Yfs*((Rd*Rl)/(Rd+Rl))\n",
- "print(\"overall volateg gain\")\n",
- "Av=(Yfs*((Rd*Rl)/(Rd+Rl))*Zi)/(rs+Zi)\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall volateg gain\n",
- "The value of Av= 4.32 \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.6 Page No 459"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=3.0*10**-3\n",
- "Vds=10.0\n",
- "Vdd=25.0\n",
- "Vgs=2.3\n",
- "\n",
- "#Calculations\n",
- "Rs=Vgs/Id\n",
- "Rd=((Vdd-Vds)/Id)-Rs\n",
- "\n",
- "#Results\n",
- "print('The value of Rd= %.2f ' %(Rd))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rd= 4233.33 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 11.7 Page No 462"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Crss=1.0*10**-12\n",
- "Ciss=5.0*10**-12\n",
- "Yfs=2500.0*10**-6\n",
- "Yos=75.0*10**-6\n",
- "Rd=5.6*10**3\n",
- "Rl=100.0*10**3\n",
- "R1=3.3*10**6\n",
- "R2=1.0*10**6\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Cgd=Crss\n",
- "Cgs=Ciss-Crss\n",
- "Av=Yfs*(((1/Yos)*Rd*Rl))/((Rd*Rl+(1/Yos)*Rd+(1/Yos)*Rl))\n",
- "Cin=Cgs+(1+Av)*Cgd\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "f2=1/(2*3.14*Cin*((rs*Zi)/(rs+Zi)))\n",
- "\n",
- "#Results\n",
- "print('The input capicitance limited = %.2f ' %(f2/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The input capicitance limited = 18.34 \n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter12.ipynb b/Electronic_Devices_and_Circuits/Chapter12.ipynb deleted file mode 100755 index b0fb9991..00000000 --- a/Electronic_Devices_and_Circuits/Chapter12.ipynb +++ /dev/null @@ -1,1196 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 12 : Small signal Amplifiers"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.1, Page No 474"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "hie=1.0*10**3\n",
- "hib=20.0\n",
- "f1=100.0\n",
- "Rc=3.3*10**3\n",
- "\n",
- "#Calculations\n",
- "Re=Rc\n",
- "print(\" required capacitance\")\n",
- "Xc2=hib\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "print(\" voltage gain with emitter terminal completely bypassed to ground\")\n",
- "Av=-(hfe*Rc)/hie\n",
- "print(\"voltage gain when f=100\")\n",
- "Av=-(hfe*Rc)/math.sqrt(((hie**2)+((1+hfe)*Xc2)**2))\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain when C2 is incorrectly selected as Xc2=Re/10\")\n",
- "Avx=-(hfe*Rc)/math.sqrt(((hie**2)+((1+hfe)*(Re/10))**2))\n",
- "print('The value of Avx= %.2f ' %(Avx))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " required capacitance\n",
- " voltage gain with emitter terminal completely bypassed to ground\n",
- "voltage gain when f=100\n",
- " voltage gain when C2 is incorrectly selected as Xc2=Re/10\n",
- "The value of Avx= -9.79 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.2, Page No 477"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=24.0\n",
- "Ve=5.0\n",
- "Vce=3.0\n",
- "Rl=120.0*10**3\n",
- "Vbe=0.7\n",
- "Rc=Rl/10.0\n",
- "\n",
- "#Calculations\n",
- "Vrc=Vcc-Vce-Ve\n",
- "Ic=Vrc/Rc\n",
- "Re=Ve/Ic#use 3.9Kohm standard value to make Ic littel less than design level\n",
- "Re=3.9*10**3\n",
- "R2=10*Re\n",
- "I2=(Ve+Vbe)/R2\n",
- "R1=(Vcc-Ve-Vbe)/I2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f ' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 125.21 \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.3 Page No 477"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "Ie=1.3*10**-3\n",
- "f1=100.0\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Rl=R1\n",
- "re=(26*10**-3)/Ie\n",
- "Xc2=re\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "C1=1/((2*3.14*f1*((Zi+rs)/10)))\n",
- "C3=1/(2*3.14*f1*((Rc+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf ' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 0.12 mf \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.5, Page No 484"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "rs=600.0\n",
- "f1=100.0\n",
- "Yfs=6000.0*10**-6\n",
- "R1=4.7*10**6\n",
- "R2=1.0*10**6\n",
- "Rd=6.8*10**3\n",
- "Rl=120*10**3\n",
- "\n",
- "#Calculations\n",
- "Xc2=1/Yfs\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "C1=1/(2*3.14*f1*(Zi+rs)/10)\n",
- "C3=1/(2*3.14*f1*(Rd+Rl)/10)\n",
- "\n",
- "#Calculations\n",
- "print('The value of C3= %.2f mF' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 0.13 mF\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.7 Page No 489"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "hie=2.0*10**3\n",
- "R7=12.0*10**3\n",
- "Zo=R7\n",
- "R5=R1\n",
- "R6=R2\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "R3=R7\n",
- "Zl=R1\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Zi2=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Av1=-(hfe*((R3*Zi2)/(R3+Zi2)))/hie\n",
- "Av2=-(hfe*((R7*Zl)/(R7+Zl)))/hie\n",
- "Av=Av1*Av2\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= 44180.12 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.8 Page No 491"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ve1=5.0\n",
- "Vce1=3.0\n",
- "Vce2=3.0\n",
- "Vbe=0.7\n",
- "Vcc=14.0\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Vb2=Ve1+Vce1\n",
- "Vc1=Vb2\n",
- "Ve2=Vb2-Vbe\n",
- "Vr5=Vcc-Ve2-Vce2\n",
- "R5=Rl/10#use 3.9Kohm satandard value\n",
- "R5=3.9*10**3\n",
- "Ic2=Vr5/R5\n",
- "R6=Ve2/Ic2#use 8.2Kohm as standard and recalculate\n",
- "R6=8.2*10**3\n",
- "Ic2=Ve2/R6\n",
- "Vr3=Vcc-Vc1\n",
- "print(\" Ic1>>Ib2 %select Ic1=1mA\")\n",
- "Ic1=1*10**-3\n",
- "R3=Vr3/Ic1#use standard value as 5.6Kohm and recalculate Ic1 in order ti keep Vb2=8V\n",
- "R3=5.6*10**3\n",
- "Ic1=Vr3/R3\n",
- "R4=Ve1/Ic1\n",
- "Vr2=Ve1+Vbe\n",
- "Vr1=Vcc-Ve1-Vbe\n",
- "R2=10*R4\n",
- "I2=(Ve1+Vbe)/R2\n",
- "R1=(Vr1*R2)/Vr2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Ic1>>Ib2 %select Ic1=1mA\n",
- "The value of R1= 67.95 kohm\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.9, Page No 493"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "re=26.0\n",
- "R1=68.0*10**3\n",
- "R2=47.0*10**3\n",
- "rs=600.0\n",
- "f1=75.0\n",
- "R5=3.9*10**3\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Xc1=(Zi+rs)/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=.65*re\n",
- "Xc3=Xc2\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "C3=C2\n",
- "Xc4=(R5+Rl)/10\n",
- "C4=1/(2*3.14*f1*Xc4)\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mf' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.48 mf\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.10, Page No 494"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "hie=1.3*10**3\n",
- "R3=5.6*10**3\n",
- "R5=3.9*10**3\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Av1=-(hfe*((R3*hie)/(R3+hie)))/hie\n",
- "Av2=-(hfe*((R5*Rl)/(R5+Rl)))/hie\n",
- "\n",
- "#Results\n",
- "print(\" overall voltage gain is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " overall voltage gain is Av=Av1*Av2\n",
- "The value of Av= 5546.20 \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.11 Page No 497"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vp=100.0*10**-3\n",
- "Rl=100.0\n",
- "Vbe=0.7\n",
- "Vcc=20.0\n",
- "\n",
- "#Calculations\n",
- "ip=Vp/Rl\n",
- "print(\"select Ie2>ip\")\n",
- "Ie2=2.0*10**-3\n",
- "Ve1=5.0\n",
- "Vce1=3.0\n",
- "Vb2=Ve1+Vce1\n",
- "Vc1=Vb2\n",
- "Ve2=Vb2-Vbe\n",
- "R5=Ve2/Ie2#use 3.3Kohm standard value\n",
- "R5=3.3*10**3\n",
- "Ic1=1*10**-3\n",
- "Vr3=Vcc-Vb2\n",
- "R3=Vr3/Ic1\n",
- "R4=Ve1/Ic1#use 4.7Kohm standard value\n",
- "R4=4.7*10**3\n",
- "Vb1=Ic1*R4+Vbe\n",
- "R2=10*R4\n",
- "R1=((Vcc-Vb1)*R2)/Vr2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select Ie2>ip\n",
- "The value of R1= 120.39 kohm \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.12 Page No 498"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "Ie1=1.0*10**-3\n",
- "hfe=50.0\n",
- "R1=120.0*10**3\n",
- "R2=47.0*10**3\n",
- "f1=150.0\n",
- "Ie2=2.0*10**-3\n",
- "R5=3.3*10**3\n",
- "R3=12.0*10**3\n",
- "Rl=100.0\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie1\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Xc1=(Zi+rs)/10\n",
- "C1=1/(2*3.14*f1*Xc1)#use 6*10**-6 as standard value\n",
- "Xc2=.65*re\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "re2=26*10**-3/Ie2\n",
- "Zo=(R5*(re2+R3/hfe))/(R5+(re2+R3/hfe))\n",
- "Xc3=.65*(Rl+Zo)\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 4.88 mf\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.13 Page No 499"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ie2=2.0*10**-3\n",
- "hfe=50.0\n",
- "R5=3.3*10**3\n",
- "Rl=100.0\n",
- "hfc2=51.0\n",
- "R3=12.0*10**3\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie2\n",
- "hic=hfe*re\n",
- "Zi2=hic+hfc2*((Rl*R5)/(Rl+R5))\n",
- "Av1=-(hfe*((R3*Zi2)/(R3+Zi2)))/hie\n",
- "Av2=1.0\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage gain is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall voltage gain is Av=Av1*Av2\n",
- "The value of Av= -143.97 \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.14, Page No 503"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "vp=50.0*10**-3\n",
- "Rl=50.0\n",
- "Ve2=5.0\n",
- "Vcc=12.0\n",
- "Vbe=0.7\n",
- "hFE=70.0\n",
- "hfe=100.0\n",
- "R2=120.0*10**3\n",
- "f1=150.0\n",
- "R3=150.0*10**3\n",
- "R1=5.6*10**3\n",
- "R4=2.2*10**3\n",
- "\n",
- "#Calculations\n",
- "ip=vp/Rl\n",
- "print(\"select Ie2>ip\")\n",
- "Ie2=2*10**-3\n",
- "R4=Ve2/Ie2#use standard 2.2Kohm\n",
- "R4=2.2*10**3\n",
- "Ie2=Ve2/R4\n",
- "Ic1=1*10**-3\n",
- "Vr1=Vcc-(Vbe+Ve2)\n",
- "R1=Vr1/Ic1#use 5.6kohm and recalculate\n",
- "R1=5.6*10**3\n",
- "Ic1=Vr1/R1\n",
- "Ib1=Ic1/hFE\n",
- "hie=hfe*(26*10**-3/Ic1)\n",
- "hie2=hfe*((26*10**-3)/(2.27*10**-3))\n",
- "Zi1=(R2*hie)/(R2+hie)\n",
- "Xc1=Zi1/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=R3/100\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "Zo=(((hie2+R1)/hfe)*R4)/(((hie2+R1)/hfe)+R4)\n",
- "Xc3=Rl+Zo\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select Ie2>ip\n",
- "The value of C3= 9.20 mf\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.15, Page No 407"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vgsoff=-6.0\n",
- "Idss=20.0*10**-3\n",
- "Yfs=4000.0*10**-6\n",
- "Id=2.0*10**-3\n",
- "Vcc=20.0\n",
- "Zi=500.0*10**3\n",
- "R2=560.0*10**3\n",
- "Rl=80.0*10**3\n",
- "Vbe=0.7\n",
- "Vce=3.0\n",
- "\n",
- "#Calculations\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vds=(-Vgsoff)+1-(-Vgs)\n",
- "Vr3=(Vcc-Vds)/2\n",
- "Vr4=Vr3\n",
- "R3=Vr4/Id#use 3.9kohm as standard and recalculate Vr3 and Vr4\n",
- "R4=R3\n",
- "R4=3.9*10**3\n",
- "Vr3=Id*R4\n",
- "Vr4=Vr3\n",
- "Vr2=Vr4-(-Vgs)\n",
- "Vr1=Vcc-Vr2\n",
- "R1=(Vr1*R2)/Vr2\n",
- "R6=Rl/10\n",
- "Vr5=Vr3-Vbe\n",
- "Vr6=Vcc-Vr5-Vce\n",
- "Ic2=Vr6/R6\n",
- "R5=Vr5/Ic2\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f kohm' %(R5/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R5= 5.74 kohm\n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.16, Page No 508"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R1=2.7*10**6\n",
- "R2=560.0*10**3\n",
- "f1=150.0\n",
- "Yfs=8000.0*10**-6\n",
- "Ie=1.2*10**-3\n",
- "Rl=80.0*10**3\n",
- "R6=8.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "Xc1=Zi/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=.65/Yfs\n",
- "C2=1/(2*3.14*f1*Xc2)#use 15pF as standard value\n",
- "re=26*10**-3/Ie\n",
- "Xc3=.65*re\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "Xc4=(R6+Rl)/10\n",
- "C4=1/(2*3.14*f1*Xc4)\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mf' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.12 mf\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.17, Page No 509"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "re=22.0\n",
- "hfe=100.0\n",
- "R3=3.9*10**3\n",
- "Yfs=4000*10**-6\n",
- "R6=8.2*10**3\n",
- "Rl=80.*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi2=hfe*re\n",
- "Av1=-Yfs*((R3*Zi2)/(R3+Zi2))\n",
- "Av2=-(hfe*((R6*Rl)/(R6+Rl)))/Zi2\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall voltage is Av=Av1*Av2\n",
- "The value of Av= 1902.09 \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.18, Page No 516"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hFE=60.0\n",
- "hfe=60.0\n",
- "hie=1.4*10**3\n",
- "Rl=70.0*10**3\n",
- "Vce=3.0\n",
- "Vbe=.7\n",
- "Vcc=10.0\n",
- "\n",
- "#Calculations\n",
- "Rc2=Rl/10#use 6.8Kohm as standard value\n",
- "Vrc2=Vcc+Vbe-Vce\n",
- "Ic=Vrc2/Rc2\n",
- "Ie=Ic\n",
- "Re=(Vcc-Vbe)/(2*Ie)#use 4.7 as standard value\n",
- "Re=4.7*10**3\n",
- "Rb=Vbe/(10*(Ic/hFE))\n",
- "Rb1=Rb\n",
- "\n",
- "#Results\n",
- "print('The value of Rb= %.2f kohm ' %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb= 3.82 kohm \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.19, Page No 517"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=60.0\n",
- "Ie=1.13*10**-3\n",
- "hfe=60.0\n",
- "Rb=3.9*10**3\n",
- "Rl=70.0*10**3\n",
- "Rc=6.8*10**3\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie#use 20 as standard value\n",
- "re=20\n",
- "hie=hfe*re\n",
- "Zb=2*hie\n",
- "Zi=(Rb*Zb)/(Rb+Zb)\n",
- "C1=1/(2*3.14*f1*Zi)\n",
- "C2=1/(2*3.14*f1*(Rl/10))\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/(2*hie)\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= 154.95 \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.20, Page No 521"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=20.0\n",
- "Rl=90.0*10**3\n",
- "hfe=50.0\n",
- "hie=1.2*10**3\n",
- "hib=24.0\n",
- "Vce=3\n",
- "Vce1=Vce\n",
- "Ve=5.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Rl/10#use 8.2kohm as standard value\n",
- "Rc=8.2*10**3\n",
- "Vrc=Vcc-Vce-Vce1-Ve\n",
- "Ic=Vrc/Rc\n",
- "Re=Ve/Ic\n",
- "Re=4.7*10**3#use 4.7 as standard value\n",
- "R3=10*Re\n",
- "Vb1=Ve+Vbe\n",
- "I3=Vb1/R3\n",
- "Vb2=Ve+Vce+Vbe\n",
- "Vr2=Vb2-Vb1\n",
- "R2=Vr2/I3\n",
- "R1=(Vcc-Vb2)/I3\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 93.18 kohm \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.21, Page No 522"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=25.0\n",
- "R2=24.7*10**3\n",
- "R3=47.0*10**3\n",
- "hie=1.2*10**3\n",
- "hib=24.0\n",
- "Rc=9.0*10**3\n",
- "Rl=90*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(R2*R3*hie)/(R2*R3+R2*hie+R3*hie)\n",
- "C1=1/(2*3.14*f1*(Zi/10))\n",
- "C2=1/(2*3.14*f1*(hie/10))\n",
- "C3=1/(2*3.14*f1*hib)\n",
- "C4=1/(2*3.14*f1*((Rc+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mF' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.64 mF\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.22, Page No 525"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hie=1.0\n",
- "hfe=50.0\n",
- "hoe=10.0*10**-6\n",
- "Cc=5*10**-12\n",
- "Cp=330*10**-12\n",
- "Lp=75*10**-6\n",
- "Rw=1.0\n",
- "Rl=5.0\n",
- "hfb=50.0\n",
- "fo=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "fo=1.0/(2.0*3.14*math.sqrt(Lp*(Cp+Cc)))\n",
- "print(\"resonance frequency is %3fHz \" %fo)\n",
- "Zp=Lp/((Cp+Cc)*Rw)\n",
- "Rc=(1.0/hoe)/1000\n",
- "RL=(Zp*Rc*Rl)/(Rl*Rc+Rc*Zp+Rl*Zp)\n",
- "RL1=4.7 #as standard value\n",
- "Av=(hfb*RL1)/hie\n",
- "print(\" voltage gain is %d \" %Av)\n",
- "Qp=7.6\n",
- "QL=(2*3.14*fo*Lp)/Rw\n",
- "print(\"since QL>Qp\")\n",
- "fo=1\n",
- "B=fo/Qp\n",
- "\n",
- "#Results\n",
- "print(\"bandwidth is %.2f kHz \" %(B*10**3))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resonance frequency is 1004586.461587Hz \n",
- " voltage gain is 235 \n",
- "since QL>Qp\n",
- "bandwidth is 131.58 kHz \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.23, Page No 528"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hie=1.0*10**3\n",
- "hfe=50.0\n",
- "hoe=10.0*10**-6\n",
- "Cc=5.0*10**-12\n",
- "Cp=330.0*10**-12\n",
- "Lp=75.0*10**-6\n",
- "Rw=1.0\n",
- "Rl=5.0*10**3\n",
- "fo=1.0*10**6\n",
- "zP=224.0*10**3\n",
- "rC=100.0*10**3\n",
- "K=0.015\n",
- "Ls=50.0*10**-6\n",
- "\n",
- "\n",
- "#Calculations\n",
- "RL=(Zp*Rc)/(Rc+Zp)\n",
- "print(\"voltage gain from the input to the primary memory winding\")\n",
- "Avp=(hfe*RL)/hie\n",
- "Vsp=K*math.sqrt(Ls/Lp)\n",
- "print(\"overall voltage gain from the input to teh secondary winding\")\n",
- "Av=Avp*Vsp\n",
- "Qp=Rc/(2*3.14*fo*Lp)\n",
- "Ql=471\n",
- "Q=(Ql*Qp)/(Ql+Qp)\n",
- "B=fo/Q\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"bandwidth is %.2f kHz \" %(B/10**5))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain from the input to the primary memory winding\n",
- "overall voltage gain from the input to teh secondary winding\n",
- "bandwidth is 47.12 kHz \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.24, Page No 530"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=1.0*10**6\n",
- "L2=50.0*10**-6\n",
- "K=0.015\n",
- "L1=75*10**-6\n",
- "rs=5.0\n",
- "Rw=1.0\n",
- "Lp=100.0*10**-6\n",
- "Cp=330.0*10**-12\n",
- "Cc=5.0*10**-12\n",
- "Rc=100.0*10**3\n",
- "hfe=50.0\n",
- "hie=1.0*10**3\n",
- "\n",
- "\n",
- "#Calculations\n",
- "C2=1/(((2*3.14*f)**2)*L2)\n",
- "M=K*math.sqrt(L1*L2)\n",
- "Rs=(((2*3.14*f)**2)*(M)**2)/rs\n",
- "Rp=Rs+Rw\n",
- "Zp=Lp/((Cp+Cc)*Rp)\n",
- "Rl=(Zp*Rc)/(Zp+Rc)\n",
- "print(\"voltage gain from the input to primary winding\")\n",
- "Avp=(hfe*Rl)/hie\n",
- "Vsp=12.2*10**-3\n",
- "Vos=((2*3.14*f)*L2)/rs\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage gain from the input to secondary winding \")\n",
- "Av=Avp*Vos*Vsp\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain from the input to primary winding\n",
- "overall voltage gain from the input to secondary winding \n",
- "The value of Av= 1074.71 \n"
- ]
- }
- ],
- "prompt_number": 22
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter12_1.ipynb b/Electronic_Devices_and_Circuits/Chapter12_1.ipynb deleted file mode 100755 index b0fb9991..00000000 --- a/Electronic_Devices_and_Circuits/Chapter12_1.ipynb +++ /dev/null @@ -1,1196 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 12 : Small signal Amplifiers"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.1, Page No 474"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "hie=1.0*10**3\n",
- "hib=20.0\n",
- "f1=100.0\n",
- "Rc=3.3*10**3\n",
- "\n",
- "#Calculations\n",
- "Re=Rc\n",
- "print(\" required capacitance\")\n",
- "Xc2=hib\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "print(\" voltage gain with emitter terminal completely bypassed to ground\")\n",
- "Av=-(hfe*Rc)/hie\n",
- "print(\"voltage gain when f=100\")\n",
- "Av=-(hfe*Rc)/math.sqrt(((hie**2)+((1+hfe)*Xc2)**2))\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain when C2 is incorrectly selected as Xc2=Re/10\")\n",
- "Avx=-(hfe*Rc)/math.sqrt(((hie**2)+((1+hfe)*(Re/10))**2))\n",
- "print('The value of Avx= %.2f ' %(Avx))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " required capacitance\n",
- " voltage gain with emitter terminal completely bypassed to ground\n",
- "voltage gain when f=100\n",
- " voltage gain when C2 is incorrectly selected as Xc2=Re/10\n",
- "The value of Avx= -9.79 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.2, Page No 477"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=24.0\n",
- "Ve=5.0\n",
- "Vce=3.0\n",
- "Rl=120.0*10**3\n",
- "Vbe=0.7\n",
- "Rc=Rl/10.0\n",
- "\n",
- "#Calculations\n",
- "Vrc=Vcc-Vce-Ve\n",
- "Ic=Vrc/Rc\n",
- "Re=Ve/Ic#use 3.9Kohm standard value to make Ic littel less than design level\n",
- "Re=3.9*10**3\n",
- "R2=10*Re\n",
- "I2=(Ve+Vbe)/R2\n",
- "R1=(Vcc-Ve-Vbe)/I2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f ' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 125.21 \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.3 Page No 477"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "Ie=1.3*10**-3\n",
- "f1=100.0\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Rl=R1\n",
- "re=(26*10**-3)/Ie\n",
- "Xc2=re\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "C1=1/((2*3.14*f1*((Zi+rs)/10)))\n",
- "C3=1/(2*3.14*f1*((Rc+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf ' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 0.12 mf \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.5, Page No 484"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "rs=600.0\n",
- "f1=100.0\n",
- "Yfs=6000.0*10**-6\n",
- "R1=4.7*10**6\n",
- "R2=1.0*10**6\n",
- "Rd=6.8*10**3\n",
- "Rl=120*10**3\n",
- "\n",
- "#Calculations\n",
- "Xc2=1/Yfs\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "C1=1/(2*3.14*f1*(Zi+rs)/10)\n",
- "C3=1/(2*3.14*f1*(Rd+Rl)/10)\n",
- "\n",
- "#Calculations\n",
- "print('The value of C3= %.2f mF' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 0.13 mF\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.7 Page No 489"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "hie=2.0*10**3\n",
- "R7=12.0*10**3\n",
- "Zo=R7\n",
- "R5=R1\n",
- "R6=R2\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "R3=R7\n",
- "Zl=R1\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Zi2=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Av1=-(hfe*((R3*Zi2)/(R3+Zi2)))/hie\n",
- "Av2=-(hfe*((R7*Zl)/(R7+Zl)))/hie\n",
- "Av=Av1*Av2\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= 44180.12 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.8 Page No 491"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ve1=5.0\n",
- "Vce1=3.0\n",
- "Vce2=3.0\n",
- "Vbe=0.7\n",
- "Vcc=14.0\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Vb2=Ve1+Vce1\n",
- "Vc1=Vb2\n",
- "Ve2=Vb2-Vbe\n",
- "Vr5=Vcc-Ve2-Vce2\n",
- "R5=Rl/10#use 3.9Kohm satandard value\n",
- "R5=3.9*10**3\n",
- "Ic2=Vr5/R5\n",
- "R6=Ve2/Ic2#use 8.2Kohm as standard and recalculate\n",
- "R6=8.2*10**3\n",
- "Ic2=Ve2/R6\n",
- "Vr3=Vcc-Vc1\n",
- "print(\" Ic1>>Ib2 %select Ic1=1mA\")\n",
- "Ic1=1*10**-3\n",
- "R3=Vr3/Ic1#use standard value as 5.6Kohm and recalculate Ic1 in order ti keep Vb2=8V\n",
- "R3=5.6*10**3\n",
- "Ic1=Vr3/R3\n",
- "R4=Ve1/Ic1\n",
- "Vr2=Ve1+Vbe\n",
- "Vr1=Vcc-Ve1-Vbe\n",
- "R2=10*R4\n",
- "I2=(Ve1+Vbe)/R2\n",
- "R1=(Vr1*R2)/Vr2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Ic1>>Ib2 %select Ic1=1mA\n",
- "The value of R1= 67.95 kohm\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.9, Page No 493"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "re=26.0\n",
- "R1=68.0*10**3\n",
- "R2=47.0*10**3\n",
- "rs=600.0\n",
- "f1=75.0\n",
- "R5=3.9*10**3\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Xc1=(Zi+rs)/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=.65*re\n",
- "Xc3=Xc2\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "C3=C2\n",
- "Xc4=(R5+Rl)/10\n",
- "C4=1/(2*3.14*f1*Xc4)\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mf' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.48 mf\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.10, Page No 494"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "hie=1.3*10**3\n",
- "R3=5.6*10**3\n",
- "R5=3.9*10**3\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Av1=-(hfe*((R3*hie)/(R3+hie)))/hie\n",
- "Av2=-(hfe*((R5*Rl)/(R5+Rl)))/hie\n",
- "\n",
- "#Results\n",
- "print(\" overall voltage gain is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " overall voltage gain is Av=Av1*Av2\n",
- "The value of Av= 5546.20 \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.11 Page No 497"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vp=100.0*10**-3\n",
- "Rl=100.0\n",
- "Vbe=0.7\n",
- "Vcc=20.0\n",
- "\n",
- "#Calculations\n",
- "ip=Vp/Rl\n",
- "print(\"select Ie2>ip\")\n",
- "Ie2=2.0*10**-3\n",
- "Ve1=5.0\n",
- "Vce1=3.0\n",
- "Vb2=Ve1+Vce1\n",
- "Vc1=Vb2\n",
- "Ve2=Vb2-Vbe\n",
- "R5=Ve2/Ie2#use 3.3Kohm standard value\n",
- "R5=3.3*10**3\n",
- "Ic1=1*10**-3\n",
- "Vr3=Vcc-Vb2\n",
- "R3=Vr3/Ic1\n",
- "R4=Ve1/Ic1#use 4.7Kohm standard value\n",
- "R4=4.7*10**3\n",
- "Vb1=Ic1*R4+Vbe\n",
- "R2=10*R4\n",
- "R1=((Vcc-Vb1)*R2)/Vr2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select Ie2>ip\n",
- "The value of R1= 120.39 kohm \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.12 Page No 498"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "Ie1=1.0*10**-3\n",
- "hfe=50.0\n",
- "R1=120.0*10**3\n",
- "R2=47.0*10**3\n",
- "f1=150.0\n",
- "Ie2=2.0*10**-3\n",
- "R5=3.3*10**3\n",
- "R3=12.0*10**3\n",
- "Rl=100.0\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie1\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Xc1=(Zi+rs)/10\n",
- "C1=1/(2*3.14*f1*Xc1)#use 6*10**-6 as standard value\n",
- "Xc2=.65*re\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "re2=26*10**-3/Ie2\n",
- "Zo=(R5*(re2+R3/hfe))/(R5+(re2+R3/hfe))\n",
- "Xc3=.65*(Rl+Zo)\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 4.88 mf\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.13 Page No 499"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ie2=2.0*10**-3\n",
- "hfe=50.0\n",
- "R5=3.3*10**3\n",
- "Rl=100.0\n",
- "hfc2=51.0\n",
- "R3=12.0*10**3\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie2\n",
- "hic=hfe*re\n",
- "Zi2=hic+hfc2*((Rl*R5)/(Rl+R5))\n",
- "Av1=-(hfe*((R3*Zi2)/(R3+Zi2)))/hie\n",
- "Av2=1.0\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage gain is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall voltage gain is Av=Av1*Av2\n",
- "The value of Av= -143.97 \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.14, Page No 503"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "vp=50.0*10**-3\n",
- "Rl=50.0\n",
- "Ve2=5.0\n",
- "Vcc=12.0\n",
- "Vbe=0.7\n",
- "hFE=70.0\n",
- "hfe=100.0\n",
- "R2=120.0*10**3\n",
- "f1=150.0\n",
- "R3=150.0*10**3\n",
- "R1=5.6*10**3\n",
- "R4=2.2*10**3\n",
- "\n",
- "#Calculations\n",
- "ip=vp/Rl\n",
- "print(\"select Ie2>ip\")\n",
- "Ie2=2*10**-3\n",
- "R4=Ve2/Ie2#use standard 2.2Kohm\n",
- "R4=2.2*10**3\n",
- "Ie2=Ve2/R4\n",
- "Ic1=1*10**-3\n",
- "Vr1=Vcc-(Vbe+Ve2)\n",
- "R1=Vr1/Ic1#use 5.6kohm and recalculate\n",
- "R1=5.6*10**3\n",
- "Ic1=Vr1/R1\n",
- "Ib1=Ic1/hFE\n",
- "hie=hfe*(26*10**-3/Ic1)\n",
- "hie2=hfe*((26*10**-3)/(2.27*10**-3))\n",
- "Zi1=(R2*hie)/(R2+hie)\n",
- "Xc1=Zi1/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=R3/100\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "Zo=(((hie2+R1)/hfe)*R4)/(((hie2+R1)/hfe)+R4)\n",
- "Xc3=Rl+Zo\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select Ie2>ip\n",
- "The value of C3= 9.20 mf\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.15, Page No 407"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vgsoff=-6.0\n",
- "Idss=20.0*10**-3\n",
- "Yfs=4000.0*10**-6\n",
- "Id=2.0*10**-3\n",
- "Vcc=20.0\n",
- "Zi=500.0*10**3\n",
- "R2=560.0*10**3\n",
- "Rl=80.0*10**3\n",
- "Vbe=0.7\n",
- "Vce=3.0\n",
- "\n",
- "#Calculations\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vds=(-Vgsoff)+1-(-Vgs)\n",
- "Vr3=(Vcc-Vds)/2\n",
- "Vr4=Vr3\n",
- "R3=Vr4/Id#use 3.9kohm as standard and recalculate Vr3 and Vr4\n",
- "R4=R3\n",
- "R4=3.9*10**3\n",
- "Vr3=Id*R4\n",
- "Vr4=Vr3\n",
- "Vr2=Vr4-(-Vgs)\n",
- "Vr1=Vcc-Vr2\n",
- "R1=(Vr1*R2)/Vr2\n",
- "R6=Rl/10\n",
- "Vr5=Vr3-Vbe\n",
- "Vr6=Vcc-Vr5-Vce\n",
- "Ic2=Vr6/R6\n",
- "R5=Vr5/Ic2\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f kohm' %(R5/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R5= 5.74 kohm\n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.16, Page No 508"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R1=2.7*10**6\n",
- "R2=560.0*10**3\n",
- "f1=150.0\n",
- "Yfs=8000.0*10**-6\n",
- "Ie=1.2*10**-3\n",
- "Rl=80.0*10**3\n",
- "R6=8.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "Xc1=Zi/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=.65/Yfs\n",
- "C2=1/(2*3.14*f1*Xc2)#use 15pF as standard value\n",
- "re=26*10**-3/Ie\n",
- "Xc3=.65*re\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "Xc4=(R6+Rl)/10\n",
- "C4=1/(2*3.14*f1*Xc4)\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mf' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.12 mf\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.17, Page No 509"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "re=22.0\n",
- "hfe=100.0\n",
- "R3=3.9*10**3\n",
- "Yfs=4000*10**-6\n",
- "R6=8.2*10**3\n",
- "Rl=80.*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi2=hfe*re\n",
- "Av1=-Yfs*((R3*Zi2)/(R3+Zi2))\n",
- "Av2=-(hfe*((R6*Rl)/(R6+Rl)))/Zi2\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall voltage is Av=Av1*Av2\n",
- "The value of Av= 1902.09 \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.18, Page No 516"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hFE=60.0\n",
- "hfe=60.0\n",
- "hie=1.4*10**3\n",
- "Rl=70.0*10**3\n",
- "Vce=3.0\n",
- "Vbe=.7\n",
- "Vcc=10.0\n",
- "\n",
- "#Calculations\n",
- "Rc2=Rl/10#use 6.8Kohm as standard value\n",
- "Vrc2=Vcc+Vbe-Vce\n",
- "Ic=Vrc2/Rc2\n",
- "Ie=Ic\n",
- "Re=(Vcc-Vbe)/(2*Ie)#use 4.7 as standard value\n",
- "Re=4.7*10**3\n",
- "Rb=Vbe/(10*(Ic/hFE))\n",
- "Rb1=Rb\n",
- "\n",
- "#Results\n",
- "print('The value of Rb= %.2f kohm ' %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb= 3.82 kohm \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.19, Page No 517"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=60.0\n",
- "Ie=1.13*10**-3\n",
- "hfe=60.0\n",
- "Rb=3.9*10**3\n",
- "Rl=70.0*10**3\n",
- "Rc=6.8*10**3\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie#use 20 as standard value\n",
- "re=20\n",
- "hie=hfe*re\n",
- "Zb=2*hie\n",
- "Zi=(Rb*Zb)/(Rb+Zb)\n",
- "C1=1/(2*3.14*f1*Zi)\n",
- "C2=1/(2*3.14*f1*(Rl/10))\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/(2*hie)\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= 154.95 \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.20, Page No 521"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=20.0\n",
- "Rl=90.0*10**3\n",
- "hfe=50.0\n",
- "hie=1.2*10**3\n",
- "hib=24.0\n",
- "Vce=3\n",
- "Vce1=Vce\n",
- "Ve=5.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Rl/10#use 8.2kohm as standard value\n",
- "Rc=8.2*10**3\n",
- "Vrc=Vcc-Vce-Vce1-Ve\n",
- "Ic=Vrc/Rc\n",
- "Re=Ve/Ic\n",
- "Re=4.7*10**3#use 4.7 as standard value\n",
- "R3=10*Re\n",
- "Vb1=Ve+Vbe\n",
- "I3=Vb1/R3\n",
- "Vb2=Ve+Vce+Vbe\n",
- "Vr2=Vb2-Vb1\n",
- "R2=Vr2/I3\n",
- "R1=(Vcc-Vb2)/I3\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 93.18 kohm \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.21, Page No 522"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=25.0\n",
- "R2=24.7*10**3\n",
- "R3=47.0*10**3\n",
- "hie=1.2*10**3\n",
- "hib=24.0\n",
- "Rc=9.0*10**3\n",
- "Rl=90*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(R2*R3*hie)/(R2*R3+R2*hie+R3*hie)\n",
- "C1=1/(2*3.14*f1*(Zi/10))\n",
- "C2=1/(2*3.14*f1*(hie/10))\n",
- "C3=1/(2*3.14*f1*hib)\n",
- "C4=1/(2*3.14*f1*((Rc+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mF' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.64 mF\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.22, Page No 525"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hie=1.0\n",
- "hfe=50.0\n",
- "hoe=10.0*10**-6\n",
- "Cc=5*10**-12\n",
- "Cp=330*10**-12\n",
- "Lp=75*10**-6\n",
- "Rw=1.0\n",
- "Rl=5.0\n",
- "hfb=50.0\n",
- "fo=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "fo=1.0/(2.0*3.14*math.sqrt(Lp*(Cp+Cc)))\n",
- "print(\"resonance frequency is %3fHz \" %fo)\n",
- "Zp=Lp/((Cp+Cc)*Rw)\n",
- "Rc=(1.0/hoe)/1000\n",
- "RL=(Zp*Rc*Rl)/(Rl*Rc+Rc*Zp+Rl*Zp)\n",
- "RL1=4.7 #as standard value\n",
- "Av=(hfb*RL1)/hie\n",
- "print(\" voltage gain is %d \" %Av)\n",
- "Qp=7.6\n",
- "QL=(2*3.14*fo*Lp)/Rw\n",
- "print(\"since QL>Qp\")\n",
- "fo=1\n",
- "B=fo/Qp\n",
- "\n",
- "#Results\n",
- "print(\"bandwidth is %.2f kHz \" %(B*10**3))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resonance frequency is 1004586.461587Hz \n",
- " voltage gain is 235 \n",
- "since QL>Qp\n",
- "bandwidth is 131.58 kHz \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.23, Page No 528"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hie=1.0*10**3\n",
- "hfe=50.0\n",
- "hoe=10.0*10**-6\n",
- "Cc=5.0*10**-12\n",
- "Cp=330.0*10**-12\n",
- "Lp=75.0*10**-6\n",
- "Rw=1.0\n",
- "Rl=5.0*10**3\n",
- "fo=1.0*10**6\n",
- "zP=224.0*10**3\n",
- "rC=100.0*10**3\n",
- "K=0.015\n",
- "Ls=50.0*10**-6\n",
- "\n",
- "\n",
- "#Calculations\n",
- "RL=(Zp*Rc)/(Rc+Zp)\n",
- "print(\"voltage gain from the input to the primary memory winding\")\n",
- "Avp=(hfe*RL)/hie\n",
- "Vsp=K*math.sqrt(Ls/Lp)\n",
- "print(\"overall voltage gain from the input to teh secondary winding\")\n",
- "Av=Avp*Vsp\n",
- "Qp=Rc/(2*3.14*fo*Lp)\n",
- "Ql=471\n",
- "Q=(Ql*Qp)/(Ql+Qp)\n",
- "B=fo/Q\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"bandwidth is %.2f kHz \" %(B/10**5))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain from the input to the primary memory winding\n",
- "overall voltage gain from the input to teh secondary winding\n",
- "bandwidth is 47.12 kHz \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.24, Page No 530"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=1.0*10**6\n",
- "L2=50.0*10**-6\n",
- "K=0.015\n",
- "L1=75*10**-6\n",
- "rs=5.0\n",
- "Rw=1.0\n",
- "Lp=100.0*10**-6\n",
- "Cp=330.0*10**-12\n",
- "Cc=5.0*10**-12\n",
- "Rc=100.0*10**3\n",
- "hfe=50.0\n",
- "hie=1.0*10**3\n",
- "\n",
- "\n",
- "#Calculations\n",
- "C2=1/(((2*3.14*f)**2)*L2)\n",
- "M=K*math.sqrt(L1*L2)\n",
- "Rs=(((2*3.14*f)**2)*(M)**2)/rs\n",
- "Rp=Rs+Rw\n",
- "Zp=Lp/((Cp+Cc)*Rp)\n",
- "Rl=(Zp*Rc)/(Zp+Rc)\n",
- "print(\"voltage gain from the input to primary winding\")\n",
- "Avp=(hfe*Rl)/hie\n",
- "Vsp=12.2*10**-3\n",
- "Vos=((2*3.14*f)*L2)/rs\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage gain from the input to secondary winding \")\n",
- "Av=Avp*Vos*Vsp\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain from the input to primary winding\n",
- "overall voltage gain from the input to secondary winding \n",
- "The value of Av= 1074.71 \n"
- ]
- }
- ],
- "prompt_number": 22
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter12_2.ipynb b/Electronic_Devices_and_Circuits/Chapter12_2.ipynb deleted file mode 100755 index b0fb9991..00000000 --- a/Electronic_Devices_and_Circuits/Chapter12_2.ipynb +++ /dev/null @@ -1,1196 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 12 : Small signal Amplifiers"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.1, Page No 474"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "hie=1.0*10**3\n",
- "hib=20.0\n",
- "f1=100.0\n",
- "Rc=3.3*10**3\n",
- "\n",
- "#Calculations\n",
- "Re=Rc\n",
- "print(\" required capacitance\")\n",
- "Xc2=hib\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "print(\" voltage gain with emitter terminal completely bypassed to ground\")\n",
- "Av=-(hfe*Rc)/hie\n",
- "print(\"voltage gain when f=100\")\n",
- "Av=-(hfe*Rc)/math.sqrt(((hie**2)+((1+hfe)*Xc2)**2))\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain when C2 is incorrectly selected as Xc2=Re/10\")\n",
- "Avx=-(hfe*Rc)/math.sqrt(((hie**2)+((1+hfe)*(Re/10))**2))\n",
- "print('The value of Avx= %.2f ' %(Avx))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " required capacitance\n",
- " voltage gain with emitter terminal completely bypassed to ground\n",
- "voltage gain when f=100\n",
- " voltage gain when C2 is incorrectly selected as Xc2=Re/10\n",
- "The value of Avx= -9.79 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.2, Page No 477"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=24.0\n",
- "Ve=5.0\n",
- "Vce=3.0\n",
- "Rl=120.0*10**3\n",
- "Vbe=0.7\n",
- "Rc=Rl/10.0\n",
- "\n",
- "#Calculations\n",
- "Vrc=Vcc-Vce-Ve\n",
- "Ic=Vrc/Rc\n",
- "Re=Ve/Ic#use 3.9Kohm standard value to make Ic littel less than design level\n",
- "Re=3.9*10**3\n",
- "R2=10*Re\n",
- "I2=(Ve+Vbe)/R2\n",
- "R1=(Vcc-Ve-Vbe)/I2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f ' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 125.21 \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.3 Page No 477"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "Ie=1.3*10**-3\n",
- "f1=100.0\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "Rl=R1\n",
- "re=(26*10**-3)/Ie\n",
- "Xc2=re\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "C1=1/((2*3.14*f1*((Zi+rs)/10)))\n",
- "C3=1/(2*3.14*f1*((Rc+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf ' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 0.12 mf \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.5, Page No 484"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "rs=600.0\n",
- "f1=100.0\n",
- "Yfs=6000.0*10**-6\n",
- "R1=4.7*10**6\n",
- "R2=1.0*10**6\n",
- "Rd=6.8*10**3\n",
- "Rl=120*10**3\n",
- "\n",
- "#Calculations\n",
- "Xc2=1/Yfs\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "C1=1/(2*3.14*f1*(Zi+rs)/10)\n",
- "C3=1/(2*3.14*f1*(Rd+Rl)/10)\n",
- "\n",
- "#Calculations\n",
- "print('The value of C3= %.2f mF' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 0.13 mF\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.7 Page No 489"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "hie=2.0*10**3\n",
- "R7=12.0*10**3\n",
- "Zo=R7\n",
- "R5=R1\n",
- "R6=R2\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "R3=R7\n",
- "Zl=R1\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Zi2=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Av1=-(hfe*((R3*Zi2)/(R3+Zi2)))/hie\n",
- "Av2=-(hfe*((R7*Zl)/(R7+Zl)))/hie\n",
- "Av=Av1*Av2\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= 44180.12 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.8 Page No 491"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ve1=5.0\n",
- "Vce1=3.0\n",
- "Vce2=3.0\n",
- "Vbe=0.7\n",
- "Vcc=14.0\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Vb2=Ve1+Vce1\n",
- "Vc1=Vb2\n",
- "Ve2=Vb2-Vbe\n",
- "Vr5=Vcc-Ve2-Vce2\n",
- "R5=Rl/10#use 3.9Kohm satandard value\n",
- "R5=3.9*10**3\n",
- "Ic2=Vr5/R5\n",
- "R6=Ve2/Ic2#use 8.2Kohm as standard and recalculate\n",
- "R6=8.2*10**3\n",
- "Ic2=Ve2/R6\n",
- "Vr3=Vcc-Vc1\n",
- "print(\" Ic1>>Ib2 %select Ic1=1mA\")\n",
- "Ic1=1*10**-3\n",
- "R3=Vr3/Ic1#use standard value as 5.6Kohm and recalculate Ic1 in order ti keep Vb2=8V\n",
- "R3=5.6*10**3\n",
- "Ic1=Vr3/R3\n",
- "R4=Ve1/Ic1\n",
- "Vr2=Ve1+Vbe\n",
- "Vr1=Vcc-Ve1-Vbe\n",
- "R2=10*R4\n",
- "I2=(Ve1+Vbe)/R2\n",
- "R1=(Vr1*R2)/Vr2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Ic1>>Ib2 %select Ic1=1mA\n",
- "The value of R1= 67.95 kohm\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.9, Page No 493"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "re=26.0\n",
- "R1=68.0*10**3\n",
- "R2=47.0*10**3\n",
- "rs=600.0\n",
- "f1=75.0\n",
- "R5=3.9*10**3\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Xc1=(Zi+rs)/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=.65*re\n",
- "Xc3=Xc2\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "C3=C2\n",
- "Xc4=(R5+Rl)/10\n",
- "C4=1/(2*3.14*f1*Xc4)\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mf' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.48 mf\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.10, Page No 494"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=50.0\n",
- "hie=1.3*10**3\n",
- "R3=5.6*10**3\n",
- "R5=3.9*10**3\n",
- "Rl=40.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Av1=-(hfe*((R3*hie)/(R3+hie)))/hie\n",
- "Av2=-(hfe*((R5*Rl)/(R5+Rl)))/hie\n",
- "\n",
- "#Results\n",
- "print(\" overall voltage gain is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " overall voltage gain is Av=Av1*Av2\n",
- "The value of Av= 5546.20 \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.11 Page No 497"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vp=100.0*10**-3\n",
- "Rl=100.0\n",
- "Vbe=0.7\n",
- "Vcc=20.0\n",
- "\n",
- "#Calculations\n",
- "ip=Vp/Rl\n",
- "print(\"select Ie2>ip\")\n",
- "Ie2=2.0*10**-3\n",
- "Ve1=5.0\n",
- "Vce1=3.0\n",
- "Vb2=Ve1+Vce1\n",
- "Vc1=Vb2\n",
- "Ve2=Vb2-Vbe\n",
- "R5=Ve2/Ie2#use 3.3Kohm standard value\n",
- "R5=3.3*10**3\n",
- "Ic1=1*10**-3\n",
- "Vr3=Vcc-Vb2\n",
- "R3=Vr3/Ic1\n",
- "R4=Ve1/Ic1#use 4.7Kohm standard value\n",
- "R4=4.7*10**3\n",
- "Vb1=Ic1*R4+Vbe\n",
- "R2=10*R4\n",
- "R1=((Vcc-Vb1)*R2)/Vr2\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select Ie2>ip\n",
- "The value of R1= 120.39 kohm \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.12 Page No 498"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "Ie1=1.0*10**-3\n",
- "hfe=50.0\n",
- "R1=120.0*10**3\n",
- "R2=47.0*10**3\n",
- "f1=150.0\n",
- "Ie2=2.0*10**-3\n",
- "R5=3.3*10**3\n",
- "R3=12.0*10**3\n",
- "Rl=100.0\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie1\n",
- "hie=(1+hfe)*re\n",
- "Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie)\n",
- "Xc1=(Zi+rs)/10\n",
- "C1=1/(2*3.14*f1*Xc1)#use 6*10**-6 as standard value\n",
- "Xc2=.65*re\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "re2=26*10**-3/Ie2\n",
- "Zo=(R5*(re2+R3/hfe))/(R5+(re2+R3/hfe))\n",
- "Xc3=.65*(Rl+Zo)\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C3= 4.88 mf\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.13 Page No 499"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ie2=2.0*10**-3\n",
- "hfe=50.0\n",
- "R5=3.3*10**3\n",
- "Rl=100.0\n",
- "hfc2=51.0\n",
- "R3=12.0*10**3\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie2\n",
- "hic=hfe*re\n",
- "Zi2=hic+hfc2*((Rl*R5)/(Rl+R5))\n",
- "Av1=-(hfe*((R3*Zi2)/(R3+Zi2)))/hie\n",
- "Av2=1.0\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage gain is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall voltage gain is Av=Av1*Av2\n",
- "The value of Av= -143.97 \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.14, Page No 503"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "vp=50.0*10**-3\n",
- "Rl=50.0\n",
- "Ve2=5.0\n",
- "Vcc=12.0\n",
- "Vbe=0.7\n",
- "hFE=70.0\n",
- "hfe=100.0\n",
- "R2=120.0*10**3\n",
- "f1=150.0\n",
- "R3=150.0*10**3\n",
- "R1=5.6*10**3\n",
- "R4=2.2*10**3\n",
- "\n",
- "#Calculations\n",
- "ip=vp/Rl\n",
- "print(\"select Ie2>ip\")\n",
- "Ie2=2*10**-3\n",
- "R4=Ve2/Ie2#use standard 2.2Kohm\n",
- "R4=2.2*10**3\n",
- "Ie2=Ve2/R4\n",
- "Ic1=1*10**-3\n",
- "Vr1=Vcc-(Vbe+Ve2)\n",
- "R1=Vr1/Ic1#use 5.6kohm and recalculate\n",
- "R1=5.6*10**3\n",
- "Ic1=Vr1/R1\n",
- "Ib1=Ic1/hFE\n",
- "hie=hfe*(26*10**-3/Ic1)\n",
- "hie2=hfe*((26*10**-3)/(2.27*10**-3))\n",
- "Zi1=(R2*hie)/(R2+hie)\n",
- "Xc1=Zi1/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=R3/100\n",
- "C2=1/(2*3.14*f1*Xc2)\n",
- "Zo=(((hie2+R1)/hfe)*R4)/(((hie2+R1)/hfe)+R4)\n",
- "Xc3=Rl+Zo\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "\n",
- "#Results\n",
- "print('The value of C3= %.2f mf' %(C3*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select Ie2>ip\n",
- "The value of C3= 9.20 mf\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.15, Page No 407"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vgsoff=-6.0\n",
- "Idss=20.0*10**-3\n",
- "Yfs=4000.0*10**-6\n",
- "Id=2.0*10**-3\n",
- "Vcc=20.0\n",
- "Zi=500.0*10**3\n",
- "R2=560.0*10**3\n",
- "Rl=80.0*10**3\n",
- "Vbe=0.7\n",
- "Vce=3.0\n",
- "\n",
- "#Calculations\n",
- "Vgs=Vgsoff*(1-math.sqrt(Id/Idss))\n",
- "Vds=(-Vgsoff)+1-(-Vgs)\n",
- "Vr3=(Vcc-Vds)/2\n",
- "Vr4=Vr3\n",
- "R3=Vr4/Id#use 3.9kohm as standard and recalculate Vr3 and Vr4\n",
- "R4=R3\n",
- "R4=3.9*10**3\n",
- "Vr3=Id*R4\n",
- "Vr4=Vr3\n",
- "Vr2=Vr4-(-Vgs)\n",
- "Vr1=Vcc-Vr2\n",
- "R1=(Vr1*R2)/Vr2\n",
- "R6=Rl/10\n",
- "Vr5=Vr3-Vbe\n",
- "Vr6=Vcc-Vr5-Vce\n",
- "Ic2=Vr6/R6\n",
- "R5=Vr5/Ic2\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f kohm' %(R5/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R5= 5.74 kohm\n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.16, Page No 508"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R1=2.7*10**6\n",
- "R2=560.0*10**3\n",
- "f1=150.0\n",
- "Yfs=8000.0*10**-6\n",
- "Ie=1.2*10**-3\n",
- "Rl=80.0*10**3\n",
- "R6=8.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(R1*R2)/(R1+R2)\n",
- "Xc1=Zi/10\n",
- "C1=1/(2*3.14*f1*Xc1)\n",
- "Xc2=.65/Yfs\n",
- "C2=1/(2*3.14*f1*Xc2)#use 15pF as standard value\n",
- "re=26*10**-3/Ie\n",
- "Xc3=.65*re\n",
- "C3=1/(2*3.14*f1*Xc3)\n",
- "Xc4=(R6+Rl)/10\n",
- "C4=1/(2*3.14*f1*Xc4)\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mf' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.12 mf\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.17, Page No 509"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "re=22.0\n",
- "hfe=100.0\n",
- "R3=3.9*10**3\n",
- "Yfs=4000*10**-6\n",
- "R6=8.2*10**3\n",
- "Rl=80.*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi2=hfe*re\n",
- "Av1=-Yfs*((R3*Zi2)/(R3+Zi2))\n",
- "Av2=-(hfe*((R6*Rl)/(R6+Rl)))/Zi2\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage is Av=Av1*Av2\")\n",
- "Av=Av1*Av2\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "overall voltage is Av=Av1*Av2\n",
- "The value of Av= 1902.09 \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.18, Page No 516"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hFE=60.0\n",
- "hfe=60.0\n",
- "hie=1.4*10**3\n",
- "Rl=70.0*10**3\n",
- "Vce=3.0\n",
- "Vbe=.7\n",
- "Vcc=10.0\n",
- "\n",
- "#Calculations\n",
- "Rc2=Rl/10#use 6.8Kohm as standard value\n",
- "Vrc2=Vcc+Vbe-Vce\n",
- "Ic=Vrc2/Rc2\n",
- "Ie=Ic\n",
- "Re=(Vcc-Vbe)/(2*Ie)#use 4.7 as standard value\n",
- "Re=4.7*10**3\n",
- "Rb=Vbe/(10*(Ic/hFE))\n",
- "Rb1=Rb\n",
- "\n",
- "#Results\n",
- "print('The value of Rb= %.2f kohm ' %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb= 3.82 kohm \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.19, Page No 517"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=60.0\n",
- "Ie=1.13*10**-3\n",
- "hfe=60.0\n",
- "Rb=3.9*10**3\n",
- "Rl=70.0*10**3\n",
- "Rc=6.8*10**3\n",
- "\n",
- "#Calculations\n",
- "re=26*10**-3/Ie#use 20 as standard value\n",
- "re=20\n",
- "hie=hfe*re\n",
- "Zb=2*hie\n",
- "Zi=(Rb*Zb)/(Rb+Zb)\n",
- "C1=1/(2*3.14*f1*Zi)\n",
- "C2=1/(2*3.14*f1*(Rl/10))\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/(2*hie)\n",
- "\n",
- "#Results\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Av= 154.95 \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.20, Page No 521"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=20.0\n",
- "Rl=90.0*10**3\n",
- "hfe=50.0\n",
- "hie=1.2*10**3\n",
- "hib=24.0\n",
- "Vce=3\n",
- "Vce1=Vce\n",
- "Ve=5.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Rl/10#use 8.2kohm as standard value\n",
- "Rc=8.2*10**3\n",
- "Vrc=Vcc-Vce-Vce1-Ve\n",
- "Ic=Vrc/Rc\n",
- "Re=Ve/Ic\n",
- "Re=4.7*10**3#use 4.7 as standard value\n",
- "R3=10*Re\n",
- "Vb1=Ve+Vbe\n",
- "I3=Vb1/R3\n",
- "Vb2=Ve+Vce+Vbe\n",
- "Vr2=Vb2-Vb1\n",
- "R2=Vr2/I3\n",
- "R1=(Vcc-Vb2)/I3\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 93.18 kohm \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.21, Page No 522"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=25.0\n",
- "R2=24.7*10**3\n",
- "R3=47.0*10**3\n",
- "hie=1.2*10**3\n",
- "hib=24.0\n",
- "Rc=9.0*10**3\n",
- "Rl=90*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(R2*R3*hie)/(R2*R3+R2*hie+R3*hie)\n",
- "C1=1/(2*3.14*f1*(Zi/10))\n",
- "C2=1/(2*3.14*f1*(hie/10))\n",
- "C3=1/(2*3.14*f1*hib)\n",
- "C4=1/(2*3.14*f1*((Rc+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C4= %.2f mF' %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4= 0.64 mF\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.22, Page No 525"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hie=1.0\n",
- "hfe=50.0\n",
- "hoe=10.0*10**-6\n",
- "Cc=5*10**-12\n",
- "Cp=330*10**-12\n",
- "Lp=75*10**-6\n",
- "Rw=1.0\n",
- "Rl=5.0\n",
- "hfb=50.0\n",
- "fo=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "fo=1.0/(2.0*3.14*math.sqrt(Lp*(Cp+Cc)))\n",
- "print(\"resonance frequency is %3fHz \" %fo)\n",
- "Zp=Lp/((Cp+Cc)*Rw)\n",
- "Rc=(1.0/hoe)/1000\n",
- "RL=(Zp*Rc*Rl)/(Rl*Rc+Rc*Zp+Rl*Zp)\n",
- "RL1=4.7 #as standard value\n",
- "Av=(hfb*RL1)/hie\n",
- "print(\" voltage gain is %d \" %Av)\n",
- "Qp=7.6\n",
- "QL=(2*3.14*fo*Lp)/Rw\n",
- "print(\"since QL>Qp\")\n",
- "fo=1\n",
- "B=fo/Qp\n",
- "\n",
- "#Results\n",
- "print(\"bandwidth is %.2f kHz \" %(B*10**3))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resonance frequency is 1004586.461587Hz \n",
- " voltage gain is 235 \n",
- "since QL>Qp\n",
- "bandwidth is 131.58 kHz \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.23, Page No 528"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hie=1.0*10**3\n",
- "hfe=50.0\n",
- "hoe=10.0*10**-6\n",
- "Cc=5.0*10**-12\n",
- "Cp=330.0*10**-12\n",
- "Lp=75.0*10**-6\n",
- "Rw=1.0\n",
- "Rl=5.0*10**3\n",
- "fo=1.0*10**6\n",
- "zP=224.0*10**3\n",
- "rC=100.0*10**3\n",
- "K=0.015\n",
- "Ls=50.0*10**-6\n",
- "\n",
- "\n",
- "#Calculations\n",
- "RL=(Zp*Rc)/(Rc+Zp)\n",
- "print(\"voltage gain from the input to the primary memory winding\")\n",
- "Avp=(hfe*RL)/hie\n",
- "Vsp=K*math.sqrt(Ls/Lp)\n",
- "print(\"overall voltage gain from the input to teh secondary winding\")\n",
- "Av=Avp*Vsp\n",
- "Qp=Rc/(2*3.14*fo*Lp)\n",
- "Ql=471\n",
- "Q=(Ql*Qp)/(Ql+Qp)\n",
- "B=fo/Q\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"bandwidth is %.2f kHz \" %(B/10**5))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain from the input to the primary memory winding\n",
- "overall voltage gain from the input to teh secondary winding\n",
- "bandwidth is 47.12 kHz \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 12.24, Page No 530"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=1.0*10**6\n",
- "L2=50.0*10**-6\n",
- "K=0.015\n",
- "L1=75*10**-6\n",
- "rs=5.0\n",
- "Rw=1.0\n",
- "Lp=100.0*10**-6\n",
- "Cp=330.0*10**-12\n",
- "Cc=5.0*10**-12\n",
- "Rc=100.0*10**3\n",
- "hfe=50.0\n",
- "hie=1.0*10**3\n",
- "\n",
- "\n",
- "#Calculations\n",
- "C2=1/(((2*3.14*f)**2)*L2)\n",
- "M=K*math.sqrt(L1*L2)\n",
- "Rs=(((2*3.14*f)**2)*(M)**2)/rs\n",
- "Rp=Rs+Rw\n",
- "Zp=Lp/((Cp+Cc)*Rp)\n",
- "Rl=(Zp*Rc)/(Zp+Rc)\n",
- "print(\"voltage gain from the input to primary winding\")\n",
- "Avp=(hfe*Rl)/hie\n",
- "Vsp=12.2*10**-3\n",
- "Vos=((2*3.14*f)*L2)/rs\n",
- "\n",
- "#Results\n",
- "print(\"overall voltage gain from the input to secondary winding \")\n",
- "Av=Avp*Vos*Vsp\n",
- "print('The value of Av= %.2f ' %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain from the input to primary winding\n",
- "overall voltage gain from the input to secondary winding \n",
- "The value of Av= 1074.71 \n"
- ]
- }
- ],
- "prompt_number": 22
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter13.ipynb b/Electronic_Devices_and_Circuits/Chapter13.ipynb deleted file mode 100755 index 0a7d7550..00000000 --- a/Electronic_Devices_and_Circuits/Chapter13.ipynb +++ /dev/null @@ -1,733 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 13 : Amplifier with negative feedback"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.1, Page No 547"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Av=100000.0\n",
- "B=1.0/100\n",
- "print(\"when Av=100000\")\n",
- "\n",
- "#Calculations\n",
- "Acl=Av/(1+Av*B)\n",
- "print(\"when Av is 150000\")\n",
- "Av=150000\n",
- "Acl=Av/(1+Av*B)\n",
- "\n",
- "#Results\n",
- "print(\"when Av is 50000\")\n",
- "Av=50000\n",
- "Acl=Av/(1+Av*B)\n",
- "print('The value of Acl= %.2f ' %(Acl))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Av=100000\n",
- "when Av is 150000\n",
- "when Av is 50000\n",
- "The value of Acl= 99.80 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.2, Page No 549"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Rf2=560.0\n",
- "Rf1=56.0*10**3\n",
- "Av=100000.0\n",
- "Zb=1.0*10**3\n",
- "R1=68.0*10**3\n",
- "R2=33.0*10**3\n",
- "\n",
- "#Calculations\n",
- "B=Rf2/(Rf2+Rf1)\n",
- "Zi=(1+Av*B)*Zb\n",
- "Zin=(Zi*R1*R2)/(R1*R2+R1*Zi+R2*Zi)\n",
- "\n",
- "#Results\n",
- "print(\"input impedance with negative feedback is %.2f ohm \" %(Zin/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance with negative feedback is 21.73 ohm \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.3 Page No 552"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Zb=1.0*10**3\n",
- "B=1.0/100\n",
- "Av=5562.0\n",
- "R1=68.0*10**3\n",
- "R2=47.0*10**3\n",
- "hoe=1.0/(50*10**3)\n",
- "Rc=3.9*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(1+Av*B)*Zb\n",
- "Zin=(R1*R2*Zi)/(R1*R2+R2*Zi+R1*Zi)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(Rc*Zo)/(Rc+Zo)\n",
- "\n",
- "#Results\n",
- "print(\" circuit output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " circuit output impedance is 720.04 ohm \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.4, Page No 554"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Zb=1.0*10**3\n",
- "hoe=1.0/(85*10**3)\n",
- "Av=58000.0\n",
- "Rf2=220.0\n",
- "Rf1=16.2*10**3\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "R7=12.0*10**3\n",
- "\n",
- "#Calculations\n",
- "B=Rf2/(Rf2+Rf1)\n",
- "print(\"voltage gain\")\n",
- "Acl=Av/(1+Av*B)\n",
- "Zi=Zb*(1+Av*B)\n",
- "Zin=(Zi*R1*R2)/(Zi*R1+R2*R1+R2*Zi)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(R7*Zo)/(R7+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain\n",
- "output impedance is 108.25 ohm \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.5 Page No 558"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rf2=220.0\n",
- "R4=3.9*10**3\n",
- "Acl=75.0\n",
- "f=100.0\n",
- "\n",
- "#Calculations\n",
- "Rf1=(Acl-1)*Rf2\n",
- "Xc2=Rf2\n",
- "C2=1/(2*3.14*f*Rf2)\n",
- "Xcf1=Rf1/100\n",
- "Cf1=1/(2*3.14*f*Xcf1)\n",
- "\n",
- "#Results\n",
- "print('The value of Cf1= %.2f mF' %(Cf1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Cf1= 9.78 mF\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.6 Page No 560"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Acl=300.0\n",
- "Rf2=220.0\n",
- "R4=4.7*10**3\n",
- "f=100.0\n",
- "\n",
- "#Calculations\n",
- "Rf1=(Acl-1)*Rf2\n",
- "xc2=Rf2\n",
- "C2=1.0/(2*3.14*f*Rf2)\n",
- "\n",
- "#Results\n",
- "print('The value of C2= %.2f mf' %(C2*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C2= 7.24 mf\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.7, Page No 565"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "Vbe=0.7\n",
- "Ic1=1.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Ic2=Ic1\n",
- "Ic3=Ic2\n",
- "Ic4=Ic3\n",
- "Vee=10.0\n",
- "Vce=3.0\n",
- "Acl=33.0\n",
- "print(\"different resistor value of circuit\")\n",
- "R1=Vbe/((10*Ic1)/hfe)\n",
- "R3=(Vee-Vbe)/(Ic1+Ic2)\n",
- "Vr2=Vee+Vbe-Vce\n",
- "R4=Vr2/Ic1\n",
- "R2=R4\n",
- "R7=(Vr2-Vbe)/(Ic3+Ic4)\n",
- "R8=Vee/Ic3\n",
- "R6=6.8*10**3\n",
- "R5=(Acl-1)*R6\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f kohm' %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "different resistor value of circuit\n",
- "The value of R5= 217.60 kohm\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.8 Page No 566"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Av=25000.0\n",
- "hie=2.0*10**3\n",
- "hib=25.0\n",
- "hoe=1.0/(100*10**3)\n",
- "R6=6.8*10**3\n",
- "R5=220.0*10**3\n",
- "R1=R6\n",
- "\n",
- "#Calculations\n",
- "R8=10*10**3\n",
- "B=R6/(R5+R6)\n",
- "Acl=Av/(1+Av*B)\n",
- "Zi=2*hie*(1+Av*B)\n",
- "Zin=(Zi*R1)/(Zi+R1)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(R8*Zo)/(R8+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output impedance is 131.48 ohm \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.9 Page No 568"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hic=2.0*10**3\n",
- "hie=hic\n",
- "hfe=100.0\n",
- "hfc=100.0\n",
- "Av=25000.0\n",
- "B=1.0/33.4\n",
- "\n",
- "#Calculations\n",
- "R8=10*10**3\n",
- "R5=R8\n",
- "Ze=(hic+R8)/hfc\n",
- "Zo=Ze/(1+Av*B)\n",
- "Zout=(R5*Zo)/(R5+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2fohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output impedance is 0.16ohm \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.10 Page No 570"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hfemin=100.0\n",
- "hfemax=400.0\n",
- "hiemin=2.0*10**3\n",
- "hiemax=5.0*10**3\n",
- "Rc=12.0*10**3\n",
- "Rl=120.0*10**3\n",
- "Re1=150.0\n",
- "\n",
- "#Calculations\n",
- "print(\" voltage gain at extreme value \")\n",
- "Avmax=(hfemax*((Rc*Rl)/(Rc+Rl)))/(hiemax+Re1*(1+hfemax))\n",
- "Avmin=(hfemin*((Rc*Rl)/(Rc+Rl)))/(hiemin+Re1*(1+hfemin))\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"approximate voltage gain\")\n",
- "Av=((Rc*Rl)/(Rc+Rl))/Re1"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage gain at extreme value \n",
- "approximate voltage gain\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.11, Page No 571"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Av=70.0\n",
- "f=100.0\n",
- "rs=600.0\n",
- "Rc=12.0*10**3\n",
- "Rl=120*10**3\n",
- "Re2=3.9*10**3\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R1=Rl\n",
- "R2=39.0*10**3\n",
- "Re1=150.0\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+Re1*(1+hfe)\n",
- "Zin=(R1*R2*Zb)/(R1*R2+R1*Zb+R2*Zb)\n",
- "C1=1/(2*3.14*f*((Zin+rs)/10))\n",
- "C2=1/(2*3.14*f*Re1)\n",
- "\n",
- "#Results\n",
- "print('The value of C2= %.2f mF ' %(C2*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C2= 10.62 mF \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.12, Page No 573"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Av=1000.0\n",
- "f=100.0\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R8=12.0*10**3\n",
- "Rl=120*10**3\n",
- "R10=3.9*10**3\n",
- "R6=Rl\n",
- "R7=39.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R3=R8\n",
- "Av1=math.sqrt(Av)\n",
- "Av2=Av1\n",
- "R9=((R8*Rl)/(R8+Rl))/Av2\n",
- "R9=330#use standard value\n",
- "Av2=((R8*Rl)/(R8+Rl))/R9\n",
- "Av1=Av/Av2\n",
- "Zb=hie+R9*(1+hfe)\n",
- "Zin=(R6*R7*Zb)/(R6*R7+R6*Zb+R7*Zb)\n",
- "R4=((R3*Zin)/(R3+Zin))/Av1\n",
- "R5=R10-R4\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f ' %(R5/1000))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R5= 3.67 \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.13, Page No 574"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R8=12.0*10**3\n",
- "Rl=120.0*10**3\n",
- "R10=3.9*10**3\n",
- "R6=Rl\n",
- "R7=39.0*10**3\n",
- "R3=R8\n",
- "R4=220.0\n",
- "rs=600.0\n",
- "Zin2=16.0*10**3\n",
- "R9=330.0\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+R4*(1+hfe)\n",
- "Zin=(R1*R2*Zb)/(R1*R2+R1*Zb+R2*Zb)\n",
- "C1=1.0/(2*3.14*f*((Zin+rs)/10))\n",
- "Xc2=0.65*R4\n",
- "C2=1.0/(2*3.14*f*Xc2)\n",
- "C3=1.0/(2*3.14*f*((Zin2+R3)/10))\n",
- "C4=1.0/(2*3.14*f*.65*R9)\n",
- "C5=1.0/(2*3.14*f*((R8+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C5= %.2f mF ' %(C5*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C5= 0.12 mF \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.14, Page No 580"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "hie=2.0*10**3\n",
- "R4=100.0\n",
- "R1=5.6*10**3\n",
- "R6=2.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=hie+(1+hfe)*R4\n",
- "print(\"open loop current gain\")\n",
- "Ai=(hfe*hfe*R1)/(R1+Zi)\n",
- "B=R4/(R4+R6)\n",
- "print(\"closed loop gain\")\n",
- "Acl=Ai/(1+Ai*B)\n",
- "Zi=hie/(1+Ai*B)\n",
- "\n",
- "#Results\n",
- "print('The value of Zi= %.2f ohm ' %(Zi))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "open loop current gain\n",
- "closed loop gain\n",
- "The value of Zi= 14.43 ohm \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.15, Page No 585"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Av=60000.0\n",
- "Acl=300.0\n",
- "f1=15.0*10**3\n",
- "B=1.0/300\n",
- "\n",
- "#Calculations\n",
- "f2=(Av*f1)/Acl\n",
- "print(\"% distortion with NFB\")\n",
- "NFB=(.1/(1+Av*B))*100.0\n",
- "\n",
- "#Results\n",
- "print(\" percenatge distortion with NFB is %.3f percent \" %NFB)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "% distortion with NFB\n",
- " percenatge distortion with NFB is 0.050 percent \n"
- ]
- }
- ],
- "prompt_number": 15
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter13_1.ipynb b/Electronic_Devices_and_Circuits/Chapter13_1.ipynb deleted file mode 100755 index 0a7d7550..00000000 --- a/Electronic_Devices_and_Circuits/Chapter13_1.ipynb +++ /dev/null @@ -1,733 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 13 : Amplifier with negative feedback"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.1, Page No 547"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Av=100000.0\n",
- "B=1.0/100\n",
- "print(\"when Av=100000\")\n",
- "\n",
- "#Calculations\n",
- "Acl=Av/(1+Av*B)\n",
- "print(\"when Av is 150000\")\n",
- "Av=150000\n",
- "Acl=Av/(1+Av*B)\n",
- "\n",
- "#Results\n",
- "print(\"when Av is 50000\")\n",
- "Av=50000\n",
- "Acl=Av/(1+Av*B)\n",
- "print('The value of Acl= %.2f ' %(Acl))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Av=100000\n",
- "when Av is 150000\n",
- "when Av is 50000\n",
- "The value of Acl= 99.80 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.2, Page No 549"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Rf2=560.0\n",
- "Rf1=56.0*10**3\n",
- "Av=100000.0\n",
- "Zb=1.0*10**3\n",
- "R1=68.0*10**3\n",
- "R2=33.0*10**3\n",
- "\n",
- "#Calculations\n",
- "B=Rf2/(Rf2+Rf1)\n",
- "Zi=(1+Av*B)*Zb\n",
- "Zin=(Zi*R1*R2)/(R1*R2+R1*Zi+R2*Zi)\n",
- "\n",
- "#Results\n",
- "print(\"input impedance with negative feedback is %.2f ohm \" %(Zin/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance with negative feedback is 21.73 ohm \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.3 Page No 552"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Zb=1.0*10**3\n",
- "B=1.0/100\n",
- "Av=5562.0\n",
- "R1=68.0*10**3\n",
- "R2=47.0*10**3\n",
- "hoe=1.0/(50*10**3)\n",
- "Rc=3.9*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(1+Av*B)*Zb\n",
- "Zin=(R1*R2*Zi)/(R1*R2+R2*Zi+R1*Zi)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(Rc*Zo)/(Rc+Zo)\n",
- "\n",
- "#Results\n",
- "print(\" circuit output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " circuit output impedance is 720.04 ohm \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.4, Page No 554"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Zb=1.0*10**3\n",
- "hoe=1.0/(85*10**3)\n",
- "Av=58000.0\n",
- "Rf2=220.0\n",
- "Rf1=16.2*10**3\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "R7=12.0*10**3\n",
- "\n",
- "#Calculations\n",
- "B=Rf2/(Rf2+Rf1)\n",
- "print(\"voltage gain\")\n",
- "Acl=Av/(1+Av*B)\n",
- "Zi=Zb*(1+Av*B)\n",
- "Zin=(Zi*R1*R2)/(Zi*R1+R2*R1+R2*Zi)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(R7*Zo)/(R7+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain\n",
- "output impedance is 108.25 ohm \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.5 Page No 558"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rf2=220.0\n",
- "R4=3.9*10**3\n",
- "Acl=75.0\n",
- "f=100.0\n",
- "\n",
- "#Calculations\n",
- "Rf1=(Acl-1)*Rf2\n",
- "Xc2=Rf2\n",
- "C2=1/(2*3.14*f*Rf2)\n",
- "Xcf1=Rf1/100\n",
- "Cf1=1/(2*3.14*f*Xcf1)\n",
- "\n",
- "#Results\n",
- "print('The value of Cf1= %.2f mF' %(Cf1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Cf1= 9.78 mF\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.6 Page No 560"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Acl=300.0\n",
- "Rf2=220.0\n",
- "R4=4.7*10**3\n",
- "f=100.0\n",
- "\n",
- "#Calculations\n",
- "Rf1=(Acl-1)*Rf2\n",
- "xc2=Rf2\n",
- "C2=1.0/(2*3.14*f*Rf2)\n",
- "\n",
- "#Results\n",
- "print('The value of C2= %.2f mf' %(C2*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C2= 7.24 mf\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.7, Page No 565"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "Vbe=0.7\n",
- "Ic1=1.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Ic2=Ic1\n",
- "Ic3=Ic2\n",
- "Ic4=Ic3\n",
- "Vee=10.0\n",
- "Vce=3.0\n",
- "Acl=33.0\n",
- "print(\"different resistor value of circuit\")\n",
- "R1=Vbe/((10*Ic1)/hfe)\n",
- "R3=(Vee-Vbe)/(Ic1+Ic2)\n",
- "Vr2=Vee+Vbe-Vce\n",
- "R4=Vr2/Ic1\n",
- "R2=R4\n",
- "R7=(Vr2-Vbe)/(Ic3+Ic4)\n",
- "R8=Vee/Ic3\n",
- "R6=6.8*10**3\n",
- "R5=(Acl-1)*R6\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f kohm' %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "different resistor value of circuit\n",
- "The value of R5= 217.60 kohm\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.8 Page No 566"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Av=25000.0\n",
- "hie=2.0*10**3\n",
- "hib=25.0\n",
- "hoe=1.0/(100*10**3)\n",
- "R6=6.8*10**3\n",
- "R5=220.0*10**3\n",
- "R1=R6\n",
- "\n",
- "#Calculations\n",
- "R8=10*10**3\n",
- "B=R6/(R5+R6)\n",
- "Acl=Av/(1+Av*B)\n",
- "Zi=2*hie*(1+Av*B)\n",
- "Zin=(Zi*R1)/(Zi+R1)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(R8*Zo)/(R8+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output impedance is 131.48 ohm \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.9 Page No 568"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hic=2.0*10**3\n",
- "hie=hic\n",
- "hfe=100.0\n",
- "hfc=100.0\n",
- "Av=25000.0\n",
- "B=1.0/33.4\n",
- "\n",
- "#Calculations\n",
- "R8=10*10**3\n",
- "R5=R8\n",
- "Ze=(hic+R8)/hfc\n",
- "Zo=Ze/(1+Av*B)\n",
- "Zout=(R5*Zo)/(R5+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2fohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output impedance is 0.16ohm \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.10 Page No 570"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hfemin=100.0\n",
- "hfemax=400.0\n",
- "hiemin=2.0*10**3\n",
- "hiemax=5.0*10**3\n",
- "Rc=12.0*10**3\n",
- "Rl=120.0*10**3\n",
- "Re1=150.0\n",
- "\n",
- "#Calculations\n",
- "print(\" voltage gain at extreme value \")\n",
- "Avmax=(hfemax*((Rc*Rl)/(Rc+Rl)))/(hiemax+Re1*(1+hfemax))\n",
- "Avmin=(hfemin*((Rc*Rl)/(Rc+Rl)))/(hiemin+Re1*(1+hfemin))\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"approximate voltage gain\")\n",
- "Av=((Rc*Rl)/(Rc+Rl))/Re1"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage gain at extreme value \n",
- "approximate voltage gain\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.11, Page No 571"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Av=70.0\n",
- "f=100.0\n",
- "rs=600.0\n",
- "Rc=12.0*10**3\n",
- "Rl=120*10**3\n",
- "Re2=3.9*10**3\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R1=Rl\n",
- "R2=39.0*10**3\n",
- "Re1=150.0\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+Re1*(1+hfe)\n",
- "Zin=(R1*R2*Zb)/(R1*R2+R1*Zb+R2*Zb)\n",
- "C1=1/(2*3.14*f*((Zin+rs)/10))\n",
- "C2=1/(2*3.14*f*Re1)\n",
- "\n",
- "#Results\n",
- "print('The value of C2= %.2f mF ' %(C2*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C2= 10.62 mF \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.12, Page No 573"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Av=1000.0\n",
- "f=100.0\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R8=12.0*10**3\n",
- "Rl=120*10**3\n",
- "R10=3.9*10**3\n",
- "R6=Rl\n",
- "R7=39.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R3=R8\n",
- "Av1=math.sqrt(Av)\n",
- "Av2=Av1\n",
- "R9=((R8*Rl)/(R8+Rl))/Av2\n",
- "R9=330#use standard value\n",
- "Av2=((R8*Rl)/(R8+Rl))/R9\n",
- "Av1=Av/Av2\n",
- "Zb=hie+R9*(1+hfe)\n",
- "Zin=(R6*R7*Zb)/(R6*R7+R6*Zb+R7*Zb)\n",
- "R4=((R3*Zin)/(R3+Zin))/Av1\n",
- "R5=R10-R4\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f ' %(R5/1000))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R5= 3.67 \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.13, Page No 574"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R8=12.0*10**3\n",
- "Rl=120.0*10**3\n",
- "R10=3.9*10**3\n",
- "R6=Rl\n",
- "R7=39.0*10**3\n",
- "R3=R8\n",
- "R4=220.0\n",
- "rs=600.0\n",
- "Zin2=16.0*10**3\n",
- "R9=330.0\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+R4*(1+hfe)\n",
- "Zin=(R1*R2*Zb)/(R1*R2+R1*Zb+R2*Zb)\n",
- "C1=1.0/(2*3.14*f*((Zin+rs)/10))\n",
- "Xc2=0.65*R4\n",
- "C2=1.0/(2*3.14*f*Xc2)\n",
- "C3=1.0/(2*3.14*f*((Zin2+R3)/10))\n",
- "C4=1.0/(2*3.14*f*.65*R9)\n",
- "C5=1.0/(2*3.14*f*((R8+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C5= %.2f mF ' %(C5*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C5= 0.12 mF \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.14, Page No 580"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "hie=2.0*10**3\n",
- "R4=100.0\n",
- "R1=5.6*10**3\n",
- "R6=2.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=hie+(1+hfe)*R4\n",
- "print(\"open loop current gain\")\n",
- "Ai=(hfe*hfe*R1)/(R1+Zi)\n",
- "B=R4/(R4+R6)\n",
- "print(\"closed loop gain\")\n",
- "Acl=Ai/(1+Ai*B)\n",
- "Zi=hie/(1+Ai*B)\n",
- "\n",
- "#Results\n",
- "print('The value of Zi= %.2f ohm ' %(Zi))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "open loop current gain\n",
- "closed loop gain\n",
- "The value of Zi= 14.43 ohm \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.15, Page No 585"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Av=60000.0\n",
- "Acl=300.0\n",
- "f1=15.0*10**3\n",
- "B=1.0/300\n",
- "\n",
- "#Calculations\n",
- "f2=(Av*f1)/Acl\n",
- "print(\"% distortion with NFB\")\n",
- "NFB=(.1/(1+Av*B))*100.0\n",
- "\n",
- "#Results\n",
- "print(\" percenatge distortion with NFB is %.3f percent \" %NFB)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "% distortion with NFB\n",
- " percenatge distortion with NFB is 0.050 percent \n"
- ]
- }
- ],
- "prompt_number": 15
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter13_2.ipynb b/Electronic_Devices_and_Circuits/Chapter13_2.ipynb deleted file mode 100755 index 0a7d7550..00000000 --- a/Electronic_Devices_and_Circuits/Chapter13_2.ipynb +++ /dev/null @@ -1,733 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 13 : Amplifier with negative feedback"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.1, Page No 547"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Av=100000.0\n",
- "B=1.0/100\n",
- "print(\"when Av=100000\")\n",
- "\n",
- "#Calculations\n",
- "Acl=Av/(1+Av*B)\n",
- "print(\"when Av is 150000\")\n",
- "Av=150000\n",
- "Acl=Av/(1+Av*B)\n",
- "\n",
- "#Results\n",
- "print(\"when Av is 50000\")\n",
- "Av=50000\n",
- "Acl=Av/(1+Av*B)\n",
- "print('The value of Acl= %.2f ' %(Acl))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Av=100000\n",
- "when Av is 150000\n",
- "when Av is 50000\n",
- "The value of Acl= 99.80 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.2, Page No 549"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Rf2=560.0\n",
- "Rf1=56.0*10**3\n",
- "Av=100000.0\n",
- "Zb=1.0*10**3\n",
- "R1=68.0*10**3\n",
- "R2=33.0*10**3\n",
- "\n",
- "#Calculations\n",
- "B=Rf2/(Rf2+Rf1)\n",
- "Zi=(1+Av*B)*Zb\n",
- "Zin=(Zi*R1*R2)/(R1*R2+R1*Zi+R2*Zi)\n",
- "\n",
- "#Results\n",
- "print(\"input impedance with negative feedback is %.2f ohm \" %(Zin/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance with negative feedback is 21.73 ohm \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.3 Page No 552"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Zb=1.0*10**3\n",
- "B=1.0/100\n",
- "Av=5562.0\n",
- "R1=68.0*10**3\n",
- "R2=47.0*10**3\n",
- "hoe=1.0/(50*10**3)\n",
- "Rc=3.9*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=(1+Av*B)*Zb\n",
- "Zin=(R1*R2*Zi)/(R1*R2+R2*Zi+R1*Zi)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(Rc*Zo)/(Rc+Zo)\n",
- "\n",
- "#Results\n",
- "print(\" circuit output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " circuit output impedance is 720.04 ohm \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.4, Page No 554"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Zb=1.0*10**3\n",
- "hoe=1.0/(85*10**3)\n",
- "Av=58000.0\n",
- "Rf2=220.0\n",
- "Rf1=16.2*10**3\n",
- "R1=120.0*10**3\n",
- "R2=39.0*10**3\n",
- "R7=12.0*10**3\n",
- "\n",
- "#Calculations\n",
- "B=Rf2/(Rf2+Rf1)\n",
- "print(\"voltage gain\")\n",
- "Acl=Av/(1+Av*B)\n",
- "Zi=Zb*(1+Av*B)\n",
- "Zin=(Zi*R1*R2)/(Zi*R1+R2*R1+R2*Zi)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(R7*Zo)/(R7+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain\n",
- "output impedance is 108.25 ohm \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.5 Page No 558"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rf2=220.0\n",
- "R4=3.9*10**3\n",
- "Acl=75.0\n",
- "f=100.0\n",
- "\n",
- "#Calculations\n",
- "Rf1=(Acl-1)*Rf2\n",
- "Xc2=Rf2\n",
- "C2=1/(2*3.14*f*Rf2)\n",
- "Xcf1=Rf1/100\n",
- "Cf1=1/(2*3.14*f*Xcf1)\n",
- "\n",
- "#Results\n",
- "print('The value of Cf1= %.2f mF' %(Cf1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Cf1= 9.78 mF\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.6 Page No 560"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Acl=300.0\n",
- "Rf2=220.0\n",
- "R4=4.7*10**3\n",
- "f=100.0\n",
- "\n",
- "#Calculations\n",
- "Rf1=(Acl-1)*Rf2\n",
- "xc2=Rf2\n",
- "C2=1.0/(2*3.14*f*Rf2)\n",
- "\n",
- "#Results\n",
- "print('The value of C2= %.2f mf' %(C2*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C2= 7.24 mf\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.7, Page No 565"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "Vbe=0.7\n",
- "Ic1=1.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Ic2=Ic1\n",
- "Ic3=Ic2\n",
- "Ic4=Ic3\n",
- "Vee=10.0\n",
- "Vce=3.0\n",
- "Acl=33.0\n",
- "print(\"different resistor value of circuit\")\n",
- "R1=Vbe/((10*Ic1)/hfe)\n",
- "R3=(Vee-Vbe)/(Ic1+Ic2)\n",
- "Vr2=Vee+Vbe-Vce\n",
- "R4=Vr2/Ic1\n",
- "R2=R4\n",
- "R7=(Vr2-Vbe)/(Ic3+Ic4)\n",
- "R8=Vee/Ic3\n",
- "R6=6.8*10**3\n",
- "R5=(Acl-1)*R6\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f kohm' %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "different resistor value of circuit\n",
- "The value of R5= 217.60 kohm\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.8 Page No 566"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Av=25000.0\n",
- "hie=2.0*10**3\n",
- "hib=25.0\n",
- "hoe=1.0/(100*10**3)\n",
- "R6=6.8*10**3\n",
- "R5=220.0*10**3\n",
- "R1=R6\n",
- "\n",
- "#Calculations\n",
- "R8=10*10**3\n",
- "B=R6/(R5+R6)\n",
- "Acl=Av/(1+Av*B)\n",
- "Zi=2*hie*(1+Av*B)\n",
- "Zin=(Zi*R1)/(Zi+R1)\n",
- "Zo=(1/hoe)/(1+Av*B)\n",
- "Zout=(R8*Zo)/(R8+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2f ohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output impedance is 131.48 ohm \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.9 Page No 568"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hic=2.0*10**3\n",
- "hie=hic\n",
- "hfe=100.0\n",
- "hfc=100.0\n",
- "Av=25000.0\n",
- "B=1.0/33.4\n",
- "\n",
- "#Calculations\n",
- "R8=10*10**3\n",
- "R5=R8\n",
- "Ze=(hic+R8)/hfc\n",
- "Zo=Ze/(1+Av*B)\n",
- "Zout=(R5*Zo)/(R5+Zo)\n",
- "\n",
- "#Results\n",
- "print(\"output impedance is %.2fohm \" %Zout)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output impedance is 0.16ohm \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.10 Page No 570"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hfemin=100.0\n",
- "hfemax=400.0\n",
- "hiemin=2.0*10**3\n",
- "hiemax=5.0*10**3\n",
- "Rc=12.0*10**3\n",
- "Rl=120.0*10**3\n",
- "Re1=150.0\n",
- "\n",
- "#Calculations\n",
- "print(\" voltage gain at extreme value \")\n",
- "Avmax=(hfemax*((Rc*Rl)/(Rc+Rl)))/(hiemax+Re1*(1+hfemax))\n",
- "Avmin=(hfemin*((Rc*Rl)/(Rc+Rl)))/(hiemin+Re1*(1+hfemin))\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"approximate voltage gain\")\n",
- "Av=((Rc*Rl)/(Rc+Rl))/Re1"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage gain at extreme value \n",
- "approximate voltage gain\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.11, Page No 571"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Av=70.0\n",
- "f=100.0\n",
- "rs=600.0\n",
- "Rc=12.0*10**3\n",
- "Rl=120*10**3\n",
- "Re2=3.9*10**3\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R1=Rl\n",
- "R2=39.0*10**3\n",
- "Re1=150.0\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+Re1*(1+hfe)\n",
- "Zin=(R1*R2*Zb)/(R1*R2+R1*Zb+R2*Zb)\n",
- "C1=1/(2*3.14*f*((Zin+rs)/10))\n",
- "C2=1/(2*3.14*f*Re1)\n",
- "\n",
- "#Results\n",
- "print('The value of C2= %.2f mF ' %(C2*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C2= 10.62 mF \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.12, Page No 573"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Av=1000.0\n",
- "f=100.0\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R8=12.0*10**3\n",
- "Rl=120*10**3\n",
- "R10=3.9*10**3\n",
- "R6=Rl\n",
- "R7=39.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R3=R8\n",
- "Av1=math.sqrt(Av)\n",
- "Av2=Av1\n",
- "R9=((R8*Rl)/(R8+Rl))/Av2\n",
- "R9=330#use standard value\n",
- "Av2=((R8*Rl)/(R8+Rl))/R9\n",
- "Av1=Av/Av2\n",
- "Zb=hie+R9*(1+hfe)\n",
- "Zin=(R6*R7*Zb)/(R6*R7+R6*Zb+R7*Zb)\n",
- "R4=((R3*Zin)/(R3+Zin))/Av1\n",
- "R5=R10-R4\n",
- "\n",
- "#Results\n",
- "print('The value of R5= %.2f ' %(R5/1000))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R5= 3.67 \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.13, Page No 574"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0\n",
- "hie=2.0*10**3\n",
- "hfe=100.0\n",
- "R8=12.0*10**3\n",
- "Rl=120.0*10**3\n",
- "R10=3.9*10**3\n",
- "R6=Rl\n",
- "R7=39.0*10**3\n",
- "R3=R8\n",
- "R4=220.0\n",
- "rs=600.0\n",
- "Zin2=16.0*10**3\n",
- "R9=330.0\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+R4*(1+hfe)\n",
- "Zin=(R1*R2*Zb)/(R1*R2+R1*Zb+R2*Zb)\n",
- "C1=1.0/(2*3.14*f*((Zin+rs)/10))\n",
- "Xc2=0.65*R4\n",
- "C2=1.0/(2*3.14*f*Xc2)\n",
- "C3=1.0/(2*3.14*f*((Zin2+R3)/10))\n",
- "C4=1.0/(2*3.14*f*.65*R9)\n",
- "C5=1.0/(2*3.14*f*((R8+Rl)/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C5= %.2f mF ' %(C5*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C5= 0.12 mF \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.14, Page No 580"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hfe=100.0\n",
- "hie=2.0*10**3\n",
- "R4=100.0\n",
- "R1=5.6*10**3\n",
- "R6=2.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Zi=hie+(1+hfe)*R4\n",
- "print(\"open loop current gain\")\n",
- "Ai=(hfe*hfe*R1)/(R1+Zi)\n",
- "B=R4/(R4+R6)\n",
- "print(\"closed loop gain\")\n",
- "Acl=Ai/(1+Ai*B)\n",
- "Zi=hie/(1+Ai*B)\n",
- "\n",
- "#Results\n",
- "print('The value of Zi= %.2f ohm ' %(Zi))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "open loop current gain\n",
- "closed loop gain\n",
- "The value of Zi= 14.43 ohm \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 13.15, Page No 585"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Av=60000.0\n",
- "Acl=300.0\n",
- "f1=15.0*10**3\n",
- "B=1.0/300\n",
- "\n",
- "#Calculations\n",
- "f2=(Av*f1)/Acl\n",
- "print(\"% distortion with NFB\")\n",
- "NFB=(.1/(1+Av*B))*100.0\n",
- "\n",
- "#Results\n",
- "print(\" percenatge distortion with NFB is %.3f percent \" %NFB)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "% distortion with NFB\n",
- " percenatge distortion with NFB is 0.050 percent \n"
- ]
- }
- ],
- "prompt_number": 15
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter14.ipynb b/Electronic_Devices_and_Circuits/Chapter14.ipynb deleted file mode 100755 index 90767c65..00000000 --- a/Electronic_Devices_and_Circuits/Chapter14.ipynb +++ /dev/null @@ -1,662 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 14 : Ic operational Amplifier and basic Op amp circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.1, Page No 597"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=0.7\n",
- "Ib=500.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "R1=Vbe/(10.0*Ib)\n",
- "R1=120.0*10**3#use standard value\n",
- "R2=R1\n",
- "I2=100.0*Ib\n",
- "Vr1=15.0\n",
- "Vr2=Vr1\n",
- "R1=Vr1/I2\n",
- "R1=270.0*10**3#use satndard value\n",
- "R2=R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 135.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.2, Page No 599"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R2=1.0*10**6\n",
- "Vb=3.0\n",
- "Vo=3.0\n",
- "Vee=9.0\n",
- "\n",
- "#Calculations\n",
- "Vr2=Vb-(-Vee)\n",
- "Vr1=Vee-Vb\n",
- "I2=Vr2/R2\n",
- "R1=Vr1/I2\n",
- "R3=0\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 500.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.3 Page No 601"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Av=200000.0\n",
- "ri=2.0*10**6\n",
- "ro=75.0\n",
- "Vo=1.0\n",
- "B=1.0\n",
- "\n",
- "#Calculations\n",
- "Vd=Vo/Av\n",
- "Zi=(1+Av*B)*ri\n",
- "Zo=ro/(1+Av*B)\n",
- "\n",
- "#Results\n",
- "print('The value of Zo= %.2f X 10^-3 kohm ' %(Zo*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Zo= 0.37 X 10^-3 kohm \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.4, Page No 603"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=70.0\n",
- "Rl=4.0*10**3\n",
- "Ib=500.0*10**-9\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "R1=Vbe/(10*Ib)\n",
- "R1=120*10**3#use standard value\n",
- "R2=R1\n",
- "print(\" desire value of capacitor is C=1/2*3.14*f*R\")\n",
- "C2=1/(2*3.14*f*Rl)\n",
- "C1=1/(2*3.14*f*(R1/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C1= %.2f mF ' %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " desire value of capacitor is C=1/2*3.14*f*R\n",
- "The value of C1= 0.19 mF \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.5 Page No 605"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=500.0*10**-9\n",
- "Vi=50.0*10**-3\n",
- "Vo=2.0\n",
- "\n",
- "#Calculations\n",
- "I2=100.0*Ib\n",
- "R3=Vi/I2\n",
- "R2=(Vo/I2)-R3\n",
- "R1=(R2*R3)/(R2+R3)\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 0.97 kohm \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.6 Page No 606"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Av=200000.0\n",
- "ri=2.0*10**6\n",
- "ro=75.0\n",
- "R3=1.0*10**3\n",
- "R2=39*10**3\n",
- "\n",
- "#Calculations\n",
- "B=R3/(R2+R3)\n",
- "Zi=(1+Av*B)*ri\n",
- "\n",
- "#Results\n",
- "print(\" typical input impedance for non-inverting amplifier is %.2f ohm \" %Zi)\n",
- "Zo=ro/(1+Av*B)\n",
- "print('The value of Zo= %.2f kohm ' %(Zo*10))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " typical input impedance for non-inverting amplifier is 10002000000.00 ohm \n",
- "The value of Zo= 0.15 kohm \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.7, Page No 607"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R2=50.0*10**3\n",
- "R3=2.2*10**3\n",
- "C2=8.2*10**-6\n",
- "Rl=600.0\n",
- "\n",
- "#Calculations\n",
- "print(\"voltage gain \")\n",
- "Acl=(R3+R2)/R3\n",
- "\n",
- "#Results\n",
- "print(\"lower cuttoff frequency \")\n",
- "f=1/(2*3.14*C2*Rl)\n",
- "print('The value of f= %.2f kohm ' %(f))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain \n",
- "lower cuttoff frequency \n",
- "The value of f= 32.36 kohm \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.8 Page No 610"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Acl=144.0\n",
- "Vi=20.0*10**-3\n",
- "Ib=500.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "I1=100.0*Ib\n",
- "R1=Vi/I1\n",
- "R1=390.0 #use standard value\n",
- "R2=Acl*R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 387.31 kohm \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.9 Page No 612"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Acl=3.0\n",
- "R4=1.0*10**6\n",
- "Vi=1.0\n",
- "\n",
- "#Calculations\n",
- "R1=R4/Acl\n",
- "R1=330.0*10**3#use standard value \n",
- "R2=R1\n",
- "R3=R1\n",
- "I1=Vi/R1\n",
- "I2=I1\n",
- "I3=I1\n",
- "I4=I1+I2+I3\n",
- "Vo=-I4*R4\n",
- "\n",
- "#Results\n",
- "print('The value of Vo= %.2f v ' %(Vo))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vo= -9.09 v \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.10 Page No 615"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=500.0*10**-9\n",
- "Vi=1.0\n",
- "Acl=10.0\n",
- "\n",
- "#Calculations\n",
- "I1=100*Ib\n",
- "R1=Vi/I1\n",
- "R1=18*10**3#use standard value\n",
- "R2=Acl*R1\n",
- "R4=R1\n",
- "R3=R1/Acl\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 1.80 kohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.11, Page No 619"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vi=10*10**-3\n",
- "Vn=1.0\n",
- "R1=33.0*10**3\n",
- "R2=300.0\n",
- "R5=15.0*10**3\n",
- "R4=15.0*10**3\n",
- "Vi2=-10.0*10**-3\n",
- "R3=R1\n",
- "R6=15.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R7=R6\n",
- "Acl=((2*R1+R2)/R2)*(R5/R4)\n",
- "print(\"at junction of R1 and R2\")\n",
- "Vb=Vi+Vn\n",
- "print(\"at junction of R2 and R3\")\n",
- "Vc=Vi2+Vn\n",
- "print(\" current through R2\")\n",
- "I2=(Vb-Vc)/R2\n",
- "print(\"at the output of A1\")\n",
- "Va=Vb+(I2*R1)\n",
- "print(\"at output of A2\")\n",
- "Vd=Vc-(I2*R3)\n",
- "print(\"at junction of R6 and R7\")\n",
- "Vf=Vd*(R7/(R6+R7))\n",
- "print(\"at junction of R4 and R5\")\n",
- "Ve=Vf\n",
- "print(\"current through R4\")\n",
- "I4=(Va-Ve)/R4\n",
- "\n",
- "#Results\n",
- "print(\"at output of A3\")\n",
- "Vg=Ve-(I4*R5)\n",
- "print('The value of Vg= %.2f kohm ' %(Vg))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "at junction of R1 and R2\n",
- "at junction of R2 and R3\n",
- " current through R2\n",
- "at the output of A1\n",
- "at output of A2\n",
- "at junction of R6 and R7\n",
- "at junction of R4 and R5\n",
- "current through R4\n",
- "at output of A3\n",
- "The value of Vg= -4.42 kohm \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.12, Page No 623"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=15.0\n",
- "Vee=-15.0\n",
- "Av=200000.0\n",
- "SR=0.5/10**-6\n",
- "Vo=14.0\n",
- "\n",
- "#Calculations\n",
- "V=(Vcc-1)-(Vee+1)\n",
- "Vi=Vo/Av\n",
- "print(\"rise time of output is \")\n",
- "t=(V/SR)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"rise time of output is %d ms \" %t)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "rise time of output is \n",
- "rise time of output is 56 ms \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.13, Page No 627"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Ib=500.0*10**-9\n",
- "UTP=5.0\n",
- "Vcc=15.0\n",
- "\n",
- "#Calculations\n",
- "I1=100.0*Ib\n",
- "R2=UTP/I1\n",
- "R1=((Vcc-1)-5)/I1\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 180.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.14, Page No 630"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=15.0\n",
- "Vsat=Vcc\n",
- "R2=150.0*10**3\n",
- "Vf=0.7\n",
- "R1=27.0*10**3\n",
- "R3=120.0*10**3\n",
- "\n",
- "#Calculations\n",
- "I2=(Vsat-Vf)/R2\n",
- "UTP=I2*R1\n",
- "\n",
- "#Results\n",
- "print(\" LTP calculation including Vf\")\n",
- "I3=(Vsat-Vf)/R3\n",
- "LTP=-I3*R1\n",
- "print('The value of LTP= %.2f kohm ' %(LTP))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " LTP calculation including Vf\n",
- "The value of LTP= -3.22 kohm \n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter14_1.ipynb b/Electronic_Devices_and_Circuits/Chapter14_1.ipynb deleted file mode 100755 index 90767c65..00000000 --- a/Electronic_Devices_and_Circuits/Chapter14_1.ipynb +++ /dev/null @@ -1,662 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 14 : Ic operational Amplifier and basic Op amp circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.1, Page No 597"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=0.7\n",
- "Ib=500.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "R1=Vbe/(10.0*Ib)\n",
- "R1=120.0*10**3#use standard value\n",
- "R2=R1\n",
- "I2=100.0*Ib\n",
- "Vr1=15.0\n",
- "Vr2=Vr1\n",
- "R1=Vr1/I2\n",
- "R1=270.0*10**3#use satndard value\n",
- "R2=R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 135.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.2, Page No 599"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R2=1.0*10**6\n",
- "Vb=3.0\n",
- "Vo=3.0\n",
- "Vee=9.0\n",
- "\n",
- "#Calculations\n",
- "Vr2=Vb-(-Vee)\n",
- "Vr1=Vee-Vb\n",
- "I2=Vr2/R2\n",
- "R1=Vr1/I2\n",
- "R3=0\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 500.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.3 Page No 601"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Av=200000.0\n",
- "ri=2.0*10**6\n",
- "ro=75.0\n",
- "Vo=1.0\n",
- "B=1.0\n",
- "\n",
- "#Calculations\n",
- "Vd=Vo/Av\n",
- "Zi=(1+Av*B)*ri\n",
- "Zo=ro/(1+Av*B)\n",
- "\n",
- "#Results\n",
- "print('The value of Zo= %.2f X 10^-3 kohm ' %(Zo*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Zo= 0.37 X 10^-3 kohm \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.4, Page No 603"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=70.0\n",
- "Rl=4.0*10**3\n",
- "Ib=500.0*10**-9\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "R1=Vbe/(10*Ib)\n",
- "R1=120*10**3#use standard value\n",
- "R2=R1\n",
- "print(\" desire value of capacitor is C=1/2*3.14*f*R\")\n",
- "C2=1/(2*3.14*f*Rl)\n",
- "C1=1/(2*3.14*f*(R1/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C1= %.2f mF ' %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " desire value of capacitor is C=1/2*3.14*f*R\n",
- "The value of C1= 0.19 mF \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.5 Page No 605"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=500.0*10**-9\n",
- "Vi=50.0*10**-3\n",
- "Vo=2.0\n",
- "\n",
- "#Calculations\n",
- "I2=100.0*Ib\n",
- "R3=Vi/I2\n",
- "R2=(Vo/I2)-R3\n",
- "R1=(R2*R3)/(R2+R3)\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 0.97 kohm \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.6 Page No 606"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Av=200000.0\n",
- "ri=2.0*10**6\n",
- "ro=75.0\n",
- "R3=1.0*10**3\n",
- "R2=39*10**3\n",
- "\n",
- "#Calculations\n",
- "B=R3/(R2+R3)\n",
- "Zi=(1+Av*B)*ri\n",
- "\n",
- "#Results\n",
- "print(\" typical input impedance for non-inverting amplifier is %.2f ohm \" %Zi)\n",
- "Zo=ro/(1+Av*B)\n",
- "print('The value of Zo= %.2f kohm ' %(Zo*10))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " typical input impedance for non-inverting amplifier is 10002000000.00 ohm \n",
- "The value of Zo= 0.15 kohm \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.7, Page No 607"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R2=50.0*10**3\n",
- "R3=2.2*10**3\n",
- "C2=8.2*10**-6\n",
- "Rl=600.0\n",
- "\n",
- "#Calculations\n",
- "print(\"voltage gain \")\n",
- "Acl=(R3+R2)/R3\n",
- "\n",
- "#Results\n",
- "print(\"lower cuttoff frequency \")\n",
- "f=1/(2*3.14*C2*Rl)\n",
- "print('The value of f= %.2f kohm ' %(f))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain \n",
- "lower cuttoff frequency \n",
- "The value of f= 32.36 kohm \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.8 Page No 610"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Acl=144.0\n",
- "Vi=20.0*10**-3\n",
- "Ib=500.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "I1=100.0*Ib\n",
- "R1=Vi/I1\n",
- "R1=390.0 #use standard value\n",
- "R2=Acl*R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 387.31 kohm \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.9 Page No 612"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Acl=3.0\n",
- "R4=1.0*10**6\n",
- "Vi=1.0\n",
- "\n",
- "#Calculations\n",
- "R1=R4/Acl\n",
- "R1=330.0*10**3#use standard value \n",
- "R2=R1\n",
- "R3=R1\n",
- "I1=Vi/R1\n",
- "I2=I1\n",
- "I3=I1\n",
- "I4=I1+I2+I3\n",
- "Vo=-I4*R4\n",
- "\n",
- "#Results\n",
- "print('The value of Vo= %.2f v ' %(Vo))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vo= -9.09 v \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.10 Page No 615"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=500.0*10**-9\n",
- "Vi=1.0\n",
- "Acl=10.0\n",
- "\n",
- "#Calculations\n",
- "I1=100*Ib\n",
- "R1=Vi/I1\n",
- "R1=18*10**3#use standard value\n",
- "R2=Acl*R1\n",
- "R4=R1\n",
- "R3=R1/Acl\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 1.80 kohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.11, Page No 619"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vi=10*10**-3\n",
- "Vn=1.0\n",
- "R1=33.0*10**3\n",
- "R2=300.0\n",
- "R5=15.0*10**3\n",
- "R4=15.0*10**3\n",
- "Vi2=-10.0*10**-3\n",
- "R3=R1\n",
- "R6=15.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R7=R6\n",
- "Acl=((2*R1+R2)/R2)*(R5/R4)\n",
- "print(\"at junction of R1 and R2\")\n",
- "Vb=Vi+Vn\n",
- "print(\"at junction of R2 and R3\")\n",
- "Vc=Vi2+Vn\n",
- "print(\" current through R2\")\n",
- "I2=(Vb-Vc)/R2\n",
- "print(\"at the output of A1\")\n",
- "Va=Vb+(I2*R1)\n",
- "print(\"at output of A2\")\n",
- "Vd=Vc-(I2*R3)\n",
- "print(\"at junction of R6 and R7\")\n",
- "Vf=Vd*(R7/(R6+R7))\n",
- "print(\"at junction of R4 and R5\")\n",
- "Ve=Vf\n",
- "print(\"current through R4\")\n",
- "I4=(Va-Ve)/R4\n",
- "\n",
- "#Results\n",
- "print(\"at output of A3\")\n",
- "Vg=Ve-(I4*R5)\n",
- "print('The value of Vg= %.2f kohm ' %(Vg))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "at junction of R1 and R2\n",
- "at junction of R2 and R3\n",
- " current through R2\n",
- "at the output of A1\n",
- "at output of A2\n",
- "at junction of R6 and R7\n",
- "at junction of R4 and R5\n",
- "current through R4\n",
- "at output of A3\n",
- "The value of Vg= -4.42 kohm \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.12, Page No 623"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=15.0\n",
- "Vee=-15.0\n",
- "Av=200000.0\n",
- "SR=0.5/10**-6\n",
- "Vo=14.0\n",
- "\n",
- "#Calculations\n",
- "V=(Vcc-1)-(Vee+1)\n",
- "Vi=Vo/Av\n",
- "print(\"rise time of output is \")\n",
- "t=(V/SR)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"rise time of output is %d ms \" %t)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "rise time of output is \n",
- "rise time of output is 56 ms \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.13, Page No 627"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Ib=500.0*10**-9\n",
- "UTP=5.0\n",
- "Vcc=15.0\n",
- "\n",
- "#Calculations\n",
- "I1=100.0*Ib\n",
- "R2=UTP/I1\n",
- "R1=((Vcc-1)-5)/I1\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 180.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.14, Page No 630"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=15.0\n",
- "Vsat=Vcc\n",
- "R2=150.0*10**3\n",
- "Vf=0.7\n",
- "R1=27.0*10**3\n",
- "R3=120.0*10**3\n",
- "\n",
- "#Calculations\n",
- "I2=(Vsat-Vf)/R2\n",
- "UTP=I2*R1\n",
- "\n",
- "#Results\n",
- "print(\" LTP calculation including Vf\")\n",
- "I3=(Vsat-Vf)/R3\n",
- "LTP=-I3*R1\n",
- "print('The value of LTP= %.2f kohm ' %(LTP))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " LTP calculation including Vf\n",
- "The value of LTP= -3.22 kohm \n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter14_2.ipynb b/Electronic_Devices_and_Circuits/Chapter14_2.ipynb deleted file mode 100755 index 90767c65..00000000 --- a/Electronic_Devices_and_Circuits/Chapter14_2.ipynb +++ /dev/null @@ -1,662 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 14 : Ic operational Amplifier and basic Op amp circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.1, Page No 597"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=0.7\n",
- "Ib=500.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "R1=Vbe/(10.0*Ib)\n",
- "R1=120.0*10**3#use standard value\n",
- "R2=R1\n",
- "I2=100.0*Ib\n",
- "Vr1=15.0\n",
- "Vr2=Vr1\n",
- "R1=Vr1/I2\n",
- "R1=270.0*10**3#use satndard value\n",
- "R2=R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 135.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.2, Page No 599"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R2=1.0*10**6\n",
- "Vb=3.0\n",
- "Vo=3.0\n",
- "Vee=9.0\n",
- "\n",
- "#Calculations\n",
- "Vr2=Vb-(-Vee)\n",
- "Vr1=Vee-Vb\n",
- "I2=Vr2/R2\n",
- "R1=Vr1/I2\n",
- "R3=0\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 500.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.3 Page No 601"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Av=200000.0\n",
- "ri=2.0*10**6\n",
- "ro=75.0\n",
- "Vo=1.0\n",
- "B=1.0\n",
- "\n",
- "#Calculations\n",
- "Vd=Vo/Av\n",
- "Zi=(1+Av*B)*ri\n",
- "Zo=ro/(1+Av*B)\n",
- "\n",
- "#Results\n",
- "print('The value of Zo= %.2f X 10^-3 kohm ' %(Zo*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Zo= 0.37 X 10^-3 kohm \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.4, Page No 603"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=70.0\n",
- "Rl=4.0*10**3\n",
- "Ib=500.0*10**-9\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "R1=Vbe/(10*Ib)\n",
- "R1=120*10**3#use standard value\n",
- "R2=R1\n",
- "print(\" desire value of capacitor is C=1/2*3.14*f*R\")\n",
- "C2=1/(2*3.14*f*Rl)\n",
- "C1=1/(2*3.14*f*(R1/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C1= %.2f mF ' %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " desire value of capacitor is C=1/2*3.14*f*R\n",
- "The value of C1= 0.19 mF \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.5 Page No 605"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=500.0*10**-9\n",
- "Vi=50.0*10**-3\n",
- "Vo=2.0\n",
- "\n",
- "#Calculations\n",
- "I2=100.0*Ib\n",
- "R3=Vi/I2\n",
- "R2=(Vo/I2)-R3\n",
- "R1=(R2*R3)/(R2+R3)\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 0.97 kohm \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.6 Page No 606"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Av=200000.0\n",
- "ri=2.0*10**6\n",
- "ro=75.0\n",
- "R3=1.0*10**3\n",
- "R2=39*10**3\n",
- "\n",
- "#Calculations\n",
- "B=R3/(R2+R3)\n",
- "Zi=(1+Av*B)*ri\n",
- "\n",
- "#Results\n",
- "print(\" typical input impedance for non-inverting amplifier is %.2f ohm \" %Zi)\n",
- "Zo=ro/(1+Av*B)\n",
- "print('The value of Zo= %.2f kohm ' %(Zo*10))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " typical input impedance for non-inverting amplifier is 10002000000.00 ohm \n",
- "The value of Zo= 0.15 kohm \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.7, Page No 607"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R2=50.0*10**3\n",
- "R3=2.2*10**3\n",
- "C2=8.2*10**-6\n",
- "Rl=600.0\n",
- "\n",
- "#Calculations\n",
- "print(\"voltage gain \")\n",
- "Acl=(R3+R2)/R3\n",
- "\n",
- "#Results\n",
- "print(\"lower cuttoff frequency \")\n",
- "f=1/(2*3.14*C2*Rl)\n",
- "print('The value of f= %.2f kohm ' %(f))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain \n",
- "lower cuttoff frequency \n",
- "The value of f= 32.36 kohm \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.8 Page No 610"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Acl=144.0\n",
- "Vi=20.0*10**-3\n",
- "Ib=500.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "I1=100.0*Ib\n",
- "R1=Vi/I1\n",
- "R1=390.0 #use standard value\n",
- "R2=Acl*R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 387.31 kohm \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.9 Page No 612"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Acl=3.0\n",
- "R4=1.0*10**6\n",
- "Vi=1.0\n",
- "\n",
- "#Calculations\n",
- "R1=R4/Acl\n",
- "R1=330.0*10**3#use standard value \n",
- "R2=R1\n",
- "R3=R1\n",
- "I1=Vi/R1\n",
- "I2=I1\n",
- "I3=I1\n",
- "I4=I1+I2+I3\n",
- "Vo=-I4*R4\n",
- "\n",
- "#Results\n",
- "print('The value of Vo= %.2f v ' %(Vo))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vo= -9.09 v \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.10 Page No 615"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=500.0*10**-9\n",
- "Vi=1.0\n",
- "Acl=10.0\n",
- "\n",
- "#Calculations\n",
- "I1=100*Ib\n",
- "R1=Vi/I1\n",
- "R1=18*10**3#use standard value\n",
- "R2=Acl*R1\n",
- "R4=R1\n",
- "R3=R1/Acl\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 1.80 kohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.11, Page No 619"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vi=10*10**-3\n",
- "Vn=1.0\n",
- "R1=33.0*10**3\n",
- "R2=300.0\n",
- "R5=15.0*10**3\n",
- "R4=15.0*10**3\n",
- "Vi2=-10.0*10**-3\n",
- "R3=R1\n",
- "R6=15.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R7=R6\n",
- "Acl=((2*R1+R2)/R2)*(R5/R4)\n",
- "print(\"at junction of R1 and R2\")\n",
- "Vb=Vi+Vn\n",
- "print(\"at junction of R2 and R3\")\n",
- "Vc=Vi2+Vn\n",
- "print(\" current through R2\")\n",
- "I2=(Vb-Vc)/R2\n",
- "print(\"at the output of A1\")\n",
- "Va=Vb+(I2*R1)\n",
- "print(\"at output of A2\")\n",
- "Vd=Vc-(I2*R3)\n",
- "print(\"at junction of R6 and R7\")\n",
- "Vf=Vd*(R7/(R6+R7))\n",
- "print(\"at junction of R4 and R5\")\n",
- "Ve=Vf\n",
- "print(\"current through R4\")\n",
- "I4=(Va-Ve)/R4\n",
- "\n",
- "#Results\n",
- "print(\"at output of A3\")\n",
- "Vg=Ve-(I4*R5)\n",
- "print('The value of Vg= %.2f kohm ' %(Vg))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "at junction of R1 and R2\n",
- "at junction of R2 and R3\n",
- " current through R2\n",
- "at the output of A1\n",
- "at output of A2\n",
- "at junction of R6 and R7\n",
- "at junction of R4 and R5\n",
- "current through R4\n",
- "at output of A3\n",
- "The value of Vg= -4.42 kohm \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.12, Page No 623"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=15.0\n",
- "Vee=-15.0\n",
- "Av=200000.0\n",
- "SR=0.5/10**-6\n",
- "Vo=14.0\n",
- "\n",
- "#Calculations\n",
- "V=(Vcc-1)-(Vee+1)\n",
- "Vi=Vo/Av\n",
- "print(\"rise time of output is \")\n",
- "t=(V/SR)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"rise time of output is %d ms \" %t)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "rise time of output is \n",
- "rise time of output is 56 ms \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.13, Page No 627"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Ib=500.0*10**-9\n",
- "UTP=5.0\n",
- "Vcc=15.0\n",
- "\n",
- "#Calculations\n",
- "I1=100.0*Ib\n",
- "R2=UTP/I1\n",
- "R1=((Vcc-1)-5)/I1\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 180.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.14, Page No 630"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=15.0\n",
- "Vsat=Vcc\n",
- "R2=150.0*10**3\n",
- "Vf=0.7\n",
- "R1=27.0*10**3\n",
- "R3=120.0*10**3\n",
- "\n",
- "#Calculations\n",
- "I2=(Vsat-Vf)/R2\n",
- "UTP=I2*R1\n",
- "\n",
- "#Results\n",
- "print(\" LTP calculation including Vf\")\n",
- "I3=(Vsat-Vf)/R3\n",
- "LTP=-I3*R1\n",
- "print('The value of LTP= %.2f kohm ' %(LTP))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " LTP calculation including Vf\n",
- "The value of LTP= -3.22 kohm \n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter15.ipynb b/Electronic_Devices_and_Circuits/Chapter15.ipynb deleted file mode 100755 index db5e05e2..00000000 --- a/Electronic_Devices_and_Circuits/Chapter15.ipynb +++ /dev/null @@ -1,282 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 15 : Operational amplifier frequency\n",
- "Response and compensation"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.2, Page No 648"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R2=1.0*10**6\n",
- "Acl=4.5\n",
- "\n",
- "#Calculations\n",
- "R1=R2/Acl\n",
- "R1=220*10**3#use standard value\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "Cf=((R1*30*10**-12)/(R1+R2))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" suitable value of capacitor is %.2fpF \" %Cf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable value of capacitor is 5.41pF \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.3, Page No 649"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=35.0*10**3\n",
- "Rf=68.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Cf=(1.0/(2*3.14*f*Rf))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" suitable miller effect capacitor is %.2f pF \" %Cf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable miller effect capacitor is 66.91 pF \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.5 Page No 652"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Acl=100.0\n",
- "Av=10.0\n",
- "print(\" for Cf=30pF\")\n",
- "GBW=800.0*10**3\n",
- "\n",
- "#Calculations\n",
- "F2=GBW/Acl\n",
- "print(\" for Cf=3pF\")\n",
- "GBW=(800*10**3)*Av\n",
- "f2=GBW/Acl\n",
- "\n",
- "#Results\n",
- "print(\" The value of f2 is %.2f pF \" %(f2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Cf=30pF\n",
- " for Cf=3pF\n",
- " The value of f2 is 80.00 pF \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.6, Page No 654"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vip=1.0\n",
- "R2=39.0*10**3\n",
- "R3=4.7*10**3\n",
- "SR=250.0/10**-6\n",
- "f=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" for the AD843\")\n",
- "Vop=((R2+R3)/R3)*Vip\n",
- "fp=SR/(2*3.14*Vop)\n",
- "print(\"full power bandwidth is %dHz \" %fp)\n",
- "print(\" for a 741\")\n",
- "SR=0.5/10**-6\n",
- "Vp=SR/(2*3.14*f)\n",
- "\n",
- "#Results\n",
- "print(\" maximum peak output voltage is %3.2fV \" %Vp)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for the AD843\n",
- "full power bandwidth is 4281508Hz \n",
- " for a 741\n",
- " maximum peak output voltage is 0.80V \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.7 Page No 656"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "R1=1.0*10**3\n",
- "R2=10.0*10**3\n",
- "f=800.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" stray capacitance\")\n",
- "Cs=1/(2*3.14*f*10*(((rs+R1)*R2)/(rs+R1+R2)))\n",
- "print(\"compensation capacitor\")\n",
- "C2=((Cs*(rs+R1))/R2)*10**12\n",
- "\n",
- "#Results\n",
- "print(\"compensation capacitor is %.2fpF \" %C2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " stray capacitance\n",
- "compensation capacitor\n",
- "compensation capacitor is 2.31pF \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.8 Page No 659"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "ro=25.0\n",
- "f=2.0*10**6\n",
- "R2=10.0*10**3\n",
- "Rx=25.0\n",
- "\n",
- "#Calculations\n",
- "Cl=(1.0/(2.0*3.14*f*(10*ro)))*10**+12\n",
- "print(\" load capacitance is %3.2fpF \" %Cl)\n",
- "Cl=0.1*10**-6\n",
- "C2=((Cl*(ro+Rx))/R2)*10**12\n",
- "\n",
- "#Results\n",
- "print(\" compensation capacitance is %.2f pF \" %C2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " load capacitance is 318.47pF \n",
- " compensation capacitance is 500.00 pF \n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter15_1.ipynb b/Electronic_Devices_and_Circuits/Chapter15_1.ipynb deleted file mode 100755 index db5e05e2..00000000 --- a/Electronic_Devices_and_Circuits/Chapter15_1.ipynb +++ /dev/null @@ -1,282 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 15 : Operational amplifier frequency\n",
- "Response and compensation"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.2, Page No 648"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R2=1.0*10**6\n",
- "Acl=4.5\n",
- "\n",
- "#Calculations\n",
- "R1=R2/Acl\n",
- "R1=220*10**3#use standard value\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "Cf=((R1*30*10**-12)/(R1+R2))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" suitable value of capacitor is %.2fpF \" %Cf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable value of capacitor is 5.41pF \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.3, Page No 649"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=35.0*10**3\n",
- "Rf=68.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Cf=(1.0/(2*3.14*f*Rf))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" suitable miller effect capacitor is %.2f pF \" %Cf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable miller effect capacitor is 66.91 pF \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.5 Page No 652"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Acl=100.0\n",
- "Av=10.0\n",
- "print(\" for Cf=30pF\")\n",
- "GBW=800.0*10**3\n",
- "\n",
- "#Calculations\n",
- "F2=GBW/Acl\n",
- "print(\" for Cf=3pF\")\n",
- "GBW=(800*10**3)*Av\n",
- "f2=GBW/Acl\n",
- "\n",
- "#Results\n",
- "print(\" The value of f2 is %.2f pF \" %(f2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Cf=30pF\n",
- " for Cf=3pF\n",
- " The value of f2 is 80.00 pF \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.6, Page No 654"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vip=1.0\n",
- "R2=39.0*10**3\n",
- "R3=4.7*10**3\n",
- "SR=250.0/10**-6\n",
- "f=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" for the AD843\")\n",
- "Vop=((R2+R3)/R3)*Vip\n",
- "fp=SR/(2*3.14*Vop)\n",
- "print(\"full power bandwidth is %dHz \" %fp)\n",
- "print(\" for a 741\")\n",
- "SR=0.5/10**-6\n",
- "Vp=SR/(2*3.14*f)\n",
- "\n",
- "#Results\n",
- "print(\" maximum peak output voltage is %3.2fV \" %Vp)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for the AD843\n",
- "full power bandwidth is 4281508Hz \n",
- " for a 741\n",
- " maximum peak output voltage is 0.80V \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.7 Page No 656"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "R1=1.0*10**3\n",
- "R2=10.0*10**3\n",
- "f=800.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" stray capacitance\")\n",
- "Cs=1/(2*3.14*f*10*(((rs+R1)*R2)/(rs+R1+R2)))\n",
- "print(\"compensation capacitor\")\n",
- "C2=((Cs*(rs+R1))/R2)*10**12\n",
- "\n",
- "#Results\n",
- "print(\"compensation capacitor is %.2fpF \" %C2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " stray capacitance\n",
- "compensation capacitor\n",
- "compensation capacitor is 2.31pF \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.8 Page No 659"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "ro=25.0\n",
- "f=2.0*10**6\n",
- "R2=10.0*10**3\n",
- "Rx=25.0\n",
- "\n",
- "#Calculations\n",
- "Cl=(1.0/(2.0*3.14*f*(10*ro)))*10**+12\n",
- "print(\" load capacitance is %3.2fpF \" %Cl)\n",
- "Cl=0.1*10**-6\n",
- "C2=((Cl*(ro+Rx))/R2)*10**12\n",
- "\n",
- "#Results\n",
- "print(\" compensation capacitance is %.2f pF \" %C2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " load capacitance is 318.47pF \n",
- " compensation capacitance is 500.00 pF \n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter15_2.ipynb b/Electronic_Devices_and_Circuits/Chapter15_2.ipynb deleted file mode 100755 index db5e05e2..00000000 --- a/Electronic_Devices_and_Circuits/Chapter15_2.ipynb +++ /dev/null @@ -1,282 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 15 : Operational amplifier frequency\n",
- "Response and compensation"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.2, Page No 648"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R2=1.0*10**6\n",
- "Acl=4.5\n",
- "\n",
- "#Calculations\n",
- "R1=R2/Acl\n",
- "R1=220*10**3#use standard value\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "Cf=((R1*30*10**-12)/(R1+R2))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" suitable value of capacitor is %.2fpF \" %Cf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable value of capacitor is 5.41pF \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.3, Page No 649"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=35.0*10**3\n",
- "Rf=68.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Cf=(1.0/(2*3.14*f*Rf))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" suitable miller effect capacitor is %.2f pF \" %Cf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable miller effect capacitor is 66.91 pF \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.5 Page No 652"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Acl=100.0\n",
- "Av=10.0\n",
- "print(\" for Cf=30pF\")\n",
- "GBW=800.0*10**3\n",
- "\n",
- "#Calculations\n",
- "F2=GBW/Acl\n",
- "print(\" for Cf=3pF\")\n",
- "GBW=(800*10**3)*Av\n",
- "f2=GBW/Acl\n",
- "\n",
- "#Results\n",
- "print(\" The value of f2 is %.2f pF \" %(f2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Cf=30pF\n",
- " for Cf=3pF\n",
- " The value of f2 is 80.00 pF \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.6, Page No 654"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vip=1.0\n",
- "R2=39.0*10**3\n",
- "R3=4.7*10**3\n",
- "SR=250.0/10**-6\n",
- "f=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" for the AD843\")\n",
- "Vop=((R2+R3)/R3)*Vip\n",
- "fp=SR/(2*3.14*Vop)\n",
- "print(\"full power bandwidth is %dHz \" %fp)\n",
- "print(\" for a 741\")\n",
- "SR=0.5/10**-6\n",
- "Vp=SR/(2*3.14*f)\n",
- "\n",
- "#Results\n",
- "print(\" maximum peak output voltage is %3.2fV \" %Vp)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for the AD843\n",
- "full power bandwidth is 4281508Hz \n",
- " for a 741\n",
- " maximum peak output voltage is 0.80V \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.7 Page No 656"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "R1=1.0*10**3\n",
- "R2=10.0*10**3\n",
- "f=800.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" stray capacitance\")\n",
- "Cs=1/(2*3.14*f*10*(((rs+R1)*R2)/(rs+R1+R2)))\n",
- "print(\"compensation capacitor\")\n",
- "C2=((Cs*(rs+R1))/R2)*10**12\n",
- "\n",
- "#Results\n",
- "print(\"compensation capacitor is %.2fpF \" %C2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " stray capacitance\n",
- "compensation capacitor\n",
- "compensation capacitor is 2.31pF \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.8 Page No 659"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "ro=25.0\n",
- "f=2.0*10**6\n",
- "R2=10.0*10**3\n",
- "Rx=25.0\n",
- "\n",
- "#Calculations\n",
- "Cl=(1.0/(2.0*3.14*f*(10*ro)))*10**+12\n",
- "print(\" load capacitance is %3.2fpF \" %Cl)\n",
- "Cl=0.1*10**-6\n",
- "C2=((Cl*(ro+Rx))/R2)*10**12\n",
- "\n",
- "#Results\n",
- "print(\" compensation capacitance is %.2f pF \" %C2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " load capacitance is 318.47pF \n",
- " compensation capacitance is 500.00 pF \n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter16.ipynb b/Electronic_Devices_and_Circuits/Chapter16.ipynb deleted file mode 100755 index 9d8b3b5f..00000000 --- a/Electronic_Devices_and_Circuits/Chapter16.ipynb +++ /dev/null @@ -1,581 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 16 : Signal generators"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.1, Page No 668"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=10.0\n",
- "Ib=500.0*10**-9\n",
- "Acl=29.0\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" phase shift oscillator\")\n",
- "I1=100*Ib\n",
- "vo=Vcc-1\n",
- "vi=vo/Acl\n",
- "R1=vi/I1\n",
- "R1=5.6*10**3#use standard value 5.6Kohm\n",
- "R2=Acl*R1\n",
- "R2=180*10**3#use satndard value 180Kohm to give Acl>180\n",
- "R3=R2R=R1\n",
- "C=1.0/(2*3.14*R3*f*math.sqrt(6))\n",
- "\n",
- "#Results\n",
- "print(\"The value of C = %.2f \" %(C*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " phase shift oscillator\n",
- "The value of C = 11.61 \n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.2, Page No 672"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=40.0*10**3\n",
- "L=100.0*10**-3\n",
- "vp=8.0\n",
- "\n",
- "#Calculations\n",
- "print(\"colpitts oscillator\")\n",
- "Ct=1/(4*3.14*3.14*(f**2)*L)\n",
- "C1=10*Ct\n",
- "C2=1/((1/Ct)-(1/C1))\n",
- "C2=180*10**-12#use standard value\n",
- "Xc2=1/(2*3.14*f*C2)\n",
- "Xc1=1/(2*3.14*f*C1)\n",
- "R1=10*Xc1\n",
- "R1=27*10**3#use standard value\n",
- "Acl=C1/C2\n",
- "R2=Acl*R1\n",
- "R2=270*10**3#use stabdard value\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*vp\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "colpitts oscillator\n",
- "The value of SR is 2009.60 \n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.3 Page No 678"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "vo=8.0\n",
- "f=100.0*10**3\n",
- "print(\" hartley oscillator\")\n",
- "Vcc=vo+1\n",
- "Xl2=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "L2=Xl2/(2*3.14*f)\n",
- "L2=1.5*10**-3#use standard value\n",
- "L1=L2/10.0\n",
- "Lt=L1+L2#(assuming M=0)\n",
- "C1=1/(4*(3.14**2)*(f**2)*Lt)\n",
- "C1=1500*10**-12#use 1500pF with aadditional parallel capacitance if necessary\n",
- "#C1>>stray capacitance\n",
- "Xl1=2*3.14*f*L1#R1>>Xl1\n",
- "R1=1*10**3\n",
- "Acl=L2/L1\n",
- "R2=Acl*R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "print(\"full power bandwidth \")\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*vo\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " hartley oscillator\n",
- "full power bandwidth \n",
- "The value of SR is 5024.00 \n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.4, Page No 680"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0*10**3\n",
- "Vo=9.0\n",
- "Acl=3.0\n",
- "\n",
- "#Calculations\n",
- "print(\" design of wein bridge oscillator\")\n",
- "Vcc=Vo+1\n",
- "C1=1000.0*10**-12#standard value\n",
- "C2=C1\n",
- "R1=1.0/(2*3.14*f*C1)\n",
- "R2=R1\n",
- "R4=R2\n",
- "R3=2*R4\n",
- "R3=3.3*10**3#use standard value\n",
- "print(\" minimum full power bandwidth\")\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*Vo\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " design of wein bridge oscillator\n",
- " minimum full power bandwidth\n",
- "The value of SR is 5652.00 \n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.5 Page No 683"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=5.0*10**3\n",
- "vo=5.0\n",
- "I1=1.0*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "print(\"phase shift oscillator\")\n",
- "R1=(vo/29.0)/I1\n",
- "R1=150#use standard value\n",
- "R2=29*R1\n",
- "R4=(2*Vf)/I1\n",
- "R4=1.5*10**3#use 1.5kohm standard value\n",
- "R5=R2-R4\n",
- "R6=.4*R5\n",
- "R7=.8*R5\n",
- "R=R1\n",
- "C=1.0/(2*3.14*R*f*math.sqrt(6))\n",
- "\n",
- "#Results\n",
- "print(\"The value of C is %.2f mF\" %(C*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "phase shift oscillator\n",
- "The value of C is 86.68 mF\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.6 Page No 686"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "rds=600.0\n",
- "Vgs=1.0\n",
- "Vd1=0.7\n",
- "f=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"wien bridge ocillator\")\n",
- "R4=560.0\n",
- "R3=2*((R4*rds)/(R4+rds))\n",
- "I5=200.0*10**-6\n",
- "Vo=6\n",
- "R6=Vgs/I5\n",
- "R5=(Vo-(Vgs+Vd1))/I5\n",
- "print(\" C4 discharge voltage \")\n",
- "Vc=.1*Vgs\n",
- "print(\"C4 discharge time\")\n",
- "T=1/f\n",
- "Ic=I5\n",
- "C4=(Ic*T)/Vc\n",
- "Xc3=rds/10#at oscillating frequency\n",
- "C3=1/(2*3.14*f*Xc3)\n",
- "\n",
- "#Results\n",
- "print(\"The value of C3 is %.2f mF\" %(C3*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "wien bridge ocillator\n",
- " C4 discharge voltage \n",
- "C4 discharge time\n",
- "The value of C3 is 26.54 mF\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.7, Page No 689"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=14.0\n",
- "Vr3=.5\n",
- "Ib=500.0*10**-9\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"square wave generator\")\n",
- "Vcc=Vo+1\n",
- "UTP=Vr3\n",
- "LTP=UTP\n",
- "I2=100*Ib\n",
- "R3=Vr3/I2\n",
- "R2=(Vo-Vr3)/I2\n",
- "t=1/(2*f)\n",
- "V=UTP-(-LTP)\n",
- "C1=.1*10**-6\n",
- "I1=(C1*V)/t\n",
- "R1=Vo/I1\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %.2f kohm\" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "square wave generator\n",
- "The value of R1 is 70.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.8 Page No 694"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R1=2.2*10**3\n",
- "R2=2.7*10**3\n",
- "C2=.5*10**-6\n",
- "Vcc=15.0\n",
- "\n",
- "#Calculations\n",
- "t1=.693*C2*(R1+R2)\n",
- "t2=.693*C2*R2\n",
- "T=t1+t2\n",
- "f=1/T\n",
- "Ic1=(Vcc/3)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ic1 is %.2f mA\" %(Ic1*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ic1 is 1.02 mA\n"
- ]
- }
- ],
- "prompt_number": 35
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.10 Page No 699"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=9.0\n",
- "Vo=3\n",
- "I1=1.0*10**-3\n",
- "f=500.0\n",
- "UTP=3.0\n",
- "\n",
- "#Calculations\n",
- "print(\"design the triangular wave\")\n",
- "Vi=Vcc-1\n",
- "V=Vo-(-Vo)\n",
- "print(\" I1>>Ibmax for op-amp\")\n",
- "R1=Vi/I1\n",
- "t=1.0/(2*f)\n",
- "C1=(I1*t)/V\n",
- "print(\"schmitt design\")\n",
- "I2=1.0*10**-3\n",
- "R2=UTP/I2\n",
- "R3=(Vcc-1)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "design the triangular wave\n",
- " I1>>Ibmax for op-amp\n",
- "schmitt design\n",
- "The value of R3 is 8.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.11 Page No 705"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0*10**3\n",
- "Rs=1.5*10**3\n",
- "R1=2.0*Rs\n",
- "\n",
- "\n",
- "#Calculations\n",
- "R1=2.7*10**3#use standard value\n",
- "R2=R1+Rs\n",
- "C1=1/(2*3.14*f*R2)\n",
- "R4=R2\n",
- "R3=2*R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3 is 8.40 kohm\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.12, Page No 705"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "fs=1.0*10**6\n",
- "Rs=700.0\n",
- "C1=1000.0*10**-12\n",
- "C2=100.0*10**-12\n",
- "R1=1.0*10**6\n",
- "R2=10.0*10**3\n",
- "Rs=700.0\n",
- "Vdd=5\n",
- "\n",
- "#Calculations\n",
- "Ct=(C1*C2)/(C1+C2)\n",
- "print(\" at resonance Xl=Xct 2*pi*f*L=1/2*pi*f*Ct\")\n",
- "L=1/(((2*3.14*f)**2)*Ct)\n",
- "ip=Vdd/(R1+R2+Rs)\n",
- "Pd=(((.707*ip)**2)*Rs)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" peak power dissipated is %.3fnW \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " at resonance Xl=Xct 2*pi*f*L=1/2*pi*f*Ct\n",
- " peak power dissipated is 8.563nW \n"
- ]
- }
- ],
- "prompt_number": 38
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter16_1.ipynb b/Electronic_Devices_and_Circuits/Chapter16_1.ipynb deleted file mode 100755 index 9d8b3b5f..00000000 --- a/Electronic_Devices_and_Circuits/Chapter16_1.ipynb +++ /dev/null @@ -1,581 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 16 : Signal generators"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.1, Page No 668"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=10.0\n",
- "Ib=500.0*10**-9\n",
- "Acl=29.0\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" phase shift oscillator\")\n",
- "I1=100*Ib\n",
- "vo=Vcc-1\n",
- "vi=vo/Acl\n",
- "R1=vi/I1\n",
- "R1=5.6*10**3#use standard value 5.6Kohm\n",
- "R2=Acl*R1\n",
- "R2=180*10**3#use satndard value 180Kohm to give Acl>180\n",
- "R3=R2R=R1\n",
- "C=1.0/(2*3.14*R3*f*math.sqrt(6))\n",
- "\n",
- "#Results\n",
- "print(\"The value of C = %.2f \" %(C*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " phase shift oscillator\n",
- "The value of C = 11.61 \n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.2, Page No 672"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=40.0*10**3\n",
- "L=100.0*10**-3\n",
- "vp=8.0\n",
- "\n",
- "#Calculations\n",
- "print(\"colpitts oscillator\")\n",
- "Ct=1/(4*3.14*3.14*(f**2)*L)\n",
- "C1=10*Ct\n",
- "C2=1/((1/Ct)-(1/C1))\n",
- "C2=180*10**-12#use standard value\n",
- "Xc2=1/(2*3.14*f*C2)\n",
- "Xc1=1/(2*3.14*f*C1)\n",
- "R1=10*Xc1\n",
- "R1=27*10**3#use standard value\n",
- "Acl=C1/C2\n",
- "R2=Acl*R1\n",
- "R2=270*10**3#use stabdard value\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*vp\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "colpitts oscillator\n",
- "The value of SR is 2009.60 \n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.3 Page No 678"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "vo=8.0\n",
- "f=100.0*10**3\n",
- "print(\" hartley oscillator\")\n",
- "Vcc=vo+1\n",
- "Xl2=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "L2=Xl2/(2*3.14*f)\n",
- "L2=1.5*10**-3#use standard value\n",
- "L1=L2/10.0\n",
- "Lt=L1+L2#(assuming M=0)\n",
- "C1=1/(4*(3.14**2)*(f**2)*Lt)\n",
- "C1=1500*10**-12#use 1500pF with aadditional parallel capacitance if necessary\n",
- "#C1>>stray capacitance\n",
- "Xl1=2*3.14*f*L1#R1>>Xl1\n",
- "R1=1*10**3\n",
- "Acl=L2/L1\n",
- "R2=Acl*R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "print(\"full power bandwidth \")\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*vo\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " hartley oscillator\n",
- "full power bandwidth \n",
- "The value of SR is 5024.00 \n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.4, Page No 680"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0*10**3\n",
- "Vo=9.0\n",
- "Acl=3.0\n",
- "\n",
- "#Calculations\n",
- "print(\" design of wein bridge oscillator\")\n",
- "Vcc=Vo+1\n",
- "C1=1000.0*10**-12#standard value\n",
- "C2=C1\n",
- "R1=1.0/(2*3.14*f*C1)\n",
- "R2=R1\n",
- "R4=R2\n",
- "R3=2*R4\n",
- "R3=3.3*10**3#use standard value\n",
- "print(\" minimum full power bandwidth\")\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*Vo\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " design of wein bridge oscillator\n",
- " minimum full power bandwidth\n",
- "The value of SR is 5652.00 \n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.5 Page No 683"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=5.0*10**3\n",
- "vo=5.0\n",
- "I1=1.0*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "print(\"phase shift oscillator\")\n",
- "R1=(vo/29.0)/I1\n",
- "R1=150#use standard value\n",
- "R2=29*R1\n",
- "R4=(2*Vf)/I1\n",
- "R4=1.5*10**3#use 1.5kohm standard value\n",
- "R5=R2-R4\n",
- "R6=.4*R5\n",
- "R7=.8*R5\n",
- "R=R1\n",
- "C=1.0/(2*3.14*R*f*math.sqrt(6))\n",
- "\n",
- "#Results\n",
- "print(\"The value of C is %.2f mF\" %(C*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "phase shift oscillator\n",
- "The value of C is 86.68 mF\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.6 Page No 686"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "rds=600.0\n",
- "Vgs=1.0\n",
- "Vd1=0.7\n",
- "f=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"wien bridge ocillator\")\n",
- "R4=560.0\n",
- "R3=2*((R4*rds)/(R4+rds))\n",
- "I5=200.0*10**-6\n",
- "Vo=6\n",
- "R6=Vgs/I5\n",
- "R5=(Vo-(Vgs+Vd1))/I5\n",
- "print(\" C4 discharge voltage \")\n",
- "Vc=.1*Vgs\n",
- "print(\"C4 discharge time\")\n",
- "T=1/f\n",
- "Ic=I5\n",
- "C4=(Ic*T)/Vc\n",
- "Xc3=rds/10#at oscillating frequency\n",
- "C3=1/(2*3.14*f*Xc3)\n",
- "\n",
- "#Results\n",
- "print(\"The value of C3 is %.2f mF\" %(C3*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "wien bridge ocillator\n",
- " C4 discharge voltage \n",
- "C4 discharge time\n",
- "The value of C3 is 26.54 mF\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.7, Page No 689"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=14.0\n",
- "Vr3=.5\n",
- "Ib=500.0*10**-9\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"square wave generator\")\n",
- "Vcc=Vo+1\n",
- "UTP=Vr3\n",
- "LTP=UTP\n",
- "I2=100*Ib\n",
- "R3=Vr3/I2\n",
- "R2=(Vo-Vr3)/I2\n",
- "t=1/(2*f)\n",
- "V=UTP-(-LTP)\n",
- "C1=.1*10**-6\n",
- "I1=(C1*V)/t\n",
- "R1=Vo/I1\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %.2f kohm\" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "square wave generator\n",
- "The value of R1 is 70.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.8 Page No 694"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R1=2.2*10**3\n",
- "R2=2.7*10**3\n",
- "C2=.5*10**-6\n",
- "Vcc=15.0\n",
- "\n",
- "#Calculations\n",
- "t1=.693*C2*(R1+R2)\n",
- "t2=.693*C2*R2\n",
- "T=t1+t2\n",
- "f=1/T\n",
- "Ic1=(Vcc/3)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ic1 is %.2f mA\" %(Ic1*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ic1 is 1.02 mA\n"
- ]
- }
- ],
- "prompt_number": 35
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.10 Page No 699"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=9.0\n",
- "Vo=3\n",
- "I1=1.0*10**-3\n",
- "f=500.0\n",
- "UTP=3.0\n",
- "\n",
- "#Calculations\n",
- "print(\"design the triangular wave\")\n",
- "Vi=Vcc-1\n",
- "V=Vo-(-Vo)\n",
- "print(\" I1>>Ibmax for op-amp\")\n",
- "R1=Vi/I1\n",
- "t=1.0/(2*f)\n",
- "C1=(I1*t)/V\n",
- "print(\"schmitt design\")\n",
- "I2=1.0*10**-3\n",
- "R2=UTP/I2\n",
- "R3=(Vcc-1)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "design the triangular wave\n",
- " I1>>Ibmax for op-amp\n",
- "schmitt design\n",
- "The value of R3 is 8.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.11 Page No 705"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0*10**3\n",
- "Rs=1.5*10**3\n",
- "R1=2.0*Rs\n",
- "\n",
- "\n",
- "#Calculations\n",
- "R1=2.7*10**3#use standard value\n",
- "R2=R1+Rs\n",
- "C1=1/(2*3.14*f*R2)\n",
- "R4=R2\n",
- "R3=2*R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3 is 8.40 kohm\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.12, Page No 705"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "fs=1.0*10**6\n",
- "Rs=700.0\n",
- "C1=1000.0*10**-12\n",
- "C2=100.0*10**-12\n",
- "R1=1.0*10**6\n",
- "R2=10.0*10**3\n",
- "Rs=700.0\n",
- "Vdd=5\n",
- "\n",
- "#Calculations\n",
- "Ct=(C1*C2)/(C1+C2)\n",
- "print(\" at resonance Xl=Xct 2*pi*f*L=1/2*pi*f*Ct\")\n",
- "L=1/(((2*3.14*f)**2)*Ct)\n",
- "ip=Vdd/(R1+R2+Rs)\n",
- "Pd=(((.707*ip)**2)*Rs)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" peak power dissipated is %.3fnW \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " at resonance Xl=Xct 2*pi*f*L=1/2*pi*f*Ct\n",
- " peak power dissipated is 8.563nW \n"
- ]
- }
- ],
- "prompt_number": 38
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter16_2.ipynb b/Electronic_Devices_and_Circuits/Chapter16_2.ipynb deleted file mode 100755 index 9d8b3b5f..00000000 --- a/Electronic_Devices_and_Circuits/Chapter16_2.ipynb +++ /dev/null @@ -1,581 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 16 : Signal generators"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.1, Page No 668"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=10.0\n",
- "Ib=500.0*10**-9\n",
- "Acl=29.0\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" phase shift oscillator\")\n",
- "I1=100*Ib\n",
- "vo=Vcc-1\n",
- "vi=vo/Acl\n",
- "R1=vi/I1\n",
- "R1=5.6*10**3#use standard value 5.6Kohm\n",
- "R2=Acl*R1\n",
- "R2=180*10**3#use satndard value 180Kohm to give Acl>180\n",
- "R3=R2R=R1\n",
- "C=1.0/(2*3.14*R3*f*math.sqrt(6))\n",
- "\n",
- "#Results\n",
- "print(\"The value of C = %.2f \" %(C*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " phase shift oscillator\n",
- "The value of C = 11.61 \n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.2, Page No 672"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=40.0*10**3\n",
- "L=100.0*10**-3\n",
- "vp=8.0\n",
- "\n",
- "#Calculations\n",
- "print(\"colpitts oscillator\")\n",
- "Ct=1/(4*3.14*3.14*(f**2)*L)\n",
- "C1=10*Ct\n",
- "C2=1/((1/Ct)-(1/C1))\n",
- "C2=180*10**-12#use standard value\n",
- "Xc2=1/(2*3.14*f*C2)\n",
- "Xc1=1/(2*3.14*f*C1)\n",
- "R1=10*Xc1\n",
- "R1=27*10**3#use standard value\n",
- "Acl=C1/C2\n",
- "R2=Acl*R1\n",
- "R2=270*10**3#use stabdard value\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*vp\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "colpitts oscillator\n",
- "The value of SR is 2009.60 \n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.3 Page No 678"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "vo=8.0\n",
- "f=100.0*10**3\n",
- "print(\" hartley oscillator\")\n",
- "Vcc=vo+1\n",
- "Xl2=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "L2=Xl2/(2*3.14*f)\n",
- "L2=1.5*10**-3#use standard value\n",
- "L1=L2/10.0\n",
- "Lt=L1+L2#(assuming M=0)\n",
- "C1=1/(4*(3.14**2)*(f**2)*Lt)\n",
- "C1=1500*10**-12#use 1500pF with aadditional parallel capacitance if necessary\n",
- "#C1>>stray capacitance\n",
- "Xl1=2*3.14*f*L1#R1>>Xl1\n",
- "R1=1*10**3\n",
- "Acl=L2/L1\n",
- "R2=Acl*R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "print(\"full power bandwidth \")\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*vo\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " hartley oscillator\n",
- "full power bandwidth \n",
- "The value of SR is 5024.00 \n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.4, Page No 680"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0*10**3\n",
- "Vo=9.0\n",
- "Acl=3.0\n",
- "\n",
- "#Calculations\n",
- "print(\" design of wein bridge oscillator\")\n",
- "Vcc=Vo+1\n",
- "C1=1000.0*10**-12#standard value\n",
- "C2=C1\n",
- "R1=1.0/(2*3.14*f*C1)\n",
- "R2=R1\n",
- "R4=R2\n",
- "R3=2*R4\n",
- "R3=3.3*10**3#use standard value\n",
- "print(\" minimum full power bandwidth\")\n",
- "f2=Acl*f\n",
- "SR=2*3.14*f*Vo\n",
- "\n",
- "#Results\n",
- "print(\"The value of SR is %.2f \" %(SR/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " design of wein bridge oscillator\n",
- " minimum full power bandwidth\n",
- "The value of SR is 5652.00 \n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.5 Page No 683"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=5.0*10**3\n",
- "vo=5.0\n",
- "I1=1.0*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "print(\"phase shift oscillator\")\n",
- "R1=(vo/29.0)/I1\n",
- "R1=150#use standard value\n",
- "R2=29*R1\n",
- "R4=(2*Vf)/I1\n",
- "R4=1.5*10**3#use 1.5kohm standard value\n",
- "R5=R2-R4\n",
- "R6=.4*R5\n",
- "R7=.8*R5\n",
- "R=R1\n",
- "C=1.0/(2*3.14*R*f*math.sqrt(6))\n",
- "\n",
- "#Results\n",
- "print(\"The value of C is %.2f mF\" %(C*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "phase shift oscillator\n",
- "The value of C is 86.68 mF\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.6 Page No 686"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "rds=600.0\n",
- "Vgs=1.0\n",
- "Vd1=0.7\n",
- "f=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"wien bridge ocillator\")\n",
- "R4=560.0\n",
- "R3=2*((R4*rds)/(R4+rds))\n",
- "I5=200.0*10**-6\n",
- "Vo=6\n",
- "R6=Vgs/I5\n",
- "R5=(Vo-(Vgs+Vd1))/I5\n",
- "print(\" C4 discharge voltage \")\n",
- "Vc=.1*Vgs\n",
- "print(\"C4 discharge time\")\n",
- "T=1/f\n",
- "Ic=I5\n",
- "C4=(Ic*T)/Vc\n",
- "Xc3=rds/10#at oscillating frequency\n",
- "C3=1/(2*3.14*f*Xc3)\n",
- "\n",
- "#Results\n",
- "print(\"The value of C3 is %.2f mF\" %(C3*10**9))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "wien bridge ocillator\n",
- " C4 discharge voltage \n",
- "C4 discharge time\n",
- "The value of C3 is 26.54 mF\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.7, Page No 689"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=14.0\n",
- "Vr3=.5\n",
- "Ib=500.0*10**-9\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"square wave generator\")\n",
- "Vcc=Vo+1\n",
- "UTP=Vr3\n",
- "LTP=UTP\n",
- "I2=100*Ib\n",
- "R3=Vr3/I2\n",
- "R2=(Vo-Vr3)/I2\n",
- "t=1/(2*f)\n",
- "V=UTP-(-LTP)\n",
- "C1=.1*10**-6\n",
- "I1=(C1*V)/t\n",
- "R1=Vo/I1\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %.2f kohm\" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "square wave generator\n",
- "The value of R1 is 70.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.8 Page No 694"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R1=2.2*10**3\n",
- "R2=2.7*10**3\n",
- "C2=.5*10**-6\n",
- "Vcc=15.0\n",
- "\n",
- "#Calculations\n",
- "t1=.693*C2*(R1+R2)\n",
- "t2=.693*C2*R2\n",
- "T=t1+t2\n",
- "f=1/T\n",
- "Ic1=(Vcc/3)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ic1 is %.2f mA\" %(Ic1*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ic1 is 1.02 mA\n"
- ]
- }
- ],
- "prompt_number": 35
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.10 Page No 699"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=9.0\n",
- "Vo=3\n",
- "I1=1.0*10**-3\n",
- "f=500.0\n",
- "UTP=3.0\n",
- "\n",
- "#Calculations\n",
- "print(\"design the triangular wave\")\n",
- "Vi=Vcc-1\n",
- "V=Vo-(-Vo)\n",
- "print(\" I1>>Ibmax for op-amp\")\n",
- "R1=Vi/I1\n",
- "t=1.0/(2*f)\n",
- "C1=(I1*t)/V\n",
- "print(\"schmitt design\")\n",
- "I2=1.0*10**-3\n",
- "R2=UTP/I2\n",
- "R3=(Vcc-1)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "design the triangular wave\n",
- " I1>>Ibmax for op-amp\n",
- "schmitt design\n",
- "The value of R3 is 8.00 kohm\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.11 Page No 705"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=100.0*10**3\n",
- "Rs=1.5*10**3\n",
- "R1=2.0*Rs\n",
- "\n",
- "\n",
- "#Calculations\n",
- "R1=2.7*10**3#use standard value\n",
- "R2=R1+Rs\n",
- "C1=1/(2*3.14*f*R2)\n",
- "R4=R2\n",
- "R3=2*R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3 is 8.40 kohm\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 16.12, Page No 705"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "fs=1.0*10**6\n",
- "Rs=700.0\n",
- "C1=1000.0*10**-12\n",
- "C2=100.0*10**-12\n",
- "R1=1.0*10**6\n",
- "R2=10.0*10**3\n",
- "Rs=700.0\n",
- "Vdd=5\n",
- "\n",
- "#Calculations\n",
- "Ct=(C1*C2)/(C1+C2)\n",
- "print(\" at resonance Xl=Xct 2*pi*f*L=1/2*pi*f*Ct\")\n",
- "L=1/(((2*3.14*f)**2)*Ct)\n",
- "ip=Vdd/(R1+R2+Rs)\n",
- "Pd=(((.707*ip)**2)*Rs)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" peak power dissipated is %.3fnW \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " at resonance Xl=Xct 2*pi*f*L=1/2*pi*f*Ct\n",
- " peak power dissipated is 8.563nW \n"
- ]
- }
- ],
- "prompt_number": 38
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter17.ipynb b/Electronic_Devices_and_Circuits/Chapter17.ipynb deleted file mode 100755 index 0bf01537..00000000 --- a/Electronic_Devices_and_Circuits/Chapter17.ipynb +++ /dev/null @@ -1,560 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 17 : Active filters"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.1, Page No 716"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "R1=12.0*10**3\n",
- "Rl=100.0*10**3\n",
- "C1=0.013*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"when Rl is not connected\")\n",
- "fc=1.0/(2*3.14*R1*C1)\n",
- "print(\" when Rl is connected\")\n",
- "fc=1.0/(2*3.14*((R1*Rl)/(R1+Rl))*C1)\n",
- "Attn=3#at fc attenuation is =3dB\n",
- "falloffrate=6\n",
- "print(\"attenuation at 2fc\")\n",
- "Attn=3+6\n",
- "print(\"attenuation at 2fc is %ddB \" %Attn)\n",
- "Attn=3+6+6\n",
- "\n",
- "#Results\n",
- "print(\" attenuation at 4fc is %ddB \" %Attn)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Rl is not connected\n",
- " when Rl is connected\n",
- "attenuation at 2fc\n",
- "attenuation at 2fc is 9dB \n",
- " attenuation at 4fc is 15dB \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.2, Page No 718"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ib=500.0*10**-9\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R1=(70.0*10**-3)/Ib\n",
- "R1=140*10**3#use standard value\n",
- "R2=R1\n",
- "C1=(1/(2*3.14*R1*f))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" capacitor used is of %.2f pF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " capacitor used is of 1137.40 pF \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.3 Page No 719"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "print(\"first order high pass active filter\")\n",
- "f=5.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "fu=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "R1=1.0/(2*3.14*f*C1)\n",
- "BW=fu-f\n",
- "print(\" bandwidth is %.2f kHz \" %(BW/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "first order high pass active filter\n",
- " bandwidth is 995.00 kHz \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.4, Page No 724"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=1.0*10**3\n",
- "Ib=500.0*10**-9\n",
- "print(\"butterworth second order filter\")\n",
- "\n",
- "#Calculations\n",
- "R=(70.0*10**-3)/Ib\n",
- "R1=R/2.0\n",
- "R1=68.1*10**3#use standard value\n",
- "R2=R1 \n",
- "R3=2.0*R1\n",
- "Xc1=math.sqrt(2)*R2\n",
- "C1=1/(2*3.14*f*math.sqrt(2)*R2)\n",
- "C2=2*C1\n",
- "fc=1/(2*3.14*(math.sqrt(R1*R2*C1*C2)))\n",
- "\n",
- "#Results\n",
- "print(\"actual cutoff frequency is %d kHz \" %(fc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "butterworth second order filter\n",
- "actual cutoff frequency is 1 kHz \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.5 Page No 725"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=12.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "print(\"butterworth second order filter\")\n",
- "C2=C1\n",
- "\n",
- "#Calculations\n",
- "R2=(math.sqrt(2))/(2*3.14*f*C1)\n",
- "R1=.5*R2\n",
- "R3=R2\n",
- "fc=1.0/(2*3.14*(math.sqrt(R1*R2*C1*C2)))\n",
- "\n",
- "#Results\n",
- "print(\"actual cutoff frequency is %d KHz \" %(fc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "butterworth second order filter\n",
- "actual cutoff frequency is 11 KHz \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.6 Page No 729"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "f=30.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "print(\" third order low pass filter\")\n",
- "print(\"-20 dB per decade stage\")\n",
- "\n",
- "#Calculations\n",
- "fc1=f/.65\n",
- "R1=1.0/(2*3.14*fc1*C1)\n",
- "R2=R1\n",
- "print(\"-40dB per decade stage\")\n",
- "C3=1000*10**-12\n",
- "C2=2*C3\n",
- "fc2=f/.8\n",
- "R4=1/(2*3.14*fc2*C3*(math.sqrt(2)))\n",
- "R3=R4\n",
- "R5=R3+R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " third order low pass filter\n",
- "-20 dB per decade stage\n",
- "-40dB per decade stage\n",
- "The value of R5 is 6.01 kohm\n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.7, Page No 730"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=20.0*10**3\n",
- "print(\"3rd order high pass filter\")\n",
- "print(\"-20dB per decade stage\")\n",
- "R1=121.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fc1=.65*f\n",
- "C1=1/(2*3.14*fc1*R1)\n",
- "#this is so small it might be effected by stray capacitor.redesign %first choosing a suitable capacitance C1\n",
- "C1=100*10**-12\n",
- "R1=1/(2*3.14*f*C1)\n",
- "R2=R1\n",
- "print(\"-40dB per decade stage\")\n",
- "C3=1000*10**-12\n",
- "R4=(math.sqrt(2))/(2*3.14*.8*f*C3)\n",
- "C2=C3\n",
- "R3=.5*R4\n",
- "R5=R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "3rd order high pass filter\n",
- "-20dB per decade stage\n",
- "-40dB per decade stage\n",
- "The value of R5 is 14.07 kohm\n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.8 Page No 734"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "f1=300.0\n",
- "f2=30.0*10**3\n",
- "print(\" single stage band pass filter\")\n",
- "\n",
- "#Calculations\n",
- "C2=1000*10**-12\n",
- "R2=1/(2*3.14*f2*C2)\n",
- "R1=R2\n",
- "Xc1=R1#at voltage gain Av=1\n",
- "C1=1/(2*3.14*f1*R1)\n",
- "R3=R2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " single stage band pass filter\n",
- "The value of R3 is 5.31 kohm\n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.9 Page No 736"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=300.0\n",
- "f2=30.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fo=math.sqrt(f1*f2)\n",
- "BW=f2-f1\n",
- "Q=fo/BW\n",
- "\n",
- "#Results\n",
- "print(\"The value of Q is %.2f \" %(Q))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Q is 0.10 \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.10 Page No 737"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R1=60.4*10**3\n",
- "R4=1.21*10**3\n",
- "C=.012*10**-6\n",
- "R2=121.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Q=math.sqrt((R1+R4)/(2*R4))\n",
- "fo=Q/(3.14*C*R2)\n",
- "print(\" center frequency is %3.2fHz \" %fo)\n",
- "BW=fo/Q\n",
- "\n",
- "#Results\n",
- "print(\" bandwidth is %3.1fHz \" %BW)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " center frequency is 1106.68Hz \n",
- " bandwidth is 219.3Hz \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.12, Page No 744"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "f1=10.3*10**3\n",
- "f2=10.9*10**3\n",
- "C1=1000.0*10**-12\n",
- "\n",
- "#Calculations\n",
- "C2=C1\n",
- "fo=math.sqrt(f1*f2)\n",
- "R5=1.0/(2*3.14*fo*C1)\n",
- "R1=R5\n",
- "Q=fo/(f2-f1)\n",
- "R2=R1*(2*Q-1)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R2 is %.2f kohm\" %(R2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R2 is 515.76 kohm\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.13, Page No 750"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f1=10.3*10**3\n",
- "f2=10.9*10**3\n",
- "Hobp=34\n",
- "\n",
- "#Calculations\n",
- "math.sqrt(f1*f2)\n",
- "Q=fo/(f2-f1)\n",
- "R3=120.0*10**3\n",
- "R2=R3/Q\n",
- "R1=R3/Hobp\n",
- "k=50*fo\n",
- "\n",
- "#Results\n",
- "print(\"The value of k is %.2f \" %(k/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of k is 529.79 \n"
- ]
- }
- ],
- "prompt_number": 27
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter17_1.ipynb b/Electronic_Devices_and_Circuits/Chapter17_1.ipynb deleted file mode 100755 index 0bf01537..00000000 --- a/Electronic_Devices_and_Circuits/Chapter17_1.ipynb +++ /dev/null @@ -1,560 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 17 : Active filters"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.1, Page No 716"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "R1=12.0*10**3\n",
- "Rl=100.0*10**3\n",
- "C1=0.013*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"when Rl is not connected\")\n",
- "fc=1.0/(2*3.14*R1*C1)\n",
- "print(\" when Rl is connected\")\n",
- "fc=1.0/(2*3.14*((R1*Rl)/(R1+Rl))*C1)\n",
- "Attn=3#at fc attenuation is =3dB\n",
- "falloffrate=6\n",
- "print(\"attenuation at 2fc\")\n",
- "Attn=3+6\n",
- "print(\"attenuation at 2fc is %ddB \" %Attn)\n",
- "Attn=3+6+6\n",
- "\n",
- "#Results\n",
- "print(\" attenuation at 4fc is %ddB \" %Attn)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Rl is not connected\n",
- " when Rl is connected\n",
- "attenuation at 2fc\n",
- "attenuation at 2fc is 9dB \n",
- " attenuation at 4fc is 15dB \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.2, Page No 718"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ib=500.0*10**-9\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R1=(70.0*10**-3)/Ib\n",
- "R1=140*10**3#use standard value\n",
- "R2=R1\n",
- "C1=(1/(2*3.14*R1*f))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" capacitor used is of %.2f pF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " capacitor used is of 1137.40 pF \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.3 Page No 719"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "print(\"first order high pass active filter\")\n",
- "f=5.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "fu=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "R1=1.0/(2*3.14*f*C1)\n",
- "BW=fu-f\n",
- "print(\" bandwidth is %.2f kHz \" %(BW/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "first order high pass active filter\n",
- " bandwidth is 995.00 kHz \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.4, Page No 724"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=1.0*10**3\n",
- "Ib=500.0*10**-9\n",
- "print(\"butterworth second order filter\")\n",
- "\n",
- "#Calculations\n",
- "R=(70.0*10**-3)/Ib\n",
- "R1=R/2.0\n",
- "R1=68.1*10**3#use standard value\n",
- "R2=R1 \n",
- "R3=2.0*R1\n",
- "Xc1=math.sqrt(2)*R2\n",
- "C1=1/(2*3.14*f*math.sqrt(2)*R2)\n",
- "C2=2*C1\n",
- "fc=1/(2*3.14*(math.sqrt(R1*R2*C1*C2)))\n",
- "\n",
- "#Results\n",
- "print(\"actual cutoff frequency is %d kHz \" %(fc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "butterworth second order filter\n",
- "actual cutoff frequency is 1 kHz \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.5 Page No 725"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=12.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "print(\"butterworth second order filter\")\n",
- "C2=C1\n",
- "\n",
- "#Calculations\n",
- "R2=(math.sqrt(2))/(2*3.14*f*C1)\n",
- "R1=.5*R2\n",
- "R3=R2\n",
- "fc=1.0/(2*3.14*(math.sqrt(R1*R2*C1*C2)))\n",
- "\n",
- "#Results\n",
- "print(\"actual cutoff frequency is %d KHz \" %(fc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "butterworth second order filter\n",
- "actual cutoff frequency is 11 KHz \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.6 Page No 729"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "f=30.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "print(\" third order low pass filter\")\n",
- "print(\"-20 dB per decade stage\")\n",
- "\n",
- "#Calculations\n",
- "fc1=f/.65\n",
- "R1=1.0/(2*3.14*fc1*C1)\n",
- "R2=R1\n",
- "print(\"-40dB per decade stage\")\n",
- "C3=1000*10**-12\n",
- "C2=2*C3\n",
- "fc2=f/.8\n",
- "R4=1/(2*3.14*fc2*C3*(math.sqrt(2)))\n",
- "R3=R4\n",
- "R5=R3+R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " third order low pass filter\n",
- "-20 dB per decade stage\n",
- "-40dB per decade stage\n",
- "The value of R5 is 6.01 kohm\n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.7, Page No 730"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=20.0*10**3\n",
- "print(\"3rd order high pass filter\")\n",
- "print(\"-20dB per decade stage\")\n",
- "R1=121.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fc1=.65*f\n",
- "C1=1/(2*3.14*fc1*R1)\n",
- "#this is so small it might be effected by stray capacitor.redesign %first choosing a suitable capacitance C1\n",
- "C1=100*10**-12\n",
- "R1=1/(2*3.14*f*C1)\n",
- "R2=R1\n",
- "print(\"-40dB per decade stage\")\n",
- "C3=1000*10**-12\n",
- "R4=(math.sqrt(2))/(2*3.14*.8*f*C3)\n",
- "C2=C3\n",
- "R3=.5*R4\n",
- "R5=R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "3rd order high pass filter\n",
- "-20dB per decade stage\n",
- "-40dB per decade stage\n",
- "The value of R5 is 14.07 kohm\n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.8 Page No 734"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "f1=300.0\n",
- "f2=30.0*10**3\n",
- "print(\" single stage band pass filter\")\n",
- "\n",
- "#Calculations\n",
- "C2=1000*10**-12\n",
- "R2=1/(2*3.14*f2*C2)\n",
- "R1=R2\n",
- "Xc1=R1#at voltage gain Av=1\n",
- "C1=1/(2*3.14*f1*R1)\n",
- "R3=R2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " single stage band pass filter\n",
- "The value of R3 is 5.31 kohm\n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.9 Page No 736"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=300.0\n",
- "f2=30.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fo=math.sqrt(f1*f2)\n",
- "BW=f2-f1\n",
- "Q=fo/BW\n",
- "\n",
- "#Results\n",
- "print(\"The value of Q is %.2f \" %(Q))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Q is 0.10 \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.10 Page No 737"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R1=60.4*10**3\n",
- "R4=1.21*10**3\n",
- "C=.012*10**-6\n",
- "R2=121.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Q=math.sqrt((R1+R4)/(2*R4))\n",
- "fo=Q/(3.14*C*R2)\n",
- "print(\" center frequency is %3.2fHz \" %fo)\n",
- "BW=fo/Q\n",
- "\n",
- "#Results\n",
- "print(\" bandwidth is %3.1fHz \" %BW)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " center frequency is 1106.68Hz \n",
- " bandwidth is 219.3Hz \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.12, Page No 744"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "f1=10.3*10**3\n",
- "f2=10.9*10**3\n",
- "C1=1000.0*10**-12\n",
- "\n",
- "#Calculations\n",
- "C2=C1\n",
- "fo=math.sqrt(f1*f2)\n",
- "R5=1.0/(2*3.14*fo*C1)\n",
- "R1=R5\n",
- "Q=fo/(f2-f1)\n",
- "R2=R1*(2*Q-1)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R2 is %.2f kohm\" %(R2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R2 is 515.76 kohm\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.13, Page No 750"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f1=10.3*10**3\n",
- "f2=10.9*10**3\n",
- "Hobp=34\n",
- "\n",
- "#Calculations\n",
- "math.sqrt(f1*f2)\n",
- "Q=fo/(f2-f1)\n",
- "R3=120.0*10**3\n",
- "R2=R3/Q\n",
- "R1=R3/Hobp\n",
- "k=50*fo\n",
- "\n",
- "#Results\n",
- "print(\"The value of k is %.2f \" %(k/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of k is 529.79 \n"
- ]
- }
- ],
- "prompt_number": 27
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter17_2.ipynb b/Electronic_Devices_and_Circuits/Chapter17_2.ipynb deleted file mode 100755 index 0bf01537..00000000 --- a/Electronic_Devices_and_Circuits/Chapter17_2.ipynb +++ /dev/null @@ -1,560 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 17 : Active filters"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.1, Page No 716"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "R1=12.0*10**3\n",
- "Rl=100.0*10**3\n",
- "C1=0.013*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"when Rl is not connected\")\n",
- "fc=1.0/(2*3.14*R1*C1)\n",
- "print(\" when Rl is connected\")\n",
- "fc=1.0/(2*3.14*((R1*Rl)/(R1+Rl))*C1)\n",
- "Attn=3#at fc attenuation is =3dB\n",
- "falloffrate=6\n",
- "print(\"attenuation at 2fc\")\n",
- "Attn=3+6\n",
- "print(\"attenuation at 2fc is %ddB \" %Attn)\n",
- "Attn=3+6+6\n",
- "\n",
- "#Results\n",
- "print(\" attenuation at 4fc is %ddB \" %Attn)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Rl is not connected\n",
- " when Rl is connected\n",
- "attenuation at 2fc\n",
- "attenuation at 2fc is 9dB \n",
- " attenuation at 4fc is 15dB \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.2, Page No 718"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ib=500.0*10**-9\n",
- "f=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R1=(70.0*10**-3)/Ib\n",
- "R1=140*10**3#use standard value\n",
- "R2=R1\n",
- "C1=(1/(2*3.14*R1*f))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" capacitor used is of %.2f pF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " capacitor used is of 1137.40 pF \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.3 Page No 719"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "print(\"first order high pass active filter\")\n",
- "f=5.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "fu=1.0*10**6\n",
- "\n",
- "#Calculations\n",
- "R1=1.0/(2*3.14*f*C1)\n",
- "BW=fu-f\n",
- "print(\" bandwidth is %.2f kHz \" %(BW/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "first order high pass active filter\n",
- " bandwidth is 995.00 kHz \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.4, Page No 724"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=1.0*10**3\n",
- "Ib=500.0*10**-9\n",
- "print(\"butterworth second order filter\")\n",
- "\n",
- "#Calculations\n",
- "R=(70.0*10**-3)/Ib\n",
- "R1=R/2.0\n",
- "R1=68.1*10**3#use standard value\n",
- "R2=R1 \n",
- "R3=2.0*R1\n",
- "Xc1=math.sqrt(2)*R2\n",
- "C1=1/(2*3.14*f*math.sqrt(2)*R2)\n",
- "C2=2*C1\n",
- "fc=1/(2*3.14*(math.sqrt(R1*R2*C1*C2)))\n",
- "\n",
- "#Results\n",
- "print(\"actual cutoff frequency is %d kHz \" %(fc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "butterworth second order filter\n",
- "actual cutoff frequency is 1 kHz \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.5 Page No 725"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=12.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "print(\"butterworth second order filter\")\n",
- "C2=C1\n",
- "\n",
- "#Calculations\n",
- "R2=(math.sqrt(2))/(2*3.14*f*C1)\n",
- "R1=.5*R2\n",
- "R3=R2\n",
- "fc=1.0/(2*3.14*(math.sqrt(R1*R2*C1*C2)))\n",
- "\n",
- "#Results\n",
- "print(\"actual cutoff frequency is %d KHz \" %(fc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "butterworth second order filter\n",
- "actual cutoff frequency is 11 KHz \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.6 Page No 729"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "f=30.0*10**3\n",
- "C1=1000.0*10**-12\n",
- "print(\" third order low pass filter\")\n",
- "print(\"-20 dB per decade stage\")\n",
- "\n",
- "#Calculations\n",
- "fc1=f/.65\n",
- "R1=1.0/(2*3.14*fc1*C1)\n",
- "R2=R1\n",
- "print(\"-40dB per decade stage\")\n",
- "C3=1000*10**-12\n",
- "C2=2*C3\n",
- "fc2=f/.8\n",
- "R4=1/(2*3.14*fc2*C3*(math.sqrt(2)))\n",
- "R3=R4\n",
- "R5=R3+R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " third order low pass filter\n",
- "-20 dB per decade stage\n",
- "-40dB per decade stage\n",
- "The value of R5 is 6.01 kohm\n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.7, Page No 730"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=20.0*10**3\n",
- "print(\"3rd order high pass filter\")\n",
- "print(\"-20dB per decade stage\")\n",
- "R1=121.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fc1=.65*f\n",
- "C1=1/(2*3.14*fc1*R1)\n",
- "#this is so small it might be effected by stray capacitor.redesign %first choosing a suitable capacitance C1\n",
- "C1=100*10**-12\n",
- "R1=1/(2*3.14*f*C1)\n",
- "R2=R1\n",
- "print(\"-40dB per decade stage\")\n",
- "C3=1000*10**-12\n",
- "R4=(math.sqrt(2))/(2*3.14*.8*f*C3)\n",
- "C2=C3\n",
- "R3=.5*R4\n",
- "R5=R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "3rd order high pass filter\n",
- "-20dB per decade stage\n",
- "-40dB per decade stage\n",
- "The value of R5 is 14.07 kohm\n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.8 Page No 734"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "f1=300.0\n",
- "f2=30.0*10**3\n",
- "print(\" single stage band pass filter\")\n",
- "\n",
- "#Calculations\n",
- "C2=1000*10**-12\n",
- "R2=1/(2*3.14*f2*C2)\n",
- "R1=R2\n",
- "Xc1=R1#at voltage gain Av=1\n",
- "C1=1/(2*3.14*f1*R1)\n",
- "R3=R2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " single stage band pass filter\n",
- "The value of R3 is 5.31 kohm\n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.9 Page No 736"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f1=300.0\n",
- "f2=30.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fo=math.sqrt(f1*f2)\n",
- "BW=f2-f1\n",
- "Q=fo/BW\n",
- "\n",
- "#Results\n",
- "print(\"The value of Q is %.2f \" %(Q))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Q is 0.10 \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.10 Page No 737"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R1=60.4*10**3\n",
- "R4=1.21*10**3\n",
- "C=.012*10**-6\n",
- "R2=121.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Q=math.sqrt((R1+R4)/(2*R4))\n",
- "fo=Q/(3.14*C*R2)\n",
- "print(\" center frequency is %3.2fHz \" %fo)\n",
- "BW=fo/Q\n",
- "\n",
- "#Results\n",
- "print(\" bandwidth is %3.1fHz \" %BW)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " center frequency is 1106.68Hz \n",
- " bandwidth is 219.3Hz \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.12, Page No 744"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "f1=10.3*10**3\n",
- "f2=10.9*10**3\n",
- "C1=1000.0*10**-12\n",
- "\n",
- "#Calculations\n",
- "C2=C1\n",
- "fo=math.sqrt(f1*f2)\n",
- "R5=1.0/(2*3.14*fo*C1)\n",
- "R1=R5\n",
- "Q=fo/(f2-f1)\n",
- "R2=R1*(2*Q-1)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R2 is %.2f kohm\" %(R2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R2 is 515.76 kohm\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 17.13, Page No 750"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f1=10.3*10**3\n",
- "f2=10.9*10**3\n",
- "Hobp=34\n",
- "\n",
- "#Calculations\n",
- "math.sqrt(f1*f2)\n",
- "Q=fo/(f2-f1)\n",
- "R3=120.0*10**3\n",
- "R2=R3/Q\n",
- "R1=R3/Hobp\n",
- "k=50*fo\n",
- "\n",
- "#Results\n",
- "print(\"The value of k is %.2f \" %(k/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of k is 529.79 \n"
- ]
- }
- ],
- "prompt_number": 27
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter18.ipynb b/Electronic_Devices_and_Circuits/Chapter18.ipynb deleted file mode 100755 index 4cac5251..00000000 --- a/Electronic_Devices_and_Circuits/Chapter18.ipynb +++ /dev/null @@ -1,684 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 18 : Linear and switching voltage regulators"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.1, Page No 761"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vs=21.0\n",
- "Vo=12.0\n",
- "Av=100.0\n",
- "\n",
- "#Calculations\n",
- "vo=(Vs*0.1)/Av#source effect is 10% of the Vs\n",
- "print(\" source effect is %3.3fV \" %vo)\n",
- "vo=(21-20)/100.0\n",
- "print(\" laod effect is %3.3fV \" %vo)\n",
- "LR=(21*10**-3 *100)/12.0\n",
- "print(\"line regulation is %3.3fpercentage \" %LR)\n",
- "LR=(10*10**-3*100)/12.0\n",
- "print(\" load effect is %3.3fpercentage \" %LR)\n",
- "RJ=20*math.log((1.0/Av),10)\n",
- "\n",
- "#Results\n",
- "print(\"ripple rejection is %d dB \" %RJ)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " source effect is 0.021V \n",
- " laod effect is 0.010V \n",
- "line regulation is 0.175percentage \n",
- " load effect is 0.083percentage \n",
- "ripple rejection is -39 dB \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.2, Page No 762"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=12.0\n",
- "Il=40.0*10**-3\n",
- "Vs=20.0\n",
- "Vbe=.7\n",
- "Vz=0.75*Vo\n",
- "print(\"for minimum D1 current select\")\n",
- "Ir2=10.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R2=(Vo-Vz)/Ir2\n",
- "Ie1=Il+Ir2\n",
- "print(\"specification for Q\")\n",
- "Vce1=20 \n",
- "Vs=Vce1\n",
- "Ic1=50*10**-3\n",
- "Pd=(Vs-Vo)*Ie1\n",
- "hfe=50\n",
- "Ib1=Ie1/hfe\n",
- "Ic2=5*10**-3\n",
- "R1=(Vs-(Vo+.7))/(Ic2+Ib1)\n",
- "Iz=Ie1+Ir2\n",
- "I4=1*10**-3\n",
- "R4=(Vz+Vbe)/I4\n",
- "R3=(Vo-(Vz+Vbe))/I4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "for minimum D1 current select\n",
- "specification for Q\n",
- "The value of R3 is 2.30 kohm\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.3 Page No 765"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "I4=1.0*10**-3\n",
- "Vb2=9.8\n",
- "\n",
- "#Calculations\n",
- "print(\" for Vo=11V moving contact at top of R5\")\n",
- "Vo=11\n",
- "R3=(Vo-Vb2)/I4\n",
- "R=Vb2/I4#R=R4+R5\n",
- "print(\" for Vo=13V moving contact at bottom of R5\")\n",
- "Vo=13\n",
- "I4=Vo/(R3+R)\n",
- "R4=Vb2/I4\n",
- "R5=R-R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Vo=11V moving contact at top of R5\n",
- " for Vo=13V moving contact at bottom of R5\n",
- "The value of R5 is 1.51 kohm\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.4, Page No 766"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hFE3=50.0\n",
- "hFE1=20.0\n",
- "Ie1=200.0*10**-3+10*10**-3\n",
- "Ic2=1.0*1**-3\n",
- "Vs=20.0\n",
- "Vb3=13.4\n",
- "Vo=12.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Ib1=Ie1/hFE1\n",
- "Ib3=Ib1/hFE3\n",
- "R1=(Vs-Vb3)/(Ic2+Ib3)\n",
- "print(\"select I6=.5*10**-3\")\n",
- "I6=.5*10**-3\n",
- "R6=(Vo+Vbe)/I6\n",
- "Pd=(Vs-Vo)*Ie1\n",
- "\n",
- "#Results\n",
- "print(\" peak power dissipated is %.3fnW \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select I6=.5*10**-3\n",
- " peak power dissipated is 1.680nW \n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.5 Page No 769"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vr1=3.0\n",
- "Ic2=1.0*10**-3\n",
- "Ib3=0.21*10**-3\n",
- "Vbe1=0.7\n",
- "Vbe3=Vbe1\n",
- "Vs=20.0\n",
- "\n",
- "#Calculations\n",
- "R1=Vr1/(Ic2+Ib3)\n",
- "Vz2=Vo+Vbe1+Vbe3+Vr1\n",
- "Ir7=5*10**-3\n",
- "R2=(Vs-Vz2)/Ir7\n",
- "\n",
- "#Results\n",
- "print(\"The value of R2 is %.2f kohm\" %(R2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R2 is 0.72 kohm\n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.6 Page No 770"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vc5=9.8\n",
- "Vb2=Vc5\n",
- "Vce5=3.0\n",
- "Vbe=0.7\n",
- "Vo=12.0\n",
- "\n",
- "#Calculations\n",
- "Vr9=Vc5-Vce5\n",
- "Vz2=Vr9+Vbe\n",
- "Ic5=1.0*10**-3\n",
- "R8=(Vo-Vc5)/Ic5\n",
- "Ir9=2*Ic5\n",
- "R9=Vr9/Ir9\n",
- "print(\" Iz2>>Ib5 and Iz2> Izk for the zener diode \")\n",
- "Iz2=10*10**-3\n",
- "R7=(Vo-Vz2)/Iz2\n",
- "I4=1*10**-3\n",
- "Vb6=7.5\n",
- "Vz2=Vb6\n",
- "print(\" when Vo=11V moving contact at top of R5 \")\n",
- "Vo=11\n",
- "R3=(Vo-Vb6)/I4\n",
- "R3=3.3*10**3#use standard value\n",
- "I4=(Vo-Vb6)/R3\n",
- "R=Vb6/I4#R=R4+R5\n",
- "print(\" when Vo=13V moving contact at bottom of R5\")\n",
- "Vo=13.0\n",
- "Vb6=7.5\n",
- "I4=Vo/(R3+R)\n",
- "R4=Vb6/I4\n",
- "R5=R-R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Iz2>>Ib5 and Iz2> Izk for the zener diode \n",
- " when Vo=11V moving contact at top of R5 \n",
- " when Vo=13V moving contact at bottom of R5\n",
- "The value of R5 is 1.09 kohm\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.7, Page No 770"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Isc=100.0*10**-3\n",
- "Vr10=0.5\n",
- "Vo=12.0\n",
- "\n",
- "#Calculations\n",
- "R10=Vr10/Isc\n",
- "R10=4.7#use standard value\n",
- "Il=200.0*10**-3\n",
- "Vr10=Il*R10\n",
- "Vr11=Vr10-.5\n",
- "I11=1.0*10**-3\n",
- "R11=Vr11/I11\n",
- "R12=(Vo+Vr10-Vr11)/I11\n",
- "\n",
- "#Results\n",
- "print(\"The value of R12 is %.2f kohm\" %(R12/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R12 is 12.50 kohm\n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.8 Page No 778"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=12.0\n",
- "hFE1=20.0\n",
- "hFE2=50.0\n",
- "Il=250.0*10**-3\n",
- "Vz=0.75*Vo\n",
- "Vz=9.1#use standard value for 1N757 diode\n",
- "Iz1=10.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=(Vo-Vz)/Iz1\n",
- "I3=1.0*10**-3\n",
- "print(\" when V0=12V(moving contact at top of R5)\")\n",
- "R3=(Vo-Vz)/I3\n",
- "R=Vz/I3\n",
- "print(\" when Vo=15V moving contact at bottom of R5\")\n",
- "Vo=15\n",
- "I3=Vo/(R+R3)\n",
- "R4=Vz/I3\n",
- "R5=R-R4\n",
- "Ir6=.5*10**-3\n",
- "R6=Vo/Ir6\n",
- "print(\" op-amp output current\")\n",
- "Ib2=Il/(hFE1*hFE2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ib2 is %.2f mA\" %(Ib2*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " when V0=12V(moving contact at top of R5)\n",
- " when Vo=15V moving contact at bottom of R5\n",
- " op-amp output current\n",
- "The value of Ib2 is 0.25 mA\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.9 Page No 782"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "I2=1.0*10**-3\n",
- "Vr2=7.15\n",
- "Vref=Vr2\n",
- "Vo=10.0\n",
- "Pdmax=1000.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R2=Vref/I2\n",
- "R2=6.8*10**3#use standard value and recalculate the I2\n",
- "I2=Vref/R2\n",
- "R1=(Vo-Vref)/I2\n",
- "Vs=Vo+5#for satisfactory operation of series pass transistor\n",
- "Iint=25*10**-3#internal circuit current\n",
- "Pi=Vs*Iint\n",
- "print(\"maximum power dissipated in series pass transistor\")\n",
- "Pd=Pdmax-Pi\n",
- "print(\"maximum load current is \")\n",
- "Il=Pd/(Vs-Vo)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Il is %.2f mA\" %(Il*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum power dissipated in series pass transistor\n",
- "maximum load current is \n",
- "The value of Il is 125.00 mA\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.10 Page No 785"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "I1=1.0*10**-3\n",
- "Vref=1.25\n",
- "Vo=6.0\n",
- "Vs=15.0\n",
- "Il=200.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=Vref/I1\n",
- "R2=(Vo-Vref)/I1\n",
- "Pd=(Vs-Vo)*Il\n",
- "\n",
- "#Results\n",
- "print(\"regulated power dissipation is %.2f W \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "regulated power dissipation is 1.80 W \n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.11, Page No 788"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=10.0\n",
- "Io=1.0\n",
- "Vce=7.0\n",
- "Vf=1.0\n",
- "\n",
- "#Calculations\n",
- "Po=Vo*Io\n",
- "print(\" linear regulator\")\n",
- "Pi=Po+(Vce*Io)\n",
- "n=(Po*100.0)/Pi#efficiency\n",
- "print(\" switching regulator\")\n",
- "Vce=1\n",
- "Pi=Po+Io*(Vce+Vf)\n",
- "n=(Po*100.0)/Pi#efficiency\n",
- "\n",
- "#Results\n",
- "print(\"The value of n is %.2f \" %(n))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " linear regulator\n",
- " switching regulator\n",
- "The value of n is 83.33 \n"
- ]
- }
- ],
- "prompt_number": 35
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.12, Page No 752"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=50.0*10**3\n",
- "Vo=12.0\n",
- "Vf=0.7\n",
- "Vi=30.0\n",
- "Vsat=1.0\n",
- "Io=500.0*10**-3\n",
- "Vr=100.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "T=1.0/f\n",
- "t=(Vo+Vf)/(Vi-Vsat-Vo)\n",
- "toff=T/1.75\n",
- "ton=T-toff\n",
- "Ip=2*Io\n",
- "L1=((Vi-Vsat-Vo)*ton)/Ip\n",
- "C1=Ip/(8.0*f*Vr)\n",
- "\n",
- "#Results\n",
- "print(\"The value of C1 is %.2f pF\" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C1 is 25.00 pF\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.13, Page No 799"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "print(\" an MC34063 controller is for step down transformer\")\n",
- "Ib=-400.0*10**-3\n",
- "I1=1.0*10**-3\n",
- "Vref=1.25\n",
- "V0=12.0\n",
- "Ip=1.0\n",
- "\n",
- "#Calculations\n",
- "ton=8.6*10**-6\n",
- "R1=Vref/I1\n",
- "R1=1.2*10**3#use standard value\n",
- "I1=Vref/R1\n",
- "R2=(Vo-Vref)/I1\n",
- "Rsc=.33/Ip\n",
- "Ct=4.8*10**-5 *ton\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ct is %.2f pF\" %(Ct*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " an MC34063 controller is for step down transformer\n",
- "The value of Ct is 0.00 pF\n"
- ]
- }
- ],
- "prompt_number": 37
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter18_1.ipynb b/Electronic_Devices_and_Circuits/Chapter18_1.ipynb deleted file mode 100755 index 4cac5251..00000000 --- a/Electronic_Devices_and_Circuits/Chapter18_1.ipynb +++ /dev/null @@ -1,684 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 18 : Linear and switching voltage regulators"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.1, Page No 761"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vs=21.0\n",
- "Vo=12.0\n",
- "Av=100.0\n",
- "\n",
- "#Calculations\n",
- "vo=(Vs*0.1)/Av#source effect is 10% of the Vs\n",
- "print(\" source effect is %3.3fV \" %vo)\n",
- "vo=(21-20)/100.0\n",
- "print(\" laod effect is %3.3fV \" %vo)\n",
- "LR=(21*10**-3 *100)/12.0\n",
- "print(\"line regulation is %3.3fpercentage \" %LR)\n",
- "LR=(10*10**-3*100)/12.0\n",
- "print(\" load effect is %3.3fpercentage \" %LR)\n",
- "RJ=20*math.log((1.0/Av),10)\n",
- "\n",
- "#Results\n",
- "print(\"ripple rejection is %d dB \" %RJ)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " source effect is 0.021V \n",
- " laod effect is 0.010V \n",
- "line regulation is 0.175percentage \n",
- " load effect is 0.083percentage \n",
- "ripple rejection is -39 dB \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.2, Page No 762"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=12.0\n",
- "Il=40.0*10**-3\n",
- "Vs=20.0\n",
- "Vbe=.7\n",
- "Vz=0.75*Vo\n",
- "print(\"for minimum D1 current select\")\n",
- "Ir2=10.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R2=(Vo-Vz)/Ir2\n",
- "Ie1=Il+Ir2\n",
- "print(\"specification for Q\")\n",
- "Vce1=20 \n",
- "Vs=Vce1\n",
- "Ic1=50*10**-3\n",
- "Pd=(Vs-Vo)*Ie1\n",
- "hfe=50\n",
- "Ib1=Ie1/hfe\n",
- "Ic2=5*10**-3\n",
- "R1=(Vs-(Vo+.7))/(Ic2+Ib1)\n",
- "Iz=Ie1+Ir2\n",
- "I4=1*10**-3\n",
- "R4=(Vz+Vbe)/I4\n",
- "R3=(Vo-(Vz+Vbe))/I4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "for minimum D1 current select\n",
- "specification for Q\n",
- "The value of R3 is 2.30 kohm\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.3 Page No 765"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "I4=1.0*10**-3\n",
- "Vb2=9.8\n",
- "\n",
- "#Calculations\n",
- "print(\" for Vo=11V moving contact at top of R5\")\n",
- "Vo=11\n",
- "R3=(Vo-Vb2)/I4\n",
- "R=Vb2/I4#R=R4+R5\n",
- "print(\" for Vo=13V moving contact at bottom of R5\")\n",
- "Vo=13\n",
- "I4=Vo/(R3+R)\n",
- "R4=Vb2/I4\n",
- "R5=R-R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Vo=11V moving contact at top of R5\n",
- " for Vo=13V moving contact at bottom of R5\n",
- "The value of R5 is 1.51 kohm\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.4, Page No 766"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hFE3=50.0\n",
- "hFE1=20.0\n",
- "Ie1=200.0*10**-3+10*10**-3\n",
- "Ic2=1.0*1**-3\n",
- "Vs=20.0\n",
- "Vb3=13.4\n",
- "Vo=12.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Ib1=Ie1/hFE1\n",
- "Ib3=Ib1/hFE3\n",
- "R1=(Vs-Vb3)/(Ic2+Ib3)\n",
- "print(\"select I6=.5*10**-3\")\n",
- "I6=.5*10**-3\n",
- "R6=(Vo+Vbe)/I6\n",
- "Pd=(Vs-Vo)*Ie1\n",
- "\n",
- "#Results\n",
- "print(\" peak power dissipated is %.3fnW \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select I6=.5*10**-3\n",
- " peak power dissipated is 1.680nW \n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.5 Page No 769"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vr1=3.0\n",
- "Ic2=1.0*10**-3\n",
- "Ib3=0.21*10**-3\n",
- "Vbe1=0.7\n",
- "Vbe3=Vbe1\n",
- "Vs=20.0\n",
- "\n",
- "#Calculations\n",
- "R1=Vr1/(Ic2+Ib3)\n",
- "Vz2=Vo+Vbe1+Vbe3+Vr1\n",
- "Ir7=5*10**-3\n",
- "R2=(Vs-Vz2)/Ir7\n",
- "\n",
- "#Results\n",
- "print(\"The value of R2 is %.2f kohm\" %(R2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R2 is 0.72 kohm\n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.6 Page No 770"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vc5=9.8\n",
- "Vb2=Vc5\n",
- "Vce5=3.0\n",
- "Vbe=0.7\n",
- "Vo=12.0\n",
- "\n",
- "#Calculations\n",
- "Vr9=Vc5-Vce5\n",
- "Vz2=Vr9+Vbe\n",
- "Ic5=1.0*10**-3\n",
- "R8=(Vo-Vc5)/Ic5\n",
- "Ir9=2*Ic5\n",
- "R9=Vr9/Ir9\n",
- "print(\" Iz2>>Ib5 and Iz2> Izk for the zener diode \")\n",
- "Iz2=10*10**-3\n",
- "R7=(Vo-Vz2)/Iz2\n",
- "I4=1*10**-3\n",
- "Vb6=7.5\n",
- "Vz2=Vb6\n",
- "print(\" when Vo=11V moving contact at top of R5 \")\n",
- "Vo=11\n",
- "R3=(Vo-Vb6)/I4\n",
- "R3=3.3*10**3#use standard value\n",
- "I4=(Vo-Vb6)/R3\n",
- "R=Vb6/I4#R=R4+R5\n",
- "print(\" when Vo=13V moving contact at bottom of R5\")\n",
- "Vo=13.0\n",
- "Vb6=7.5\n",
- "I4=Vo/(R3+R)\n",
- "R4=Vb6/I4\n",
- "R5=R-R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Iz2>>Ib5 and Iz2> Izk for the zener diode \n",
- " when Vo=11V moving contact at top of R5 \n",
- " when Vo=13V moving contact at bottom of R5\n",
- "The value of R5 is 1.09 kohm\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.7, Page No 770"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Isc=100.0*10**-3\n",
- "Vr10=0.5\n",
- "Vo=12.0\n",
- "\n",
- "#Calculations\n",
- "R10=Vr10/Isc\n",
- "R10=4.7#use standard value\n",
- "Il=200.0*10**-3\n",
- "Vr10=Il*R10\n",
- "Vr11=Vr10-.5\n",
- "I11=1.0*10**-3\n",
- "R11=Vr11/I11\n",
- "R12=(Vo+Vr10-Vr11)/I11\n",
- "\n",
- "#Results\n",
- "print(\"The value of R12 is %.2f kohm\" %(R12/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R12 is 12.50 kohm\n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.8 Page No 778"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=12.0\n",
- "hFE1=20.0\n",
- "hFE2=50.0\n",
- "Il=250.0*10**-3\n",
- "Vz=0.75*Vo\n",
- "Vz=9.1#use standard value for 1N757 diode\n",
- "Iz1=10.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=(Vo-Vz)/Iz1\n",
- "I3=1.0*10**-3\n",
- "print(\" when V0=12V(moving contact at top of R5)\")\n",
- "R3=(Vo-Vz)/I3\n",
- "R=Vz/I3\n",
- "print(\" when Vo=15V moving contact at bottom of R5\")\n",
- "Vo=15\n",
- "I3=Vo/(R+R3)\n",
- "R4=Vz/I3\n",
- "R5=R-R4\n",
- "Ir6=.5*10**-3\n",
- "R6=Vo/Ir6\n",
- "print(\" op-amp output current\")\n",
- "Ib2=Il/(hFE1*hFE2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ib2 is %.2f mA\" %(Ib2*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " when V0=12V(moving contact at top of R5)\n",
- " when Vo=15V moving contact at bottom of R5\n",
- " op-amp output current\n",
- "The value of Ib2 is 0.25 mA\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.9 Page No 782"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "I2=1.0*10**-3\n",
- "Vr2=7.15\n",
- "Vref=Vr2\n",
- "Vo=10.0\n",
- "Pdmax=1000.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R2=Vref/I2\n",
- "R2=6.8*10**3#use standard value and recalculate the I2\n",
- "I2=Vref/R2\n",
- "R1=(Vo-Vref)/I2\n",
- "Vs=Vo+5#for satisfactory operation of series pass transistor\n",
- "Iint=25*10**-3#internal circuit current\n",
- "Pi=Vs*Iint\n",
- "print(\"maximum power dissipated in series pass transistor\")\n",
- "Pd=Pdmax-Pi\n",
- "print(\"maximum load current is \")\n",
- "Il=Pd/(Vs-Vo)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Il is %.2f mA\" %(Il*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum power dissipated in series pass transistor\n",
- "maximum load current is \n",
- "The value of Il is 125.00 mA\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.10 Page No 785"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "I1=1.0*10**-3\n",
- "Vref=1.25\n",
- "Vo=6.0\n",
- "Vs=15.0\n",
- "Il=200.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=Vref/I1\n",
- "R2=(Vo-Vref)/I1\n",
- "Pd=(Vs-Vo)*Il\n",
- "\n",
- "#Results\n",
- "print(\"regulated power dissipation is %.2f W \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "regulated power dissipation is 1.80 W \n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.11, Page No 788"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=10.0\n",
- "Io=1.0\n",
- "Vce=7.0\n",
- "Vf=1.0\n",
- "\n",
- "#Calculations\n",
- "Po=Vo*Io\n",
- "print(\" linear regulator\")\n",
- "Pi=Po+(Vce*Io)\n",
- "n=(Po*100.0)/Pi#efficiency\n",
- "print(\" switching regulator\")\n",
- "Vce=1\n",
- "Pi=Po+Io*(Vce+Vf)\n",
- "n=(Po*100.0)/Pi#efficiency\n",
- "\n",
- "#Results\n",
- "print(\"The value of n is %.2f \" %(n))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " linear regulator\n",
- " switching regulator\n",
- "The value of n is 83.33 \n"
- ]
- }
- ],
- "prompt_number": 35
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.12, Page No 752"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=50.0*10**3\n",
- "Vo=12.0\n",
- "Vf=0.7\n",
- "Vi=30.0\n",
- "Vsat=1.0\n",
- "Io=500.0*10**-3\n",
- "Vr=100.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "T=1.0/f\n",
- "t=(Vo+Vf)/(Vi-Vsat-Vo)\n",
- "toff=T/1.75\n",
- "ton=T-toff\n",
- "Ip=2*Io\n",
- "L1=((Vi-Vsat-Vo)*ton)/Ip\n",
- "C1=Ip/(8.0*f*Vr)\n",
- "\n",
- "#Results\n",
- "print(\"The value of C1 is %.2f pF\" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C1 is 25.00 pF\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.13, Page No 799"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "print(\" an MC34063 controller is for step down transformer\")\n",
- "Ib=-400.0*10**-3\n",
- "I1=1.0*10**-3\n",
- "Vref=1.25\n",
- "V0=12.0\n",
- "Ip=1.0\n",
- "\n",
- "#Calculations\n",
- "ton=8.6*10**-6\n",
- "R1=Vref/I1\n",
- "R1=1.2*10**3#use standard value\n",
- "I1=Vref/R1\n",
- "R2=(Vo-Vref)/I1\n",
- "Rsc=.33/Ip\n",
- "Ct=4.8*10**-5 *ton\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ct is %.2f pF\" %(Ct*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " an MC34063 controller is for step down transformer\n",
- "The value of Ct is 0.00 pF\n"
- ]
- }
- ],
- "prompt_number": 37
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter18_2.ipynb b/Electronic_Devices_and_Circuits/Chapter18_2.ipynb deleted file mode 100755 index 4cac5251..00000000 --- a/Electronic_Devices_and_Circuits/Chapter18_2.ipynb +++ /dev/null @@ -1,684 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 18 : Linear and switching voltage regulators"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.1, Page No 761"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vs=21.0\n",
- "Vo=12.0\n",
- "Av=100.0\n",
- "\n",
- "#Calculations\n",
- "vo=(Vs*0.1)/Av#source effect is 10% of the Vs\n",
- "print(\" source effect is %3.3fV \" %vo)\n",
- "vo=(21-20)/100.0\n",
- "print(\" laod effect is %3.3fV \" %vo)\n",
- "LR=(21*10**-3 *100)/12.0\n",
- "print(\"line regulation is %3.3fpercentage \" %LR)\n",
- "LR=(10*10**-3*100)/12.0\n",
- "print(\" load effect is %3.3fpercentage \" %LR)\n",
- "RJ=20*math.log((1.0/Av),10)\n",
- "\n",
- "#Results\n",
- "print(\"ripple rejection is %d dB \" %RJ)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " source effect is 0.021V \n",
- " laod effect is 0.010V \n",
- "line regulation is 0.175percentage \n",
- " load effect is 0.083percentage \n",
- "ripple rejection is -39 dB \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.2, Page No 762"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=12.0\n",
- "Il=40.0*10**-3\n",
- "Vs=20.0\n",
- "Vbe=.7\n",
- "Vz=0.75*Vo\n",
- "print(\"for minimum D1 current select\")\n",
- "Ir2=10.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R2=(Vo-Vz)/Ir2\n",
- "Ie1=Il+Ir2\n",
- "print(\"specification for Q\")\n",
- "Vce1=20 \n",
- "Vs=Vce1\n",
- "Ic1=50*10**-3\n",
- "Pd=(Vs-Vo)*Ie1\n",
- "hfe=50\n",
- "Ib1=Ie1/hfe\n",
- "Ic2=5*10**-3\n",
- "R1=(Vs-(Vo+.7))/(Ic2+Ib1)\n",
- "Iz=Ie1+Ir2\n",
- "I4=1*10**-3\n",
- "R4=(Vz+Vbe)/I4\n",
- "R3=(Vo-(Vz+Vbe))/I4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "for minimum D1 current select\n",
- "specification for Q\n",
- "The value of R3 is 2.30 kohm\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.3 Page No 765"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "I4=1.0*10**-3\n",
- "Vb2=9.8\n",
- "\n",
- "#Calculations\n",
- "print(\" for Vo=11V moving contact at top of R5\")\n",
- "Vo=11\n",
- "R3=(Vo-Vb2)/I4\n",
- "R=Vb2/I4#R=R4+R5\n",
- "print(\" for Vo=13V moving contact at bottom of R5\")\n",
- "Vo=13\n",
- "I4=Vo/(R3+R)\n",
- "R4=Vb2/I4\n",
- "R5=R-R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Vo=11V moving contact at top of R5\n",
- " for Vo=13V moving contact at bottom of R5\n",
- "The value of R5 is 1.51 kohm\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.4, Page No 766"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "hFE3=50.0\n",
- "hFE1=20.0\n",
- "Ie1=200.0*10**-3+10*10**-3\n",
- "Ic2=1.0*1**-3\n",
- "Vs=20.0\n",
- "Vb3=13.4\n",
- "Vo=12.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Ib1=Ie1/hFE1\n",
- "Ib3=Ib1/hFE3\n",
- "R1=(Vs-Vb3)/(Ic2+Ib3)\n",
- "print(\"select I6=.5*10**-3\")\n",
- "I6=.5*10**-3\n",
- "R6=(Vo+Vbe)/I6\n",
- "Pd=(Vs-Vo)*Ie1\n",
- "\n",
- "#Results\n",
- "print(\" peak power dissipated is %.3fnW \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "select I6=.5*10**-3\n",
- " peak power dissipated is 1.680nW \n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.5 Page No 769"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vr1=3.0\n",
- "Ic2=1.0*10**-3\n",
- "Ib3=0.21*10**-3\n",
- "Vbe1=0.7\n",
- "Vbe3=Vbe1\n",
- "Vs=20.0\n",
- "\n",
- "#Calculations\n",
- "R1=Vr1/(Ic2+Ib3)\n",
- "Vz2=Vo+Vbe1+Vbe3+Vr1\n",
- "Ir7=5*10**-3\n",
- "R2=(Vs-Vz2)/Ir7\n",
- "\n",
- "#Results\n",
- "print(\"The value of R2 is %.2f kohm\" %(R2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R2 is 0.72 kohm\n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.6 Page No 770"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vc5=9.8\n",
- "Vb2=Vc5\n",
- "Vce5=3.0\n",
- "Vbe=0.7\n",
- "Vo=12.0\n",
- "\n",
- "#Calculations\n",
- "Vr9=Vc5-Vce5\n",
- "Vz2=Vr9+Vbe\n",
- "Ic5=1.0*10**-3\n",
- "R8=(Vo-Vc5)/Ic5\n",
- "Ir9=2*Ic5\n",
- "R9=Vr9/Ir9\n",
- "print(\" Iz2>>Ib5 and Iz2> Izk for the zener diode \")\n",
- "Iz2=10*10**-3\n",
- "R7=(Vo-Vz2)/Iz2\n",
- "I4=1*10**-3\n",
- "Vb6=7.5\n",
- "Vz2=Vb6\n",
- "print(\" when Vo=11V moving contact at top of R5 \")\n",
- "Vo=11\n",
- "R3=(Vo-Vb6)/I4\n",
- "R3=3.3*10**3#use standard value\n",
- "I4=(Vo-Vb6)/R3\n",
- "R=Vb6/I4#R=R4+R5\n",
- "print(\" when Vo=13V moving contact at bottom of R5\")\n",
- "Vo=13.0\n",
- "Vb6=7.5\n",
- "I4=Vo/(R3+R)\n",
- "R4=Vb6/I4\n",
- "R5=R-R4\n",
- "\n",
- "#Results\n",
- "print(\"The value of R5 is %.2f kohm\" %(R5/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Iz2>>Ib5 and Iz2> Izk for the zener diode \n",
- " when Vo=11V moving contact at top of R5 \n",
- " when Vo=13V moving contact at bottom of R5\n",
- "The value of R5 is 1.09 kohm\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.7, Page No 770"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Isc=100.0*10**-3\n",
- "Vr10=0.5\n",
- "Vo=12.0\n",
- "\n",
- "#Calculations\n",
- "R10=Vr10/Isc\n",
- "R10=4.7#use standard value\n",
- "Il=200.0*10**-3\n",
- "Vr10=Il*R10\n",
- "Vr11=Vr10-.5\n",
- "I11=1.0*10**-3\n",
- "R11=Vr11/I11\n",
- "R12=(Vo+Vr10-Vr11)/I11\n",
- "\n",
- "#Results\n",
- "print(\"The value of R12 is %.2f kohm\" %(R12/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R12 is 12.50 kohm\n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.8 Page No 778"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=12.0\n",
- "hFE1=20.0\n",
- "hFE2=50.0\n",
- "Il=250.0*10**-3\n",
- "Vz=0.75*Vo\n",
- "Vz=9.1#use standard value for 1N757 diode\n",
- "Iz1=10.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=(Vo-Vz)/Iz1\n",
- "I3=1.0*10**-3\n",
- "print(\" when V0=12V(moving contact at top of R5)\")\n",
- "R3=(Vo-Vz)/I3\n",
- "R=Vz/I3\n",
- "print(\" when Vo=15V moving contact at bottom of R5\")\n",
- "Vo=15\n",
- "I3=Vo/(R+R3)\n",
- "R4=Vz/I3\n",
- "R5=R-R4\n",
- "Ir6=.5*10**-3\n",
- "R6=Vo/Ir6\n",
- "print(\" op-amp output current\")\n",
- "Ib2=Il/(hFE1*hFE2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ib2 is %.2f mA\" %(Ib2*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " when V0=12V(moving contact at top of R5)\n",
- " when Vo=15V moving contact at bottom of R5\n",
- " op-amp output current\n",
- "The value of Ib2 is 0.25 mA\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.9 Page No 782"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "I2=1.0*10**-3\n",
- "Vr2=7.15\n",
- "Vref=Vr2\n",
- "Vo=10.0\n",
- "Pdmax=1000.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R2=Vref/I2\n",
- "R2=6.8*10**3#use standard value and recalculate the I2\n",
- "I2=Vref/R2\n",
- "R1=(Vo-Vref)/I2\n",
- "Vs=Vo+5#for satisfactory operation of series pass transistor\n",
- "Iint=25*10**-3#internal circuit current\n",
- "Pi=Vs*Iint\n",
- "print(\"maximum power dissipated in series pass transistor\")\n",
- "Pd=Pdmax-Pi\n",
- "print(\"maximum load current is \")\n",
- "Il=Pd/(Vs-Vo)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Il is %.2f mA\" %(Il*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum power dissipated in series pass transistor\n",
- "maximum load current is \n",
- "The value of Il is 125.00 mA\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.10 Page No 785"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "I1=1.0*10**-3\n",
- "Vref=1.25\n",
- "Vo=6.0\n",
- "Vs=15.0\n",
- "Il=200.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=Vref/I1\n",
- "R2=(Vo-Vref)/I1\n",
- "Pd=(Vs-Vo)*Il\n",
- "\n",
- "#Results\n",
- "print(\"regulated power dissipation is %.2f W \" %Pd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "regulated power dissipation is 1.80 W \n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.11, Page No 788"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vo=10.0\n",
- "Io=1.0\n",
- "Vce=7.0\n",
- "Vf=1.0\n",
- "\n",
- "#Calculations\n",
- "Po=Vo*Io\n",
- "print(\" linear regulator\")\n",
- "Pi=Po+(Vce*Io)\n",
- "n=(Po*100.0)/Pi#efficiency\n",
- "print(\" switching regulator\")\n",
- "Vce=1\n",
- "Pi=Po+Io*(Vce+Vf)\n",
- "n=(Po*100.0)/Pi#efficiency\n",
- "\n",
- "#Results\n",
- "print(\"The value of n is %.2f \" %(n))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " linear regulator\n",
- " switching regulator\n",
- "The value of n is 83.33 \n"
- ]
- }
- ],
- "prompt_number": 35
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.12, Page No 752"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=50.0*10**3\n",
- "Vo=12.0\n",
- "Vf=0.7\n",
- "Vi=30.0\n",
- "Vsat=1.0\n",
- "Io=500.0*10**-3\n",
- "Vr=100.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "T=1.0/f\n",
- "t=(Vo+Vf)/(Vi-Vsat-Vo)\n",
- "toff=T/1.75\n",
- "ton=T-toff\n",
- "Ip=2*Io\n",
- "L1=((Vi-Vsat-Vo)*ton)/Ip\n",
- "C1=Ip/(8.0*f*Vr)\n",
- "\n",
- "#Results\n",
- "print(\"The value of C1 is %.2f pF\" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C1 is 25.00 pF\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.13, Page No 799"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "print(\" an MC34063 controller is for step down transformer\")\n",
- "Ib=-400.0*10**-3\n",
- "I1=1.0*10**-3\n",
- "Vref=1.25\n",
- "V0=12.0\n",
- "Ip=1.0\n",
- "\n",
- "#Calculations\n",
- "ton=8.6*10**-6\n",
- "R1=Vref/I1\n",
- "R1=1.2*10**3#use standard value\n",
- "I1=Vref/R1\n",
- "R2=(Vo-Vref)/I1\n",
- "Rsc=.33/Ip\n",
- "Ct=4.8*10**-5 *ton\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ct is %.2f pF\" %(Ct*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " an MC34063 controller is for step down transformer\n",
- "The value of Ct is 0.00 pF\n"
- ]
- }
- ],
- "prompt_number": 37
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter19.ipynb b/Electronic_Devices_and_Circuits/Chapter19.ipynb deleted file mode 100755 index f144d168..00000000 --- a/Electronic_Devices_and_Circuits/Chapter19.ipynb +++ /dev/null @@ -1,1316 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 19 : Power amplifiers"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.1, Page No 810"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "Rpy=40.0\n",
- "N1=74.0\n",
- "N2=14.0\n",
- "R2=3.7*10**3\n",
- "R1=4.7*10**3\n",
- "Vbe=0.7\n",
- "Re=1.0*10**3\n",
- "Vcc=13.0\n",
- "Rl=56.0\n",
- "\n",
- "#Calculations\n",
- "print(\"Q-point\")\n",
- "Vb=Vcc*(R2/(R1+R2))\n",
- "Ic=(Vb-Vbe)/Re\n",
- "Ie=Ic\n",
- "Vce=Vcc-Ic*(Rpy+Re)\n",
- "rl=(N1/N2)**2 *Rl\n",
- "rl=rl+Rpy\n",
- "Ic=5*10**-3\n",
- "Vce=Ic*rl\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vce is %.2f v \" %Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Q-point\n",
- "The value of Vce is 8.02 v \n"
- ]
- }
- ],
- "prompt_number": 44
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.2, Page No 814"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=13.0\n",
- "Icq=5.0*10**-3\n",
- "Vceq=8.0\n",
- "Vp=Vceq\n",
- "Ip=Icq\n",
- "nt=0.8\n",
- "\n",
- "#Calculations\n",
- "Pi=Vcc*Icq\n",
- "Po=.5*Vp*Ip\n",
- "P0=nt*Po\n",
- "n=(P0/Pi)*100.0\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum efficiency is 24.62 percentage \n"
- ]
- }
- ],
- "prompt_number": 45
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.4 Page No 821"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "N1=60.0\n",
- "N2=10.0\n",
- "Rl=16.0\n",
- "Rpy=0\n",
- "R6=56.0\n",
- "Vcc=27.0\n",
- "Vce=0.5\n",
- "n=0.79\n",
- "\n",
- "#Calculations\n",
- "print(\" Referred laod\")\n",
- "rl=(N1/N2)**2 *Rl\n",
- "print(\" tatol ac load line in series with each of Q2 and Q3\")\n",
- "Rl=rl+R6+Rpy\n",
- "print(\" peak primary current\")\n",
- "Ip=(Vcc-Vce)/Rl\n",
- "print(\"peak primary voltage\")\n",
- "Vp=Vcc-Vce-(Ip*R6)\n",
- "print(\"power delivered to primary\")\n",
- "Po=.5*Vp*Ip\n",
- "\n",
- "#Calculations\n",
- "Po=Po*n#n is power efficiency\n",
- "print(\"power delivered to the load %.2f W \" %Po)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Referred laod\n",
- " tatol ac load line in series with each of Q2 and Q3\n",
- " peak primary current\n",
- "peak primary voltage\n",
- "power delivered to primary\n",
- "power delivered to the load 0.40 W \n"
- ]
- }
- ],
- "prompt_number": 46
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.5, Page No 824"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Po=4.0\n",
- "nt=0.8\n",
- "Vcc=30.0\n",
- "Vp=Vcc\n",
- "Rl=16.0\n",
- "\n",
- "#Calculations\n",
- "P0=Po/nt\n",
- "rl=(Vp)**2 /(2*P0)\n",
- "rl=4*rl\n",
- "print(\"transformer specification Po=4 %Rl=16 rl=360\")\n",
- "Vce=2.0*Vcc\n",
- "Ip=(2.0*P0)/Vp\n",
- "Pi=Vcc*.636*Ip\n",
- "Pt=0.5*(Pi-P0)\n",
- "\n",
- "#Results\n",
- "print(\" transistor specification is Py=.68W Vce=60 Ip=333mA\")\n",
- "print(\"power delivered to the load Pi = %.2f W \" %Pi)\n",
- "print(\"power delivered to the load Pt = %.2f W \" %Pt)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "transformer specification Po=4 %Rl=16 rl=360\n",
- " transistor specification is Py=.68W Vce=60 Ip=333mA\n",
- "power delivered to the load Pi = 6.36 W \n",
- "power delivered to the load Pt = 0.68 W \n"
- ]
- }
- ],
- "prompt_number": 47
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.6 Page No 830"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rl=50.0\n",
- "Po=1.0\n",
- "hFE=50.0\n",
- "Vbe=0.7\n",
- "Vrc=4.0\n",
- "Vre=1.0\n",
- "Vd1=0.7\n",
- "\n",
- "#Calculations\n",
- "Vd2=Vd1\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "Re3=.1*Rl\n",
- "Re2=4.7#use stabdard value\n",
- "Re2=Re3\n",
- "Icq=.1*Ip\n",
- "Vb=Vbe+Icq*(Re2+Re3)+Vbe\n",
- "Vc1=Vrc\n",
- "Ib2=Ip/hFE\n",
- "Irc=Ib2+1*10**-3\n",
- "Rc=Vrc/Irc\n",
- "Rc=680.0 #use standard value\n",
- "Vcc=2.0*(Vp+Vre+Vbe+Vrc)\n",
- "Vcc=32#use standard value\n",
- "Vrcdc=.5*(Vcc-Vb)\n",
- "Ic1=Vrcdc/Rc\n",
- "Rb=(Vb-Vd1-Vd2)/Ic1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kOhm \" %Rb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 8.95 kOhm \n"
- ]
- }
- ],
- "prompt_number": 48
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.7 Page No 832"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=32.0\n",
- "Vce=32.0\n",
- "Ip=200.0*10**-3\n",
- "Po=1.0\n",
- "\n",
- "#Calculations\n",
- "Ic=1.1*Ip\n",
- "Pi=0.35*Vcc*Ip\n",
- "Pt=0.5*(Pi-Po)\n",
- "\n",
- "#Results\n",
- "print(\"power delivered to the load Pi = %.2f \" %Pi)\n",
- "print(\"power delivered to the load Pt = %.2f \" %Pt)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "power delivered to the load Pi = 2.24 \n",
- "power delivered to the load Pt = 0.62 \n"
- ]
- }
- ],
- "prompt_number": 49
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.8, Page No 832"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=50.0\n",
- "hib=2.0\n",
- "Rl=50.0\n",
- "\n",
- "#Calculations\n",
- "Ce=1.0/(2*3.14*f*hib)\n",
- "Co=1.0/(2*3.14*50*.1*Rl)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ce is %.2f pF \" %(Ce*10**3))\n",
- "print(\"The value of Co is %.2f pF \" %(Co*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ce is 1.59 pF \n",
- "The value of Co is 0.64 pF \n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.9 Page No 834"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hFE=2000.0\n",
- "Vbe=1.4\n",
- "Vp=10.0\n",
- "Ip=200.0*10**-3\n",
- "Icq2=20.0*10**-3\n",
- "Re3=4.7\n",
- "Re2=4.7\n",
- "Vd=0.7\n",
- "Ve1=3.0\n",
- "Vc1=15.2\n",
- "\n",
- "#Calculations\n",
- "Vrc=Vc1\n",
- "Vb=Vbe+Icq*(Re2+Re3)+Vbe\n",
- "Vcc=Vrc+Vc1+Vb\n",
- "Ib2=Ip/hFE\n",
- "Irc=1.0*10**-3\n",
- "Vrcac=4.0\n",
- "Rc=Vrcac/Irc\n",
- "Ic1=Vrc/Rc\n",
- "Rb=(Vb-(4*Vd))/Ic1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kohm \" %Rb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 49.47 kohm \n"
- ]
- }
- ],
- "prompt_number": 51
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.10 Page No 838"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vb=3.2\n",
- "Ic1=5*10**-3\n",
- "Vce=3.2\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vbmin=Vb-0.5\n",
- "Vbmax=Vb+0.5\n",
- "I10=.1*Ic1\n",
- "R10=(Vce-Vbe)/I10\n",
- "R10=4.7*10**3#use standard value\n",
- "print(\" for Vce=3.7\")\n",
- "Vce=3.7\n",
- "I10max=(Vce-Vbe)/R10\n",
- "print(\"Vce=2.7V\")\n",
- "Vce=2.7\n",
- "I10min=(Vce-Vbe)/R10\n",
- "R=Vbe/I10min\n",
- "R11=Vbe/I10max\n",
- "R12=R-R11\n",
- "\n",
- "#Results\n",
- "print(\"The value of R12 is %.2f kohm \" %R12)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Vce=3.7\n",
- "Vce=2.7V\n",
- "The value of R12 is 548.33 kohm \n"
- ]
- }
- ],
- "prompt_number": 52
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.11 Page No 843"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=16.0\n",
- "Po=6.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2.0*Rl*Po)\n",
- "Vr14=0.1*Vp\n",
- "Vr15=Vr14\n",
- "R14=0.1*Rl\n",
- "R15=R14\n",
- "Vce3=1.0\n",
- "Vce4=Vce3\n",
- "Vr9=3.0\n",
- "Vr11=Vr9\n",
- "Vcc=(Vp+Vr14+Vbe+Vce3+Vr9)\n",
- "Vee=-Vcc\n",
- "Ip=Vp/Rl\n",
- "print(\" DC power inpit from supply line\")\n",
- "Pi=(Vcc-Vee)*.35*Ip\n",
- "Pt=.5*(Pi-Po)\n",
- "Vce=2*Vcc\n",
- "Ic=1.1*Ip\n",
- "\n",
- "#Results\n",
- "print(\" output transistor specification %.2f mA\" %Ic)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " DC power inpit from supply line\n",
- " output transistor specification 0.95 mA\n"
- ]
- }
- ],
- "prompt_number": 53
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.12, Page No 844"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "hFE7=20.0\n",
- "Icbo=50.0*10**-6\n",
- "hFE5=70.0\n",
- "Vr9=3.0\n",
- "Ip=869.0*10**-3\n",
- "R15=1.5\n",
- "R8=15.0*10**3\n",
- "Vbe=0.7\n",
- "Vr11=3.0\n",
- "Vee=20.0\n",
- "\n",
- "#Calculations\n",
- "R12=0.01/Icbo\n",
- "R12=220#use standard value\n",
- "R13=R12\n",
- "Ib5=Ip/(hFE7*hFE5)\n",
- "Ic3=2.0*10**-3\n",
- "R9=Vr9/Ic3\n",
- "R11=R9\n",
- "Iq78=0.1*Ip\n",
- "Vr14=Iq78*R15\n",
- "Vr15=Vr14\n",
- "Vr10=(Vr14+Vr15)+(Vr14+Vr15)/2\n",
- "R10=Vr10/Ic3\n",
- "Ir8=(Vr11+Vbe)/R8\n",
- "R7=(Vee-(Vr11+Vbe))/Ir8\n",
- "\n",
- "#Results\n",
- "print(\"The value of R7 is %.2f kohm \" %(R7/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R7 is 66.08 kohm \n"
- ]
- }
- ],
- "prompt_number": 54
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.13, Page No 848"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=20.0\n",
- "Po=2.5\n",
- "Rd=4.0\n",
- "Vr6=1.0\n",
- "Vr9=Vr6\n",
- "Vth=1.0\n",
- "gFS=250.0*10**-3\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "Vcc=(Vp+Ip*Rd)\n",
- "vr6=Ip/gFS\n",
- "Vr2=vr6+1\n",
- "Vce=Vr2\n",
- "Vce3=1.0\n",
- "Vr2=Vcc-Vce\n",
- "Vee=Vcc\n",
- "Vr3=Vee-Vbe\n",
- "Vr7=Vr2-Vr6\n",
- "Vr8=Vcc-(-Vee)-Vr6-Vr7-Vr9\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vr8 is %.2f V \" %Vr8)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vr8 is 14.00 V \n"
- ]
- }
- ],
- "prompt_number": 55
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.14, Page No 849"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R6=100.0*10**3\n",
- "R9=R6\n",
- "Vth=1.0\n",
- "Vr7=8.0\n",
- "Vr8=14.0\n",
- "Vr3=11.3\n",
- "Vpout=10.0\n",
- "Vpin=800.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "I6=Vth/R6\n",
- "R7=Vr7/I6\n",
- "R8=Vr8/I6\n",
- "Ic1=1*10**-4\n",
- "Ic2=Ic1\n",
- "Vr2=9\n",
- "R2=Vr2/Ic1\n",
- "R3=Vr3/(Ic1+Ic2)\n",
- "R5=4.7*10**3\n",
- "Acl=Vpout/Vpin\n",
- "R4=R5/(Acl-1.0)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R4 is %.2f kohm \" %(R4/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R4 is 0.41 kohm \n"
- ]
- }
- ],
- "prompt_number": 56
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.15, Page No 854"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vce=1.5\n",
- "Vcc=17.0\n",
- "Vd1=0.7\n",
- "R8=1.5*10**3\n",
- "R9=R8\n",
- "Rl=100.0\n",
- "R6=8.2\n",
- "\n",
- "#Calculations\n",
- "I4=(Vcc-Vd1)/(R8+R9)\n",
- "Vc3=Vcc-(I4*R8)\n",
- "print(\" bootstrap capacitance terminal voltage is %3.1fV \" %Vc3)\n",
- "V=Vcc-Vce#V=Vp+Vr6\n",
- "Ip=V/(Rl+R6)\n",
- "Vp=Ip*Rl\n",
- "print(\" peak output voltage is %3.1fV \" %Vp)\n",
- "Po=(Vp)**2.0/(2.0*Rl)\n",
- "\n",
- "#Results\n",
- "print(\" peak output power is %dW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " bootstrap capacitance terminal voltage is 8.8V \n",
- " peak output voltage is 14.3V \n",
- " peak output power is 1W \n"
- ]
- }
- ],
- "prompt_number": 57
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.16, Page No 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=8.0\n",
- "Po=6.0\n",
- "vs=0.1\n",
- "hFE=1000.0\n",
- "Vce=2.0\n",
- "f=50.0*10**3\n",
- "Vd1=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "R6=.1*Rl\n",
- "R7=R6\n",
- "Vcc=Vp+Ip*R6+Vce\n",
- "Ib=Ip/hFE\n",
- "I4=2*10**-3\n",
- "R4=(Vcc-Vd1-Vd1)/I4\n",
- "R8=.5*R4\n",
- "Acl=Vp/vs\n",
- "R3=100*10**3\n",
- "R2=R3/(Acl-1)\n",
- "SR=(2*3.14*f*Vp)*10**-6\n",
- "\n",
- "#Results\n",
- "print(\" slew rate is %.2f V/us \" %SR)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " slew rate is 3.08 V/us \n"
- ]
- }
- ],
- "prompt_number": 58
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.17, Page No 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=50.0\n",
- "R1=100.0*10**3\n",
- "R2=1.0*10**3\n",
- "R8=2.7*10**3\n",
- "\n",
- "#Calculations\n",
- "R9=R8\n",
- "C1=1/(2*3.14*f*.1*R1)\n",
- "C2=1/(2*3.14*f*R2)\n",
- "Xc3=.1*((R8*R9)/(R8+R9))\n",
- "C3=1/(2*3.14*f*Xc3)\n",
- "C4=C3\n",
- "\n",
- "#Results\n",
- "print(\"The value of C4 is %.2f pF \" %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4 is 23.59 pF \n"
- ]
- }
- ],
- "prompt_number": 59
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.18, Page No 860"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ismin=1.8*10**-3\n",
- "Ismax=3.4*10**-3\n",
- "R7=820.0\n",
- "R5=390.0\n",
- "R6=18.0*10**3\n",
- "Vi=100.0*10**-3\n",
- "Rl=10.0\n",
- "\n",
- "#Calculations\n",
- "Vgsmin=Ismin*R7\n",
- "Vgsmax=Ismax*R7\n",
- "Acl=(R5+R6)/R5\n",
- "Vp=Acl*Vi\n",
- "Ip=Vp/Rl\n",
- "print(\"peak output current is %3.3fA \" %Ip)\n",
- "Po=(Vp*Ip)/2.0\n",
- "\n",
- "#Results\n",
- "print(\"peak output power is %3.2fW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "peak output current is 0.472A \n",
- "peak output power is 1.11W \n"
- ]
- }
- ],
- "prompt_number": 60
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.19, Page No 862"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vbe=0.7\n",
- "R2=560.0\n",
- "R3min=0\n",
- "R3max=1.0*10**3\n",
- "Is=2.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Ic2max=Vbe/(R2+R3min)\n",
- "Ic2min=Vbe/(R2+R3max)\n",
- "Vgsmin=(Is+Ic2min)*820.0\n",
- "Vgsmax=(Is+Ic2max)*820.0\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vgsmax is %.2f v \" %Vgsmax)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vgsmax is 2.67 v \n"
- ]
- }
- ],
- "prompt_number": 61
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.20, Page No 865"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=12.0\n",
- "Rl=10.0\n",
- "Rd=0.5\n",
- "gfs=2.5\n",
- "R7=820.0\n",
- "V9=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R10=R9\n",
- "Vp=(Vcc*Rl)/(Rd+Rl)\n",
- "Ip=Vp/Rl\n",
- "Vgs=Ip/gfs\n",
- "Vr7=Is*R7\n",
- "Vs=Vcc-Vr7-Vgs\n",
- "Vr9=(Vp*R9)/(R9+R10)\n",
- "\n",
- "#Results\n",
- "print(\"op-amp peak output voltage is %.2f v \" %Vr9)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "op-amp peak output voltage is 5.71 v \n"
- ]
- }
- ],
- "prompt_number": 62
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.21, Page No 867"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=0.7\n",
- "R2=470.0\n",
- "R3=1.0*10**3\n",
- "Is=0.5*10**-3\n",
- "R7=1.5*10**3\n",
- "Vcc=15\n",
- "\n",
- "#Calculations\n",
- "Ic2max=Vbe/R2\n",
- "Ic2min=Vbe/(R2+R3)\n",
- "Vgs=(Is+Ic2max)*R7\n",
- "print(\" MOSFET maximum gate source voltage is %.1fV \" %Vgs)\n",
- "Vs=Vcc-Vgs\n",
- "\n",
- "#Results\n",
- "print(\" op-amp minimum suppy is %.2fV \" %Vs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " MOSFET maximum gate source voltage is 3.0V \n",
- " op-amp minimum suppy is 12.02V \n"
- ]
- }
- ],
- "prompt_number": 63
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.22, Page No 868"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=15.0\n",
- "Rl=15.0\n",
- "Rd=0.3\n",
- "R5=2.2*10**3\n",
- "R6=33.0*10**3\n",
- "C2=3.9*10**-6\n",
- "C4=100.0*10**-12\n",
- "\n",
- "#Calculations\n",
- "print(\" power output\")\n",
- "Vp=(Vcc*Rl)/(Rd+Rl)\n",
- "Ip=Vp/Rl\n",
- "Po=(Vp*Ip)/2.0\n",
- "print(\" voltage gain\")\n",
- "Av=(R5+R6)/R5\n",
- "print(\"cutoff frequency\")\n",
- "f1=1.0/(2*3.14*C2*R5)\n",
- "f2=1.0/(2*3.14*C4*R6)\n",
- "\n",
- "#Results\n",
- "print(\" cutoff frequency f1 %.2f \" %f1)\n",
- "print(\" cutoff frequency f2 %.2f \" %f2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " power output\n",
- " voltage gain\n",
- "cutoff frequency\n",
- " cutoff frequency f1 18.56 \n",
- " cutoff frequency f2 48253.23 \n"
- ]
- }
- ],
- "prompt_number": 64
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.23, Page No 871"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=23.0\n",
- "Rl=8.0\n",
- "Rf2=100.0*10**3\n",
- "Rf1=5.6*10**3\n",
- "Cf=1.0*10**-6\n",
- "Vp=Vcc-5\n",
- "\n",
- "#Calculations\n",
- "Po=(Vp)**2/(2*Rl)\n",
- "print(\"maximum output power is %3.2fW \" %Po)\n",
- "Acl=(Rf1+Rf2)/Rf1\n",
- "print(\" voltage gain %3.1f \" %Acl)\n",
- "f=1/(2*3.14*Cf*Rf1)\n",
- "\n",
- "#Results\n",
- "print(\"lower cutoff frequency is %dHz \" %f)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum output power is 20.25W \n",
- " voltage gain 18.9 \n",
- "lower cutoff frequency is 28Hz \n"
- ]
- }
- ],
- "prompt_number": 65
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.24, Page No 875"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rf=15.0*10**3\n",
- "R1=5.6*10**3\n",
- "vs=0.5\n",
- "Vp=2.7\n",
- "\n",
- "#Calculations\n",
- "Acl=(2.0*Rf)/R1\n",
- "Vo=Acl*vs\n",
- "Po=(Vp)**2.0/(2.0*Rl)\n",
- "\n",
- "#Results\n",
- "print(\"load power dissipation is %.2fW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "load power dissipation is 0.46W \n"
- ]
- }
- ],
- "prompt_number": 66
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.24, Page No 875"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=10.0\n",
- "Rl=1.0*10**3\n",
- "f=3.0*10**6\n",
- "Ip=25.0*10**-3\n",
- "Vce=0.3\n",
- "\n",
- "#Calculations\n",
- "Vp=Vcc-Vce\n",
- "Po=(Vp)**2 /(2*Rl)\n",
- "T=1.0/f\n",
- "t=(Po*T)/(Ip*Vp)\n",
- "angle=(t/T)*360\n",
- "print(\" conduction angle is %3.1fdegree \" %angle)\n",
- "Idc=Po/Vp\n",
- "Pi=Vcc*Idc\n",
- "print( \"dc input power is %3.4fW \" %Pi)\n",
- "n=(Po/Pi)*100#efficiency\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " conduction angle is 69.8degree \n",
- "dc input power is 0.0485W \n",
- " maximum efficiency is 97.00 percentage \n"
- ]
- }
- ],
- "prompt_number": 67
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.26, Page No 882"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=1.0*10**6\n",
- "Xc=120.0\n",
- "Vce=0.5\n",
- "Vcc=30.0\n",
- "Rl=1.2*10**3\n",
- "O=100.0\n",
- "\n",
- "#Calculations\n",
- "Cp=1.0/(2*3.14*f*Xc)\n",
- "Cp=1300*10**-12#use standard value\n",
- "Lp=1/(((2*3.14*f)**2)*Cp)\n",
- "Vp=Vcc-Vce\n",
- "Po=((Vp)**2) /(2*Rl)\n",
- "Idc=Po/Vp\n",
- "T=1.0/f\n",
- "t=(O*T)/360.0\n",
- "Ip=(Idc*T)/t\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ip is %.2f mA \" %(Ip*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ip is 44.25 mA \n"
- ]
- }
- ],
- "prompt_number": 68
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.27, Page No 883"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rw=0.1\n",
- "f=1.0*10**6\n",
- "Lp=19.5*10**-6\n",
- "Rl=1.2*10**3\n",
- "Vcc=30.0\n",
- "\n",
- "#Calculations\n",
- "Idc=12.3*10**-3\n",
- "QL=(2*3.14*f*Lp)/Rw\n",
- "Qp=Rl/(2*3.14*f*Lp)\n",
- "B=f/Qp\n",
- "Il=(.707*Vp)/(2*3.14*f*Lp)\n",
- "Pl=(Il)**2 *Rw\n",
- "Pi=(Vcc*Idc)+Pl\n",
- "n=(Po/Pi)*100.0\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum efficiency is 97.50 percentage \n"
- ]
- }
- ],
- "prompt_number": 69
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter19_1.ipynb b/Electronic_Devices_and_Circuits/Chapter19_1.ipynb deleted file mode 100755 index f144d168..00000000 --- a/Electronic_Devices_and_Circuits/Chapter19_1.ipynb +++ /dev/null @@ -1,1316 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 19 : Power amplifiers"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.1, Page No 810"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "Rpy=40.0\n",
- "N1=74.0\n",
- "N2=14.0\n",
- "R2=3.7*10**3\n",
- "R1=4.7*10**3\n",
- "Vbe=0.7\n",
- "Re=1.0*10**3\n",
- "Vcc=13.0\n",
- "Rl=56.0\n",
- "\n",
- "#Calculations\n",
- "print(\"Q-point\")\n",
- "Vb=Vcc*(R2/(R1+R2))\n",
- "Ic=(Vb-Vbe)/Re\n",
- "Ie=Ic\n",
- "Vce=Vcc-Ic*(Rpy+Re)\n",
- "rl=(N1/N2)**2 *Rl\n",
- "rl=rl+Rpy\n",
- "Ic=5*10**-3\n",
- "Vce=Ic*rl\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vce is %.2f v \" %Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Q-point\n",
- "The value of Vce is 8.02 v \n"
- ]
- }
- ],
- "prompt_number": 44
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.2, Page No 814"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=13.0\n",
- "Icq=5.0*10**-3\n",
- "Vceq=8.0\n",
- "Vp=Vceq\n",
- "Ip=Icq\n",
- "nt=0.8\n",
- "\n",
- "#Calculations\n",
- "Pi=Vcc*Icq\n",
- "Po=.5*Vp*Ip\n",
- "P0=nt*Po\n",
- "n=(P0/Pi)*100.0\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum efficiency is 24.62 percentage \n"
- ]
- }
- ],
- "prompt_number": 45
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.4 Page No 821"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "N1=60.0\n",
- "N2=10.0\n",
- "Rl=16.0\n",
- "Rpy=0\n",
- "R6=56.0\n",
- "Vcc=27.0\n",
- "Vce=0.5\n",
- "n=0.79\n",
- "\n",
- "#Calculations\n",
- "print(\" Referred laod\")\n",
- "rl=(N1/N2)**2 *Rl\n",
- "print(\" tatol ac load line in series with each of Q2 and Q3\")\n",
- "Rl=rl+R6+Rpy\n",
- "print(\" peak primary current\")\n",
- "Ip=(Vcc-Vce)/Rl\n",
- "print(\"peak primary voltage\")\n",
- "Vp=Vcc-Vce-(Ip*R6)\n",
- "print(\"power delivered to primary\")\n",
- "Po=.5*Vp*Ip\n",
- "\n",
- "#Calculations\n",
- "Po=Po*n#n is power efficiency\n",
- "print(\"power delivered to the load %.2f W \" %Po)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Referred laod\n",
- " tatol ac load line in series with each of Q2 and Q3\n",
- " peak primary current\n",
- "peak primary voltage\n",
- "power delivered to primary\n",
- "power delivered to the load 0.40 W \n"
- ]
- }
- ],
- "prompt_number": 46
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.5, Page No 824"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Po=4.0\n",
- "nt=0.8\n",
- "Vcc=30.0\n",
- "Vp=Vcc\n",
- "Rl=16.0\n",
- "\n",
- "#Calculations\n",
- "P0=Po/nt\n",
- "rl=(Vp)**2 /(2*P0)\n",
- "rl=4*rl\n",
- "print(\"transformer specification Po=4 %Rl=16 rl=360\")\n",
- "Vce=2.0*Vcc\n",
- "Ip=(2.0*P0)/Vp\n",
- "Pi=Vcc*.636*Ip\n",
- "Pt=0.5*(Pi-P0)\n",
- "\n",
- "#Results\n",
- "print(\" transistor specification is Py=.68W Vce=60 Ip=333mA\")\n",
- "print(\"power delivered to the load Pi = %.2f W \" %Pi)\n",
- "print(\"power delivered to the load Pt = %.2f W \" %Pt)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "transformer specification Po=4 %Rl=16 rl=360\n",
- " transistor specification is Py=.68W Vce=60 Ip=333mA\n",
- "power delivered to the load Pi = 6.36 W \n",
- "power delivered to the load Pt = 0.68 W \n"
- ]
- }
- ],
- "prompt_number": 47
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.6 Page No 830"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rl=50.0\n",
- "Po=1.0\n",
- "hFE=50.0\n",
- "Vbe=0.7\n",
- "Vrc=4.0\n",
- "Vre=1.0\n",
- "Vd1=0.7\n",
- "\n",
- "#Calculations\n",
- "Vd2=Vd1\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "Re3=.1*Rl\n",
- "Re2=4.7#use stabdard value\n",
- "Re2=Re3\n",
- "Icq=.1*Ip\n",
- "Vb=Vbe+Icq*(Re2+Re3)+Vbe\n",
- "Vc1=Vrc\n",
- "Ib2=Ip/hFE\n",
- "Irc=Ib2+1*10**-3\n",
- "Rc=Vrc/Irc\n",
- "Rc=680.0 #use standard value\n",
- "Vcc=2.0*(Vp+Vre+Vbe+Vrc)\n",
- "Vcc=32#use standard value\n",
- "Vrcdc=.5*(Vcc-Vb)\n",
- "Ic1=Vrcdc/Rc\n",
- "Rb=(Vb-Vd1-Vd2)/Ic1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kOhm \" %Rb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 8.95 kOhm \n"
- ]
- }
- ],
- "prompt_number": 48
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.7 Page No 832"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=32.0\n",
- "Vce=32.0\n",
- "Ip=200.0*10**-3\n",
- "Po=1.0\n",
- "\n",
- "#Calculations\n",
- "Ic=1.1*Ip\n",
- "Pi=0.35*Vcc*Ip\n",
- "Pt=0.5*(Pi-Po)\n",
- "\n",
- "#Results\n",
- "print(\"power delivered to the load Pi = %.2f \" %Pi)\n",
- "print(\"power delivered to the load Pt = %.2f \" %Pt)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "power delivered to the load Pi = 2.24 \n",
- "power delivered to the load Pt = 0.62 \n"
- ]
- }
- ],
- "prompt_number": 49
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.8, Page No 832"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=50.0\n",
- "hib=2.0\n",
- "Rl=50.0\n",
- "\n",
- "#Calculations\n",
- "Ce=1.0/(2*3.14*f*hib)\n",
- "Co=1.0/(2*3.14*50*.1*Rl)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ce is %.2f pF \" %(Ce*10**3))\n",
- "print(\"The value of Co is %.2f pF \" %(Co*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ce is 1.59 pF \n",
- "The value of Co is 0.64 pF \n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.9 Page No 834"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hFE=2000.0\n",
- "Vbe=1.4\n",
- "Vp=10.0\n",
- "Ip=200.0*10**-3\n",
- "Icq2=20.0*10**-3\n",
- "Re3=4.7\n",
- "Re2=4.7\n",
- "Vd=0.7\n",
- "Ve1=3.0\n",
- "Vc1=15.2\n",
- "\n",
- "#Calculations\n",
- "Vrc=Vc1\n",
- "Vb=Vbe+Icq*(Re2+Re3)+Vbe\n",
- "Vcc=Vrc+Vc1+Vb\n",
- "Ib2=Ip/hFE\n",
- "Irc=1.0*10**-3\n",
- "Vrcac=4.0\n",
- "Rc=Vrcac/Irc\n",
- "Ic1=Vrc/Rc\n",
- "Rb=(Vb-(4*Vd))/Ic1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kohm \" %Rb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 49.47 kohm \n"
- ]
- }
- ],
- "prompt_number": 51
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.10 Page No 838"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vb=3.2\n",
- "Ic1=5*10**-3\n",
- "Vce=3.2\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vbmin=Vb-0.5\n",
- "Vbmax=Vb+0.5\n",
- "I10=.1*Ic1\n",
- "R10=(Vce-Vbe)/I10\n",
- "R10=4.7*10**3#use standard value\n",
- "print(\" for Vce=3.7\")\n",
- "Vce=3.7\n",
- "I10max=(Vce-Vbe)/R10\n",
- "print(\"Vce=2.7V\")\n",
- "Vce=2.7\n",
- "I10min=(Vce-Vbe)/R10\n",
- "R=Vbe/I10min\n",
- "R11=Vbe/I10max\n",
- "R12=R-R11\n",
- "\n",
- "#Results\n",
- "print(\"The value of R12 is %.2f kohm \" %R12)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Vce=3.7\n",
- "Vce=2.7V\n",
- "The value of R12 is 548.33 kohm \n"
- ]
- }
- ],
- "prompt_number": 52
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.11 Page No 843"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=16.0\n",
- "Po=6.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2.0*Rl*Po)\n",
- "Vr14=0.1*Vp\n",
- "Vr15=Vr14\n",
- "R14=0.1*Rl\n",
- "R15=R14\n",
- "Vce3=1.0\n",
- "Vce4=Vce3\n",
- "Vr9=3.0\n",
- "Vr11=Vr9\n",
- "Vcc=(Vp+Vr14+Vbe+Vce3+Vr9)\n",
- "Vee=-Vcc\n",
- "Ip=Vp/Rl\n",
- "print(\" DC power inpit from supply line\")\n",
- "Pi=(Vcc-Vee)*.35*Ip\n",
- "Pt=.5*(Pi-Po)\n",
- "Vce=2*Vcc\n",
- "Ic=1.1*Ip\n",
- "\n",
- "#Results\n",
- "print(\" output transistor specification %.2f mA\" %Ic)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " DC power inpit from supply line\n",
- " output transistor specification 0.95 mA\n"
- ]
- }
- ],
- "prompt_number": 53
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.12, Page No 844"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "hFE7=20.0\n",
- "Icbo=50.0*10**-6\n",
- "hFE5=70.0\n",
- "Vr9=3.0\n",
- "Ip=869.0*10**-3\n",
- "R15=1.5\n",
- "R8=15.0*10**3\n",
- "Vbe=0.7\n",
- "Vr11=3.0\n",
- "Vee=20.0\n",
- "\n",
- "#Calculations\n",
- "R12=0.01/Icbo\n",
- "R12=220#use standard value\n",
- "R13=R12\n",
- "Ib5=Ip/(hFE7*hFE5)\n",
- "Ic3=2.0*10**-3\n",
- "R9=Vr9/Ic3\n",
- "R11=R9\n",
- "Iq78=0.1*Ip\n",
- "Vr14=Iq78*R15\n",
- "Vr15=Vr14\n",
- "Vr10=(Vr14+Vr15)+(Vr14+Vr15)/2\n",
- "R10=Vr10/Ic3\n",
- "Ir8=(Vr11+Vbe)/R8\n",
- "R7=(Vee-(Vr11+Vbe))/Ir8\n",
- "\n",
- "#Results\n",
- "print(\"The value of R7 is %.2f kohm \" %(R7/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R7 is 66.08 kohm \n"
- ]
- }
- ],
- "prompt_number": 54
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.13, Page No 848"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=20.0\n",
- "Po=2.5\n",
- "Rd=4.0\n",
- "Vr6=1.0\n",
- "Vr9=Vr6\n",
- "Vth=1.0\n",
- "gFS=250.0*10**-3\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "Vcc=(Vp+Ip*Rd)\n",
- "vr6=Ip/gFS\n",
- "Vr2=vr6+1\n",
- "Vce=Vr2\n",
- "Vce3=1.0\n",
- "Vr2=Vcc-Vce\n",
- "Vee=Vcc\n",
- "Vr3=Vee-Vbe\n",
- "Vr7=Vr2-Vr6\n",
- "Vr8=Vcc-(-Vee)-Vr6-Vr7-Vr9\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vr8 is %.2f V \" %Vr8)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vr8 is 14.00 V \n"
- ]
- }
- ],
- "prompt_number": 55
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.14, Page No 849"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R6=100.0*10**3\n",
- "R9=R6\n",
- "Vth=1.0\n",
- "Vr7=8.0\n",
- "Vr8=14.0\n",
- "Vr3=11.3\n",
- "Vpout=10.0\n",
- "Vpin=800.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "I6=Vth/R6\n",
- "R7=Vr7/I6\n",
- "R8=Vr8/I6\n",
- "Ic1=1*10**-4\n",
- "Ic2=Ic1\n",
- "Vr2=9\n",
- "R2=Vr2/Ic1\n",
- "R3=Vr3/(Ic1+Ic2)\n",
- "R5=4.7*10**3\n",
- "Acl=Vpout/Vpin\n",
- "R4=R5/(Acl-1.0)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R4 is %.2f kohm \" %(R4/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R4 is 0.41 kohm \n"
- ]
- }
- ],
- "prompt_number": 56
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.15, Page No 854"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vce=1.5\n",
- "Vcc=17.0\n",
- "Vd1=0.7\n",
- "R8=1.5*10**3\n",
- "R9=R8\n",
- "Rl=100.0\n",
- "R6=8.2\n",
- "\n",
- "#Calculations\n",
- "I4=(Vcc-Vd1)/(R8+R9)\n",
- "Vc3=Vcc-(I4*R8)\n",
- "print(\" bootstrap capacitance terminal voltage is %3.1fV \" %Vc3)\n",
- "V=Vcc-Vce#V=Vp+Vr6\n",
- "Ip=V/(Rl+R6)\n",
- "Vp=Ip*Rl\n",
- "print(\" peak output voltage is %3.1fV \" %Vp)\n",
- "Po=(Vp)**2.0/(2.0*Rl)\n",
- "\n",
- "#Results\n",
- "print(\" peak output power is %dW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " bootstrap capacitance terminal voltage is 8.8V \n",
- " peak output voltage is 14.3V \n",
- " peak output power is 1W \n"
- ]
- }
- ],
- "prompt_number": 57
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.16, Page No 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=8.0\n",
- "Po=6.0\n",
- "vs=0.1\n",
- "hFE=1000.0\n",
- "Vce=2.0\n",
- "f=50.0*10**3\n",
- "Vd1=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "R6=.1*Rl\n",
- "R7=R6\n",
- "Vcc=Vp+Ip*R6+Vce\n",
- "Ib=Ip/hFE\n",
- "I4=2*10**-3\n",
- "R4=(Vcc-Vd1-Vd1)/I4\n",
- "R8=.5*R4\n",
- "Acl=Vp/vs\n",
- "R3=100*10**3\n",
- "R2=R3/(Acl-1)\n",
- "SR=(2*3.14*f*Vp)*10**-6\n",
- "\n",
- "#Results\n",
- "print(\" slew rate is %.2f V/us \" %SR)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " slew rate is 3.08 V/us \n"
- ]
- }
- ],
- "prompt_number": 58
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.17, Page No 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=50.0\n",
- "R1=100.0*10**3\n",
- "R2=1.0*10**3\n",
- "R8=2.7*10**3\n",
- "\n",
- "#Calculations\n",
- "R9=R8\n",
- "C1=1/(2*3.14*f*.1*R1)\n",
- "C2=1/(2*3.14*f*R2)\n",
- "Xc3=.1*((R8*R9)/(R8+R9))\n",
- "C3=1/(2*3.14*f*Xc3)\n",
- "C4=C3\n",
- "\n",
- "#Results\n",
- "print(\"The value of C4 is %.2f pF \" %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4 is 23.59 pF \n"
- ]
- }
- ],
- "prompt_number": 59
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.18, Page No 860"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ismin=1.8*10**-3\n",
- "Ismax=3.4*10**-3\n",
- "R7=820.0\n",
- "R5=390.0\n",
- "R6=18.0*10**3\n",
- "Vi=100.0*10**-3\n",
- "Rl=10.0\n",
- "\n",
- "#Calculations\n",
- "Vgsmin=Ismin*R7\n",
- "Vgsmax=Ismax*R7\n",
- "Acl=(R5+R6)/R5\n",
- "Vp=Acl*Vi\n",
- "Ip=Vp/Rl\n",
- "print(\"peak output current is %3.3fA \" %Ip)\n",
- "Po=(Vp*Ip)/2.0\n",
- "\n",
- "#Results\n",
- "print(\"peak output power is %3.2fW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "peak output current is 0.472A \n",
- "peak output power is 1.11W \n"
- ]
- }
- ],
- "prompt_number": 60
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.19, Page No 862"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vbe=0.7\n",
- "R2=560.0\n",
- "R3min=0\n",
- "R3max=1.0*10**3\n",
- "Is=2.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Ic2max=Vbe/(R2+R3min)\n",
- "Ic2min=Vbe/(R2+R3max)\n",
- "Vgsmin=(Is+Ic2min)*820.0\n",
- "Vgsmax=(Is+Ic2max)*820.0\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vgsmax is %.2f v \" %Vgsmax)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vgsmax is 2.67 v \n"
- ]
- }
- ],
- "prompt_number": 61
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.20, Page No 865"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=12.0\n",
- "Rl=10.0\n",
- "Rd=0.5\n",
- "gfs=2.5\n",
- "R7=820.0\n",
- "V9=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R10=R9\n",
- "Vp=(Vcc*Rl)/(Rd+Rl)\n",
- "Ip=Vp/Rl\n",
- "Vgs=Ip/gfs\n",
- "Vr7=Is*R7\n",
- "Vs=Vcc-Vr7-Vgs\n",
- "Vr9=(Vp*R9)/(R9+R10)\n",
- "\n",
- "#Results\n",
- "print(\"op-amp peak output voltage is %.2f v \" %Vr9)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "op-amp peak output voltage is 5.71 v \n"
- ]
- }
- ],
- "prompt_number": 62
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.21, Page No 867"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=0.7\n",
- "R2=470.0\n",
- "R3=1.0*10**3\n",
- "Is=0.5*10**-3\n",
- "R7=1.5*10**3\n",
- "Vcc=15\n",
- "\n",
- "#Calculations\n",
- "Ic2max=Vbe/R2\n",
- "Ic2min=Vbe/(R2+R3)\n",
- "Vgs=(Is+Ic2max)*R7\n",
- "print(\" MOSFET maximum gate source voltage is %.1fV \" %Vgs)\n",
- "Vs=Vcc-Vgs\n",
- "\n",
- "#Results\n",
- "print(\" op-amp minimum suppy is %.2fV \" %Vs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " MOSFET maximum gate source voltage is 3.0V \n",
- " op-amp minimum suppy is 12.02V \n"
- ]
- }
- ],
- "prompt_number": 63
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.22, Page No 868"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=15.0\n",
- "Rl=15.0\n",
- "Rd=0.3\n",
- "R5=2.2*10**3\n",
- "R6=33.0*10**3\n",
- "C2=3.9*10**-6\n",
- "C4=100.0*10**-12\n",
- "\n",
- "#Calculations\n",
- "print(\" power output\")\n",
- "Vp=(Vcc*Rl)/(Rd+Rl)\n",
- "Ip=Vp/Rl\n",
- "Po=(Vp*Ip)/2.0\n",
- "print(\" voltage gain\")\n",
- "Av=(R5+R6)/R5\n",
- "print(\"cutoff frequency\")\n",
- "f1=1.0/(2*3.14*C2*R5)\n",
- "f2=1.0/(2*3.14*C4*R6)\n",
- "\n",
- "#Results\n",
- "print(\" cutoff frequency f1 %.2f \" %f1)\n",
- "print(\" cutoff frequency f2 %.2f \" %f2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " power output\n",
- " voltage gain\n",
- "cutoff frequency\n",
- " cutoff frequency f1 18.56 \n",
- " cutoff frequency f2 48253.23 \n"
- ]
- }
- ],
- "prompt_number": 64
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.23, Page No 871"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=23.0\n",
- "Rl=8.0\n",
- "Rf2=100.0*10**3\n",
- "Rf1=5.6*10**3\n",
- "Cf=1.0*10**-6\n",
- "Vp=Vcc-5\n",
- "\n",
- "#Calculations\n",
- "Po=(Vp)**2/(2*Rl)\n",
- "print(\"maximum output power is %3.2fW \" %Po)\n",
- "Acl=(Rf1+Rf2)/Rf1\n",
- "print(\" voltage gain %3.1f \" %Acl)\n",
- "f=1/(2*3.14*Cf*Rf1)\n",
- "\n",
- "#Results\n",
- "print(\"lower cutoff frequency is %dHz \" %f)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum output power is 20.25W \n",
- " voltage gain 18.9 \n",
- "lower cutoff frequency is 28Hz \n"
- ]
- }
- ],
- "prompt_number": 65
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.24, Page No 875"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rf=15.0*10**3\n",
- "R1=5.6*10**3\n",
- "vs=0.5\n",
- "Vp=2.7\n",
- "\n",
- "#Calculations\n",
- "Acl=(2.0*Rf)/R1\n",
- "Vo=Acl*vs\n",
- "Po=(Vp)**2.0/(2.0*Rl)\n",
- "\n",
- "#Results\n",
- "print(\"load power dissipation is %.2fW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "load power dissipation is 0.46W \n"
- ]
- }
- ],
- "prompt_number": 66
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.24, Page No 875"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=10.0\n",
- "Rl=1.0*10**3\n",
- "f=3.0*10**6\n",
- "Ip=25.0*10**-3\n",
- "Vce=0.3\n",
- "\n",
- "#Calculations\n",
- "Vp=Vcc-Vce\n",
- "Po=(Vp)**2 /(2*Rl)\n",
- "T=1.0/f\n",
- "t=(Po*T)/(Ip*Vp)\n",
- "angle=(t/T)*360\n",
- "print(\" conduction angle is %3.1fdegree \" %angle)\n",
- "Idc=Po/Vp\n",
- "Pi=Vcc*Idc\n",
- "print( \"dc input power is %3.4fW \" %Pi)\n",
- "n=(Po/Pi)*100#efficiency\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " conduction angle is 69.8degree \n",
- "dc input power is 0.0485W \n",
- " maximum efficiency is 97.00 percentage \n"
- ]
- }
- ],
- "prompt_number": 67
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.26, Page No 882"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=1.0*10**6\n",
- "Xc=120.0\n",
- "Vce=0.5\n",
- "Vcc=30.0\n",
- "Rl=1.2*10**3\n",
- "O=100.0\n",
- "\n",
- "#Calculations\n",
- "Cp=1.0/(2*3.14*f*Xc)\n",
- "Cp=1300*10**-12#use standard value\n",
- "Lp=1/(((2*3.14*f)**2)*Cp)\n",
- "Vp=Vcc-Vce\n",
- "Po=((Vp)**2) /(2*Rl)\n",
- "Idc=Po/Vp\n",
- "T=1.0/f\n",
- "t=(O*T)/360.0\n",
- "Ip=(Idc*T)/t\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ip is %.2f mA \" %(Ip*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ip is 44.25 mA \n"
- ]
- }
- ],
- "prompt_number": 68
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.27, Page No 883"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rw=0.1\n",
- "f=1.0*10**6\n",
- "Lp=19.5*10**-6\n",
- "Rl=1.2*10**3\n",
- "Vcc=30.0\n",
- "\n",
- "#Calculations\n",
- "Idc=12.3*10**-3\n",
- "QL=(2*3.14*f*Lp)/Rw\n",
- "Qp=Rl/(2*3.14*f*Lp)\n",
- "B=f/Qp\n",
- "Il=(.707*Vp)/(2*3.14*f*Lp)\n",
- "Pl=(Il)**2 *Rw\n",
- "Pi=(Vcc*Idc)+Pl\n",
- "n=(Po/Pi)*100.0\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum efficiency is 97.50 percentage \n"
- ]
- }
- ],
- "prompt_number": 69
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter19_2.ipynb b/Electronic_Devices_and_Circuits/Chapter19_2.ipynb deleted file mode 100755 index f144d168..00000000 --- a/Electronic_Devices_and_Circuits/Chapter19_2.ipynb +++ /dev/null @@ -1,1316 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 19 : Power amplifiers"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.1, Page No 810"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "Rpy=40.0\n",
- "N1=74.0\n",
- "N2=14.0\n",
- "R2=3.7*10**3\n",
- "R1=4.7*10**3\n",
- "Vbe=0.7\n",
- "Re=1.0*10**3\n",
- "Vcc=13.0\n",
- "Rl=56.0\n",
- "\n",
- "#Calculations\n",
- "print(\"Q-point\")\n",
- "Vb=Vcc*(R2/(R1+R2))\n",
- "Ic=(Vb-Vbe)/Re\n",
- "Ie=Ic\n",
- "Vce=Vcc-Ic*(Rpy+Re)\n",
- "rl=(N1/N2)**2 *Rl\n",
- "rl=rl+Rpy\n",
- "Ic=5*10**-3\n",
- "Vce=Ic*rl\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vce is %.2f v \" %Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Q-point\n",
- "The value of Vce is 8.02 v \n"
- ]
- }
- ],
- "prompt_number": 44
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.2, Page No 814"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=13.0\n",
- "Icq=5.0*10**-3\n",
- "Vceq=8.0\n",
- "Vp=Vceq\n",
- "Ip=Icq\n",
- "nt=0.8\n",
- "\n",
- "#Calculations\n",
- "Pi=Vcc*Icq\n",
- "Po=.5*Vp*Ip\n",
- "P0=nt*Po\n",
- "n=(P0/Pi)*100.0\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum efficiency is 24.62 percentage \n"
- ]
- }
- ],
- "prompt_number": 45
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.4 Page No 821"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "N1=60.0\n",
- "N2=10.0\n",
- "Rl=16.0\n",
- "Rpy=0\n",
- "R6=56.0\n",
- "Vcc=27.0\n",
- "Vce=0.5\n",
- "n=0.79\n",
- "\n",
- "#Calculations\n",
- "print(\" Referred laod\")\n",
- "rl=(N1/N2)**2 *Rl\n",
- "print(\" tatol ac load line in series with each of Q2 and Q3\")\n",
- "Rl=rl+R6+Rpy\n",
- "print(\" peak primary current\")\n",
- "Ip=(Vcc-Vce)/Rl\n",
- "print(\"peak primary voltage\")\n",
- "Vp=Vcc-Vce-(Ip*R6)\n",
- "print(\"power delivered to primary\")\n",
- "Po=.5*Vp*Ip\n",
- "\n",
- "#Calculations\n",
- "Po=Po*n#n is power efficiency\n",
- "print(\"power delivered to the load %.2f W \" %Po)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Referred laod\n",
- " tatol ac load line in series with each of Q2 and Q3\n",
- " peak primary current\n",
- "peak primary voltage\n",
- "power delivered to primary\n",
- "power delivered to the load 0.40 W \n"
- ]
- }
- ],
- "prompt_number": 46
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.5, Page No 824"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Po=4.0\n",
- "nt=0.8\n",
- "Vcc=30.0\n",
- "Vp=Vcc\n",
- "Rl=16.0\n",
- "\n",
- "#Calculations\n",
- "P0=Po/nt\n",
- "rl=(Vp)**2 /(2*P0)\n",
- "rl=4*rl\n",
- "print(\"transformer specification Po=4 %Rl=16 rl=360\")\n",
- "Vce=2.0*Vcc\n",
- "Ip=(2.0*P0)/Vp\n",
- "Pi=Vcc*.636*Ip\n",
- "Pt=0.5*(Pi-P0)\n",
- "\n",
- "#Results\n",
- "print(\" transistor specification is Py=.68W Vce=60 Ip=333mA\")\n",
- "print(\"power delivered to the load Pi = %.2f W \" %Pi)\n",
- "print(\"power delivered to the load Pt = %.2f W \" %Pt)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "transformer specification Po=4 %Rl=16 rl=360\n",
- " transistor specification is Py=.68W Vce=60 Ip=333mA\n",
- "power delivered to the load Pi = 6.36 W \n",
- "power delivered to the load Pt = 0.68 W \n"
- ]
- }
- ],
- "prompt_number": 47
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.6 Page No 830"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rl=50.0\n",
- "Po=1.0\n",
- "hFE=50.0\n",
- "Vbe=0.7\n",
- "Vrc=4.0\n",
- "Vre=1.0\n",
- "Vd1=0.7\n",
- "\n",
- "#Calculations\n",
- "Vd2=Vd1\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "Re3=.1*Rl\n",
- "Re2=4.7#use stabdard value\n",
- "Re2=Re3\n",
- "Icq=.1*Ip\n",
- "Vb=Vbe+Icq*(Re2+Re3)+Vbe\n",
- "Vc1=Vrc\n",
- "Ib2=Ip/hFE\n",
- "Irc=Ib2+1*10**-3\n",
- "Rc=Vrc/Irc\n",
- "Rc=680.0 #use standard value\n",
- "Vcc=2.0*(Vp+Vre+Vbe+Vrc)\n",
- "Vcc=32#use standard value\n",
- "Vrcdc=.5*(Vcc-Vb)\n",
- "Ic1=Vrcdc/Rc\n",
- "Rb=(Vb-Vd1-Vd2)/Ic1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kOhm \" %Rb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 8.95 kOhm \n"
- ]
- }
- ],
- "prompt_number": 48
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.7 Page No 832"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=32.0\n",
- "Vce=32.0\n",
- "Ip=200.0*10**-3\n",
- "Po=1.0\n",
- "\n",
- "#Calculations\n",
- "Ic=1.1*Ip\n",
- "Pi=0.35*Vcc*Ip\n",
- "Pt=0.5*(Pi-Po)\n",
- "\n",
- "#Results\n",
- "print(\"power delivered to the load Pi = %.2f \" %Pi)\n",
- "print(\"power delivered to the load Pt = %.2f \" %Pt)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "power delivered to the load Pi = 2.24 \n",
- "power delivered to the load Pt = 0.62 \n"
- ]
- }
- ],
- "prompt_number": 49
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.8, Page No 832"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=50.0\n",
- "hib=2.0\n",
- "Rl=50.0\n",
- "\n",
- "#Calculations\n",
- "Ce=1.0/(2*3.14*f*hib)\n",
- "Co=1.0/(2*3.14*50*.1*Rl)\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ce is %.2f pF \" %(Ce*10**3))\n",
- "print(\"The value of Co is %.2f pF \" %(Co*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ce is 1.59 pF \n",
- "The value of Co is 0.64 pF \n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.9 Page No 834"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hFE=2000.0\n",
- "Vbe=1.4\n",
- "Vp=10.0\n",
- "Ip=200.0*10**-3\n",
- "Icq2=20.0*10**-3\n",
- "Re3=4.7\n",
- "Re2=4.7\n",
- "Vd=0.7\n",
- "Ve1=3.0\n",
- "Vc1=15.2\n",
- "\n",
- "#Calculations\n",
- "Vrc=Vc1\n",
- "Vb=Vbe+Icq*(Re2+Re3)+Vbe\n",
- "Vcc=Vrc+Vc1+Vb\n",
- "Ib2=Ip/hFE\n",
- "Irc=1.0*10**-3\n",
- "Vrcac=4.0\n",
- "Rc=Vrcac/Irc\n",
- "Ic1=Vrc/Rc\n",
- "Rb=(Vb-(4*Vd))/Ic1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kohm \" %Rb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 49.47 kohm \n"
- ]
- }
- ],
- "prompt_number": 51
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.10 Page No 838"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vb=3.2\n",
- "Ic1=5*10**-3\n",
- "Vce=3.2\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vbmin=Vb-0.5\n",
- "Vbmax=Vb+0.5\n",
- "I10=.1*Ic1\n",
- "R10=(Vce-Vbe)/I10\n",
- "R10=4.7*10**3#use standard value\n",
- "print(\" for Vce=3.7\")\n",
- "Vce=3.7\n",
- "I10max=(Vce-Vbe)/R10\n",
- "print(\"Vce=2.7V\")\n",
- "Vce=2.7\n",
- "I10min=(Vce-Vbe)/R10\n",
- "R=Vbe/I10min\n",
- "R11=Vbe/I10max\n",
- "R12=R-R11\n",
- "\n",
- "#Results\n",
- "print(\"The value of R12 is %.2f kohm \" %R12)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Vce=3.7\n",
- "Vce=2.7V\n",
- "The value of R12 is 548.33 kohm \n"
- ]
- }
- ],
- "prompt_number": 52
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.11 Page No 843"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=16.0\n",
- "Po=6.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2.0*Rl*Po)\n",
- "Vr14=0.1*Vp\n",
- "Vr15=Vr14\n",
- "R14=0.1*Rl\n",
- "R15=R14\n",
- "Vce3=1.0\n",
- "Vce4=Vce3\n",
- "Vr9=3.0\n",
- "Vr11=Vr9\n",
- "Vcc=(Vp+Vr14+Vbe+Vce3+Vr9)\n",
- "Vee=-Vcc\n",
- "Ip=Vp/Rl\n",
- "print(\" DC power inpit from supply line\")\n",
- "Pi=(Vcc-Vee)*.35*Ip\n",
- "Pt=.5*(Pi-Po)\n",
- "Vce=2*Vcc\n",
- "Ic=1.1*Ip\n",
- "\n",
- "#Results\n",
- "print(\" output transistor specification %.2f mA\" %Ic)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " DC power inpit from supply line\n",
- " output transistor specification 0.95 mA\n"
- ]
- }
- ],
- "prompt_number": 53
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.12, Page No 844"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "hFE7=20.0\n",
- "Icbo=50.0*10**-6\n",
- "hFE5=70.0\n",
- "Vr9=3.0\n",
- "Ip=869.0*10**-3\n",
- "R15=1.5\n",
- "R8=15.0*10**3\n",
- "Vbe=0.7\n",
- "Vr11=3.0\n",
- "Vee=20.0\n",
- "\n",
- "#Calculations\n",
- "R12=0.01/Icbo\n",
- "R12=220#use standard value\n",
- "R13=R12\n",
- "Ib5=Ip/(hFE7*hFE5)\n",
- "Ic3=2.0*10**-3\n",
- "R9=Vr9/Ic3\n",
- "R11=R9\n",
- "Iq78=0.1*Ip\n",
- "Vr14=Iq78*R15\n",
- "Vr15=Vr14\n",
- "Vr10=(Vr14+Vr15)+(Vr14+Vr15)/2\n",
- "R10=Vr10/Ic3\n",
- "Ir8=(Vr11+Vbe)/R8\n",
- "R7=(Vee-(Vr11+Vbe))/Ir8\n",
- "\n",
- "#Results\n",
- "print(\"The value of R7 is %.2f kohm \" %(R7/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R7 is 66.08 kohm \n"
- ]
- }
- ],
- "prompt_number": 54
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.13, Page No 848"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=20.0\n",
- "Po=2.5\n",
- "Rd=4.0\n",
- "Vr6=1.0\n",
- "Vr9=Vr6\n",
- "Vth=1.0\n",
- "gFS=250.0*10**-3\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "Vcc=(Vp+Ip*Rd)\n",
- "vr6=Ip/gFS\n",
- "Vr2=vr6+1\n",
- "Vce=Vr2\n",
- "Vce3=1.0\n",
- "Vr2=Vcc-Vce\n",
- "Vee=Vcc\n",
- "Vr3=Vee-Vbe\n",
- "Vr7=Vr2-Vr6\n",
- "Vr8=Vcc-(-Vee)-Vr6-Vr7-Vr9\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vr8 is %.2f V \" %Vr8)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vr8 is 14.00 V \n"
- ]
- }
- ],
- "prompt_number": 55
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.14, Page No 849"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R6=100.0*10**3\n",
- "R9=R6\n",
- "Vth=1.0\n",
- "Vr7=8.0\n",
- "Vr8=14.0\n",
- "Vr3=11.3\n",
- "Vpout=10.0\n",
- "Vpin=800.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "I6=Vth/R6\n",
- "R7=Vr7/I6\n",
- "R8=Vr8/I6\n",
- "Ic1=1*10**-4\n",
- "Ic2=Ic1\n",
- "Vr2=9\n",
- "R2=Vr2/Ic1\n",
- "R3=Vr3/(Ic1+Ic2)\n",
- "R5=4.7*10**3\n",
- "Acl=Vpout/Vpin\n",
- "R4=R5/(Acl-1.0)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R4 is %.2f kohm \" %(R4/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R4 is 0.41 kohm \n"
- ]
- }
- ],
- "prompt_number": 56
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.15, Page No 854"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vce=1.5\n",
- "Vcc=17.0\n",
- "Vd1=0.7\n",
- "R8=1.5*10**3\n",
- "R9=R8\n",
- "Rl=100.0\n",
- "R6=8.2\n",
- "\n",
- "#Calculations\n",
- "I4=(Vcc-Vd1)/(R8+R9)\n",
- "Vc3=Vcc-(I4*R8)\n",
- "print(\" bootstrap capacitance terminal voltage is %3.1fV \" %Vc3)\n",
- "V=Vcc-Vce#V=Vp+Vr6\n",
- "Ip=V/(Rl+R6)\n",
- "Vp=Ip*Rl\n",
- "print(\" peak output voltage is %3.1fV \" %Vp)\n",
- "Po=(Vp)**2.0/(2.0*Rl)\n",
- "\n",
- "#Results\n",
- "print(\" peak output power is %dW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " bootstrap capacitance terminal voltage is 8.8V \n",
- " peak output voltage is 14.3V \n",
- " peak output power is 1W \n"
- ]
- }
- ],
- "prompt_number": 57
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.16, Page No 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rl=8.0\n",
- "Po=6.0\n",
- "vs=0.1\n",
- "hFE=1000.0\n",
- "Vce=2.0\n",
- "f=50.0*10**3\n",
- "Vd1=0.7\n",
- "\n",
- "#Calculations\n",
- "Vp=math.sqrt(2*Rl*Po)\n",
- "Ip=Vp/Rl\n",
- "R6=.1*Rl\n",
- "R7=R6\n",
- "Vcc=Vp+Ip*R6+Vce\n",
- "Ib=Ip/hFE\n",
- "I4=2*10**-3\n",
- "R4=(Vcc-Vd1-Vd1)/I4\n",
- "R8=.5*R4\n",
- "Acl=Vp/vs\n",
- "R3=100*10**3\n",
- "R2=R3/(Acl-1)\n",
- "SR=(2*3.14*f*Vp)*10**-6\n",
- "\n",
- "#Results\n",
- "print(\" slew rate is %.2f V/us \" %SR)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " slew rate is 3.08 V/us \n"
- ]
- }
- ],
- "prompt_number": 58
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.17, Page No 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=50.0\n",
- "R1=100.0*10**3\n",
- "R2=1.0*10**3\n",
- "R8=2.7*10**3\n",
- "\n",
- "#Calculations\n",
- "R9=R8\n",
- "C1=1/(2*3.14*f*.1*R1)\n",
- "C2=1/(2*3.14*f*R2)\n",
- "Xc3=.1*((R8*R9)/(R8+R9))\n",
- "C3=1/(2*3.14*f*Xc3)\n",
- "C4=C3\n",
- "\n",
- "#Results\n",
- "print(\"The value of C4 is %.2f pF \" %(C4*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of C4 is 23.59 pF \n"
- ]
- }
- ],
- "prompt_number": 59
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.18, Page No 860"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ismin=1.8*10**-3\n",
- "Ismax=3.4*10**-3\n",
- "R7=820.0\n",
- "R5=390.0\n",
- "R6=18.0*10**3\n",
- "Vi=100.0*10**-3\n",
- "Rl=10.0\n",
- "\n",
- "#Calculations\n",
- "Vgsmin=Ismin*R7\n",
- "Vgsmax=Ismax*R7\n",
- "Acl=(R5+R6)/R5\n",
- "Vp=Acl*Vi\n",
- "Ip=Vp/Rl\n",
- "print(\"peak output current is %3.3fA \" %Ip)\n",
- "Po=(Vp*Ip)/2.0\n",
- "\n",
- "#Results\n",
- "print(\"peak output power is %3.2fW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "peak output current is 0.472A \n",
- "peak output power is 1.11W \n"
- ]
- }
- ],
- "prompt_number": 60
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.19, Page No 862"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vbe=0.7\n",
- "R2=560.0\n",
- "R3min=0\n",
- "R3max=1.0*10**3\n",
- "Is=2.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "Ic2max=Vbe/(R2+R3min)\n",
- "Ic2min=Vbe/(R2+R3max)\n",
- "Vgsmin=(Is+Ic2min)*820.0\n",
- "Vgsmax=(Is+Ic2max)*820.0\n",
- "\n",
- "#Results\n",
- "print(\"The value of Vgsmax is %.2f v \" %Vgsmax)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vgsmax is 2.67 v \n"
- ]
- }
- ],
- "prompt_number": 61
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.20, Page No 865"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=12.0\n",
- "Rl=10.0\n",
- "Rd=0.5\n",
- "gfs=2.5\n",
- "R7=820.0\n",
- "V9=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R10=R9\n",
- "Vp=(Vcc*Rl)/(Rd+Rl)\n",
- "Ip=Vp/Rl\n",
- "Vgs=Ip/gfs\n",
- "Vr7=Is*R7\n",
- "Vs=Vcc-Vr7-Vgs\n",
- "Vr9=(Vp*R9)/(R9+R10)\n",
- "\n",
- "#Results\n",
- "print(\"op-amp peak output voltage is %.2f v \" %Vr9)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "op-amp peak output voltage is 5.71 v \n"
- ]
- }
- ],
- "prompt_number": 62
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.21, Page No 867"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=0.7\n",
- "R2=470.0\n",
- "R3=1.0*10**3\n",
- "Is=0.5*10**-3\n",
- "R7=1.5*10**3\n",
- "Vcc=15\n",
- "\n",
- "#Calculations\n",
- "Ic2max=Vbe/R2\n",
- "Ic2min=Vbe/(R2+R3)\n",
- "Vgs=(Is+Ic2max)*R7\n",
- "print(\" MOSFET maximum gate source voltage is %.1fV \" %Vgs)\n",
- "Vs=Vcc-Vgs\n",
- "\n",
- "#Results\n",
- "print(\" op-amp minimum suppy is %.2fV \" %Vs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " MOSFET maximum gate source voltage is 3.0V \n",
- " op-amp minimum suppy is 12.02V \n"
- ]
- }
- ],
- "prompt_number": 63
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.22, Page No 868"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=15.0\n",
- "Rl=15.0\n",
- "Rd=0.3\n",
- "R5=2.2*10**3\n",
- "R6=33.0*10**3\n",
- "C2=3.9*10**-6\n",
- "C4=100.0*10**-12\n",
- "\n",
- "#Calculations\n",
- "print(\" power output\")\n",
- "Vp=(Vcc*Rl)/(Rd+Rl)\n",
- "Ip=Vp/Rl\n",
- "Po=(Vp*Ip)/2.0\n",
- "print(\" voltage gain\")\n",
- "Av=(R5+R6)/R5\n",
- "print(\"cutoff frequency\")\n",
- "f1=1.0/(2*3.14*C2*R5)\n",
- "f2=1.0/(2*3.14*C4*R6)\n",
- "\n",
- "#Results\n",
- "print(\" cutoff frequency f1 %.2f \" %f1)\n",
- "print(\" cutoff frequency f2 %.2f \" %f2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " power output\n",
- " voltage gain\n",
- "cutoff frequency\n",
- " cutoff frequency f1 18.56 \n",
- " cutoff frequency f2 48253.23 \n"
- ]
- }
- ],
- "prompt_number": 64
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.23, Page No 871"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=23.0\n",
- "Rl=8.0\n",
- "Rf2=100.0*10**3\n",
- "Rf1=5.6*10**3\n",
- "Cf=1.0*10**-6\n",
- "Vp=Vcc-5\n",
- "\n",
- "#Calculations\n",
- "Po=(Vp)**2/(2*Rl)\n",
- "print(\"maximum output power is %3.2fW \" %Po)\n",
- "Acl=(Rf1+Rf2)/Rf1\n",
- "print(\" voltage gain %3.1f \" %Acl)\n",
- "f=1/(2*3.14*Cf*Rf1)\n",
- "\n",
- "#Results\n",
- "print(\"lower cutoff frequency is %dHz \" %f)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum output power is 20.25W \n",
- " voltage gain 18.9 \n",
- "lower cutoff frequency is 28Hz \n"
- ]
- }
- ],
- "prompt_number": 65
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.24, Page No 875"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rf=15.0*10**3\n",
- "R1=5.6*10**3\n",
- "vs=0.5\n",
- "Vp=2.7\n",
- "\n",
- "#Calculations\n",
- "Acl=(2.0*Rf)/R1\n",
- "Vo=Acl*vs\n",
- "Po=(Vp)**2.0/(2.0*Rl)\n",
- "\n",
- "#Results\n",
- "print(\"load power dissipation is %.2fW \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "load power dissipation is 0.46W \n"
- ]
- }
- ],
- "prompt_number": 66
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.24, Page No 875"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=10.0\n",
- "Rl=1.0*10**3\n",
- "f=3.0*10**6\n",
- "Ip=25.0*10**-3\n",
- "Vce=0.3\n",
- "\n",
- "#Calculations\n",
- "Vp=Vcc-Vce\n",
- "Po=(Vp)**2 /(2*Rl)\n",
- "T=1.0/f\n",
- "t=(Po*T)/(Ip*Vp)\n",
- "angle=(t/T)*360\n",
- "print(\" conduction angle is %3.1fdegree \" %angle)\n",
- "Idc=Po/Vp\n",
- "Pi=Vcc*Idc\n",
- "print( \"dc input power is %3.4fW \" %Pi)\n",
- "n=(Po/Pi)*100#efficiency\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " conduction angle is 69.8degree \n",
- "dc input power is 0.0485W \n",
- " maximum efficiency is 97.00 percentage \n"
- ]
- }
- ],
- "prompt_number": 67
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.26, Page No 882"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=1.0*10**6\n",
- "Xc=120.0\n",
- "Vce=0.5\n",
- "Vcc=30.0\n",
- "Rl=1.2*10**3\n",
- "O=100.0\n",
- "\n",
- "#Calculations\n",
- "Cp=1.0/(2*3.14*f*Xc)\n",
- "Cp=1300*10**-12#use standard value\n",
- "Lp=1/(((2*3.14*f)**2)*Cp)\n",
- "Vp=Vcc-Vce\n",
- "Po=((Vp)**2) /(2*Rl)\n",
- "Idc=Po/Vp\n",
- "T=1.0/f\n",
- "t=(O*T)/360.0\n",
- "Ip=(Idc*T)/t\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ip is %.2f mA \" %(Ip*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ip is 44.25 mA \n"
- ]
- }
- ],
- "prompt_number": 68
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.27, Page No 883"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rw=0.1\n",
- "f=1.0*10**6\n",
- "Lp=19.5*10**-6\n",
- "Rl=1.2*10**3\n",
- "Vcc=30.0\n",
- "\n",
- "#Calculations\n",
- "Idc=12.3*10**-3\n",
- "QL=(2*3.14*f*Lp)/Rw\n",
- "Qp=Rl/(2*3.14*f*Lp)\n",
- "B=f/Qp\n",
- "Il=(.707*Vp)/(2*3.14*f*Lp)\n",
- "Pl=(Il)**2 *Rw\n",
- "Pi=(Vcc*Idc)+Pl\n",
- "n=(Po/Pi)*100.0\n",
- "\n",
- "#Results\n",
- "print(\" maximum efficiency is %3.2f percentage \" %n)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum efficiency is 97.50 percentage \n"
- ]
- }
- ],
- "prompt_number": 69
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter1_1.ipynb b/Electronic_Devices_and_Circuits/Chapter1_1.ipynb deleted file mode 100755 index 47b8b5fc..00000000 --- a/Electronic_Devices_and_Circuits/Chapter1_1.ipynb +++ /dev/null @@ -1,307 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 01 : Basic semiconductor and pn junction theory"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.1, Page No 15"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Nd=3*10**14\n",
- "Na=0.5*10**14 #all in atom/cm**3\n",
- "ni=1.5*10**10\n",
- "\n",
- "#Calculations\n",
- "print(\"resultant densities of free electrons and hole\")\n",
- "ne=(-(Na-Nd)+(math.sqrt(((Na-Nd)**2)+4*ni**2)))/2\n",
- "print(\"Electron densities = %.1f x 10^14 electron/cm**3\" %(ne/(10**14))) #electron densities in electron/cm**3\n",
- "Nd>Na\n",
- "n=Nd-Na\n",
- "print(n)\n",
- "p=(ni**2)/n\n",
- "\n",
- "#Results\n",
- "\n",
- "print(\"densities of hole is =%.1f X 10^6 dhole/cm3\" %(p/(10**6)))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resultant densities of free electrons and hole\n",
- "Electron densities = 2.5 x 10^14 electron/cm**3\n",
- "2.5e+14\n",
- "densities of hole is =0.9 X 10^6 dhole/cm3\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.2, Page No 18"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "l=1*10**-3\n",
- "E=10\n",
- "\n",
- "#Calculations\n",
- "un=1500*10**-4\n",
- "up=500*10-4\n",
- "Vn=-(un*E)/l\n",
- "\n",
- "#Results\n",
- "print(\"drift current is =%.2dm/s\\n\" %Vn)\n",
- "print(\"drift current of hole\")\n",
- "Vp=(up*E)/l\n",
- "print(\"drift current is =%.f dm/s\\n\" %(Vp/10**5))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "drift current is =-1500m/s\n",
- "\n",
- "drift current of hole\n",
- "drift current is =500 dm/s\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.3 Page No 19"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "l=1*10**-3\n",
- "a=0.1*10**-4\n",
- "ni=1.5*10**10\n",
- "p=1.5*10**10\n",
- "un=1500\n",
- "up=500 #in cm3/V.s\n",
- "q=1.6*10**-19\n",
- "\n",
- "#Calculations\n",
- "m=q*((ni*un)+(p*up))*10**6\n",
- "print( \"mobility is =%.1fmicro/ohmcm\" %m)\n",
- "R=l/(m*a)\n",
- "print(\" resistance is =%.1fMohm\" %R)\n",
- "\n",
- "#for doped material\n",
- "n=8*10**13\n",
- "p=(ni**2)/n\n",
- "m=q*((n*un)+(p*up))\n",
- "\n",
- "#Results\n",
- "print(\"mobility is =%3.4f/ohmcm\" %m)\n",
- "R=l/(m*a)\n",
- "print(\" resistance is %.2f Kohm\" %(R/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "mobility is =4.8micro/ohmcm\n",
- " resistance is =20.8Mohm\n",
- "mobility is =0.0192/ohmcm\n",
- " resistance is 5.21 Kohm\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.4, Page No 25"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "T1=25.0\n",
- "T2=35.0\n",
- "T3=45.0\n",
- "I0=30.0 # nA\n",
- "print(\"I0(35)=I0*2**(T2-T1)/10\")\n",
- "#on solving\n",
- "I035=I0*2**((T2-T1)/10)\n",
- "print(\"Current at 35c is =%.2f nA\\n\" %I035)\n",
- "print(\"I0(45)=I0*2**(T3-T1)/10\")\n",
- "#on solving\n",
- "I045=30*2**2\n",
- "print(\"current at 45c is =%.2f nA\\n\" %I045)\n",
- "I_CS=100.0 \n",
- "V_CC=200.0 \n",
- "t_on=40*10**-6"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "I0(35)=I0*2**(T2-T1)/10\n",
- "Current at 35c is =60.00 nA\n",
- "\n",
- "I0(45)=I0*2**(T3-T1)/10\n",
- "current at 45c is =120.00 nA\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.5, Page No 28"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "I0=30\n",
- "Vd=0.7\n",
- "n=2\n",
- "\n",
- "#Calculations\n",
- "Vt=26.0*10**-3\n",
- "k=Vd/(n*Vt)\n",
- "Id=I0*((2.7**k)-1)*10**-6 #Junction current\n",
- "print(\" a) Forward bais current is =%.2f mA\\n\" %Id)\n",
- "Vd=-10 #reverse bais\n",
- "k=Vd/(n*Vt)\n",
- "Id=I0*((2.7**k)-1)\n",
- "\n",
- "#Results\n",
- "print(\" b) Forward bais current is =%.2f nA\" %Id)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " a) Forward bais current is =19.23 mA\n",
- "\n",
- " b) Forward bais current is =-30.00 nA\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.6, Page No 29"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=.1*10**-3\n",
- "n=2\n",
- "vt=26*10**-3\n",
- "I0=30*10**-9\n",
- "\n",
- "#Calculations\n",
- "Vd=(n*Vt)*math.log(Id/I0)*10**3\n",
- "print(\" a) Forward bais current is =%.2f mV\\n\" %Vd)\n",
- "Id=10*10**-3\n",
- "Vd=(n*Vt)*math.log(Id/I0)*10**3\n",
- "\n",
- "#Results\n",
- "print(\"b) forward bais current is %dmV\\n\" %Vd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " a) Forward bais current is =421.81 mV\n",
- "\n",
- "b) forward bais current is 661mV\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter1_2.ipynb b/Electronic_Devices_and_Circuits/Chapter1_2.ipynb deleted file mode 100755 index 47b8b5fc..00000000 --- a/Electronic_Devices_and_Circuits/Chapter1_2.ipynb +++ /dev/null @@ -1,307 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 01 : Basic semiconductor and pn junction theory"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.1, Page No 15"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Nd=3*10**14\n",
- "Na=0.5*10**14 #all in atom/cm**3\n",
- "ni=1.5*10**10\n",
- "\n",
- "#Calculations\n",
- "print(\"resultant densities of free electrons and hole\")\n",
- "ne=(-(Na-Nd)+(math.sqrt(((Na-Nd)**2)+4*ni**2)))/2\n",
- "print(\"Electron densities = %.1f x 10^14 electron/cm**3\" %(ne/(10**14))) #electron densities in electron/cm**3\n",
- "Nd>Na\n",
- "n=Nd-Na\n",
- "print(n)\n",
- "p=(ni**2)/n\n",
- "\n",
- "#Results\n",
- "\n",
- "print(\"densities of hole is =%.1f X 10^6 dhole/cm3\" %(p/(10**6)))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resultant densities of free electrons and hole\n",
- "Electron densities = 2.5 x 10^14 electron/cm**3\n",
- "2.5e+14\n",
- "densities of hole is =0.9 X 10^6 dhole/cm3\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.2, Page No 18"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "l=1*10**-3\n",
- "E=10\n",
- "\n",
- "#Calculations\n",
- "un=1500*10**-4\n",
- "up=500*10-4\n",
- "Vn=-(un*E)/l\n",
- "\n",
- "#Results\n",
- "print(\"drift current is =%.2dm/s\\n\" %Vn)\n",
- "print(\"drift current of hole\")\n",
- "Vp=(up*E)/l\n",
- "print(\"drift current is =%.f dm/s\\n\" %(Vp/10**5))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "drift current is =-1500m/s\n",
- "\n",
- "drift current of hole\n",
- "drift current is =500 dm/s\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.3 Page No 19"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "l=1*10**-3\n",
- "a=0.1*10**-4\n",
- "ni=1.5*10**10\n",
- "p=1.5*10**10\n",
- "un=1500\n",
- "up=500 #in cm3/V.s\n",
- "q=1.6*10**-19\n",
- "\n",
- "#Calculations\n",
- "m=q*((ni*un)+(p*up))*10**6\n",
- "print( \"mobility is =%.1fmicro/ohmcm\" %m)\n",
- "R=l/(m*a)\n",
- "print(\" resistance is =%.1fMohm\" %R)\n",
- "\n",
- "#for doped material\n",
- "n=8*10**13\n",
- "p=(ni**2)/n\n",
- "m=q*((n*un)+(p*up))\n",
- "\n",
- "#Results\n",
- "print(\"mobility is =%3.4f/ohmcm\" %m)\n",
- "R=l/(m*a)\n",
- "print(\" resistance is %.2f Kohm\" %(R/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "mobility is =4.8micro/ohmcm\n",
- " resistance is =20.8Mohm\n",
- "mobility is =0.0192/ohmcm\n",
- " resistance is 5.21 Kohm\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.4, Page No 25"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "T1=25.0\n",
- "T2=35.0\n",
- "T3=45.0\n",
- "I0=30.0 # nA\n",
- "print(\"I0(35)=I0*2**(T2-T1)/10\")\n",
- "#on solving\n",
- "I035=I0*2**((T2-T1)/10)\n",
- "print(\"Current at 35c is =%.2f nA\\n\" %I035)\n",
- "print(\"I0(45)=I0*2**(T3-T1)/10\")\n",
- "#on solving\n",
- "I045=30*2**2\n",
- "print(\"current at 45c is =%.2f nA\\n\" %I045)\n",
- "I_CS=100.0 \n",
- "V_CC=200.0 \n",
- "t_on=40*10**-6"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "I0(35)=I0*2**(T2-T1)/10\n",
- "Current at 35c is =60.00 nA\n",
- "\n",
- "I0(45)=I0*2**(T3-T1)/10\n",
- "current at 45c is =120.00 nA\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.5, Page No 28"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "I0=30\n",
- "Vd=0.7\n",
- "n=2\n",
- "\n",
- "#Calculations\n",
- "Vt=26.0*10**-3\n",
- "k=Vd/(n*Vt)\n",
- "Id=I0*((2.7**k)-1)*10**-6 #Junction current\n",
- "print(\" a) Forward bais current is =%.2f mA\\n\" %Id)\n",
- "Vd=-10 #reverse bais\n",
- "k=Vd/(n*Vt)\n",
- "Id=I0*((2.7**k)-1)\n",
- "\n",
- "#Results\n",
- "print(\" b) Forward bais current is =%.2f nA\" %Id)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " a) Forward bais current is =19.23 mA\n",
- "\n",
- " b) Forward bais current is =-30.00 nA\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1.6, Page No 29"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Id=.1*10**-3\n",
- "n=2\n",
- "vt=26*10**-3\n",
- "I0=30*10**-9\n",
- "\n",
- "#Calculations\n",
- "Vd=(n*Vt)*math.log(Id/I0)*10**3\n",
- "print(\" a) Forward bais current is =%.2f mV\\n\" %Vd)\n",
- "Id=10*10**-3\n",
- "Vd=(n*Vt)*math.log(Id/I0)*10**3\n",
- "\n",
- "#Results\n",
- "print(\"b) forward bais current is %dmV\\n\" %Vd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " a) Forward bais current is =421.81 mV\n",
- "\n",
- "b) forward bais current is 661mV\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter2.ipynb b/Electronic_Devices_and_Circuits/Chapter2.ipynb deleted file mode 100755 index 1c97e28b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter2.ipynb +++ /dev/null @@ -1,571 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 02 : Semiconductor diodes"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.1, Page No 37"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=100*10**-3\n",
- "Vf=.75 #given\n",
- "print(\"a)\")\n",
- "print(\"forward resistance\")\n",
- "\n",
- "#Calculations\n",
- "Rf=Vf/If\n",
- "print(\"forward resistnace is %3.1fohm \" %Rf)\n",
- "print(\"b)\")\n",
- "Vr=50\n",
- "Ir=100*10**-9\n",
- "Rr=(Vr/Ir)\n",
- "\n",
- "#Results\n",
- "print(\"reverse resistnace is %.1fohm \" %(Rr/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "a)\n",
- "forward resistance\n",
- "forward resistnace is 7.5ohm \n",
- "b)\n",
- "reverse resistnace is 500.0ohm \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.2, Page No 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=70*10**-3\n",
- "\n",
- "#Calculations\n",
- "rd=(26*10**-3)/If\n",
- "print(\"dynamic resistance is %.2fohm \" %rd)\n",
- "If=60*10**-3\n",
- "Vf=.025\n",
- "rd=Vf/If\n",
- "\n",
- "#Results\n",
- "print(\"dynamic resistance is %.2fohm \" %rd)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "dynamic resistance is 0.37ohm \n",
- "dynamic resistance is 0.42ohm \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.3 Page No 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=4.7*10**3\n",
- "E=15.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "print(\"diode current is E=If*R1+Vf\")\n",
- "If=((E-Vf)/R1)*10**3\n",
- "\n",
- "#Results\n",
- "print(\" diode current is %.2fmA \" %If) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "diode current is E=If*R1+Vf\n",
- " diode current is 3.04mA \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.5, Page No 41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=1.5\n",
- "Vf=0.7\n",
- "R1=10\n",
- "rd=.25\n",
- "\n",
- "#Calculations\n",
- "print(\"a)\")\n",
- "If=(E-Vf)/R1\n",
- "print(\" forward current is %0.1fmA \" %(If*1000))\n",
- "print(\"b)\")\n",
- "If=(E-Vf)/(R1+rd)\n",
- "\n",
- "#Results\n",
- "print(\" forward current is %0.1fmA \" %(If*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "a)\n",
- " forward current is 80.0mA \n",
- "b)\n",
- " forward current is 78.0mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.6 Page No 43"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=0\n",
- "Vf=5.0\n",
- "R1=100.0\n",
- "\n",
- "#Calculations\n",
- "E=(If*R1)+Vf\n",
- "print(\"B)\")\n",
- "Vf=0\n",
- "E=5.0\n",
- "R1=100.0\n",
- "If=(E/R1)*1000\n",
- "\n",
- "#Results\n",
- "print(\"resistance is %dmA \" %If) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "B)\n",
- "resistance is 50mA \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.8 Page No 45"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=50*10**-3\n",
- "Vf=1.1\n",
- "R1=100.0\n",
- "\n",
- "#Calculations\n",
- "Vf1=If*R1\n",
- "E=Vf1+Vf\n",
- "\n",
- "#Results\n",
- "print(\" new supply voltage is %.2fV \" %E)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " new supply voltage is 6.10V \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.9, Page No 48"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "P1=700.0*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "If=P1/Vf\n",
- "#at 65C\n",
- "D=5*10**-3\n",
- "T=65-25\n",
- "P2=P1-D*T\n",
- "If=P2/Vf\n",
- "\n",
- "#Results\n",
- "print( \"maximum forward current at 65C is %.1fA \" %(If*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum forward current at 65C is 714.3A \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.10 Page No 49"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vf1=0.7\n",
- "Vf=-1.8*10**-3\n",
- "If=26.0*10**-3\n",
- "T=100-25\n",
- "\n",
- "#Calculations\n",
- "Vf2=Vf1+(T*Vf)\n",
- "print(\" voltage at 100C is %.3f V \" %Vf2)\n",
- "print(\"At 25C\")\n",
- "T1=25.0\n",
- "rd=(26*10**-3/If)*((T1+273)/298)\n",
- "print(\" resistance at 25 C is %.2f ohm \" %rd)\n",
- "print(\" At 100C\")\n",
- "T2=100.0\n",
- "rd=(26*10**-3/If)*((T2+273)/298)\n",
- "\n",
- "#Results\n",
- "print(\" resistance at 100 C is %.2fohm \" %rd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage at 100C is 0.565 V \n",
- "At 25C\n",
- " resistance at 25 C is 1.00 ohm \n",
- " At 100C\n",
- " resistance at 100 C is 1.25ohm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.11 Page No 51"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variablesV_s=230\n",
- "If=10*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "t=70.0*10**-9\n",
- "Cd=((t*If)/Vf)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" diffusion capacitance is %.2f nF \" %Cd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " diffusion capacitance is 1.00 nF \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.12 Page No 53"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "print(\"A\")\n",
- "trr=10.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "tf=10.0*trr*10**9\n",
- "print(\"minimum fall times is %d ns \" %tf)\n",
- "print(\"B)\")\n",
- "trr=3.0\n",
- "tf=10*trr\n",
- "\n",
- "#Results\n",
- "print(\"minimum fall times is %d ns \" %tf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "A\n",
- "minimum fall times is 100 ns \n",
- "B)\n",
- "minimum fall times is 30 ns \n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.14, Page No 58"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Io=75.0*10**-3\n",
- "#vertical scale of 5mA/cm \n",
- "\n",
- "#Calculations\n",
- "If=Io/5*10**-3\n",
- "R1=15/(75*10**-3)\n",
- "P=((Io)**2)*R1\n",
- "\n",
- "#Results\n",
- "print(\"Pr1 = %1.1f W \" %P)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Pr1 = 1.1 W \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.15, Page No 63"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=7.5\n",
- "Pd=400.0*10**-3\n",
- "D=3.2*10**-3\n",
- "\n",
- "#Calculations\n",
- "Izm=Pd/Vz\n",
- "print(\"current at 50C is %.1fA \" %(Izm*1000))\n",
- "print(\"At 100C\")\n",
- "P2=Pd-((100-50)*D)\n",
- "print(\" power at 100C is %.3fW \" %P2)\n",
- "Izm=P2/Vz\n",
- "\n",
- "#Results\n",
- "print(\" current at 100C is %.1fA \" %(Izm*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "current at 50C is 53.3A \n",
- "At 100C\n",
- " power at 100C is 0.240W \n",
- " current at 100C is 32.0A \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.16, Page No 64"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=20.0\n",
- "R1=620.0\n",
- "Vz=7.5\n",
- "\n",
- "#Calculations\n",
- "Vr1=E-Vz\n",
- "Iz=Vr1/R1\n",
- "print(\" diode current is %.1f mA \" %(Iz*1000))\n",
- "Pd=Vz*Iz\n",
- "\n",
- "#Results\n",
- "print( \"power dissipation is %.1f mW \" %(Pd*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " diode current is 20.2 mA \n",
- "power dissipation is 151.2 mW \n"
- ]
- }
- ],
- "prompt_number": 26
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter20.ipynb b/Electronic_Devices_and_Circuits/Chapter20.ipynb deleted file mode 100755 index dcf6cb7f..00000000 --- a/Electronic_Devices_and_Circuits/Chapter20.ipynb +++ /dev/null @@ -1,434 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 20 : Thyristors "
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.1, Page No 902"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vs=25.0\n",
- "Vtm=1.7\n",
- "Rl=25.0\n",
- "Ih=5*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vspk=1.414*Vs\n",
- "Ilpk=(Vs-Vtm)/Rl\n",
- "print(\" for half wave rectifier sinusodial waveform\")\n",
- "Ilrms=.5*Ilpk\n",
- "es=Vtm+(Ih*Rl)\n",
- "\n",
- "#Results\n",
- "print(\" switch-off voltage =%.2f v\" %es)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for half wave rectifier sinusodial waveform\n",
- " switch-off voltage =1.82 v\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.2, Page No 905"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vs=30.0\n",
- "Vd1=.7\n",
- "Vg=.8\n",
- "Ig=200*10**-6\n",
- "\n",
- "#Calculations\n",
- "Vspk=1.414*Vs\n",
- "print(\" at 5 degree\")\n",
- "es=Vspk*.087 # sin5=.087\n",
- "print(\" at 90 degree\")\n",
- "es=Vspk\n",
- "Vt=Vd1+Vg\n",
- "print(\" to trigger at es=3.7V the R2 moving contact is at the top\")\n",
- "es=3.7\n",
- "Vr1=es-Vt\n",
- "I1=1*10**-3\n",
- "R1=Vr1/I1\n",
- "R=Vt/I1 #R=R2+R3\n",
- "es=42.4\n",
- "Vr3=Vt\n",
- "I1=es/(R+R1)\n",
- "R3=Vt/I1\n",
- "R2=R-R3\n",
- "\n",
- "#Results\n",
- "print(\" To trigger at es =42.4 the R2 moving contact at the bottom =%.2f\" %R2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " at 5 degree\n",
- " at 90 degree\n",
- " to trigger at es=3.7V the R2 moving contact is at the top\n",
- " To trigger at es =42.4 the R2 moving contact at the bottom =1369.10\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.3 Page No 906"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "R1=2.2*10**3\n",
- "R2=1.5*10**3\n",
- "R3=120.0\n",
- "Vt=1.5\n",
- "\n",
- "#Calculations\n",
- "Vak1=Vt*((R1+R2+R3)/(R3+.5*R2))\n",
- "Vak2=Vt*((R1+R2+R3)/R3)\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\" with R2 contact at center = %.2f\" %Vak1)\n",
- "print(\" with R2 contact at zero = %.2f\" %Vak2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R2 contact at center = 6.59\n",
- " with R2 contact at zero = 47.75\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.4, Page No 911"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vs=5.0\n",
- "Ilmax=300*10**-3\n",
- "Vl=7.0\n",
- "Vg=0.8\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Vz=Vl-Vg\n",
- "print(\" for D1, select a 1N753 with Vz=6.2\")\n",
- "Izmin=1*10**-3\n",
- "R1=Vg/Izmin\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %d kohm \" %R1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for D1, select a 1N753 with Vz=6.2\n",
- "The value of R1 is 800 kohm \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.5 Page No 911"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=25*10**3\n",
- "R2=2.7*10**3\n",
- "C1=3*10**-6\n",
- "Vg=0.8\n",
- "Vd1=8.0\n",
- "Vs=115.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Vc1=Vd1+Vg\n",
- "#assume the average charging voltage is\n",
- "Vac=1.414*Vs\n",
- "E=.636*Vac\n",
- "#average charging\n",
- "Ic=E/(R1+R2)\n",
- "#charging time\n",
- "t=(C1*Vc1)/Ic\n",
- "T=1/f\n",
- "q=(t*360)/T\n",
- "a=180-q\n",
- "\n",
- "#Results\n",
- "print(\"Conduction angle =%.2f degrees\" %a)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Conduction angle =27.27 degrees\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.6 Page No 925"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vs=10.0\n",
- "Vf=1.7\n",
- "Is=500*10**-6\n",
- "Ih=1.5*10**-3\n",
- "E=30.0\n",
- "\n",
- "#Calculations\n",
- "R=27*10**3\n",
- "C=0.5*10**-6\n",
- "R1max=(E-Vs)/Is\n",
- "R1min=(E-Vf)/Ih\n",
- "t=C*R*math.log((E-Vf)/(E-Vs))\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"Capacitor charging time is %3.4f s\" %t)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitor charging time is 0.0047 s\n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.7, Page No 931"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rbb=4.0*10**3\n",
- "Pd25=360.0*10**-3\n",
- "D=2.4*10**-3\n",
- "T2=100.0\n",
- "\n",
- "#Calculations\n",
- "Pd=Pd25-D*(T2-25)\n",
- "Vb1b1=math.sqrt(Rbb*Pd)\n",
- "\n",
- "#Results\n",
- "print(\"Maximum Vb1b1 that should be used at a temp 100 is %3.1fV \" %Vb1b1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum Vb1b1 that should be used at a temp 100 is 26.8V \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.8 Page No 931"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Vb1b1=25\n",
- "nmax=0.86\n",
- "nmin=0.74\n",
- "Vd=0.7\n",
- "\n",
- "#Calculations\n",
- "Vpmax=Vd+(nmax*Vb1b1)\n",
- "Vpmin=Vd+(nmin*Vb1b1)\n",
- "\n",
- "#Results\n",
- "print(\"Maximum Vpmax that should be is %3.1fV \" %Vpmax)\n",
- "print(\"Minimum Vpmin that should be is %3.1fV \" %Vpmin)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum Vpmax that should be is 22.2V \n",
- "Minimum Vpmin that should be is 19.2V \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.9 Page No 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Ip=.6*10**-6\n",
- "Iv=2*10**-3\n",
- "Veb1=2.5\n",
- "Vpmin=19.2\n",
- "Vpmax=22.2\n",
- "Vbb=25.0\n",
- "C=1*10**-6\n",
- "R=18*10**3\n",
- "Vp=20.0\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Vpmin=(Vbb-Vpmax)/Ip\n",
- "Remax=(Vbb-Veb1)/Iv\n",
- "t=C*R*math.log((Vbb-Veb1)/(Vbb-Vp))\n",
- "f=1.0/t\n",
- "\n",
- "#Results\n",
- "print(\"The value of f is %.2f \" %f)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of f is 36.94 \n"
- ]
- }
- ],
- "prompt_number": 23
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter20_1.ipynb b/Electronic_Devices_and_Circuits/Chapter20_1.ipynb deleted file mode 100755 index dcf6cb7f..00000000 --- a/Electronic_Devices_and_Circuits/Chapter20_1.ipynb +++ /dev/null @@ -1,434 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 20 : Thyristors "
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.1, Page No 902"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vs=25.0\n",
- "Vtm=1.7\n",
- "Rl=25.0\n",
- "Ih=5*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vspk=1.414*Vs\n",
- "Ilpk=(Vs-Vtm)/Rl\n",
- "print(\" for half wave rectifier sinusodial waveform\")\n",
- "Ilrms=.5*Ilpk\n",
- "es=Vtm+(Ih*Rl)\n",
- "\n",
- "#Results\n",
- "print(\" switch-off voltage =%.2f v\" %es)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for half wave rectifier sinusodial waveform\n",
- " switch-off voltage =1.82 v\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.2, Page No 905"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vs=30.0\n",
- "Vd1=.7\n",
- "Vg=.8\n",
- "Ig=200*10**-6\n",
- "\n",
- "#Calculations\n",
- "Vspk=1.414*Vs\n",
- "print(\" at 5 degree\")\n",
- "es=Vspk*.087 # sin5=.087\n",
- "print(\" at 90 degree\")\n",
- "es=Vspk\n",
- "Vt=Vd1+Vg\n",
- "print(\" to trigger at es=3.7V the R2 moving contact is at the top\")\n",
- "es=3.7\n",
- "Vr1=es-Vt\n",
- "I1=1*10**-3\n",
- "R1=Vr1/I1\n",
- "R=Vt/I1 #R=R2+R3\n",
- "es=42.4\n",
- "Vr3=Vt\n",
- "I1=es/(R+R1)\n",
- "R3=Vt/I1\n",
- "R2=R-R3\n",
- "\n",
- "#Results\n",
- "print(\" To trigger at es =42.4 the R2 moving contact at the bottom =%.2f\" %R2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " at 5 degree\n",
- " at 90 degree\n",
- " to trigger at es=3.7V the R2 moving contact is at the top\n",
- " To trigger at es =42.4 the R2 moving contact at the bottom =1369.10\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.3 Page No 906"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "R1=2.2*10**3\n",
- "R2=1.5*10**3\n",
- "R3=120.0\n",
- "Vt=1.5\n",
- "\n",
- "#Calculations\n",
- "Vak1=Vt*((R1+R2+R3)/(R3+.5*R2))\n",
- "Vak2=Vt*((R1+R2+R3)/R3)\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\" with R2 contact at center = %.2f\" %Vak1)\n",
- "print(\" with R2 contact at zero = %.2f\" %Vak2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R2 contact at center = 6.59\n",
- " with R2 contact at zero = 47.75\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.4, Page No 911"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vs=5.0\n",
- "Ilmax=300*10**-3\n",
- "Vl=7.0\n",
- "Vg=0.8\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Vz=Vl-Vg\n",
- "print(\" for D1, select a 1N753 with Vz=6.2\")\n",
- "Izmin=1*10**-3\n",
- "R1=Vg/Izmin\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %d kohm \" %R1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for D1, select a 1N753 with Vz=6.2\n",
- "The value of R1 is 800 kohm \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.5 Page No 911"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=25*10**3\n",
- "R2=2.7*10**3\n",
- "C1=3*10**-6\n",
- "Vg=0.8\n",
- "Vd1=8.0\n",
- "Vs=115.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Vc1=Vd1+Vg\n",
- "#assume the average charging voltage is\n",
- "Vac=1.414*Vs\n",
- "E=.636*Vac\n",
- "#average charging\n",
- "Ic=E/(R1+R2)\n",
- "#charging time\n",
- "t=(C1*Vc1)/Ic\n",
- "T=1/f\n",
- "q=(t*360)/T\n",
- "a=180-q\n",
- "\n",
- "#Results\n",
- "print(\"Conduction angle =%.2f degrees\" %a)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Conduction angle =27.27 degrees\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.6 Page No 925"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vs=10.0\n",
- "Vf=1.7\n",
- "Is=500*10**-6\n",
- "Ih=1.5*10**-3\n",
- "E=30.0\n",
- "\n",
- "#Calculations\n",
- "R=27*10**3\n",
- "C=0.5*10**-6\n",
- "R1max=(E-Vs)/Is\n",
- "R1min=(E-Vf)/Ih\n",
- "t=C*R*math.log((E-Vf)/(E-Vs))\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"Capacitor charging time is %3.4f s\" %t)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitor charging time is 0.0047 s\n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.7, Page No 931"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rbb=4.0*10**3\n",
- "Pd25=360.0*10**-3\n",
- "D=2.4*10**-3\n",
- "T2=100.0\n",
- "\n",
- "#Calculations\n",
- "Pd=Pd25-D*(T2-25)\n",
- "Vb1b1=math.sqrt(Rbb*Pd)\n",
- "\n",
- "#Results\n",
- "print(\"Maximum Vb1b1 that should be used at a temp 100 is %3.1fV \" %Vb1b1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum Vb1b1 that should be used at a temp 100 is 26.8V \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.8 Page No 931"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Vb1b1=25\n",
- "nmax=0.86\n",
- "nmin=0.74\n",
- "Vd=0.7\n",
- "\n",
- "#Calculations\n",
- "Vpmax=Vd+(nmax*Vb1b1)\n",
- "Vpmin=Vd+(nmin*Vb1b1)\n",
- "\n",
- "#Results\n",
- "print(\"Maximum Vpmax that should be is %3.1fV \" %Vpmax)\n",
- "print(\"Minimum Vpmin that should be is %3.1fV \" %Vpmin)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum Vpmax that should be is 22.2V \n",
- "Minimum Vpmin that should be is 19.2V \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.9 Page No 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Ip=.6*10**-6\n",
- "Iv=2*10**-3\n",
- "Veb1=2.5\n",
- "Vpmin=19.2\n",
- "Vpmax=22.2\n",
- "Vbb=25.0\n",
- "C=1*10**-6\n",
- "R=18*10**3\n",
- "Vp=20.0\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Vpmin=(Vbb-Vpmax)/Ip\n",
- "Remax=(Vbb-Veb1)/Iv\n",
- "t=C*R*math.log((Vbb-Veb1)/(Vbb-Vp))\n",
- "f=1.0/t\n",
- "\n",
- "#Results\n",
- "print(\"The value of f is %.2f \" %f)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of f is 36.94 \n"
- ]
- }
- ],
- "prompt_number": 23
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter20_2.ipynb b/Electronic_Devices_and_Circuits/Chapter20_2.ipynb deleted file mode 100755 index dcf6cb7f..00000000 --- a/Electronic_Devices_and_Circuits/Chapter20_2.ipynb +++ /dev/null @@ -1,434 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 20 : Thyristors "
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.1, Page No 902"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vs=25.0\n",
- "Vtm=1.7\n",
- "Rl=25.0\n",
- "Ih=5*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vspk=1.414*Vs\n",
- "Ilpk=(Vs-Vtm)/Rl\n",
- "print(\" for half wave rectifier sinusodial waveform\")\n",
- "Ilrms=.5*Ilpk\n",
- "es=Vtm+(Ih*Rl)\n",
- "\n",
- "#Results\n",
- "print(\" switch-off voltage =%.2f v\" %es)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for half wave rectifier sinusodial waveform\n",
- " switch-off voltage =1.82 v\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.2, Page No 905"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vs=30.0\n",
- "Vd1=.7\n",
- "Vg=.8\n",
- "Ig=200*10**-6\n",
- "\n",
- "#Calculations\n",
- "Vspk=1.414*Vs\n",
- "print(\" at 5 degree\")\n",
- "es=Vspk*.087 # sin5=.087\n",
- "print(\" at 90 degree\")\n",
- "es=Vspk\n",
- "Vt=Vd1+Vg\n",
- "print(\" to trigger at es=3.7V the R2 moving contact is at the top\")\n",
- "es=3.7\n",
- "Vr1=es-Vt\n",
- "I1=1*10**-3\n",
- "R1=Vr1/I1\n",
- "R=Vt/I1 #R=R2+R3\n",
- "es=42.4\n",
- "Vr3=Vt\n",
- "I1=es/(R+R1)\n",
- "R3=Vt/I1\n",
- "R2=R-R3\n",
- "\n",
- "#Results\n",
- "print(\" To trigger at es =42.4 the R2 moving contact at the bottom =%.2f\" %R2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " at 5 degree\n",
- " at 90 degree\n",
- " to trigger at es=3.7V the R2 moving contact is at the top\n",
- " To trigger at es =42.4 the R2 moving contact at the bottom =1369.10\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.3 Page No 906"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "R1=2.2*10**3\n",
- "R2=1.5*10**3\n",
- "R3=120.0\n",
- "Vt=1.5\n",
- "\n",
- "#Calculations\n",
- "Vak1=Vt*((R1+R2+R3)/(R3+.5*R2))\n",
- "Vak2=Vt*((R1+R2+R3)/R3)\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\" with R2 contact at center = %.2f\" %Vak1)\n",
- "print(\" with R2 contact at zero = %.2f\" %Vak2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R2 contact at center = 6.59\n",
- " with R2 contact at zero = 47.75\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.4, Page No 911"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vs=5.0\n",
- "Ilmax=300*10**-3\n",
- "Vl=7.0\n",
- "Vg=0.8\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Vz=Vl-Vg\n",
- "print(\" for D1, select a 1N753 with Vz=6.2\")\n",
- "Izmin=1*10**-3\n",
- "R1=Vg/Izmin\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %d kohm \" %R1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for D1, select a 1N753 with Vz=6.2\n",
- "The value of R1 is 800 kohm \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.5 Page No 911"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=25*10**3\n",
- "R2=2.7*10**3\n",
- "C1=3*10**-6\n",
- "Vg=0.8\n",
- "Vd1=8.0\n",
- "Vs=115.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Vc1=Vd1+Vg\n",
- "#assume the average charging voltage is\n",
- "Vac=1.414*Vs\n",
- "E=.636*Vac\n",
- "#average charging\n",
- "Ic=E/(R1+R2)\n",
- "#charging time\n",
- "t=(C1*Vc1)/Ic\n",
- "T=1/f\n",
- "q=(t*360)/T\n",
- "a=180-q\n",
- "\n",
- "#Results\n",
- "print(\"Conduction angle =%.2f degrees\" %a)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Conduction angle =27.27 degrees\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.6 Page No 925"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vs=10.0\n",
- "Vf=1.7\n",
- "Is=500*10**-6\n",
- "Ih=1.5*10**-3\n",
- "E=30.0\n",
- "\n",
- "#Calculations\n",
- "R=27*10**3\n",
- "C=0.5*10**-6\n",
- "R1max=(E-Vs)/Is\n",
- "R1min=(E-Vf)/Ih\n",
- "t=C*R*math.log((E-Vf)/(E-Vs))\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"Capacitor charging time is %3.4f s\" %t)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitor charging time is 0.0047 s\n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.7, Page No 931"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rbb=4.0*10**3\n",
- "Pd25=360.0*10**-3\n",
- "D=2.4*10**-3\n",
- "T2=100.0\n",
- "\n",
- "#Calculations\n",
- "Pd=Pd25-D*(T2-25)\n",
- "Vb1b1=math.sqrt(Rbb*Pd)\n",
- "\n",
- "#Results\n",
- "print(\"Maximum Vb1b1 that should be used at a temp 100 is %3.1fV \" %Vb1b1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum Vb1b1 that should be used at a temp 100 is 26.8V \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.8 Page No 931"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Vb1b1=25\n",
- "nmax=0.86\n",
- "nmin=0.74\n",
- "Vd=0.7\n",
- "\n",
- "#Calculations\n",
- "Vpmax=Vd+(nmax*Vb1b1)\n",
- "Vpmin=Vd+(nmin*Vb1b1)\n",
- "\n",
- "#Results\n",
- "print(\"Maximum Vpmax that should be is %3.1fV \" %Vpmax)\n",
- "print(\"Minimum Vpmin that should be is %3.1fV \" %Vpmin)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum Vpmax that should be is 22.2V \n",
- "Minimum Vpmin that should be is 19.2V \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 20.9 Page No 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Ip=.6*10**-6\n",
- "Iv=2*10**-3\n",
- "Veb1=2.5\n",
- "Vpmin=19.2\n",
- "Vpmax=22.2\n",
- "Vbb=25.0\n",
- "C=1*10**-6\n",
- "R=18*10**3\n",
- "Vp=20.0\n",
- "\n",
- "\n",
- "#Calculations\n",
- "Vpmin=(Vbb-Vpmax)/Ip\n",
- "Remax=(Vbb-Veb1)/Iv\n",
- "t=C*R*math.log((Vbb-Veb1)/(Vbb-Vp))\n",
- "f=1.0/t\n",
- "\n",
- "#Results\n",
- "print(\"The value of f is %.2f \" %f)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of f is 36.94 \n"
- ]
- }
- ],
- "prompt_number": 23
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter21.ipynb b/Electronic_Devices_and_Circuits/Chapter21.ipynb deleted file mode 100755 index adcb4972..00000000 --- a/Electronic_Devices_and_Circuits/Chapter21.ipynb +++ /dev/null @@ -1,241 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 21 : Optoelectronic Devices"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.1, Page No 947"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "r=3.0\n",
- "Os=25.0\n",
- "area=0.25\n",
- "\n",
- "#Calculations\n",
- "Ea=Os/(4.0*3.14*(r)**2)\n",
- "Tf=Ea*area\n",
- "\n",
- "#Results\n",
- "print(\" total flux is %3.3fW \" %Tf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " total flux is 0.055W \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.3, Page No 951"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=9.0\n",
- "Vf=1.6\n",
- "Vb=7.0\n",
- "hFE=100.0\n",
- "Vce=0.2\n",
- "Ic=10.0*10**-3\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "R2=(Vcc-Vf-Vce)/Ic\n",
- "R2=680#use standard value\n",
- "Ic=(Vcc-Vf-Vce)/R2\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vb-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %d kohm\" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 59 kohm\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.4 Page No 952"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=5.0\n",
- "N=(3*7.0)+(1.0*2)\n",
- "\n",
- "#Calculations\n",
- "It=N*10.0*10**-3\n",
- "P=It*Vcc\n",
- "\n",
- "#Results\n",
- "print(\"The value of power is %.2f W\" %P)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of power is 1.15 W\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.5, Page No 957"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=1.0*10**3\n",
- "I=10.0*10**-3\n",
- "E=30.0\n",
- "\n",
- "#Calculations\n",
- "R1=E/I -Rc\n",
- "R1=1.8*10**3#use standard value\n",
- "print(\" when dark Rc=100Kohm\")\n",
- "Rc=100*10**3\n",
- "I=E/(R1+Rc)\n",
- "\n",
- "#Results\n",
- "print(\"The value of I is %.2f mA\" %(I*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " when dark Rc=100Kohm\n",
- "The value of I is 0.29 mA\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.6 Page No 958"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vee=6.0\n",
- "Vbe=0.7\n",
- "Ib=200.0*10**-6\n",
- "Vb=0.7\n",
- "Vcc=6.0\n",
- "\n",
- "#Calculations\n",
- "print(\"when cell is dark Rc=100Kohm\")\n",
- "Rc=100.0*10**3\n",
- "Vrc=Vee+Vbe\n",
- "Irc=Vrc/Rc\n",
- "Ir1=Irc+Ib\n",
- "Vr1=Vcc-Vb\n",
- "R1=Vr1/Ir1\n",
- "R1=18.0*10**3#use standard value\n",
- "print(\" when Q1 is off\")\n",
- "Vr1=6.0\n",
- "Vrc=6.0\n",
- "Ir1=Vr1/R1\n",
- "Rc=Vrc/Ir1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rc is %d kohm\" %(Rc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when cell is dark Rc=100Kohm\n",
- " when Q1 is off\n",
- "The value of Rc is 18 kohm\n"
- ]
- }
- ],
- "prompt_number": 17
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter21_1.ipynb b/Electronic_Devices_and_Circuits/Chapter21_1.ipynb deleted file mode 100755 index adcb4972..00000000 --- a/Electronic_Devices_and_Circuits/Chapter21_1.ipynb +++ /dev/null @@ -1,241 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 21 : Optoelectronic Devices"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.1, Page No 947"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "r=3.0\n",
- "Os=25.0\n",
- "area=0.25\n",
- "\n",
- "#Calculations\n",
- "Ea=Os/(4.0*3.14*(r)**2)\n",
- "Tf=Ea*area\n",
- "\n",
- "#Results\n",
- "print(\" total flux is %3.3fW \" %Tf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " total flux is 0.055W \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.3, Page No 951"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=9.0\n",
- "Vf=1.6\n",
- "Vb=7.0\n",
- "hFE=100.0\n",
- "Vce=0.2\n",
- "Ic=10.0*10**-3\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "R2=(Vcc-Vf-Vce)/Ic\n",
- "R2=680#use standard value\n",
- "Ic=(Vcc-Vf-Vce)/R2\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vb-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %d kohm\" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 59 kohm\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.4 Page No 952"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=5.0\n",
- "N=(3*7.0)+(1.0*2)\n",
- "\n",
- "#Calculations\n",
- "It=N*10.0*10**-3\n",
- "P=It*Vcc\n",
- "\n",
- "#Results\n",
- "print(\"The value of power is %.2f W\" %P)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of power is 1.15 W\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.5, Page No 957"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=1.0*10**3\n",
- "I=10.0*10**-3\n",
- "E=30.0\n",
- "\n",
- "#Calculations\n",
- "R1=E/I -Rc\n",
- "R1=1.8*10**3#use standard value\n",
- "print(\" when dark Rc=100Kohm\")\n",
- "Rc=100*10**3\n",
- "I=E/(R1+Rc)\n",
- "\n",
- "#Results\n",
- "print(\"The value of I is %.2f mA\" %(I*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " when dark Rc=100Kohm\n",
- "The value of I is 0.29 mA\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.6 Page No 958"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vee=6.0\n",
- "Vbe=0.7\n",
- "Ib=200.0*10**-6\n",
- "Vb=0.7\n",
- "Vcc=6.0\n",
- "\n",
- "#Calculations\n",
- "print(\"when cell is dark Rc=100Kohm\")\n",
- "Rc=100.0*10**3\n",
- "Vrc=Vee+Vbe\n",
- "Irc=Vrc/Rc\n",
- "Ir1=Irc+Ib\n",
- "Vr1=Vcc-Vb\n",
- "R1=Vr1/Ir1\n",
- "R1=18.0*10**3#use standard value\n",
- "print(\" when Q1 is off\")\n",
- "Vr1=6.0\n",
- "Vrc=6.0\n",
- "Ir1=Vr1/R1\n",
- "Rc=Vrc/Ir1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rc is %d kohm\" %(Rc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when cell is dark Rc=100Kohm\n",
- " when Q1 is off\n",
- "The value of Rc is 18 kohm\n"
- ]
- }
- ],
- "prompt_number": 17
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter21_2.ipynb b/Electronic_Devices_and_Circuits/Chapter21_2.ipynb deleted file mode 100755 index adcb4972..00000000 --- a/Electronic_Devices_and_Circuits/Chapter21_2.ipynb +++ /dev/null @@ -1,241 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 21 : Optoelectronic Devices"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.1, Page No 947"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "r=3.0\n",
- "Os=25.0\n",
- "area=0.25\n",
- "\n",
- "#Calculations\n",
- "Ea=Os/(4.0*3.14*(r)**2)\n",
- "Tf=Ea*area\n",
- "\n",
- "#Results\n",
- "print(\" total flux is %3.3fW \" %Tf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " total flux is 0.055W \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.3, Page No 951"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=9.0\n",
- "Vf=1.6\n",
- "Vb=7.0\n",
- "hFE=100.0\n",
- "Vce=0.2\n",
- "Ic=10.0*10**-3\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "R2=(Vcc-Vf-Vce)/Ic\n",
- "R2=680#use standard value\n",
- "Ic=(Vcc-Vf-Vce)/R2\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vb-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %d kohm\" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 59 kohm\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.4 Page No 952"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=5.0\n",
- "N=(3*7.0)+(1.0*2)\n",
- "\n",
- "#Calculations\n",
- "It=N*10.0*10**-3\n",
- "P=It*Vcc\n",
- "\n",
- "#Results\n",
- "print(\"The value of power is %.2f W\" %P)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of power is 1.15 W\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.5, Page No 957"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=1.0*10**3\n",
- "I=10.0*10**-3\n",
- "E=30.0\n",
- "\n",
- "#Calculations\n",
- "R1=E/I -Rc\n",
- "R1=1.8*10**3#use standard value\n",
- "print(\" when dark Rc=100Kohm\")\n",
- "Rc=100*10**3\n",
- "I=E/(R1+Rc)\n",
- "\n",
- "#Results\n",
- "print(\"The value of I is %.2f mA\" %(I*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " when dark Rc=100Kohm\n",
- "The value of I is 0.29 mA\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 21.6 Page No 958"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vee=6.0\n",
- "Vbe=0.7\n",
- "Ib=200.0*10**-6\n",
- "Vb=0.7\n",
- "Vcc=6.0\n",
- "\n",
- "#Calculations\n",
- "print(\"when cell is dark Rc=100Kohm\")\n",
- "Rc=100.0*10**3\n",
- "Vrc=Vee+Vbe\n",
- "Irc=Vrc/Rc\n",
- "Ir1=Irc+Ib\n",
- "Vr1=Vcc-Vb\n",
- "R1=Vr1/Ir1\n",
- "R1=18.0*10**3#use standard value\n",
- "print(\" when Q1 is off\")\n",
- "Vr1=6.0\n",
- "Vrc=6.0\n",
- "Ir1=Vr1/R1\n",
- "Rc=Vrc/Ir1\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rc is %d kohm\" %(Rc/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when cell is dark Rc=100Kohm\n",
- " when Q1 is off\n",
- "The value of Rc is 18 kohm\n"
- ]
- }
- ],
- "prompt_number": 17
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter2_1.ipynb b/Electronic_Devices_and_Circuits/Chapter2_1.ipynb deleted file mode 100755 index 1c97e28b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter2_1.ipynb +++ /dev/null @@ -1,571 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 02 : Semiconductor diodes"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.1, Page No 37"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=100*10**-3\n",
- "Vf=.75 #given\n",
- "print(\"a)\")\n",
- "print(\"forward resistance\")\n",
- "\n",
- "#Calculations\n",
- "Rf=Vf/If\n",
- "print(\"forward resistnace is %3.1fohm \" %Rf)\n",
- "print(\"b)\")\n",
- "Vr=50\n",
- "Ir=100*10**-9\n",
- "Rr=(Vr/Ir)\n",
- "\n",
- "#Results\n",
- "print(\"reverse resistnace is %.1fohm \" %(Rr/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "a)\n",
- "forward resistance\n",
- "forward resistnace is 7.5ohm \n",
- "b)\n",
- "reverse resistnace is 500.0ohm \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.2, Page No 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=70*10**-3\n",
- "\n",
- "#Calculations\n",
- "rd=(26*10**-3)/If\n",
- "print(\"dynamic resistance is %.2fohm \" %rd)\n",
- "If=60*10**-3\n",
- "Vf=.025\n",
- "rd=Vf/If\n",
- "\n",
- "#Results\n",
- "print(\"dynamic resistance is %.2fohm \" %rd)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "dynamic resistance is 0.37ohm \n",
- "dynamic resistance is 0.42ohm \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.3 Page No 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=4.7*10**3\n",
- "E=15.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "print(\"diode current is E=If*R1+Vf\")\n",
- "If=((E-Vf)/R1)*10**3\n",
- "\n",
- "#Results\n",
- "print(\" diode current is %.2fmA \" %If) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "diode current is E=If*R1+Vf\n",
- " diode current is 3.04mA \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.5, Page No 41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=1.5\n",
- "Vf=0.7\n",
- "R1=10\n",
- "rd=.25\n",
- "\n",
- "#Calculations\n",
- "print(\"a)\")\n",
- "If=(E-Vf)/R1\n",
- "print(\" forward current is %0.1fmA \" %(If*1000))\n",
- "print(\"b)\")\n",
- "If=(E-Vf)/(R1+rd)\n",
- "\n",
- "#Results\n",
- "print(\" forward current is %0.1fmA \" %(If*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "a)\n",
- " forward current is 80.0mA \n",
- "b)\n",
- " forward current is 78.0mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.6 Page No 43"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=0\n",
- "Vf=5.0\n",
- "R1=100.0\n",
- "\n",
- "#Calculations\n",
- "E=(If*R1)+Vf\n",
- "print(\"B)\")\n",
- "Vf=0\n",
- "E=5.0\n",
- "R1=100.0\n",
- "If=(E/R1)*1000\n",
- "\n",
- "#Results\n",
- "print(\"resistance is %dmA \" %If) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "B)\n",
- "resistance is 50mA \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.8 Page No 45"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=50*10**-3\n",
- "Vf=1.1\n",
- "R1=100.0\n",
- "\n",
- "#Calculations\n",
- "Vf1=If*R1\n",
- "E=Vf1+Vf\n",
- "\n",
- "#Results\n",
- "print(\" new supply voltage is %.2fV \" %E)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " new supply voltage is 6.10V \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.9, Page No 48"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "P1=700.0*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "If=P1/Vf\n",
- "#at 65C\n",
- "D=5*10**-3\n",
- "T=65-25\n",
- "P2=P1-D*T\n",
- "If=P2/Vf\n",
- "\n",
- "#Results\n",
- "print( \"maximum forward current at 65C is %.1fA \" %(If*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum forward current at 65C is 714.3A \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.10 Page No 49"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vf1=0.7\n",
- "Vf=-1.8*10**-3\n",
- "If=26.0*10**-3\n",
- "T=100-25\n",
- "\n",
- "#Calculations\n",
- "Vf2=Vf1+(T*Vf)\n",
- "print(\" voltage at 100C is %.3f V \" %Vf2)\n",
- "print(\"At 25C\")\n",
- "T1=25.0\n",
- "rd=(26*10**-3/If)*((T1+273)/298)\n",
- "print(\" resistance at 25 C is %.2f ohm \" %rd)\n",
- "print(\" At 100C\")\n",
- "T2=100.0\n",
- "rd=(26*10**-3/If)*((T2+273)/298)\n",
- "\n",
- "#Results\n",
- "print(\" resistance at 100 C is %.2fohm \" %rd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage at 100C is 0.565 V \n",
- "At 25C\n",
- " resistance at 25 C is 1.00 ohm \n",
- " At 100C\n",
- " resistance at 100 C is 1.25ohm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.11 Page No 51"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variablesV_s=230\n",
- "If=10*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "t=70.0*10**-9\n",
- "Cd=((t*If)/Vf)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" diffusion capacitance is %.2f nF \" %Cd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " diffusion capacitance is 1.00 nF \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.12 Page No 53"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "print(\"A\")\n",
- "trr=10.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "tf=10.0*trr*10**9\n",
- "print(\"minimum fall times is %d ns \" %tf)\n",
- "print(\"B)\")\n",
- "trr=3.0\n",
- "tf=10*trr\n",
- "\n",
- "#Results\n",
- "print(\"minimum fall times is %d ns \" %tf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "A\n",
- "minimum fall times is 100 ns \n",
- "B)\n",
- "minimum fall times is 30 ns \n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.14, Page No 58"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Io=75.0*10**-3\n",
- "#vertical scale of 5mA/cm \n",
- "\n",
- "#Calculations\n",
- "If=Io/5*10**-3\n",
- "R1=15/(75*10**-3)\n",
- "P=((Io)**2)*R1\n",
- "\n",
- "#Results\n",
- "print(\"Pr1 = %1.1f W \" %P)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Pr1 = 1.1 W \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.15, Page No 63"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=7.5\n",
- "Pd=400.0*10**-3\n",
- "D=3.2*10**-3\n",
- "\n",
- "#Calculations\n",
- "Izm=Pd/Vz\n",
- "print(\"current at 50C is %.1fA \" %(Izm*1000))\n",
- "print(\"At 100C\")\n",
- "P2=Pd-((100-50)*D)\n",
- "print(\" power at 100C is %.3fW \" %P2)\n",
- "Izm=P2/Vz\n",
- "\n",
- "#Results\n",
- "print(\" current at 100C is %.1fA \" %(Izm*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "current at 50C is 53.3A \n",
- "At 100C\n",
- " power at 100C is 0.240W \n",
- " current at 100C is 32.0A \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.16, Page No 64"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=20.0\n",
- "R1=620.0\n",
- "Vz=7.5\n",
- "\n",
- "#Calculations\n",
- "Vr1=E-Vz\n",
- "Iz=Vr1/R1\n",
- "print(\" diode current is %.1f mA \" %(Iz*1000))\n",
- "Pd=Vz*Iz\n",
- "\n",
- "#Results\n",
- "print( \"power dissipation is %.1f mW \" %(Pd*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " diode current is 20.2 mA \n",
- "power dissipation is 151.2 mW \n"
- ]
- }
- ],
- "prompt_number": 26
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter2_2.ipynb b/Electronic_Devices_and_Circuits/Chapter2_2.ipynb deleted file mode 100755 index 1c97e28b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter2_2.ipynb +++ /dev/null @@ -1,571 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 02 : Semiconductor diodes"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.1, Page No 37"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=100*10**-3\n",
- "Vf=.75 #given\n",
- "print(\"a)\")\n",
- "print(\"forward resistance\")\n",
- "\n",
- "#Calculations\n",
- "Rf=Vf/If\n",
- "print(\"forward resistnace is %3.1fohm \" %Rf)\n",
- "print(\"b)\")\n",
- "Vr=50\n",
- "Ir=100*10**-9\n",
- "Rr=(Vr/Ir)\n",
- "\n",
- "#Results\n",
- "print(\"reverse resistnace is %.1fohm \" %(Rr/10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "a)\n",
- "forward resistance\n",
- "forward resistnace is 7.5ohm \n",
- "b)\n",
- "reverse resistnace is 500.0ohm \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.2, Page No 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=70*10**-3\n",
- "\n",
- "#Calculations\n",
- "rd=(26*10**-3)/If\n",
- "print(\"dynamic resistance is %.2fohm \" %rd)\n",
- "If=60*10**-3\n",
- "Vf=.025\n",
- "rd=Vf/If\n",
- "\n",
- "#Results\n",
- "print(\"dynamic resistance is %.2fohm \" %rd)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "dynamic resistance is 0.37ohm \n",
- "dynamic resistance is 0.42ohm \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.3 Page No 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=4.7*10**3\n",
- "E=15.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "print(\"diode current is E=If*R1+Vf\")\n",
- "If=((E-Vf)/R1)*10**3\n",
- "\n",
- "#Results\n",
- "print(\" diode current is %.2fmA \" %If) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "diode current is E=If*R1+Vf\n",
- " diode current is 3.04mA \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.5, Page No 41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=1.5\n",
- "Vf=0.7\n",
- "R1=10\n",
- "rd=.25\n",
- "\n",
- "#Calculations\n",
- "print(\"a)\")\n",
- "If=(E-Vf)/R1\n",
- "print(\" forward current is %0.1fmA \" %(If*1000))\n",
- "print(\"b)\")\n",
- "If=(E-Vf)/(R1+rd)\n",
- "\n",
- "#Results\n",
- "print(\" forward current is %0.1fmA \" %(If*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "a)\n",
- " forward current is 80.0mA \n",
- "b)\n",
- " forward current is 78.0mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.6 Page No 43"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=0\n",
- "Vf=5.0\n",
- "R1=100.0\n",
- "\n",
- "#Calculations\n",
- "E=(If*R1)+Vf\n",
- "print(\"B)\")\n",
- "Vf=0\n",
- "E=5.0\n",
- "R1=100.0\n",
- "If=(E/R1)*1000\n",
- "\n",
- "#Results\n",
- "print(\"resistance is %dmA \" %If) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "B)\n",
- "resistance is 50mA \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.8 Page No 45"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "If=50*10**-3\n",
- "Vf=1.1\n",
- "R1=100.0\n",
- "\n",
- "#Calculations\n",
- "Vf1=If*R1\n",
- "E=Vf1+Vf\n",
- "\n",
- "#Results\n",
- "print(\" new supply voltage is %.2fV \" %E)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " new supply voltage is 6.10V \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.9, Page No 48"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "P1=700.0*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "If=P1/Vf\n",
- "#at 65C\n",
- "D=5*10**-3\n",
- "T=65-25\n",
- "P2=P1-D*T\n",
- "If=P2/Vf\n",
- "\n",
- "#Results\n",
- "print( \"maximum forward current at 65C is %.1fA \" %(If*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum forward current at 65C is 714.3A \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.10 Page No 49"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vf1=0.7\n",
- "Vf=-1.8*10**-3\n",
- "If=26.0*10**-3\n",
- "T=100-25\n",
- "\n",
- "#Calculations\n",
- "Vf2=Vf1+(T*Vf)\n",
- "print(\" voltage at 100C is %.3f V \" %Vf2)\n",
- "print(\"At 25C\")\n",
- "T1=25.0\n",
- "rd=(26*10**-3/If)*((T1+273)/298)\n",
- "print(\" resistance at 25 C is %.2f ohm \" %rd)\n",
- "print(\" At 100C\")\n",
- "T2=100.0\n",
- "rd=(26*10**-3/If)*((T2+273)/298)\n",
- "\n",
- "#Results\n",
- "print(\" resistance at 100 C is %.2fohm \" %rd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage at 100C is 0.565 V \n",
- "At 25C\n",
- " resistance at 25 C is 1.00 ohm \n",
- " At 100C\n",
- " resistance at 100 C is 1.25ohm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.11 Page No 51"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variablesV_s=230\n",
- "If=10*10**-3\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "t=70.0*10**-9\n",
- "Cd=((t*If)/Vf)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" diffusion capacitance is %.2f nF \" %Cd)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " diffusion capacitance is 1.00 nF \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.12 Page No 53"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "print(\"A\")\n",
- "trr=10.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "tf=10.0*trr*10**9\n",
- "print(\"minimum fall times is %d ns \" %tf)\n",
- "print(\"B)\")\n",
- "trr=3.0\n",
- "tf=10*trr\n",
- "\n",
- "#Results\n",
- "print(\"minimum fall times is %d ns \" %tf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "A\n",
- "minimum fall times is 100 ns \n",
- "B)\n",
- "minimum fall times is 30 ns \n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.14, Page No 58"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Io=75.0*10**-3\n",
- "#vertical scale of 5mA/cm \n",
- "\n",
- "#Calculations\n",
- "If=Io/5*10**-3\n",
- "R1=15/(75*10**-3)\n",
- "P=((Io)**2)*R1\n",
- "\n",
- "#Results\n",
- "print(\"Pr1 = %1.1f W \" %P)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Pr1 = 1.1 W \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.15, Page No 63"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=7.5\n",
- "Pd=400.0*10**-3\n",
- "D=3.2*10**-3\n",
- "\n",
- "#Calculations\n",
- "Izm=Pd/Vz\n",
- "print(\"current at 50C is %.1fA \" %(Izm*1000))\n",
- "print(\"At 100C\")\n",
- "P2=Pd-((100-50)*D)\n",
- "print(\" power at 100C is %.3fW \" %P2)\n",
- "Izm=P2/Vz\n",
- "\n",
- "#Results\n",
- "print(\" current at 100C is %.1fA \" %(Izm*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "current at 50C is 53.3A \n",
- "At 100C\n",
- " power at 100C is 0.240W \n",
- " current at 100C is 32.0A \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.16, Page No 64"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=20.0\n",
- "R1=620.0\n",
- "Vz=7.5\n",
- "\n",
- "#Calculations\n",
- "Vr1=E-Vz\n",
- "Iz=Vr1/R1\n",
- "print(\" diode current is %.1f mA \" %(Iz*1000))\n",
- "Pd=Vz*Iz\n",
- "\n",
- "#Results\n",
- "print( \"power dissipation is %.1f mW \" %(Pd*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " diode current is 20.2 mA \n",
- "power dissipation is 151.2 mW \n"
- ]
- }
- ],
- "prompt_number": 26
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter3.ipynb b/Electronic_Devices_and_Circuits/Chapter3.ipynb deleted file mode 100755 index 8f8a6a3b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter3.ipynb +++ /dev/null @@ -1,1201 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 03 : Diode applications"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.1, Page No 73"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=.7\n",
- "Rl=500.0\n",
- "Vi=22.0\n",
- "Vpi=1.414*Vi\n",
- "\n",
- "#Calculations\n",
- "Vpo=Vpi-Vf\n",
- "print(\" peak vouput voltage is %3.2fV \" %Vpo)\n",
- "Ip=Vpo/Rl\n",
- "\n",
- "#Results\n",
- "print(\"peak load current is %3.4fA \" %Ip)\n",
- "PIV=Vpi\n",
- "print(\"diode paek reverse voltage %3.2fV \" %PIV)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " peak vouput voltage is 30.41V \n",
- "peak load current is 0.0608A \n",
- "diode paek reverse voltage 31.11V \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.2, Page No 79"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vi=30.0\n",
- "Rl=300.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "Vpi=1.414*Vi\n",
- "Vpo=Vpi-2*Vf\n",
- "print(\" peak output voltage %.3f V \" %Vpo)\n",
- "Ip=Vpo/Rl\n",
- "\n",
- "#Results\n",
- "print(\" current bridge is %.1f mA \" %(Ip*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " peak output voltage 41.020 V \n",
- " current bridge is 136.7 mA \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.3 Page No 83"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "C1=680.0*10**-6\n",
- "Eo=28.0\n",
- "Rl=200.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Il=Eo/Rl\n",
- "T=1/f\n",
- "t1=T\n",
- "Vr=(Il*t1)/C1\n",
- "\n",
- "#Results\n",
- "print(\"peak to peak ripple voltage is %.2f V \" %Vr)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "peak to peak ripple voltage is 3.43 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.4, Page No 84"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "Rl=500.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Vr=(10*Eo)/100#10% of Eo\n",
- "Il=Eo/Rl\n",
- "T=1/f\n",
- "t1=T\n",
- "C1=((Il*t1)/Vr)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"Reservior capacitance is %.2f uF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Reservior capacitance is 333.33 uF \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.5 Page No 85"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "f=60.0\n",
- "Rl=500.0\n",
- "Il=Eo/Rl\n",
- "\n",
- "#Calculations\n",
- "Vr=(10.0*Eo)/100\n",
- "print(\"10percent of Eo is %.2f V \" %Vr)\n",
- "Eomin=Eo-0.5*Vr\n",
- "Eomax=Eo+0.5*Vr\n",
- "Q1=math.asin(Eomin/Eomax)\n",
- "Q1=65\n",
- "Q2=90-Q1\n",
- "T=1/f\n",
- "t2=(Q2*T)/360\n",
- "print(\" charging time is %.2fs \" %t2)\n",
- "t1=T-t2\n",
- "print(\"discharging time is %.2fs \" %t1)\n",
- "C1=((Il*t1)/Vr)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"reservior capacitance is %.2f uF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "10percent of Eo is 2.00 V \n",
- " charging time is 0.00s \n",
- "discharging time is 0.02s \n",
- "reservior capacitance is 310.19 uF \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.6 Page No 88"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "t1=1.16*10**-3\n",
- "t2=15.54*10**-3\n",
- "Vp=Eo+Vf\n",
- "Vr=2*Vp\n",
- "Il=40*10**-4\n",
- "Ifrm=(Il*(t1+t2))/t2\n",
- "Ifsm=30.0\n",
- "Rs=Vp/Ifsm\n",
- "\n",
- "#Results\n",
- "print(\" surge limiting resistance is %3.2fohm \" %Rs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " surge limiting resistance is 0.72ohm \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.7, Page No 89 "
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=.7\n",
- "Eo=21.0\n",
- "\n",
- "#Calculations\n",
- "Il=40*10**-3\n",
- "Vp=115.0\n",
- "Vs=.707*(Vf+Eo)\n",
- "print(\" Vrms voltage is %3.3fV \" %Vs)\n",
- "Is=3.6*Il\n",
- "print(\" rms current is %.2f mA \" %(Is*1000))\n",
- "Ip=(Vs*Is)/Vp\n",
- "\n",
- "#Results\n",
- "print(\"primary current is %.2f mA \" %(Ip*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Vrms voltage is 15.342V \n",
- " rms current is 144.00 mA \n",
- "primary current is 19.21 mA \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.8 Page No 92"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Vr=2.0\n",
- "T=16.7*10**-3\n",
- "t2=1.16*10**-3\n",
- "\n",
- "#Calculations\n",
- "Il=40.0*10**-3#from example 3.5\n",
- "t1=(T/2.0)-t2\n",
- "C1=(Il*t1)/Vr\n",
- "\n",
- "#Results\n",
- "print(\" resrvior capacitor is %.2f mF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " resrvior capacitor is 143.80 mF \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.9 Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vr=2.0\n",
- "T=16.7*10**-3\n",
- "Il=40.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "t1=T/2\n",
- "C1=(Il*t1)/Vr\n",
- "\n",
- "#Results\n",
- "print(\" reservior capacitance is %.1fF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " reservior capacitance is 167.0F \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.10 Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "Il=40.0*10**-3\n",
- "t1=7.19*10**-3\n",
- "t2=1.16*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vp=Eo+(2*Vf)\n",
- "Vr=Vp\n",
- "If=Il/2\n",
- "Ifrm=Il*(t1+t2)/t2\n",
- "Ifsm=30\n",
- "Rs=Vp/Ifsm\n",
- "\n",
- "#Results\n",
- "print(\"surge limiting resistance is %.3fohm \" %Rs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "surge limiting resistance is 0.747ohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.11, Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "Il=40*10**-3\n",
- "Vp=115.0\n",
- "\n",
- "#Calculations\n",
- "Vs=0.707*(Eo+2*Vf)\n",
- "Is=1.6*Il\n",
- "Ip=(Vs*Is)/Vp\n",
- "\n",
- "#Results\n",
- "print(\" supply current is %.1f mA \" %(Ip*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " supply current is 8.8 mA \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.12, Page No 97"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "Il=40.0*10**-3\n",
- "R1=22.0\n",
- "Vr=2.0\n",
- "C1=150*10**-6\n",
- "C2=C1\n",
- "fr=120\n",
- "\n",
- "#Calculations\n",
- "Vo=Eo-Il*R1\n",
- "vi=Vr/3.14\n",
- "Xc2=1/(2*3.14*fr*C2)\n",
- "vo=(vi*Xc2)/math.sqrt((R1**2) + (Xc2**2))\n",
- "print(\" dc output voltage is %.3fV \" %vo)\n",
- "Vpp=2*vo\n",
- "\n",
- "#Results\n",
- "print(\" peak to peak voltage is %.1fV \" %(Vpp*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " dc output voltage is 0.238V \n",
- " peak to peak voltage is 475.3V \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.13, Page No 98"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "C1=150*10**-6\n",
- "C2=C1\n",
- "vi=4.0\n",
- "vo=1.0\n",
- "f=120.0\n",
- "\n",
- "#Calculations\n",
- "Xc2=8.84 #FROM EXAMPLE 3.12\n",
- "Xl=Xc2*((vi/vo)+1)\n",
- "L1=Xl/(2*3.14*f)\n",
- "\n",
- "#Results\n",
- "print(\" suitable value of L1 is %.3fH \" %(L1*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable value of L1 is 58.652H \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.14, Page No 101"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Edc=20.0\n",
- "vo=0.24\n",
- "Vo=20.0\n",
- "Il=40*10**-3\n",
- "fr=120.0\n",
- "\n",
- "#Calculations\n",
- "Eomax=(3.14*Edc)/2\n",
- "Epeak=(4*Eomax)/(3*3.14)\n",
- "vi=Epeak\n",
- "Rl=Vo/Il\n",
- "Xlc=(2*Rl)/3\n",
- "Lc=Xlc/(2*3.14*fr)\n",
- "L=1.25*Lc\n",
- "Xl=2*3.14*fr*L\n",
- "Xc=Xl/((vi/vo)+1)\n",
- "C1=1/(2*3.14*fr*Xc)\n",
- "\n",
- "#Results\n",
- "print(\"The value of c1 = %.2f mF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of c1 = 180.11 mF \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.15, Page No 105"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "E0=20-19.7 #load effect\n",
- "\n",
- "#Calculations\n",
- "loadregulation =(E0*100)/Eo#percentage\n",
- "sourceeffect=20.2-20\n",
- "lineregulation =(sourceeffect*100)/Eo\n",
- "\n",
- "#Results\n",
- "print(\"Line regulation = %.1f percent \" %lineregulation)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Line regulation = 1.0 percent \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.16, Page No 108"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=9.1\n",
- "Izt=20*10**-3\n",
- "Es=30.0\n",
- "\n",
- "#Calculations\n",
- "R1=(Es-Vz)/Izt\n",
- "Pr1=(Izt**2)*R1\n",
- "Es=27\n",
- "Iz=(Es-Vz)/R1\n",
- "\n",
- "#Results\n",
- "print(\"The circuit current is %.2f mA \" %(Iz*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The circuit current is 17.13 mA \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.17, Page No 110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=6.2\n",
- "Pd=400.0*10**-3\n",
- "Es=16.0\n",
- "\n",
- "#Calculations\n",
- "Izm=Pd/Vz\n",
- "R1=(Es-Vz)/Izm\n",
- "Pr1=(Izm**2)*R1\n",
- "Izmin=5.0*10**-3\n",
- "Izmax=Izm-Izmin\n",
- "\n",
- "#Results\n",
- "print(\"maximum current is %3.2f mA \" %(Izmax*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum current is 59.52 mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.18, Page No 112"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Zz=7.0\n",
- "Es=16.0\n",
- "Vo=6.2\n",
- "Il=59.5*10**-3\n",
- "\n",
- "#Calculations\n",
- "es=(10*Es)/100.0 #10% os Es\n",
- "Rl=Vo/Il\n",
- "print(\"es*Zz||Rl/R1+Zz||Rl\")\n",
- "V0=es*((Zz*Rl)/(Zz+Rl))/(R1+((Zz*Rl)/(Zz+Rl)))\n",
- "lineregulation=(V0*100)/Vo\n",
- "print(\"line regulation voltage is %3.3fpercentage \" %lineregulation)\n",
- "V0=Il*((Zz*R1)/(Zz+R1))\n",
- "loadregulation=(V0*100)/Vo\n",
- "print(\"loadregulation voltage is %3.3fpercentage \" %loadregulation)\n",
- "Rr=((Zz*Rl)/(Zz+Rl))/(R1+(Zz*Rl)/(Zz+Rl))\n",
- "\n",
- "#Results\n",
- "print(\"ripple rejection is %3.2f X 10^-2 \" %(Rr*10**2))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "es*Zz||Rl/R1+Zz||Rl\n",
- "line regulation voltage is 1.068percentage \n",
- "loadregulation voltage is 6.422percentage \n",
- "ripple rejection is 4.14 X 10^-2 \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.19, Page No 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "E=9.0\n",
- "Vf=.7\n",
- "\n",
- "#Calculations\n",
- "If=1.0*10**-3\n",
- "Vo=E-Vf\n",
- "R1=Vo/If\n",
- "Vr=E\n",
- "\n",
- "#Results\n",
- "print(\"diode forward voltage is %3.2fohm \" %Vr)\n",
- "print(\"diode forward current is %3.1fA \" %(If*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "diode forward voltage is 9.00ohm \n",
- "diode forward current is 1.0A \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.20, Page No 117"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=5.0\n",
- "Vo=4.5\n",
- "Il=2.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=(E-Vo)/Il\n",
- "print(\" suitable resistance is %dohm \" %R1)\n",
- "Vr=E\n",
- "print(\"when diode is forward baised\")\n",
- "If=(E-Vf)/R1\n",
- "\n",
- "#Results\n",
- "print(\" diode forward current is %3.2fA \" %(If*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable resistance is 250ohm \n",
- "when diode is forward baised\n",
- " diode forward current is 17.20A \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.21, Page No 119"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vo=2.7\n",
- "Vf=.7\n",
- "E=9.0\n",
- "If=1*10**-3\n",
- "\n",
- "#Calculations\n",
- "Il=If\n",
- "Vb=Vo-Vf\n",
- "R1=(E-Vo)/(Il+If)\n",
- "\n",
- "#Results\n",
- "print(\"resistance is %.2f kOhm \" %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistance is 3.15 kOhm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.22, Page No 120"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vo=5.0\n",
- "Vf=0.7\n",
- "Iz=5.0\n",
- "Il=1.0\n",
- "E=20.0\n",
- "\n",
- "#Calculations\n",
- "Vz=Vo-Vf\n",
- "R1=(E-Vo)/(Il+Iz)\n",
- "\n",
- "#Results\n",
- "print(\"zener diode resistance si %.2f ohm \" %R1)\n",
- "#Answer in the book is wrong"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "zener diode resistance si 2.50 ohm \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.23, Page No 122"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=10.0\n",
- "R1=56.0*10**3\n",
- "f=1000.0\n",
- "C1=1.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "Vo=2*E\n",
- "Ic=Vo/R1\n",
- "t=1/(2*f)\n",
- "Vc=(Ic*t)/C1\n",
- "\n",
- "#Results\n",
- "print(\" tilt output voltage is %3.2fV \" %(Vc*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " tilt output voltage is 178.57V \n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.24, Page No 124"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=500.0\n",
- "Rs=600.0\n",
- "E=8.0\n",
- "\n",
- "#Calculations\n",
- "t=1.0/(2*f)\n",
- "PW=t\n",
- "C1=PW/Rs\n",
- "Vo=2.0*E\n",
- "Vc=(1*Vo)/100#1% of the Vo\n",
- "Ic=(Vc*C1)/t\n",
- "R1=(2*E)/(Ic*1000)\n",
- "\n",
- "#Results\n",
- "print(\"suitable value of R1 is %.2f ohm \" %R1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "suitable value of R1 is 60.00 ohm \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.25, Page No 125"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=0.7\n",
- "E=6.0\n",
- "Vb1=3.0\n",
- "\n",
- "#Calculations\n",
- "Vc=Vb1-Vf-(-E)\n",
- "Vo=Vb1-Vf\n",
- "print(\"when input is -E\")\n",
- "Vo=E+Vc\n",
- "Vo=Vb1+Vf\n",
- "print(\"Capicitor voltage is %.2f ohm \" %Vc)\n",
- "print(\"when input is +E\")\n",
- "Vo=E+(Vc)\n",
- "\n",
- "#Results\n",
- "print(\"Capicitor voltage is %.2f ohm \" %Vo)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when input is -E\n",
- "Capicitor voltage is 8.30 ohm \n",
- "when input is +E\n",
- "Capicitor voltage is 14.30 ohm \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.26, Page No 130"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=12.0\n",
- "Vf=0.7\n",
- "Rl=47*10**3\n",
- "f=5000.0\n",
- "\n",
- "#Calculations\n",
- "Vo=2*(E-Vf)\n",
- "Il=Vo/Rl\n",
- "print(\" capacitor discharge time\")\n",
- "t=1.0/(2*f)\n",
- "print(\" for 1% ripple allow .5% due to discharge of C2 %.5%due to discharge of C1\")\n",
- "Vc=(.5*Vo)/100\n",
- "C2=((Il*t)/Vc)*10**6\n",
- "print(\" value of capacitor C2 is %3.2fuF \" %C2)\n",
- "C1=2*C2\n",
- "\n",
- "#Results\n",
- "print(\"value of capacitor C1 is %3.2fuF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " capacitor discharge time\n",
- " for 1% ripple allow .5% due to discharge of C2 %.5%due to discharge of C1\n",
- " value of capacitor C2 is 0.43uF \n",
- "value of capacitor C1 is 0.85uF \n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.27, Page No 133"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=5.0\n",
- "Vf=.7\n",
- "R1=3.3*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"A)\")\n",
- "Ir1=(Vcc-Vf)/R1\n",
- "print(\"diode forward current when all input are low is %3.4fA \" %Ir1)\n",
- "print(\"for each diode\")\n",
- "If=Ir1/3\n",
- "print(\"B)\")\n",
- "If2=Ir1/2\n",
- "If3=If2\n",
- "print(\" forward current when input A is high is %3.5fA \" %If3)\n",
- "print(\"C)\")\n",
- "If3=Ir1\n",
- "\n",
- "#Results\n",
- "print(\" forward current when input A and B are high and C is low %3.2fA \" %(If3*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "A)\n",
- "diode forward current when all input are low is 0.0013A \n",
- "for each diode\n",
- "B)\n",
- " forward current when input A is high is 0.00065A \n",
- "C)\n",
- " forward current when input A and B are high and C is low 1.30A \n"
- ]
- }
- ],
- "prompt_number": 27
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter3_1.ipynb b/Electronic_Devices_and_Circuits/Chapter3_1.ipynb deleted file mode 100755 index 8f8a6a3b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter3_1.ipynb +++ /dev/null @@ -1,1201 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 03 : Diode applications"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.1, Page No 73"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=.7\n",
- "Rl=500.0\n",
- "Vi=22.0\n",
- "Vpi=1.414*Vi\n",
- "\n",
- "#Calculations\n",
- "Vpo=Vpi-Vf\n",
- "print(\" peak vouput voltage is %3.2fV \" %Vpo)\n",
- "Ip=Vpo/Rl\n",
- "\n",
- "#Results\n",
- "print(\"peak load current is %3.4fA \" %Ip)\n",
- "PIV=Vpi\n",
- "print(\"diode paek reverse voltage %3.2fV \" %PIV)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " peak vouput voltage is 30.41V \n",
- "peak load current is 0.0608A \n",
- "diode paek reverse voltage 31.11V \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.2, Page No 79"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vi=30.0\n",
- "Rl=300.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "Vpi=1.414*Vi\n",
- "Vpo=Vpi-2*Vf\n",
- "print(\" peak output voltage %.3f V \" %Vpo)\n",
- "Ip=Vpo/Rl\n",
- "\n",
- "#Results\n",
- "print(\" current bridge is %.1f mA \" %(Ip*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " peak output voltage 41.020 V \n",
- " current bridge is 136.7 mA \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.3 Page No 83"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "C1=680.0*10**-6\n",
- "Eo=28.0\n",
- "Rl=200.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Il=Eo/Rl\n",
- "T=1/f\n",
- "t1=T\n",
- "Vr=(Il*t1)/C1\n",
- "\n",
- "#Results\n",
- "print(\"peak to peak ripple voltage is %.2f V \" %Vr)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "peak to peak ripple voltage is 3.43 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.4, Page No 84"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "Rl=500.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Vr=(10*Eo)/100#10% of Eo\n",
- "Il=Eo/Rl\n",
- "T=1/f\n",
- "t1=T\n",
- "C1=((Il*t1)/Vr)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"Reservior capacitance is %.2f uF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Reservior capacitance is 333.33 uF \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.5 Page No 85"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "f=60.0\n",
- "Rl=500.0\n",
- "Il=Eo/Rl\n",
- "\n",
- "#Calculations\n",
- "Vr=(10.0*Eo)/100\n",
- "print(\"10percent of Eo is %.2f V \" %Vr)\n",
- "Eomin=Eo-0.5*Vr\n",
- "Eomax=Eo+0.5*Vr\n",
- "Q1=math.asin(Eomin/Eomax)\n",
- "Q1=65\n",
- "Q2=90-Q1\n",
- "T=1/f\n",
- "t2=(Q2*T)/360\n",
- "print(\" charging time is %.2fs \" %t2)\n",
- "t1=T-t2\n",
- "print(\"discharging time is %.2fs \" %t1)\n",
- "C1=((Il*t1)/Vr)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"reservior capacitance is %.2f uF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "10percent of Eo is 2.00 V \n",
- " charging time is 0.00s \n",
- "discharging time is 0.02s \n",
- "reservior capacitance is 310.19 uF \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.6 Page No 88"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "t1=1.16*10**-3\n",
- "t2=15.54*10**-3\n",
- "Vp=Eo+Vf\n",
- "Vr=2*Vp\n",
- "Il=40*10**-4\n",
- "Ifrm=(Il*(t1+t2))/t2\n",
- "Ifsm=30.0\n",
- "Rs=Vp/Ifsm\n",
- "\n",
- "#Results\n",
- "print(\" surge limiting resistance is %3.2fohm \" %Rs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " surge limiting resistance is 0.72ohm \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.7, Page No 89 "
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=.7\n",
- "Eo=21.0\n",
- "\n",
- "#Calculations\n",
- "Il=40*10**-3\n",
- "Vp=115.0\n",
- "Vs=.707*(Vf+Eo)\n",
- "print(\" Vrms voltage is %3.3fV \" %Vs)\n",
- "Is=3.6*Il\n",
- "print(\" rms current is %.2f mA \" %(Is*1000))\n",
- "Ip=(Vs*Is)/Vp\n",
- "\n",
- "#Results\n",
- "print(\"primary current is %.2f mA \" %(Ip*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Vrms voltage is 15.342V \n",
- " rms current is 144.00 mA \n",
- "primary current is 19.21 mA \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.8 Page No 92"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Vr=2.0\n",
- "T=16.7*10**-3\n",
- "t2=1.16*10**-3\n",
- "\n",
- "#Calculations\n",
- "Il=40.0*10**-3#from example 3.5\n",
- "t1=(T/2.0)-t2\n",
- "C1=(Il*t1)/Vr\n",
- "\n",
- "#Results\n",
- "print(\" resrvior capacitor is %.2f mF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " resrvior capacitor is 143.80 mF \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.9 Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vr=2.0\n",
- "T=16.7*10**-3\n",
- "Il=40.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "t1=T/2\n",
- "C1=(Il*t1)/Vr\n",
- "\n",
- "#Results\n",
- "print(\" reservior capacitance is %.1fF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " reservior capacitance is 167.0F \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.10 Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "Il=40.0*10**-3\n",
- "t1=7.19*10**-3\n",
- "t2=1.16*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vp=Eo+(2*Vf)\n",
- "Vr=Vp\n",
- "If=Il/2\n",
- "Ifrm=Il*(t1+t2)/t2\n",
- "Ifsm=30\n",
- "Rs=Vp/Ifsm\n",
- "\n",
- "#Results\n",
- "print(\"surge limiting resistance is %.3fohm \" %Rs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "surge limiting resistance is 0.747ohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.11, Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "Il=40*10**-3\n",
- "Vp=115.0\n",
- "\n",
- "#Calculations\n",
- "Vs=0.707*(Eo+2*Vf)\n",
- "Is=1.6*Il\n",
- "Ip=(Vs*Is)/Vp\n",
- "\n",
- "#Results\n",
- "print(\" supply current is %.1f mA \" %(Ip*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " supply current is 8.8 mA \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.12, Page No 97"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "Il=40.0*10**-3\n",
- "R1=22.0\n",
- "Vr=2.0\n",
- "C1=150*10**-6\n",
- "C2=C1\n",
- "fr=120\n",
- "\n",
- "#Calculations\n",
- "Vo=Eo-Il*R1\n",
- "vi=Vr/3.14\n",
- "Xc2=1/(2*3.14*fr*C2)\n",
- "vo=(vi*Xc2)/math.sqrt((R1**2) + (Xc2**2))\n",
- "print(\" dc output voltage is %.3fV \" %vo)\n",
- "Vpp=2*vo\n",
- "\n",
- "#Results\n",
- "print(\" peak to peak voltage is %.1fV \" %(Vpp*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " dc output voltage is 0.238V \n",
- " peak to peak voltage is 475.3V \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.13, Page No 98"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "C1=150*10**-6\n",
- "C2=C1\n",
- "vi=4.0\n",
- "vo=1.0\n",
- "f=120.0\n",
- "\n",
- "#Calculations\n",
- "Xc2=8.84 #FROM EXAMPLE 3.12\n",
- "Xl=Xc2*((vi/vo)+1)\n",
- "L1=Xl/(2*3.14*f)\n",
- "\n",
- "#Results\n",
- "print(\" suitable value of L1 is %.3fH \" %(L1*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable value of L1 is 58.652H \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.14, Page No 101"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Edc=20.0\n",
- "vo=0.24\n",
- "Vo=20.0\n",
- "Il=40*10**-3\n",
- "fr=120.0\n",
- "\n",
- "#Calculations\n",
- "Eomax=(3.14*Edc)/2\n",
- "Epeak=(4*Eomax)/(3*3.14)\n",
- "vi=Epeak\n",
- "Rl=Vo/Il\n",
- "Xlc=(2*Rl)/3\n",
- "Lc=Xlc/(2*3.14*fr)\n",
- "L=1.25*Lc\n",
- "Xl=2*3.14*fr*L\n",
- "Xc=Xl/((vi/vo)+1)\n",
- "C1=1/(2*3.14*fr*Xc)\n",
- "\n",
- "#Results\n",
- "print(\"The value of c1 = %.2f mF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of c1 = 180.11 mF \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.15, Page No 105"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "E0=20-19.7 #load effect\n",
- "\n",
- "#Calculations\n",
- "loadregulation =(E0*100)/Eo#percentage\n",
- "sourceeffect=20.2-20\n",
- "lineregulation =(sourceeffect*100)/Eo\n",
- "\n",
- "#Results\n",
- "print(\"Line regulation = %.1f percent \" %lineregulation)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Line regulation = 1.0 percent \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.16, Page No 108"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=9.1\n",
- "Izt=20*10**-3\n",
- "Es=30.0\n",
- "\n",
- "#Calculations\n",
- "R1=(Es-Vz)/Izt\n",
- "Pr1=(Izt**2)*R1\n",
- "Es=27\n",
- "Iz=(Es-Vz)/R1\n",
- "\n",
- "#Results\n",
- "print(\"The circuit current is %.2f mA \" %(Iz*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The circuit current is 17.13 mA \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.17, Page No 110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=6.2\n",
- "Pd=400.0*10**-3\n",
- "Es=16.0\n",
- "\n",
- "#Calculations\n",
- "Izm=Pd/Vz\n",
- "R1=(Es-Vz)/Izm\n",
- "Pr1=(Izm**2)*R1\n",
- "Izmin=5.0*10**-3\n",
- "Izmax=Izm-Izmin\n",
- "\n",
- "#Results\n",
- "print(\"maximum current is %3.2f mA \" %(Izmax*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum current is 59.52 mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.18, Page No 112"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Zz=7.0\n",
- "Es=16.0\n",
- "Vo=6.2\n",
- "Il=59.5*10**-3\n",
- "\n",
- "#Calculations\n",
- "es=(10*Es)/100.0 #10% os Es\n",
- "Rl=Vo/Il\n",
- "print(\"es*Zz||Rl/R1+Zz||Rl\")\n",
- "V0=es*((Zz*Rl)/(Zz+Rl))/(R1+((Zz*Rl)/(Zz+Rl)))\n",
- "lineregulation=(V0*100)/Vo\n",
- "print(\"line regulation voltage is %3.3fpercentage \" %lineregulation)\n",
- "V0=Il*((Zz*R1)/(Zz+R1))\n",
- "loadregulation=(V0*100)/Vo\n",
- "print(\"loadregulation voltage is %3.3fpercentage \" %loadregulation)\n",
- "Rr=((Zz*Rl)/(Zz+Rl))/(R1+(Zz*Rl)/(Zz+Rl))\n",
- "\n",
- "#Results\n",
- "print(\"ripple rejection is %3.2f X 10^-2 \" %(Rr*10**2))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "es*Zz||Rl/R1+Zz||Rl\n",
- "line regulation voltage is 1.068percentage \n",
- "loadregulation voltage is 6.422percentage \n",
- "ripple rejection is 4.14 X 10^-2 \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.19, Page No 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "E=9.0\n",
- "Vf=.7\n",
- "\n",
- "#Calculations\n",
- "If=1.0*10**-3\n",
- "Vo=E-Vf\n",
- "R1=Vo/If\n",
- "Vr=E\n",
- "\n",
- "#Results\n",
- "print(\"diode forward voltage is %3.2fohm \" %Vr)\n",
- "print(\"diode forward current is %3.1fA \" %(If*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "diode forward voltage is 9.00ohm \n",
- "diode forward current is 1.0A \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.20, Page No 117"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=5.0\n",
- "Vo=4.5\n",
- "Il=2.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=(E-Vo)/Il\n",
- "print(\" suitable resistance is %dohm \" %R1)\n",
- "Vr=E\n",
- "print(\"when diode is forward baised\")\n",
- "If=(E-Vf)/R1\n",
- "\n",
- "#Results\n",
- "print(\" diode forward current is %3.2fA \" %(If*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable resistance is 250ohm \n",
- "when diode is forward baised\n",
- " diode forward current is 17.20A \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.21, Page No 119"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vo=2.7\n",
- "Vf=.7\n",
- "E=9.0\n",
- "If=1*10**-3\n",
- "\n",
- "#Calculations\n",
- "Il=If\n",
- "Vb=Vo-Vf\n",
- "R1=(E-Vo)/(Il+If)\n",
- "\n",
- "#Results\n",
- "print(\"resistance is %.2f kOhm \" %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistance is 3.15 kOhm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.22, Page No 120"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vo=5.0\n",
- "Vf=0.7\n",
- "Iz=5.0\n",
- "Il=1.0\n",
- "E=20.0\n",
- "\n",
- "#Calculations\n",
- "Vz=Vo-Vf\n",
- "R1=(E-Vo)/(Il+Iz)\n",
- "\n",
- "#Results\n",
- "print(\"zener diode resistance si %.2f ohm \" %R1)\n",
- "#Answer in the book is wrong"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "zener diode resistance si 2.50 ohm \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.23, Page No 122"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=10.0\n",
- "R1=56.0*10**3\n",
- "f=1000.0\n",
- "C1=1.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "Vo=2*E\n",
- "Ic=Vo/R1\n",
- "t=1/(2*f)\n",
- "Vc=(Ic*t)/C1\n",
- "\n",
- "#Results\n",
- "print(\" tilt output voltage is %3.2fV \" %(Vc*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " tilt output voltage is 178.57V \n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.24, Page No 124"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=500.0\n",
- "Rs=600.0\n",
- "E=8.0\n",
- "\n",
- "#Calculations\n",
- "t=1.0/(2*f)\n",
- "PW=t\n",
- "C1=PW/Rs\n",
- "Vo=2.0*E\n",
- "Vc=(1*Vo)/100#1% of the Vo\n",
- "Ic=(Vc*C1)/t\n",
- "R1=(2*E)/(Ic*1000)\n",
- "\n",
- "#Results\n",
- "print(\"suitable value of R1 is %.2f ohm \" %R1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "suitable value of R1 is 60.00 ohm \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.25, Page No 125"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=0.7\n",
- "E=6.0\n",
- "Vb1=3.0\n",
- "\n",
- "#Calculations\n",
- "Vc=Vb1-Vf-(-E)\n",
- "Vo=Vb1-Vf\n",
- "print(\"when input is -E\")\n",
- "Vo=E+Vc\n",
- "Vo=Vb1+Vf\n",
- "print(\"Capicitor voltage is %.2f ohm \" %Vc)\n",
- "print(\"when input is +E\")\n",
- "Vo=E+(Vc)\n",
- "\n",
- "#Results\n",
- "print(\"Capicitor voltage is %.2f ohm \" %Vo)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when input is -E\n",
- "Capicitor voltage is 8.30 ohm \n",
- "when input is +E\n",
- "Capicitor voltage is 14.30 ohm \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.26, Page No 130"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=12.0\n",
- "Vf=0.7\n",
- "Rl=47*10**3\n",
- "f=5000.0\n",
- "\n",
- "#Calculations\n",
- "Vo=2*(E-Vf)\n",
- "Il=Vo/Rl\n",
- "print(\" capacitor discharge time\")\n",
- "t=1.0/(2*f)\n",
- "print(\" for 1% ripple allow .5% due to discharge of C2 %.5%due to discharge of C1\")\n",
- "Vc=(.5*Vo)/100\n",
- "C2=((Il*t)/Vc)*10**6\n",
- "print(\" value of capacitor C2 is %3.2fuF \" %C2)\n",
- "C1=2*C2\n",
- "\n",
- "#Results\n",
- "print(\"value of capacitor C1 is %3.2fuF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " capacitor discharge time\n",
- " for 1% ripple allow .5% due to discharge of C2 %.5%due to discharge of C1\n",
- " value of capacitor C2 is 0.43uF \n",
- "value of capacitor C1 is 0.85uF \n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.27, Page No 133"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=5.0\n",
- "Vf=.7\n",
- "R1=3.3*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"A)\")\n",
- "Ir1=(Vcc-Vf)/R1\n",
- "print(\"diode forward current when all input are low is %3.4fA \" %Ir1)\n",
- "print(\"for each diode\")\n",
- "If=Ir1/3\n",
- "print(\"B)\")\n",
- "If2=Ir1/2\n",
- "If3=If2\n",
- "print(\" forward current when input A is high is %3.5fA \" %If3)\n",
- "print(\"C)\")\n",
- "If3=Ir1\n",
- "\n",
- "#Results\n",
- "print(\" forward current when input A and B are high and C is low %3.2fA \" %(If3*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "A)\n",
- "diode forward current when all input are low is 0.0013A \n",
- "for each diode\n",
- "B)\n",
- " forward current when input A is high is 0.00065A \n",
- "C)\n",
- " forward current when input A and B are high and C is low 1.30A \n"
- ]
- }
- ],
- "prompt_number": 27
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter3_2.ipynb b/Electronic_Devices_and_Circuits/Chapter3_2.ipynb deleted file mode 100755 index 8f8a6a3b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter3_2.ipynb +++ /dev/null @@ -1,1201 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 03 : Diode applications"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.1, Page No 73"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=.7\n",
- "Rl=500.0\n",
- "Vi=22.0\n",
- "Vpi=1.414*Vi\n",
- "\n",
- "#Calculations\n",
- "Vpo=Vpi-Vf\n",
- "print(\" peak vouput voltage is %3.2fV \" %Vpo)\n",
- "Ip=Vpo/Rl\n",
- "\n",
- "#Results\n",
- "print(\"peak load current is %3.4fA \" %Ip)\n",
- "PIV=Vpi\n",
- "print(\"diode paek reverse voltage %3.2fV \" %PIV)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " peak vouput voltage is 30.41V \n",
- "peak load current is 0.0608A \n",
- "diode paek reverse voltage 31.11V \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.2, Page No 79"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vi=30.0\n",
- "Rl=300.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "Vpi=1.414*Vi\n",
- "Vpo=Vpi-2*Vf\n",
- "print(\" peak output voltage %.3f V \" %Vpo)\n",
- "Ip=Vpo/Rl\n",
- "\n",
- "#Results\n",
- "print(\" current bridge is %.1f mA \" %(Ip*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " peak output voltage 41.020 V \n",
- " current bridge is 136.7 mA \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.3 Page No 83"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "C1=680.0*10**-6\n",
- "Eo=28.0\n",
- "Rl=200.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Il=Eo/Rl\n",
- "T=1/f\n",
- "t1=T\n",
- "Vr=(Il*t1)/C1\n",
- "\n",
- "#Results\n",
- "print(\"peak to peak ripple voltage is %.2f V \" %Vr)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "peak to peak ripple voltage is 3.43 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.4, Page No 84"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "Rl=500.0\n",
- "f=60.0\n",
- "\n",
- "#Calculations\n",
- "Vr=(10*Eo)/100#10% of Eo\n",
- "Il=Eo/Rl\n",
- "T=1/f\n",
- "t1=T\n",
- "C1=((Il*t1)/Vr)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"Reservior capacitance is %.2f uF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Reservior capacitance is 333.33 uF \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.5 Page No 85"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "f=60.0\n",
- "Rl=500.0\n",
- "Il=Eo/Rl\n",
- "\n",
- "#Calculations\n",
- "Vr=(10.0*Eo)/100\n",
- "print(\"10percent of Eo is %.2f V \" %Vr)\n",
- "Eomin=Eo-0.5*Vr\n",
- "Eomax=Eo+0.5*Vr\n",
- "Q1=math.asin(Eomin/Eomax)\n",
- "Q1=65\n",
- "Q2=90-Q1\n",
- "T=1/f\n",
- "t2=(Q2*T)/360\n",
- "print(\" charging time is %.2fs \" %t2)\n",
- "t1=T-t2\n",
- "print(\"discharging time is %.2fs \" %t1)\n",
- "C1=((Il*t1)/Vr)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"reservior capacitance is %.2f uF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "10percent of Eo is 2.00 V \n",
- " charging time is 0.00s \n",
- "discharging time is 0.02s \n",
- "reservior capacitance is 310.19 uF \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.6 Page No 88"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "\n",
- "#Calculations\n",
- "t1=1.16*10**-3\n",
- "t2=15.54*10**-3\n",
- "Vp=Eo+Vf\n",
- "Vr=2*Vp\n",
- "Il=40*10**-4\n",
- "Ifrm=(Il*(t1+t2))/t2\n",
- "Ifsm=30.0\n",
- "Rs=Vp/Ifsm\n",
- "\n",
- "#Results\n",
- "print(\" surge limiting resistance is %3.2fohm \" %Rs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " surge limiting resistance is 0.72ohm \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.7, Page No 89 "
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=.7\n",
- "Eo=21.0\n",
- "\n",
- "#Calculations\n",
- "Il=40*10**-3\n",
- "Vp=115.0\n",
- "Vs=.707*(Vf+Eo)\n",
- "print(\" Vrms voltage is %3.3fV \" %Vs)\n",
- "Is=3.6*Il\n",
- "print(\" rms current is %.2f mA \" %(Is*1000))\n",
- "Ip=(Vs*Is)/Vp\n",
- "\n",
- "#Results\n",
- "print(\"primary current is %.2f mA \" %(Ip*1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Vrms voltage is 15.342V \n",
- " rms current is 144.00 mA \n",
- "primary current is 19.21 mA \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.8 Page No 92"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Vr=2.0\n",
- "T=16.7*10**-3\n",
- "t2=1.16*10**-3\n",
- "\n",
- "#Calculations\n",
- "Il=40.0*10**-3#from example 3.5\n",
- "t1=(T/2.0)-t2\n",
- "C1=(Il*t1)/Vr\n",
- "\n",
- "#Results\n",
- "print(\" resrvior capacitor is %.2f mF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " resrvior capacitor is 143.80 mF \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.9 Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vr=2.0\n",
- "T=16.7*10**-3\n",
- "Il=40.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "t1=T/2\n",
- "C1=(Il*t1)/Vr\n",
- "\n",
- "#Results\n",
- "print(\" reservior capacitance is %.1fF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " reservior capacitance is 167.0F \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.10 Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "Il=40.0*10**-3\n",
- "t1=7.19*10**-3\n",
- "t2=1.16*10**-3\n",
- "\n",
- "#Calculations\n",
- "Vp=Eo+(2*Vf)\n",
- "Vr=Vp\n",
- "If=Il/2\n",
- "Ifrm=Il*(t1+t2)/t2\n",
- "Ifsm=30\n",
- "Rs=Vp/Ifsm\n",
- "\n",
- "#Results\n",
- "print(\"surge limiting resistance is %.3fohm \" %Rs)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "surge limiting resistance is 0.747ohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.11, Page No 93"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Eo=21.0\n",
- "Vf=0.7\n",
- "Il=40*10**-3\n",
- "Vp=115.0\n",
- "\n",
- "#Calculations\n",
- "Vs=0.707*(Eo+2*Vf)\n",
- "Is=1.6*Il\n",
- "Ip=(Vs*Is)/Vp\n",
- "\n",
- "#Results\n",
- "print(\" supply current is %.1f mA \" %(Ip*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " supply current is 8.8 mA \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.12, Page No 97"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "Il=40.0*10**-3\n",
- "R1=22.0\n",
- "Vr=2.0\n",
- "C1=150*10**-6\n",
- "C2=C1\n",
- "fr=120\n",
- "\n",
- "#Calculations\n",
- "Vo=Eo-Il*R1\n",
- "vi=Vr/3.14\n",
- "Xc2=1/(2*3.14*fr*C2)\n",
- "vo=(vi*Xc2)/math.sqrt((R1**2) + (Xc2**2))\n",
- "print(\" dc output voltage is %.3fV \" %vo)\n",
- "Vpp=2*vo\n",
- "\n",
- "#Results\n",
- "print(\" peak to peak voltage is %.1fV \" %(Vpp*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " dc output voltage is 0.238V \n",
- " peak to peak voltage is 475.3V \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.13, Page No 98"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "C1=150*10**-6\n",
- "C2=C1\n",
- "vi=4.0\n",
- "vo=1.0\n",
- "f=120.0\n",
- "\n",
- "#Calculations\n",
- "Xc2=8.84 #FROM EXAMPLE 3.12\n",
- "Xl=Xc2*((vi/vo)+1)\n",
- "L1=Xl/(2*3.14*f)\n",
- "\n",
- "#Results\n",
- "print(\" suitable value of L1 is %.3fH \" %(L1*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable value of L1 is 58.652H \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.14, Page No 101"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Edc=20.0\n",
- "vo=0.24\n",
- "Vo=20.0\n",
- "Il=40*10**-3\n",
- "fr=120.0\n",
- "\n",
- "#Calculations\n",
- "Eomax=(3.14*Edc)/2\n",
- "Epeak=(4*Eomax)/(3*3.14)\n",
- "vi=Epeak\n",
- "Rl=Vo/Il\n",
- "Xlc=(2*Rl)/3\n",
- "Lc=Xlc/(2*3.14*fr)\n",
- "L=1.25*Lc\n",
- "Xl=2*3.14*fr*L\n",
- "Xc=Xl/((vi/vo)+1)\n",
- "C1=1/(2*3.14*fr*Xc)\n",
- "\n",
- "#Results\n",
- "print(\"The value of c1 = %.2f mF \" %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of c1 = 180.11 mF \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.15, Page No 105"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Eo=20.0\n",
- "E0=20-19.7 #load effect\n",
- "\n",
- "#Calculations\n",
- "loadregulation =(E0*100)/Eo#percentage\n",
- "sourceeffect=20.2-20\n",
- "lineregulation =(sourceeffect*100)/Eo\n",
- "\n",
- "#Results\n",
- "print(\"Line regulation = %.1f percent \" %lineregulation)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Line regulation = 1.0 percent \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.16, Page No 108"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=9.1\n",
- "Izt=20*10**-3\n",
- "Es=30.0\n",
- "\n",
- "#Calculations\n",
- "R1=(Es-Vz)/Izt\n",
- "Pr1=(Izt**2)*R1\n",
- "Es=27\n",
- "Iz=(Es-Vz)/R1\n",
- "\n",
- "#Results\n",
- "print(\"The circuit current is %.2f mA \" %(Iz*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The circuit current is 17.13 mA \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.17, Page No 110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vz=6.2\n",
- "Pd=400.0*10**-3\n",
- "Es=16.0\n",
- "\n",
- "#Calculations\n",
- "Izm=Pd/Vz\n",
- "R1=(Es-Vz)/Izm\n",
- "Pr1=(Izm**2)*R1\n",
- "Izmin=5.0*10**-3\n",
- "Izmax=Izm-Izmin\n",
- "\n",
- "#Results\n",
- "print(\"maximum current is %3.2f mA \" %(Izmax*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum current is 59.52 mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.18, Page No 112"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Zz=7.0\n",
- "Es=16.0\n",
- "Vo=6.2\n",
- "Il=59.5*10**-3\n",
- "\n",
- "#Calculations\n",
- "es=(10*Es)/100.0 #10% os Es\n",
- "Rl=Vo/Il\n",
- "print(\"es*Zz||Rl/R1+Zz||Rl\")\n",
- "V0=es*((Zz*Rl)/(Zz+Rl))/(R1+((Zz*Rl)/(Zz+Rl)))\n",
- "lineregulation=(V0*100)/Vo\n",
- "print(\"line regulation voltage is %3.3fpercentage \" %lineregulation)\n",
- "V0=Il*((Zz*R1)/(Zz+R1))\n",
- "loadregulation=(V0*100)/Vo\n",
- "print(\"loadregulation voltage is %3.3fpercentage \" %loadregulation)\n",
- "Rr=((Zz*Rl)/(Zz+Rl))/(R1+(Zz*Rl)/(Zz+Rl))\n",
- "\n",
- "#Results\n",
- "print(\"ripple rejection is %3.2f X 10^-2 \" %(Rr*10**2))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "es*Zz||Rl/R1+Zz||Rl\n",
- "line regulation voltage is 1.068percentage \n",
- "loadregulation voltage is 6.422percentage \n",
- "ripple rejection is 4.14 X 10^-2 \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.19, Page No 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "E=9.0\n",
- "Vf=.7\n",
- "\n",
- "#Calculations\n",
- "If=1.0*10**-3\n",
- "Vo=E-Vf\n",
- "R1=Vo/If\n",
- "Vr=E\n",
- "\n",
- "#Results\n",
- "print(\"diode forward voltage is %3.2fohm \" %Vr)\n",
- "print(\"diode forward current is %3.1fA \" %(If*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "diode forward voltage is 9.00ohm \n",
- "diode forward current is 1.0A \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.20, Page No 117"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=5.0\n",
- "Vo=4.5\n",
- "Il=2.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "R1=(E-Vo)/Il\n",
- "print(\" suitable resistance is %dohm \" %R1)\n",
- "Vr=E\n",
- "print(\"when diode is forward baised\")\n",
- "If=(E-Vf)/R1\n",
- "\n",
- "#Results\n",
- "print(\" diode forward current is %3.2fA \" %(If*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable resistance is 250ohm \n",
- "when diode is forward baised\n",
- " diode forward current is 17.20A \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.21, Page No 119"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vo=2.7\n",
- "Vf=.7\n",
- "E=9.0\n",
- "If=1*10**-3\n",
- "\n",
- "#Calculations\n",
- "Il=If\n",
- "Vb=Vo-Vf\n",
- "R1=(E-Vo)/(Il+If)\n",
- "\n",
- "#Results\n",
- "print(\"resistance is %.2f kOhm \" %(R1/10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistance is 3.15 kOhm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.22, Page No 120"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vo=5.0\n",
- "Vf=0.7\n",
- "Iz=5.0\n",
- "Il=1.0\n",
- "E=20.0\n",
- "\n",
- "#Calculations\n",
- "Vz=Vo-Vf\n",
- "R1=(E-Vo)/(Il+Iz)\n",
- "\n",
- "#Results\n",
- "print(\"zener diode resistance si %.2f ohm \" %R1)\n",
- "#Answer in the book is wrong"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "zener diode resistance si 2.50 ohm \n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.23, Page No 122"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=10.0\n",
- "R1=56.0*10**3\n",
- "f=1000.0\n",
- "C1=1.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "Vo=2*E\n",
- "Ic=Vo/R1\n",
- "t=1/(2*f)\n",
- "Vc=(Ic*t)/C1\n",
- "\n",
- "#Results\n",
- "print(\" tilt output voltage is %3.2fV \" %(Vc*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " tilt output voltage is 178.57V \n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.24, Page No 124"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "f=500.0\n",
- "Rs=600.0\n",
- "E=8.0\n",
- "\n",
- "#Calculations\n",
- "t=1.0/(2*f)\n",
- "PW=t\n",
- "C1=PW/Rs\n",
- "Vo=2.0*E\n",
- "Vc=(1*Vo)/100#1% of the Vo\n",
- "Ic=(Vc*C1)/t\n",
- "R1=(2*E)/(Ic*1000)\n",
- "\n",
- "#Results\n",
- "print(\"suitable value of R1 is %.2f ohm \" %R1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "suitable value of R1 is 60.00 ohm \n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.25, Page No 125"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vf=0.7\n",
- "E=6.0\n",
- "Vb1=3.0\n",
- "\n",
- "#Calculations\n",
- "Vc=Vb1-Vf-(-E)\n",
- "Vo=Vb1-Vf\n",
- "print(\"when input is -E\")\n",
- "Vo=E+Vc\n",
- "Vo=Vb1+Vf\n",
- "print(\"Capicitor voltage is %.2f ohm \" %Vc)\n",
- "print(\"when input is +E\")\n",
- "Vo=E+(Vc)\n",
- "\n",
- "#Results\n",
- "print(\"Capicitor voltage is %.2f ohm \" %Vo)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when input is -E\n",
- "Capicitor voltage is 8.30 ohm \n",
- "when input is +E\n",
- "Capicitor voltage is 14.30 ohm \n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.26, Page No 130"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "E=12.0\n",
- "Vf=0.7\n",
- "Rl=47*10**3\n",
- "f=5000.0\n",
- "\n",
- "#Calculations\n",
- "Vo=2*(E-Vf)\n",
- "Il=Vo/Rl\n",
- "print(\" capacitor discharge time\")\n",
- "t=1.0/(2*f)\n",
- "print(\" for 1% ripple allow .5% due to discharge of C2 %.5%due to discharge of C1\")\n",
- "Vc=(.5*Vo)/100\n",
- "C2=((Il*t)/Vc)*10**6\n",
- "print(\" value of capacitor C2 is %3.2fuF \" %C2)\n",
- "C1=2*C2\n",
- "\n",
- "#Results\n",
- "print(\"value of capacitor C1 is %3.2fuF \" %C1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " capacitor discharge time\n",
- " for 1% ripple allow .5% due to discharge of C2 %.5%due to discharge of C1\n",
- " value of capacitor C2 is 0.43uF \n",
- "value of capacitor C1 is 0.85uF \n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.27, Page No 133"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=5.0\n",
- "Vf=.7\n",
- "R1=3.3*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\"A)\")\n",
- "Ir1=(Vcc-Vf)/R1\n",
- "print(\"diode forward current when all input are low is %3.4fA \" %Ir1)\n",
- "print(\"for each diode\")\n",
- "If=Ir1/3\n",
- "print(\"B)\")\n",
- "If2=Ir1/2\n",
- "If3=If2\n",
- "print(\" forward current when input A is high is %3.5fA \" %If3)\n",
- "print(\"C)\")\n",
- "If3=Ir1\n",
- "\n",
- "#Results\n",
- "print(\" forward current when input A and B are high and C is low %3.2fA \" %(If3*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "A)\n",
- "diode forward current when all input are low is 0.0013A \n",
- "for each diode\n",
- "B)\n",
- " forward current when input A is high is 0.00065A \n",
- "C)\n",
- " forward current when input A and B are high and C is low 1.30A \n"
- ]
- }
- ],
- "prompt_number": 27
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter4.ipynb b/Electronic_Devices_and_Circuits/Chapter4.ipynb deleted file mode 100755 index eb199d80..00000000 --- a/Electronic_Devices_and_Circuits/Chapter4.ipynb +++ /dev/null @@ -1,237 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 04 : Bipolar junction transistors"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.1, Page No 153"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Adc=.98\n",
- "Ib=100*10**-6\n",
- "\n",
- "#Calculations\n",
- "Ic=(Adc*Ib)/(1-Adc)\n",
- "print(\"value of Ic is %3.3fA \" %Ic)\n",
- "Ie=Ic/Adc\n",
- "\n",
- "#Results\n",
- "print(\" value of Ie is %3.3fA \" %Ie)\n",
- "Bdc=Adc/(1-Adc)\n",
- "print(\"The value of Bdc = %.2f \" %Bdc) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "value of Ic is 0.005A \n",
- " value of Ie is 0.005A \n",
- "The value of Bdc = 49.00 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.2, Page No 153"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ic=1.0*10**-3\n",
- "Ib=25.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "Bdc=Ic/Ib\n",
- "Ie=Ic+Ib\n",
- "Adc=Ic/Ie\n",
- "Ic=5\n",
- "Ib=Ic/Bdc\n",
- "\n",
- "print(\"The new base current = %.2f mA\" %(Ib*10**3)) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The new base current = 125.00 mA\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.3 Page No 157"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Bdc=80.0\n",
- "Bac=Bdc\n",
- "Vcc=18.0\n",
- "R1=10.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ib=15.0*10**-6#for Vb=.7\n",
- "Ic=Bdc*Ib\n",
- "Vc=Vcc-(Ic*R1)\n",
- "\n",
- "#Results\n",
- "print(\"dc collector voltage is %dV \" %Vc)\n",
- "print(\" when vi=50mV\")\n",
- "Ib=3.0*10**-6\n",
- "Vi=50.0*10**-3\n",
- "Ic=Bdc*Ib\n",
- "Vo=Ic*R1\n",
- "Av=Vo/Vi\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "dc collector voltage is 6V \n",
- " when vi=50mV\n",
- "Current voltage is 48.0 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.4, Page No 160"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=5.0\n",
- "Vce=.2\n",
- "R2=4.7*10**3\n",
- "Vi=2\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "R1=12.0*10**3\n",
- "Ic=(Vcc-Vce)/R2\n",
- "Ib=(Vi-Vbe)/R1\n",
- "hFE=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\"Transistor current gain is %.2f V \" %(hFE))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Transistor current gain is 9.43 V \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.6 Page No 169"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=.7\n",
- "Vce=-6\n",
- "\n",
- "#Calculations\n",
- "Ib=20.0*10**-6\n",
- "Ic=2.5*10**-3#from output characteristics\n",
- "Bdc=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Bdc is %.1f V \" %Bdc)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Bdc is 125.0 V \n"
- ]
- }
- ],
- "prompt_number": 5
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter4_1.ipynb b/Electronic_Devices_and_Circuits/Chapter4_1.ipynb deleted file mode 100755 index eb199d80..00000000 --- a/Electronic_Devices_and_Circuits/Chapter4_1.ipynb +++ /dev/null @@ -1,237 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 04 : Bipolar junction transistors"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.1, Page No 153"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Adc=.98\n",
- "Ib=100*10**-6\n",
- "\n",
- "#Calculations\n",
- "Ic=(Adc*Ib)/(1-Adc)\n",
- "print(\"value of Ic is %3.3fA \" %Ic)\n",
- "Ie=Ic/Adc\n",
- "\n",
- "#Results\n",
- "print(\" value of Ie is %3.3fA \" %Ie)\n",
- "Bdc=Adc/(1-Adc)\n",
- "print(\"The value of Bdc = %.2f \" %Bdc) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "value of Ic is 0.005A \n",
- " value of Ie is 0.005A \n",
- "The value of Bdc = 49.00 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.2, Page No 153"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ic=1.0*10**-3\n",
- "Ib=25.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "Bdc=Ic/Ib\n",
- "Ie=Ic+Ib\n",
- "Adc=Ic/Ie\n",
- "Ic=5\n",
- "Ib=Ic/Bdc\n",
- "\n",
- "print(\"The new base current = %.2f mA\" %(Ib*10**3)) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The new base current = 125.00 mA\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.3 Page No 157"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Bdc=80.0\n",
- "Bac=Bdc\n",
- "Vcc=18.0\n",
- "R1=10.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ib=15.0*10**-6#for Vb=.7\n",
- "Ic=Bdc*Ib\n",
- "Vc=Vcc-(Ic*R1)\n",
- "\n",
- "#Results\n",
- "print(\"dc collector voltage is %dV \" %Vc)\n",
- "print(\" when vi=50mV\")\n",
- "Ib=3.0*10**-6\n",
- "Vi=50.0*10**-3\n",
- "Ic=Bdc*Ib\n",
- "Vo=Ic*R1\n",
- "Av=Vo/Vi\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "dc collector voltage is 6V \n",
- " when vi=50mV\n",
- "Current voltage is 48.0 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.4, Page No 160"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=5.0\n",
- "Vce=.2\n",
- "R2=4.7*10**3\n",
- "Vi=2\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "R1=12.0*10**3\n",
- "Ic=(Vcc-Vce)/R2\n",
- "Ib=(Vi-Vbe)/R1\n",
- "hFE=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\"Transistor current gain is %.2f V \" %(hFE))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Transistor current gain is 9.43 V \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.6 Page No 169"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=.7\n",
- "Vce=-6\n",
- "\n",
- "#Calculations\n",
- "Ib=20.0*10**-6\n",
- "Ic=2.5*10**-3#from output characteristics\n",
- "Bdc=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Bdc is %.1f V \" %Bdc)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Bdc is 125.0 V \n"
- ]
- }
- ],
- "prompt_number": 5
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter4_2.ipynb b/Electronic_Devices_and_Circuits/Chapter4_2.ipynb deleted file mode 100755 index eb199d80..00000000 --- a/Electronic_Devices_and_Circuits/Chapter4_2.ipynb +++ /dev/null @@ -1,237 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 04 : Bipolar junction transistors"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.1, Page No 153"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Adc=.98\n",
- "Ib=100*10**-6\n",
- "\n",
- "#Calculations\n",
- "Ic=(Adc*Ib)/(1-Adc)\n",
- "print(\"value of Ic is %3.3fA \" %Ic)\n",
- "Ie=Ic/Adc\n",
- "\n",
- "#Results\n",
- "print(\" value of Ie is %3.3fA \" %Ie)\n",
- "Bdc=Adc/(1-Adc)\n",
- "print(\"The value of Bdc = %.2f \" %Bdc) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "value of Ic is 0.005A \n",
- " value of Ie is 0.005A \n",
- "The value of Bdc = 49.00 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.2, Page No 153"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ic=1.0*10**-3\n",
- "Ib=25.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "Bdc=Ic/Ib\n",
- "Ie=Ic+Ib\n",
- "Adc=Ic/Ie\n",
- "Ic=5\n",
- "Ib=Ic/Bdc\n",
- "\n",
- "print(\"The new base current = %.2f mA\" %(Ib*10**3)) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The new base current = 125.00 mA\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.3 Page No 157"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Bdc=80.0\n",
- "Bac=Bdc\n",
- "Vcc=18.0\n",
- "R1=10.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ib=15.0*10**-6#for Vb=.7\n",
- "Ic=Bdc*Ib\n",
- "Vc=Vcc-(Ic*R1)\n",
- "\n",
- "#Results\n",
- "print(\"dc collector voltage is %dV \" %Vc)\n",
- "print(\" when vi=50mV\")\n",
- "Ib=3.0*10**-6\n",
- "Vi=50.0*10**-3\n",
- "Ic=Bdc*Ib\n",
- "Vo=Ic*R1\n",
- "Av=Vo/Vi\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Av))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "dc collector voltage is 6V \n",
- " when vi=50mV\n",
- "Current voltage is 48.0 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.4, Page No 160"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=5.0\n",
- "Vce=.2\n",
- "R2=4.7*10**3\n",
- "Vi=2\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "R1=12.0*10**3\n",
- "Ic=(Vcc-Vce)/R2\n",
- "Ib=(Vi-Vbe)/R1\n",
- "hFE=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\"Transistor current gain is %.2f V \" %(hFE))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Transistor current gain is 9.43 V \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.6 Page No 169"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=.7\n",
- "Vce=-6\n",
- "\n",
- "#Calculations\n",
- "Ib=20.0*10**-6\n",
- "Ic=2.5*10**-3#from output characteristics\n",
- "Bdc=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Bdc is %.1f V \" %Bdc)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Bdc is 125.0 V \n"
- ]
- }
- ],
- "prompt_number": 5
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter5.ipynb b/Electronic_Devices_and_Circuits/Chapter5.ipynb deleted file mode 100755 index 07d0da6b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter5.ipynb +++ /dev/null @@ -1,1022 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 05 : BJT biasing"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.1, Page No 182"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=12.0*10**3\n",
- "Vcc=20.0\n",
- "print(\" When Ic=0\")\n",
- "Ic=0\n",
- "\n",
- "#Calculations\n",
- "Vce=Vcc-Ic*Rc\n",
- "print(\" At point A Ic=0 nad Vce=20\")\n",
- "print(\"When Vce=0\")\n",
- "Vce=0\n",
- "Ic=Vcc/Rc\n",
- "\n",
- "#Results\n",
- "print(\" At point B Ic=1.7mA and Vce=0\")\n",
- "print(\"Ic is %.1f mA \" %(Ic*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " When Ic=0\n",
- " At point A Ic=0 nad Vce=20\n",
- "When Vce=0\n",
- " At point B Ic=1.7mA and Vce=0\n",
- "Ic is 1.7 mA \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.2 Page No 186"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=18.0\n",
- "Rc=2.2*10**3\n",
- "Ib=40.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"when Ic=0\")\n",
- "Ic=0\n",
- "Vce=Vcc-Ic*Rc\n",
- "print(\"At point A Ic=0 and Vce=18\")\n",
- "print(\"when Vce=0\")\n",
- "Ic=Vcc/Rc\n",
- "\n",
- "#Results\n",
- "print(\" at point B Ic=8.2mA and Vce=0\")\n",
- "print(\"Ic = %.1f mA \" %(Ic*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Ic=0\n",
- "At point A Ic=0 and Vce=18\n",
- "when Vce=0\n",
- " at point B Ic=8.2mA and Vce=0\n",
- "Ic = 8.2 mA \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.3 Page No 189"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Rb=470*10**3\n",
- "Rc=2.2*10**3\n",
- "Vcc=18.0\n",
- "hfe=100\n",
- "Vee=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vee)/Rb\n",
- "Ic=hfe*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.9 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.4, Page No 189"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hFEmin=50.0\n",
- "hFEmax=200.0\n",
- "Vcc=18.0\n",
- "Vbe=0.7\n",
- "Rb=470.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vbe)/Rb\n",
- "Ic=hFEmin*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "Ic=hFEmax*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 1.8 V \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.5 Page No 193"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rb=270*10**3\n",
- "Rc=2.2*10**3\n",
- "Vcc=18.0\n",
- "hFE=100\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vbe)/(Rb+Rc*(hFE+1))\n",
- "Ic=hFE*Ib\n",
- "Vce=Vcc-Rc*(Ic+Ib)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 10.2 V \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.7 Page No 197"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "R1=33.0*10**3\n",
- "R2=12.0*10**3\n",
- "Rc=1.2*10**3\n",
- "Re=1*10**3\n",
- "Vcc=18.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "Ve=Vb-Vbe\n",
- "Ie=(Vb-Vbe)/Re\n",
- "Ic=Ie\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.0 V \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.8, Page No 199"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=18.0\n",
- "Vbe=.7\n",
- "hfe=100.0\n",
- "R1=33*10**3\n",
- "R2=12.0*10**3\n",
- "Re=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Vt=(Vcc*R2)/(R1+R2)\n",
- "Rt=(R1*R2)/(R1+R2)\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.7 V \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.9 Page No 200"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hfe=50.0\n",
- "Vt=4.8\n",
- "Rt=8.8*10**3#from example 5.7\n",
- "Re=1.0*10**3\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 10.4 V \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.10 Page No 201"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vt=4.8\n",
- "Rt=8.8*10**3#from example 5.8\n",
- "Re=1*10**3\n",
- "Vbe=.7\n",
- "hfe=200.0\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.4 V \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.11 Page No 208"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ic=5*10**-3\n",
- "Vcc=15.0\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "Rc=(Vcc-Vce)/Ic\n",
- "Ib=Ic/hfe\n",
- "Rb=(Vcc-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rv is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rv is 286.0 kohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.12, Page No 209"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ic=5*10**-3\n",
- "Vcc=15.0\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "Ib=Ic/hfe\n",
- "Rc=(Vcc-Vce)/(Ic+Ib)\n",
- "Rb=(Vce-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 86.0 kohm \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.13, Page No 211"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ve=Vce\n",
- "Ic=5.0*10**-3\n",
- "hFE=100.0\n",
- "Vcc=15.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "Re=Ve/Ie\n",
- "Rc=(Vcc-Vce-Ve)/Ic\n",
- "I2=Ic/10\n",
- "Vb=Ve+Vbe\n",
- "R2=Vb/I2\n",
- "R1=(Vcc-Vb)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kOhm \" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 18.6 kOhm \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.14, Page No 212"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=3.0\n",
- "Ve=5.0\n",
- "Ic=1*10**-3\n",
- "Vcc=12.0\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "R4=Ve/Ie\n",
- "print(\" with Ic=1mA and R4=4.7Kohm\")\n",
- "R4=4.7*10**3\n",
- "Ve=Ic*R4\n",
- "Vc=Ve+Vce\n",
- "Vr3=Vcc-Vc\n",
- "R3=Vr3/Ic\n",
- "Vb=Ve+Vbe\n",
- "I2=Ic/10\n",
- "R2=Vb/I2\n",
- "print(\" with R2=56Kohm and Vb=5.4V\")\n",
- "R2=56*10**3\n",
- "I2=Vb/R2\n",
- "R1=(Vcc-Vb)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %.1f V \" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with Ic=1mA and R4=4.7Kohm\n",
- " with R2=56Kohm and Vb=5.4V\n",
- "The value of R1 is 68.4 V \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.15, Page No 214"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=9.0\n",
- "Ve=4.0\n",
- "Ic=4*10**-3\n",
- "Vcc=18.0\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "R4=Ve/Ie\n",
- "Vb=Ve+Vbe\n",
- "I2=Ic/10\n",
- "R2=Vb/I2\n",
- "print(\" with R2=12Kohm standard\")\n",
- "R2=12*10**3\n",
- "I2=Vb/R2\n",
- "R1=(Vce+Ve-Vb)/I2\n",
- "print(\" with R1=22kohm standard\")\n",
- "R1=22*10**3\n",
- "Vr3=Vcc-Vce-Ve\n",
- "R3=Vr3/(Ic+I2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 %.2f V \" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R2=12Kohm standard\n",
- " with R1=22kohm standard\n",
- "The value of R3 1.14 V \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.16, Page No 216"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vc=5.0\n",
- "Ic=1.0*10**-3\n",
- "hFE=70.0\n",
- "Vbe=.7\n",
- "Vee=9.0\n",
- "Vcc=Vee\n",
- "Re=8.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Ve=Vee-Vbe\n",
- "Ie=Ic\n",
- "R3=Ve/Ie\n",
- "print(\" with R3=8.2kohm standard value\")\n",
- "R3=8.2*10**3\n",
- "Ie=Ve/R3\n",
- "Vr2=Vcc-Vc\n",
- "R2=Vr2/Ic\n",
- "Ib=Ic/hFE\n",
- "Vr1=Vbe/10\n",
- "R1=Vr1/Ib\n",
- "print(\" use 4.7Kohm as standard\")\n",
- "#the transistor emitter terminal is .7 below ground and voltage across Re is\n",
- "Ve=Vee-Vbe\n",
- "Ie=Ve/Re\n",
- "Vc=Vcc-(Ie*3.9*10**3)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vc))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R3=8.2kohm standard value\n",
- " use 4.7Kohm as standard\n",
- "Current voltage is 5.1 V \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.17, Page No 220"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hFE=100.0\n",
- "Rc=2.2*10**3\n",
- "Rb=270.0*10**3\n",
- "Re=1.0*10**3\n",
- "R1=33.0*10**3\n",
- "R2=12*10**3\n",
- "\n",
- "#Calculations\n",
- "S=1+hFE\n",
- "print(\"for collector to base bias\")\n",
- "S=(1+hFE)/(1+(hFE*Rc)/(Rc+Rb))\n",
- "print(\" for voltage divider bias\")\n",
- "print(\"S=(1+hFE)/(1+hFE*Re(Re+R1||R2))\")\n",
- "S=(1+hFE)/(1+(hFE*Re)/(Re+(R1*R2)/(R1+R2)))\n",
- "\n",
- "#Results\n",
- "print(\"Voltage-divider bias is %.2f \" %(S))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "for collector to base bias\n",
- " for voltage divider bias\n",
- "S=(1+hFE)/(1+hFE*Re(Re+R1||R2))\n",
- "Voltage-divider bias is 9.01 \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.18, Page No 221"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Icbo1=15.0*10**-9# at 25C\n",
- "S=101.0\n",
- "print(\"chnage in temp\")\n",
- "T=105-25\n",
- "print(\" n=T in 10 step\")\n",
- "n=T/10.0\n",
- "\n",
- "#Calculations\n",
- "Icbo2=Icbo1*2**n\n",
- "Icbo=Icbo2-Icbo1\n",
- "print(\" for base bais\")\n",
- "Ic=S*Icbo\n",
- "print(\" for collector to base bais\")\n",
- "S=56\n",
- "Ic=S*Icbo\n",
- "print(\" for voltage divider bais\")\n",
- "S=8.2\n",
- "Ic=S*Icbo\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ic is %.1f mA \" %(Ic*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "chnage in temp\n",
- " n=T in 10 step\n",
- " for base bais\n",
- " for collector to base bais\n",
- " for voltage divider bais\n",
- "The value of Ic is 31.4 mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.19, Page No 223"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Re=4.7*10**3\n",
- "T=125-25\n",
- "\n",
- "#Calculations\n",
- "Vbe=T*(1.8*10**-3)\n",
- "Ie=Vbe/Re\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ie is %.1f V \" %(Ie*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ie is 38.3 V \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.20, Page No 223"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=10.0\n",
- "Rc=1.0*10**3\n",
- "Rb=6.8*10**3\n",
- "Vs=5.0\n",
- "\n",
- "#Calculations\n",
- "print(\" hFE calculation\")\n",
- "Ic=Vcc/Rc\n",
- "Ib=(Vs-Vbe)/Rb\n",
- "hFE=Ic/Ib\n",
- "print(\"when hFE=10\")\n",
- "hFE=10\n",
- "Ic=hFE*Ib\n",
- "Vce=Vcc-(Ic*Rc)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " hFE calculation\n",
- "when hFE=10\n",
- "Current voltage is 2.9 V \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.21, Page No 227"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Vcc=15.0\n",
- "Rc=3.3*10**3\n",
- "Vbe=.7\n",
- "Rb=56.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ic=Vcc/Rc\n",
- "Ib=(Vcc-Vbe)/Rb\n",
- "hFE=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\" minimum hFE is %3.2f \" %hFE)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " minimum hFE is 17.80 \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.22, Page No 229"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Vcc=12.0\n",
- "Ic=1.5*10**-3\n",
- "Vs=5.0\n",
- "hFE=10.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Vcc/Ic\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vs-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 28.7 kohm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.23, Page No 229"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculations\n",
- "Vcc=9.0\n",
- "Ic=2*10**-3\n",
- "hFE=10.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Vcc/Ic\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vcc-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 41.50 kohm \n"
- ]
- }
- ],
- "prompt_number": 22
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter5_1.ipynb b/Electronic_Devices_and_Circuits/Chapter5_1.ipynb deleted file mode 100755 index 07d0da6b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter5_1.ipynb +++ /dev/null @@ -1,1022 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 05 : BJT biasing"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.1, Page No 182"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=12.0*10**3\n",
- "Vcc=20.0\n",
- "print(\" When Ic=0\")\n",
- "Ic=0\n",
- "\n",
- "#Calculations\n",
- "Vce=Vcc-Ic*Rc\n",
- "print(\" At point A Ic=0 nad Vce=20\")\n",
- "print(\"When Vce=0\")\n",
- "Vce=0\n",
- "Ic=Vcc/Rc\n",
- "\n",
- "#Results\n",
- "print(\" At point B Ic=1.7mA and Vce=0\")\n",
- "print(\"Ic is %.1f mA \" %(Ic*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " When Ic=0\n",
- " At point A Ic=0 nad Vce=20\n",
- "When Vce=0\n",
- " At point B Ic=1.7mA and Vce=0\n",
- "Ic is 1.7 mA \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.2 Page No 186"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=18.0\n",
- "Rc=2.2*10**3\n",
- "Ib=40.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"when Ic=0\")\n",
- "Ic=0\n",
- "Vce=Vcc-Ic*Rc\n",
- "print(\"At point A Ic=0 and Vce=18\")\n",
- "print(\"when Vce=0\")\n",
- "Ic=Vcc/Rc\n",
- "\n",
- "#Results\n",
- "print(\" at point B Ic=8.2mA and Vce=0\")\n",
- "print(\"Ic = %.1f mA \" %(Ic*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Ic=0\n",
- "At point A Ic=0 and Vce=18\n",
- "when Vce=0\n",
- " at point B Ic=8.2mA and Vce=0\n",
- "Ic = 8.2 mA \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.3 Page No 189"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Rb=470*10**3\n",
- "Rc=2.2*10**3\n",
- "Vcc=18.0\n",
- "hfe=100\n",
- "Vee=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vee)/Rb\n",
- "Ic=hfe*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.9 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.4, Page No 189"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hFEmin=50.0\n",
- "hFEmax=200.0\n",
- "Vcc=18.0\n",
- "Vbe=0.7\n",
- "Rb=470.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vbe)/Rb\n",
- "Ic=hFEmin*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "Ic=hFEmax*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 1.8 V \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.5 Page No 193"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rb=270*10**3\n",
- "Rc=2.2*10**3\n",
- "Vcc=18.0\n",
- "hFE=100\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vbe)/(Rb+Rc*(hFE+1))\n",
- "Ic=hFE*Ib\n",
- "Vce=Vcc-Rc*(Ic+Ib)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 10.2 V \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.7 Page No 197"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "R1=33.0*10**3\n",
- "R2=12.0*10**3\n",
- "Rc=1.2*10**3\n",
- "Re=1*10**3\n",
- "Vcc=18.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "Ve=Vb-Vbe\n",
- "Ie=(Vb-Vbe)/Re\n",
- "Ic=Ie\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.0 V \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.8, Page No 199"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=18.0\n",
- "Vbe=.7\n",
- "hfe=100.0\n",
- "R1=33*10**3\n",
- "R2=12.0*10**3\n",
- "Re=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Vt=(Vcc*R2)/(R1+R2)\n",
- "Rt=(R1*R2)/(R1+R2)\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.7 V \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.9 Page No 200"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hfe=50.0\n",
- "Vt=4.8\n",
- "Rt=8.8*10**3#from example 5.7\n",
- "Re=1.0*10**3\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 10.4 V \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.10 Page No 201"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vt=4.8\n",
- "Rt=8.8*10**3#from example 5.8\n",
- "Re=1*10**3\n",
- "Vbe=.7\n",
- "hfe=200.0\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.4 V \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.11 Page No 208"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ic=5*10**-3\n",
- "Vcc=15.0\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "Rc=(Vcc-Vce)/Ic\n",
- "Ib=Ic/hfe\n",
- "Rb=(Vcc-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rv is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rv is 286.0 kohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.12, Page No 209"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ic=5*10**-3\n",
- "Vcc=15.0\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "Ib=Ic/hfe\n",
- "Rc=(Vcc-Vce)/(Ic+Ib)\n",
- "Rb=(Vce-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 86.0 kohm \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.13, Page No 211"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ve=Vce\n",
- "Ic=5.0*10**-3\n",
- "hFE=100.0\n",
- "Vcc=15.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "Re=Ve/Ie\n",
- "Rc=(Vcc-Vce-Ve)/Ic\n",
- "I2=Ic/10\n",
- "Vb=Ve+Vbe\n",
- "R2=Vb/I2\n",
- "R1=(Vcc-Vb)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kOhm \" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 18.6 kOhm \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.14, Page No 212"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=3.0\n",
- "Ve=5.0\n",
- "Ic=1*10**-3\n",
- "Vcc=12.0\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "R4=Ve/Ie\n",
- "print(\" with Ic=1mA and R4=4.7Kohm\")\n",
- "R4=4.7*10**3\n",
- "Ve=Ic*R4\n",
- "Vc=Ve+Vce\n",
- "Vr3=Vcc-Vc\n",
- "R3=Vr3/Ic\n",
- "Vb=Ve+Vbe\n",
- "I2=Ic/10\n",
- "R2=Vb/I2\n",
- "print(\" with R2=56Kohm and Vb=5.4V\")\n",
- "R2=56*10**3\n",
- "I2=Vb/R2\n",
- "R1=(Vcc-Vb)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %.1f V \" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with Ic=1mA and R4=4.7Kohm\n",
- " with R2=56Kohm and Vb=5.4V\n",
- "The value of R1 is 68.4 V \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.15, Page No 214"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=9.0\n",
- "Ve=4.0\n",
- "Ic=4*10**-3\n",
- "Vcc=18.0\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "R4=Ve/Ie\n",
- "Vb=Ve+Vbe\n",
- "I2=Ic/10\n",
- "R2=Vb/I2\n",
- "print(\" with R2=12Kohm standard\")\n",
- "R2=12*10**3\n",
- "I2=Vb/R2\n",
- "R1=(Vce+Ve-Vb)/I2\n",
- "print(\" with R1=22kohm standard\")\n",
- "R1=22*10**3\n",
- "Vr3=Vcc-Vce-Ve\n",
- "R3=Vr3/(Ic+I2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 %.2f V \" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R2=12Kohm standard\n",
- " with R1=22kohm standard\n",
- "The value of R3 1.14 V \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.16, Page No 216"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vc=5.0\n",
- "Ic=1.0*10**-3\n",
- "hFE=70.0\n",
- "Vbe=.7\n",
- "Vee=9.0\n",
- "Vcc=Vee\n",
- "Re=8.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Ve=Vee-Vbe\n",
- "Ie=Ic\n",
- "R3=Ve/Ie\n",
- "print(\" with R3=8.2kohm standard value\")\n",
- "R3=8.2*10**3\n",
- "Ie=Ve/R3\n",
- "Vr2=Vcc-Vc\n",
- "R2=Vr2/Ic\n",
- "Ib=Ic/hFE\n",
- "Vr1=Vbe/10\n",
- "R1=Vr1/Ib\n",
- "print(\" use 4.7Kohm as standard\")\n",
- "#the transistor emitter terminal is .7 below ground and voltage across Re is\n",
- "Ve=Vee-Vbe\n",
- "Ie=Ve/Re\n",
- "Vc=Vcc-(Ie*3.9*10**3)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vc))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R3=8.2kohm standard value\n",
- " use 4.7Kohm as standard\n",
- "Current voltage is 5.1 V \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.17, Page No 220"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hFE=100.0\n",
- "Rc=2.2*10**3\n",
- "Rb=270.0*10**3\n",
- "Re=1.0*10**3\n",
- "R1=33.0*10**3\n",
- "R2=12*10**3\n",
- "\n",
- "#Calculations\n",
- "S=1+hFE\n",
- "print(\"for collector to base bias\")\n",
- "S=(1+hFE)/(1+(hFE*Rc)/(Rc+Rb))\n",
- "print(\" for voltage divider bias\")\n",
- "print(\"S=(1+hFE)/(1+hFE*Re(Re+R1||R2))\")\n",
- "S=(1+hFE)/(1+(hFE*Re)/(Re+(R1*R2)/(R1+R2)))\n",
- "\n",
- "#Results\n",
- "print(\"Voltage-divider bias is %.2f \" %(S))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "for collector to base bias\n",
- " for voltage divider bias\n",
- "S=(1+hFE)/(1+hFE*Re(Re+R1||R2))\n",
- "Voltage-divider bias is 9.01 \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.18, Page No 221"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Icbo1=15.0*10**-9# at 25C\n",
- "S=101.0\n",
- "print(\"chnage in temp\")\n",
- "T=105-25\n",
- "print(\" n=T in 10 step\")\n",
- "n=T/10.0\n",
- "\n",
- "#Calculations\n",
- "Icbo2=Icbo1*2**n\n",
- "Icbo=Icbo2-Icbo1\n",
- "print(\" for base bais\")\n",
- "Ic=S*Icbo\n",
- "print(\" for collector to base bais\")\n",
- "S=56\n",
- "Ic=S*Icbo\n",
- "print(\" for voltage divider bais\")\n",
- "S=8.2\n",
- "Ic=S*Icbo\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ic is %.1f mA \" %(Ic*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "chnage in temp\n",
- " n=T in 10 step\n",
- " for base bais\n",
- " for collector to base bais\n",
- " for voltage divider bais\n",
- "The value of Ic is 31.4 mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.19, Page No 223"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Re=4.7*10**3\n",
- "T=125-25\n",
- "\n",
- "#Calculations\n",
- "Vbe=T*(1.8*10**-3)\n",
- "Ie=Vbe/Re\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ie is %.1f V \" %(Ie*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ie is 38.3 V \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.20, Page No 223"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=10.0\n",
- "Rc=1.0*10**3\n",
- "Rb=6.8*10**3\n",
- "Vs=5.0\n",
- "\n",
- "#Calculations\n",
- "print(\" hFE calculation\")\n",
- "Ic=Vcc/Rc\n",
- "Ib=(Vs-Vbe)/Rb\n",
- "hFE=Ic/Ib\n",
- "print(\"when hFE=10\")\n",
- "hFE=10\n",
- "Ic=hFE*Ib\n",
- "Vce=Vcc-(Ic*Rc)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " hFE calculation\n",
- "when hFE=10\n",
- "Current voltage is 2.9 V \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.21, Page No 227"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Vcc=15.0\n",
- "Rc=3.3*10**3\n",
- "Vbe=.7\n",
- "Rb=56.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ic=Vcc/Rc\n",
- "Ib=(Vcc-Vbe)/Rb\n",
- "hFE=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\" minimum hFE is %3.2f \" %hFE)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " minimum hFE is 17.80 \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.22, Page No 229"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Vcc=12.0\n",
- "Ic=1.5*10**-3\n",
- "Vs=5.0\n",
- "hFE=10.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Vcc/Ic\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vs-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 28.7 kohm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.23, Page No 229"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculations\n",
- "Vcc=9.0\n",
- "Ic=2*10**-3\n",
- "hFE=10.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Vcc/Ic\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vcc-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 41.50 kohm \n"
- ]
- }
- ],
- "prompt_number": 22
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter5_2.ipynb b/Electronic_Devices_and_Circuits/Chapter5_2.ipynb deleted file mode 100755 index 07d0da6b..00000000 --- a/Electronic_Devices_and_Circuits/Chapter5_2.ipynb +++ /dev/null @@ -1,1022 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 05 : BJT biasing"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.1, Page No 182"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=12.0*10**3\n",
- "Vcc=20.0\n",
- "print(\" When Ic=0\")\n",
- "Ic=0\n",
- "\n",
- "#Calculations\n",
- "Vce=Vcc-Ic*Rc\n",
- "print(\" At point A Ic=0 nad Vce=20\")\n",
- "print(\"When Vce=0\")\n",
- "Vce=0\n",
- "Ic=Vcc/Rc\n",
- "\n",
- "#Results\n",
- "print(\" At point B Ic=1.7mA and Vce=0\")\n",
- "print(\"Ic is %.1f mA \" %(Ic*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " When Ic=0\n",
- " At point A Ic=0 nad Vce=20\n",
- "When Vce=0\n",
- " At point B Ic=1.7mA and Vce=0\n",
- "Ic is 1.7 mA \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.2 Page No 186"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vcc=18.0\n",
- "Rc=2.2*10**3\n",
- "Ib=40.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"when Ic=0\")\n",
- "Ic=0\n",
- "Vce=Vcc-Ic*Rc\n",
- "print(\"At point A Ic=0 and Vce=18\")\n",
- "print(\"when Vce=0\")\n",
- "Ic=Vcc/Rc\n",
- "\n",
- "#Results\n",
- "print(\" at point B Ic=8.2mA and Vce=0\")\n",
- "print(\"Ic = %.1f mA \" %(Ic*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "when Ic=0\n",
- "At point A Ic=0 and Vce=18\n",
- "when Vce=0\n",
- " at point B Ic=8.2mA and Vce=0\n",
- "Ic = 8.2 mA \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.3 Page No 189"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Rb=470*10**3\n",
- "Rc=2.2*10**3\n",
- "Vcc=18.0\n",
- "hfe=100\n",
- "Vee=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vee)/Rb\n",
- "Ic=hfe*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.9 V \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.4, Page No 189"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hFEmin=50.0\n",
- "hFEmax=200.0\n",
- "Vcc=18.0\n",
- "Vbe=0.7\n",
- "Rb=470.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vbe)/Rb\n",
- "Ic=hFEmin*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "Ic=hFEmax*Ib\n",
- "Vce=Vcc-Ic*Rc\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 1.8 V \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.5 Page No 193"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Rb=270*10**3\n",
- "Rc=2.2*10**3\n",
- "Vcc=18.0\n",
- "hFE=100\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vcc-Vbe)/(Rb+Rc*(hFE+1))\n",
- "Ic=hFE*Ib\n",
- "Vce=Vcc-Rc*(Ic+Ib)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 10.2 V \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.7 Page No 197"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "R1=33.0*10**3\n",
- "R2=12.0*10**3\n",
- "Rc=1.2*10**3\n",
- "Re=1*10**3\n",
- "Vcc=18.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "Ve=Vb-Vbe\n",
- "Ie=(Vb-Vbe)/Re\n",
- "Ic=Ie\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.0 V \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.8, Page No 199"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=18.0\n",
- "Vbe=.7\n",
- "hfe=100.0\n",
- "R1=33*10**3\n",
- "R2=12.0*10**3\n",
- "Re=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Vt=(Vcc*R2)/(R1+R2)\n",
- "Rt=(R1*R2)/(R1+R2)\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.7 V \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.9 Page No 200"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hfe=50.0\n",
- "Vt=4.8\n",
- "Rt=8.8*10**3#from example 5.7\n",
- "Re=1.0*10**3\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 10.4 V \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.10 Page No 201"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vt=4.8\n",
- "Rt=8.8*10**3#from example 5.8\n",
- "Re=1*10**3\n",
- "Vbe=.7\n",
- "hfe=200.0\n",
- "\n",
- "#Calculations\n",
- "Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
- "Ic=hfe*Ib\n",
- "Ie=Ib+Ic\n",
- "Ve=Ie*Re\n",
- "Vc=Vcc-(Ic*Rc)\n",
- "Vce=Vc-Ve\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current voltage is 9.4 V \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.11 Page No 208"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ic=5*10**-3\n",
- "Vcc=15.0\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "Rc=(Vcc-Vce)/Ic\n",
- "Ib=Ic/hfe\n",
- "Rb=(Vcc-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rv is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rv is 286.0 kohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.12, Page No 209"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ic=5*10**-3\n",
- "Vcc=15.0\n",
- "hfe=100.0\n",
- "\n",
- "#Calculations\n",
- "Ib=Ic/hfe\n",
- "Rc=(Vcc-Vce)/(Ic+Ib)\n",
- "Rb=(Vce-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 86.0 kohm \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.13, Page No 211"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=5.0\n",
- "Ve=Vce\n",
- "Ic=5.0*10**-3\n",
- "hFE=100.0\n",
- "Vcc=15.0\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "Re=Ve/Ie\n",
- "Rc=(Vcc-Vce-Ve)/Ic\n",
- "I2=Ic/10\n",
- "Vb=Ve+Vbe\n",
- "R2=Vb/I2\n",
- "R1=(Vcc-Vb)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kOhm \" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 18.6 kOhm \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.14, Page No 212"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=3.0\n",
- "Ve=5.0\n",
- "Ic=1*10**-3\n",
- "Vcc=12.0\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "R4=Ve/Ie\n",
- "print(\" with Ic=1mA and R4=4.7Kohm\")\n",
- "R4=4.7*10**3\n",
- "Ve=Ic*R4\n",
- "Vc=Ve+Vce\n",
- "Vr3=Vcc-Vc\n",
- "R3=Vr3/Ic\n",
- "Vb=Ve+Vbe\n",
- "I2=Ic/10\n",
- "R2=Vb/I2\n",
- "print(\" with R2=56Kohm and Vb=5.4V\")\n",
- "R2=56*10**3\n",
- "I2=Vb/R2\n",
- "R1=(Vcc-Vb)/I2\n",
- "\n",
- "#Results\n",
- "print(\"The value of R1 is %.1f V \" %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with Ic=1mA and R4=4.7Kohm\n",
- " with R2=56Kohm and Vb=5.4V\n",
- "The value of R1 is 68.4 V \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.15, Page No 214"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vce=9.0\n",
- "Ve=4.0\n",
- "Ic=4*10**-3\n",
- "Vcc=18.0\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "R4=Ve/Ie\n",
- "Vb=Ve+Vbe\n",
- "I2=Ic/10\n",
- "R2=Vb/I2\n",
- "print(\" with R2=12Kohm standard\")\n",
- "R2=12*10**3\n",
- "I2=Vb/R2\n",
- "R1=(Vce+Ve-Vb)/I2\n",
- "print(\" with R1=22kohm standard\")\n",
- "R1=22*10**3\n",
- "Vr3=Vcc-Vce-Ve\n",
- "R3=Vr3/(Ic+I2)\n",
- "\n",
- "#Results\n",
- "print(\"The value of R3 %.2f V \" %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R2=12Kohm standard\n",
- " with R1=22kohm standard\n",
- "The value of R3 1.14 V \n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.16, Page No 216"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vc=5.0\n",
- "Ic=1.0*10**-3\n",
- "hFE=70.0\n",
- "Vbe=.7\n",
- "Vee=9.0\n",
- "Vcc=Vee\n",
- "Re=8.2*10**3\n",
- "\n",
- "#Calculations\n",
- "Ve=Vee-Vbe\n",
- "Ie=Ic\n",
- "R3=Ve/Ie\n",
- "print(\" with R3=8.2kohm standard value\")\n",
- "R3=8.2*10**3\n",
- "Ie=Ve/R3\n",
- "Vr2=Vcc-Vc\n",
- "R2=Vr2/Ic\n",
- "Ib=Ic/hFE\n",
- "Vr1=Vbe/10\n",
- "R1=Vr1/Ib\n",
- "print(\" use 4.7Kohm as standard\")\n",
- "#the transistor emitter terminal is .7 below ground and voltage across Re is\n",
- "Ve=Vee-Vbe\n",
- "Ie=Ve/Re\n",
- "Vc=Vcc-(Ie*3.9*10**3)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vc))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " with R3=8.2kohm standard value\n",
- " use 4.7Kohm as standard\n",
- "Current voltage is 5.1 V \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.17, Page No 220"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hFE=100.0\n",
- "Rc=2.2*10**3\n",
- "Rb=270.0*10**3\n",
- "Re=1.0*10**3\n",
- "R1=33.0*10**3\n",
- "R2=12*10**3\n",
- "\n",
- "#Calculations\n",
- "S=1+hFE\n",
- "print(\"for collector to base bias\")\n",
- "S=(1+hFE)/(1+(hFE*Rc)/(Rc+Rb))\n",
- "print(\" for voltage divider bias\")\n",
- "print(\"S=(1+hFE)/(1+hFE*Re(Re+R1||R2))\")\n",
- "S=(1+hFE)/(1+(hFE*Re)/(Re+(R1*R2)/(R1+R2)))\n",
- "\n",
- "#Results\n",
- "print(\"Voltage-divider bias is %.2f \" %(S))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "for collector to base bias\n",
- " for voltage divider bias\n",
- "S=(1+hFE)/(1+hFE*Re(Re+R1||R2))\n",
- "Voltage-divider bias is 9.01 \n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.18, Page No 221"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Icbo1=15.0*10**-9# at 25C\n",
- "S=101.0\n",
- "print(\"chnage in temp\")\n",
- "T=105-25\n",
- "print(\" n=T in 10 step\")\n",
- "n=T/10.0\n",
- "\n",
- "#Calculations\n",
- "Icbo2=Icbo1*2**n\n",
- "Icbo=Icbo2-Icbo1\n",
- "print(\" for base bais\")\n",
- "Ic=S*Icbo\n",
- "print(\" for collector to base bais\")\n",
- "S=56\n",
- "Ic=S*Icbo\n",
- "print(\" for voltage divider bais\")\n",
- "S=8.2\n",
- "Ic=S*Icbo\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ic is %.1f mA \" %(Ic*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "chnage in temp\n",
- " n=T in 10 step\n",
- " for base bais\n",
- " for collector to base bais\n",
- " for voltage divider bais\n",
- "The value of Ic is 31.4 mA \n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.19, Page No 223"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Re=4.7*10**3\n",
- "T=125-25\n",
- "\n",
- "#Calculations\n",
- "Vbe=T*(1.8*10**-3)\n",
- "Ie=Vbe/Re\n",
- "\n",
- "#Results\n",
- "print(\"The value of Ie is %.1f V \" %(Ie*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ie is 38.3 V \n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.20, Page No 223"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=10.0\n",
- "Rc=1.0*10**3\n",
- "Rb=6.8*10**3\n",
- "Vs=5.0\n",
- "\n",
- "#Calculations\n",
- "print(\" hFE calculation\")\n",
- "Ic=Vcc/Rc\n",
- "Ib=(Vs-Vbe)/Rb\n",
- "hFE=Ic/Ib\n",
- "print(\"when hFE=10\")\n",
- "hFE=10\n",
- "Ic=hFE*Ib\n",
- "Vce=Vcc-(Ic*Rc)\n",
- "\n",
- "#Results\n",
- "print(\"Current voltage is %.1f V \" %(Vce))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " hFE calculation\n",
- "when hFE=10\n",
- "Current voltage is 2.9 V \n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.21, Page No 227"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Vcc=15.0\n",
- "Rc=3.3*10**3\n",
- "Vbe=.7\n",
- "Rb=56.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ic=Vcc/Rc\n",
- "Ib=(Vcc-Vbe)/Rb\n",
- "hFE=Ic/Ib\n",
- "\n",
- "#Results\n",
- "print(\" minimum hFE is %3.2f \" %hFE)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " minimum hFE is 17.80 \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.22, Page No 229"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Vcc=12.0\n",
- "Ic=1.5*10**-3\n",
- "Vs=5.0\n",
- "hFE=10.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Vcc/Ic\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vs-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.1f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 28.7 kohm \n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.23, Page No 229"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculations\n",
- "Vcc=9.0\n",
- "Ic=2*10**-3\n",
- "hFE=10.0\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "Rc=Vcc/Ic\n",
- "Ib=Ic/hFE\n",
- "Rb=(Vcc-Vbe)/Ib\n",
- "\n",
- "#Results\n",
- "print(\"The value of Rb is %.2f kohm \" %(Rb/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Rb is 41.50 kohm \n"
- ]
- }
- ],
- "prompt_number": 22
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter6.ipynb b/Electronic_Devices_and_Circuits/Chapter6.ipynb deleted file mode 100755 index 85bada6c..00000000 --- a/Electronic_Devices_and_Circuits/Chapter6.ipynb +++ /dev/null @@ -1,656 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 06 : Ac analysis of BJT circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.1, Page No 240"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=12.0\n",
- "R2=15.0*10**3\n",
- "R1=33.0*10**3\n",
- "rs=600\n",
- "\n",
- "#Calculations\n",
- "print(\"with no signal source\")\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "print(\" base bais voltage when no signal source is present %3.2fV \" %Vb)\n",
- "print(\" signal source directly connected\")\n",
- "Vb=(Vcc*((rs*R2)/(rs+R2))/(R1+((rs*R2)/(rs+R2))))\n",
- "\n",
- "#Results\n",
- "print(\"base bais voltage is %3.2fV \" %Vb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "with no signal source\n",
- " base bais voltage when no signal source is present 3.75V \n",
- " signal source directly connected\n",
- "base bais voltage is 0.21V \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.2, Page No 244"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Rc=2.2*10**3\n",
- "Re=2.7*10**3\n",
- "R1=18.0*10**3\n",
- "R2=8.2*10**3\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "print(\"drawing dc load line\")\n",
- "Rldc=Rc+Re\n",
- "print(\" for Vce\")\n",
- "Ic=0\n",
- "Vcc=20\n",
- "Vce=Vcc-Ic*(Rc+Re)\n",
- "print(\"plot point A at\")\n",
- "Ic=Vcc/(Rc+Re)\n",
- "print(\"plot point B Ic=4.08mA and Vce=0\")\n",
- "print(\" draw dc laod line through point A nad B\")\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "Ve=Vb-Vbe\n",
- "Ic=Ve/Re\n",
- "Ie=Ic\n",
- "print(\"drawing the ac load line\")\n",
- "Rlac=Rc#when there is no external Rl\n",
- "Vce=Ic*Rc\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"The voltage is %.2f v \" %Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "drawing dc load line\n",
- " for Vce\n",
- "plot point A at\n",
- "plot point B Ic=4.08mA and Vce=0\n",
- " draw dc laod line through point A nad B\n",
- "drawing the ac load line\n",
- "The voltage is 4.53 v \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.3 Page No 251"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=4.5\n",
- "Ib=40.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"from current characteristic at Vce=4.5V and Ib=40uA\")\n",
- "Ic=4.0*10**-3\n",
- "Ib=30.0*10**-6\n",
- "hFE=Ic/Ib\n",
- "print(\" the value of hFE is %d \" %hFE)\n",
- "print(\"from output characteristic at Vce=4.5 and Ib=40uA\")\n",
- "Ic=0.2\n",
- "Vce=6\n",
- "hoe=(Ic/Vce)\n",
- "R=1/hoe\n",
- "\n",
- "#Results\n",
- "print(\"the value of hoe is %3.1fuS \" %(hoe*10**3))\n",
- "print(\"the value of 1/hoe is %3.1fuS \" %(1/hoe))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "from current characteristic at Vce=4.5V and Ib=40uA\n",
- " the value of hFE is 133 \n",
- "from output characteristic at Vce=4.5 and Ib=40uA\n",
- "the value of hoe is 33.3uS \n",
- "the value of 1/hoe is 30.0uS \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.4, Page No 253"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hfe=133.0\n",
- "hoe=33.3*10**-6\n",
- "hfc=1+hfe\n",
- "\n",
- "#Calculations\n",
- "hob=hoe/(1+hfe)\n",
- "A=hfe/(1+hfe)\n",
- "\n",
- "#Results\n",
- "print(\"tye value of a is %3.1fuS \" %(A))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "tye value of a is 1.0uS \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.5 Page No 253"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=20.0*10**-6\n",
- "Ic=1.0*10**-3\n",
- "Ie=Ic\n",
- "\n",
- "#Calculations\n",
- "re=(26*10**-3)/Ie\n",
- "hfe=Ic/Ib\n",
- "hie=(1+hfe)*re\n",
- "r=hie\n",
- "B=hfe\n",
- "\n",
- "#Results\n",
- "print(\"the value of b is %3.1f \" %(B))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "the value of b is 50.0 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.6 Page No 258"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "hoe=1*10**-6\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" input impedance Zi=R1||R2||hie\")\n",
- "Zi=((R1*R2*hie)/(R1+R2+hie))*10**-3\n",
- "print(\" input impedance is %3.2fKohm \" %Zi)\n",
- "print(\"output impedance is Zo=Rc||(1/hoe)\")\n",
- "Zo=((Rc*(1/hoe))/(Rc+(1/hoe)))*10**-3\n",
- "print(\" output impadance is %f3.2fKohm \" %Zo)\n",
- "Av=-(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %d \" %Av)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input impedance Zi=R1||R2||hie\n",
- " input impedance is 63416.34Kohm \n",
- "output impedance is Zo=Rc||(1/hoe)\n",
- " output impadance is 3.8848493.2fKohm \n",
- " voltage gain is -132 \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.7, Page No 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Ic=1.5*10**-3\n",
- "Rc=4.7*10**3\n",
- "Rl=56.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "re=(26*10**-3)/Ie\n",
- "Av=-(((Rc*Rl)/(Rc+Rl))/re)\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %d \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage gain is -250 \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.8 Page No 262"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "hoe=1.0*10**-6\n",
- "Re=4.7*10**3\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+Re*(1+hfe)\n",
- "print(\" input impedance is Zi=R1||R2||Zb\")\n",
- "Zi=((R1*R2*Zb)/(R1+R2+Zb))\n",
- "print(\" input circuit resistance is %3.3fKohm \" %Zi)\n",
- "Zo=Rc\n",
- "Av=-hfe*((Rc*Rl)/(Rc+Rl))/(hie+Re*(1+hfe))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input impedance is Zi=R1||R2||Zb\n",
- " input circuit resistance is 2830983654.045Kohm \n",
- "voltage gain is -0.777 \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.9 Page No 267"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "R1=10.0*10**3\n",
- "R2=10.0*10**3\n",
- "Re=4.7*10**3\n",
- "Rl=12.0*10**3\n",
- "rs=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" Rl is not connected\")\n",
- "hic=hie\n",
- "hfc=1+hfe\n",
- "Zb=hic+hfc*(Re)\n",
- "Zi=(R1*R2*Zb)/(R1+R2+Zb)\n",
- "Ze=(hic+(R1*R2*rs)/(R1+R2+rs))/hfc\n",
- "Z0=(Ze*Re)/(Ze+Re)\n",
- "print(\" when Rl is connected\")\n",
- "Zb=hic+hfc*((Re*Rl)/(Re+Rl))\n",
- "Zi=(R1*R2*Zb)/(R1+R2+Zb)\n",
- "hib=hie/(1+hfe)\n",
- "Av=((Re*Rl)/(Re+Rl))/(hib+((Re*Rl)/(Re+Rl)))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Rl is not connected\n",
- " when Rl is connected\n",
- "voltage gain is 0.992 \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.10 Page No 273"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "Re=4.7*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "hib=hie/(1+hfe)\n",
- "hfb=hfe/(1+hfe)\n",
- "Zi=(hib*Re)/(Re+hib)\n",
- "print(\"input impedance is %3.2fohm \" %Zi)\n",
- "Zo=Rc\n",
- "print(\" output impedance is %3.2fohm \" %Zo)\n",
- "Av=(hfb*((Rc*Rl)/(Rc+Rl)))/hib\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %3.2f \" %Av)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance is 27.47ohm \n",
- " output impedance is 3900.00ohm \n",
- " voltage gain is 132.96 \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.11, Page No 273"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hib=27.6\n",
- "hfb=.987\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Re=4.7*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Ze=hib+Rb*(1-hfb)\n",
- "Zi=(Ze*Re)/(Ze+Re)\n",
- "Av=(hfb*((Rc*Rl)/(Rc+Rl)))/(hib+Rb*(1-hfb))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain is 8.609 \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.12, Page No 277"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=5.6*10**3\n",
- "Rl=33.0*10**3\n",
- "rs=600.0\n",
- "hfe=100\n",
- "hie=1.5*10**3\n",
- "vs=50.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "print(\" CE circuit operation with vs at transistor base and Re bypassed\")\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Zb=hie\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Zi=(Rb*Zb)/(Rb+Zb)\n",
- "vi=(vs*Zi)/(rs+Zi)\n",
- "vo=Av*vi\n",
- "print(\"Cb circuit operation with vs at emitter and the base resistor bypassed\")\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Ze=hie/(1+hfe)\n",
- "Zi=(Ze*Re)/(Ze+Re)\n",
- "vi=(vs*Zi)/(rs+Zi)\n",
- "vo=Av*vi\n",
- "\n",
- "#Results\n",
- "print(\"voltage vo is %3.2f \" %(vo*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " CE circuit operation with vs at transistor base and Re bypassed\n",
- "Cb circuit operation with vs at emitter and the base resistor bypassed\n",
- "voltage vo is 384.29 \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.13, Page No 279"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Io=50.0*10**-9\n",
- "Vbe=.7\n",
- "Vbc=-10\n",
- "Af=.995\n",
- "Ar=.5\n",
- "Vt=26.0*10**-3\n",
- "n=2.0\n",
- "Vd=-10.0\n",
- "\n",
- "#Calculations\n",
- "x=Vd/(n*Vt)\n",
- "Idc=(Io*((2.73**-x)-1))*10**9\n",
- "Idc=Io*(-1)\n",
- "y=Vbe/(n*Vt)\n",
- "Ide=Io*((2.73**y)-1)\n",
- "I1=Af*Ide\n",
- "I2=Ar*Idc\n",
- "Ic=I1-Idc\n",
- "Ie=Ide-I2\n",
- "Ib=Ie-Ic\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %(Ib*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain is 185.909 \n"
- ]
- }
- ],
- "prompt_number": 13
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter6_1.ipynb b/Electronic_Devices_and_Circuits/Chapter6_1.ipynb deleted file mode 100755 index 85bada6c..00000000 --- a/Electronic_Devices_and_Circuits/Chapter6_1.ipynb +++ /dev/null @@ -1,656 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 06 : Ac analysis of BJT circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.1, Page No 240"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=12.0\n",
- "R2=15.0*10**3\n",
- "R1=33.0*10**3\n",
- "rs=600\n",
- "\n",
- "#Calculations\n",
- "print(\"with no signal source\")\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "print(\" base bais voltage when no signal source is present %3.2fV \" %Vb)\n",
- "print(\" signal source directly connected\")\n",
- "Vb=(Vcc*((rs*R2)/(rs+R2))/(R1+((rs*R2)/(rs+R2))))\n",
- "\n",
- "#Results\n",
- "print(\"base bais voltage is %3.2fV \" %Vb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "with no signal source\n",
- " base bais voltage when no signal source is present 3.75V \n",
- " signal source directly connected\n",
- "base bais voltage is 0.21V \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.2, Page No 244"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Rc=2.2*10**3\n",
- "Re=2.7*10**3\n",
- "R1=18.0*10**3\n",
- "R2=8.2*10**3\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "print(\"drawing dc load line\")\n",
- "Rldc=Rc+Re\n",
- "print(\" for Vce\")\n",
- "Ic=0\n",
- "Vcc=20\n",
- "Vce=Vcc-Ic*(Rc+Re)\n",
- "print(\"plot point A at\")\n",
- "Ic=Vcc/(Rc+Re)\n",
- "print(\"plot point B Ic=4.08mA and Vce=0\")\n",
- "print(\" draw dc laod line through point A nad B\")\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "Ve=Vb-Vbe\n",
- "Ic=Ve/Re\n",
- "Ie=Ic\n",
- "print(\"drawing the ac load line\")\n",
- "Rlac=Rc#when there is no external Rl\n",
- "Vce=Ic*Rc\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"The voltage is %.2f v \" %Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "drawing dc load line\n",
- " for Vce\n",
- "plot point A at\n",
- "plot point B Ic=4.08mA and Vce=0\n",
- " draw dc laod line through point A nad B\n",
- "drawing the ac load line\n",
- "The voltage is 4.53 v \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.3 Page No 251"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=4.5\n",
- "Ib=40.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"from current characteristic at Vce=4.5V and Ib=40uA\")\n",
- "Ic=4.0*10**-3\n",
- "Ib=30.0*10**-6\n",
- "hFE=Ic/Ib\n",
- "print(\" the value of hFE is %d \" %hFE)\n",
- "print(\"from output characteristic at Vce=4.5 and Ib=40uA\")\n",
- "Ic=0.2\n",
- "Vce=6\n",
- "hoe=(Ic/Vce)\n",
- "R=1/hoe\n",
- "\n",
- "#Results\n",
- "print(\"the value of hoe is %3.1fuS \" %(hoe*10**3))\n",
- "print(\"the value of 1/hoe is %3.1fuS \" %(1/hoe))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "from current characteristic at Vce=4.5V and Ib=40uA\n",
- " the value of hFE is 133 \n",
- "from output characteristic at Vce=4.5 and Ib=40uA\n",
- "the value of hoe is 33.3uS \n",
- "the value of 1/hoe is 30.0uS \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.4, Page No 253"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hfe=133.0\n",
- "hoe=33.3*10**-6\n",
- "hfc=1+hfe\n",
- "\n",
- "#Calculations\n",
- "hob=hoe/(1+hfe)\n",
- "A=hfe/(1+hfe)\n",
- "\n",
- "#Results\n",
- "print(\"tye value of a is %3.1fuS \" %(A))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "tye value of a is 1.0uS \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.5 Page No 253"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=20.0*10**-6\n",
- "Ic=1.0*10**-3\n",
- "Ie=Ic\n",
- "\n",
- "#Calculations\n",
- "re=(26*10**-3)/Ie\n",
- "hfe=Ic/Ib\n",
- "hie=(1+hfe)*re\n",
- "r=hie\n",
- "B=hfe\n",
- "\n",
- "#Results\n",
- "print(\"the value of b is %3.1f \" %(B))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "the value of b is 50.0 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.6 Page No 258"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "hoe=1*10**-6\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" input impedance Zi=R1||R2||hie\")\n",
- "Zi=((R1*R2*hie)/(R1+R2+hie))*10**-3\n",
- "print(\" input impedance is %3.2fKohm \" %Zi)\n",
- "print(\"output impedance is Zo=Rc||(1/hoe)\")\n",
- "Zo=((Rc*(1/hoe))/(Rc+(1/hoe)))*10**-3\n",
- "print(\" output impadance is %f3.2fKohm \" %Zo)\n",
- "Av=-(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %d \" %Av)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input impedance Zi=R1||R2||hie\n",
- " input impedance is 63416.34Kohm \n",
- "output impedance is Zo=Rc||(1/hoe)\n",
- " output impadance is 3.8848493.2fKohm \n",
- " voltage gain is -132 \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.7, Page No 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Ic=1.5*10**-3\n",
- "Rc=4.7*10**3\n",
- "Rl=56.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "re=(26*10**-3)/Ie\n",
- "Av=-(((Rc*Rl)/(Rc+Rl))/re)\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %d \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage gain is -250 \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.8 Page No 262"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "hoe=1.0*10**-6\n",
- "Re=4.7*10**3\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+Re*(1+hfe)\n",
- "print(\" input impedance is Zi=R1||R2||Zb\")\n",
- "Zi=((R1*R2*Zb)/(R1+R2+Zb))\n",
- "print(\" input circuit resistance is %3.3fKohm \" %Zi)\n",
- "Zo=Rc\n",
- "Av=-hfe*((Rc*Rl)/(Rc+Rl))/(hie+Re*(1+hfe))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input impedance is Zi=R1||R2||Zb\n",
- " input circuit resistance is 2830983654.045Kohm \n",
- "voltage gain is -0.777 \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.9 Page No 267"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "R1=10.0*10**3\n",
- "R2=10.0*10**3\n",
- "Re=4.7*10**3\n",
- "Rl=12.0*10**3\n",
- "rs=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" Rl is not connected\")\n",
- "hic=hie\n",
- "hfc=1+hfe\n",
- "Zb=hic+hfc*(Re)\n",
- "Zi=(R1*R2*Zb)/(R1+R2+Zb)\n",
- "Ze=(hic+(R1*R2*rs)/(R1+R2+rs))/hfc\n",
- "Z0=(Ze*Re)/(Ze+Re)\n",
- "print(\" when Rl is connected\")\n",
- "Zb=hic+hfc*((Re*Rl)/(Re+Rl))\n",
- "Zi=(R1*R2*Zb)/(R1+R2+Zb)\n",
- "hib=hie/(1+hfe)\n",
- "Av=((Re*Rl)/(Re+Rl))/(hib+((Re*Rl)/(Re+Rl)))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Rl is not connected\n",
- " when Rl is connected\n",
- "voltage gain is 0.992 \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.10 Page No 273"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "Re=4.7*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "hib=hie/(1+hfe)\n",
- "hfb=hfe/(1+hfe)\n",
- "Zi=(hib*Re)/(Re+hib)\n",
- "print(\"input impedance is %3.2fohm \" %Zi)\n",
- "Zo=Rc\n",
- "print(\" output impedance is %3.2fohm \" %Zo)\n",
- "Av=(hfb*((Rc*Rl)/(Rc+Rl)))/hib\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %3.2f \" %Av)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance is 27.47ohm \n",
- " output impedance is 3900.00ohm \n",
- " voltage gain is 132.96 \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.11, Page No 273"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hib=27.6\n",
- "hfb=.987\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Re=4.7*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Ze=hib+Rb*(1-hfb)\n",
- "Zi=(Ze*Re)/(Ze+Re)\n",
- "Av=(hfb*((Rc*Rl)/(Rc+Rl)))/(hib+Rb*(1-hfb))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain is 8.609 \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.12, Page No 277"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=5.6*10**3\n",
- "Rl=33.0*10**3\n",
- "rs=600.0\n",
- "hfe=100\n",
- "hie=1.5*10**3\n",
- "vs=50.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "print(\" CE circuit operation with vs at transistor base and Re bypassed\")\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Zb=hie\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Zi=(Rb*Zb)/(Rb+Zb)\n",
- "vi=(vs*Zi)/(rs+Zi)\n",
- "vo=Av*vi\n",
- "print(\"Cb circuit operation with vs at emitter and the base resistor bypassed\")\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Ze=hie/(1+hfe)\n",
- "Zi=(Ze*Re)/(Ze+Re)\n",
- "vi=(vs*Zi)/(rs+Zi)\n",
- "vo=Av*vi\n",
- "\n",
- "#Results\n",
- "print(\"voltage vo is %3.2f \" %(vo*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " CE circuit operation with vs at transistor base and Re bypassed\n",
- "Cb circuit operation with vs at emitter and the base resistor bypassed\n",
- "voltage vo is 384.29 \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.13, Page No 279"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Io=50.0*10**-9\n",
- "Vbe=.7\n",
- "Vbc=-10\n",
- "Af=.995\n",
- "Ar=.5\n",
- "Vt=26.0*10**-3\n",
- "n=2.0\n",
- "Vd=-10.0\n",
- "\n",
- "#Calculations\n",
- "x=Vd/(n*Vt)\n",
- "Idc=(Io*((2.73**-x)-1))*10**9\n",
- "Idc=Io*(-1)\n",
- "y=Vbe/(n*Vt)\n",
- "Ide=Io*((2.73**y)-1)\n",
- "I1=Af*Ide\n",
- "I2=Ar*Idc\n",
- "Ic=I1-Idc\n",
- "Ie=Ide-I2\n",
- "Ib=Ie-Ic\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %(Ib*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain is 185.909 \n"
- ]
- }
- ],
- "prompt_number": 13
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter6_2.ipynb b/Electronic_Devices_and_Circuits/Chapter6_2.ipynb deleted file mode 100755 index 85bada6c..00000000 --- a/Electronic_Devices_and_Circuits/Chapter6_2.ipynb +++ /dev/null @@ -1,656 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 06 : Ac analysis of BJT circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.1, Page No 240"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vcc=12.0\n",
- "R2=15.0*10**3\n",
- "R1=33.0*10**3\n",
- "rs=600\n",
- "\n",
- "#Calculations\n",
- "print(\"with no signal source\")\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "print(\" base bais voltage when no signal source is present %3.2fV \" %Vb)\n",
- "print(\" signal source directly connected\")\n",
- "Vb=(Vcc*((rs*R2)/(rs+R2))/(R1+((rs*R2)/(rs+R2))))\n",
- "\n",
- "#Results\n",
- "print(\"base bais voltage is %3.2fV \" %Vb)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "with no signal source\n",
- " base bais voltage when no signal source is present 3.75V \n",
- " signal source directly connected\n",
- "base bais voltage is 0.21V \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.2, Page No 244"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Rc=2.2*10**3\n",
- "Re=2.7*10**3\n",
- "R1=18.0*10**3\n",
- "R2=8.2*10**3\n",
- "Vbe=.7\n",
- "\n",
- "#Calculations\n",
- "print(\"drawing dc load line\")\n",
- "Rldc=Rc+Re\n",
- "print(\" for Vce\")\n",
- "Ic=0\n",
- "Vcc=20\n",
- "Vce=Vcc-Ic*(Rc+Re)\n",
- "print(\"plot point A at\")\n",
- "Ic=Vcc/(Rc+Re)\n",
- "print(\"plot point B Ic=4.08mA and Vce=0\")\n",
- "print(\" draw dc laod line through point A nad B\")\n",
- "Vb=(Vcc*R2)/(R1+R2)\n",
- "Ve=Vb-Vbe\n",
- "Ic=Ve/Re\n",
- "Ie=Ic\n",
- "print(\"drawing the ac load line\")\n",
- "Rlac=Rc#when there is no external Rl\n",
- "Vce=Ic*Rc\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\"The voltage is %.2f v \" %Vce)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "drawing dc load line\n",
- " for Vce\n",
- "plot point A at\n",
- "plot point B Ic=4.08mA and Vce=0\n",
- " draw dc laod line through point A nad B\n",
- "drawing the ac load line\n",
- "The voltage is 4.53 v \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.3 Page No 251"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=4.5\n",
- "Ib=40.0*10**-6\n",
- "\n",
- "#Calculations\n",
- "print(\"from current characteristic at Vce=4.5V and Ib=40uA\")\n",
- "Ic=4.0*10**-3\n",
- "Ib=30.0*10**-6\n",
- "hFE=Ic/Ib\n",
- "print(\" the value of hFE is %d \" %hFE)\n",
- "print(\"from output characteristic at Vce=4.5 and Ib=40uA\")\n",
- "Ic=0.2\n",
- "Vce=6\n",
- "hoe=(Ic/Vce)\n",
- "R=1/hoe\n",
- "\n",
- "#Results\n",
- "print(\"the value of hoe is %3.1fuS \" %(hoe*10**3))\n",
- "print(\"the value of 1/hoe is %3.1fuS \" %(1/hoe))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "from current characteristic at Vce=4.5V and Ib=40uA\n",
- " the value of hFE is 133 \n",
- "from output characteristic at Vce=4.5 and Ib=40uA\n",
- "the value of hoe is 33.3uS \n",
- "the value of 1/hoe is 30.0uS \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.4, Page No 253"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hfe=133.0\n",
- "hoe=33.3*10**-6\n",
- "hfc=1+hfe\n",
- "\n",
- "#Calculations\n",
- "hob=hoe/(1+hfe)\n",
- "A=hfe/(1+hfe)\n",
- "\n",
- "#Results\n",
- "print(\"tye value of a is %3.1fuS \" %(A))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "tye value of a is 1.0uS \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.5 Page No 253"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=20.0*10**-6\n",
- "Ic=1.0*10**-3\n",
- "Ie=Ic\n",
- "\n",
- "#Calculations\n",
- "re=(26*10**-3)/Ie\n",
- "hfe=Ic/Ib\n",
- "hie=(1+hfe)*re\n",
- "r=hie\n",
- "B=hfe\n",
- "\n",
- "#Results\n",
- "print(\"the value of b is %3.1f \" %(B))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "the value of b is 50.0 \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.6 Page No 258"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "hoe=1*10**-6\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" input impedance Zi=R1||R2||hie\")\n",
- "Zi=((R1*R2*hie)/(R1+R2+hie))*10**-3\n",
- "print(\" input impedance is %3.2fKohm \" %Zi)\n",
- "print(\"output impedance is Zo=Rc||(1/hoe)\")\n",
- "Zo=((Rc*(1/hoe))/(Rc+(1/hoe)))*10**-3\n",
- "print(\" output impadance is %f3.2fKohm \" %Zo)\n",
- "Av=-(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %d \" %Av)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input impedance Zi=R1||R2||hie\n",
- " input impedance is 63416.34Kohm \n",
- "output impedance is Zo=Rc||(1/hoe)\n",
- " output impadance is 3.8848493.2fKohm \n",
- " voltage gain is -132 \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.7, Page No 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Ic=1.5*10**-3\n",
- "Rc=4.7*10**3\n",
- "Rl=56.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "re=(26*10**-3)/Ie\n",
- "Av=-(((Rc*Rl)/(Rc+Rl))/re)\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %d \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " voltage gain is -250 \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.8 Page No 262"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "hoe=1.0*10**-6\n",
- "Re=4.7*10**3\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Zb=hie+Re*(1+hfe)\n",
- "print(\" input impedance is Zi=R1||R2||Zb\")\n",
- "Zi=((R1*R2*Zb)/(R1+R2+Zb))\n",
- "print(\" input circuit resistance is %3.3fKohm \" %Zi)\n",
- "Zo=Rc\n",
- "Av=-hfe*((Rc*Rl)/(Rc+Rl))/(hie+Re*(1+hfe))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input impedance is Zi=R1||R2||Zb\n",
- " input circuit resistance is 2830983654.045Kohm \n",
- "voltage gain is -0.777 \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.9 Page No 267"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "R1=10.0*10**3\n",
- "R2=10.0*10**3\n",
- "Re=4.7*10**3\n",
- "Rl=12.0*10**3\n",
- "rs=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" Rl is not connected\")\n",
- "hic=hie\n",
- "hfc=1+hfe\n",
- "Zb=hic+hfc*(Re)\n",
- "Zi=(R1*R2*Zb)/(R1+R2+Zb)\n",
- "Ze=(hic+(R1*R2*rs)/(R1+R2+rs))/hfc\n",
- "Z0=(Ze*Re)/(Ze+Re)\n",
- "print(\" when Rl is connected\")\n",
- "Zb=hic+hfc*((Re*Rl)/(Re+Rl))\n",
- "Zi=(R1*R2*Zb)/(R1+R2+Zb)\n",
- "hib=hie/(1+hfe)\n",
- "Av=((Re*Rl)/(Re+Rl))/(hib+((Re*Rl)/(Re+Rl)))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Rl is not connected\n",
- " when Rl is connected\n",
- "voltage gain is 0.992 \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.10 Page No 273"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hie=2.1*10**3\n",
- "hfe=75.0\n",
- "Re=4.7*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "hib=hie/(1+hfe)\n",
- "hfb=hfe/(1+hfe)\n",
- "Zi=(hib*Re)/(Re+hib)\n",
- "print(\"input impedance is %3.2fohm \" %Zi)\n",
- "Zo=Rc\n",
- "print(\" output impedance is %3.2fohm \" %Zo)\n",
- "Av=(hfb*((Rc*Rl)/(Rc+Rl)))/hib\n",
- "\n",
- "#Results\n",
- "print(\" voltage gain is %3.2f \" %Av)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "input impedance is 27.47ohm \n",
- " output impedance is 3900.00ohm \n",
- " voltage gain is 132.96 \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.11, Page No 273"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "hib=27.6\n",
- "hfb=.987\n",
- "R1=68.0*10**3\n",
- "R2=56.0*10**3\n",
- "Re=4.7*10**3\n",
- "Rc=3.9*10**3\n",
- "Rl=82.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Ze=hib+Rb*(1-hfb)\n",
- "Zi=(Ze*Re)/(Ze+Re)\n",
- "Av=(hfb*((Rc*Rl)/(Rc+Rl)))/(hib+Rb*(1-hfb))\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %Av)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain is 8.609 \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.12, Page No 277"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Rc=5.6*10**3\n",
- "Rl=33.0*10**3\n",
- "rs=600.0\n",
- "hfe=100\n",
- "hie=1.5*10**3\n",
- "vs=50.0*10**-3\n",
- "\n",
- "#Calculations\n",
- "print(\" CE circuit operation with vs at transistor base and Re bypassed\")\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Zb=hie\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Zi=(Rb*Zb)/(Rb+Zb)\n",
- "vi=(vs*Zi)/(rs+Zi)\n",
- "vo=Av*vi\n",
- "print(\"Cb circuit operation with vs at emitter and the base resistor bypassed\")\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Ze=hie/(1+hfe)\n",
- "Zi=(Ze*Re)/(Ze+Re)\n",
- "vi=(vs*Zi)/(rs+Zi)\n",
- "vo=Av*vi\n",
- "\n",
- "#Results\n",
- "print(\"voltage vo is %3.2f \" %(vo*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " CE circuit operation with vs at transistor base and Re bypassed\n",
- "Cb circuit operation with vs at emitter and the base resistor bypassed\n",
- "voltage vo is 384.29 \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6.13, Page No 279"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Io=50.0*10**-9\n",
- "Vbe=.7\n",
- "Vbc=-10\n",
- "Af=.995\n",
- "Ar=.5\n",
- "Vt=26.0*10**-3\n",
- "n=2.0\n",
- "Vd=-10.0\n",
- "\n",
- "#Calculations\n",
- "x=Vd/(n*Vt)\n",
- "Idc=(Io*((2.73**-x)-1))*10**9\n",
- "Idc=Io*(-1)\n",
- "y=Vbe/(n*Vt)\n",
- "Ide=Io*((2.73**y)-1)\n",
- "I1=Af*Ide\n",
- "I2=Ar*Idc\n",
- "Ic=I1-Idc\n",
- "Ie=Ide-I2\n",
- "Ib=Ie-Ic\n",
- "\n",
- "#Results\n",
- "print(\"voltage gain is %3.3f \" %(Ib*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain is 185.909 \n"
- ]
- }
- ],
- "prompt_number": 13
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter8.ipynb b/Electronic_Devices_and_Circuits/Chapter8.ipynb deleted file mode 100755 index d91fc639..00000000 --- a/Electronic_Devices_and_Circuits/Chapter8.ipynb +++ /dev/null @@ -1,499 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 08 : BJT specifications and performance"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.2, Page No 313"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "P2=25.0*10**-3#when frequency increase to 20KHz\n",
- "P1=50.0*10**-3#when signal frequency is 5KHz\n",
- "\n",
- "#Calculations\n",
- "Po=10*math.log((P2/P1),10)\n",
- "\n",
- "#Results\n",
- "print(\" output power change in decibels is %.2f dB \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " output power change in decibels is -3.01 dB \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.3, Page No 314"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "v1=1# output voltage measured at 5KHz\n",
- "v2=.707# output voltage measure at 20kHz\n",
- "\n",
- "#Calculations\n",
- "Po=20*math.log((v2/v1),10)\n",
- "\n",
- "#Results\n",
- "print(\" output power change is %.2f dB \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " output power change is -3.01 dB \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.4 Page No 317"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ic=1.0*10**-3\n",
- "hfe=50.0\n",
- "hie=1.3*10**3\n",
- "fT=250.0*10**6\n",
- "Cbc=5.0*10**-12\n",
- "Rc=8.2*10**3\n",
- "Rl=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Cbe=(6.1*Ie)/fT\n",
- "Cin=(Cbe+(1+Av)*Cbc)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" input capacitance when the circuit operated as CE is %.2fnF \"%Cin)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input capacitance when the circuit operated as CE is 1.49nF \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.5, Page No 319"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=100*10**3\n",
- "R2=47.0*10**3\n",
- "Re=4.7*10**3\n",
- "Cbc=5.0*10**-12\n",
- "Cbe=24.4*10**-12\n",
- "hfe=50\n",
- "hie=1.3*10**3\n",
- "hib=24.5\n",
- "rs=hib\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "print(\" common emitter circuit\")\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Zi=(Rb*hie)/(Rb+hie)\n",
- "Cin=1.48*10**-9\n",
- "f2=1/(2*3.14*Cin*((rs*Zi)/(rs+Zi)))\n",
- "print(\"input-capacitance upper cutoff frequency is %dHz \" %f2)\n",
- "print(\"common base circuit\")\n",
- "Zi=(Re*hib)/(Re+hib)\n",
- "Cin=(Cbe+Cbc)\n",
- "f2=(1/(2*3.14*Cin*((rs*Zi)/(rs+Zi))))*10**-6\n",
- "\n",
- "#Results\n",
- "print(\" input capacitance upper cutoff when operating as CB circuit with base bypassed to ground is %.2f MHz \" %f2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " common emitter circuit\n",
- "input-capacitance upper cutoff frequency is 265447Hz \n",
- "common base circuit\n",
- " input capacitance upper cutoff when operating as CB circuit with base bypassed to ground is 231.25 MHz \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.6 Page No 322"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "fT=50.0*10**6\n",
- "hfe=50.0\n",
- "f2o=60.0*10**3\n",
- "Rc=10.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fae=fT/hfe\n",
- "C4=(1.0/(2*3.14*f2o*Rc))*10**12\n",
- "\n",
- "#Results\n",
- "print(\"capacitance required for C4 to give 60kHz upper cutoff frequency is %.2f pF \" %C4)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "capacitance required for C4 to give 60kHz upper cutoff frequency is 265.39 pF \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.8 Page No 326"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "ton=100.0*10**-9\n",
- "Rs=600.0\n",
- "Rb=4.7*10**3\n",
- "\n",
- "#Calculations\n",
- "C1=(ton/Rs)*10**12\n",
- "print(\" suitable speed up capacitor is %dpF \" %C1)\n",
- "C1=160*10**-12#standard value\n",
- "PWmin=(5*Rs*C1)\n",
- "SWmin=5*Rb*C1\n",
- "fmax=1/(PWmin+SWmin)\n",
- "\n",
- "#Results\n",
- "print(\"maximum signal frequency is %.2f Hz \" %(fmax/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable speed up capacitor is 166pF \n",
- "maximum signal frequency is 235.85 Hz \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.9, Page No 330"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=30.0*10**3\n",
- "R2=30.0*10**3\n",
- "rs=30.0*10**3\n",
- "f2=40.0*10**3\n",
- "f1=100.0\n",
- "k=1.37*10**-23\n",
- "R=10.0*10**3\n",
- "Av=600.0\n",
- "Ri=3.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Rg=(rs*Rb)/(rs+Rb)\n",
- "T=(273+25)\n",
- "B=f2-f1\n",
- "en=math.sqrt(4*k*T*B*R)\n",
- "eni=en*((Ri/(Ri+Rg)))\n",
- "eno=(Av*eni)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"noise output voltage is %.2f uV \" %eno)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "noise output voltage is 353.44 uV \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.10 Page No 331"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Ic=30.0*10**-6\n",
- "Vce=5.0\n",
- "eno=354.0*10**-6\n",
- "NF=10.0\n",
- "F=2.51#F=antilog(NF/10)\n",
- "\n",
- "#Calculations\n",
- "Vn=((math.sqrt(F))*eno)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"total noise output volateg for amplifier is %.2f uV \" %Vn)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "total noise output volateg for amplifier is 560.84 uV \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.11 Page No 333"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Pd25=625.0*10**-3\n",
- "D=5.0*10**-3\n",
- "Vce=10.0\n",
- "T2=55.0\n",
- "\n",
- "#Calculations\n",
- "Pdt2=Pd25-D*(T2-25)\n",
- "Pd=Pdt2\n",
- "Ic=Pd/Vce\n",
- "\n",
- "#Results\n",
- "print(\" maximum Ic level is %.2fA \" %(Ic*1000))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum Ic level is 47.50A \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.13 Page No 335"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Pd=80.0\n",
- "Vce=60.0\n",
- "\n",
- "#Calculations\n",
- "Ic=Pd/Vce\n",
- "print(\"point 1 Vce=60 and Ic= %.2f A\" %Ic)\n",
- "Vce=40.0\n",
- "Ic=Pd/Vce\n",
- "print(\"point 2 Vce=40 and Ic= %.2f A\" %Ic)\n",
- "Vce=20.0\n",
- "Ic=Pd/Vce\n",
- "print(\" point 3 Vce=20 and Ic= %.2f A\" %Ic)\n",
- "Vce=10.0\n",
- "Ic=Pd/Vce\n",
- "\n",
- "#Results\n",
- "print(\" point 4 Vce=10 and Ic= %.2f A\" %Ic)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "point 1 Vce=60 and Ic= 1.33 A\n",
- "point 2 Vce=40 and Ic= 2.00 A\n",
- " point 3 Vce=20 and Ic= 4.00 A\n",
- " point 4 Vce=10 and Ic= 8.00 A\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.14, Page No 339"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=20.0\n",
- "Ic=1.0\n",
- "T2=90.0\n",
- "T1=25.0\n",
- "\n",
- "#Calculations\n",
- "Q=Vce*Ic\n",
- "Qcs=.4\n",
- "Qjc=1#from table\n",
- "Qsa=((T2-T1)/Q)-(Qjc+Qcs)\n",
- "\n",
- "#Results\n",
- "print(\"Qsa= %.2f \" %Qsa)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Qsa= 1.85 \n"
- ]
- }
- ],
- "prompt_number": 11
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter8_1.ipynb b/Electronic_Devices_and_Circuits/Chapter8_1.ipynb deleted file mode 100755 index d91fc639..00000000 --- a/Electronic_Devices_and_Circuits/Chapter8_1.ipynb +++ /dev/null @@ -1,499 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 08 : BJT specifications and performance"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.2, Page No 313"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "P2=25.0*10**-3#when frequency increase to 20KHz\n",
- "P1=50.0*10**-3#when signal frequency is 5KHz\n",
- "\n",
- "#Calculations\n",
- "Po=10*math.log((P2/P1),10)\n",
- "\n",
- "#Results\n",
- "print(\" output power change in decibels is %.2f dB \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " output power change in decibels is -3.01 dB \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.3, Page No 314"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "v1=1# output voltage measured at 5KHz\n",
- "v2=.707# output voltage measure at 20kHz\n",
- "\n",
- "#Calculations\n",
- "Po=20*math.log((v2/v1),10)\n",
- "\n",
- "#Results\n",
- "print(\" output power change is %.2f dB \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " output power change is -3.01 dB \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.4 Page No 317"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ic=1.0*10**-3\n",
- "hfe=50.0\n",
- "hie=1.3*10**3\n",
- "fT=250.0*10**6\n",
- "Cbc=5.0*10**-12\n",
- "Rc=8.2*10**3\n",
- "Rl=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Cbe=(6.1*Ie)/fT\n",
- "Cin=(Cbe+(1+Av)*Cbc)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" input capacitance when the circuit operated as CE is %.2fnF \"%Cin)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input capacitance when the circuit operated as CE is 1.49nF \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.5, Page No 319"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=100*10**3\n",
- "R2=47.0*10**3\n",
- "Re=4.7*10**3\n",
- "Cbc=5.0*10**-12\n",
- "Cbe=24.4*10**-12\n",
- "hfe=50\n",
- "hie=1.3*10**3\n",
- "hib=24.5\n",
- "rs=hib\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "print(\" common emitter circuit\")\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Zi=(Rb*hie)/(Rb+hie)\n",
- "Cin=1.48*10**-9\n",
- "f2=1/(2*3.14*Cin*((rs*Zi)/(rs+Zi)))\n",
- "print(\"input-capacitance upper cutoff frequency is %dHz \" %f2)\n",
- "print(\"common base circuit\")\n",
- "Zi=(Re*hib)/(Re+hib)\n",
- "Cin=(Cbe+Cbc)\n",
- "f2=(1/(2*3.14*Cin*((rs*Zi)/(rs+Zi))))*10**-6\n",
- "\n",
- "#Results\n",
- "print(\" input capacitance upper cutoff when operating as CB circuit with base bypassed to ground is %.2f MHz \" %f2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " common emitter circuit\n",
- "input-capacitance upper cutoff frequency is 265447Hz \n",
- "common base circuit\n",
- " input capacitance upper cutoff when operating as CB circuit with base bypassed to ground is 231.25 MHz \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.6 Page No 322"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "fT=50.0*10**6\n",
- "hfe=50.0\n",
- "f2o=60.0*10**3\n",
- "Rc=10.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fae=fT/hfe\n",
- "C4=(1.0/(2*3.14*f2o*Rc))*10**12\n",
- "\n",
- "#Results\n",
- "print(\"capacitance required for C4 to give 60kHz upper cutoff frequency is %.2f pF \" %C4)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "capacitance required for C4 to give 60kHz upper cutoff frequency is 265.39 pF \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.8 Page No 326"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "ton=100.0*10**-9\n",
- "Rs=600.0\n",
- "Rb=4.7*10**3\n",
- "\n",
- "#Calculations\n",
- "C1=(ton/Rs)*10**12\n",
- "print(\" suitable speed up capacitor is %dpF \" %C1)\n",
- "C1=160*10**-12#standard value\n",
- "PWmin=(5*Rs*C1)\n",
- "SWmin=5*Rb*C1\n",
- "fmax=1/(PWmin+SWmin)\n",
- "\n",
- "#Results\n",
- "print(\"maximum signal frequency is %.2f Hz \" %(fmax/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable speed up capacitor is 166pF \n",
- "maximum signal frequency is 235.85 Hz \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.9, Page No 330"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=30.0*10**3\n",
- "R2=30.0*10**3\n",
- "rs=30.0*10**3\n",
- "f2=40.0*10**3\n",
- "f1=100.0\n",
- "k=1.37*10**-23\n",
- "R=10.0*10**3\n",
- "Av=600.0\n",
- "Ri=3.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Rg=(rs*Rb)/(rs+Rb)\n",
- "T=(273+25)\n",
- "B=f2-f1\n",
- "en=math.sqrt(4*k*T*B*R)\n",
- "eni=en*((Ri/(Ri+Rg)))\n",
- "eno=(Av*eni)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"noise output voltage is %.2f uV \" %eno)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "noise output voltage is 353.44 uV \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.10 Page No 331"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Ic=30.0*10**-6\n",
- "Vce=5.0\n",
- "eno=354.0*10**-6\n",
- "NF=10.0\n",
- "F=2.51#F=antilog(NF/10)\n",
- "\n",
- "#Calculations\n",
- "Vn=((math.sqrt(F))*eno)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"total noise output volateg for amplifier is %.2f uV \" %Vn)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "total noise output volateg for amplifier is 560.84 uV \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.11 Page No 333"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Pd25=625.0*10**-3\n",
- "D=5.0*10**-3\n",
- "Vce=10.0\n",
- "T2=55.0\n",
- "\n",
- "#Calculations\n",
- "Pdt2=Pd25-D*(T2-25)\n",
- "Pd=Pdt2\n",
- "Ic=Pd/Vce\n",
- "\n",
- "#Results\n",
- "print(\" maximum Ic level is %.2fA \" %(Ic*1000))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum Ic level is 47.50A \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.13 Page No 335"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Pd=80.0\n",
- "Vce=60.0\n",
- "\n",
- "#Calculations\n",
- "Ic=Pd/Vce\n",
- "print(\"point 1 Vce=60 and Ic= %.2f A\" %Ic)\n",
- "Vce=40.0\n",
- "Ic=Pd/Vce\n",
- "print(\"point 2 Vce=40 and Ic= %.2f A\" %Ic)\n",
- "Vce=20.0\n",
- "Ic=Pd/Vce\n",
- "print(\" point 3 Vce=20 and Ic= %.2f A\" %Ic)\n",
- "Vce=10.0\n",
- "Ic=Pd/Vce\n",
- "\n",
- "#Results\n",
- "print(\" point 4 Vce=10 and Ic= %.2f A\" %Ic)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "point 1 Vce=60 and Ic= 1.33 A\n",
- "point 2 Vce=40 and Ic= 2.00 A\n",
- " point 3 Vce=20 and Ic= 4.00 A\n",
- " point 4 Vce=10 and Ic= 8.00 A\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.14, Page No 339"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=20.0\n",
- "Ic=1.0\n",
- "T2=90.0\n",
- "T1=25.0\n",
- "\n",
- "#Calculations\n",
- "Q=Vce*Ic\n",
- "Qcs=.4\n",
- "Qjc=1#from table\n",
- "Qsa=((T2-T1)/Q)-(Qjc+Qcs)\n",
- "\n",
- "#Results\n",
- "print(\"Qsa= %.2f \" %Qsa)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Qsa= 1.85 \n"
- ]
- }
- ],
- "prompt_number": 11
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/Chapter8_2.ipynb b/Electronic_Devices_and_Circuits/Chapter8_2.ipynb deleted file mode 100755 index d91fc639..00000000 --- a/Electronic_Devices_and_Circuits/Chapter8_2.ipynb +++ /dev/null @@ -1,499 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 08 : BJT specifications and performance"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.2, Page No 313"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "P2=25.0*10**-3#when frequency increase to 20KHz\n",
- "P1=50.0*10**-3#when signal frequency is 5KHz\n",
- "\n",
- "#Calculations\n",
- "Po=10*math.log((P2/P1),10)\n",
- "\n",
- "#Results\n",
- "print(\" output power change in decibels is %.2f dB \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " output power change in decibels is -3.01 dB \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.3, Page No 314"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "v1=1# output voltage measured at 5KHz\n",
- "v2=.707# output voltage measure at 20kHz\n",
- "\n",
- "#Calculations\n",
- "Po=20*math.log((v2/v1),10)\n",
- "\n",
- "#Results\n",
- "print(\" output power change is %.2f dB \" %Po)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " output power change is -3.01 dB \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.4 Page No 317"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Ic=1.0*10**-3\n",
- "hfe=50.0\n",
- "hie=1.3*10**3\n",
- "fT=250.0*10**6\n",
- "Cbc=5.0*10**-12\n",
- "Rc=8.2*10**3\n",
- "Rl=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Ie=Ic\n",
- "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
- "Cbe=(6.1*Ie)/fT\n",
- "Cin=(Cbe+(1+Av)*Cbc)*10**9\n",
- "\n",
- "#Results\n",
- "print(\" input capacitance when the circuit operated as CE is %.2fnF \"%Cin)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " input capacitance when the circuit operated as CE is 1.49nF \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.5, Page No 319"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=100*10**3\n",
- "R2=47.0*10**3\n",
- "Re=4.7*10**3\n",
- "Cbc=5.0*10**-12\n",
- "Cbe=24.4*10**-12\n",
- "hfe=50\n",
- "hie=1.3*10**3\n",
- "hib=24.5\n",
- "rs=hib\n",
- "rs=600.0\n",
- "\n",
- "#Calculations\n",
- "print(\" common emitter circuit\")\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Zi=(Rb*hie)/(Rb+hie)\n",
- "Cin=1.48*10**-9\n",
- "f2=1/(2*3.14*Cin*((rs*Zi)/(rs+Zi)))\n",
- "print(\"input-capacitance upper cutoff frequency is %dHz \" %f2)\n",
- "print(\"common base circuit\")\n",
- "Zi=(Re*hib)/(Re+hib)\n",
- "Cin=(Cbe+Cbc)\n",
- "f2=(1/(2*3.14*Cin*((rs*Zi)/(rs+Zi))))*10**-6\n",
- "\n",
- "#Results\n",
- "print(\" input capacitance upper cutoff when operating as CB circuit with base bypassed to ground is %.2f MHz \" %f2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " common emitter circuit\n",
- "input-capacitance upper cutoff frequency is 265447Hz \n",
- "common base circuit\n",
- " input capacitance upper cutoff when operating as CB circuit with base bypassed to ground is 231.25 MHz \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.6 Page No 322"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "fT=50.0*10**6\n",
- "hfe=50.0\n",
- "f2o=60.0*10**3\n",
- "Rc=10.0*10**3\n",
- "\n",
- "#Calculations\n",
- "fae=fT/hfe\n",
- "C4=(1.0/(2*3.14*f2o*Rc))*10**12\n",
- "\n",
- "#Results\n",
- "print(\"capacitance required for C4 to give 60kHz upper cutoff frequency is %.2f pF \" %C4)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "capacitance required for C4 to give 60kHz upper cutoff frequency is 265.39 pF \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.8 Page No 326"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "ton=100.0*10**-9\n",
- "Rs=600.0\n",
- "Rb=4.7*10**3\n",
- "\n",
- "#Calculations\n",
- "C1=(ton/Rs)*10**12\n",
- "print(\" suitable speed up capacitor is %dpF \" %C1)\n",
- "C1=160*10**-12#standard value\n",
- "PWmin=(5*Rs*C1)\n",
- "SWmin=5*Rb*C1\n",
- "fmax=1/(PWmin+SWmin)\n",
- "\n",
- "#Results\n",
- "print(\"maximum signal frequency is %.2f Hz \" %(fmax/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable speed up capacitor is 166pF \n",
- "maximum signal frequency is 235.85 Hz \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.9, Page No 330"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "R1=30.0*10**3\n",
- "R2=30.0*10**3\n",
- "rs=30.0*10**3\n",
- "f2=40.0*10**3\n",
- "f1=100.0\n",
- "k=1.37*10**-23\n",
- "R=10.0*10**3\n",
- "Av=600.0\n",
- "Ri=3.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Rb=(R1*R2)/(R1+R2)\n",
- "Rg=(rs*Rb)/(rs+Rb)\n",
- "T=(273+25)\n",
- "B=f2-f1\n",
- "en=math.sqrt(4*k*T*B*R)\n",
- "eni=en*((Ri/(Ri+Rg)))\n",
- "eno=(Av*eni)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"noise output voltage is %.2f uV \" %eno)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "noise output voltage is 353.44 uV \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.10 Page No 331"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "Ic=30.0*10**-6\n",
- "Vce=5.0\n",
- "eno=354.0*10**-6\n",
- "NF=10.0\n",
- "F=2.51#F=antilog(NF/10)\n",
- "\n",
- "#Calculations\n",
- "Vn=((math.sqrt(F))*eno)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"total noise output volateg for amplifier is %.2f uV \" %Vn)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "total noise output volateg for amplifier is 560.84 uV \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.11 Page No 333"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Pd25=625.0*10**-3\n",
- "D=5.0*10**-3\n",
- "Vce=10.0\n",
- "T2=55.0\n",
- "\n",
- "#Calculations\n",
- "Pdt2=Pd25-D*(T2-25)\n",
- "Pd=Pdt2\n",
- "Ic=Pd/Vce\n",
- "\n",
- "#Results\n",
- "print(\" maximum Ic level is %.2fA \" %(Ic*1000))\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " maximum Ic level is 47.50A \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.13 Page No 335"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Pd=80.0\n",
- "Vce=60.0\n",
- "\n",
- "#Calculations\n",
- "Ic=Pd/Vce\n",
- "print(\"point 1 Vce=60 and Ic= %.2f A\" %Ic)\n",
- "Vce=40.0\n",
- "Ic=Pd/Vce\n",
- "print(\"point 2 Vce=40 and Ic= %.2f A\" %Ic)\n",
- "Vce=20.0\n",
- "Ic=Pd/Vce\n",
- "print(\" point 3 Vce=20 and Ic= %.2f A\" %Ic)\n",
- "Vce=10.0\n",
- "Ic=Pd/Vce\n",
- "\n",
- "#Results\n",
- "print(\" point 4 Vce=10 and Ic= %.2f A\" %Ic)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "point 1 Vce=60 and Ic= 1.33 A\n",
- "point 2 Vce=40 and Ic= 2.00 A\n",
- " point 3 Vce=20 and Ic= 4.00 A\n",
- " point 4 Vce=10 and Ic= 8.00 A\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.14, Page No 339"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "Vce=20.0\n",
- "Ic=1.0\n",
- "T2=90.0\n",
- "T1=25.0\n",
- "\n",
- "#Calculations\n",
- "Q=Vce*Ic\n",
- "Qcs=.4\n",
- "Qjc=1#from table\n",
- "Qsa=((T2-T1)/Q)-(Qjc+Qcs)\n",
- "\n",
- "#Results\n",
- "print(\"Qsa= %.2f \" %Qsa)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Qsa= 1.85 \n"
- ]
- }
- ],
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\ No newline at end of file diff --git a/Electronic_Devices_and_Circuits/README.txt b/Electronic_Devices_and_Circuits/README.txt deleted file mode 100755 index 005586a5..00000000 --- a/Electronic_Devices_and_Circuits/README.txt +++ /dev/null @@ -1,10 +0,0 @@ -Contributed By: Mayur Sabban -Course: be -College/Institute/Organization: Vishwakarma Institute of Technology Pune -Department/Designation: Computer Engg -Book Title: Electronic Devices and Circuits -Author: David A. Bell -Publisher: Oxford University Press(2008), -Year of publication: 2008 -Isbn: 019569340 -Edition: 5
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