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diff --git a/Electronic_Devices_and_Circuits/Chapter6_2.ipynb b/Electronic_Devices_and_Circuits/Chapter6_2.ipynb new file mode 100755 index 00000000..85bada6c --- /dev/null +++ b/Electronic_Devices_and_Circuits/Chapter6_2.ipynb @@ -0,0 +1,656 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 06 : Ac analysis of BJT circuits"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.1, Page No 240"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Vcc=12.0\n",
+ "R2=15.0*10**3\n",
+ "R1=33.0*10**3\n",
+ "rs=600\n",
+ "\n",
+ "#Calculations\n",
+ "print(\"with no signal source\")\n",
+ "Vb=(Vcc*R2)/(R1+R2)\n",
+ "print(\" base bais voltage when no signal source is present %3.2fV \" %Vb)\n",
+ "print(\" signal source directly connected\")\n",
+ "Vb=(Vcc*((rs*R2)/(rs+R2))/(R1+((rs*R2)/(rs+R2))))\n",
+ "\n",
+ "#Results\n",
+ "print(\"base bais voltage is %3.2fV \" %Vb)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "with no signal source\n",
+ " base bais voltage when no signal source is present 3.75V \n",
+ " signal source directly connected\n",
+ "base bais voltage is 0.21V \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.2, Page No 244"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Rc=2.2*10**3\n",
+ "Re=2.7*10**3\n",
+ "R1=18.0*10**3\n",
+ "R2=8.2*10**3\n",
+ "Vbe=.7\n",
+ "\n",
+ "#Calculations\n",
+ "print(\"drawing dc load line\")\n",
+ "Rldc=Rc+Re\n",
+ "print(\" for Vce\")\n",
+ "Ic=0\n",
+ "Vcc=20\n",
+ "Vce=Vcc-Ic*(Rc+Re)\n",
+ "print(\"plot point A at\")\n",
+ "Ic=Vcc/(Rc+Re)\n",
+ "print(\"plot point B Ic=4.08mA and Vce=0\")\n",
+ "print(\" draw dc laod line through point A nad B\")\n",
+ "Vb=(Vcc*R2)/(R1+R2)\n",
+ "Ve=Vb-Vbe\n",
+ "Ic=Ve/Re\n",
+ "Ie=Ic\n",
+ "print(\"drawing the ac load line\")\n",
+ "Rlac=Rc#when there is no external Rl\n",
+ "Vce=Ic*Rc\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print(\"The voltage is %.2f v \" %Vce)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "drawing dc load line\n",
+ " for Vce\n",
+ "plot point A at\n",
+ "plot point B Ic=4.08mA and Vce=0\n",
+ " draw dc laod line through point A nad B\n",
+ "drawing the ac load line\n",
+ "The voltage is 4.53 v \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.3 Page No 251"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "Vce=4.5\n",
+ "Ib=40.0*10**-6\n",
+ "\n",
+ "#Calculations\n",
+ "print(\"from current characteristic at Vce=4.5V and Ib=40uA\")\n",
+ "Ic=4.0*10**-3\n",
+ "Ib=30.0*10**-6\n",
+ "hFE=Ic/Ib\n",
+ "print(\" the value of hFE is %d \" %hFE)\n",
+ "print(\"from output characteristic at Vce=4.5 and Ib=40uA\")\n",
+ "Ic=0.2\n",
+ "Vce=6\n",
+ "hoe=(Ic/Vce)\n",
+ "R=1/hoe\n",
+ "\n",
+ "#Results\n",
+ "print(\"the value of hoe is %3.1fuS \" %(hoe*10**3))\n",
+ "print(\"the value of 1/hoe is %3.1fuS \" %(1/hoe))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "from current characteristic at Vce=4.5V and Ib=40uA\n",
+ " the value of hFE is 133 \n",
+ "from output characteristic at Vce=4.5 and Ib=40uA\n",
+ "the value of hoe is 33.3uS \n",
+ "the value of 1/hoe is 30.0uS \n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.4, Page No 253"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "hfe=133.0\n",
+ "hoe=33.3*10**-6\n",
+ "hfc=1+hfe\n",
+ "\n",
+ "#Calculations\n",
+ "hob=hoe/(1+hfe)\n",
+ "A=hfe/(1+hfe)\n",
+ "\n",
+ "#Results\n",
+ "print(\"tye value of a is %3.1fuS \" %(A))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "tye value of a is 1.0uS \n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.5 Page No 253"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Ib=20.0*10**-6\n",
+ "Ic=1.0*10**-3\n",
+ "Ie=Ic\n",
+ "\n",
+ "#Calculations\n",
+ "re=(26*10**-3)/Ie\n",
+ "hfe=Ic/Ib\n",
+ "hie=(1+hfe)*re\n",
+ "r=hie\n",
+ "B=hfe\n",
+ "\n",
+ "#Results\n",
+ "print(\"the value of b is %3.1f \" %(B))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "the value of b is 50.0 \n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.6 Page No 258"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "hie=2.1*10**3\n",
+ "hfe=75.0\n",
+ "hoe=1*10**-6\n",
+ "R1=68.0*10**3\n",
+ "R2=56.0*10**3\n",
+ "Rc=3.9*10**3\n",
+ "Rl=82*10**3\n",
+ "\n",
+ "#Calculations\n",
+ "print(\" input impedance Zi=R1||R2||hie\")\n",
+ "Zi=((R1*R2*hie)/(R1+R2+hie))*10**-3\n",
+ "print(\" input impedance is %3.2fKohm \" %Zi)\n",
+ "print(\"output impedance is Zo=Rc||(1/hoe)\")\n",
+ "Zo=((Rc*(1/hoe))/(Rc+(1/hoe)))*10**-3\n",
+ "print(\" output impadance is %f3.2fKohm \" %Zo)\n",
+ "Av=-(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print(\" voltage gain is %d \" %Av)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " input impedance Zi=R1||R2||hie\n",
+ " input impedance is 63416.34Kohm \n",
+ "output impedance is Zo=Rc||(1/hoe)\n",
+ " output impadance is 3.8848493.2fKohm \n",
+ " voltage gain is -132 \n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.7, Page No 259"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Ic=1.5*10**-3\n",
+ "Rc=4.7*10**3\n",
+ "Rl=56.0*10**3\n",
+ "\n",
+ "#Calculations\n",
+ "Ie=Ic\n",
+ "re=(26*10**-3)/Ie\n",
+ "Av=-(((Rc*Rl)/(Rc+Rl))/re)\n",
+ "\n",
+ "#Results\n",
+ "print(\" voltage gain is %d \" %Av)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " voltage gain is -250 \n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.8 Page No 262"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "#initialisation of variables\n",
+ "hie=2.1*10**3\n",
+ "hfe=75.0\n",
+ "hoe=1.0*10**-6\n",
+ "Re=4.7*10**3\n",
+ "R1=68.0*10**3\n",
+ "R2=56.0*10**3\n",
+ "Rc=3.9*10**3\n",
+ "Rl=82.0*10**3\n",
+ "\n",
+ "#Calculations\n",
+ "Zb=hie+Re*(1+hfe)\n",
+ "print(\" input impedance is Zi=R1||R2||Zb\")\n",
+ "Zi=((R1*R2*Zb)/(R1+R2+Zb))\n",
+ "print(\" input circuit resistance is %3.3fKohm \" %Zi)\n",
+ "Zo=Rc\n",
+ "Av=-hfe*((Rc*Rl)/(Rc+Rl))/(hie+Re*(1+hfe))\n",
+ "\n",
+ "#Results\n",
+ "print(\"voltage gain is %3.3f \" %Av)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " input impedance is Zi=R1||R2||Zb\n",
+ " input circuit resistance is 2830983654.045Kohm \n",
+ "voltage gain is -0.777 \n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.9 Page No 267"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "hie=2.1*10**3\n",
+ "hfe=75.0\n",
+ "R1=10.0*10**3\n",
+ "R2=10.0*10**3\n",
+ "Re=4.7*10**3\n",
+ "Rl=12.0*10**3\n",
+ "rs=1.0*10**3\n",
+ "\n",
+ "#Calculations\n",
+ "print(\" Rl is not connected\")\n",
+ "hic=hie\n",
+ "hfc=1+hfe\n",
+ "Zb=hic+hfc*(Re)\n",
+ "Zi=(R1*R2*Zb)/(R1+R2+Zb)\n",
+ "Ze=(hic+(R1*R2*rs)/(R1+R2+rs))/hfc\n",
+ "Z0=(Ze*Re)/(Ze+Re)\n",
+ "print(\" when Rl is connected\")\n",
+ "Zb=hic+hfc*((Re*Rl)/(Re+Rl))\n",
+ "Zi=(R1*R2*Zb)/(R1+R2+Zb)\n",
+ "hib=hie/(1+hfe)\n",
+ "Av=((Re*Rl)/(Re+Rl))/(hib+((Re*Rl)/(Re+Rl)))\n",
+ "\n",
+ "#Results\n",
+ "print(\"voltage gain is %3.3f \" %Av)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " Rl is not connected\n",
+ " when Rl is connected\n",
+ "voltage gain is 0.992 \n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.10 Page No 273"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "hie=2.1*10**3\n",
+ "hfe=75.0\n",
+ "Re=4.7*10**3\n",
+ "Rc=3.9*10**3\n",
+ "Rl=82.0*10**3\n",
+ "\n",
+ "#Calculations\n",
+ "hib=hie/(1+hfe)\n",
+ "hfb=hfe/(1+hfe)\n",
+ "Zi=(hib*Re)/(Re+hib)\n",
+ "print(\"input impedance is %3.2fohm \" %Zi)\n",
+ "Zo=Rc\n",
+ "print(\" output impedance is %3.2fohm \" %Zo)\n",
+ "Av=(hfb*((Rc*Rl)/(Rc+Rl)))/hib\n",
+ "\n",
+ "#Results\n",
+ "print(\" voltage gain is %3.2f \" %Av)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "input impedance is 27.47ohm \n",
+ " output impedance is 3900.00ohm \n",
+ " voltage gain is 132.96 \n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.11, Page No 273"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "hib=27.6\n",
+ "hfb=.987\n",
+ "R1=68.0*10**3\n",
+ "R2=56.0*10**3\n",
+ "Re=4.7*10**3\n",
+ "Rc=3.9*10**3\n",
+ "Rl=82.0*10**3\n",
+ "\n",
+ "#Calculations\n",
+ "Rb=(R1*R2)/(R1+R2)\n",
+ "Ze=hib+Rb*(1-hfb)\n",
+ "Zi=(Ze*Re)/(Ze+Re)\n",
+ "Av=(hfb*((Rc*Rl)/(Rc+Rl)))/(hib+Rb*(1-hfb))\n",
+ "\n",
+ "#Results\n",
+ "print(\"voltage gain is %3.3f \" %Av)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "voltage gain is 8.609 \n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.12, Page No 277"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Rc=5.6*10**3\n",
+ "Rl=33.0*10**3\n",
+ "rs=600.0\n",
+ "hfe=100\n",
+ "hie=1.5*10**3\n",
+ "vs=50.0*10**-3\n",
+ "\n",
+ "#Calculations\n",
+ "print(\" CE circuit operation with vs at transistor base and Re bypassed\")\n",
+ "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
+ "Zb=hie\n",
+ "Rb=(R1*R2)/(R1+R2)\n",
+ "Zi=(Rb*Zb)/(Rb+Zb)\n",
+ "vi=(vs*Zi)/(rs+Zi)\n",
+ "vo=Av*vi\n",
+ "print(\"Cb circuit operation with vs at emitter and the base resistor bypassed\")\n",
+ "Av=(hfe*((Rc*Rl)/(Rc+Rl)))/hie\n",
+ "Ze=hie/(1+hfe)\n",
+ "Zi=(Ze*Re)/(Ze+Re)\n",
+ "vi=(vs*Zi)/(rs+Zi)\n",
+ "vo=Av*vi\n",
+ "\n",
+ "#Results\n",
+ "print(\"voltage vo is %3.2f \" %(vo*10**3))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " CE circuit operation with vs at transistor base and Re bypassed\n",
+ "Cb circuit operation with vs at emitter and the base resistor bypassed\n",
+ "voltage vo is 384.29 \n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6.13, Page No 279"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Io=50.0*10**-9\n",
+ "Vbe=.7\n",
+ "Vbc=-10\n",
+ "Af=.995\n",
+ "Ar=.5\n",
+ "Vt=26.0*10**-3\n",
+ "n=2.0\n",
+ "Vd=-10.0\n",
+ "\n",
+ "#Calculations\n",
+ "x=Vd/(n*Vt)\n",
+ "Idc=(Io*((2.73**-x)-1))*10**9\n",
+ "Idc=Io*(-1)\n",
+ "y=Vbe/(n*Vt)\n",
+ "Ide=Io*((2.73**y)-1)\n",
+ "I1=Af*Ide\n",
+ "I2=Ar*Idc\n",
+ "Ic=I1-Idc\n",
+ "Ie=Ide-I2\n",
+ "Ib=Ie-Ic\n",
+ "\n",
+ "#Results\n",
+ "print(\"voltage gain is %3.3f \" %(Ib*10**6))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "voltage gain is 185.909 \n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |