diff options
Diffstat (limited to 'Electronic_Devices_and_Circuits/Chapter19_1.ipynb')
| -rwxr-xr-x | Electronic_Devices_and_Circuits/Chapter19_1.ipynb | 1316 |
1 files changed, 1316 insertions, 0 deletions
diff --git a/Electronic_Devices_and_Circuits/Chapter19_1.ipynb b/Electronic_Devices_and_Circuits/Chapter19_1.ipynb new file mode 100755 index 00000000..f144d168 --- /dev/null +++ b/Electronic_Devices_and_Circuits/Chapter19_1.ipynb @@ -0,0 +1,1316 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 19 : Power amplifiers"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.1, Page No 810"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "Rpy=40.0\n",
+ "N1=74.0\n",
+ "N2=14.0\n",
+ "R2=3.7*10**3\n",
+ "R1=4.7*10**3\n",
+ "Vbe=0.7\n",
+ "Re=1.0*10**3\n",
+ "Vcc=13.0\n",
+ "Rl=56.0\n",
+ "\n",
+ "#Calculations\n",
+ "print(\"Q-point\")\n",
+ "Vb=Vcc*(R2/(R1+R2))\n",
+ "Ic=(Vb-Vbe)/Re\n",
+ "Ie=Ic\n",
+ "Vce=Vcc-Ic*(Rpy+Re)\n",
+ "rl=(N1/N2)**2 *Rl\n",
+ "rl=rl+Rpy\n",
+ "Ic=5*10**-3\n",
+ "Vce=Ic*rl\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of Vce is %.2f v \" %Vce)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Q-point\n",
+ "The value of Vce is 8.02 v \n"
+ ]
+ }
+ ],
+ "prompt_number": 44
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.2, Page No 814"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Vcc=13.0\n",
+ "Icq=5.0*10**-3\n",
+ "Vceq=8.0\n",
+ "Vp=Vceq\n",
+ "Ip=Icq\n",
+ "nt=0.8\n",
+ "\n",
+ "#Calculations\n",
+ "Pi=Vcc*Icq\n",
+ "Po=.5*Vp*Ip\n",
+ "P0=nt*Po\n",
+ "n=(P0/Pi)*100.0\n",
+ "\n",
+ "#Results\n",
+ "print(\" maximum efficiency is %3.2f percentage \" %n)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " maximum efficiency is 24.62 percentage \n"
+ ]
+ }
+ ],
+ "prompt_number": 45
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.4 Page No 821"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "N1=60.0\n",
+ "N2=10.0\n",
+ "Rl=16.0\n",
+ "Rpy=0\n",
+ "R6=56.0\n",
+ "Vcc=27.0\n",
+ "Vce=0.5\n",
+ "n=0.79\n",
+ "\n",
+ "#Calculations\n",
+ "print(\" Referred laod\")\n",
+ "rl=(N1/N2)**2 *Rl\n",
+ "print(\" tatol ac load line in series with each of Q2 and Q3\")\n",
+ "Rl=rl+R6+Rpy\n",
+ "print(\" peak primary current\")\n",
+ "Ip=(Vcc-Vce)/Rl\n",
+ "print(\"peak primary voltage\")\n",
+ "Vp=Vcc-Vce-(Ip*R6)\n",
+ "print(\"power delivered to primary\")\n",
+ "Po=.5*Vp*Ip\n",
+ "\n",
+ "#Calculations\n",
+ "Po=Po*n#n is power efficiency\n",
+ "print(\"power delivered to the load %.2f W \" %Po)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " Referred laod\n",
+ " tatol ac load line in series with each of Q2 and Q3\n",
+ " peak primary current\n",
+ "peak primary voltage\n",
+ "power delivered to primary\n",
+ "power delivered to the load 0.40 W \n"
+ ]
+ }
+ ],
+ "prompt_number": 46
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.5, Page No 824"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Po=4.0\n",
+ "nt=0.8\n",
+ "Vcc=30.0\n",
+ "Vp=Vcc\n",
+ "Rl=16.0\n",
+ "\n",
+ "#Calculations\n",
+ "P0=Po/nt\n",
+ "rl=(Vp)**2 /(2*P0)\n",
+ "rl=4*rl\n",
+ "print(\"transformer specification Po=4 %Rl=16 rl=360\")\n",
+ "Vce=2.0*Vcc\n",
+ "Ip=(2.0*P0)/Vp\n",
+ "Pi=Vcc*.636*Ip\n",
+ "Pt=0.5*(Pi-P0)\n",
+ "\n",
+ "#Results\n",
+ "print(\" transistor specification is Py=.68W Vce=60 Ip=333mA\")\n",
+ "print(\"power delivered to the load Pi = %.2f W \" %Pi)\n",
+ "print(\"power delivered to the load Pt = %.2f W \" %Pt)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "transformer specification Po=4 %Rl=16 rl=360\n",
+ " transistor specification is Py=.68W Vce=60 Ip=333mA\n",
+ "power delivered to the load Pi = 6.36 W \n",
+ "power delivered to the load Pt = 0.68 W \n"
+ ]
+ }
+ ],
+ "prompt_number": 47
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.6 Page No 830"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Rl=50.0\n",
+ "Po=1.0\n",
+ "hFE=50.0\n",
+ "Vbe=0.7\n",
+ "Vrc=4.0\n",
+ "Vre=1.0\n",
+ "Vd1=0.7\n",
+ "\n",
+ "#Calculations\n",
+ "Vd2=Vd1\n",
+ "Vp=math.sqrt(2*Rl*Po)\n",
+ "Ip=Vp/Rl\n",
+ "Re3=.1*Rl\n",
+ "Re2=4.7#use stabdard value\n",
+ "Re2=Re3\n",
+ "Icq=.1*Ip\n",
+ "Vb=Vbe+Icq*(Re2+Re3)+Vbe\n",
+ "Vc1=Vrc\n",
+ "Ib2=Ip/hFE\n",
+ "Irc=Ib2+1*10**-3\n",
+ "Rc=Vrc/Irc\n",
+ "Rc=680.0 #use standard value\n",
+ "Vcc=2.0*(Vp+Vre+Vbe+Vrc)\n",
+ "Vcc=32#use standard value\n",
+ "Vrcdc=.5*(Vcc-Vb)\n",
+ "Ic1=Vrcdc/Rc\n",
+ "Rb=(Vb-Vd1-Vd2)/Ic1\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of Rb is %.2f kOhm \" %Rb)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of Rb is 8.95 kOhm \n"
+ ]
+ }
+ ],
+ "prompt_number": 48
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.7 Page No 832"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Vcc=32.0\n",
+ "Vce=32.0\n",
+ "Ip=200.0*10**-3\n",
+ "Po=1.0\n",
+ "\n",
+ "#Calculations\n",
+ "Ic=1.1*Ip\n",
+ "Pi=0.35*Vcc*Ip\n",
+ "Pt=0.5*(Pi-Po)\n",
+ "\n",
+ "#Results\n",
+ "print(\"power delivered to the load Pi = %.2f \" %Pi)\n",
+ "print(\"power delivered to the load Pt = %.2f \" %Pt)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "power delivered to the load Pi = 2.24 \n",
+ "power delivered to the load Pt = 0.62 \n"
+ ]
+ }
+ ],
+ "prompt_number": 49
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.8, Page No 832"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "f=50.0\n",
+ "hib=2.0\n",
+ "Rl=50.0\n",
+ "\n",
+ "#Calculations\n",
+ "Ce=1.0/(2*3.14*f*hib)\n",
+ "Co=1.0/(2*3.14*50*.1*Rl)\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of Ce is %.2f pF \" %(Ce*10**3))\n",
+ "print(\"The value of Co is %.2f pF \" %(Co*10**3))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of Ce is 1.59 pF \n",
+ "The value of Co is 0.64 pF \n"
+ ]
+ }
+ ],
+ "prompt_number": 50
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.9 Page No 834"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "#initialisation of variables\n",
+ "hFE=2000.0\n",
+ "Vbe=1.4\n",
+ "Vp=10.0\n",
+ "Ip=200.0*10**-3\n",
+ "Icq2=20.0*10**-3\n",
+ "Re3=4.7\n",
+ "Re2=4.7\n",
+ "Vd=0.7\n",
+ "Ve1=3.0\n",
+ "Vc1=15.2\n",
+ "\n",
+ "#Calculations\n",
+ "Vrc=Vc1\n",
+ "Vb=Vbe+Icq*(Re2+Re3)+Vbe\n",
+ "Vcc=Vrc+Vc1+Vb\n",
+ "Ib2=Ip/hFE\n",
+ "Irc=1.0*10**-3\n",
+ "Vrcac=4.0\n",
+ "Rc=Vrcac/Irc\n",
+ "Ic1=Vrc/Rc\n",
+ "Rb=(Vb-(4*Vd))/Ic1\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of Rb is %.2f kohm \" %Rb)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of Rb is 49.47 kohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 51
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.10 Page No 838"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Vb=3.2\n",
+ "Ic1=5*10**-3\n",
+ "Vce=3.2\n",
+ "Vbe=0.7\n",
+ "\n",
+ "#Calculations\n",
+ "Vbmin=Vb-0.5\n",
+ "Vbmax=Vb+0.5\n",
+ "I10=.1*Ic1\n",
+ "R10=(Vce-Vbe)/I10\n",
+ "R10=4.7*10**3#use standard value\n",
+ "print(\" for Vce=3.7\")\n",
+ "Vce=3.7\n",
+ "I10max=(Vce-Vbe)/R10\n",
+ "print(\"Vce=2.7V\")\n",
+ "Vce=2.7\n",
+ "I10min=(Vce-Vbe)/R10\n",
+ "R=Vbe/I10min\n",
+ "R11=Vbe/I10max\n",
+ "R12=R-R11\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of R12 is %.2f kohm \" %R12)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " for Vce=3.7\n",
+ "Vce=2.7V\n",
+ "The value of R12 is 548.33 kohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 52
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.11 Page No 843"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Rl=16.0\n",
+ "Po=6.0\n",
+ "Vbe=0.7\n",
+ "\n",
+ "#Calculations\n",
+ "Vp=math.sqrt(2.0*Rl*Po)\n",
+ "Vr14=0.1*Vp\n",
+ "Vr15=Vr14\n",
+ "R14=0.1*Rl\n",
+ "R15=R14\n",
+ "Vce3=1.0\n",
+ "Vce4=Vce3\n",
+ "Vr9=3.0\n",
+ "Vr11=Vr9\n",
+ "Vcc=(Vp+Vr14+Vbe+Vce3+Vr9)\n",
+ "Vee=-Vcc\n",
+ "Ip=Vp/Rl\n",
+ "print(\" DC power inpit from supply line\")\n",
+ "Pi=(Vcc-Vee)*.35*Ip\n",
+ "Pt=.5*(Pi-Po)\n",
+ "Vce=2*Vcc\n",
+ "Ic=1.1*Ip\n",
+ "\n",
+ "#Results\n",
+ "print(\" output transistor specification %.2f mA\" %Ic)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " DC power inpit from supply line\n",
+ " output transistor specification 0.95 mA\n"
+ ]
+ }
+ ],
+ "prompt_number": 53
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.12, Page No 844"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "\n",
+ "hFE7=20.0\n",
+ "Icbo=50.0*10**-6\n",
+ "hFE5=70.0\n",
+ "Vr9=3.0\n",
+ "Ip=869.0*10**-3\n",
+ "R15=1.5\n",
+ "R8=15.0*10**3\n",
+ "Vbe=0.7\n",
+ "Vr11=3.0\n",
+ "Vee=20.0\n",
+ "\n",
+ "#Calculations\n",
+ "R12=0.01/Icbo\n",
+ "R12=220#use standard value\n",
+ "R13=R12\n",
+ "Ib5=Ip/(hFE7*hFE5)\n",
+ "Ic3=2.0*10**-3\n",
+ "R9=Vr9/Ic3\n",
+ "R11=R9\n",
+ "Iq78=0.1*Ip\n",
+ "Vr14=Iq78*R15\n",
+ "Vr15=Vr14\n",
+ "Vr10=(Vr14+Vr15)+(Vr14+Vr15)/2\n",
+ "R10=Vr10/Ic3\n",
+ "Ir8=(Vr11+Vbe)/R8\n",
+ "R7=(Vee-(Vr11+Vbe))/Ir8\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of R7 is %.2f kohm \" %(R7/1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of R7 is 66.08 kohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 54
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.13, Page No 848"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Rl=20.0\n",
+ "Po=2.5\n",
+ "Rd=4.0\n",
+ "Vr6=1.0\n",
+ "Vr9=Vr6\n",
+ "Vth=1.0\n",
+ "gFS=250.0*10**-3\n",
+ "Vbe=0.7\n",
+ "\n",
+ "#Calculations\n",
+ "Vp=math.sqrt(2*Rl*Po)\n",
+ "Ip=Vp/Rl\n",
+ "Vcc=(Vp+Ip*Rd)\n",
+ "vr6=Ip/gFS\n",
+ "Vr2=vr6+1\n",
+ "Vce=Vr2\n",
+ "Vce3=1.0\n",
+ "Vr2=Vcc-Vce\n",
+ "Vee=Vcc\n",
+ "Vr3=Vee-Vbe\n",
+ "Vr7=Vr2-Vr6\n",
+ "Vr8=Vcc-(-Vee)-Vr6-Vr7-Vr9\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of Vr8 is %.2f V \" %Vr8)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of Vr8 is 14.00 V \n"
+ ]
+ }
+ ],
+ "prompt_number": 55
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.14, Page No 849"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "R6=100.0*10**3\n",
+ "R9=R6\n",
+ "Vth=1.0\n",
+ "Vr7=8.0\n",
+ "Vr8=14.0\n",
+ "Vr3=11.3\n",
+ "Vpout=10.0\n",
+ "Vpin=800.0*10**-3\n",
+ "\n",
+ "#Calculations\n",
+ "I6=Vth/R6\n",
+ "R7=Vr7/I6\n",
+ "R8=Vr8/I6\n",
+ "Ic1=1*10**-4\n",
+ "Ic2=Ic1\n",
+ "Vr2=9\n",
+ "R2=Vr2/Ic1\n",
+ "R3=Vr3/(Ic1+Ic2)\n",
+ "R5=4.7*10**3\n",
+ "Acl=Vpout/Vpin\n",
+ "R4=R5/(Acl-1.0)\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of R4 is %.2f kohm \" %(R4/1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of R4 is 0.41 kohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 56
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.15, Page No 854"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Vce=1.5\n",
+ "Vcc=17.0\n",
+ "Vd1=0.7\n",
+ "R8=1.5*10**3\n",
+ "R9=R8\n",
+ "Rl=100.0\n",
+ "R6=8.2\n",
+ "\n",
+ "#Calculations\n",
+ "I4=(Vcc-Vd1)/(R8+R9)\n",
+ "Vc3=Vcc-(I4*R8)\n",
+ "print(\" bootstrap capacitance terminal voltage is %3.1fV \" %Vc3)\n",
+ "V=Vcc-Vce#V=Vp+Vr6\n",
+ "Ip=V/(Rl+R6)\n",
+ "Vp=Ip*Rl\n",
+ "print(\" peak output voltage is %3.1fV \" %Vp)\n",
+ "Po=(Vp)**2.0/(2.0*Rl)\n",
+ "\n",
+ "#Results\n",
+ "print(\" peak output power is %dW \" %Po)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " bootstrap capacitance terminal voltage is 8.8V \n",
+ " peak output voltage is 14.3V \n",
+ " peak output power is 1W \n"
+ ]
+ }
+ ],
+ "prompt_number": 57
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.16, Page No 856"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Rl=8.0\n",
+ "Po=6.0\n",
+ "vs=0.1\n",
+ "hFE=1000.0\n",
+ "Vce=2.0\n",
+ "f=50.0*10**3\n",
+ "Vd1=0.7\n",
+ "\n",
+ "#Calculations\n",
+ "Vp=math.sqrt(2*Rl*Po)\n",
+ "Ip=Vp/Rl\n",
+ "R6=.1*Rl\n",
+ "R7=R6\n",
+ "Vcc=Vp+Ip*R6+Vce\n",
+ "Ib=Ip/hFE\n",
+ "I4=2*10**-3\n",
+ "R4=(Vcc-Vd1-Vd1)/I4\n",
+ "R8=.5*R4\n",
+ "Acl=Vp/vs\n",
+ "R3=100*10**3\n",
+ "R2=R3/(Acl-1)\n",
+ "SR=(2*3.14*f*Vp)*10**-6\n",
+ "\n",
+ "#Results\n",
+ "print(\" slew rate is %.2f V/us \" %SR)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " slew rate is 3.08 V/us \n"
+ ]
+ }
+ ],
+ "prompt_number": 58
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.17, Page No 856"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "f=50.0\n",
+ "R1=100.0*10**3\n",
+ "R2=1.0*10**3\n",
+ "R8=2.7*10**3\n",
+ "\n",
+ "#Calculations\n",
+ "R9=R8\n",
+ "C1=1/(2*3.14*f*.1*R1)\n",
+ "C2=1/(2*3.14*f*R2)\n",
+ "Xc3=.1*((R8*R9)/(R8+R9))\n",
+ "C3=1/(2*3.14*f*Xc3)\n",
+ "C4=C3\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of C4 is %.2f pF \" %(C4*10**6))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of C4 is 23.59 pF \n"
+ ]
+ }
+ ],
+ "prompt_number": 59
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.18, Page No 860"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Ismin=1.8*10**-3\n",
+ "Ismax=3.4*10**-3\n",
+ "R7=820.0\n",
+ "R5=390.0\n",
+ "R6=18.0*10**3\n",
+ "Vi=100.0*10**-3\n",
+ "Rl=10.0\n",
+ "\n",
+ "#Calculations\n",
+ "Vgsmin=Ismin*R7\n",
+ "Vgsmax=Ismax*R7\n",
+ "Acl=(R5+R6)/R5\n",
+ "Vp=Acl*Vi\n",
+ "Ip=Vp/Rl\n",
+ "print(\"peak output current is %3.3fA \" %Ip)\n",
+ "Po=(Vp*Ip)/2.0\n",
+ "\n",
+ "#Results\n",
+ "print(\"peak output power is %3.2fW \" %Po)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "peak output current is 0.472A \n",
+ "peak output power is 1.11W \n"
+ ]
+ }
+ ],
+ "prompt_number": 60
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.19, Page No 862"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Vbe=0.7\n",
+ "R2=560.0\n",
+ "R3min=0\n",
+ "R3max=1.0*10**3\n",
+ "Is=2.0*10**-3\n",
+ "\n",
+ "#Calculations\n",
+ "Ic2max=Vbe/(R2+R3min)\n",
+ "Ic2min=Vbe/(R2+R3max)\n",
+ "Vgsmin=(Is+Ic2min)*820.0\n",
+ "Vgsmax=(Is+Ic2max)*820.0\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of Vgsmax is %.2f v \" %Vgsmax)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of Vgsmax is 2.67 v \n"
+ ]
+ }
+ ],
+ "prompt_number": 61
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.20, Page No 865"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "\n",
+ "Vcc=12.0\n",
+ "Rl=10.0\n",
+ "Rd=0.5\n",
+ "gfs=2.5\n",
+ "R7=820.0\n",
+ "V9=1.0*10**3\n",
+ "\n",
+ "#Calculations\n",
+ "R10=R9\n",
+ "Vp=(Vcc*Rl)/(Rd+Rl)\n",
+ "Ip=Vp/Rl\n",
+ "Vgs=Ip/gfs\n",
+ "Vr7=Is*R7\n",
+ "Vs=Vcc-Vr7-Vgs\n",
+ "Vr9=(Vp*R9)/(R9+R10)\n",
+ "\n",
+ "#Results\n",
+ "print(\"op-amp peak output voltage is %.2f v \" %Vr9)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "op-amp peak output voltage is 5.71 v \n"
+ ]
+ }
+ ],
+ "prompt_number": 62
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.21, Page No 867"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Vbe=0.7\n",
+ "R2=470.0\n",
+ "R3=1.0*10**3\n",
+ "Is=0.5*10**-3\n",
+ "R7=1.5*10**3\n",
+ "Vcc=15\n",
+ "\n",
+ "#Calculations\n",
+ "Ic2max=Vbe/R2\n",
+ "Ic2min=Vbe/(R2+R3)\n",
+ "Vgs=(Is+Ic2max)*R7\n",
+ "print(\" MOSFET maximum gate source voltage is %.1fV \" %Vgs)\n",
+ "Vs=Vcc-Vgs\n",
+ "\n",
+ "#Results\n",
+ "print(\" op-amp minimum suppy is %.2fV \" %Vs)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " MOSFET maximum gate source voltage is 3.0V \n",
+ " op-amp minimum suppy is 12.02V \n"
+ ]
+ }
+ ],
+ "prompt_number": 63
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.22, Page No 868"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Vcc=15.0\n",
+ "Rl=15.0\n",
+ "Rd=0.3\n",
+ "R5=2.2*10**3\n",
+ "R6=33.0*10**3\n",
+ "C2=3.9*10**-6\n",
+ "C4=100.0*10**-12\n",
+ "\n",
+ "#Calculations\n",
+ "print(\" power output\")\n",
+ "Vp=(Vcc*Rl)/(Rd+Rl)\n",
+ "Ip=Vp/Rl\n",
+ "Po=(Vp*Ip)/2.0\n",
+ "print(\" voltage gain\")\n",
+ "Av=(R5+R6)/R5\n",
+ "print(\"cutoff frequency\")\n",
+ "f1=1.0/(2*3.14*C2*R5)\n",
+ "f2=1.0/(2*3.14*C4*R6)\n",
+ "\n",
+ "#Results\n",
+ "print(\" cutoff frequency f1 %.2f \" %f1)\n",
+ "print(\" cutoff frequency f2 %.2f \" %f2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " power output\n",
+ " voltage gain\n",
+ "cutoff frequency\n",
+ " cutoff frequency f1 18.56 \n",
+ " cutoff frequency f2 48253.23 \n"
+ ]
+ }
+ ],
+ "prompt_number": 64
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.23, Page No 871"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Vcc=23.0\n",
+ "Rl=8.0\n",
+ "Rf2=100.0*10**3\n",
+ "Rf1=5.6*10**3\n",
+ "Cf=1.0*10**-6\n",
+ "Vp=Vcc-5\n",
+ "\n",
+ "#Calculations\n",
+ "Po=(Vp)**2/(2*Rl)\n",
+ "print(\"maximum output power is %3.2fW \" %Po)\n",
+ "Acl=(Rf1+Rf2)/Rf1\n",
+ "print(\" voltage gain %3.1f \" %Acl)\n",
+ "f=1/(2*3.14*Cf*Rf1)\n",
+ "\n",
+ "#Results\n",
+ "print(\"lower cutoff frequency is %dHz \" %f)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "maximum output power is 20.25W \n",
+ " voltage gain 18.9 \n",
+ "lower cutoff frequency is 28Hz \n"
+ ]
+ }
+ ],
+ "prompt_number": 65
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.24, Page No 875"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Rf=15.0*10**3\n",
+ "R1=5.6*10**3\n",
+ "vs=0.5\n",
+ "Vp=2.7\n",
+ "\n",
+ "#Calculations\n",
+ "Acl=(2.0*Rf)/R1\n",
+ "Vo=Acl*vs\n",
+ "Po=(Vp)**2.0/(2.0*Rl)\n",
+ "\n",
+ "#Results\n",
+ "print(\"load power dissipation is %.2fW \" %Po)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "load power dissipation is 0.46W \n"
+ ]
+ }
+ ],
+ "prompt_number": 66
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.24, Page No 875"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Vcc=10.0\n",
+ "Rl=1.0*10**3\n",
+ "f=3.0*10**6\n",
+ "Ip=25.0*10**-3\n",
+ "Vce=0.3\n",
+ "\n",
+ "#Calculations\n",
+ "Vp=Vcc-Vce\n",
+ "Po=(Vp)**2 /(2*Rl)\n",
+ "T=1.0/f\n",
+ "t=(Po*T)/(Ip*Vp)\n",
+ "angle=(t/T)*360\n",
+ "print(\" conduction angle is %3.1fdegree \" %angle)\n",
+ "Idc=Po/Vp\n",
+ "Pi=Vcc*Idc\n",
+ "print( \"dc input power is %3.4fW \" %Pi)\n",
+ "n=(Po/Pi)*100#efficiency\n",
+ "\n",
+ "#Results\n",
+ "print(\" maximum efficiency is %3.2f percentage \" %n)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " conduction angle is 69.8degree \n",
+ "dc input power is 0.0485W \n",
+ " maximum efficiency is 97.00 percentage \n"
+ ]
+ }
+ ],
+ "prompt_number": 67
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.26, Page No 882"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "f=1.0*10**6\n",
+ "Xc=120.0\n",
+ "Vce=0.5\n",
+ "Vcc=30.0\n",
+ "Rl=1.2*10**3\n",
+ "O=100.0\n",
+ "\n",
+ "#Calculations\n",
+ "Cp=1.0/(2*3.14*f*Xc)\n",
+ "Cp=1300*10**-12#use standard value\n",
+ "Lp=1/(((2*3.14*f)**2)*Cp)\n",
+ "Vp=Vcc-Vce\n",
+ "Po=((Vp)**2) /(2*Rl)\n",
+ "Idc=Po/Vp\n",
+ "T=1.0/f\n",
+ "t=(O*T)/360.0\n",
+ "Ip=(Idc*T)/t\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of Ip is %.2f mA \" %(Ip*10**3))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of Ip is 44.25 mA \n"
+ ]
+ }
+ ],
+ "prompt_number": 68
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 19.27, Page No 883"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Rw=0.1\n",
+ "f=1.0*10**6\n",
+ "Lp=19.5*10**-6\n",
+ "Rl=1.2*10**3\n",
+ "Vcc=30.0\n",
+ "\n",
+ "#Calculations\n",
+ "Idc=12.3*10**-3\n",
+ "QL=(2*3.14*f*Lp)/Rw\n",
+ "Qp=Rl/(2*3.14*f*Lp)\n",
+ "B=f/Qp\n",
+ "Il=(.707*Vp)/(2*3.14*f*Lp)\n",
+ "Pl=(Il)**2 *Rw\n",
+ "Pi=(Vcc*Idc)+Pl\n",
+ "n=(Po/Pi)*100.0\n",
+ "\n",
+ "#Results\n",
+ "print(\" maximum efficiency is %3.2f percentage \" %n)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " maximum efficiency is 97.50 percentage \n"
+ ]
+ }
+ ],
+ "prompt_number": 69
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |