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Diffstat (limited to 'Electronic_Devices_and_Circuits/Chapter15_1.ipynb')
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diff --git a/Electronic_Devices_and_Circuits/Chapter15_1.ipynb b/Electronic_Devices_and_Circuits/Chapter15_1.ipynb deleted file mode 100755 index db5e05e2..00000000 --- a/Electronic_Devices_and_Circuits/Chapter15_1.ipynb +++ /dev/null @@ -1,282 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 15 : Operational amplifier frequency\n",
- "Response and compensation"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.2, Page No 648"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R2=1.0*10**6\n",
- "Acl=4.5\n",
- "\n",
- "#Calculations\n",
- "R1=R2/Acl\n",
- "R1=220*10**3#use standard value\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "Cf=((R1*30*10**-12)/(R1+R2))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" suitable value of capacitor is %.2fpF \" %Cf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable value of capacitor is 5.41pF \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.3, Page No 649"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "f=35.0*10**3\n",
- "Rf=68.0*10**3\n",
- "\n",
- "#Calculations\n",
- "Cf=(1.0/(2*3.14*f*Rf))*10**12\n",
- "\n",
- "#Results\n",
- "print(\" suitable miller effect capacitor is %.2f pF \" %Cf)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " suitable miller effect capacitor is 66.91 pF \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.5 Page No 652"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Acl=100.0\n",
- "Av=10.0\n",
- "print(\" for Cf=30pF\")\n",
- "GBW=800.0*10**3\n",
- "\n",
- "#Calculations\n",
- "F2=GBW/Acl\n",
- "print(\" for Cf=3pF\")\n",
- "GBW=(800*10**3)*Av\n",
- "f2=GBW/Acl\n",
- "\n",
- "#Results\n",
- "print(\" The value of f2 is %.2f pF \" %(f2/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for Cf=30pF\n",
- " for Cf=3pF\n",
- " The value of f2 is 80.00 pF \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.6, Page No 654"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vip=1.0\n",
- "R2=39.0*10**3\n",
- "R3=4.7*10**3\n",
- "SR=250.0/10**-6\n",
- "f=100.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" for the AD843\")\n",
- "Vop=((R2+R3)/R3)*Vip\n",
- "fp=SR/(2*3.14*Vop)\n",
- "print(\"full power bandwidth is %dHz \" %fp)\n",
- "print(\" for a 741\")\n",
- "SR=0.5/10**-6\n",
- "Vp=SR/(2*3.14*f)\n",
- "\n",
- "#Results\n",
- "print(\" maximum peak output voltage is %3.2fV \" %Vp)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " for the AD843\n",
- "full power bandwidth is 4281508Hz \n",
- " for a 741\n",
- " maximum peak output voltage is 0.80V \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.7 Page No 656"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "rs=600.0\n",
- "R1=1.0*10**3\n",
- "R2=10.0*10**3\n",
- "f=800.0*10**3\n",
- "\n",
- "#Calculations\n",
- "print(\" stray capacitance\")\n",
- "Cs=1/(2*3.14*f*10*(((rs+R1)*R2)/(rs+R1+R2)))\n",
- "print(\"compensation capacitor\")\n",
- "C2=((Cs*(rs+R1))/R2)*10**12\n",
- "\n",
- "#Results\n",
- "print(\"compensation capacitor is %.2fpF \" %C2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " stray capacitance\n",
- "compensation capacitor\n",
- "compensation capacitor is 2.31pF \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 15.8 Page No 659"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "ro=25.0\n",
- "f=2.0*10**6\n",
- "R2=10.0*10**3\n",
- "Rx=25.0\n",
- "\n",
- "#Calculations\n",
- "Cl=(1.0/(2.0*3.14*f*(10*ro)))*10**+12\n",
- "print(\" load capacitance is %3.2fpF \" %Cl)\n",
- "Cl=0.1*10**-6\n",
- "C2=((Cl*(ro+Rx))/R2)*10**12\n",
- "\n",
- "#Results\n",
- "print(\" compensation capacitance is %.2f pF \" %C2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " load capacitance is 318.47pF \n",
- " compensation capacitance is 500.00 pF \n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
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