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Diffstat (limited to 'Electronic_Devices_and_Circuits/Chapter14_1.ipynb')
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diff --git a/Electronic_Devices_and_Circuits/Chapter14_1.ipynb b/Electronic_Devices_and_Circuits/Chapter14_1.ipynb deleted file mode 100755 index 90767c65..00000000 --- a/Electronic_Devices_and_Circuits/Chapter14_1.ipynb +++ /dev/null @@ -1,662 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 14 : Ic operational Amplifier and basic Op amp circuits"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.1, Page No 597"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Vbe=0.7\n",
- "Ib=500.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "R1=Vbe/(10.0*Ib)\n",
- "R1=120.0*10**3#use standard value\n",
- "R2=R1\n",
- "I2=100.0*Ib\n",
- "Vr1=15.0\n",
- "Vr2=Vr1\n",
- "R1=Vr1/I2\n",
- "R1=270.0*10**3#use satndard value\n",
- "R2=R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 135.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.2, Page No 599"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "R2=1.0*10**6\n",
- "Vb=3.0\n",
- "Vo=3.0\n",
- "Vee=9.0\n",
- "\n",
- "#Calculations\n",
- "Vr2=Vb-(-Vee)\n",
- "Vr1=Vee-Vb\n",
- "I2=Vr2/R2\n",
- "R1=Vr1/I2\n",
- "R3=0\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 500.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.3 Page No 601"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Av=200000.0\n",
- "ri=2.0*10**6\n",
- "ro=75.0\n",
- "Vo=1.0\n",
- "B=1.0\n",
- "\n",
- "#Calculations\n",
- "Vd=Vo/Av\n",
- "Zi=(1+Av*B)*ri\n",
- "Zo=ro/(1+Av*B)\n",
- "\n",
- "#Results\n",
- "print('The value of Zo= %.2f X 10^-3 kohm ' %(Zo*10**3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Zo= 0.37 X 10^-3 kohm \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.4, Page No 603"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "f=70.0\n",
- "Rl=4.0*10**3\n",
- "Ib=500.0*10**-9\n",
- "Vbe=0.7\n",
- "\n",
- "#Calculations\n",
- "R1=Vbe/(10*Ib)\n",
- "R1=120*10**3#use standard value\n",
- "R2=R1\n",
- "print(\" desire value of capacitor is C=1/2*3.14*f*R\")\n",
- "C2=1/(2*3.14*f*Rl)\n",
- "C1=1/(2*3.14*f*(R1/10))\n",
- "\n",
- "#Results\n",
- "print('The value of C1= %.2f mF ' %(C1*10**6))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " desire value of capacitor is C=1/2*3.14*f*R\n",
- "The value of C1= 0.19 mF \n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.5 Page No 605"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=500.0*10**-9\n",
- "Vi=50.0*10**-3\n",
- "Vo=2.0\n",
- "\n",
- "#Calculations\n",
- "I2=100.0*Ib\n",
- "R3=Vi/I2\n",
- "R2=(Vo/I2)-R3\n",
- "R1=(R2*R3)/(R2+R3)\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 0.97 kohm \n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.6 Page No 606"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Av=200000.0\n",
- "ri=2.0*10**6\n",
- "ro=75.0\n",
- "R3=1.0*10**3\n",
- "R2=39*10**3\n",
- "\n",
- "#Calculations\n",
- "B=R3/(R2+R3)\n",
- "Zi=(1+Av*B)*ri\n",
- "\n",
- "#Results\n",
- "print(\" typical input impedance for non-inverting amplifier is %.2f ohm \" %Zi)\n",
- "Zo=ro/(1+Av*B)\n",
- "print('The value of Zo= %.2f kohm ' %(Zo*10))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " typical input impedance for non-inverting amplifier is 10002000000.00 ohm \n",
- "The value of Zo= 0.15 kohm \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.7, Page No 607"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "R2=50.0*10**3\n",
- "R3=2.2*10**3\n",
- "C2=8.2*10**-6\n",
- "Rl=600.0\n",
- "\n",
- "#Calculations\n",
- "print(\"voltage gain \")\n",
- "Acl=(R3+R2)/R3\n",
- "\n",
- "#Results\n",
- "print(\"lower cuttoff frequency \")\n",
- "f=1/(2*3.14*C2*Rl)\n",
- "print('The value of f= %.2f kohm ' %(f))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage gain \n",
- "lower cuttoff frequency \n",
- "The value of f= 32.36 kohm \n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.8 Page No 610"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math \n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Acl=144.0\n",
- "Vi=20.0*10**-3\n",
- "Ib=500.0*10**-9\n",
- "\n",
- "#Calculations\n",
- "I1=100.0*Ib\n",
- "R1=Vi/I1\n",
- "R1=390.0 #use standard value\n",
- "R2=Acl*R1\n",
- "R3=(R1*R2)/(R1+R2)\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 387.31 kohm \n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.9 Page No 612"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "Acl=3.0\n",
- "R4=1.0*10**6\n",
- "Vi=1.0\n",
- "\n",
- "#Calculations\n",
- "R1=R4/Acl\n",
- "R1=330.0*10**3#use standard value \n",
- "R2=R1\n",
- "R3=R1\n",
- "I1=Vi/R1\n",
- "I2=I1\n",
- "I3=I1\n",
- "I4=I1+I2+I3\n",
- "Vo=-I4*R4\n",
- "\n",
- "#Results\n",
- "print('The value of Vo= %.2f v ' %(Vo))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Vo= -9.09 v \n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.10 Page No 615"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Ib=500.0*10**-9\n",
- "Vi=1.0\n",
- "Acl=10.0\n",
- "\n",
- "#Calculations\n",
- "I1=100*Ib\n",
- "R1=Vi/I1\n",
- "R1=18*10**3#use standard value\n",
- "R2=Acl*R1\n",
- "R4=R1\n",
- "R3=R1/Acl\n",
- "\n",
- "#Results\n",
- "print('The value of R3= %.2f kohm ' %(R3/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R3= 1.80 kohm \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.11, Page No 619"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "\n",
- "#initialisation of variables\n",
- "\n",
- "Vi=10*10**-3\n",
- "Vn=1.0\n",
- "R1=33.0*10**3\n",
- "R2=300.0\n",
- "R5=15.0*10**3\n",
- "R4=15.0*10**3\n",
- "Vi2=-10.0*10**-3\n",
- "R3=R1\n",
- "R6=15.0*10**3\n",
- "\n",
- "#Calculations\n",
- "R7=R6\n",
- "Acl=((2*R1+R2)/R2)*(R5/R4)\n",
- "print(\"at junction of R1 and R2\")\n",
- "Vb=Vi+Vn\n",
- "print(\"at junction of R2 and R3\")\n",
- "Vc=Vi2+Vn\n",
- "print(\" current through R2\")\n",
- "I2=(Vb-Vc)/R2\n",
- "print(\"at the output of A1\")\n",
- "Va=Vb+(I2*R1)\n",
- "print(\"at output of A2\")\n",
- "Vd=Vc-(I2*R3)\n",
- "print(\"at junction of R6 and R7\")\n",
- "Vf=Vd*(R7/(R6+R7))\n",
- "print(\"at junction of R4 and R5\")\n",
- "Ve=Vf\n",
- "print(\"current through R4\")\n",
- "I4=(Va-Ve)/R4\n",
- "\n",
- "#Results\n",
- "print(\"at output of A3\")\n",
- "Vg=Ve-(I4*R5)\n",
- "print('The value of Vg= %.2f kohm ' %(Vg))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "at junction of R1 and R2\n",
- "at junction of R2 and R3\n",
- " current through R2\n",
- "at the output of A1\n",
- "at output of A2\n",
- "at junction of R6 and R7\n",
- "at junction of R4 and R5\n",
- "current through R4\n",
- "at output of A3\n",
- "The value of Vg= -4.42 kohm \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.12, Page No 623"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=15.0\n",
- "Vee=-15.0\n",
- "Av=200000.0\n",
- "SR=0.5/10**-6\n",
- "Vo=14.0\n",
- "\n",
- "#Calculations\n",
- "V=(Vcc-1)-(Vee+1)\n",
- "Vi=Vo/Av\n",
- "print(\"rise time of output is \")\n",
- "t=(V/SR)*10**6\n",
- "\n",
- "#Results\n",
- "print(\"rise time of output is %d ms \" %t)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "rise time of output is \n",
- "rise time of output is 56 ms \n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.13, Page No 627"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variables\n",
- "Ib=500.0*10**-9\n",
- "UTP=5.0\n",
- "Vcc=15.0\n",
- "\n",
- "#Calculations\n",
- "I1=100.0*Ib\n",
- "R2=UTP/I1\n",
- "R1=((Vcc-1)-5)/I1\n",
- "\n",
- "#Results\n",
- "print('The value of R1= %.2f kohm ' %(R1/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of R1= 180.00 kohm \n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.14, Page No 630"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#initialisation of variables\n",
- "\n",
- "Vcc=15.0\n",
- "Vsat=Vcc\n",
- "R2=150.0*10**3\n",
- "Vf=0.7\n",
- "R1=27.0*10**3\n",
- "R3=120.0*10**3\n",
- "\n",
- "#Calculations\n",
- "I2=(Vsat-Vf)/R2\n",
- "UTP=I2*R1\n",
- "\n",
- "#Results\n",
- "print(\" LTP calculation including Vf\")\n",
- "I3=(Vsat-Vf)/R3\n",
- "LTP=-I3*R1\n",
- "print('The value of LTP= %.2f kohm ' %(LTP))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " LTP calculation including Vf\n",
- "The value of LTP= -3.22 kohm \n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |