diff options
Diffstat (limited to 'Electronic_Devices/Chapter5.ipynb')
-rwxr-xr-x | Electronic_Devices/Chapter5.ipynb | 419 |
1 files changed, 419 insertions, 0 deletions
diff --git a/Electronic_Devices/Chapter5.ipynb b/Electronic_Devices/Chapter5.ipynb new file mode 100755 index 00000000..1bcf9f83 --- /dev/null +++ b/Electronic_Devices/Chapter5.ipynb @@ -0,0 +1,419 @@ +{ + "metadata": { + "name": "Chapter_5" + }, + "nbformat": 2, + "worksheets": [ + { + "cells": [ + { + "cell_type": "markdown", + "source": [ + "<h1>Chapter 5: Transistor Bias Circuits<h1>" + ] + }, + { + "cell_type": "markdown", + "source": [ + "<h3>Example 5.1, Page Number: 146<h3>" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "%pylab inline" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "", + "Welcome to pylab, a matplotlib-based Python environment [backend: module://IPython.zmq.pylab.backend_inline].", + "For more information, type 'help(pylab)'." + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "", + "# variable declaration", + "V_BB=10.0; #voltage in volt", + "V_CC=20.0; #voltage in volt", + "B_DC=200.0; #B_DC value", + "R_B=47.0*10**3; #resistance in ohm", + "R_C=330.0; #resistance in ohm", + "V_BE=0.7; #voltage in volt", + "", + "#current", + "I_B=(V_BB-V_BE)/R_B; #base current", + "I_C=B_DC*I_B; #Q POINT", + "V_CE=V_CC-I_C*R_C; #Q POINT", + "I_C_sat=V_CC/R_C; #saturation current", + "I_c_peak=I_C_sat-I_C; #peak current ", + "I_b_peak=I_c_peak/B_DC; #peak current in ampere", + "", + "#result", + "print \"Q point of I_C = %.3f amperes\" %I_C", + "print \"Q point of V_CE = %.2f volts\" %V_CE", + "print \"peak base current = %.4f amperes\" %I_b_peak" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Q point of I_C = 0.040 amperes", + "Q point of V_CE = 6.94 volts", + "peak base current = 0.0001 amperes" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "markdown", + "source": [ + "<h3>Example 5.2, Page Number: 149<h3>" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "", + "# variable declaration", + "B_DC=125.0; #DC value", + "R_E=10.0**3; #resistance in ohm", + "", + "#calculation", + "R_IN_base=B_DC*R_E; #base resistance", + "", + "#Result", + "print \"DC input resistance, looking at base of transistor = %d ohm\" %R_IN_base" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "DC input resistance, looking at base of transistor = 125000 ohm" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "markdown", + "source": [ + "<h3>Example 5.3, Page Number: 151<h3>" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "", + "# variable declaration", + "B_DC=100; #DC value", + "R1=10*10**3; #resistance in ohm", + "R2=5.6*10**3; #resistance in ohm", + "R_C=1*10**3; #resistance in ohm", + "R_E=560; #resistance in ohm", + "V_CC=10; #voltage in volt", + "V_BE=0.7 #voltage in volt", + "", + "#calculation", + "R_IN_base=B_DC*R_E; #calculate base resistance", + "#We can neglect R_IN_base as it is equal to 10*R2", + "print \"input resistance seen from base = %d ohm\" %R_IN_base", + "print \"which can be neglected as it is 10 times R2\"", + "", + "V_B=(R2/(R1+R2))*V_CC; #base voltage", + "V_E=V_B-V_BE; #emitter voltage", + "I_E=V_E/R_E; #emitter current", + "I_C=I_E; #currents are equal", + "V_CE=V_CC-I_C*(R_C+R_E); #voltage in volt", + "", + "#result", + "print \"V_CE = %.2f volts\" %V_CE", + "print \"I_C = %.3f amperes\" %I_C", + "print \"Since V_CE>0V, transistor is not in saturation\"" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "input resistance seen from base = 56000 ohm", + "which can be neglected as it is 10 times R2", + "V_CE = 1.95 volts", + "I_C = 0.005 amperes", + "Since V_CE>0V, transistor is not in saturation" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "markdown", + "source": [ + "<h3>Example 5.4, Page Number: 154<h3>" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "", + "# variable declaration", + "V_EE=10.0; #voltage in volt", + "V_BE=0.7; #voltage in volt", + "B_DC=150.0; #DC value ", + "R1=22.0*10**3; #resistance in ohm", + "R2=10.0*10**3; #resistance in ohm", + "R_C=2.2*10**3; #resistance in ohm", + "R_E=1.0*10**3; #resistance in ohm", + "", + "#calculation", + "R_IN_base=B_DC*R_E; #R_IN_base>10*R2,so it can be neglected", + "print \"input resistance as seen from base = %d ohm\" %R_IN_base", + "print \"it can be neglected as it is greater than 10 times R2\"", + "V_B=(R1/(R1+R2))*V_EE; #base voltage", + "V_E=V_B+V_BE; #emitter voltage", + "I_E=(V_EE-V_E)/R_E; #emitter current", + "I_C=I_E; #currents are equal", + "V_C=I_C*R_C; #collector voltage", + "V_EC=V_E-V_C; #emitter-collector voltage", + "", + "#result", + "print \"I_C collector current = %.4f amperes\" %I_C", + "print \"V_EC emitter-collector voltage = %.2f Volts\" %V_EC" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "input resistance as seen from base = 150000 ohm", + "it can be neglected as it is greater than 10 times R2", + "I_C collector current = 0.0024 amperes", + "V_EC emitter-collector voltage = 2.24 Volts" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "markdown", + "source": [ + "<h3>Example 5.5, PAge Number: 154<h3>" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "", + "# variable declaration", + "R1=68.0*10**3; #resistance in ohm", + "R2=47.0*10**3; #resistance in ohm", + "R_C=1.8*10**3; #resistance in ohm", + "R_E=2.2*10**3; #resistance in ohm", + "V_CC=-6.0; #voltage in volt", + "V_BE=0.7; #voltage in volt", + "B_DC=75.0; #DC value", + "", + "#calculation", + "R_IN_base=B_DC*R_E;", + "print \"input resistance as seen from base\"", + "print \"is not greater than 10 times R2 so it should be taken into account\"", + "#R_IN_base in parallel with R2", + "V_B=((R2*R_IN_base)/(R2+R_IN_base)/(R1+(R2*R_IN_base)/(R2+R_IN_base)))*V_CC;", + "V_E=V_B+V_BE; #emitter voltage", + "I_E=V_E/R_E; #emitter current", + "I_C=I_E; #currents are equal", + "V_C=V_CC-I_C*R_C; #collector voltage", + "V_CE=V_C-V_E; #collector-emitter voltage", + "", + "#result", + "print \"collector current = %.4f amperes\" %I_C", + "print \"collector emitter voltage = %.2f volts\" %V_CE" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "input resistance as seen from base", + "is not greater than 10 times R2 so it should be taken into account", + "collector current = -0.0006 amperes", + "collector emitter voltage = -3.46 volts" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "markdown", + "source": [ + "<h3>Example 5.6, Page Number: 156<h3>" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "", + "# variable declaration", + "V_CC=12.0; #voltage in volt", + "R_B=100.0*10**3; #resistance in ohm", + "R_C=560.0; #resistance in ohm", + "#FOR B_DC=85 AND V_BE=0.7V", + "B_DC=85.0; #DC value", + "V_BE=0.7; #base-emitter voltage", + "", + "#calculation", + "I_C_1=B_DC*(V_CC-V_BE)/R_B; #collector current", + "V_CE_1=V_CC-I_C_1*R_C; #collector-emittor voltage", + "#FOR B_DC=100 AND V_BE=0.6V", + "B_DC=100.0; #DC value ", + "V_BE=0.6; #base emitter voltage", + "I_C_2=B_DC*(V_CC-V_BE)/R_B; #collector current", + "V_CE_2=V_CC-I_C_2*R_C; #voltage in volt", + "p_del_I_C=((I_C_2-I_C_1)/I_C_1)*100; #percent change in collector current ", + "p_del_V_CE=((V_CE_2-V_CE_1)/V_CE_1)*100; #percent change in C-E voltage", + "", + "#result", + "print \"percent change in collector current = %.2f\" %p_del_I_C", + "print \"percent change in collector emitter voltage = %.2f\" %p_del_V_CE" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "percent change in collector current = 18.69", + "percent change in collector emitter voltage = -15.18" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "markdown", + "source": [ + "<h3>Example 5.7, Page Number: 159<h3>" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "", + "# variable declaration", + "V_CC=20.0; #voltage in volt", + "R_C=4.7*10**3; #resistance in ohm", + "R_E=10.0*10**3; #resistance in ohm", + "V_EE=-20.0; #voltage in volt", + "R_B=100*10**3; #resistance in ohm", + "#FOR B_DC=85 AND V_BE=0.7V", + "B_DC=85; #DC value", + "V_BE=0.7; #base-emitter voltage", + "I_C_1=(-V_EE-V_BE)/(R_E+(R_B/B_DC));", + "V_C=V_CC-I_C_1*R_C; #colector voltage", + "I_E=I_C_1; #emittor current", + "V_E=V_EE+I_E*R_E; #emittor voltage", + "V_CE_1=V_C-V_E; #CE voltage", + "print \"I_C_1 = %.3f\" %I_C_1", + "print \"V_CE_1 = %.2f\" %V_CE_1", + "#FOR B_DC=100 AND V_BE=0.6V", + "B_DC=100; #DC value ", + "V_BE=0.6; #base-emitter voltage", + "I_C_2=(-V_EE-V_BE)/(R_E+(R_B/B_DC));", + "V_C=V_CC-I_C_2*R_C;#colector voltage", + "I_E=I_C_2; #emittor current", + "V_E=V_EE+I_E*R_E; #emittor voltage", + "V_CE_2=V_C-V_E; #CE voltage", + "print \"I_C_2 = %.3f\" %I_C_2", + "print \"V_CE_2 = %.2f\" %V_CE_2", + "", + "p_del_I_C=((I_C_2-I_C_1)/I_C_1)*100;", + "p_del_V_CE=((V_CE_2-V_CE_1)/V_CE_1)*100;", + "print \"percent change in collector currrent = %.2f\" %p_del_I_C", + "print \"percent change in collector emitter voltage = %.2f\" %p_del_V_CE", + "print \"answers in book are approximated\"" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "I_C_1 = 0.002", + "V_CE_1 = 14.61", + "I_C_2 = 0.002", + "V_CE_2 = 14.07", + "percent change in collector currrent = 2.13", + "percent change in collector emitter voltage = -3.69", + "answers in book are approximated" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "markdown", + "source": [ + "<h3>Example 5.8, Page Number: 161<h3>" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "", + "# variable declaratio", + "V_CC=10.0; #voltage in volt", + "B_DC=100.0; #Dc value", + "R_C=10.0*10**3; #resistance in ohm", + "R_B=100.0*10**3; #resistance in ohm", + "V_BE=0.7; #base-emittor voltage", + "", + "#calculation", + "I_C=(V_CC-V_BE)/(R_C+(R_B/B_DC)); #collector current", + "V_CE=V_CC-I_C*R_C; #CE voltage", + "", + "#result", + "print \"Q point of collector current %.4f amperes\" %I_C", + "print \"Q point of collector-emitter voltage %.3f volts\" %V_CE" + ], + "language": "python", + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Q point of collector current 0.0008 amperes", + "Q point of collector-emitter voltage 1.545 volts" + ] + } + ], + "prompt_number": 9 + } + ] + } + ] +}
\ No newline at end of file |