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Diffstat (limited to 'Electrical_Power_System_by_C.L._Wadhwa/Chapter15.ipynb')
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diff --git a/Electrical_Power_System_by_C.L._Wadhwa/Chapter15.ipynb b/Electrical_Power_System_by_C.L._Wadhwa/Chapter15.ipynb new file mode 100755 index 00000000..f6a5df58 --- /dev/null +++ b/Electrical_Power_System_by_C.L._Wadhwa/Chapter15.ipynb @@ -0,0 +1,238 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 15 : Circuit Breakers"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15.1, Page No 486"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "i=5.0\n",
+ "L=5*(10**6)\n",
+ "C=0.01\n",
+ "\n",
+ "#Calculations\n",
+ "e=i*math.sqrt(L/C)\n",
+ "\n",
+ "#Results\n",
+ "print(\"The voltage appearing across the pole of C.B.=%.2f V \" %e)\n",
+ "R=0.5*math.sqrt(L/C)\n",
+ "print(\"The value of resistance to be used across contacts, R=%.2f ohms\" %R)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The voltage appearing across the pole of C.B.=111803.40 V \n",
+ "The value of resistance to be used across contacts, R=11180.34 ohms\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15.2, Page No 487"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Vnl=132*math.sqrt(2)/math.sqrt(3) #peak value of peak to neutral voltage(kV)\n",
+ "Vr1=Vnl*.95 #recovery voltage (kV)\n",
+ "\n",
+ "#Calculations\n",
+ "Vr=102.4*.916 # active recovery voltage(kV)\n",
+ "Vrmax=2.0*Vr\n",
+ "fn=16.0*(10**3)\n",
+ "t=1.0/(2*fn)\n",
+ "RRRV=Vrmax*(10**-6)/t\n",
+ "\n",
+ "#Results\n",
+ "print(\"Rate of rise of restriking voltage, RRRV = %.0f kV/micro-sec \" %RRRV)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Rate of rise of restriking voltage, RRRV = 6 kV/micro-sec \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15.3, Page No 487"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Vm=132*math.sqrt(2)/math.sqrt(3)\n",
+ "K1=0.9\n",
+ "K2=1.5\n",
+ "K=K1*K2\n",
+ "sinq=0.92\n",
+ "\n",
+ "#Calculations\n",
+ "Vr=K*Vm*sinq\n",
+ "fn=16*(10**3)\n",
+ "RRRV=2*Vr*(10**-6)*fn*2\n",
+ "\n",
+ "#Results\n",
+ "print(\"Average rate of rise of restriking voltage,RRRV=%.3f kV/micro-sec\" %RRRV)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Average rate of rise of restriking voltage,RRRV=8.567 kV/micro-sec\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15.4 Page No 504"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "In=1500.0\n",
+ "\n",
+ "#Calculations\n",
+ "Ib=2000/(math.sqrt(3.0)*33.0)\n",
+ "Im=2.55*Ib\n",
+ "Is=Ib\n",
+ "\n",
+ "#Results\n",
+ "print(\"rated normal current=%.0f amps\" %In)\n",
+ "print(\"Breaking current=%.2f KA\" %Ib)\n",
+ "print(\"Making current =%.2f kA\" %Im)\n",
+ "print(\"Short time rating for 3 sec=%.2f kA \" %Is)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "rated normal current=1500 amps\n",
+ "Breaking current=34.99 KA\n",
+ "Making current =89.23 kA\n",
+ "Short time rating for 3 sec=34.99 kA \n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15.5, Page No 504"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "MVA=10.0\n",
+ "Is=MVA*1000/(math.sqrt(3)*13.8)\n",
+ "print(\"(i)sustained short circuit current in the breaker =%.0f amps\" %Is)\n",
+ "MVA1=100.0\n",
+ "Isc=MVA1*1000.0/(math.sqrt(3)*13.8)\n",
+ "\n",
+ "#Calculations\n",
+ "print(\"(ii)initial symmetrical r.m.s current in the breaker r.m.s=%.0f amps\" %Isc)\n",
+ "Im=math.sqrt(2)*Isc\n",
+ "print(\"(iii)maximum possible d.c component of the short circuit current in the breaker =%.0f amps\" %Im)\n",
+ "Im2=1.6*Isc\n",
+ "print(\"(iv)momentary current rating of the breaker=%.0f amps\" %Im2)\n",
+ "Ib=1.2*Isc\n",
+ "print(\"(v)the current to be interrupted by the breaker =%.0f amps\" %Ib)\n",
+ "KVA=math.sqrt(3)*13.8*5016\n",
+ "\n",
+ "#Results\n",
+ "print(\"(vi)the interupting =%.0f KVA\"%KVA)\n",
+ "#Answers don't match due to difference in rounding off of digits"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i)sustained short circuit current in the breaker =418 amps\n",
+ "(ii)initial symmetrical r.m.s current in the breaker r.m.s=4184 amps\n",
+ "(iii)maximum possible d.c component of the short circuit current in the breaker =5917 amps\n",
+ "(iv)momentary current rating of the breaker=6694 amps\n",
+ "(v)the current to be interrupted by the breaker =5020 amps\n",
+ "(vi)the interupting =119894 KVA\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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