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diff --git a/Concepts_of_Thermodynamics/Chapter9.ipynb b/Concepts_of_Thermodynamics/Chapter9.ipynb new file mode 100755 index 00000000..ff2f789c --- /dev/null +++ b/Concepts_of_Thermodynamics/Chapter9.ipynb @@ -0,0 +1,773 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 9 - Properties of the pure substance"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 1 - Pg 194"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the internal energy of the system.\n",
+ "#Initialization of variables\n",
+ "T=32. #F\n",
+ "m=1 #lbm\n",
+ "J=778.16\n",
+ "#calculations\n",
+ "print '%s' %(\"From steam tables,\")\n",
+ "hf=0 \n",
+ "p=0.08854 #psia\n",
+ "vf=0.01602 #ft^3/lbm\n",
+ "u=hf-p*144*vf/J\n",
+ "#results\n",
+ "print '%s %.7f %s' %(\"Internal energy =\",u,\"Btu/lbm\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From steam tables,\n",
+ "Internal energy = -0.0002625 Btu/lbm\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2 - Pg 194"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the change in entropy of the process\n",
+ "#Initialization of variables\n",
+ "P=40. #psia\n",
+ "#calculations\n",
+ "print '%s' %(\"from steam tables,\")\n",
+ "hf=200.8 #Btu/lbm\n",
+ "hg=27 #Btu/lbm\n",
+ "T=495. #R\n",
+ "ds=(hf-hg)/T\n",
+ "#results\n",
+ "print '%s %.3f %s' %(\"Change in entropy =\",ds,\"Btu/lbm R\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "from steam tables,\n",
+ "Change in entropy = 0.351 Btu/lbm R\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3 - Pg 194"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the specific enthalpy of the mixture\n",
+ "#Initialization of variables\n",
+ "x=0.35\n",
+ "T=18. #F\n",
+ "#calculations\n",
+ "print '%s' %(\"From table B-14,\")\n",
+ "hf=12.12 #Btu/lbm\n",
+ "hg=80.27 #Btu.lbm\n",
+ "hfg=-hf+hg\n",
+ "h=hf+x*hfg\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"specific enthalpy =\",h,\"Btu/lbm\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From table B-14,\n",
+ "specific enthalpy = 36.0 Btu/lbm\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4 - Pg 194"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the heat required for the process\n",
+ "#Initialization of variables\n",
+ "x=0.35\n",
+ "T=18. #F\n",
+ "T2=55.5 #F\n",
+ "#calculations\n",
+ "print '%s' %(\"From table B-14,\")\n",
+ "hf=12.12 #Btu/lbm\n",
+ "hg=80.27 #Btu.lbm\n",
+ "hfg=-hf+hg\n",
+ "h=hf+x*hfg\n",
+ "h2=85.68 #Btu/lbm\n",
+ "dh=h2-h\n",
+ "#results\n",
+ "print '%s %.2f %s' %(\"Heat required =\",dh,\"Btu/lbm\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From table B-14,\n",
+ "Heat required = 49.71 Btu/lbm\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5 - Pg 194"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the enthalpy given out and the quality of the gas\n",
+ "#Initialization of variables\n",
+ "P=1460. #psia\n",
+ "T=135. #F\n",
+ "P2=700. #psia\n",
+ "#calculations\n",
+ "print '%s' %(\"From mollier chart,\")\n",
+ "h=120 #Btu/lbm\n",
+ "x=0.83\n",
+ "#results\n",
+ "print '%s %d %s' %(\"enthalpy =\",h,\" Btu/lbm\")\n",
+ "print '%s %.2f' %(\"\\n Qulaity = \",x)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From mollier chart,\n",
+ "enthalpy = 120 Btu/lbm\n",
+ "\n",
+ " Qulaity = 0.83\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6 - Pg 195"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the heat transferred in the process\n",
+ "#Initialization of variables\n",
+ "m=1 #lbm\n",
+ "P1=144. #psia\n",
+ "P2=150. #psia\n",
+ "T1=360. #F\n",
+ "J=778.16\n",
+ "#calculations\n",
+ "print '%s' %(\"From table 3,\")\n",
+ "v1=3.160 #ft^3/lbm\n",
+ "h1=1196.5 #Btu/lbm\n",
+ "u1=h1-P1*144*v1/J\n",
+ "h2=1211.4 #Btu/lbm\n",
+ "u2=h2-P2*144*v1/J\n",
+ "dq=u2-u1\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Heat transferred =\",dq,\" Btu/lbm\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From table 3,\n",
+ "Heat transferred = 11.4 Btu/lbm\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 7 - Pg 195"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the work required, reversible work and the work done in compression \n",
+ "#Initialization of variables\n",
+ "T1=100 #F\n",
+ "P2=1000. #psia\n",
+ "x=0.6\n",
+ "J=778.16\n",
+ "tir=2 \n",
+ "P1=0.9 #psia\n",
+ "#calculations\n",
+ "print '%s' %(\"From table 3,\")\n",
+ "hf=67.97\n",
+ "htc=2.7\n",
+ "hpc=0.32\n",
+ "h1=67.97\n",
+ "dv=0.000051\n",
+ "v=0.01613\n",
+ "h2=hf+htc+hpc\n",
+ "wrev=h1-h2\n",
+ "wact=wrev/x\n",
+ "dt=hpc+tir\n",
+ "t2act=T1+dt\n",
+ "wrev2=-v*144*(P2-P1)/J\n",
+ "dw=(P1+P2)/2. *dv *144/J\n",
+ "#results\n",
+ "print '%s %.2f %s' %(\"Work required =\",wact,\" Btu/lbm\")\n",
+ "print '%s %.2f %s' %(\"\\n reversible work done =\",wrev2,\" Btu/lbm\")\n",
+ "print '%s %.4f %s' %(\"\\n Work done in compression =\",dw,\"Btu/lbm\")\n",
+ "print '%s' %(\"The answers are a bit different due to rounding off error in textbook\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From table 3,\n",
+ "Work required = -5.03 Btu/lbm\n",
+ "\n",
+ " reversible work done = -2.98 Btu/lbm\n",
+ "\n",
+ " Work done in compression = 0.0047 Btu/lbm\n",
+ "The answers are a bit different due to rounding off error in textbook\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8 - Pg 196"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the heat transferred in the process\n",
+ "#Initialization of variables\n",
+ "pa=1000. #atm\n",
+ "ta=100. #F\n",
+ "#calculations\n",
+ "hf=67.97 #Btu/lbm\n",
+ "w=3 #Btu/lbm\n",
+ "ha=hf+w\n",
+ "print '%s' %(\"from steam table 2,\")\n",
+ "hc=1191.8 #Btu/lbm\n",
+ "qrev=hc-ha\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Heat transferred =\",qrev,\"Btu/lbm\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "from steam table 2,\n",
+ "Heat transferred = 1120.8 Btu/lbm\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 10 - Pg 197"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the work done and final pressure\n",
+ "#Initialization of variables\n",
+ "P1=144 #psia\n",
+ "T1=400 #F\n",
+ "y=0.7\n",
+ "#calculations\n",
+ "print '%s' %(\"From steam tables,\")\n",
+ "h1=1220.4 #Btu/lbm\n",
+ "s1=1.6050 #Btu/lbm R\n",
+ "s2=1.6050 #Btu/lbm R\n",
+ "P2=3 #psia\n",
+ "sf=0.2008 #Btu/lbm R\n",
+ "sfg=1.6855 #Btu/lbm R\n",
+ "x=(s1-sf)/sfg\n",
+ "hf=109.37 #Btu/lbm\n",
+ "hfg=1013.2 #Btu/;bm\n",
+ "h2=hf+x*hfg\n",
+ "work=h1-h2\n",
+ "dw=y*work\n",
+ "h2d=h1-dw\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Work done =\",work,\"Btu/lbm\")\n",
+ "print '%s %.1f %s' %(\"\\n work done in case 2 =\",dw,\"Btu/lbm\")\n",
+ "print '%s %d %s' %(\"\\n Final state pressure =\",P2,\"psia\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From steam tables,\n",
+ "Work done = 266 Btu/lbm\n",
+ "\n",
+ " work done in case 2 = 186.8 Btu/lbm\n",
+ "\n",
+ " Final state pressure = 3 psia\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11 - Pg 200"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the quality of wet steam\n",
+ "#Initialization of variables\n",
+ "pb=14.696 #psia\n",
+ "pa=150 #psia\n",
+ "tb=300 #F\n",
+ "#calculations\n",
+ "print '%s' %(\"From steam tables,\")\n",
+ "hb=1192.8 #Btu/lbm\n",
+ "ha=hb\n",
+ "hf=330.51 #Btu/lbm\n",
+ "hfg=863.6 #Btu/lbm\n",
+ "x=(ha-hf)/hfg*100\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Quality of wet steam =\",x,\"percent\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From steam tables,\n",
+ "Quality of wet steam = 99.8 percent\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12 - Pg 204"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the thermal and furnace efficiencies\n",
+ "#Initialization of variables\n",
+ "p1=600 #psia\n",
+ "p2=0.2563 #psia\n",
+ "t1=486.21 #F\n",
+ "t2=60 #F\n",
+ "fur=0.75\n",
+ "#calculations\n",
+ "print '%s' %(\"from steam tables,\")\n",
+ "h1=1203.2\n",
+ "hf1=471.6\n",
+ "hfg1=731.6\n",
+ "h2=1088\n",
+ "hf2=28.06\n",
+ "hfg2=1059.9\n",
+ "s1=1.4454\n",
+ "sf1=0.6720\n",
+ "sfg1=0.7734\n",
+ "s2=2.0948\n",
+ "sf2=0.0555\n",
+ "sfg2=2.0393\n",
+ "xd=(s1-sf2)/sfg2\n",
+ "hd=hf2+xd*hfg2\n",
+ "xa=0.3023\n",
+ "ha=hf2+xa*hfg2\n",
+ "wbc=0\n",
+ "wda=0\n",
+ "wcd=h1-hd\n",
+ "wab=ha-hf1\n",
+ "W=wab+wcd+wbc+wda\n",
+ "Wrev=hfg1- (t2+459.7)*sfg1\n",
+ "etat=(t1-t2)/(t1+459.7)*100\n",
+ "eta=fur*etat\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Thermal efficiency =\",etat,\"percent\")\n",
+ "print '%s %.1f %s' %(\"\\n Furnace efficiency =\",eta,\"percent\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "from steam tables,\n",
+ "Thermal efficiency = 45 percent\n",
+ "\n",
+ " Furnace efficiency = 33.8 percent\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 13 - Pg 204"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the thermal and overall efficiencies\n",
+ "#Initialization of variables\n",
+ "dhab=-123.1\n",
+ "etac=0.5\n",
+ "ha=348.5\n",
+ "etaf=0.75\n",
+ "eta=0.85\n",
+ "hf=471.6\n",
+ "hfg=731.6\n",
+ "hc=1203.2\n",
+ "dhcd=452.7\n",
+ "#calculations\n",
+ "dwabs=dhab/etac\n",
+ "hbd=ha-dwabs\n",
+ "dwcds=dhcd*eta\n",
+ "dqa=hc-hbd\n",
+ "etat=(dwcds+dwabs)/dqa*100\n",
+ "eta=etat*etaf\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Thermal efficiency =\",etat,\"percent\")\n",
+ "print '%s %.1f %s' %(\"\\n Overall efficiency =\",eta,\"percent\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Thermal efficiency = 22.8 percent\n",
+ "\n",
+ " Overall efficiency = 17.1 percent\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 14 - Pg 205"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the thermal and overall efficiencies\n",
+ "#Initialization of variables\n",
+ "t=60 #F\n",
+ "J=778.16\n",
+ "p1=600 #psia\n",
+ "p2=0.2563 #psia\n",
+ "etaf=0.85 \n",
+ "#calculations\n",
+ "print '%s' %(\"From steam tables,\")\n",
+ "vf=0.01604 #ft^3/lbm\n",
+ "dw=-vf*(p1-p2)*144/J\n",
+ "ha=28.06 #Btu/lbm\n",
+ "hb=29.84 #Btu/lbm\n",
+ "hd=1203.2 #Btu/lbm\n",
+ "he=750.5 #Btu/lbm\n",
+ "dqa=hd-hb\n",
+ "dqr=ha-he\n",
+ "dw=dqa+dqr\n",
+ "dwturb=hd-he\n",
+ "dwpump=ha-hb\n",
+ "etat=dw/dqa*100\n",
+ "eta=etat*etaf\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Thermal efficiency =\",etat,\"percent\")\n",
+ "print '%s %.1f %s' %(\"\\n Overall efficiency =\",eta,\"percent\")\n",
+ " \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From steam tables,\n",
+ "Thermal efficiency = 38.4 percent\n",
+ "\n",
+ " Overall efficiency = 32.7 percent\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15 - Pg 206"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the thermal and overall efficiencies\n",
+ "#Initialization of variables\n",
+ "dhab=-1.78\n",
+ "etac=0.5\n",
+ "ha=28.06\n",
+ "eta=0.85\n",
+ "hf=471.6\n",
+ "hfg=731.6\n",
+ "hd=1203.2\n",
+ "dhcd=452.7\n",
+ "#calculations\n",
+ "dwabs=dhab/etac\n",
+ "hbd=ha-dwabs\n",
+ "dwcds=dhcd*eta\n",
+ "dqa=hd-hbd\n",
+ "etat=(dwcds+dwabs)/dqa*100\n",
+ "eta=etat*eta\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Thermal efficiency =\",etat,\"percent\")\n",
+ "print '%s %.1f %s' %(\"\\n Overall efficiency =\",eta,\"percent\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Thermal efficiency = 32.5 percent\n",
+ "\n",
+ " Overall efficiency = 27.7 percent\n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 16 - Pg 207"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the coefficient of performance, hp required, work of compression and expansion\n",
+ "#Initialization of variables\n",
+ "Ta=500. #R\n",
+ "Tr=540. #R\n",
+ "#calculations\n",
+ "cop=Ta/(Tr-Ta)\n",
+ "hp=4.71/cop\n",
+ "print '%s' %(\"From steam tables,\")\n",
+ "ha=48.02\n",
+ "hb=46.6\n",
+ "hc=824.1\n",
+ "hd=886.9\n",
+ "Wc=-(hd-hc)\n",
+ "We=-(hb-ha)\n",
+ "#results\n",
+ "print '%s %.1f' %(\"Coefficient of performance = \",cop)\n",
+ "print '%s %.3f %s' %(\"\\n horsepower required per ton of refrigeration =\",hp,\"hp/ton refrigeration\")\n",
+ "print '%s %.1f %s' %(\"\\n Work of compression =\",Wc,\"Btu/lbm\")\n",
+ "print '%s %.2f %s' %(\"\\n Work of expansion =\",We,\"Btu/lbm\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "From steam tables,\n",
+ "Coefficient of performance = 12.5\n",
+ "\n",
+ " horsepower required per ton of refrigeration = 0.377 hp/ton refrigeration\n",
+ "\n",
+ " Work of compression = -62.8 Btu/lbm\n",
+ "\n",
+ " Work of expansion = 1.42 Btu/lbm\n"
+ ]
+ }
+ ],
+ "prompt_number": 15
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17 - Pg 209"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the coefficient of performance\n",
+ "#Initialization of variables\n",
+ "x=0.8\n",
+ "he=26.28 #Btu/lbm\n",
+ "hb=26.28 #Btu/lbm\n",
+ "pe=98.76 #psia\n",
+ "pc=51.68 #psia\n",
+ "hc=82.71 #Btu/lbm\n",
+ "hf=86.80+0.95\n",
+ "#calculations\n",
+ "dwisen=-(hf-hc)\n",
+ "dwact=dwisen/x\n",
+ "hd=hc-dwact\n",
+ "cop=(hc-hb)/(hd-hc)\n",
+ "#results\n",
+ "print '%s %.2f' %(\"Coefficient of performance = \",cop)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Coefficient of performance = 8.96\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |