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diff --git a/Concepts_Of_Modern_Physics/Chapter_10.ipynb b/Concepts_Of_Modern_Physics/Chapter_10.ipynb new file mode 100755 index 00000000..a9c68145 --- /dev/null +++ b/Concepts_Of_Modern_Physics/Chapter_10.ipynb @@ -0,0 +1,152 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 10:The Solid state"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 10.1,Page no:342"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Variable declaration \n",
+ "import math\n",
+ "Ro= 0.281 #equilibrium distance between ions, nm\n",
+ "alpha= 1.748 #Madelung constant\n",
+ "n= 9 #exponent, from observed compressibilities of NaCl\n",
+ "e= 1.6*(10**(-19)) #charge of an electron, C\n",
+ "Po= 8.85*(10**(-12)) #Permittivity of free space, F/m\n",
+ "\n",
+ "#Calculation\n",
+ "K=1.0/(4*(math.pi)*Po) #constant, N.m**2/C**2\n",
+ "Uo= -(K*alpha*(e**2)*(1.0-(1.0/n)))/(Ro*(10**(-9))) #Potential energy per ion pair, J\n",
+ "Uo= Uo/e #converting to eV\n",
+ "E1= 5.14 #Ionisation energy for Na, eV\n",
+ "E2= -3.61 #electron affinity of Cl, eV\n",
+ "E= E1+E2 #Electron transfer energy, eV\n",
+ "Ecohesive = (Uo +E) #per electron pair, eV\n",
+ "Ecohesive= Ecohesive/2.0 #for each ion, eV\n",
+ "\n",
+ "#Result\n",
+ "print\"The cohesive energy in NaCl is: \",round(Ecohesive,2),\"eV\"\n",
+ "print\"\\nWhich is not far from experimental value of -3.28 eV\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The cohesive energy in NaCl is: -3.21 eV\n",
+ "\n",
+ "Which is not far from experimental value of -3.28 eV\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.2,Page no:350"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "#Variable declaration \n",
+ "A= 1.0 #cross-sectional area of wire, mm**2\n",
+ "I= 1.0 #current in wire, A\n",
+ "n= 8.5*(10**28) # electrons/m**3\n",
+ "e= 1.6*(10**(-19)) #charge of an electron, C\n",
+ "\n",
+ "#Calculation\n",
+ "Vdrift= I/(n*(A*(10**(-6)))*e) #m/s\n",
+ "\n",
+ "#Result\n",
+ "print\"The drift velocity of electrons in the copper wire is:%.2g\"%Vdrift,\"m/s\"\n",
+ "print\"\\nNOTE:Calculation mistake in book.Wrongly written as 7.4*10^-4\"\n",
+ " \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The drift velocity of electrons in the copper wire is:7.4e-05 m/s\n",
+ "\n",
+ "NOTE:Calculation mistake in book.Wrongly written as 7.4*10^-4\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.3,Page no:353"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Variable declaration \n",
+ "n= 8.48*(10**28) #free electron density, m**(-3)\n",
+ "Vfermi= 1.57*(10**6) #Fermi Velocity, m/s\n",
+ "rho= 1.72*(10**(-8)) #resistivity, ohm\n",
+ "e= 1.6*(10**(-19)) #charge of an electron, C\n",
+ "Me= 9.1*(10**(-31)) #mass of electron, kg\n",
+ "\n",
+ "#Calculation\n",
+ "lamda= Me*Vfermi/(n*(e**2)*rho) #m\n",
+ "lamda= lamda*(10**9) #converting to nm\n",
+ "\n",
+ "#Result\n",
+ "print\"The mean free path is:\",round(lamda,1),\"nm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The mean free path is: 38.3 nm\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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