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diff --git a/Chemical_Reaction_Engineering/ch26.ipynb b/Chemical_Reaction_Engineering/ch26.ipynb new file mode 100755 index 00000000..cb1d9f92 --- /dev/null +++ b/Chemical_Reaction_Engineering/ch26.ipynb @@ -0,0 +1,214 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 26 :\n", + "\n", + "Fluid-Particle Reactors: Design" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 26.1 pageno : 592" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Lets say F(Ri)/F = F_ri\n", + "\n", + "# Variables\n", + "F_50 = 0.3\n", + "F_100 = 0.4\n", + "F_200 = 0.3;\n", + "t_50 = 5.\n", + "t_100 = 10.\n", + "t_200 = 20.\n", + "tp = 8.\n", + "\n", + "# Calculations\n", + "a = ((1-(tp/t_50))**3)*F_50\n", + "b = ((1-(tp/t_100))**3)*F_100\n", + "c = ((1-(tp/t_200))**3)*F_200;\n", + "g = [a,b,c];\n", + "sum1 = 0;\n", + "for p in range(3):\n", + " if g[p]>0:\n", + " sum1 = sum1+g[p];\n", + "f_converted = 1-sum1;\n", + "\n", + "# Results\n", + "print \" The fraction of solid converted equals %.1f %%\"%(f_converted*100)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The fraction of solid converted equals 93.2 %\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 26.2 pageno : 597" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "t_avg = 60. # min\n", + "t = 20. #min\n", + "\n", + "# Calculations\n", + "unconverted = ((1./4)*(t/t_avg))-((1./20)*(t/t_avg)**2)+((1./120)*(t/t_avg)**3);\n", + "unconverted1 = ((1./5)*(t/t_avg))-((19./420)*(t/t_avg)**2)+((41./4620)*(t/t_avg)**3);\n", + "c_avg = (unconverted+unconverted1)/2;\n", + "\n", + "# Results\n", + "print \"Fraction of original sulfide ore remain unconverted is %.2f\"%(c_avg)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Fraction of original sulfide ore remain unconverted is 0.07\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 26.3 page no : 600" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "F = 1000. #gm/min\n", + "W = 10000. #gm\n", + "\n", + "# Calculations\n", + "t_avg = W/F;\n", + "F_50 = 300.\n", + "F_100 = 400.\n", + "F_200 = 300. #gm/min\n", + "t_50 = 5.\n", + "t_100 = 10.\n", + "t_200 = 20. #min\n", + "\n", + "unconverted = ((((1./4)*(t_50/t_avg))-((1./20)*(t_50/t_avg)**2)+ ((1./120)*(t_50/t_avg)**3))*(F_50/F))+((((1./4)*(t_100/t_avg))-((1./20)*(t_100/t_avg)**2)+((1./120)*(t_50/t_avg)**3))*(F_100/F))+((((1./4)*(t_200/t_avg))-((1./20)*(t_200/t_avg)**2)+((1./120) *(t_50/t_avg)**3))*(F_200/F))\n", + "converted = 1-unconverted;\n", + "\n", + "# Results\n", + "print \"The mean conversion of soild is %f\"%(converted)\n", + "print \" The answer slightly differs from those given in book as we have considered \\\n", + "only significant terms in infinite series\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The mean conversion of soild is 0.795208\n", + " The answer slightly differs from those given in book as we have considered only significant terms in infinite series\n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 26.4 pageno : 601" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "t1 = 1. #hr\n", + "t2 = t1/0.1 \n", + "a = 0.\n", + "r = 1 #ton/hr\n", + "# Calculations\n", + "while a<=1:\n", + " x = (1./4)*(a)-((1./20)*(a)**2)+((1./120)*(a)**3);\n", + " if x >0.099 and x<0.1005:\n", + " r = a;\n", + " a += .0001\n", + "\n", + "FBo = 1. #tons/hr\n", + "t_avg = t2/r;\n", + "W = t_avg*FBo;\n", + "\n", + "# Results\n", + "print \" The needed weight of bed is %.f\"%(W),\n", + "print \"tons\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The needed weight of bed is 23 tons\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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