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diff --git a/Basic_Engineering_Thermodynamics/ch7.ipynb b/Basic_Engineering_Thermodynamics/ch7.ipynb new file mode 100755 index 00000000..b6ea2d15 --- /dev/null +++ b/Basic_Engineering_Thermodynamics/ch7.ipynb @@ -0,0 +1,204 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:c994036a387ecf3d6e1af15e46c49ba61b58c1363388a5e580f169263936cabd" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 7 : Reversibility and The Thermodynamic Temperature Scale" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 7.1 Page No : 174" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "print \"Part a\";\n", + "\t\t\t\n", + "# Variables\n", + "Q1 = 500. \t\t\t#kJ \t\t\t#Heat transfer from reservoir at t1\n", + "Q2 = 187.5 \t\t\t#kJ \t\t\t#Heat transfer from reservoir at t2\n", + "\n", + "\t\t\t\n", + "# Calculations and Results\n", + "nr = 1-(Q2/Q1) \t\t\t#Efficiency\n", + "W = nr*Q1 \t\t\t#kJ \t\t\t#Work output of the engine\n", + "print \"Work output of the engine = %.1f kJ\"%(W);\n", + "\n", + "\t\t\t#Part(b)\n", + "print \"Part b\";\n", + "\t\t\t\n", + "# Variables\n", + "Q1 = 500. \t\t\t#kJ \t\t\t#Heat transfer from reservoir at t1\n", + "\t\t\t\n", + "# Calculations and Results\n", + "COP_hp = 1/nr\n", + "W = Q1/COP_hp \t\t\t#kJ \t\t\t#Work input to heat pump\n", + "Q2 = Q1-W \t\t\t#kJ \t\t\t#heat ineraction with reservoir at t2\n", + "print \"Heat ineraction with reservoir at t2 = %.1f kJ\"%(Q2);\n", + "print \"Work input to the heat pump = %.1f kJ\"%(W);\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Part a\n", + "Work output of the engine = 312.5 kJ\n", + "Part b\n", + "Heat ineraction with reservoir at t2 = 187.5 kJ\n", + "Work input to the heat pump = 312.5 kJ\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 7.2 Page No : 178" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\t\t\t\n", + "# Variables\n", + "nr = 0.7 \t\t\t#maximum efficiency\n", + "W = 80. \t\t\t#kJ \t\t\t#Work\n", + "Q1 = 100. \t\t\t#kJ \t\t\t#heat transfered\n", + "\t\t\t\n", + "# Calculations and Results\n", + "nx = W/Q1 \t\t\t#claimed efficiency\n", + "if nx>nr :\n", + " print \"Engine X is not a viable proposition because the claimed efficiency %.2f is greater than maximum efficiency %.2f\"%(nx,nr)\n", + "else:\n", + " print \"Engine X is a viable proposition because the claimed efficiency %.2f is less than maximum efficiency %.2f\"%(nx,nr) \n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Engine X is not a viable proposition because the claimed efficiency 0.80 is greater than maximum efficiency 0.70\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 7.4 Page No : 191" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\t\t\t\n", + "# Variables\n", + "T1 = (527.+273) \t\t\t#K\n", + "T2 = (27.+273) \t\t\t#K\n", + "\n", + "# calculations and results\n", + "#Part (a)\n", + "print \"Part a\";\n", + "nr = 1 - (T2/T1) \t\t\t#reversible efficiency\n", + "print \"Reversible efficiency = %.3f \"%(nr);\n", + "\n", + "#Part(b)\n", + "print \"Part b\";\n", + "print \"As the values of at least any two from among Q1,Q2 and W \\\n", + "are not given the efficiency of the engine cannot be evaluated.However\\\n", + "according to Carnots statement, the efficiency will be less than %.3f\"%(nr)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Part a\n", + "Reversible efficiency = 0.625 \n", + "Part b\n", + "As the values of at least any two from among Q1,Q2 and W are not given the efficiency of the engine cannot be evaluated.Howeveraccording to Carnots statement, the efficiency will be less than 0.625\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 7.5 Page No : 192" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\t\t\t\n", + "# Variables\n", + "T1 = 273. + 37 \t\t\t#K \n", + "T2 = 273. - 13 \t\t\t#K\n", + "\n", + "\t\t\t#Part(a)\n", + "print \"Part a\";\n", + "COP_ref = T2/(T1-T2) \t\t\t#COP of reversible heat engine as refrigerator.\n", + "print \"COP of reversible heat engine as refrigerator = %.1f\"%(COP_ref)\n", + "\t\t\t#Part(b)\n", + "print \"Part b\";\n", + "COP_hp = T1/(T1-T2) \t\t\t#COP of reversible heat engine as heat pump.\n", + "print \"COP of reversible heat engine as heat pump = %.1f\"%(COP_hp)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Part a\n", + "COP of reversible heat engine as refrigerator = 5.2\n", + "Part b\n", + "COP of reversible heat engine as heat pump = 6.2\n" + ] + } + ], + "prompt_number": 5 + } + ], + "metadata": {} + } + ] +}
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