1 files changed, 0 insertions, 130 deletions
diff --git a/Basic_Electronics_and_Linear_Circuits/ch10.ipynb b/Basic_Electronics_and_Linear_Circuits/ch10.ipynb
deleted file mode 100755
index 1268374a..00000000
--- a/Basic_Electronics_and_Linear_Circuits/ch10.ipynb
+++ /dev/null
@@ -1,130 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:c0e331b614f072bb0c21b302f0e54b6a8366fa46ba53ae4810b072360f344e0d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 10: Power Amplifiers"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 10.1 Page No.345"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "RL=16                                                     # Ohms, load resistance\n",
-      "RLd=10000.0                                         # Ohms ,effective load resistance\n",
-      "\n",
-      "#Calculation\n",
-      "import math\n",
-      "N12=math.sqrt(RLd/RL)                               #N12=N1/N2\n",
-      "\n",
-      "# Result\n",
-      "print \" The Transformer Turns Ratio is N1/N2\",N12,\":1\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " The Transformer Turns Ratio is N1/N2 25.0 :1\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 10.2 Page No.345"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "#Given Circuit Data\n",
-      "Rl=8.0                                        #Ohms, load resistance\n",
-      "N12=15.0                                  #N12=N1/N2, transformer turns ratio\n",
-      "\n",
-      "#Calculation\n",
-      "Rld=(N12)**2*Rl                 #effective resistance\n",
-      "\n",
-      "# Result\n",
-      "print \" The Effective Resistance seen looking into the Primary, Rld =  \",Rld/10**3,\"k ohm\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": []
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 10.3  Page No.353"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "I1=15                                            #A\n",
-      "I2=1.5                                           #A\n",
-      "I3=1.2                                           #A\n",
-      "I4=0.5                                           #A\n",
-      "\n",
-      "#Calculation\n",
-      "D2=(I2/I1)*100                               #percentage harmonic distribution of component  2\n",
-      "D3=(I3/I1)*100                               #percentage harmonic distribution of component  3\n",
-      "D4=(I4/I1)*100                               #percentage harmonic distribution of component  4\n",
-      "\n",
-      "#Result\n",
-      "print \" The Second Harmonic Distortion is, D2 =  percent .\",D2\n",
-      "print \" The Third  Harmonic Distortion is, D3 =  percent .\",D3\n",
-      "print \" The Fourth Harmonic Distortion is, D4 =  percent .\",round(D4,2)\n",
-      "\n",
-      "#(b)\n",
-      "import math\n",
-      "P1=1        #say\n",
-      "\n",
-      "#Calculation\n",
-      "D=math.sqrt(D2**2+D3**2+D4**2)    #Distortion Factor\n",
-      "P=(1+(D/100)**2)*P1\n",
-      "Pi=((P-P1)/P1)*100\n",
-      "\n",
-      "#Result\n",
-      "print \"The Percentage Increase in Power because of Distortion is, Pi (in percent)= \",round(Pi,2)"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": []
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file