diff options
Diffstat (limited to 'Applied_Physics/Chapter2.ipynb')
| -rwxr-xr-x | Applied_Physics/Chapter2.ipynb | 291 |
1 files changed, 291 insertions, 0 deletions
diff --git a/Applied_Physics/Chapter2.ipynb b/Applied_Physics/Chapter2.ipynb new file mode 100755 index 00000000..2d0b7a14 --- /dev/null +++ b/Applied_Physics/Chapter2.ipynb @@ -0,0 +1,291 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:f14517ab3de72640bce8c38f7d46947caa54ae7067bb37477a81849b7b917982"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 2:Crystal Structure"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2.1 , Page no:40"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "N=6.02*10**26; #in /Kg-molecule (Avogadro's number)\n",
+ "n=4; #number of molecules per unit cell ofr NaCl\n",
+ "M=58.5; #in Kg/Kg-molecule (molecular weight of NaCl)\n",
+ "p=2189; #in Kg/m^3 (density)\n",
+ "\n",
+ "#calculate\n",
+ "a=pow(((n*M)/(N*p)),0.3333333);\n",
+ "a1=a*10**10; #changing unit to Angstrom\n",
+ "\n",
+ "#result\n",
+ "print\"The lattice constant is a=\",a,\"m\";\n",
+ "print\"\\t\\t\\ta=\",a1,\"Angstrom\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The lattice constant is a= 5.62072226997e-10 m\n",
+ "\t\t\ta= 5.62072226997 Angstrom\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2.2 , Page no:41"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#given\n",
+ "N=6.02*10**23; #in /gram-atom (Avogadro's number)\n",
+ "n=4; #number of atom per unit cell for fcc structure\n",
+ "M=63.5; #in gram/gram-atom (atomic weight of Cu)\n",
+ "p=8.96; #in g/cm^3 (density)\n",
+ "\n",
+ "#calculate\n",
+ "a=pow((n*M/(N*p)),0.3333333);\n",
+ "a=a*1E8; #changing unit from cm to Angstrom\n",
+ "d=a/math.sqrt(2); #distance infcc lattice\n",
+ "\n",
+ "#result\n",
+ "print\"lattice constant is a=\",a,\"E-08 cm\";\n",
+ "print\"\\t\\t a=\",round(a,4),\"Angstrom\";\n",
+ "print\"distance between two nearest Cu atoms is d=\",round(d,2),\"Angstrom\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "lattice constant is a= 3.61113576149 E-08 cm\n",
+ "\t\t a= 3.6111 Angstrom\n",
+ "distance between two nearest Cu atoms is d= 2.55 Angstrom\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2.3 , Page no:41"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#given\n",
+ "N=6.02E26; #in /Kg-atom (Avogadro's number)\n",
+ "n=2; #number of molecules per unit cell for bcc lattice\n",
+ "M=55.85; #in Kg/Kg-atom (atomic weight of Iron)\n",
+ "p=7860; #in Kg/m^3 (density)\n",
+ "\n",
+ "#calculate\n",
+ "a=pow((n*M/(N*p)),0.33333);\n",
+ "a1=a*1E10; #changing unit to Angstrom\n",
+ "\n",
+ "#result\n",
+ "print\"The lattice constant is a=\",a,\"m\";\n",
+ "print\"\\t\\t\\ta=\",round(a1,3),\"Angstrom\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The lattice constant is a= 2.86928355016e-10 m\n",
+ "\t\t\ta= 2.869 Angstrom\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2.4 , Page no:42"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#given\n",
+ "N=6.02*10**26; #in /Kg-atom (Avogadro's number)\n",
+ "n=2; #number of molecules per unit cell for bcc lattice\n",
+ "M=6.94; #in Kg/Kg-atom (atomic weight of Iron)\n",
+ "p=530; #in Kg/m^3 (density)\n",
+ "\n",
+ "#calculate\n",
+ "a=pow((n*M/(N*p)),0.33333);\n",
+ "a1=a*1E10; #changing unit to Angstrom\n",
+ "\n",
+ "#result\n",
+ "print\"The lattice constant is a=\",a,\"m\";\n",
+ "print\"\\t\\t\\ta=\",round(a1,3),\"Angstrom\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The lattice constant is a= 3.51776567326e-10 m\n",
+ "\t\t\ta= 3.518 Angstrom\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2.5 , Page no:42"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#given\n",
+ "N=6.02*10**23; #in /gram-molecule (Avogadro's number)\n",
+ "M=58.5; #in gram/gram-molecule (atomic weight of NaCl)\n",
+ "p=2.17; #in g/cm^3 (density)\n",
+ "\n",
+ "#calculate\n",
+ "#since V=M/p\n",
+ "#(1/d)^-3=2N/V=2Np/M\n",
+ "#therefore d= (M/2Np)^-3\n",
+ "d=pow((M/(2*N*p)),0.33333333);\n",
+ "d1=d*1*10**8; #changing unit from cm to Angstrom\n",
+ "\n",
+ "#result\n",
+ "print\"The distance between two adjacent atoms of NaCl is d=\",d,\"m\";\n",
+ "print\"\\t\\t\\t\\t\\t\\t d=\",round(d1,3),\"Angstrom\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The distance between two adjacent atoms of NaCl is d= 2.81853408124e-08 m\n",
+ "\t\t\t\t\t\t d= 2.819 Angstrom\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2.6 , Page no:43"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#given\n",
+ "r_Na=0.98; #in Angstrom (radius of sodium ion)\n",
+ "r_Cl=1.81; #in Angstrom (radius of chloride ion)\n",
+ "M_Na=22.99; #in amu (atomic mass of sodium)\n",
+ "M_Cl=35.45; #in amu (atomic mass of chlorine)\n",
+ "\n",
+ "#calculate\n",
+ "a=2*(r_Na+r_Cl); #lattice parameter\n",
+ "#PF=volume of ions present in the unit cell/volume of unit cell\n",
+ "PF=((4*(4/3)*3.14)*r_Na**3+(4*(4/3)*3.14)*r_Cl**3)/a**3;\n",
+ "#Density=mass of unit cell/volume of unit cell\n",
+ "p=4*(M_Na+M_Cl)*1.66E-27/(a*1E-10)**3;\n",
+ "p1=p*1E-3; #changing unit to gm/cm^-3\n",
+ "\n",
+ "#result\n",
+ "print\"Lattice constant is a=\",round(a,3),\"Angstrom\";\n",
+ "print\"Packing fraction is =\",round(PF,3); \n",
+ "print\"Density is p=\",round(p),\"Kg/m^3\";\n",
+ "print\"Density is p=\",round(p1,2),\"g/cm^3\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Lattice constant is a= 5.58 Angstrom\n",
+ "Packing fraction is = 0.662\n",
+ "Density is p= 2233.0 Kg/m^3\n",
+ "Density is p= 2.23 g/cm^3\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |