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diff --git a/Applied_Physics-II/chapter4.ipynb b/Applied_Physics-II/chapter4.ipynb deleted file mode 100755 index 11b66b2f..00000000 --- a/Applied_Physics-II/chapter4.ipynb +++ /dev/null @@ -1,163 +0,0 @@ -{ - "metadata": { - "celltoolbar": "Raw Cell Format", - "name": "", - "signature": "sha256:e413b3bea25c7729b7ae1f595bf0f843336be8c682782f6b92de1c93aa46ed9d" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 4: Laser" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.1,Page number 4-27" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "\n", - "#Given Data:\n", - "lamda=694.3*10**-9 #Wavelength in meter\n", - "T=300 #Temperature in Kelvin\n", - "\n", - "h=6.63*10**-34 #Planck's Constant\n", - "c=3*10**8 #Velocity of light\n", - "K=1.38*10**-21 #Boltzmann Constant\n", - "\n", - "#Calculations:\n", - "delE= h*c/lamda #Energy difference between two energy states N and N0\n", - "\n", - "#N=N0*e^-delE/(K*T)\n", - "R=math.e**(-delE/(K*T)) #R=Ratio of N and N0 i.e.(R=N/N0)\n", - "\n", - "#(Printing mistake in textbook)\n", - "#instead of e^-.692, it has taken e^-69.2\n", - "\n", - "print\"The ratio of population of two energy states is = \",R\n", - "print\" (calculation mistake in book)\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The ratio of population of two energy states is = 0.500588928485\n", - " (calculation mistake in book)\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.2,Page number 4-28" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "import math\n", - "\n", - "#Given Data:\n", - "lamda=6328*10**-10 #Wavelength in meter\n", - "P=4.5*10**-3 #Power in watts\n", - "h=6.63*10**-34 #Planck's Constant\n", - "c=3*10**8 #Velocity of light\n", - "\n", - "#Calculations:\n", - "delE= h*c/lamda #Energy difference\n", - "#N*delE=P\n", - "N=P/delE #number of photons emitted per second\n", - "\n", - "print\"Number of photons emitted per second is =\",N\n", - "\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Number of photons emitted per second is = 1.43167420814e+16\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.3,Page number 4-29" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "\n", - "#Given Data:\n", - "lamda=780*10**-9 #Wavelength of photon in meter\n", - "P=20*10**-3 #Power of each pulse in watts\n", - "t=10*10**-9 #Duration of each pulse\n", - "h=6.63*10**-34 #Planck's Constant\n", - "c=3*10**8 #Velocity of light\n", - "\n", - "#Calculations:\n", - "delE= h*c/lamda #Energy of each photon\n", - "E=P*t #Energy of each pulse\n", - "\n", - "N=E/delE #Number of photons in each pulse\n", - "print\"Number of photons in each pulse is =\",N\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Number of photons in each pulse is = 784313725.49\n" - ] - } - ], - "prompt_number": 6 - }, - { - "cell_type": "code", - "collapsed": false, - "input": [], - "language": "python", - "metadata": {}, - "outputs": [] - } - ], - "metadata": {} - } - ] -}
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