1 files changed, 103 insertions, 0 deletions
diff --git a/A_Textbook_Of_Engineering_Physics/Chapter19.ipynb b/A_Textbook_Of_Engineering_Physics/Chapter19.ipynb
new file mode 100755
index 00000000..9cd6b0d3
--- /dev/null
+++ b/A_Textbook_Of_Engineering_Physics/Chapter19.ipynb
@@ -0,0 +1,103 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:e62a104ff81010a41974070c37970149915a1689606735dc017583e29241aaa5"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter19-PN-Junction Diode"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex1-pg571"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "##Example 19.1\n",
+      "##calculation of potential barrier\n",
+      "\n",
+      "##given values\n",
+      "e=1.6*10**-19.;\n",
+      "n=4.4*10**28.;##no of atoms per m**3\n",
+      "kT=.026*e;##temp eqvlnt at room temp\n",
+      "ni=2.4*10**19.;##no of intrinsic carriers per m**3\n",
+      "NA=n/10**6.;##no of acceptors\n",
+      "ND=n/10**6.;##no of donors\n",
+      "\n",
+      "##calculation\n",
+      "V=(kT/e)*math.log(NA*ND/ni**2);\n",
+      "print'%s %.2f %s'%('potential barrier in volts is',V,'');\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "potential barrier in volts is 0.39 \n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex2-pg578"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "##Example 19.2\n",
+      "##calculation of current\n",
+      "\n",
+      "##given values\n",
+      "e=1.6*10**-19.;\n",
+      "kT=.026*e;##temp eqvlnt at room temp\n",
+      "Io=2*10**-7;##current flowing at room temp in A\n",
+      "V=.1;##forward bias voltage in volts\n",
+      "\n",
+      "##calculation\n",
+      "I=Io*(math.e**(e*V/kT)-1);##in Ampere\n",
+      "print'%s %.2f %s'%('current flowing when forward bias applied(in microampere)is',I*10**6,'');\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "current flowing when forward bias applied(in microampere)is 9.16 \n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file